12-28 Exercise 3: Anagrams function

0 like 0 dislike
12k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited | 12k views
0 0
STRUPES!
commented by (323 points)

79 Answers

0 like 0 dislike 
Hidden content!
#include    ** **   *  * *
#include  *  * ** **  *
#include * **   *** *
int * ***     * a[],char b[])
{
** * ** ** *  *** ****  first[26] = {0}, second[26] = {0}, c = 0;
* **  
 * * ********       *   * *** frequency of      in first string
*     *
*   * ****      *   **  (a[c] != '\0')
***  * ***  **   *  * ** ** 
      ** *   * * ** *  * ***      *      *  *** *   **
 ***     * * **  ** ** *****  *  *  * **   ****
* *   ******* **   **
 **  
* * *        **   *  = 0;
* *****
   *    * *** ***  *** (b[c] != '\0')
 * ***  ** * *** 
 ***    **  * *** *    *** *  * *     * * ** * *
*   ***    ** *   *    ** *  * * * ** * **** 
 *  ***   *   ***   *  **  
*  *   *
** ***  *  * * *   *** Comparing frequency of    * *   
***   **
 ** ***  * ***  * *** *** (c = 0; c < 26; c++)
 *****   *   **     
   * ** ** *  **      ** * **  * ****** **   (first[c] != second[c])
*  *** **    *    ***** *  *  ** *    *** * *   ** **    *** ***** 0;
*      *    *** * ** 
     
* *** ***   *    ***  **  *   1;
}

int ** *  
{
  *** ****    ** **** *  ***     *  * 
* ** *  ** *     ** *  *      *      A,B);
    * *  * *  *  *    *  **  **** **   *** ** *   * words or phrases are ** **  *    *
**** *   *  **     ***      *  ***** *  *  words or phrases are not     ******  * 

 **   **   * *   ** * * ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ****  *    * *
#include  **  ***** * *
#include * * ** *  *****
int   * ** *  * a[],char b[])
{
* *           *      first[26] = {0}, second[26] = {0}, c = 0;
  *** * 
***  *   * *****   * *   *     frequency of characters in first string
   * **  
    * **   ** *  * * *  **  (a[c] != '\0')
*  * *    ***   *   **  
 ***   * *    *       * * *    **  *   * * * 
 *** *  ** ** **** ***** **** *  ** ** **   
   ** ** *    **
* * **
** **    ** ** **** = 0;
***** *
 *   *        * *** *  (b[c] != '\0')
*  *** *  * *  * *  
* *  *     ****  *  ** ***      **     *  ** *** * *
   ** *** * *  ****  *  * *** * *** *    **
  *   *  **   ** *  ***
**  **
***  **   *  * * *  * Comparing frequency of    *  **
 **** **
  * * **** * ***      (c = 0; c < 26; c++)
   **     ***  
** * *** **    * *** ***   **** **    **   * (first[c] != *  *
*  * ** * * ** *  *******  *** *      ** **  * ** *  **     * ** ***  0;
 * * **  * *    *  ***
   ***
 *    * ***** * * *   **** 1;
}

int main(void)
{
    ** *   *     *   *   **** 
*    *   **  ***  ** ****  ** ****** *  *   **   * ***   ****
 **    **   *** ** ****       * *  *  * *    words or phrases are   * ***    **  
 **   ***   * ******** *** * *       * words or phrases are not     * *   

****  ** * **   * **      0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *     * ** **
#include * **      ******   
#include   **** *** ******
int is_anagrams(char A[],char B[])
{
  * **  ** * * ** *  *    * YOUR CODE HERE*/
 * **  * * ***** *   * * **  *  ** * *  * *  
* ** *** ** * *   *     ***  * *    * * *  **
   *** *  * *         ** ***
  **   **** *** *** *** *  *     **  *   **    ** * * *** *   **   * **** ***  && * ** * * *    *  
        *          *   *    * **   **  * * ***  *  **    ** * *** *   ***   * ** **   ** *  
**    **    * * * * ***** *  **  * *  *    ******   ** ****  *   *   &&  ** * * *** **    
**   *    **** * *    *  *  * *  * *  ** **   * *   *    * * **    *   ****  *  *  * *  *   
 ** * *   * *****   **** *  *
 **  *** **  * * *  ****  *    * ***  ***
   *   * * * **       * *  *** 
    *** * *  **    **   ****   *  ***  ***** *** *   * ** (cA[i]!=cB[i])
 **         ***  ** *   ****     * * **** ** *** **  **   *  ** ** ****    *** 0;
 * *    * ** * **  * *   * 
  *  *  **    **    ** *** ** 1;
* *      *   *****  * OF YOUR CODE*/
**  ** *        * *      function should return 1 if two words or phrases are anagrams,
**  ** ***  * **  *** if two words or phrases are not anagrams.
}

