12-28 Exercise 3: Anagrams function

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Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
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prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
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}
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prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
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prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
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#include <stdio.h>

int is_anagrams(char A[],char B[])
{
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}
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#include <stdio.h>

int is_anagrams(char A[],char B[])
{
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#include *  ** ****   *** **
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}
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prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
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Hidden content!
#include   ** ** * **** 
#include **  * * *   * 
#include **     ** **  * 
int is_anagrams(char A[],char B[])
{
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}
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#include * ** **  * ***
#include  ****   ****** 
#include *** *  * * **** **
int is_anagrams(char A[],char B[])
{
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}

int main(void)
{
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** **  *   ****    * **** printf("Two words or phrases are not anagrams");

 ** ** *    *  **        0;
}
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Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
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Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
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Hidden content!
#include    ***     *  *
#include   ***   **** ***
#include *** *  *********
int   **    * *  A[],char B[])
{
  *   * **     ******  *  ****  YOUR CODE HERE*/
*   *   * ***  *  ***** *  ***   **    **  
* **  **   *** ** * ***  ** ***** ****   ** * ** * 
     **** * * **** * ***   
* ** *  ****  *** ***    ****      * ****  *** ** *  **    * *  **** 
    *    *  **    * *    * *** *  ** **   *  **** *     **   *
 **          *****  *    *   
   ***** ** *   *      *  (A[i] || B[i])
  ** **   *** * * ***  * ***  *  * *** ** 0;

** *** *  ****  ****  **** (i = 0; i < 256; i++)
** **   * *  ********  *  * ** ******  *  *   * *  *   *  **
      *  *     ******** *   *       * *    **  *****     * *    **   ** *    ** * ****  0;
***   *  * *     **  **  **  1;

*  * *******  **  *** **  OF YOUR CODE*/
* *  ***  ** **      function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * ****
{
* * *** *   **   *  **  **    ** * *
*  * *  * **   *** *     YOUR CODE HERE*/
***** ***   * ***  ***    *** ** *  ***  *  **  **  *** *  *   
*     **  **** *  * * *  *    ***** *** * **** *     **

    * *   * *   ***  ** ** OF YOUR CODE*/
*    *     ** * **  **   * * *    **        words or phrases are     ****** * *
 *   * ***  *  * **  ***     *  **  ***   * words or phrases are not  * * *   ** ***

*** *     * **  *       0;
}
answered by (-196 points)
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prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
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Hidden content!
#include ******* **  ***
#include *****   **   
#include  ** *  *   * 
int * **     ** A[],char B[])
{
    *   ** ***   * *  YOUR CODE HERE*/
   *    * *  *     * **  *  **    
 *  * *  **  ** * *****  * **   * **  * *** *  **  *****  *** 
***** *** ** *  ***** ****
 * *   *** * * * *  *   ***   * **   **** ** *   **   *** * * * 
 **    *   ** *   *  ***** * ** * ***  *  **   *** * *     ***
*** * ****  *  *  *  *** *  
* ***   *  *** **       * * (A[i] || B[i])
**   *    **  *****   **  **  * *  *********  *  0;

 * **  *  **       * *****  (i = 0; i < 256; i++)
   * * * **  ** * ****   **    **   ** ****   ** * *   *    *
*  **  **  *     * **     **   *     *   * **   *    *   *  **  ***   * **        * *  * * * **** 0;
 *****  *   ***  * ** * * *** 1;

*  * ****   ******  * OF YOUR CODE*/
   *    ***      *  *    *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int     *
{
    * *  ***  ** ** *** *    *  *
* ***   * * *  ***  YOUR CODE HERE*/
* *** **** * ***  ***     ***  * * *    ** * *  * * * *
** **  * * **** * *     * *** *  * ** *  **    ****  **

  * * *   *   *  *     *** OF YOUR CODE*/
**    **   *  ***  * ****   *  ***** *        ** *    words or phrases are    **  ***  *  
* *  *   ***    *  ***  **  **** **  * *  *  words or phrases are not *  *  *  * 

*     ****  * ***  **  *  * 0;
}
answered by (-196 points)
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prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
commented by (4.3k points)
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