0 like 0 dislike
17.4k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 17.4k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ****** * *
#include ** * ** **
#include **** * *
int * **** ** a[],char b[])
{
* *** * ** * * * first[26] = {0}, second[26] = {0}, c = 0;
**
* * *** **** * * frequency of * * in first string
**
**** * * * * * (a[c] != '\0')
* *** *
*** ** * * * *** * * * ** * ***
* * ** ** * ** ** * ** *** * *** **
* * **** ***
** ** **
*** *** ** ** ** = 0;
* * **
* * *** * ** * * * (b[c] != '\0')
* * * ** * **
** *** * * **** ** * * ** ********* * * *** ** *
* * * **** * * ** * ****
*** ** * ** *
* *
* * *** * * * Comparing frequency of * *
*
** * * * * (c = 0; c < 26; c++)
* ** ** * ** * * ***
*** ** ** * * ** * * ** *** *** (first[c] != second[c])
* **** ******* * * * ** * * * ** ** * ** 0;
** * ****** *
* * * * *
** * * **** * * * * **** ** 1;
}

int * * *
{
* *** ** * **** ** ** *
***** ** ** ** *** ** **** ** ****** A,B);
* *** * * * * **** ******* ** ** ** *** * words or phrases are ****** **
**** ****** * *** * ** ** words or phrases are not ** ** ** * * *

** * **** * * ** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** *** ****
#include ***** * * ** *
#include * **** ** *
int * * * a[],char b[])
{
* * * ** * * first[26] = {0}, second[26] = {0}, c = 0;
*
** ***** ** * * * ** ** frequency of characters in first string
* *
* *** * *** * ** (a[c] != '\0')
** * * * ** * * *
** **** **** * **** ** * ** * ** * *
** ** ** * *** *** ** * * ** *** *
* ** ** * *

* *** ** * * * * * = 0;
* **
* **** *** ** * * * (b[c] != '\0')
*** ** * * * **
**** ******** * * * ***** ** ** * ** * *
* ** *** * **** * *** * *****
** *** * *** * * *
* ******
***** **** * * Comparing frequency of ****
* *
* * ** (c = 0; c < 26; c++)
** ** * **** ** **
** * *** ** ** ** *** *** * * * * * (first[c] != *
* * ** * * **** ** * ***** * *** *** ** * *** ** 0;
* * * ** ***
* *
*** * **** * * * * * 1;
}

int main(void)
{
* ** ** * * *** * * **
*** ** ** ** ** *** * * ***** * ** *
**** ** ***** * ** *** * * ** * *** ** * words or phrases are * * * ***
* * * ***** * * ** **** words or phrases are not *** * *

** * * ** ** ****** ** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * ** **** **
#include * * * * ** *
#include * *** ** **** **
int is_anagrams(char A[],char B[])
{
* **** **** * * ** *** YOUR CODE HERE*/
** * ** ** ** * *** *** ** * * * ***
*** * * * * * * **** ********* * **
** ******* * *** **
* ** * **** **** * * ** * * ***** ** ******* * * **** * *** * && *** ******* * *
* * * ****** ***** * * * * ** * ** *** *** * ** * **** * ** * ***
* *** * * * * * *** * ** ** * * ** **** ***** * && *** ** * *
** * * * * * * * ** * * ** ** ** * * * ** * * * ** **** ** ** **
* * * *** * ** * * *
* ** * *** * * * * * ** * *
* * *** * ** * ***** * **
*** *** * ** * ** * * * ****** *** * * (cA[i]!=cB[i])
** * * * * * * * * *** * ** * **** * *** * * * * * * ** ***** ** 0;
** ** * * * ** * ******
** * * * * * *** * * 1;
* ** * *** * * * **** OF YOUR CODE*/
* * *** *** function should return 1 if two words or phrases are anagrams,
*** * ** *** * * if two words or phrases are not anagrams.
}