int main(void)
{
*** * *     * **   **** A[100],B[100];
 **  * *** *  * *    **  YOUR CODE HERE*/
***       *   ***** ** *****   **** *  *** * * *    *  * * 
 ** **  **** *       * *       *    * ***** *  *  * 
** * *    *     *  *  * * (is_anagrams(A,B))
 **  *     **** * *** ** **   *      *     *      **  * *****  words or phrases are anagrams");
**** *** *  *** **   * **
* ** ******  * *  **    * *    *  ***   **  **    ****  **  **   * words or phrases are not anagrams");
** **    *  ** * *   *  ****** * ** *  0;
*       ***  * * *  OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
 * *  * *****   ****        **  Array1[26] = {0}, Array2[26] = {0}, i = 0;
    **   ** *** ***  * * *  * 
 *  * *  *   *   ***     (A[i] != '\0')
* * **  **      * *    ****  
   *   *  **  ** * * ** *** **   * * * *   * *  ** * ** ***** *    **** **
 * * *** * *  *  * ***  * *   **** **  * *  **  ** *   ***
    ** * * *       **
*****    *  *     **   
* ** ***   ** ** **    ***** ** = 0;
********  ****     ***  *   * 
 ** ** * **** **   *****  **  (B[i] != '\0')
  *           ****** ***   *
** **   * ** *  ***  **       * ***  ******* * *   * **   * *  **
** *  **  *  ** * ** ***** * *  **** ** ********  **  *   **
 *  ****  *** ** * **   *** * 
    
**    *   * *  *  *    ** * (i = 0; i < 26; i++)
****   *          ***  
 *  *  *  * *** **  *  *** *     * * ** *   *** (Array1[i] != Array2[i])
** *   ** *   **  *** **    *   ****  ** ***   **** * *  *** * ****  **  **  * 0;
******* *   *  **   **** * * 
*    * * *  ***** *** **  *** 
 ** ** **** ****  *  *****  *** 1;
}

int main()
{
* ***** **  * * ***  **** **  A[100],B[100];

*   * *     * * ** *** **   ***   *** *  *   
  ***  **    ** * **  * ** * **** ***
     ***  *****   *** ***  
 * *** * *** * **  **  *** *** * (is_anagrams(A,B))
 *   *** ***  *** *  
 ***    *  **** ** **  * **** **  **** ****    *  **  ****  * words or phrases are anagrams");
****     **  * *  ***      **
*     *  *   ** ***  ** * ***  * printf("Two words or phrases are not anagrams");
* *  *    * *** * * *** *
   *** * ** ****** ******* **    ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * * ** * * *   *  *   ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
    *******   *  **** * *
   *    *   * ***** * *     *   (A[i] != '\0')
 *** ***  ** * ** ** * *  **
*   ** **  *    * *  ******* **  *  ****     *   ** ** **  * 
* *** ** **  ** *  * **   **      ** *     * *     **     
*****  *** ** * ***   *   * *  
 * * ***  * * *** *** *  
    * *     ***  ****  ***** = 0;
   *  *  *   ***** *    
 **** *****  **** ** * *** **   (B[i] != '\0')
***   * * *   * **   ***  *  *
*    **   **  ***  ****    *   **** ** *  ** ** * ** *** **
* *   * * * **  *     **** ** * *****      * **  * **   * * **  
  *** ** *  * * * ** * **
    
