12-28 Exercise 3: Anagrams function

0 like 0 dislike
21.4k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited | 21.4k views
0 0
STRUPES!
commented by (323 points)

79 Answers

0 like 0 dislike 
Hidden content!
#include ****** **  * * * ** 
#include ****  **   *  * *
#include   ** * *  *** 
int * ** * *      a[],char b[])
{
 *  *  *  **    ** **  first[26] = {0}, second[26] = {0}, c = 0;
*****  
  ** **      ***  *  *   * **** frequency of    in first string
 * **
* * **** *** *** ** *** **   (a[c] != '\0')
* *  ****   *  *   *** **
  *** *   ** **        ** * *   *     *****   ***   *     ** **
***  *  **  ***       *   ** * **** *  * ***
** ******    *** *
*  ***
**** **  * **   ** **    * = 0;
  *
 ****   ****  * *  *** *   (b[c] != '\0')
 ***  * *     ** ****
   ** **   *** * ** *  * *** *  *  *  *  **   * ** 
 * *   *  * * * *    * * * * ****    *****      
*   *     **   **   *    
 ***   
 *  *  * *** **   *  *  * Comparing frequency of * *****
* *  **
  **** *** **   (c = 0; c < 26; c++)
* **     ** *  * ***
 **** *** *******  ** **  ** *    * (first[c] != second[c])
**  ** * ** *  * *****   *  **   **** *  *  * *  **** * *  **** * ******** *  0;
* *  *   *   * * ***
* **  *  
  * ****         * **  1;
}

int ** *   
{
** *  *****  * * *  *** **  
  * * * * ****** *   **  ***  * *   ********* *** A,B);
** *  ** ****** * * * *     ****  * * * ** ** ** ** words or phrases are * **  ** *  * ** *
*  *  **    **   ** ***   * ***  * *    *  words or phrases are not ** *    *** *  

 * ** * ***   *    *  **   0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***** **** **  ***
#include ****** ** * *  
#include ******* ****** 
int  ** *  ***  a[],char b[])
{
 * ** **       **      *  first[26] = {0}, second[26] = {0}, c = 0;
   * **
 **  ** ****** * *****  **     frequency of characters in first string
*  *** ***
*** * ** ***   ***** * (a[c] != '\0')
**   *   * ****  * 
  *******  *** ** * ** ** * * *    * *** ****   **  **
 ***  **  *  ***   ** *  * *    **** * * 
*******  ***  * *   *   
 ***** 
 *** * *  ** *  *** *  * * = 0;
  *  
*  * *    ***  * *** *   (b[c] != '\0')
   *** ** * ********* 
 * * ** * * ** *** *  ******     * **** **    **   * *  *
   * ** * *     ***   ** * ****** **   *  ***
* **   * * ** ** *
  * 
  **  * **  *  *   *   Comparing frequency of ** *   
 * *    
**  **     * *    ** *** (c = 0; c < 26; c++)
** ** *  **  ***  *
** *** *   ** *   *   **     * *******  ** (first[c] != * * ** 
*   ** * ***   * ** ******* ***  ****    *  **********  *  **** 0;
* *   **  * ** *    *
* *  **  
* *   *** ***   * *** *** *  1;
}

int main(void)
{
 ** ** *****  *  *  * * *  ** *  *
 * *  *    **  **   *  **   * * **  *     * *   * *     *  *
 * **** ***  ***  **    *** **     ***   ** **  words or phrases are *******    ** * 
 **        *  *   *    ** ** * *  *****   *** words or phrases are not   ** *** ** *