int main(void)
{
* **** ** *** **** A[100],B[100];
* * * **** * *** ** * YOUR CODE HERE*/
*** * * * ** **** ********* * ** * * *
* ****** * ** ** * * ** * * ***** ** **
** * * ** * (is_anagrams(A,B))
* * **** * ** * **** * * * *** **** *** **** ** words or phrases are anagrams");
***** * * *** * * * ****
*** *** * * * ** ***** * * * *** ***** *** * * words or phrases are not anagrams");
** * * * ** **** ** ** ** 0;
* ** * * **** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * * **** *** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ** * ***** *** *
*** ** * * ** * ********* (A[i] != '\0')
**** ** * * ** * * ***
** *** ** * * * * * * * * * * *** * * * **** ****** *
* * * * ***** * * **** ***** * *** *
**** *** * * * * ** **
* ** * * * ** *
*** ** **** * = 0;
* *** ** * * * **** *
**** ** * ** *** * **** (B[i] != '\0')
*** * ** ** * *****
* * * *** * *** * *** * * ** *** * **** ** ** *
* * ** ** * * * * * ** * ** **
* ** * * * * * * ** * * *
    
******* ** ***** * * (i = 0; i < 26; i++)
*** * * * * ** *
* * ** * * ** **** * * * * ** * * *** (Array1[i] != Array2[i])
**** ** * ** * ** * * *** * * ** * ** *** * *** * ** * * * * 0;
* *********** * *
*** **** * **** *
* * ** * * * * ** **** * 1;
}

int main()
{
** * ** **** * * ** ** * A[100],B[100];

* *** ***** * ** * ****
***** * * * * ** ** * ** ** *
* ** * * **** * *** * ***
* * **** ***** * ** * (is_anagrams(A,B))
**** ** ** ** ** **
* * *** ** * ** *** ** * * ** *** * **** * * *** * words or phrases are anagrams");
* * ****** **** * **
***** * *** * * ****** printf("Two words or phrases are not anagrams");
** * * * ** * ** * **
* ** ** * ** * *** *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** *** ** *** * ** **** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ** **************
* * * ** **** * *** *** ** (A[i] != '\0')
** *** ** * * *** ** *
* * ** ***** **** * ** ** ********* * ** * ** *** ** * *
** * ** ******* * * ** * ** ***** * ****
** ** *** * ** ** * ***
* * *** ** * *** *
*** ** *** * * * ** = 0;
* * **** ** ** * *
* * ** ** * * * * (B[i] != '\0')
** **** **** ****
* ** **** *** * ** * * * * * *** *** * ** **** *
* * ** *** * *** * * ******** * * *** * * * ***** *
* ** *** ** * * ** *
    
* * ** * ***** * ***** (i = 0; i < 26; i++)
* * ** * * *** * * * **
** ** ** ** * ** ** * ** ********* * * * (Array1[i] != Array2[i])
* * * * ** *** * * **** * * * * ** ** * * * **** * * * ** * * * * 0;
* * * * * * ***** * ***
*** * ** * * ** * *** *
** * ** * * * * ** 1;
}

int main()
{
* * * **** * ** *** A[100],B[100];

* * * ** * * * * * *** * ** * *** ** ** *
* ** ****** ** * * *** ** ** * * * *** ***
* *** ** ** * * * *
* * ** * **** (is_anagrams(A,B))
* * * * **** *
*** ** ** * * * * * ** ** ** *** * * ** * * *** words or phrases are anagrams");
** ** * * ** * * **
*** * ** * *** printf("Two words or phrases are not anagrams");
* * * **** * * **** ** ***
* * ***** **** ** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** *** *
#include ** ** * **
#include * * ******** *
int is_anagrams(char A[],char B[])
{
* *** ****** ** ** *** * lenA = strlen(A),lenB = strlen(B);
* * ** * * * * *** != lenB)
** * ** *** ** * ** * *** * * * *** * * ** * *** * 0;

