12-28 Exercise 3: Anagrams function

0 like 0 dislike
25.8k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited | 25.8k views
0 0
STRUPES!
commented by (323 points)

79 Answers

0 like 0 dislike 
Hidden content!
#include * * **** ** * *
#include ******  **    ***
#include  *** * 
int *****   **** a[],char b[])
{
**   *   *   **  *** first[26] = {0}, second[26] = {0}, c = 0;
  **** *
   * *******   * **     *** *  *** *  frequency of     in first string
  ***    
*     ***** ***      **** * (a[c] != '\0')
*    *    *  *   *
* * ***   *********  ** ****  * *   * * *   ** **
 **  *** **** ** *******  ** *****  *     *** 
* * *   * **     * 
    ***
      ** **  *     = 0;
  * *
 *   *******  *   *   (b[c] != '\0')
 * *  ** *    *****  **
****** ****  * **  * ***   *  ***  **  **** * **
 * **  ****      *    **** *** * * ***  
   ******** * ******
*  ***  
   **    **   *****   *** Comparing frequency of *  **  *
* **   *  
*        **   *      **** (c = 0; c < 26; c++)
 * **** * ** **  * ** 
   *  * ****    * *   * *  ** * ***  ****   (first[c] != second[c])
   * *** * **   * * * *     * *  *** ** ** * ** *   **** *    * ***  0;
  *  * **    *  ****** 
*** * *  
*   ** ******  *    1;
}

int *  * * 
{
* ****** *******  **   **   *  * 
**  *     *  * **          ****** ** A,B);
**  *        **** ** *****     * *  **  *     *  **    words or phrases are **** ** * ***** 
 * **** ***    ***    *  *   **   words or phrases are not **** **  **  

  ***   ****  **   **  **** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *****   ** *
#include    * * *  * * * 
#include * ** * **    * * *
int ***  ****    a[],char b[])
{
 **   ** * *** * * *****   * first[26] = {0}, second[26] = {0}, c = 0;
* *   *
   *    * *   *    * * *  ** frequency of characters in first string
 ** *  * 
 ***  *  *  * **** **    (a[c] != '\0')
 *  *  ***  *  *  *  
  **   ** **   * *  **  ***    * * * * ****  ***** *   **
*  * * **  ** *     *    ***    *        
******  ******** ** *   
 *    *
* ****  ** *  * ***** * = 0;
***  *
  **  *** * *   * *** **** (b[c] != '\0')
 ** *  ** ** ***  * * 
*  *   ** *   * * ****** ***   *  **  * **        *
* * * *  **** * * ******  *** * *   *
*    ***  ****  **   
 * **
*   * *  **** ** *   Comparing frequency of *** *
  ***
 *** * *  *  * * ** **  *  (c = 0; c < 26; c++)
 *** * * *****   *  
  **  ****  ** **    * ******  ***      * (first[c] != *  **  
 **  *** ***   ** *   *** *    *  **    **    **  ***  *** ** *   * 0;
**      ** * * * ** 
*** *
   ** * ** *  * ** 1;
}

int main(void)
{
  *     **   *** * *  ****** * 
*   *** *     **  * ** *  ***    **     **  *   **   *** * **
 *** ***    ***  ***   * *  *  * ** *** *   ** words or phrases are *   * **  *  **
*   ** *   **       *** * *   *** ** words or phrases are not  * * * *   ** * 

*** * ** ****** *** * *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** **   *** **
#include   *  * * ***  * **
#include **   ******    *
int is_anagrams(char A[],char B[])
{
* ***   **  **** * * *** *  YOUR CODE HERE*/
    * *      *  ****     * * **  *   ****  *  ***  *
    **  ********* *    *** ** * ***  ** **** *******
  * * * ***  *** ***** 
******  *  **    ** **   * ***  *        * * ** *******   *   *  **  **    * **  && *** * *     ** *   **
  * **   **  *         ** **  *   * *  *  * * *  **  * ** ** **  * ** ******   **     *  ** 
 **  *    * **  ** * * **  ***   **** *     ** * * * * ** * ******     * && * * **     *   *
*      **     ***  **  * ** *    *   *******    * *** *  * * *  * * ** *  *******    ***** ***** 
******    *** ** **** * *
** * *  *  *     *  ** * *       *   *****  * **
 ****** * *   * *   * *
 *** *  ** *** * * *** *  ** ** *   **** * ***  ******* (cA[i]!=cB[i])
  *   *** *  ** * ** ** ****   ****   * ** *** **   ** ***  ******* * ***** 0;
 **   ******       * ***** **
***      * **   *    * ** *** 1;
 *       * **** * ** *  OF YOUR CODE*/
* **** * * *****  *   function should return 1 if two words or phrases are anagrams,
***     * *** ***  * ** if two words or phrases are not anagrams.
}

