0 like 0 dislike
22.8k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 22.8k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * * *
#include ** ** **
#include *** * * ** *
int ***** ** a[],char b[])
{
* * * * *** ** ** first[26] = {0}, second[26] = {0}, c = 0;
* * *
* * * *** * * ** ****** frequency of ***** in first string
* *
**** * ** * ** (a[c] != '\0')
* ***** * ** * **
*** * *** * *** ** * **** * ** *** ** **
* ** * * * ***** *** * ****
**** *** * * *
****
* * * * * ** * * **** = 0;
* ****
* * ******** ** (b[c] != '\0')
* * ** **** ****
** ** * ** * * ** * ** * **** ** * ** * ** * *****
** * ** ** ** *** ** *** *******
* ******* * ******
*** **
* * ** *** * ** Comparing frequency of ** **
** **
** * *** * * (c = 0; c < 26; c++)
* ** * * * ** ** ** *
* ** *** * * ** ** ** * (first[c] != second[c])
* *** *** *** **** ** * * ** ** * * * ** *** * * 0;
* ** * * ** * **
*******
* * ** ** ** * 1;
}

int ****
{
* ** ** ** * * ***
* * *** * * ***** *** ** * * ** A,B);
* **** ** ** ******* **** * ** ** words or phrases are * ** ***
** * * ** *** ** * ***** ** words or phrases are not * ** * **

*** **** * ** *** * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * *
#include ** * ** * *
#include * *
int *** * * a[],char b[])
{
* * ** *** ***** * first[26] = {0}, second[26] = {0}, c = 0;
* *
* * *** ** *** ** * * * * frequency of characters in first string
*******
* ** * ** ** ** **** ** (a[c] != '\0')
* *** ** * * * *
** * **** ** * ** ****** *** *** *
*** ** * * * ** * ** ** * ** *
* * * *
***
* * * ** * ** * * * = 0;
******
** **** * * * * * (b[c] != '\0')
********** ** ***
*** * ** **** * ** * * ******* * * *
* *** * * ******* * * * * ** ***
** * **** ** * ** **
*
**** *** ** **** ** Comparing frequency of *** ***
* **
*** ** * **** * * (c = 0; c < 26; c++)
* ** ** * *
**** ***** ** * ** * * * **** * (first[c] != * *
** * ** * * * **** ***** * *** * *** * ** ****** *** ** * 0;
** * ****** *****
*** *
* **** *** **** ** * 1;
}

int main(void)
{
** *** * * * * *** * *
*** * ** * ** *** ** ** * **** *
* * *** ** * * *** ** **** * *** * *** *** * ** words or phrases are * ** ***
*** * **** * ** ** words or phrases are not ** **** *

* *** * *** * ** * *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * ** **
#include * * ** * *** *
#include * * *** ** *
int is_anagrams(char A[],char B[])
{
**** * * * * * YOUR CODE HERE*/
*** ** * * *** *** *** * ** *********
** ** ** ** * *** *** * * *
* * * *** *** ** ***
*** * *** * ** * * ** * * * *** * *** * * * ** ******* && * * *** ** **
* ** **** * *** ***** ****** ** * ** * ** *** * *** ** **** * ** * *** ******
***** * **** * ** ** * * * ** ** **** *** * * * && ** * * ** *
*** **** ** * ** * * * ** ***** * ***** ** *** ** **** * *** ******* *
*** ** * * * **** ****
* *** ** **** *** ** *** ** * **
**** * * * * ** * * *
***** * ** * * *** ****** * * * * * (cA[i]!=cB[i])
* * ** * *** ***** *** * ** * * * ** ** ** * * * * * 0;
* * ** **** * * ** * **
* **** * * *** ** **** * 1;
** ****** ** *** OF YOUR CODE*/
* ****** * ** * * function should return 1 if two words or phrases are anagrams,
**** ** * * ** ******* if two words or phrases are not anagrams.
}

