0 like 0 dislike
3.7k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 3.7k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * ** ** *
#include *** ** * * ** *
#include ** *** * ***
int **** ** * a[],char b[])
{
**** * ** *** ** first[26] = {0}, second[26] = {0}, c = 0;
*
* ** * * * **** ** *** *** frequency of *** in first string
* **
* **** * * (a[c] != '\0')
* ** ** **
*** * * *** * ** * ** * **** * ** ***
** * ***** ** * ** * * * *** *
* ****** * ***** ***
* ***
** **** * ** = 0;
** *
** *** ** ** * * * (b[c] != '\0')
* *** ** *
** * **** * * ***** * * **** * * *** *
* * * * ** ** *** *
* * * * **
** * **
** * * *** * * * * Comparing frequency of ** ***
* *
** ** * ** ** ** ** (c = 0; c < 26; c++)
*** *** * * * *
*** ****** * * **** * * * * * * * (first[c] != second[c])
*** * * * * ** ***** * *** **** * ** * * * * * * 0;
*** ** *** ***
** *
** * * * * ***** ** 1;
}

int ****
{
*** *** * * * * * ** * * *
** * * * ** * ** **** * ** A,B);
* ** ** * * * ** * * * * ****** * * words or phrases are * *
* ** * * * * * ** *** words or phrases are not *** ** ****

* * * * * * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** ***** * *
#include *** * *
#include ** * *
int * * * a[],char b[])
{
* *** * * * ** * * * first[26] = {0}, second[26] = {0}, c = 0;
* ****
* ** ** ** ** * frequency of characters in first string
** * **
** ** ** * ** * * (a[c] != '\0')
* ** **** * **** **
* * * ** ** * ** * *** ** **
* ** ****** ** ***** * * * *** * * * *
*** *** ***** **
** * *
*** * * * ****** = 0;
* * * *
*** * * *** * * (b[c] != '\0')
** * * *** * * * * *
* **** * * *** * ** * ***** ** **** *** *
* * * **** **** ** ** * * * *** **
** *** ** *
******
** ** ***** ** * Comparing frequency of * **
** **
** ***** **** (c = 0; c < 26; c++)
* ** * * * * **
*** ** ** *** * * ** *** * (first[c] != * * **
** * ** ** * *** * * * * *** ** ******* * * ** ** * * * 0;
* ** *** ******** *
*
* * ** ** ** 1;
}

int main(void)
{
** ** * *** ** * * * ** ** *
** *** * * * * * * * * * *** * *** * *
* * * *** * ** * * * * ** * ****** words or phrases are * * **** *****
* * * ** **** * ** * ** * ** words or phrases are not * ** * ** *

******* * * ** * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * *** ***
#include * * * * **
#include * * ***
int is_anagrams(char A[],char B[])
{
* ** ***** * ** YOUR CODE HERE*/
* * * * * * *** *** ** *
*** * ** * *** * * * * **** * * *
** ** ** ** * * *
*** * *** *** * * ** * ***** *** ******* * * ***** * * * * * && * * * * ** *
*** * * ** * * * *** ** * * * * *** ** *** * ** ** * * *** **** *** * *
* * * ** * ** ** * * *** * * * **** * ** * * ** * ** *** && * ***** ** ****
* * * ****** ** ** * ** ** * * * *** * ** * * ** ** ** * ** ***** * * *
*** * **** * * **
* **** * * ** * **** * **** **
* **** ** ** ** * **
***** * ** ** ** *** * ** * * ** * * * (cA[i]!=cB[i])
*** ** ** ** ** * ** * * *** *** *** ** *** *** * ** * ** ** * *** 0;
* * * * **** * * **
* * * * ***** * *** * *** 1;
*** ** * ** * * OF YOUR CODE*/
** * * ***** * * ** * function should return 1 if two words or phrases are anagrams,
****** ***** * ** if two words or phrases are not anagrams.
}

