0 like 0 dislike
16.1k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 16.1k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * * ****
#include ****** *
#include * * * *
int ** ** ** a[],char b[])
{
**** * ** first[26] = {0}, second[26] = {0}, c = 0;
**
** *** * ** * *** * *** * frequency of * in first string
* * *
* *** * * * ** ** *** (a[c] != '\0')
* ** **** *
** * * ** * ** * * * **** *** * ******
* *** * * * * * * ***** *** * * * *****
**** * * * ** * *
*** *
******* * * * = 0;
* ** *
* * **** *** (b[c] != '\0')
* * * * ** *
* ****** *** *** ** * **** * *** ** ** **
********* * *** * **** *** ** ** * ** **
* * * *** * ** *
**** * *
************* * ** Comparing frequency of ** ***
***
**** * * * * ** (c = 0; c < 26; c++)
* ** ** **
* ** ****** ************ ** * * * *** (first[c] != second[c])
***** * * ** ** ** *** * * ** ** ** *** *** ** *** 0;
** *** * ** ** * * *
** *****
***** *** ***** * * 1;
}

int * * ****
{
* *** * * * * ** * * * ** **
* * ** * ** ** ** * * * * ** A,B);
* ** ** * * *** * *** *** words or phrases are ****** *
** ** ** ** * ** * * ** * * words or phrases are not * ***** *

** * * ***** * *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** ** ***
#include * ** *
#include ** * * *
int ****** a[],char b[])
{
* * * *** * ** first[26] = {0}, second[26] = {0}, c = 0;
* *
* * ** * ** ** ** ** **** frequency of characters in first string
* ***** *
* * * ***** ** (a[c] != '\0')
* ** **** * * ** *
* * * * * * ** *** * ** *
* **** * * ******* * ****** * ** *
* * * * *** ** *
* *
*** * * ** ** * = 0;
* * **
* *** * * * ** (b[c] != '\0')
* * *** * * * *** **
* *** * * ***** * ** *** * *** ** * *
**** * * *** * ** **** ** * * * * ** * *
*** *** * ** ** *
* *****
** *** ****** Comparing frequency of ** **
* **
* * * *** * * * (c = 0; c < 26; c++)
* **** * ** ** ** *
* ** ****** *** ** *** * * ** * (first[c] != ***
* * * ** *** * *** *** * ******* * ** * *** * * *** 0;
**** *** ** **** *
* ***
*** * **** ** ** 1;
}

int main(void)
{
*** * ** *** * * * * *** *
* ** * ** *** ** ** * *** * *** *** *** ** *** **
* * ****** ** ** * * * * words or phrases are *** * *
* * ** * * * * words or phrases are not * ***** *

* * ** ****** * *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include **** ** *
#include * ** * *
#include *** * * *
int is_anagrams(char A[],char B[])
{
* * ** * * *** * * YOUR CODE HERE*/
* *** ** * *** * * * ** ** *
* * ***** * * ** ** ** ***** ** * * **
** * ** * * * ** **
** *** ** **** * * ** * ** ** ** ** *** * *** * **** * * && ** ** ** *
** ***** * * * * **** * *** ** ** * *** * * * *** * * ** * ** * *** * * *
* * * ******** *** * **** * **** * * ****** *** * ***** ** * **** * && **** *** * * ** *
* * * ***** ** * * *** *** * * *** * ** ** *** * ****** * * * ** * * *
********* * *
** * * ** *** * *** * **** ***** * **** * *
* * * ** ** *
* * ** ********* * * ** * * * * ** (cA[i]!=cB[i])
* * ** * * * *** * * *** * ****** ***** * ** * *** * *** * ***** 0;
** ***** ** * * ** **** * **
* * **** * * *** ** * * 1;
*** *** **** * ** OF YOUR CODE*/
* *** * * * ** *** function should return 1 if two words or phrases are anagrams,
* * *** *** ** * if two words or phrases are not anagrams.
}