int main(void)
{
* **** ** * * * * ** ** A[100],B[100];
* ** ***** ***** ** * ** YOUR CODE HERE*/
* ** ** * *** ** * ** * * * ** * * ***
* * * * **** ** ** ***** * ** ** * ** * * * **
* **** * * ********* (is_anagrams(A,B))
* ** ** * *** * *** * ** * * ** ** * * *** **** words or phrases are anagrams");
**** **** *** ** * * * * * **
* *** * *** *** * * ****** * ****** * *** * ******* ** ** * words or phrases are not anagrams");
**** ** **** **** ** *** 0;
* ** * **** *** * ** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** * *** ******** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * ***** * * *** **
** *** * * * * * ** ** (A[i] != '\0')
**** **** * *
* ***** * *** ** ***** ** * * * * **
** * ******* * * ***** * * ** * * * ** ** *** *
***** * * * * *** ***
* ** **** * **** **
*** *** * ** * ** *** *** * = 0;
* ** * ** ** * ** ** *
** * * * *** *** * ** * ** * (B[i] != '\0')
* ** ** * *****
***** **** * * **** ** ** * ** *** * ** ** ***
** ***** ** ** * ** *** *** * ** ** * *** * *
* * *** * ** * * * * ***
    
**** * * * ** * (i = 0; i < 26; i++)
** * ** * * *** * * *
* ** ** *** ***** ** *** ** * **** ***** * * * (Array1[i] != Array2[i])
** *** * * * ** * * * ***** ** *** * * *** ****** * ********* ** *** 0;
* * ** * ** **** * *
** * * * ** * ** * ***
*** ** ** *** *** ** 1;
}

int main()
{
** * * ** * ** * ** ** * A[100],B[100];

**** * * ** ** * ***** ***
** * * ** ** * ***** ** * **
* ******** *** * ***
*** * * * **** ** ***** (is_anagrams(A,B))
*** *** * ** **** * *
** * *** *** *** ** * **** * ** ** **** *** ** *** ** ** *** words or phrases are anagrams");
* ** * * * * * ***
***** * * * *** **** printf("Two words or phrases are not anagrams");
** ** * ** **
** * ** * ********** * * *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** *** * * * ******** ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ***** **** ***** * ** *
* * * * * ** ** ** (A[i] != '\0')
** ** ** ** * * *
* * * * ** * ** ** *** * * *** ***** * * * * **
* *** * **** * * *** * ** * ** * *** ** * * ** * ** ***
* * ** * *** * *** ** ** * *
** * * * * * * **
* ** * ***** ** ** * = 0;
** ** ** * ** * *
* * **** ** ** **** * **** (B[i] != '\0')
* **** * ** * * *** * *
* ** * *** **** * * ** *** * *** * ******** * * *
****** ** ** *** **** * *** * * ** ** *
** * ** * *** ** *
    
** ***** * * * * **** * ** (i = 0; i < 26; i++)
** ***** ** * ***
**** ** **** ** ****** ** *** ** * (Array1[i] != Array2[i])
* * * *** ** ***** *** ***** ** * * *** ** * * * ******* ** **** 0;
* ** *** * * ** **
* * * **** ** * *
* *** **** ** *** ** *** ** 1;
}

int main()
{
* * ** ****** * * *** A[100],B[100];

**** **** * *** * ** * * * ** ** * * *
** ** ** ** * *** ** ** * ** **** *** * *
* * ***** ** * * * ** *
** ** * * * ** ** * (is_anagrams(A,B))
* * ** *** ** * **** *
*** *** * *** * * ** ** * *** * * * *** words or phrases are anagrams");
** * *** ** * **********
* * * * ** *** * printf("Two words or phrases are not anagrams");
** ** ** * ** ** **
* *** *** ** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** *** *
#include * * * ** * * *
#include ** * * * ****
int is_anagrams(char A[],char B[])
{
* * **** * *** * *** lenA = strlen(A),lenB = strlen(B);
* ** * *** **** * ** ** * != lenB)
** **** ** * ** * * * *** ** * * ** * ** * ** * 0;