int main(void)
{
* ** * ** ** * A[100],B[100];
** * *** **** YOUR CODE HERE*/
** * *** * ** ***** ** * * * ***** * * * *
* ** ** *** ** **** * *** *** * * * **
* ** *** ** ****** * * *** ** (is_anagrams(A,B))
*** * ** **** * * * ** * * * ******* words or phrases are anagrams");
* ** ** * * * * * *
** ** * ** *** *** ** ** * ** *** ** * * ** words or phrases are not anagrams");
* * * *** ** **** ** ****** 0;
* *** * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * ** * *** ** ** *** * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
*** * ** * ** **
* **** ***** * **** **** * (A[i] != '\0')
* *** * *** * *
** *** * * *** * ** * ** * *** * ** * * * *** ** ****
* ** * * *** * ** * *** * ** * * * *
* ***** * * ** * **** * * ****
** * * * ** *** * *** *
*** ******* *** * * * = 0;
* * * ** * * * * * ** *
* * *** * * * * * (B[i] != '\0')
*** ** * *** ** * *
* ** * ** * * ** ** * *** * * * ** ** ***** ****
** * *** * ***** * * * * *** ** ** * ****
* ** *** * **** * **
    
* * * * * * * * * ** * * (i = 0; i < 26; i++)
* * * **** * ****
** * ** ** **** * * * * * * *** * **** * * ** **** (Array1[i] != Array2[i])
******** **** * ** * *** *** * *** **** * ** * ** * ** * 0;
** * ** ** *** *
** ****** *** ** * * ***
* * * ******* * ** * * *** 1;
}

int main()
{
* * * * * * ******* * A[100],B[100];

** ** ** * * **** *
* ******* * *** *** * * *** ** ****
* ** ****** * * ** * *
*** ** * *** ** (is_anagrams(A,B))
** * ***** * ***
*** ** * * * ** ** * * ** * *** * * * ** *** ** ***** *** * * words or phrases are anagrams");
* * ** *** * ** ** ** *
* **** * * * * *** * ***** printf("Two words or phrases are not anagrams");
* * * ** ** * * * * * *
****** ** ***** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ***** * *** **** ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
*** * * * * * * * * **
* * *** ** ****** * * * (A[i] != '\0')
* * * ** ** *** ** ** *
* * * *** ** *** * * * ***** * ** * * * * * ** **** *
* * * ******* *** *** ** * * * ** ** **
****** *** * * * ** **
*** ** * * *
** ****** ** ********* = 0;
*** **** ** * * *****
** * *** ** * * * * *** * ** (B[i] != '\0')
**** **** * * * * * ** *
** ** * * ** ** **** *** ****** *** * **
* ** * * * * ** * * * * * **
**** * *** ** *** *
    
*** * ***** ***** * * ** * (i = 0; i < 26; i++)
* * ** * ** ******
** * * *** ** * ** ** ** * *** * ** * * ** * * (Array1[i] != Array2[i])
** ** * * * *** ** * ** * **** ** ***** * ** * * ** * * * * * 0;
* * * * * * *
* ** ** * * ** *
* ** ********* ***** * * 1;
}

int main()
{
** * *** ** ** *** A[100],B[100];

*** * * * ** * *** ** * * *** * *** **
**** * * ** * * * ********** * * ***** * *** *
* * * * * * * * *
* * * * ** * ** * (is_anagrams(A,B))
* * * * *** * *
**** * *** *** **** * ** * ** ** *** * ** * * *** **** * ** words or phrases are anagrams");
******** ** * * *******
** * ** ** *** * printf("Two words or phrases are not anagrams");
* ** * * * * ***
**** * * *** * ** ****** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * **
#include ** ** * * **
#include * **** * *
int is_anagrams(char A[],char B[])
{
*** * *** * * * ** * * * * lenA = strlen(A),lenB = strlen(B);
* * * * *** * * *** ** *** != lenB)
**** ***** * ** * ** *** * * * * * * ** * ** * 0;