int main(void)
{
  *  * * **           A[100],B[100];
** ** *   * *  * * *   ***     * YOUR CODE HERE*/
 **  ** **  *   *   **** *   * *** * ****   **  
*** * *      *** * *  * * *    * ** *      ****   *     
** *** * *  ***** * * * * *  (is_anagrams(A,B))
     * **  *        ** * *  * * *** *    * *  ******* *  * *  *     ** * words or phrases are anagrams");
   **  ****     **** **** 
*** **      ** ** * **   **     * *   * ***    * **** **  * * ** **** *  *  words or phrases are not anagrams");
**** *    * *     **** *  ***** * *  0;
** * **  ** *  * *    *     OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
**** *  **  ******* *   **** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * *    ***  *  *  ** *     *
   * ** **   ****       ** (A[i] != '\0')
 ***   ** **** *    ***
*** ** *  ***  **    * ***   **  ** **  ** *  *** * **  ** * *
* ****   * ****   **** ****  ** **     * *****   ***  
 * *      **   *   *  **  *** 
 * ** ** **   *  *** ***    
**    ** **    ** ** ** *** *    = 0;
* ***  **     ** ***  * ****
*  * *  * ****  ***   * **  ***  * (B[i] != '\0')
***  *   *      *** * * ***
 *** * **  * *      *    * * *  **  * *    *  * * * ***     *   * ***
**  ***    *  **  ** * *   ***      ** *   * ** ****  
*** **  *   *   **   * * *  **
    
   *****  ** ** * ** **  *    *  (i = 0; i < 26; i++)
 * **    * **  *  ***** ***** 
** * *****  ****  * ***  ** **   ***** *  * ** ** *  **** (Array1[i] != Array2[i])
   * * *** **      * *** *  * * **   *   * * **     * *  **   **  * * *  **  *   *  0;
***** * *  *   **  * * *  
 *  ***** * *    ** * *  * **
**** *   ** ***   * *  *  *    1;
}

int main()
{
 * **** **  *** ***   A[100],B[100];

 * **  **  *  * ** ***** **  * *  * *** 
* * **  * *   **   *  **  *  *  ** **  ***** 
 *   *  ** *  * **   **     *
* *****    **** ***  *     ** (is_anagrams(A,B))
*** *  ** *   **   * * **   * 
 **  *******  *****       *** ***   *  *** ** * *  **  **  *** *****  ** words or phrases are anagrams");
 **  ***   *****     *** ** *
*  *  ** *   **   ****** *  * * printf("Two words or phrases are not anagrams");
 * * * *  * ** *******  *  *
 *** *   *   * ** ** ***  ***** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
 *** * **   ** ** *   *  Array1[26] = {0}, Array2[26] = {0}, i = 0;
*   **   ***** ****    * *
  * **  *****  * **  *** ** (A[i] != '\0')
***      ** *  *  *      * * *  ***
***   * **  * * **    *** **** **   ** *       *** *  **** *** ** **   
**     **  * ***  **      ** ***  *  ***   ***  *  ****
 ***    ** ****  **     ** *
 *** ** *** *  *** ** ** ** 
 *    * **  *  * **      **    = 0;
*     *      ***    * 
  ***        ** *  *     *** (B[i] != '\0')
* *  ***  * ** *** * * ***
 * ****** **** * ***  * *  *** *   *  *** ***** *** * *** ** **  
*** ***   * * ** ****** *   ****  *     * * **  ** *** * 
*  *  *       **** *****   ****
    