int main(void)
{
**** *** * ****** A[100],B[100];
** *** ** ** * * YOUR CODE HERE*/
** *** * *** * * * * *** ** ****
*** * * ** * *** **** * * ** * ** ** ****
** * * * * * ** *** * (is_anagrams(A,B))
****** * ****** ** * * * * * ** ** * * * * *** * words or phrases are anagrams");
** * * **** * ** ** *** **
*** *** *** **** *** ** ** **** * *** * ******* words or phrases are not anagrams");
* * * *** * * * ** * 0;
** * * *** ** ***** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
*** ** ** ** * ** ** ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * ****** * * **
* * ***** * ** * (A[i] != '\0')
*** ** * * ***
*** * **** * * * * ***** * ** **** * * * ** ** *
* ** * ** * **** * * *** * ** * ** * * * **
** * * * ***** ***
* * **** ***** ** * **
*** * *** * ***** *** = 0;
* * ****** *** ** * * * *
* * ** * ** * * ***** **** (B[i] != '\0')
** ******* ** **** * ** ***
*** ** ****** * *** * *** * * ******* * ** ** * *** *
***** **** ***** **** ** **** * * * ** * * **
* * *** * * ** * * * **
    
***** * * ** ** * * * * * ** ** (i = 0; i < 26; i++)
** * *** * * * * ******
** ** * *** * * ** ** ***** *** ** * (Array1[i] != Array2[i])
*** ***** *** *** * ** * * ** *** * * * * * * ******** ***** 0;
* * * * ** ** *** **
* * ** * * ** ** *
** ** * ***** ** * *** ** * ** 1;
}

int main()
{
** * * * * ** * ***** ** * * A[100],B[100];

* * ***** ***** *** * * * *** *
* *** * ** * * *** * * * *
** * * ****** *** **
* * ************ * **** (is_anagrams(A,B))
** * *****
* * ** * * ****** ** *** *** * * ** *** * * * words or phrases are anagrams");
*** * * * * ** *******
*** * ** ** * * ** * * printf("Two words or phrases are not anagrams");
* * * ** ** * *** ** *
* * ** * * ***** *** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * * ** * ****** ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
** ** * *** * **
** * ** * * * * * ** (A[i] != '\0')
* ** * * * * ** *
** * ***** * ** **** * ** **** **** ** * * *
* ** ******* * ** * ** * * **** **** * *** *
** * * ** * * ** *
* * ****** ** **** ** **
*** *** ** **** *** * = 0;
* * ** * ***** ***
** *** * ** *** * *** * * (B[i] != '\0')
** * ** * ***** * **
* * **** ** ** * ** ** *** ** * * * * ******
**** *** * *** * * * * * * **** ** **** * *
* ** ** * * * * ***
    
*** * *** **** ** * (i = 0; i < 26; i++)
***** * ******* * *
* ** * * ** * * **** ** * *** ** * * * * ** **** (Array1[i] != Array2[i])
**** *** * * *** ******* *** * ** *** * * * ** ***** * * * **** 0;
******* ** * **
** ***** * * * *
**** * * *** *** 1;
}

int main()
{
* * ** ** ** * *** * * ** A[100],B[100];

* * ***** ********* ** * ***** * ** *
** ** * * **** * * *** * ** ** ** * ** * ** * * * * *
* *** *** * *
* * * * ** * * * (is_anagrams(A,B))
** * * * * * **
* *** * * * **** * ** ** *** * * ******* ******* words or phrases are anagrams");
** * * **** ** ***** *** * *
* * ** * *** * * * ** * * printf("Two words or phrases are not anagrams");
** * * * * * * ** ***
** *** * * * *** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** * * **
#include * ** ** **
#include **** * ** ***
int is_anagrams(char A[],char B[])
{
*** * ** *** * ***** * lenA = strlen(A),lenB = strlen(B);
* ** * *** ** * * ** != lenB)
* **** ***** ** ***** * * **** * ** ** * ** * 0;