** *      ** **   **  *  0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ****  * ** ** **
#include ***  **** ****  
#include *   * **** ****
int is_anagrams(char A[],char B[])
{
 ***  **  *  *  **** ** *  *  * YOUR CODE HERE*/
   ******  **  * * **  **   * ********** ** ** * 
**  * **    ** *  *  * *** **   *** * *      *****
*   *   *   **** ** * * *  *
 * ***  * *            **  * ** **   *  * *****    ****    **   * *   * ***   **   && *    ** *** **  * *
* *  * ***  * *** * *   ** *** ** ** *  *     ** ** * ***** **  **  *****  *** * *** ****** *      **
 *    ***  ** *  * ******    ** *        *     **  *    **  * *** *** * && *****  ***  *  *  *  
 * *** ***    ** * *    *  *   *** ******       * *  *    * ***** **** ** ** ** * *  **  ***  *  
 * * ** **     *   *    ** *
* * **  ***  *  ** *   *  **    * * ***   **  ** *  
 * *    * *    ** *  ** 
 *  *       **  ******   ***     *  *  ***   ***   (cA[i]!=cB[i])
 **     * *   ** *   *** * *  *  *  *     *  ******   *** * *  *  * ***** * **        0;
    ** ** *   ** * ***  ***   *
    **  **  ** **  *    * ***  * *  1;
 * *    *  ***  ***** *  * OF YOUR CODE*/
    ***   * * *  * *** function should return 1 if two words or phrases are anagrams,
*** ******  *      * if two words or phrases are not anagrams.
}

int main(void)
{
*   * ****   *  *** *    A[100],B[100];
* *****  * ***   *** *  **  YOUR CODE HERE*/
*      ***     * ** * ***   *  * * *   ***  ***********   
 * *  * **  ****** * ***  *** *  *  *  *  *     * 
***** *** *  * **   * *****   (is_anagrams(A,B))
 *  * *  * * ****    *  **** * ** * *   * *    * *     ** ** **  * *** **  words or phrases are anagrams");
    *         **   *  **** 
 *******    * *    *   *** *  ****  * ** ***   **** *  ** ** ******  words or phrases are not anagrams");
** * *** ***** ** **  * * *    0;
* * * *  ****  ***** *  OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
 * ***** **  * *   **** *  Array1[26] = {0}, Array2[26] = {0}, i = 0;
****  *****  **    * 
** * **  ** *    ***   * ***      (A[i] != '\0')
 * *  *** **  * *  *   **    
 * * ** *** *  * **    *  ***  *       ***     ** * * *  * * 
**   *    * **  ** *   ***   ** ***** * ****   ****  * *** *
*****  * *  **  ***  ****  *
** ****   ****  ** * *   *** ***  
 ***    *  ********** *  * * = 0;
 ** *  *  * * *** **  * *** 
  ***  **   *    **   **** * * *   *   (B[i] != '\0')
 **** *** *** *****      
     * *** ***** *****  * ** **  * * ***        **  ** ****  **   **  
 **   * *  *     * *  **   *****    ***** *  *****  
* **     ** * * ** ** ** *** 
    
  *   *   * ***     *   * (i = 0; i < 26; i++)
 *  *   * *** * **  *   * *
    **  **  ****** *      ** *   ****   ******  *  ** (Array1[i] != Array2[i])
* ***    ******* * ***    ** ** ** ****  ** * * ** * *      ** *  * ***  * *  **** 0;
  ** * *****   ** * * *     
 * *    ** *  * * **  **    
  * * **  **   * * * *  ** *    **  1;
}

int main()
{
*  **   *   **   * *  *  **   A[100],B[100];

** * **** ****   ****  * * ** *  * * 
***       ***  * * *  **      ****
  ** *** **    ** *    *    
 ** *  *   * * * * *  *  ** ***** (is_anagrams(A,B))
***   *   *  ** * * **   *
*  * *   * * * * **** * *   **  * **   * ** *  **   * * ** ** *  * words or phrases are anagrams");
* ***  **  *   * * 
**   *    **  ** * *  ** *    * * * printf("Two words or phrases are not anagrams");
*  **  **** ***  ***      *
***  * **** * ***    * * *       * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
***   ** *   ****   ** * ****   Array1[26] = {0}, Array2[26] = {0}, i = 0;
* **      **  ** ***** * **
* *  *  *** *** *   * * **    (A[i] != '\0')
***** *** ******** *** *    
* ***      * **    ***    *  ** **       *** ** * *  ******  **    *****
  **  * * *  *   **  ***  **      *  * *     ***  * * * 
* *        * *** * **  ** **  *
*****  ***    *      * ** ****  * 
* * **  *   * ***** * *** *   = 0;
   *   **** *  ** ** **** ** 
 *  ** ***    * *** *    * * **  (B[i] != '\0')
 **   * *** **  *****    *
 *   ** ***   ** *  * **   ** * *******    * * ****  *   ***   
** * ***    *     * ** * ****  ***  *     *  **  ****    
** ***  *   *** *       * ** 
    
