0 like 0 dislike
12.8k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 12.8k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * ** * *
#include *** * ***
#include ** *** * *
int * * a[],char b[])
{
* ** *** * * * first[26] = {0}, second[26] = {0}, c = 0;
** **
* * * ** ** * ** * * frequency of * * * * in first string
** *
*** *** ** *** * * ** * (a[c] != '\0')
** ** * ** ** *** * **
*** **** ***** ***** * * * *** * ** * * *
* ** * **** ** * * ****
**** ****** **
***
* *** ** ** * * = 0;
**
* * *** * * * * ** * ** (b[c] != '\0')
* ** ** *
* ** * * * **** * ** * ** **** * ** ***
* * *** * * ***** * ** ** ***** * * **
***** ****** * ****
*** **
* ****** ** *** Comparing frequency of * ***
* ******
* * ** * *** * (c = 0; c < 26; c++)
* *** * * ** *
**** ** *** * * **** * * **** (first[c] != second[c])
** ** * ** ** ******* * * ** *** *** * * ** * 0;
**** *** ** *
** *****
* * **** 1;
}

int * *
{
* * * ** * ***** * * ** *
* * ** * *** * ** * ** * ** A,B);
* * * * ** ** * ** * * *** ** ** ** * ** *** words or phrases are * * *
*** ** ** * ** * * * words or phrases are not *** ***

* *** * **** * **** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** ** * *
#include * * ** * * **
#include *** *** *
int **** ** ** * a[],char b[])
{
* * ** * *** * first[26] = {0}, second[26] = {0}, c = 0;
*******
* * * ** * * * frequency of characters in first string
** ** *
* ** ** * ** **** (a[c] != '\0')
* * * ******** *
***** * * *** *** ******* * * * **** ** *
* * * * * ** * * * ** *** * *
** * ** *****
** *
** *** * * * * ** = 0;
**** ** * *
* * ** ** * *** * (b[c] != '\0')
* ** ****
* ******** ** * * ** ** ** ** *** * * *
**** *** * ** * **** * * * * *** **
* ** ****
*** *
* * **** * **** *** * Comparing frequency of ***
* *
* **** ** * ******** (c = 0; c < 26; c++)
* * ** ****** * *
**** ** ** ******* *** *** ** * *** (first[c] != ** ****
* ******** * * * *** * * ** *** * ** ** ***** * * ** 0;
** ** * * * *
*
*** *** * *** * *** 1;
}

int main(void)
{
** ** ** * *
***** * ** ** ****** * ****** * ** *********
* ** ** *** *** ** ***** *** * * * ** ** * words or phrases are *** * *****
* * * * ** * **** **** ** words or phrases are not * * * *

** * ** **** ** ** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** * * ** *
#include * * *
#include **** * ** **
int is_anagrams(char A[],char B[])
{
*** * ** **** ***** * YOUR CODE HERE*/
* * *** ** * * ** ***** ** * * *
* *** * **** * * * * **** * * *
** *** * * * *** *
*** * ** ** *** **** * ** ** ** * ** ** ** * * && * ** * * * ***
* ** ** * ***** * **** * ** ******* * *** *** ** ** * **** * * * * * * * * **
***** * * * * * * *** * * **** ** ** *** * *** * * && * * * ***** ***
* * * * ** ** * *** * ** * *** *** * * ** ** * * * * *** * * * *** * *** *
**** ** * * * * *****
* * * *** *** ** * * * * *
* ** * *** * * * * ** *
* *** ** *** ** ** ******* ** * * * * * (cA[i]!=cB[i])
*** * *** * * * ***** ** **** **** **** ***** * * * ** * * * 0;
** * ** ***** **
** * ***** *** * * ** **** 1;
* ** * * ** * * ** OF YOUR CODE*/
* * *** **** * ** * function should return 1 if two words or phrases are anagrams,
** * * ** *** ** if two words or phrases are not anagrams.
}