* ** * * ** * *** *** * i,j,k,a[26] ={0},b[26] = {0};
** * * * * ** ***** = 0 ; i < lenA ; i++)
* * ** ** * * **** *
**** ** *** ** * * * ** * * * *** ***** * = 0 ; j < 26 ; j++)
* ** * * * ** * * ***** * * ** * * * ***
** ** ****** * ** ** * ******* ** * * * ** * ** * ** ** * ** ** ***** == A[i] || 'A'+j == A[i])
****** *** **** ** *** **** * ** *** * * ** ** * *** * ** * ** * **** * *** **
* ** ** ** ** * * *** ** * ** * ****
** * ********* * * *
** * * * * ***** ** *** * = 0 ; i < lenB ; i++)
** * ** **** * ***
* ** * * * ** * ******* * * * ** = 0 ; j < 26 ; j++)
* ** * * ** ** **** * ** ** *** ** *
* *** ** ** * * ***** * * ***** **** **** * *** *** *** **** ** *** ** * == B[i] || 'A'+j == B[i])
*** * * * ** * ** ** ******* * **** * * * ** ** **** * * * *** * * * * ** * * * ** * ** **
** ****** * *** ***** *** * * ** *********** ***
* * ***** ** **** ** *
** *** *** * * ** ******* * * = 0 ; j < 26 ; j++)
* * **** *** * **** *
* ** *** ***** ** **** ** ** *** ** *** * * ** ** != b[j])
*** *** ***** * *** * * ***** * * * ** * ** * ** * * * *** * * 0;
* ** * **** ** * *
* ** * *** * * * 1;

}

int main(void)
{
** * ** ** *** * ** A[100],B[100];
* **** * * * ***** * * ** %s",A,B);

** **** * * * (is_anagrams(A,B)) * *** * *** words or phrases are anagrams");
* ** * ** ** * ** ** printf("Two words or phrases are not ** ** ** ***

* ** ** ** * * ** ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * *
#include * * * * *** *
#include **** * ** ** *
int is_anagrams(char A[],char B[])
{
* **** **** *** * * * * lenA = strlen(A),lenB = strlen(B),i,j,k;
* ****** * * * * * * a = 0,b = 0;
*** ** * * ** * ****** != lenB)
**** *** * * ****** ** * * * * ** * * **** 0;
* * ** ** ** * * ** *** = 0 ; k < 26 ; k++)
* *** *** ** * * *
* ** * * * *** * * * * *** * * * ** = 0 ; i < lenA ; i++)
* * * ***** * * *** *** ** *** ** * *
* * * * * **** *** *** * * *** ***** * * * * * * * * **** == A[i] || 'A'+k == A[i])
**** ** * *** ** ** *** **** *** * * ** **** *** ******** * ** ** ** * ** * ****** * * * * *
** ** * ** * *** * * * ** * **** ** * * *****
**** *** * *** * **** ** *** * ** * * = 0 ; i < lenB ; i++)
* * * ** ** * ** * **** * * ****** **** ** *
* * ***** * * ** * *** * * * * * * ***** * ** *** * * == B[i] || 'A'+k == B[i])
* * * ******** * * *** *** ******** * ** **** ** *********** * *** ** * **** ***** * * * * * * **
* * * * *** *** * * * ** * * ** * * **
** * ** ** * ** ** * ** ** ******* * * ** * ** * != b)
* ** ** * * ******* * * * * * ** * * * * * * *** ******* * * * ** * 0;
*** * ***** ***** * * ** ** *
** * * * * *** ** * *** * ** * * * * **** *** * * * * ** *** *** * 1;
}

int main(void)
{
* ** * ** * ** * * A[100],B[100];
** * ** * ********* **** *
* * ** ******* ***** * * ***
* * ** ** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* **** ** * ***** * printf("Two words or phrases are not anagrams");

***** * * ** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ****** * ******
#include * * **** * *
#include * * ** * **
int is_anagrams(char A[],char B[])
{
**** * *** * ** ** YOUR CODE HERE*/
* **** * * ***** * *** * i,count[256]={0};
*** *** ** * * *** *** ***
* *** **** ** * *****
* ** * ***** ** * ** * *** **** * **** * * * * * ** *** ** * *
** * ** *** * * ***
* ** *** * * * * ****** * **
* ** ***** ** * ** * *** *
*** ** * * * ** ******* * ** ** ** ** * * * *** ** * * * *** * * **
** ** ** * ******** ** * *
/*
** ** * ** ** * * (A[i]!=0 || B[i]!=0){
* * * * *** * *** ** ** ******* * * * * * *** *** * ** ** ** ***
* ** * * * * *** ***** * ** * *** ***** ** * 0;
** *** * * *** *** ***
*/ * * * * ** ***** * ** * *** 0;