    **    *********   ****  (i = 0; i < 26; i++)
  ****   ****   *   *  **** *  
 * *** **   * ****  ***   *  * *  ****  * ***  **     *  * (Array1[i] != Array2[i])
*  *   *  * * * * * *    **** **    *  **  ****  ** **   **  *  * *  *  ** ****  0;
* ** *  * **  **** *   **  
 *   **** * ** * ***   ***  ***
  ** ** * *   *   *****   **  *  1;
}

int main()
{
* *   *     * **** **    ** A[100],B[100];

  *   *       ****  ****   *  *    * ** *    * *   ***
**  *** *  *  * *****  **** *** *   * * **** ****   * *
 ****** ** * * *** * *   **  
  *  * *** * *** *** *  ** *** (is_anagrams(A,B))
* *** ** * *  * *****     **   *
* *  *  ******* *****    ** *  *** **  ******   **** ** * *  * ***   ** words or phrases are anagrams");
** **  *   ** * *  ** *   ***  
  * *** ** ****  *** ***** ** printf("Two words or phrases are not anagrams");
   ***   * * *   * *  ***   **
  *     ***** ** ***   **   0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  ** *  **  
#include    **   * * * * 
#include ***  *  **   *  *
int is_anagrams(char A[],char B[])
{
* ** ******  ** *  *  ****   lenA = strlen(A),lenB = strlen(B);
 *  * *   **  **   *  * * * **  != lenB)
 *  *  ****    **  * *  * * ** * **  **  * ** *  * * * * ** 0;

 * *   ** *  *   * *  ** ** *  ***   i,j,k,a[26] ={0},b[26] = {0};
******* * *****       * ***** = 0 ; i < lenA ; i++)
** *   ** * *  ****  * *   *
** *** ***  *   * *   ***   **** **  ****   *       **  = 0 ; j < 26 ; j++)
***  *      *  *****   *   *** ****    *  *  ***    * *
   * ** *  ** ** **** * * ***   *** *  * *** ** ******* *  * **** **  *   **** *   * *  *** == A[i] || 'A'+j == A[i])
** * * ** ** *  **** ** ** **  * ** ***   ** ***** ***** *       *  *  *    *****     *  * *  **  *** ****** *     
* *  ** *     ** *  * * ** ** *****  ****     ** *  **   *
  *  * ** **  * *  * * * 
 ***  *   *  *  *   *** ****  = 0 ; i < lenB ; i++)
 *   **    * **    * ***    ****
*  *  **   * **  *** ** *    ******       * *  *   *    = 0 ; j < 26 ; j++)
    *  *** * * * ***   * * *  *** ** *****  *  * **   * ***
 *  * * *  *   *** * *** *  *** * *  * **** **      * **  * *  ** *** *   **   * * *** * ***   == B[i] || 'A'+j == B[i])
**  * *  *** ** *    *  *  * *****      ****** ** ** *** ** ***** * * ***  **** ***  *      * ** ******  **  
  **    ******* ****  ***  * ** *******  ** *  * **  **   **
*   * ***   *  *  ** **     *  
*  *** *** ***   ***      ****  = 0 ; j < 26 ; j++)
 * *** * ***        * *  **
  * *    *  *      *****   * * *  * * *  *  ** **    * **   *** != b[j])
**   ****   * ****    *    **    *      * ** *** ** * ** ** ***   ** *   *** *** *  0;
  *  ***  * * * ********  
 ***  * ***  * ***  **  ***   1;

}

int main(void)
{
  ***  * **  *   * *  A[100],B[100];
 ** *** *  *  *   *  **   ** *  %s",A,B);

   ****  ** *     ** * (is_anagrams(A,B)) **  ** *  * ** words or phrases are anagrams");
*** **    *  *     * *     printf("Two words or phrases are not  * * *     **