***    * **  *   **    (i = 0; i < 26; i++)
* * * ** **  ************ 
* * **   * *    ** *    ***** ** ** **  ** * ******* (Array1[i] != Array2[i])
* * * * *  *  *  * *** ****   **  ****  *    *    ** * *****  *********   * ***  * 0;
****     * * *** *  **  **  *
** **     * *** ** ** ****
 * *   * ** * **    * *  *****  *** 1;
}

int main()
{
***   **    *  **   *****  *****  A[100],B[100];

     *  * ** ***   ****  * * ***  * * *  ***   
    * **    ****     ******** *    * **** * *  *** * 
   ***    *        ***   * **
 *   *** * * *** *  *   *** *  (is_anagrams(A,B))
*  * ** ** *   ** ** ** ** 
 *** *   *  ** **   *** *  *******  * **  *  * **  **  **   words or phrases are anagrams");
*****  ** *    * ** ** *   *** *
    ***    *****    * * * ****  printf("Two words or phrases are not anagrams");
  *   * * **  *** **      **
   *   **  **    ********* *   ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  * *** ** 
#include  *  **    *   ** 
#include **     *** *
int is_anagrams(char A[],char B[])
{
  *  *   * **     * *  *   lenA = strlen(A),lenB = strlen(B);
   *********    * **  * *   != lenB)
** ***   *** *  ** *   *   *      **  ** * * ** *  *    * ** 0;

*    **** ** ** ** *  ***   ** i,j,k,a[26] ={0},b[26] = {0};
** ** *** * ***   ****  * *    = 0 ; i < lenA ; i++)
* *  * *   *    * ***  ** 
** * ***   **********    * *     **  ***** *  ** **  * = 0 ; j < 26 ; j++)
 *    * * * * *  *  ***    ** *  **     *  ** ****   * *   * **
*  ** *  ** * *   * *** *    *  *   **    ** **   * **   *****   ** ** * *  **  ****  == A[i] || 'A'+j == A[i])
***** ********  **  * **    *  **  *  **  **        * ***  * ****      * * * *  ***   ** * *  *   ***   * **   **   *
**     * *    * *** ** ***    * * ** **** ****  * * * 
*** ****   *   *  * *  * * * 
  *   *** * *      *** *** ******  = 0 ; i < lenB ; i++)
***   *  *  ** * * * *** ** 
  ***     * * * ***  *** **  ** **  **    *  *     ** **     = 0 ; j < 26 ; j++)
*  **  **** *  *   *  **  ***  **   ****  *  *  *  **
  **  *   *    * ** * **    *   **  * *  *  * ***   * * ****  ** ** ** ***  * ** == B[i] || 'A'+j == B[i])
   ** * * **** **  * **     **  ** *** * **        * *** *****          * **** **          * **  ***  ** * 
* ** ** * *   *   **** ***  ***  * *** * ******    *
 *    *    *   *     *** * ***
*** *  * * ******    *  *   *   = 0 ; j < 26 ; j++)
      *****  **   * **   *
  *** *  ******   **    **  *       **  *  * * **** ***  != b[j])
**  *    * *  * *****   *    *  ** * *  ** *    ****** **  *   *** * ****** 0;
* *   **   * **  *  **  *** *
 *  * *  * *    ** *  ** ** *    * ** 1;

}

int main(void)
{
**     ** ******* *   **   *** A[100],B[100];
 * **  *   * *     **  ** **  %s",A,B);

   *     *** **  *   *  (is_anagrams(A,B)) *         * *   words or phrases are anagrams");
*     ***  *  ***  *** printf("Two words or phrases are not ***    **