** * * * * *** * * ** * ***** i,j,k,a[26] ={0},b[26] = {0};
*** * * * * ** *** = 0 ; i < lenA ; i++)
* * * * * * **** * *
* **** ** * *** * * ** *** ** ** * ** ** **** * * * ** = 0 ; j < 26 ; j++)
** * * * ** * * ** *** ** * *** ** * ** * ***
*** ** **** * * * * ** * *** * *** *** *** **** ** * * ** ** * * ** * ** == A[i] || 'A'+j == A[i])
* * * * **** **** *** * * * * ***** * * ** * ***** ***** ** * ** * * * **
** ** * **** ** **** **** * * * * ****
** ** * ** * *** ****
* ** **** *** *** * ** ******* = 0 ; i < lenB ; i++)
* * ** ** ****** * * * * *
* *** * *** ** ****** ** * * * * **** ** ***** = 0 ; j < 26 ; j++)
* ** * * ** * ** ** * ** * * ** * *
** ** ** ******* ** * * * * * * * **** * * * *** * ** * *** * == B[i] || 'A'+j == B[i])
* ** * * ** *** *** * * ******* * * * ** * ** ** ** **** ***** ** * ** * **** *** * * ***
*** * ** * ****** *** *** ***** **** * ** ***
** * ** * **** ** * * *
* ** *** * **** * = 0 ; j < 26 ; j++)
**** * ** ** * * **
* * * * * * ** * *** ***** *** * ** ** ** != b[j])
**** * * **** * ** *** * * **** ** * ** ** ** *** ** * ** *** * ** 0;
* *** *** **** * * * **
* **** ** * * * * ** * * * * 1;

}

int main(void)
{
** * ******** * * A[100],B[100];
** *** ** **** ** * %s",A,B);

*** ** ** * ** **** (is_anagrams(A,B)) * * * * * words or phrases are anagrams");
****** * ** *** printf("Two words or phrases are not ****

*** * * * ** *** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * * *
#include * ** ** ** ****
#include ******* *
int is_anagrams(char A[],char B[])
{
* **** **** ** * * lenA = strlen(A),lenB = strlen(B),i,j,k;
** * *** ** ** * **** * a = 0,b = 0;
* * * **** * ****** **** ** ** != lenB)
*** * * * * * ***** *** * ** **** *** * * 0;
* * **** * ********** * * = 0 ; k < 26 ; k++)
*** ** *** * * ***
** *** ** ** * * * **** *** ** * * **** * ** ** = 0 ; i < lenA ; i++)
** * * ** * * *** ** *** ***** *** *
* ***** * * ** * * * * * **** ** ** *** *** ** * ** * * * == A[i] || 'A'+k == A[i])
** *** * * * * * *** * ** * ** *** * *** * * * ** *** * ** ** ** ** * ***
**** ** * * * ** ** * * * * ** *** * ** * * *
**** ** ** *** * *** * ***** * * * *** = 0 ; i < lenB ; i++)
** ** * * ** * * * * **** * ** ******** **
******* * * * * * ******* * ***** * ** * * * * ** ***** * * == B[i] || 'A'+k == B[i])
* * ******* * ** ** * * ** ** ** ****** * ***** *** * * ****** * * *** * * *
**** ** **** * **** ** * ** *** ** * * ** *** *
* ** * ***** * *** * ** ** *** * * **** ***** != b)
** **** ***** **** ** **** * * * *** ** * **** *** ** **** * 0;
** *** *** * * *** *** **
** ** *** * **** * * *** * ** ** * * * ****** * * ** * * * ********* ** ** * * ** 1;
}

int main(void)
{
**** * ** * ****** * **** A[100],B[100];
* ** ********** ** ***
* *** **** ** *** * *** ** ***
* ****** ***** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*** * ** *** *** *** printf("Two words or phrases are not anagrams");

* * * * **** * *** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * *
#include *** * *
#include ** *** *
int is_anagrams(char A[],char B[])
{
** * * *** * ** *** YOUR CODE HERE*/
** * * * ******* ** i,count[256]={0};
* * ** * * * * * ** * * ** *
** * *** * * * ****** **
* * ****** * * *** ** * ** *** * ** * * * ** ** * *** ****
* * ** * * * * ** **
* * * * **** * * *** *** *****
**** ** * **** * ** **
* **** * ****** ** ** ** ** ** ** ** * * **** ** *** *** * * **
** * * * ** * **** *
/*
*** * * * * * ** * * (A[i]!=0 || B[i]!=0){
** *** * * * *** ** * * *** ***** **** ***** * ** * ***
**** ** *** * * * * ****** ** ***** *** *** * * 0;
* ** *** * * *******
*/ * *** * * * * * ** * *** * * ** 0;

