0 like 0 dislike
7.4k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 7.4k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * ** * *** *
#include * * **
#include *** * * ***
int * *** ** a[],char b[])
{
* **** * ** * ***** * first[26] = {0}, second[26] = {0}, c = 0;
* *
**** * * *** *** * * * * frequency of **** in first string
* **
*** * * * *** * * *** (a[c] != '\0')
***** * * * *
** ** * **** ** ** *** * ** * * * ** * *
* ** *** ** * * ***** *** * ** * *
* * * ** * ** **
*
* ***** * * * = 0;
* **
* * ** * * (b[c] != '\0')
** **** * *
* ** ** * * * * ** ** ** ** * * * **
* * *** ** * *** ** * * ***
* * * * * *** ** *
***
**** * ** * * * * * Comparing frequency of * * *
** * *
*** ** ** * *** (c = 0; c < 26; c++)
*** *** * *****
* * * *** ** *** * * * ** * *** (first[c] != second[c])
* **** * *** * **** ** * ** ** ** * ** ****** * ** ** ** 0;
******* ** *****
* *
***** * ***** 1;
}

int ** ***
{
* *** * * * ** ****
* ** ** *** *** ****** ** *** * ** A,B);
** *** * * ** ** * * * **** * * *** words or phrases are ** * * *
** * ** * ** * ** ** * * * words or phrases are not * * ***

* **** ** ** ** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * **** * **
#include * * * *** **
#include ** ** * ** **
int * * * * * a[],char b[])
{
* * ***** * * * first[26] = {0}, second[26] = {0}, c = 0;
******
*** * * *** ** frequency of characters in first string
** * *
* * * * **** * * * (a[c] != '\0')
* * * * * **** **
*** * * ** *** *** * **** ** ** * * ** *
*** ** ***** * * * ** * ** *
** * * * ** * *
** *
*** ****** ** * ** * * = 0;
**
*** **** * (b[c] != '\0')
* * ** * * ******
* *** * * ***** * * * ** * * * *
** * ** ****** ** ** ** * *
**** ** * * *
* * * *
* * * * ** * Comparing frequency of * ***
*****
* **** * * **** (c = 0; c < 26; c++)
***** ** * * *
* ** ** * *** *** * ******* **** * * ** (first[c] != * *
** * * ** * **** * ** * ***** *** ** ** * * *** 0;
**** * * *** ** ***
* ** * *
*** * **** * * * 1;
}

int main(void)
{
*** *** *** **** * ** ** *
** * * *** ** **** ***** ** *** *****
** ***** ** ** ***** ***** * ***** * * words or phrases are * * ** * **
** * * * ** **** *** * ** words or phrases are not ** * ****

** ** * ** * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * *** *** *
#include * ****** * ******
#include * * * ** *
int is_anagrams(char A[],char B[])
{
* * ** ***** * *** YOUR CODE HERE*/
** ** * **** ** ** **** **** * *
*** * * * **** * ** ***** * ** *** ** **
* * * ** * ** ** *** ***
* ** * * **** ** ** * * * * ** * * * * * * **** ******* * && * ********* * **
*** * ** * ****** * ** * * * ** ** * ** *** * * * * *
** * *** ** * * ** * * * ** ** * ** **** ***** * * && ************ **
******* * ** *** * * * ** **** *** ** **** *** ** ***** *** ** ***** *
*** **** * ** * *** * **
*** ***** * * *** ** * **** * ** ** ** **
** * * *** * ****
* **** ** * * * * * *** * * **** ** * ** (cA[i]!=cB[i])
** *** * **** **** **** ** * * ** * * * ** ** ** * ** *** 0;
** * ***** ** * * * * **
** * **** *** *** * ** 1;
* **** * **** ***** OF YOUR CODE*/
*** *** * *** ***** function should return 1 if two words or phrases are anagrams,
* ** * **** if two words or phrases are not anagrams.
}