int main(void)
{
** *** * **** * ** A[100],B[100];
* ** ** ** YOUR CODE HERE*/
** ** ** *** ******* * * * ** * ** ** *** *
* ** ** *** * *** * **** ** * * *
*** ***** ** * ** * (is_anagrams(A,B))
* * * *** *** **** * * * * * *** ****** *** * *** * * words or phrases are anagrams");
** * ** * * * **** *
* ***** * * ** *** ** * **** ** *** ***** * *** * words or phrases are not anagrams");
** * **** * *** * ***** * 0;
** ***** *** ***** * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
**** **** * * *** * ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
*** *** * * * * * ***
* ****** ** ** ***** (A[i] != '\0')
*** ** ** **** * **** ****
** * * ** * ** * ** * * * * * *** * * * *
* * *** * * * * ** **** * ** * * ** ** *** ** * ***
** ** * *** * ** * * **
* *** * * * *** * * **
*** * *** ***** ** = 0;
* * **** * * ***
* * * * * * * * * (B[i] != '\0')
* * * * ** *** * * * *
* * *** * *** ** **** * * * * * *** * ** ** ** *
** * *** **** * *** * *** * *** * ** ** **
** ** ** ***** * * ***** *
    
*** *** * * *** **** (i = 0; i < 26; i++)
* * **** ***** ** *
* ** ** * * * *** *** * * * *** * * * ** ****** * (Array1[i] != Array2[i])
* * * ******* * * **** ** * * * * *** * * ** * **** * ** **** * * *** 0;
** *** * ** * * **** *
* * ***** * * *** * * **
* * * * * * ** * * 1;
}

int main()
{
** * *** ** ** * * A[100],B[100];

* * * * *** ** ** * *** ** * * *
* * **** ***** ** * * * **
*** * * * ** *** **
*** * * ***** * ** ** (is_anagrams(A,B))
*** *** ** * *** * ***** ***
****** * ** * * ** * * * ** * * ** * ** * * * **** words or phrases are anagrams");
** * * * * * * * ** *
* ** * ** * ** *** * * printf("Two words or phrases are not anagrams");
* ***** *** * ***
** *** ** ** * **** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * *** **** * ** ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
** ** *** ** ** **** *
* * * **** **** (A[i] != '\0')
* ** ****** * ** **
* * ** * * **** * **** **** * * * ** ** *******
** * *** ** **** * *** ** * *** **
* *** * * *** * *
** * ** *** *** * * * *
* * ** ** *** * **** * *** = 0;
*** **** * ** ** *
* ** ** ** ** * *** (B[i] != '\0')
* ** * ** *** * ** * *
* * ** *** * ** * ***** *** *** * ****** ** ** ** **** *
*** * **** ** **** **** * ** * ** * ** **
* * * * ** **
    
** * * * ****** **** * * (i = 0; i < 26; i++)
* * ******* * ** ****
** **** ** ** ** **** * * * ** * * * * (Array1[i] != Array2[i])
* *** ***** ** ** ****** * **** * **** ** * ** * *** ** ** 0;
** * * *** ** * ***
* * * ** * *** * * ****
* * ** ** ** **** * * 1;
}

int main()
{
*** ** * * * * ** A[100],B[100];

** **** ** ** * * * *** ** ** *
*** * *** ** * ** * ** * * **** * **
* * * **** * ******* *
**** * ****** * * * (is_anagrams(A,B))
* ** ****** * *** ****
*** ****** ** * *** * * *** *** * ** ** * *** * * ** * * words or phrases are anagrams");
* * * * ** *** * * **
* * ** ** **** * * * printf("Two words or phrases are not anagrams");
** ****** * * ** * *
******** ** * * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * * *** * *
#include * * ** * *
#include * **
int is_anagrams(char A[],char B[])
{
*** * * * * *** * ** ***** lenA = strlen(A),lenB = strlen(B);
* * ** **** *** *** ** != lenB)
*** **** * * ** *** **** ** ** * *** * * 0;