** ******* * ** ***** i,j,k,a[26] ={0},b[26] = {0};
** ** * *** **** * ** * = 0 ; i < lenA ; i++)
* ** ** **** * **
* **** ******** ** * ** ** **** * * * * * ** ** = 0 ; j < 26 ; j++)
** ** ** * **** *** * * ** ** * ****** *** *
* ** * *** ** * * ****** ** * * ******* * * * **** * * *** ** * ** == A[i] || 'A'+j == A[i])
* *** *** ** * * ** **** ** ** * * ** * ** * * *** ** **** **** *** ** * * ***
* **** ** * * * ** **** ** * * ** * *
**** ** *** * ****
** *** * * * * * * ** = 0 ; i < lenB ; i++)
* * ***** ** **
***** * ** ******* ** **** * * **** ** * ** ** ** = 0 ; j < 26 ; j++)
*** *** * * * ** ** **** * *** ** * *** **
* *** ** ** **** * * ***** * ** * ** * ** *** * * *** == B[i] || 'A'+j == B[i])
* ** *** * * ** ******* * * ** * ** ** *** * * * * * * *** ***** ** * * ** **** * *
*** ** **** *** * *** * ** *** * * ** *** ** ******
** * * * * * * ****
** * **** * ** ** ******** = 0 ; j < 26 ; j++)
* ***** * *
*** *** ** ** ***** ** ** *** **** * != b[j])
* * * ****** * *** ** ** * * ** * ** * ** * ****** * * *** * * * ** ** 0;
** * * * * *** ** ***
** ** * * * * * * ** **** 1;

}

int main(void)
{
* ****** * * * * ** A[100],B[100];
*** ***** * **** *** *** **** ** %s",A,B);

* ** * * *** ** * (is_anagrams(A,B)) * * ** * ** words or phrases are anagrams");
* ** ** * ***** * printf("Two words or phrases are not * * *

* * ** * * ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * **** **
#include ** * * * *
#include * **
int is_anagrams(char A[],char B[])
{
** * * * * * ** * ** * lenA = strlen(A),lenB = strlen(B),i,j,k;
****** * * ** ** * * * * a = 0,b = 0;
* ** ******* * * * ** * != lenB)
* ** ** ** * * * ** ** * * * ** * **** * * 0;
*** * ** * * * ** *** = 0 ; k < 26 ; k++)
*** ***** * ** * * ** **
* ** * * **** * ***** **** * * * * * * * ** = 0 ; i < lenA ; i++)
** ** * ** ** *** ** * * ***** * * ***
*** * ** * * * * * ** * * * ** * * ***** * *** *** * ** == A[i] || 'A'+k == A[i])
*** * ** ******** * * ***** *** * **** * ** * ** **** * ** ** * ** **** ** *
* *** *** ** ** * ** ***** * ** ***
* * * * * * * * * ** * ** * *** *** * * ** * = 0 ; i < lenB ; i++)
** ** * ** *** * ** * * **** ***** * ** ** * ****
** ** ** * **** * * * ** ** ** **** ** ** ** * **** ** * * ** * * == B[i] || 'A'+k == B[i])
* ** * * ** * ** *** ** * * ** ***** * * *** * ****** * ** *** * * ** * * ** * *
** * * * * * ** *** ** **** *********
* * *** *** * * ***** *** * * ** * *** *** != b)
* * *** ******** * ********* **** * * ** ** ** * * * 0;
* * * *** * *** ** * **
* ** *** *** * ** * * * ** * * *** * **** *** * ** * ** * * * ** * ** 1;
}

int main(void)
{
** * * ******** * ** A[100],B[100];
*** ** * * **** ** ** * * * * *
** * ***** **** * * * * *
* * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
***** ***** ** * * printf("Two words or phrases are not anagrams");

***** * **** * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** *** * *
#include **
#include ***** ***** *
int is_anagrams(char A[],char B[])
{
** * * * * *** **** **** YOUR CODE HERE*/
* ***** * *** * *** * i,count[256]={0};
**** ** * **** ** *** * ** *
* * * * ** * * ***
* * * * ****** ** *** ** ** * * ** ***** * ** ** * * ****** ** * ****** * *
* ** * * * *** **** **
* * ****** * * *** *** * * *
** ** * * ** * * *
* * *** ** **** * ** ** * ****** * *** *** * * *** **** * *****
* ** ** * * * * * * ** **
/*
** * **** * * ****** ** * (A[i]!=0 || B[i]!=0){
*** ** * * ** * ** ** ** * * * * * * *** * * ** ** *
* ****** * * *** * **** ** **** ** ** * *** * *** *** 0;
*** ** * * *** *
*/ *** * **** *** * ** *** 0;