 *  *** *  *** **** **   0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    **  ** **** 
#include * *   ** ***** ****
#include  *  * *       
int is_anagrams(char A[],char B[])
{
 *  * * * ** *** ** ***** *   lenA = strlen(A),lenB = strlen(B),i,j,k;
* ** ** *       ** * * **** * a = 0,b = 0;
* ****   * *  *    **      **  *** != lenB)
***   * * **   ** ***  *** *  ***** * ** ***  * *    **** 0;
* * **** ***  *   *  *** * = 0 ; k < 26 ; k++)
* **  * * ** * * * *  *** * 
* ** *   * ****    **** * ***** *** *******   *  *  * **   **  * * = 0 ; i < lenA ; i++)
   ***  ** **** ********  *  *  * *  * *****    *  * * * **
***** ** ** ** ***  * ***  ****  *    ***  **   ***  *   **   *** *      **        == A[i] || 'A'+k == A[i])
 * *** *      * ****       *  **    *  **      *  ***** *   * *  **** ****  *** *** **** *  * * ***      ** ***  ***
**  **     **  **  **  *   **** *    ******* *
 *    ** **  *  * * ** * *** * **    **** * *  **** *  ******  * = 0 ; i < lenB ; i++)
* ** ** **********   * *******   ****  *   *  *   *******
  ***  *** **** *** **  ** **             *        * *   *** **  ***      **  *    **  == B[i] || 'A'+k == B[i])
   * *    ** * *** **   *****  *   *    * ***  **   ** *     ** *      *  * *** ** * *   * * ** ***** **  *  *  *
 ***     *     ****  *** *   ********* ** ** * * *** *
 * ** * *  **  *   * ***   ****      *  * *    ** **** != b)
 *** ***  * *  * *  * ** *    *  *** *   **  *   ***    **  ** *  * *    *  * **  * ****  0;
** *** ***    *    ** *    ****
*   *      **   *  ***** * * * **    *  *  ***** *** * *** *    ***  ** **        *  *  1;
}

int main(void)
{
*  ** *  *  ***  **   A[100],B[100];
****  ** *   *  *  * *  * * *****
**    ** ****** **  * ******  * *
*  *  **** ***  ** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
 ****     **  *  * *  *  printf("Two words or phrases are not anagrams");

 *      **          *   0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * **  * *****
#include       *** *  *
#include ****   *** *
int is_anagrams(char A[],char B[])
{
  ** * * *         *   YOUR CODE HERE*/
* ***    *   ** * *****  * *** * i,count[256]={0};
   *****  ** ******* **  * *  **   * * *   
  * **** **  *  * *     * ***   
* *   *****  **** ****    ******** *** *  *   *  * ***  * * *** * * ** * *  * **   **  **  **** **** *
*  * * * *   * ***** * ****** 
     *  *** **** * *  * * **  * ***** ** **
     *  * *  *   * **   ** **
     * *  *  *** ** * * ** ** *   * *   * ****   *  **  * ***  *** *    * ** ***   *  **       *
  *   * * ** * *  * * 
/*
*  **      *   *******  *  **  (A[i]!=0 || B[i]!=0){
 *  ** ****  * *    **   * *  * * *  * *   ***  ** *  **  *     ***    **  *    *  *
* ******* *   *    **  *** **  *    **  **  ** **  *   *   0;
* * * * ****  * *  *  *     ***
*/   *  * ***** *           **   **   *   * 0;

   ***  *  **   ***   **  *** (i = 0; i <256 ; i++)
*** *    ***   *   **** *   ** *** *  ***** ** ***  (count[i] && i!=' '){
 * *** *   * ****    *  * ***   ** * * *  **  * **   *   * *   ** * **   ** *  *    * ** **  *       *** **    
  ***   ** *   **  **       *  * ** * * * * **  ** ** *    * *  * **  * *** *  *        0;
** *   ******    *      *   ****  *****       ****  *


* ***    ******   *   * ** *  *** 1;

* * *  *** *** **  *  *** OF YOUR CODE*/
 **   *    *  * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
  ** **** * *** *  *    A[100],B[100];
*** **  *  **** *    ** *  YOUR CODE HERE*/