* * ** * * * ** * *** * i,j,k,a[26] ={0},b[26] = {0};
* **** * * * ** * * *** * *** = 0 ; i < lenA ; i++)
* * * **** *** * * **
* *** * ** * *** ** **** ** * *** * * * * *** *** = 0 ; j < 26 ; j++)
* ** * ** **** * * ** **** ***** * ** ***
* * * * *** *** * ***** * * *** * *** *** * * * * * ** ** ** * * ***** == A[i] || 'A'+j == A[i])
* * *** * * *** * * * *** * * * ***** * **** ** * * * * * * ** **** *** ***** * *
*** * *** ** ** ** * * ** *** ** **** **
**** ** * ** ** * * * * **
* *** * ** * **** *** = 0 ; i < lenB ; i++)
* * * ****** ** ***
** ** * * * * * ** * **** * * ** ** * * * * *** * = 0 ; j < 26 ; j++)
* ** ** ** * * * * ** * * * *** **** ** *
* * ** ** ****** * * * * * ** *** ** *** *** * * **** * *** * * * * == B[i] || 'A'+j == B[i])
* * ** ** * * *** ***** * ** ** ** ***** ** *** * * * ** *** *** * * ** ** * ***
* ***** ** ** * ****** * ***** *** * * * **
* ***** *** * * ***
* ****** * ** ** ** ** = 0 ; j < 26 ; j++)
** ** *** ** * ** ** *****
* ** * **** ** * **** **** ** * ** ** != b[j])
*** * * * * * * ** ** ** * * * * * * * * ** * * * 0;
**** **** ** * * ***
* ** ** ** *** * * 1;

}

int main(void)
{
* **** * * ** *** ** * A[100],B[100];
* ** * ** * ** *** * * * %s",A,B);

*** ***** * * * (is_anagrams(A,B)) * * * * words or phrases are anagrams");
* * * *** * * * * printf("Two words or phrases are not ****** * *

**** ** * ** ** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** ***
#include *** **
#include *** ** * *
int is_anagrams(char A[],char B[])
{
* * ***** ** * * *** * lenA = strlen(A),lenB = strlen(B),i,j,k;
* * *** ** * *** ** **** a = 0,b = 0;
** **** ***** * ****** * * *** * != lenB)
*** ** * * ** * * * ***** ** * ** * ** * * * * 0;
*** * ** * * * * ** = 0 ; k < 26 ; k++)
**** *** ** ** *** ** *
** * ** * ** ** *** ** * * * ** ********* ** ** = 0 ; i < lenA ; i++)
**** ** * * ** ** * * ****** ** *** * *
** * * ** * ** ******** ** * * * *** * **** *** * ** * * == A[i] || 'A'+k == A[i])
** ** * * * * ** * * *** ** * * **** * * * * * * ***** * * * ** * ******* **
* * * * * * * *** * * *** * * * * *** ****
* * * ** * * * **** *** * * ** *** * ** ** = 0 ; i < lenB ; i++)
** * * ** ** * *** * ***** ** *** * * * ** * * * *
* ** **** * *********** * ** ** * *** ** * ******* ** *** * * ** * *** * == B[i] || 'A'+k == B[i])
* * * * * * ** * * * * *** ** * * * **** * * * *** * ** ** ** ********* *** ** * * * * *
* ** *** * ****** ** * * * ** * **** * * ****
****** * * ** ** ** * * * **** * != b)
** *** * *** * *** * ** * * **** *** ** * ** * * * ** * *** * 0;
** * ** * * ***** *** * *
*** * * *** * * * * *** ** * * ** ** ** * * ** * ****** * *** ** * ** *** 1;
}

int main(void)
{
** ** ** ** ** *** A[100],B[100];
*** ***** * * * * **
* * * * ** ** *** ***
*** ***** * ** * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * ** * ** printf("Two words or phrases are not anagrams");

* * * ** ****** ** * * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** *
#include * **** * ****
#include ** *** * *
int is_anagrams(char A[],char B[])
{
*** * ** ** * ****** * YOUR CODE HERE*/
**** * *** * *** **** **** i,count[256]={0};
* **** ***** ******** * *
* * *** *** *** **** **
** * * * * * ** ** ** **** * * ** * * *** * * * * * * * * *** * ** ****
* ** * * * * ** **
****** **** ** * ** ** * * ** *****
*** * * ** ** * * ****
** *** * *** * *** * ** * * * * **** * ** ** ***** ** * *** *****
* * * ***** * * ****
/*
* ** * ** * ** * * ** (A[i]!=0 || B[i]!=0){
* * **** * * * ** ***** * ** ****** * * * * ***** * **
* *** **** ** ** ***** **** * *** * * *** * ** * 0;
** ** **** *** ** ** ***
*/ * * ****** * ** * * *** 0;