** *** * ** ** ** ** * * **** (i = 0; i <256 ; i++)
* ** ** *** * * * ** ** *** * * * * * (count[i] && i!=' '){
* * **** ** * * * **** * ********* * ** **** * ** ** *** *** * * * * ***
*** * ** * * * * **** * * * ** * *** ** ** * * * * ** * **** 0;
*** **** * ** ** * * ** *** ** ***** * ** *** * **


* * ** ** *** ***** ** ** 1;

****** * ** * ** OF YOUR CODE*/
* ** *** ** **** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * *** * ** * ** A[100],B[100];
**** * ** ** ** ** ** * YOUR CODE HERE*/

*** * * * ** *** *
**** ** *** ** * * ** * * *** *

*** * ** ** *** * ** * * * * = '\0';
  // * * = '\0';
* *** ** * * ** ****** i;
* *** ** **** **** *** *** * * *** *
* ***** * ** *** * ** **** * ******** ***** ***** ** * * *** **
** * * * * * *** * * * * ** ******** * * ** *
*** * ***** ** ****** * *** * * * *
** * * * * ** * * * * ** ** * ** * ****** ** * * * * * ****** * * ** * **
* * * ******* * * * **** * ***** ***** ****** *** * *

***** ****** **** ** * OF YOUR CODE*/
**** *** * * **** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ** ***** * * * * *** printf("Two words or phrases are not anagrams");

********* *** **** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * **
#include * * **
#include ** * * * * **
int * * * * * A[],char B[])
{
** *** * ** * * ** YOUR CODE HERE*/
* * * * ** ** * * ****** * ****** *
** * * * **** * ***** ** *** **** ** * ******
* * * ** ** ** ** *
* * * **** * ** * ***** * ** * * ***** ** ** *** **
** ** **** * * * *** ** ** ** ** * *** *
*** ***** * *** ** *
* * **** * * *** * **** (A[i] || B[i])
* * * ******** * * * ***** ** ** **** * 0;

**** * ** ** * * * (i = 0; i < 256; i++)
** * *** ** * * * * * ** **** *** *
***** * *** * * * * ** * * ***** ***** * * **** *** **** ** ** *** * *** * ** 0;
* * * **** ** *** 1;

* **** * ** * * * OF YOUR CODE*/
********* * * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
** * ** ** * * ** * * **
* * *** * * * * * * YOUR CODE HERE*/
** *** * * *** * ** ** * ** * * *
** * ** * ** ***** *** ** * ** ** * *** **

* * ** * * * OF YOUR CODE*/
* ** * *** ** ** * * * * ** * ** ** * * words or phrases are ****
* * ** * * * *** **** ** words or phrases are not *** * **

* ** * * * ***** *** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** ** **
#include * ** * *
#include * * * ***
int ****** * A[],char B[])
{
* * * * * ** *** * * YOUR CODE HERE*/
** * * * **** ** *** ** * **** *
** * * *** * * * * ** * ** * * *
** * * **** * *
**** ****** ** * ***** * * * * *** ********* * * *** *** *
* * ** *** ** * * * * ***** ***** ****** *** * * ***** *
* * * **** * * ** * ** * *
* ** **** *** * (A[i] || B[i])
** * * *** ** * * ** ***** ** * 0;

** ** ** **** * * **** (i = 0; i < 256; i++)
** *** *** ** *** * ** * * **** *** ***** * ** * * * ** *
**** **** ** *** * * * **** ** * ****** ** * ** ** ** ***** ** 0;
* * * * * *** * * * * 1;

* ** * ** * OF YOUR CODE*/
* ** ** * **** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** *** *
{
*** * * ** * * ** *** **
** * ** ** * *** YOUR CODE HERE*/
****** * ** * ** * * * ** ** * * * **
* * * * ** **** *** * * * * **** * **** *

****** ** ** *** **** * * OF YOUR CODE*/
***** * ** ** * ** ***** ** ** * ** * words or phrases are * * * * * * *
*** * * **** * ** * ** **** * words or phrases are not ** *

* * **** * * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 12.1k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 11.3k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 10.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users