0 like 0 dislike
19k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 19k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include *** ** ****
#include ** * * ****** *
#include *************
int *** **** a[],char b[])
{
**** ** ** * * * * first[26] = {0}, second[26] = {0}, c = 0;
**** ***
* * * * * ***** frequency of *** * in first string
***
**** * * * ** (a[c] != '\0')
* ** * * ** *
* * * * * * ****** * * * **** * * *** ** ***
* ** * ********* * ** *
* * * ** ** ***
* *
*** **** ** *** * * = 0;
****
** ** * ** * * (b[c] != '\0')
* ** * ** ** *****
* **** ** *** * ** ** ** *** * ****
* *** **** *** * * ***** **** *** * *
** **** *
* **
* * ** * ** * * Comparing frequency of * *
** *
** ** * ** * * * (c = 0; c < 26; c++)
* * ***** ***** *
** * *** * ** ** * *** * *** ** * (first[c] != second[c])
** * *** * **** ** * * ** *** *** ****** * 0;
* * ** * ** * *
* * *
* * *** * * ** * 1;
}

int * ***
{
** ** **** * * *** *** * *
** * * ** * *** *** ** ** A,B);
* *** *** ****** ** * ** ***** words or phrases are ***** * *
** ** ** * * * *** * * words or phrases are not * *

** ** ** *** ** ***** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * *** *
#include ** *** *
#include **** ** * **
int ** * ** a[],char b[])
{
* ** **** ** * * * first[26] = {0}, second[26] = {0}, c = 0;
* * ****
* * * * * frequency of characters in first string

* * **** * * * (a[c] != '\0')
** * ****** *
* *** ** **** * * * ** ** ** * * ** ** ** * *
* ** * ** ** * ** ****** ** *
* ** * * * ***** *

* * = 0;
** * *
* ** *** **** ** * * (b[c] != '\0')
* ** * *** ** * *
** * ** * ** **** * ** * **** * *** * * **
* * ****** *** *** * * *** ** * *
** * *** ** *** *
* **
* * * *** * * * *** * Comparing frequency of * ***
********
* * * * * * * ** (c = 0; c < 26; c++)
* **** * ********
** * * * ** **** * ** * ***** (first[c] != *
** **** ** * ** ** * **** * * ** **** *** ** * * *** 0;
**** * *
* *
* ** * ** *** ** ** 1;
}

int main(void)
{
* * *** * ** ****** **
**** *** *** **** ** * *** * **** ** ***
** **** ** * ***** ** ** *** ******** words or phrases are *** ******
* *** ** * ** * ******** words or phrases are not *** * ***** *

* * * *** ********* * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * ** ** ** ****
#include * *** * ***
#include ** ** ******
int is_anagrams(char A[],char B[])
{
** * * * * * * * YOUR CODE HERE*/
**** ** * ** * * * * **** ** ** * **
* *** ****** * * ** * * * * * ***** *** ** *
** * * * * * * ** * **
** * * **** ** ** ** ** * ** * ** * * * ** * * * ** ** && *** **** * *** *
** ** *** **** * ****** * * ***** **** * ** * * * * * ** *** * ** * * **** *
** ** ** ** **** **** ** * ***** * * * * ** * *** ** * ** && **** *** * ***
** *** * ** **** ** * *** ** * ** * ** *** ** * ** * ***** ** *** * **** **** * ** * ***
* * **** ** * * ***
*** * *** * ** *** ** ************
* * *** * ******* * *** ** *
* ** ** * * * * ** *** * * ** ********** (cA[i]!=cB[i])
** ******* ** * ** *** * ***** * * * ** * **** *** *** *** *** *** 0;
** * * * **** * **
** * ** * **** ** ****** ** 1;
* ** * * * * *** * OF YOUR CODE*/
***** ** ***** * function should return 1 if two words or phrases are anagrams,
** * ******* * * if two words or phrases are not anagrams.
}