  **  *     *   ****   *** *   (i = 0; i < 26; i++)
**     * ****  **   *   *** *
*   **** * * * ***  ***  *   ***  * *  *  ** ** *    *  (Array1[i] != Array2[i])
*    *  **  *** ** **     ***  *   **    **   ** **    *  ** *  ** *** * *  * **   * **  0;
****   **    ****** * **
 *    *  ** *    ** *   
 ***  ***     **** *  * **  * * 1;
}

int main()
{
*        * **  ** *     ****  A[100],B[100];

  *  **      ** * *  * ***  ** ** ******  ** * * **  
******  *** * *    *     **     *** **   * **   ** *
**** ** *  **** *  **      * 
 *   *  **  * * ** * *  *   (is_anagrams(A,B))
   ****  ***     *   *  **  *
** *  *   ****    *** *****  * *  ***** **  **** *  * *  * ** **** words or phrases are anagrams");
 *  ** * * **** ****   *  
 *     *   *    *  *   ****     printf("Two words or phrases are not anagrams");
  *  *  ****  * **  *** 
**     **  * ***   * ***** ** * * **  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** **   *** **** 
#include ****** ****  ** ***
#include * * *  *** ** 
int is_anagrams(char A[],char B[])
{
* * * *** *   * ** * **   lenA = strlen(A),lenB = strlen(B);
*  * * *   *    ** **  *   **       != lenB)
 * **  *  *  *** ** ** ** *   **     *** ** ** * *  * **  0;

     *  *  **  *      ** * *  i,j,k,a[26] ={0},b[26] = {0};
* ** **********  *******  **   = 0 ; i < lenA ; i++)
* ** ***** * *  ** **** * *  *** 
**  *    *   * *** ** *    * ****      *   **** **  *   = 0 ; j < 26 ; j++)
  ****  * ***  *** ******  **   *  *    *  ** *  **** **    
 **   ******  ******   * *  * ***  *****   **  *** * * *   **  ** * * ***   * == A[i] || 'A'+j == A[i])
* ** ****  * ** *  * **   ***     ** **        *  * *   ** * * *   **  * *** ** *  * *** * *          * **** *
 * ****** ** * *****     **   ** ** * ******  ***   **   
* * * * **   *       * *** **
*  * *****  * *  * ** ** *    ** = 0 ; i < lenB ; i++)
****  ** ****    *     **
 *  *      *  *    *   ***   * *  * **** * *       * * = 0 ; j < 26 ; j++)
*  * **   *     ******   * ***** **** ** * * **  *
 *       * *  *  * **** * ** **  * ***   * * ***** * *** **  **** ** * ** * *****    == B[i] || 'A'+j == B[i])
  *** *  * *   *  * * ****** *   *  * *     * *** ****** ****  * *  ** * **** * ****  **    ***  ** *** *
** * **    **** ***    * *   ****  *    *** **  *** *** ** *
 ** * * *   * ***  *** ** *
      *   * **   * ***** ****      **    = 0 ; j < 26 ; j++)
*  *  *   *****   **   
* ** *  *  *   ***** ****  *****   *    * **    ****   *  *    * != b[j])
*  *     * ****** * *  ***   ****     * *     * **  *** *** * *   *** *   *   * * 0;
*  *** **  ****   *  *    * **
* *  *     *  *** ******** * *  1;

}

int main(void)
{
*   **   ** *    * *  A[100],B[100];
**  *****  *   **** *** *** *** %s",A,B);

 ***** * * *** * **   (is_anagrams(A,B))  ***      **   * words or phrases are anagrams");
*     *** **   *     ***  ** printf("Two words or phrases are not    *    *  *