 * **   ** *** *  ** *  **  **    **
*** * **  * **  *** ****** *  * * * **

*** ***   ** *   * **    *** = '\0';
  // **   * *    *  * = '\0';
  * **   **    * **  ** *  *  * i;
 * ***   * * *  ** * ** * *   *****
   **** * ** ** ** *****     ***  * ** * *  *   * *   *** *  ** *  *  **** *  ***  ***** **
** *** * ** *  ** *  * ** **  * ***  *  * ** *** *   *  *
 **  ** * **  *  * *   ****    *    *  * 
*  ** *    **   *  *   *** * *  * **    *  * * *  ** * ****  ******   ** * * ** **** * *  **   *  **
*  * ** *    ** ********* *** **       **   **    ** *  *  

   *   * *** *  *** ***    OF YOUR CODE*/
 ***    *   *** **  ****  (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*    *  *****  ** ****    * printf("Two words or phrases are not anagrams");

  *    * *  **  * *** * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **** *  **  * 
#include ****  * *   * *
#include   * **   **  
int **   *    * A[],char B[])
{
 ******* * *  *  *  ** * YOUR CODE HERE*/
* * **  *   *  **** ******    *  **  * *  **
 ** * **   *** ***  ** ** * *   ** *  *  * * **
* ***  *   *  ** *** *  *
  *   *  * * *  *   ** **  **   ** ****   *** **  ***    ****     
 *  **    ** **   ** *   ******   *   ***** * *  ** * ** ***  *  *
 ****   * * *   *    ** *    *
*  * *  *  * **   *** * ** (A[i] || B[i])
* * * * *** *  ****    ** *   *** **     * 0;

** *  * *** *  ***  **    * (i = 0; i < 256; i++)
 ***      *  **   ** ** ** * *  ** **** ****  ** ** *  * ** * 
* *   **  *   *  *** *       *** * *  **   *          **    *  * * ***   ** ***      ** 0;
** * *   * * *  **     * * **  **  1;

 * *** ***    ***** ** ** OF YOUR CODE*/
    **  ** *  * * * * *   function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int   ***
{
*  *   *       ** *      ** 
* ** ***  * *  *****    * YOUR CODE HERE*/
*        *** * **** * **  *  ***    *    *   *  ** 
  *   **   * *** *  ** *   *   *   ******** ****  *** *    **

*** * ****  *    *  ** *     OF YOUR CODE*/
**** **   *******  *  **   * ** *   **  ***   ** words or phrases are *   ** ** *
     *** *  ***  ** *  * *  **      **** words or phrases are not ***  * * **   *

   *** * ** * * * **     0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ****  *  * * *  
#include **  **  ** * **
#include   *   ****** 
int  ** ** *   * A[],char B[])
{
*  *  *   * **** *     ****  YOUR CODE HERE*/
  **  *** *****    ***   *   ******
 * *   *  * ****  *     **     **  ***   ***      *
 * ******    * * *** ***** 
* *   ***  **   **    *      * **** *   * *   * *   *  ** *  
 **   ** ** *** * ***    ***  * * ** ** ** **    * *   **  *
 * **   * ***    * **   * **  
**  **  *  ** * ***  ** * (A[i] || B[i])
    ***  ** **  *** * *  ****** **** * ** 0;

  **   *       ***  **  *  *  **  (i = 0; i < 256; i++)
        * * *  **      *  ** *           **   *** ** *  
* *  *   **     *** *   * * ****** ** *  ** ** *   *  *****   *   * ***  *****   * * 0;
*    *** ** * * *   *   *  ** 1;

**  *   **   **      *  OF YOUR CODE*/
*  * **  *** ** * **  function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int  * * **
{
 ** * * *   * * * *  ** *    *    ***
 *    *  ** *  * * **  *  *   YOUR CODE HERE*/
 *** * ***  *   * ** * **  *** *** ** **  ** **       
** * **     **** *** ***  **** *       *   ** ** * ** 

*****  * **   * *    *  OF YOUR CODE*/
*** ***  ** ** **         **  *    * **** * *   words or phrases are * ****  * ***   
 *  * *   **   * * * ***  ****** *****     words or phrases are not *    **   ** 

 *  *  ***  * *     *  0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
47 answers
12-07 Exercise 3: Function to delete an element from an array
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 11.1k views
0 like 0 dislike
45 answers
12-07 Exercise 2: Function num_digits
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 10.6k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 9.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users