int main(void)
{
* ** ** * ** * A[100],B[100];
** * * ** * * * ** * * * YOUR CODE HERE*/
* **** ** ** * ** ** * * * ******* * * *
* *** ******* * *** ****** **** * ******* *
* ** * * **** * * * (is_anagrams(A,B))
* * * ***** * ** * * **** ** ** *** ** * * ** * words or phrases are anagrams");
** * ******** * * ** ****
* *** * *** * *** ** * ** ** * ** ** * * ** ** words or phrases are not anagrams");
* ***** *** ** ** ** * * 0;
* *** * *** * **** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * ** * *** * ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * ** ** **
** ** **** * * * * (A[i] != '\0')
* * ** * * **** * **
* * * * ** ***** * * ***** * * *** * * ** *
******* * * * * * * * * **** * ** * ** * **
* * * * * * **
** ** ***** **** ***
**** ** * * ** * = 0;
* *** ** ** **** *
* **** *** ** * * (B[i] != '\0')
** * *** * ** * ** *
* *** ** * * * ** * * * * ** *** * ** *
* * ** *** ***** * ***** *** * *** * * *** ** ** *
* * * **
    
*** ** **** * *** ** (i = 0; i < 26; i++)
* ***** * * * *****
** * *** **** * * ** *** * (Array1[i] != Array2[i])
** * *** *** * * * * ** ** * * **** *** **** ** * ** * ****** 0;
** * ** * ** * ** *** **
* ***** ****** ** **
**** ** *** * * * *** ** 1;
}

int main()
{
**** * *** * ** A[100],B[100];

**** * ** * ** *** * *** * * * *
** ** *** * * * ** **** * *
* ** ** *
****** * * ** * ** ** ** (is_anagrams(A,B))
* * *** ** ** * * *
*** *** ** * **** * ** ***** * *** **** **** * * ** * words or phrases are anagrams");
* ** ** * * * ** *
* ** **** *** **** printf("Two words or phrases are not anagrams");
* * ** ** ** *** * ***
*** ******** * ** ** * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
**** ** **** * * *** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * ** * * * *
*** * * * ** ** ** ** * * (A[i] != '\0')
* ** * * * **
* * * ****** ** * * *** * ** * *** ****** * * ***
* ** **** * **** * ** ** ** * ** * * * *
* * *** ** * ** * *
* * *** ** ***
* * * * ** ** * *** ** = 0;
* ***** * * * ** * * *
** ** ** **** * * ** (B[i] != '\0')
**** * ** *** * * * * *
* * *** * ** *** **** * ***** * ** * * ***** * ****
* * ***** * *** ** ** ** * * * * * * ****
* **** * * *** *** ****
    
** ********* ** ** * ** ** (i = 0; i < 26; i++)
** * * **** * ** *
**** * *** * * *** * * *** *** * ** * (Array1[i] != Array2[i])
*** ** * * *** * * * * * * ** * * * * * ** ** 0;
* * * * *** * *****
* **** * * ** ***** *****
* * ** * * **** **** *** * * * 1;
}

int main()
{
** ** * * * ** *** * * * A[100],B[100];

* * * * ** ******* *** * ** ** *** * **
** *** ** *** * ***** ****** *** *** ** **** * * *
** ** * * * * *** *** *
** * * * ******* * * * (is_anagrams(A,B))
* **** * **** **
* * ** ***** * * * ** * * ** ** ** ** * ***** * words or phrases are anagrams");
* **** ** * * ** *
** * **** * *** * * printf("Two words or phrases are not anagrams");
**** * * * * * ** *** *
* **** ** * * *** ** * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** **
#include ** * *** **
#include * * * ** *
int is_anagrams(char A[],char B[])
{
****** ***** ** * * ** lenA = strlen(A),lenB = strlen(B);
*** * ********** *** ** != lenB)
** * * *** * * ** ** * * ** * ** 0;