**** *** * * ***** ** (i = 0; i <256 ; i++)
* ********* * * * ***** **** * ** (count[i] && i!=' '){
* * * ** ** *** ** ** * * ** ** * *** **** * * *** *** * * ** * **** * * ****** * * ** *
* ** ** * ***** ** **** **** * * * * *** *** * **** ** * ** * * * * 0;
* * *** ** **** * ** * * * *** ** * * * * **


* * *** * * * ***** * 1;

** ** *** **** * * * OF YOUR CODE*/
* * * *** * * * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* ** ** *** * * *** * A[100],B[100];
** * **** ** ***** ** YOUR CODE HERE*/

** * ** * * *** * * ** * *** **** **
* ****** ** * * ** * * *

* ******** *** * * *** *** * = '\0';
  // *** *** ** ** = '\0';
* * ** *** **** * ** * i;
* * ** * ** * * ** ** *
*** *** ** * * * ******* * *** ** * ** **** * *** * * * * *** *** *** ** **
* * ***** * *** **** *** * * * *** ** *** *
* * ** * * ***** * * * *** *** *
* ** ** * ** ** * **** * * **** ** *** *** * *** **** ***** *** * * ***** **
* * ** * * * ** * * ** * ** * * ** ** ** ****** * ** *

** * * * * ** OF YOUR CODE*/
* * * * * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * ***** * ** * printf("Two words or phrases are not anagrams");

** * ********* * * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** **** * ***
#include * ** * * *
#include * * *** *
int **** * A[],char B[])
{
* * ** * ****** YOUR CODE HERE*/
* **** * ** ** * * ** ***** * * * *
** *** ** ****** * *** * * * * * ** *******
*** *** * * * * **
* * ** * * * * * *** * ***** * * * * ** * * ****
** * * * * * * * * ** * ** * * * **** **
** * ***** ** * ** * **
* ** **** * * (A[i] || B[i])
*** * ** * * * ** * * * **** 0;

* ** * * ** ** * * * * (i = 0; i < 256; i++)
*** ****** ** * ** ** * * * * * *** *** * * ** ***
** *** * ******* * * * ** * * ** **** * ** ***** * * *** ** * ** ** 0;
* * ** * * ** * ** * * * ****** 1;

** ** * ** OF YOUR CODE*/
** ** * *** * * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * **
{
**** ** * * * *** * *****
* **** **** ** *** YOUR CODE HERE*/
* * ** * * ** * ** ** * * *** * ** *** *** ****
********* * ******* * * ******* **** * *

** ** ** ** * ** OF YOUR CODE*/
******* **** * **** * * ** * ** * *** words or phrases are * * * *
* **** ** * * * * ** * * words or phrases are not * * **** * *

* ** * ** ** ** * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * *
#include * *** * * *
#include ** * *
int ** * ** A[],char B[])
{
****** * *** ****** YOUR CODE HERE*/
** * * * * * ** * * * * * **
* ** * ** ** **** * ** * ** * ** ** * *
***** **** *** * * * * *
* * *** * * ********** * ** * *** * * ** * ** *****
*** ** * * ***** *** * * * ** * * ** * *** * *** ** * * * * **
* *** ****** * ***
* ** **** *** ** ** ****** ** (A[i] || B[i])
** *** * * * ** ** **** ** * * 0;

** * **** * **** ** * * (i = 0; i < 256; i++)
* *** * * * ***** * ** *** ** * * * ** ***** *
* **** ** ** * ** ** * *** * * ******* * * * ** **** 0;
*** * * * *** * ***** * * ** 1;

*** * ** * * OF YOUR CODE*/
** * *** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *** **
{
** * * * * *** **** *
** **** * * ** * ** YOUR CODE HERE*/
* **** ** * *** ** ** * * **** * * * ** *
* **** * * * ****** ****** ****** **** ** ***

**** * ** * * * * * * OF YOUR CODE*/
*** ** * *** ** * * * ***** * * words or phrases are ** * * * **
* ** * **** * ** * * * ** *** * * words or phrases are not ******* *

* **** ** ** *** ** * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.8
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.3k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users