* * ** *    *****   *** *** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ** ** ***  ** **
#include *** ** *** * ** 
#include  *  * **    * 
int is_anagrams(char A[],char B[])
{
*** *** * **  *    * * * lenA = strlen(A),lenB = strlen(B),i,j,k;
   *   *** * ** *****  *   *  a = 0,b = 0;
****     **    ****** **** *** != lenB)
**   ** *  *  ** * **  * * * *  *** ** *  **   **** * * ** *  *  0;
 ******  * *      ***  ******  = 0 ; k < 26 ; k++)
  * **    *  *   * *******
***   *    *******    *   * ** *   ** **      *** *    = 0 ; i < lenA ; i++)
 *    *    ***** * ** ** * ** ** **   *  **  * * ** *  *  * *
   * ***  **   **   ** ** ***  *    * * **      * *  *  **** * * *      ******** **  ** ** ** == A[i] || 'A'+k == A[i])
*  * *****   ***  ****      ** **  **  ** *  * ** * **      * **  ** ***  *  * *  * **  * *    *   **** 
 *   * *  ** * **  * **** ***** ****   **      
 **** * ***   *   ***  * * * *   **    ***** * * ** *  * = 0 ; i < lenB ; i++)
 *    *  * * *  **** *    **   ***   *  *     *******
** * **   *  *   **** * *** * *  **  * **** *    * **   **  **  * ** ** *   *  *** *   == B[i] || 'A'+k == B[i])
* * *    ***  * *   *  **  ** * **    * * ***  ******** *  *     **** **  ** *  * **  ** *****  **   ***    * ** 
 *  ** ** *****  **  * *****  *  *   *    **  *****  ***
**   ***  ***  ***   * ***     * * ****  ** * *  *  ****  ** ** != b)
     *   * * *   ***  *   **** ** **  *    ***    **  *  ***** * **** **   * ** 0;
* **  *  *        *      ****** * * ****
* **  *  ** * *** ***  ****  **** *   *  *   **     * ** *      *    * * * **    * *   *  *  1;
}

int main(void)
{
* * *** **** *** *  ** A[100],B[100];
 *   **** *** ** * *** * **** * 
*  ** *** ** *  *   *    *******
     *  *    *  ****  ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** ***    ** *   *  printf("Two words or phrases are not anagrams");

   *  ***  **   ** **  0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    ** ***   * ** *
#include ***    **** *  *   
#include    * * ***** **
int is_anagrams(char A[],char B[])
{
   **   * *  *** ****  ** YOUR CODE HERE*/
  *  ***** * *    ** ** *** i,count[256]={0};
 * *****   ** *** ** ** ********   
  *  *****  ****  * * **   
   * * *     * * ****  ** ****   **   *  *  ** * *  *** * *   *    **   *     * ********     **
******* *  *  * ** *** **  
* *  ***    *  ***** * * * *  **   ** *
** * **   ***  * *** *  *     
** **   **    *  ***  *********  *  ***  *** *  ****   *   ******   *        ***  **   
     * * ** ** ** *** *****
/*
 *  **** * ** * * **  *  *  * * * (A[i]!=0 || B[i]!=0){
    *   *******  *   ** ** *** ******  *  ****  * ********    **    **  *** 
  * *    **** ***** **  *  **     **   *** * ** *        0;
 *   * * *   *** ** ***   ** ** 
*/ * *  ***   * * ****  ** ** *** ** ***** 0;

   *** *  *  ** * *  ** *  **  * * * (i = 0; i <256 ; i++)
****  ** *** ****  * * **      **  *  *  ******  (count[i] && i!=' '){
 *  *** **   ** ** * **   **   * ** **  * ****** * ***  *** *     * * **** *   * **  *  *    * ** **   *   *
** * * * * * *     *** * *** **  * **  *****  * ** * ******* *  **  **  **    *** **** 0;
* ** *    ******** *    *   **  ** **   **    ***    * * *  *


  ** *  *   * * * * **   ***  * 1;

 * *  *         *  **   OF YOUR CODE*/
**    * * *   *  *****  *  function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
 *** ****   * *   *  **  * A[100],B[100];
*  ******   *  * * ***      YOUR CODE HERE*/

   ******  * *  * *  ***** *  *** *****   
  * ** *   *  **** **   * * **   ** * *  *

 *    * ***    *** * *   **         *** = '\0';
  //   **   ** ****  *  = '\0';
****  *** * *  * * *  * *** i;
* * *      * * ****  * * ***  *   * ***   ** ***   *
   *    *  *** *  **    * ** * **   *      * *** * **** *  *     *  **  * * ***  * ** ***
  **     ** **  *  ******  ***  *  *  * * *    **   *  * ** ** ***  
   *** * **  *  * **  *   *  * *** *  ** *   
 **     *   ***  *   ** ** **** *   **   **  *  *** * **     ** ***** ** **  ***  **   *
*  ****     ** ***   *  **    **  ***   *** *  *  *   **   * 