int main(void)
{
** **** ** * * *** * A[100],B[100];
* * * **** ** * **** * YOUR CODE HERE*/
* ** ****** **** *** ** * * * **** *****
* * ** * * ** * * * **** ** * * ** * * **
* ***** * * ** ** * ** * (is_anagrams(A,B))
*** * * *** * **** ** *** ** * *** **** ** * ** ** ** words or phrases are anagrams");
* * ** ** * ** ******
** * **** * * * ** * ** *** * * ** ** ** ** words or phrases are not anagrams");
* ** ********* * * ** ** * 0;
* * ** *** ** ** ** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** * ***** * ** ***** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * ** * * ***
*** ** * * * *** * (A[i] != '\0')
* ** * ** **** *** ***
* * ***** *** * * *** * ** * * * ** **** * ** * * *
************ ** * **** * * *** * *** * ** * ** *
* * * * * *
** *** * * * *
** * ** *** **** *** = 0;
*** * * *** * ** **** *
* *** * ** * *** * **** (B[i] != '\0')
* *** ** **** * ** *
*** * ***** ** ** ***** ** ** **** ** * * **
*** ** * *** * * ************ * * ***** ***** * ***
** ** * * ***** ** * **
    
***** ***** *** * ** * (i = 0; i < 26; i++)
** **** * **** * ** * *
*** ** * * ******* * ** ***** * ** * * * (Array1[i] != Array2[i])
* * * * * * * * *** ** ** ** *** *** * ** ** ** ** *** * * * ** * * 0;
** **** **** * * *
* ** * ** *** **** ** **
** * * ** * *** *** ** 1;
}

int main()
{
* ******* *** ** * ** ** *** ** A[100],B[100];

* *** * * ***** * *** *** ****
** * ** * * * * ** * *****
* ** ** * *** ** *****
**** **** *** ** * * * * * (is_anagrams(A,B))
* * ** *** * *** *
**** * ** ** * ** * * *** ** * * ** ** ***** ** *** words or phrases are anagrams");
* ** ** ** * * * ***** **
* *** ** ** * *** printf("Two words or phrases are not anagrams");
* ** * * *** ** ****
** * ** * * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * ** ** * * ****** **** Array1[26] = {0}, Array2[26] = {0}, i = 0;
**** * * * ** * ****
* ** ** * * * **** (A[i] != '\0')
* ***** * **** * ** ***
* * * * * *** * * *** * * ** * ** **** * * ** ***
* * ** ****** * * * *** * ** * * * **** *** *
* * * ** **** * *
* * * *** *** **** *
** * * * * * ** * * = 0;
* * * * * *** * ** *****
* ** **** * ** * **** * * (B[i] != '\0')
* ** * ** * ** * *
* ** * * **** **** ** *** *** *** * *** *** ***** ***
*** * * ** *** ****** * * ** ** * *** *
** **** * ** * * *
    
* *** * * ** *** * * * (i = 0; i < 26; i++)
*** ***** * ** *** * ******
*** * ****** ***** * ** ** ** * ** * (Array1[i] != Array2[i])
* * * * *** * ***** * * ** ** * ********* * * ** *** ** *** * *** *** 0;
** * ** * ** **** **
** **** * * ** ** ** *
* *** * ****** * ** ** ** 1;
}

int main()
{
** *** *** * *** ****** A[100],B[100];

** ** ** ** **** **** **** ****** ** * * **
***** * * *** *** * * * * ** * *** *******
* * * ** ** *** *
*** *** ** ***** * ** (is_anagrams(A,B))
* ** *********** ***** ** *
* * ** * * ***** * *** * *** ** * * ** ******* words or phrases are anagrams");
* ** * *** ** * * * *** *
* *** *** * * ***** * * ** *** printf("Two words or phrases are not anagrams");
* ** * ** *** * ****
** * * * * *** **** * * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** **
#include * * ***
#include ** * * * * **
int is_anagrams(char A[],char B[])
{
* ******* ** *** lenA = strlen(A),lenB = strlen(B);
* ** * * * ** ***** * ****** != lenB)
* *** * ** ** **** * ** * * * * *** 0;