** ** * * ** *** * * i,j,k,a[26] ={0},b[26] = {0};
** *** ** *** * ** * *** * = 0 ; i < lenA ; i++)
** * ** *** * ** *** * **
** * ** * * * ** * * ** * ** * * = 0 ; j < 26 ; j++)
** * ** * * **** ** *** ***** ** ** * *
** * ** * ** ** * * ** * * * ******** *** ** * ** ** * ** * **** * **** * * * ** == A[i] || 'A'+j == A[i])
*** * **** * * * ** * * * ******** *** *** *** * * * ****** ** * ** * ** * **** **** * * ****
** * ** * * * ***** ** *** * ** * * ** * * * **
* ** ** * *** * *
* ** **** * * * * **** = 0 ; i < lenB ; i++)
** *** * *** * * **
* * * ***** * ** *** * * * * **** *** ** * * * * = 0 ; j < 26 ; j++)
** * ****** * ***** * * ** ** **** *
* ** * ** * * * * ** *** ** * *** ** **** ** * ** * **** * ** ** * * == B[i] || 'A'+j == B[i])
* * ** ** * **** * ** * * * ***** *** ** * * * * ** * * * * **** ** ** ** * ** *
* * * * ** * * * * * *** * ** ****
*** ** * ** **** *
******* * * * * * * * = 0 ; j < 26 ; j++)
* *** * * * * * *** **
** * *** * * *** ** * *** * *** **** ** * *** * != b[j])
* * * **** **** **** * * * **** **** ** *** ** * *** * ** * * *** 0;
**** *** * **** * *
******* ** ** *** * * * 1;

}

int main(void)
{
* * ****** **** ** ** A[100],B[100];
**** * *** * * ** * ** *** %s",A,B);

**** * * ** *** (is_anagrams(A,B)) * ***** words or phrases are anagrams");
* * *** * *** * printf("Two words or phrases are not * * * * ** *

* ** ** * ** ******* ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ****** **
#include ** *** * *
#include ** **** * * ***
int is_anagrams(char A[],char B[])
{
**** * * * ** ** * * lenA = strlen(A),lenB = strlen(B),i,j,k;
* ***** * ** * **** *** * *** a = 0,b = 0;
* * *** ** * * * * != lenB)
* * *** ** * **** ** ***** * * * ** ** **** * 0;
*** ** ** ** ** *** *** = 0 ; k < 26 ; k++)
** **** **** *********** *
** **** * *** * * * ** * * * * ** *** = 0 ; i < lenA ; i++)
* * * * ** ***** * ** ***** * * ** ***
**** ********** * ** ** * ** * ** * * * ** ** *** *** * ***** ** == A[i] || 'A'+k == A[i])
** * * * *** ****** * ** * *** * **** ** * * ** * ** ** * ** * * * * * ** * *
* *** ******* *** * * *** * * ** * * **
* * * **** ********** * * *** ** ** * ** **** * **** = 0 ; i < lenB ; i++)
* **** * ** * **** ** *** * * * ***** * * ***
* * ** ******* * * * * **** **** * ** *** ** ** *** ** ****** ***** * == B[i] || 'A'+k == B[i])
* ** *** ** ** ** *** ** * ** ** *** *** *** * ******** * ** *** **** * * **** * * * * * * *
***** *** * * * * ** * ** ** ** * ** *****
* * * *** * * * * * * * ** *** * * != b)
*** * * * * * ** * ** **** * * * * * * **** * * *** * 0;
* ** ** * * * *** *
*** ***** ** * * * * *** ** * * ** ** * ** **** * * ** * ** * 1;
}

int main(void)
{
* * * * * * * A[100],B[100];
** * * * * * * * ** * ** *
**** **** * ** ** *** *
**** ** *** * *** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** ** * * * * * printf("Two words or phrases are not anagrams");

* **** ** ** ** * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * * **
#include * * * *** *
#include * * * *
int is_anagrams(char A[],char B[])
{
*** * * ** * ** * YOUR CODE HERE*/
* *** * ** ** **** ** i,count[256]={0};
**** ****** **** *** * * * *** *
* * * ****** *** ***
*** ** *** * * ** **** * **** * ** ** **** ******** * * ** **** ** ** *
*** * *** * * ** * *
** * * *** * * *** ***** ** **
** ***** *** * * * ** *
** * * * * * * *** * ** *** *** **** * * ** ** ***** *** * *** **
*** * * ***** *
/*
*** *** *** (A[i]!=0 || B[i]!=0){
** * **** * * * **** ** ** * ** *** * * * * * * * **
* * ** * * ** ** * * ** * * ***** ** * *** * * ** 0;
* ** * ** ** * **
*/ *** *** *** * ** * * *** ** ** * * 0;