* * * *** ** * * ** (i = 0; i <256 ; i++)
****** ****** *** ***** *** * **** (count[i] && i!=' '){
* *** **** ******* * *** *** ** * ***** * ** ** * * ** * *** **** * * * ** * ***
** * * * * * * * ** *** * * * ** * * ***** *** ** * *** * * * 0;
* * ** *** *** ** * * * *** * * * * * **


* ** ** * ***** ** ** * *** 1;

** ** ** * ** * OF YOUR CODE*/
** ** * *** * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
** * ** * * * * * A[100],B[100];
* * ** * *** * *** *** YOUR CODE HERE*/

*** ** ***** * **** ** *
*** ** * * ** * **** ******* * **

* * ** * ** ****** * * = '\0';
  // * * * ** * * = '\0';
*** ** *** ** ** ** *** * ** i;
* * * * * ** * * * **
* ** * **** * * ***** * * * * ** ** ** * * *** *** ** * * *** **** ** ** *******
* * **** **** * ** * * ** ** * * ** ** ** * ** * **
*** * *** * ** **** ******* * ** * *
**** * * * * * * * * * * * * *** * ****** ** *** ***** * ***
* * ** *** * ** * *** ***** * *** ** **** *

* ***** * * OF YOUR CODE*/
** ****** ** * *** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * ******** ** * * printf("Two words or phrases are not anagrams");

* * * ** * * * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** *****
#include ** ***** **
#include *** * *
int ** ** ** A[],char B[])
{
**** * ******* * ** YOUR CODE HERE*/
* *** *** * ** ** * * *** *
****** * * * *** ** ** ** * ** *** ** * ** * ***
** ***** * **** ** * * **
* ** * ** ** ***** * **** * *** ** ** ** ******
** * * * ** * * * ** ** ** * **
* ** ** * * ** **
* * * ** ******* ****** (A[i] || B[i])
** ** * * ** ** *** * **** *** ***** * * * 0;

* * *** ** * * *** * (i = 0; i < 256; i++)
**** * ** *** * * * * ** ** **** * ** * ** ** * * * *
** * ** ** **** * ***** ** * * *** * ** * * * * ******* * * ** 0;
* ** **** * ***** * ** * 1;

** * * * * * * OF YOUR CODE*/
*** * ** *** * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
* * * * * * * ** **
* * * * * * ** * * YOUR CODE HERE*/
** * **** * ** * ** * ** **** * * * * ** *** *
** ** ** *** ** ** ** *** ***** * ** * * ** *

* *** *** ** * OF YOUR CODE*/
* ** ***** * ** ** * * ***** ****** words or phrases are ** *** **
* ** * *** * * *** *** ** * words or phrases are not *** ** *

***** * * * * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * **** **
#include ***** *
#include *** * *** *
int *** * ** ** A[],char B[])
{
* * ** * * *** * * YOUR CODE HERE*/
* ** ***** * ****** * *
* * ** **** * ** * ** *** **** * ** *
*** * * * ** * * * ** * *
***** * *** ** * * * * *** ** *** ** ***** * ** * *
* ** * * * *** ** * *** ** **** ** * ******
** ** * *** * * ** * **
**** ** **** ** ** ** ** * * (A[i] || B[i])
* * * ****** * ** **** * * ** 0;

* ** *** * ** * **** ** * * (i = 0; i < 256; i++)
* * **** *** ** *** * ** * *** * *** * ** * **
* ** * * **** **** * * ** * * * * ** *** * ** * ** * * 0;
* * * * ** * * ** 1;

**** ****** ** * * OF YOUR CODE*/
** ** ** **** **** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int
{
** ** * ** ** * ******* *** ***
* ** ** ** *** * * YOUR CODE HERE*/
*** * * * *** * ****** * ******** * * * * * * ********
* * ** *** * ***** * *** * * * ** *** * ***

* * ** * * * * OF YOUR CODE*/
* **** * * * ** *** ** * * * * words or phrases are * ** ****
** * ** * ** * * ** ***** * words or phrases are not **** ** *

** ** *** * *** ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.157
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.3k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.6k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users