  *  ** * **        *  *    0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   * **  
#include  **  ** **   ** 
#include *  * * * *  ***
int is_anagrams(char A[],char B[])
{
 ***  ** *  ** * ** * lenA = strlen(A),lenB = strlen(B),i,j,k;
*  * * ** **  *  ** * *  *   ** a = 0,b = 0;
  *  **  **    **    *      != lenB)
*******  ** ** *  *  * *  * **  ** **  **  **   * **  0;
** ** *  ***   ***** ****  **  ***  = 0 ; k < 26 ; k++)
* *   **   ** *   **  * ** 
*** *** ***   ** * *  *** ** * *** *          ** ** *   *   * = 0 ; i < lenA ; i++)
* * * *  *** * ***** * ***      ****  *** **    *
*  *     ****  **  ** ******** *****   **    *  **    * * ***  *** ****** ***  ** *******   == A[i] || 'A'+k == A[i])
* ** **  **  *** **  **  ** ** **  *   ** * * ** *   * * ** *** *  *** * **  *  *      *  * ** *   **    * 
*  *        * *   *    *   ***   *  **      *    ** * 
 **     *  **  ***      **   *   *  * ** *  **  *   ** * = 0 ; i < lenB ; i++)
*  * **** ***  ***  * ***** ***  ** ****** *   * ***  ** 
 *** ** * ** *    * **  *  * **  *  *  *****   **** * *** *  * **   * ** * *****  **    * == B[i] || 'A'+k == B[i])
* ** * **** *** ** * *  * *  *  ** **  *  *  *****   * *  *  **   **  ** *     * * *** * * ******* *** **   * 
 * *** * *** *  ***  * * * *  *** ** ** *** *** ** **
*   *     *** ****   * **** ** ***     * **  **  *  ** *  != b)
 * ***  *  * * *   * * **  *    *** **   ***    ** **   *  *  *   ***** **  **      *   * 0;
** * *    * **  * *****  ****  **  * * *  
 *  * * **  ***    * * * ***     ***   * ***  **** **  ** **  *    **      **   * **    1;
}

int main(void)
{
* *  *   *     *** *** **  A[100],B[100];
*    ** * * *** ***  * * ***    *
**   ** **     *   * *******     **
  **       *** * *  *     (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*   *   *   *  *   ** * printf("Two words or phrases are not anagrams");

**   * *  **   * *  ***   0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  **  *  * 
#include  ******    * * **
#include * *  ***   
int is_anagrams(char A[],char B[])
{
***  * *    * * ***    *** YOUR CODE HERE*/
***      *  * *    ***         * i,count[256]={0};
*   *   ****     *    *** *   * * ****
 ** ***  * **   *****  *
 ** ** *  *  * **  * *  *  *  **  *    *   *  *     **   ***   *** *** * *    *   
 **  * * ** *****  * * ***
* **** * *** **   *   **  **    * * **  * *
 ***  ****  * ** * ******
*  **** ******  *   ****** ***   *** ** ****   * **   *****   ** * ****         
  ****  *   **** *     * *  **
/*
*** * *** *    *** ** (A[i]!=0 || B[i]!=0){
  *      ****  ****   * *  * **** ***  ** ** *  **    ** ** ** *** *** **** *** **
 * *       *   **  *  * *   * * *  *  *  * ** ****  *   *   0;
     * **     * *  *   
*/  * *  * ***   * * *   *****    ***  * ***   0;

**   **  ** *   *  *   ** ** (i = 0; i <256 ; i++)
 * **** ***  *  ** * ** * ** ** *  ***  **   **  * ** **  (count[i] && i!=' '){
*   *  *  *****  *   *   *  *  * **** *** ** *****   * * * *****  *    **    *    *   ***  *  **
**  *   **  ****  **** ******    * *    * ** *   *** * ** *****      **      0;
** *** ** ***  * ****  ***  * * * **  *     *   *   * *  


       *  ****   *** ***   * 1;

**** **** *** ****** *  OF YOUR CODE*/
   * * **   ** * * * *  function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
 * **   **  *   ** ** A[100],B[100];
 * ** *** *** *  ****  YOUR CODE HERE*/

*  * * **  *     *  **  ** * * * ** *  
 **** **   ** ** *    ***    ***  *  ** * * 