* **** ** ** ** * * i,j,k,a[26] ={0},b[26] = {0};
* ** ** * ********* ***** = 0 ; i < lenA ; i++)
* * * ** * *
* ** ***** ** * * ** * * * ** * ** * **** * = 0 ; j < 26 ; j++)
** * ** *** ** * * ** * *** **** * * * ** * ** * **
* ******* ** *** * *** * * * * * * ** *** ***** * *** ** * ** ****** == A[i] || 'A'+j == A[i])
*** ** ** ** * *** * ***** ***** * * *** ******* * * * * * * ***** *** * *** ***
** ** * * * * * * ** * * * * ** *** **
* *** ** ** **
* ** * *** * * **** * = 0 ; i < lenB ; i++)
** * ** ** ** ** * ***
* * * * * * * * ** *** * ** ***** **** * * = 0 ; j < 26 ; j++)
** *** ** * * **** ** * * * ** ** ***** * *
* * * * * **** * * **** ** * ** * * * ** ** * ** * * * ** * == B[i] || 'A'+j == B[i])
** * ****** ** * ***** * * * *** * * * * ***** ** *** ** * * ** * ** *** * * * ** * **
* * * * *** *** * ** * ** *** *** * *** *
** ***** * ** ** * ***
* * ** *** *** * *** * * = 0 ; j < 26 ; j++)
* * * **** *****
** * * * * * * ** * ** * * * * * * * * != b[j])
** * * * *** ** ** * *** ** ******** * **** * ***** ** * ** **** ** 0;
******* * *** ****** *
** ** ** ** ** ** * * ****** 1;

}

int main(void)
{
* *** * * * A[100],B[100];
*** * ** * *** * * * * %s",A,B);

* * ** *** (is_anagrams(A,B)) * * words or phrases are anagrams");
** *** * * ***** * printf("Two words or phrases are not * ******* ***

****** *** * * * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ***** **
#include * *** *** * ***
#include *** * *
int is_anagrams(char A[],char B[])
{
** * * ** * *** ** * * lenA = strlen(A),lenB = strlen(B),i,j,k;
*** ** * * *** *** ** ** * * a = 0,b = 0;
* ** *** ****** ** ** != lenB)
* *** * ** **** * ***** **** *** ** ** * 0;
*** ** ** **** * ** * = 0 ; k < 26 ; k++)
* * ** *** **** *
*** ** ** ** *** * * ** * * * * * ********** = 0 ; i < lenA ; i++)
**** * * *** * * * * ******* ** ** * ** *
* * * * ** * ** ***** * * ** ** ** ******* * * **** * * * * ** == A[i] || 'A'+k == A[i])
* * ** ** * * ****** ***** ** ** * * * *** ** * * * **** **** ** * * ** * ** ** *** ** ** ** ** * ** *
* ***** ** ** ***** * * ** ** ** ** * *
* * ** * *** *** *** ** **** ** ** ** = 0 ; i < lenB ; i++)
* *** * ** ** *** ** * **** ***** ** *
** * * ****** * * ** * ** ***** * ** *** *** *** * * ** * * ** * ** * *** == B[i] || 'A'+k == B[i])
* * * **** * ** ** * ** * *** * * * * * **** ** * *** ** * * * * * **** * * * *
* * * * * * * ** *** ** ** ** ** * * **** *
*** * ******* * * * **** * ** *** * *** * ** != b)
* * * ** * ** * ****** ***** * * * *** ** * *** * ** * *** *** ** 0;
** ** ** ** *** ***** *
** * * ** *** **** * * *** * *** *** * ** ** * ** ** ** 1;
}

int main(void)
{
** * * *** * ** * *** A[100],B[100];
* ** * * **** **** * **
* * ****** * * ** * * *
* * * ** **** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* **** * * * * printf("Two words or phrases are not anagrams");

* * ** *** ** * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** *** * ** *
#include * * * * ***
#include *** * * ***** ** **
int is_anagrams(char A[],char B[])
{
* **** * * ** ** * YOUR CODE HERE*/
* * ** ** * *** *** *** i,count[256]={0};
** ** * * * ****** ** * *
* *** *** ******** * **
* ****** ** * **** * ****** *** * ** * ** * * ** ** * * *** ** *
** * **** ** * **** * *
* * * * ** * * ** ** *
* * ** ** * ** **
* ** *** * ** **** * * * * **** * * ****** * * * * ** * ******* ** *
****** ** * * ** * **
/*
* * ******* *** **** *** * (A[i]!=0 || B[i]!=0){
** *** ** ** * * * * ** * * ** ******** *** ** *** ** * ** ** * *
* * ***** * * ** ** *** *** 0;
** * ** * * ** * *
*/ * * ****** * * *** * **** ** 0;