* *** * * * * *** ** *** * i,j,k,a[26] ={0},b[26] = {0};
* ** * * * * *** * * = 0 ; i < lenA ; i++)
* ** * ** ** ** **
* ** * *** ****** *** *** * **** ** ** = 0 ; j < 26 ; j++)
* ** ***** ** * *** * ** * ** * *** ** **
* * *** ** **** ** *** * ***** *** * * ** ** ** * * * ** * * * == A[i] || 'A'+j == A[i])
** * * * *** *** * ** * ** * ** * **** *** * * ** *** *** *** *** ******* ** * * ** *
* * **** *** * * * ** * *** *** ** * ** * ** ** ***
**** ** ** * ** * ** *
* * ***** * * * ** * * *** = 0 ; i < lenB ; i++)
* ***** * * ** ** *
* **** * ** * ** *** ******** * *** * * **** *** * * = 0 ; j < 26 ; j++)
*** * ** * ***** *** ** * * * *** ***** ** ** *
** ***** * * ** ** * ** * ** * *** * **** *** *** **** *** == B[i] || 'A'+j == B[i])
**** * ******** * ** ** * *** * ** * ** * *** * ** * * * ** **** * ***** * *** * ** * ** **** *
* * * ***** * ** *** ** ** ** * ***** *
*** * * * *** * ** ***
* **** *** ** ** * * *** = 0 ; j < 26 ; j++)
* * ** * ** * *****
*** * **** ****** * * ** *** ** * ****** * ** * * * * != b[j])
* * * **** * * * ** * *** **** * * * * * * * * 0;
* ***** * ** ** ** **
** * * ** ** ** * * 1;

}

int main(void)
{
** * * * ** *** A[100],B[100];
****** * *** * *** ** %s",A,B);

* ** * * * * * * * (is_anagrams(A,B)) * ****** **** words or phrases are anagrams");
* * * *** **** * * printf("Two words or phrases are not ** * ** *

** * ** * ** * ** * * * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** ***
#include *** * **** * *
#include *** *** *
int is_anagrams(char A[],char B[])
{
** * * **** **** * * lenA = strlen(A),lenB = strlen(B),i,j,k;
** * * ** ** * * a = 0,b = 0;
**** ** * * ** * *** * != lenB)
* * **** ** ** *** ***** *** ** ** * * * * * * 0;
*** ** * * * * * * * ** = 0 ; k < 26 ; k++)
* **** * ** ** *** *
* * ** * ** **** ** * *** * **** * *** * = 0 ; i < lenA ; i++)
** * * * ** **** * ** ** ** *** *** * *
* * * * *** *** ** ** * ****** * ****** ** ** ** ***** * **** * * ****** == A[i] || 'A'+k == A[i])
* **** ** ** ** * **** *** ***** * * **** ** * * * * ***** ** * * ** * ** **
***** * * * ** * *** * *** * ******* *****
** ** * * * * * * * *** * * **** *** ** ** * * * = 0 ; i < lenB ; i++)
** * ** ** *** ** * *** ** *** * * ** * *** * *
** *** ** * **** *** *** * ** *** ** * * ***** ** * * ********* * == B[i] || 'A'+k == B[i])
* ******* * * *** ** **** **** * * * * ** ** * * ** ** ** * ** ** * * * *
** ** ***** ** ****** *** * * * * *** ** ***
****** **** * * ** ***** * ** * * * * != b)
* * * * ** ** *** * * * * * * * ** ** * * *** ** * 0;
** * * * ** * * * * ** ***
******** ****** **** * * * *** **** * ** ** *** *** * *** **** * *** * 1;
}

int main(void)
{
** * **** * * * A[100],B[100];
* * ** ** ** * * ** ** * **
** *** ** ** ***** **** *** **
**** *** ** *** * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
**** ** * * * printf("Two words or phrases are not anagrams");

* ***** ** * ** * ** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** *
#include ** * * ** * *
#include * * ** * ** * *
int is_anagrams(char A[],char B[])
{
*** * * *** * *** YOUR CODE HERE*/
* ****** * ** *** ** ** i,count[256]={0};
*** ** * * ** * *** ** * * * * * * **
* * * * * * ** *
* * * * * ** * *** * * * * ** *** * ***** * * * * * * *** * **** *
** *** * ** ** ** * **
* * * * * * ** * * ** ****
** ** * * ***** ***
** ** * * * *** ******* * ** * * * ** * * ** ** * ** ** * **
*** ** * * * * * *
/*
***** * * * ** ** ******* (A[i]!=0 || B[i]!=0){
** ** ** ** ****** * **** * * ** * * * * **** * **
** * ** ** ** * * *** *** *** * *** ** * **** ** * 0;
** ** **** *** * *
*/ * * ***** * ******** * * * * * * 0;