* **** * ** **** * * (i = 0; i <256 ; i++)
*** * * ****** * ********* ***** *** * * (count[i] && i!=' '){
*** *** * *** * * * * *** * ** *** * ***** ** * * * ** * *** **** ** * ** * * * *
* ** * ****** * ** ** ** ** * * *** ** * ** ** *** * **** **** 0;
* ** **** * *** **** * ** * ********


** *** ** * ** * * ** * 1;

********** * * ***** OF YOUR CODE*/
* ** * ***** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * * *** * ** A[100],B[100];
** * **** * * ** YOUR CODE HERE*/

* *** *** * ** ** ***** * ** * ** **
** ** ** * * *** ** * * ** * *

* * ** ** * **** **** * * * = '\0';
  // ** * * ** * = '\0';
** *** * * * * *** i;
****** * ** ** *** * *
**** ** * * * ** * * * *** * ** * * * ** ** ** ** * *** * ***** ** * ***
***** *** ** * ** *** * ****** * * ** * **** ***** * * *
* ******* *** ** *** ***** ** * *** *****
* *** ** *** * ** * * * * **** * * ** ** * * *********** * ** ** * * * ****
* * *** *** * **** * ** *** ** * *** * ** * * ** *

* ** * * * * *** ** OF YOUR CODE*/
* * * * ** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** ** * **** * * printf("Two words or phrases are not anagrams");

* *** * ** * * *** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * *
#include *********** * *
#include **** *** *
int *** * * A[],char B[])
{
** *** * ** * ** * ** * YOUR CODE HERE*/
* ** ** ** ** * * *** ** *
*** * * * ** ** * * * * * **** * *
****** * ** *** **** * * *
* * * *** *** ** *** ***** ** ****** * * * * * *
* *** ** * * *** ** ** ***** ** ** * ** ** *****
* ***** **** ****** * *
*** * * * * *** ******* * (A[i] || B[i])
** ** ** * * ** *** ***** ** *** * 0;

* * ** ** * ** ** *** * ** * (i = 0; i < 256; i++)
** * * * * ** ** * *** ** * ** *** **** *** * ***
* * ** **** ***** * * *** * ** ** * *** *** **** * ** ** * **** * * * 0;
** * *** * * ** ** * * * 1;

* * ** * ***** **** ** OF YOUR CODE*/
*** *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ****
{
**** * **** *** ******** * *
* * * ** ** ** ** *** YOUR CODE HERE*/
** ** ***** * * *** * ** * * * * * *** * *
* * ***** * * **** ** **** * ***** *

** ** **** * OF YOUR CODE*/
** * ** * ** * * * * * * * * **** words or phrases are * * * * * **
* * * * ******* * ** *** * * *** words or phrases are not ****** **

** * * ** ** **** **** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** ** *
#include **** ** ***
#include * ****** ** **
int * * * * * A[],char B[])
{
*** *** *** * * ***** ** YOUR CODE HERE*/
* * * * * * * * *** * *
**** ** * ** * *** ** ** * * ****** * ** ****** * *
** **** * ****** * ***
**** * * * *** ******** * *** * **** * *** ***
* * *** * * * *** * *** ** * * * ***** **** *
*** ** ** * * **
* * ** * * * * *** * * (A[i] || B[i])
**** * * * * ** *** ** * * * ** 0;

*** * * * * * (i = 0; i < 256; i++)
****** * ** ***** *** ****** * ** * * ***** ** **
* ** ******** * ** * *** * * * * * * * *** ** *** * * **** * 0;
* ** * *** ** * ** ** 1;

* * * * ** ** *** ** OF YOUR CODE*/
**** ** * * **** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ***
{
* * * *** * * **
*** * * *** * *** * YOUR CODE HERE*/
** * * * *** * * ** ** ** * *** ***** **
*** **** ** ** * **** **** ** * * * * ** **

****** ** ** ** * OF YOUR CODE*/
** **** * ** * *** ** * * **** * ** *** words or phrases are *** * * ***
* ***** * ** * ** * ** *** * words or phrases are not *** ******** *

***** ** ** ** ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.108
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.8k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users