*** ** *** * ******* (i = 0; i <256 ; i++)
*** * ***** ***** * * *** *** * * ** (count[i] && i!=' '){
* *** * * * ** * * * **** * * ***** ** ** * * * ** **** * * ** * * * * **
* ** **** **** ** ** *** * **** ** ** ** * *** * * * * * * **** 0;
** * *** ** ** *** * ** *********** ** **


* * * * ** ** ** *** ** * ***** 1;

* * * ** * * * OF YOUR CODE*/
* ** * *** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
*** *** * * A[100],B[100];
***** * * *** * * * YOUR CODE HERE*/

* * * * * **** * **** *
** * ***** ** ** ** * ** *

* * ****** * ** ** * * * * = '\0';
  // * * ** * * * * = '\0';
** ** *** ** ** * * * * i;
* ****** * ** ** * * ** * ****** **
* * ** ** * * * * * * * ** ** ** * ******** ******* ** *** * *
** ** *** **** *** ** ** * * * * * * **** * ** ***
**** ******* **** * * **** ******** ***
* * **** * *** *** ** ** *** ** * ***** ** * * ***
** * *** * * **** ** * * ** * * *** **** **** **

** **** * * * ** OF YOUR CODE*/
*** ** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
******* * * * * * printf("Two words or phrases are not anagrams");

* * ** * * ** ***** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *** ** ** **
#include * ** * *****
#include *** * * * **
int ** * A[],char B[])
{
* ** * * ** *** * YOUR CODE HERE*/
** ** *** **** ** * * * * * * *
* *** **** * * ** ** * *** ** *** * ** * **
* * * * * * * * *
* * ** ** * **** * ** ** * * **** * ** * ** *
*** **** * *** * * ** * ** ** * *** *** **
* ***** * ** * *** ** ***
***** * ** **** ** * (A[i] || B[i])
* * ** * ** * **** * * * ** *** 0;

** * ****** ** * * * *** (i = 0; i < 256; i++)
** ********** * ** * * * * * ** * * * ** **
* ** * ** **** *** * * * * ****** * * * *** * * ** 0;
***** * * *** ** ** * ****** 1;

**** * ** ***** ** OF YOUR CODE*/
*** * *** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ***
{
* ** * ** * * * **
* ** * * ** * * * * YOUR CODE HERE*/
* * * **** ** *** * * **** * * * *** * *
* *** ** *** * * **** ** *** * ** **

* ** ** **** ** * OF YOUR CODE*/
* * * * * * * * * ******** * words or phrases are *** ***** *
* ** ********** * **** * * ** * words or phrases are not ** * * *

* * ****** ** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * ** ** **
#include *** * *
#include * * * * ******
int **** * * A[],char B[])
{
* * ** *** * * ** YOUR CODE HERE*/
* *** * *** * * * * * ***** * *
*** * * * * * * *** ** *** ** *
** * * * * ** * * *
* * * * ******** ** ** ** * * * * * *** *** *
** * *** ** ** *** * * ** * * * ** **** ** * ** * *
* *** *** * * * ** *
*** ** * ** * ** * * (A[i] || B[i])
* * *** ****** ** * * * * * * * * 0;

** ****** * * * * * (i = 0; i < 256; i++)
** * ** ** *** ***** * * *** * **** * * ****** *** * *
* ** ** * ** * * * * **** ** ******** **** **** ** ** * * ** ** * 0;
** *** *** ** ** **** * 1;

* ** * * * ***** * OF YOUR CODE*/
* **** * **** *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * * *
{
* ** **** ****** * ** *** *
* ** ** ** ** * YOUR CODE HERE*/
**** * * * *** ** ***** * * *** ******* ** *
**** * *** ****** * * ***** *** ** ** **

* ** ** * * ** * OF YOUR CODE*/
** * *** ** ****** * * ******** ** words or phrases are * ** *****
*** ** * ** ** * ** ** * *** ** words or phrases are not * ** * ****

* ** * * * *** * *** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.38
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.7k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.6k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 8.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users