  *****   *   **** *    ****  ***  = '\0';
  // * *** *  *     * = '\0';
*  ****  **** **    **   ** * i;
*   **  **  ** * * *** *   *  *** ** **   * *
   ** **   *** *  ***** **   *****    *  *    **  * *  ** * * * *  * * * *  ***   *    ***** **  *
      ***   * * *   * ** * ******** **** *** **  ** *  *****
* **   * **  ********  * * ** * **  ***
*  ** **  *    ***  *   **   *  *  *    **   *** * *   ***  * * ** *    *  *  
**   *    * **  *  * * * **   *  ** ** ** *** * **** * *****   * 

*****   * *  *     OF YOUR CODE*/
* *** *****   ** *   *  (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** *** *  **** *    * * printf("Two words or phrases are not anagrams");

*** *** * ** * **  *  0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ** *   *  *** *
#include  *** *  * ** **
#include **  **** **  
int   *  *** *  ** A[],char B[])
{
 * ** **   *  *       YOUR CODE HERE*/
  ** ** *** *  ** * *    *  *  **      **
** * **** **  *   *** **  *    ** *   **    *  * *
    * **  * **   *****  
**  ***   * *  *    * *    * * *  ********  *        ** * ** *  
*   * * *  *  *    **  ********      ******   ***      ** *
**** * *** *  **  *  * 
*  * *    ********  *** * **    (A[i] || B[i])
*   ** **   *  * **  **  *  ***** **** *  *   0;

**  **  *  **  * ** ** * *** (i = 0; i < 256; i++)
 **  ** ** ** ** * ** *  *  ***   * * ***   * *  ** *
  *** * ***  *   ***  * * ** **  *  ** ***      ***  ** *   ** * ** * *** **  0;
* *  ** * ** *   * * *    ***  1;

* ***  * *** *** * OF YOUR CODE*/
 *   * *  * **  *****   function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *** * 
{
** ******* ***  * *  * *  ***** **  
 ***** * **  *  *** * * **  YOUR CODE HERE*/
* **    **  * * * **   *  * * * * *  *  *** **  *   
   *  ******* *** *    ** * ** ** **   *  *    **   *** *

** *  ***  *  ** * **** * *  OF YOUR CODE*/
  ** ** ***    *  * **  **  * **  *  ** **  ** *  * words or phrases are **   * *****   * * 
  **   *** ****** * **  *  ** *   *  words or phrases are not *****  ** **

* * * *  ***  * ** *  0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  ** * * *    
#include *  * ** ** * 
#include  ***  *    ***
int  **   ***    A[],char B[])
{
** * *   * *   ** *** YOUR CODE HERE*/
  ***   *  ** *  * *** * **    ***    
 *  *  ** * * **** * * **  ** * * * ****  *  ***** **** *  *  
**  *** ** **  * * * ***** * 
 **  *  *  *  *  * *    * *  *** *****      ** **** * *  * ** *
*    *  * ** ** ****  *     ****       *** **  ****** * ***    
** * *    *    *  ** * ***  ****
   **   ***  *** *  * * *      (A[i] || B[i])
     **    * * *****  ** **    *  *   ***  **  0;

*** ** ********   **** ** **  ** (i = 0; i < 256; i++)
   * *  * ***   *         ** * *** *  *   * ** ***   ** * ** 
**  * **  *    * *** ****      * * *****   ***   ****    ** ******     ****  ***** **  ***      0;
* *   *  * ** ******  *** *  *  *   1;

* **   * * **     *  * OF YOUR CODE*/
**   * * ** ** ****  function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *  ** 
{
 **  *  ** ** *  *** * * ** *   
*  * ***   **** * *   * YOUR CODE HERE*/
* * *  * *   ***** *  **   **    **** *  * * ** * **
   **  * * * *   * ** **   ***** * ** *  **     *  * *  

* **  *******  * *   OF YOUR CODE*/
***  *   *  *** ***    ***** ** **   * *   * **** words or phrases are * * *****
    ** *       *   *   * ***  **  *** * words or phrases are not     *     ** * 

 ***  ** ****  **** * * *  0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
47 answers
12-07 Exercise 3: Function to delete an element from an array
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 13.6k views
0 like 0 dislike
45 answers
12-07 Exercise 2: Function num_digits
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 12.7k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 11.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users