    *   * *      ******   * OF YOUR CODE*/
  ** *** **  *    *****  (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
 *      **   ** *  *  ** printf("Two words or phrases are not anagrams");

** *****  *****   *** * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  * *    ** * 
#include    ** * * ** *   *
#include **** *   *  **
int   * **    A[],char B[])
{
**   *** * ***** *** *  YOUR CODE HERE*/
* ***** ***   *      *     * *  * * * * 
 **  **  * **   *** *   ***  **    ** *   * *  ***   
       ** *  * * **  *  *  *
 ** **** * *  **  *      ** *  * * **   ***   * * **** * **   *****
 * ***  *  *  **   * ***   **  **** *  * *  ****  * *  * 
 *  **   **     *  * * ****
* ****** * *** ** ***  ***  (A[i] || B[i])
 * *    ** **   *      **       * **    ** *  0;

 **  *   **     *  * *   * *** (i = 0; i < 256; i++)
  * ** * *  ** *** ** * ***** ***** *   *****  *   *   
**** * *** ** ***  * * ** ** ** *  ** ** ******      * ******* *** ** *  * * *** *  0;
 * *     **  ***   *** *  **   1;

** ***   * *  *** * ** * OF YOUR CODE*/
  *****    * ** *  ** ***  function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *  * *
{
  ****    * **** ***      *** * * 
* * ***          *     *** YOUR CODE HERE*/
* * **  **** * * ** *** * * *  * **   *  * * ********* 
   * * **   ** *    ** **  ***   **  * **** **    ***   * **

* ******** * ** * ** OF YOUR CODE*/
   ***   ** *     *  **    ** * * *** *  *  ***  words or phrases are  *    * **  
  **  * * ** * *     *  ** * *  **** *  words or phrases are not    *  **    ** 

 *   ***    *   ***  * * **  0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *  **  * * 
#include * **     *   * **
#include    * *** *  **   *
int **  ** ** A[],char B[])
{
     *    * *   *  *** * *    YOUR CODE HERE*/
  *  **    *  *   * *     ***   **   ** *
*  *   * ***  ** *****     ***   * *** *   **  ***
*** *  *     * ** **** ** *
  **  * *  * *  **  ***  *   *   *  * *  ** * *    ** * **   
*   *  **  *  *****   ** *  **  ****   * *     ** * *  **** * 
* *     **  *  *** * **** *
  * *   *  ** * * * * * *  *  (A[i] || B[i])
****  * *** *    ****** * ***  * ** *  ** 0;

* * ** *  ** * *  *  * **   (i = 0; i < 256; i++)
*  * *   * **    **** *  *   * *  ** * *   ***** * * *** *  *   *
* ***       *  *   ** **  *** *** * *  *  *  **   * **   *   **    * ** *   0;
*** *    *  *** *   *  *     **  * 1;

** *  ** ***      * **** OF YOUR CODE*/
* *   * *  *** ****   *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int     * * 
{
****  **   **  *** * *  ** *      *
 ***  ****** **  * ***** *  YOUR CODE HERE*/
* * *  * * ******    * *    *  * **   ** * ** * *   ***   
 **  **** *** ***   ** **    *** ****    *  * * *****

  *** *  * *  *  **   * OF YOUR CODE*/
  **    ** *** **  * *  *   *   ** *    ** * *  words or phrases are  ***  ** * *  
**** ** *   ** ** *  * ***** *    * words or phrases are not *  * ** ***

**  * *  *  ****  ** *  0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.139
©2016-2025

Related questions

0 like 0 dislike
47 answers
12-07 Exercise 3: Function to delete an element from an array
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 5.9k views
0 like 0 dislike
45 answers
12-07 Exercise 2: Function num_digits
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 6.3k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 5.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users