* *** ** * * * ** * *** * * (i = 0; i <256 ; i++)
* * * ** ******* * ** * ******* * ** * ** ** (count[i] && i!=' '){
** ***** * * *** *** ** * * *** **** * * ** ** * * *** * * ** * ** * **
* *** ** * * * * ** ** **** *** * * * ***** ** ** *** ** ** ***** **** 0;
***** ***** ** * * ** * *** * *** * ** * *


** ** **** ** * * * ***** ** 1;

*** *** *** * *** ** OF YOUR CODE*/
** * ** * * ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* *** **** * * * * A[100],B[100];
***** ** * * ** YOUR CODE HERE*/

* * ** * ** **** * ** * * *
* * * *** ** *** * *** * * * *

** **** ** * *** *** = '\0';
  // ** * *** = '\0';
*** *** ** ** ** * * * i;
* * ***** ** ***** * ** * * **
* * * ** * **** ** * * * ** **** *** ******* ***** * ** **** * ** *** *** *
* * ** ** * * * * * ********* ** ** * * * * * * * *
**** * ** * ** * ** **** * *** * ***
***** *** *** * **** * * ** ** * *** ***** ** * * * ***** *** ** * *
** ** ****** * * * ** * * * * ** * * * *** * * ******

** * ***** * * ** OF YOUR CODE*/
*** * ***** * **** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** ***** ** **** ** printf("Two words or phrases are not anagrams");

* * ***** * * ** * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ***** * **** *
#include ****
#include * **** * * *
int *** ***** A[],char B[])
{
* * *** * * *********** YOUR CODE HERE*/
** * ** ** *** * * ** * * ** * *
*** * ** **** * * * *** * *
** *** * ** *** *
* * ***** ** * * ** *** ** ** * *** ****** *** *** * * **
** * * * * ** ** * ** * ** ** * * * *** *
** * **** * * * ** ** * ****
*** ***** * * * ** * ** (A[i] || B[i])
** **** ** * ** ** * * * *** ******** ** 0;

*** * **** *** * **** (i = 0; i < 256; i++)
* ** ***** **** * ** ** * * * *** * *** *
* * ** ** * ** * *** ** ****** **** * ** ****** * ** * ** * * 0;
** *** * * * * * * 1;

** * ***** OF YOUR CODE*/
* * * ** *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
* *** * ** ** * ** * **
*** * **** *** YOUR CODE HERE*/
* * ** ** ** ** ** * **** * ** ******
* **** ** ** * *** ******* ** *

**** ****** ** * OF YOUR CODE*/
* * ** **** * ** * * ** * * *** * words or phrases are * * **
** **** * ** ***** * words or phrases are not *** * * *** ***

* * * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * *
#include ******* * ** *
#include * * ***
int *** * * A[],char B[])
{
* * * **** ** ** * * **** * YOUR CODE HERE*/
*** ** ***** * * * ** ** * ** *
* * * * **** * ** ***** * ** ** **
***** **** ** ** * * **
* *** * *** ** ** * * ** ** * ** * * ** ** * *
*** * ***** * ** ******* **** ** * * **** * * **** *
*** * * ****** ** * **
** **** * ** **** * ** * ** * (A[i] || B[i])
* * ****** *** * * * ** ******* * 0;

** **** ** *** * * * (i = 0; i < 256; i++)
** * ** ** * ******* ** **** * *** * *** *****
* ***** * * *** ** * *** ** ******* *** * * * *** * * * *** * ** ***** 0;
*** * **** ** * ** **** ** 1;

** * * ** *** * OF YOUR CODE*/
** ** ** **** * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** * **
{
** *** *** *** **** * ***
*** * *** * ** *** YOUR CODE HERE*/
** * *** ** **** ** * *** * ** **********
** ** * * * * * * **** * * *** * **

** * * *** ** * ** OF YOUR CODE*/
**** ** *** * *** ** ** **** ** ** ** ****** words or phrases are **** * *****
** ** *** ** * ** ** **** words or phrases are not ** * *****

* *** * * * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.126
©2016-2024

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 3.6k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 3.8k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 3.2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users