* * ** * * * *** (i = 0; i <256 ; i++)
* * * *** * * ******* * * * *** *** * * (count[i] && i!=' '){
***** * *** * ** ** * ** ** * * * * ** ** *** ***** * ** * * ** * * * *** *** * * **
** * * *** ** * *** * * * ** ** ** ***** ** * ** *** ** * 0;
* ** **** ** * * * ** * * * ****


** * ***** *** * * ** * 1;

** ** * * ** * ** OF YOUR CODE*/
* * **** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * *** * ** **** A[100],B[100];
****** ** ** ** ** YOUR CODE HERE*/

** *** * * * ** ** ** ** * *** ** *
**** **** * * ** * *** * ** *

* * ** * * * * **** ** = '\0';
  // * *** * *** = '\0';
* *** * * * *** *** * ** i;
* * ** * **** * * * * ***** ***
* * ** * * ** ** * * ** * ** * *** ** * * **** * **** * * *
* ** * ** ** *** * * * ** * * ** ******* * *
** * *** *** *** *** *** *
**** *** ** **** **** * ** ** *** * * * ** * * ** ** ** * * *** *** *
* **** ******* * ** *** * * * * * * * ** ***

* ** *** ** * * * OF YOUR CODE*/
* * ** *** * * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ***** *** *** * * printf("Two words or phrases are not anagrams");

* * ** ** ** ******* 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** *** *** *
#include ** *** *** * ** *
#include * ** ***
int * A[],char B[])
{
* * ** ** * **** YOUR CODE HERE*/
* * *** ** * *** ** *** *** *
******* * ** ** **** * * *** * * * *** * ***
** * **** ** * * * * ***
*** * * ** * **** * ** ** * *** * ****
** *** * * * ** * * *** *** ** * ** **** *** *
*** * * * * * ***
* **** **** *** ** ** (A[i] || B[i])
* * ** ** * * *** **** * ** *** *** 0;

* * * *** ** ** * * * (i = 0; i < 256; i++)
* *** * ** * ** * ** * ***** * * * * ** ***
* ** ** *** ** * *** * **** ***** * ** * * ** ***** 0;
* * * * * * * * * 1;

* * * * ** **** OF YOUR CODE*/
* * ** ** * ** ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** * *
{
** * ********** ** * *
**** *** * ** * ****** * YOUR CODE HERE*/
*** ** ** **** * *** * * *** * ** ** ** *
* * * ** * ** **** * **** * ***** * *

* * * ** * * * OF YOUR CODE*/
***** *** * ** ** * * ** ** * ** * ***** words or phrases are ** ***
** ********* ** * * *** * words or phrases are not **** * *****

* * ** * * ** * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * *** *
#include ** * ** ** * * *
#include * **** *
int ** * A[],char B[])
{
* * * * * * ** * ** ** YOUR CODE HERE*/
* * ** * * *** * * * *
** ** *** ** * ***** *** ** ** *
* ** *** **
* ** * **** * *** * ** * * **** * * *** ***** *
* * ** * **** ** *** * ** * **** * * ** * **
* ** **** * ** ** * * ***
* ***** * * * (A[i] || B[i])
*** * * ***** * * * * * * 0;

* *** *** *** * **** * (i = 0; i < 256; i++)
* * ** ** * ** *** * *** ** * ** * * *** * ***
* *** ** ** * * *** * *** ** * * * ** * * ** *** * *** * ** * ** * *** 0;
* ** * * ** ** **** 1;

* * *** * ****** * * * * OF YOUR CODE*/
** ***** ** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ***
{
* ** *** *** * * * * ****
*** ** ***** * * * ** YOUR CODE HERE*/
*** *** * * * * * ** * ******* **** *
** ** * *** * ** * ****** * *** * *

** * ** * ** ** OF YOUR CODE*/
* * *** ** * *** *** * * * ** * ****** * * words or phrases are ** ** * *****
**** * *** **** *** **** ** ** words or phrases are not ****** * * *

**** *** * * * * * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.184
©2016-2024

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 1.5k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 2.1k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 1.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users