12-28 Exercise 3: Anagrams function

0 like 0 dislike
15.6k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited | 15.6k views
0 0
STRUPES!
commented by (323 points)

79 Answers

0 like 0 dislike 
Hidden content!
#include * *** * * *   * 
#include ** *    *  **
#include ***  ***  *      
int     ** * ** a[],char b[])
{
* ********* ** *        first[26] = {0}, second[26] = {0}, c = 0;
 * ***** 
* ***    ** *    ******  *     frequency of     *  in first string
* * *  **
* * * *  *    ***  ****** (a[c] != '\0')
  ***   *   ** ** **
    *     *  * * * **      * * **** * *   **
 *   * ****   ** **    **  **       * 
**  **   * * ****   **
 *  ***  
 *   * ***  *** *** * = 0;
*     * *
 * ***  ** *****  **  (b[c] != '\0')
** * **   *****  ** 
 * **  *  * *  **  **   *      **  *  * **   ***  ***
*   * ***   * **** * ***    **  *   ** * ** *
****** * ** *** **
 * * ***
**  *** * * * Comparing frequency of  * **   
**  ***  
 * ***  *** *   ** * **** (c = 0; c < 26; c++)
 *   * *****  **** *
**  *** *       * *** ** **  * * ***** (first[c] != second[c])
* * *      ****   ******* *    *  * *    ***  * **  *    *     * * 0;
*********** ****** **  *
*  * ******
**   *  *  * **** *     1;
}

int ****  
{
*  ****    *  *** **  * ** ****     
**  *  ******** ** *** ** *  *  **    * * *  * * *   A,B);
 *  ** ***** ***  **  * *   *       * ** * *   * *  ** words or phrases are  ***    * * *
*   ***  *  * *** **  **  *   * words or phrases are not   **  ** * *

*  * **   **   ***   ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **** *** * *** 
#include  *  * *    *  * 
#include  ** *    *  * ***
int *   *  ***  a[],char b[])
{
 ***  **   * ** **    * first[26] = {0}, second[26] = {0}, c = 0;
* ****
   *** ***    * *  ** *   * **  frequency of characters in first string
      
 **   *** * * * ****   (a[c] != '\0')
 ** * *  * *  ***     * 
 **      * ** *  ****  ** *    * *** * *       
     ***  *  *   *** ** ********  **   *** *  *
 * *** ****  ****  
  *  * *
    **    ** ** *  = 0;
    *  *
    *   * *  * * ** *  ** (b[c] != '\0')
 ****  ***  ******    
****  *     **   *        * **     **    * *  *  **   *
 ***  **   *  ***  **      * *** *  ** ** ** 
 **  **  * **** *   **   
* *  * *  
* *  *     ****   *    Comparing frequency of   * **
** *  * 
   *   *  **  **** * * (c = 0; c < 26; c++)
****  * **   *   *   ** 
*  *   **  **** ****** *  *  * * * **** * (first[c] != * * *   
   **  ***     *****   *  ***    *    *** * **   * ****  *    ** *  0;
  *  * ***  ** **  * ** 
 *** *   
  *    *   **  *  *****   1;
}

int main(void)
{
*  ***   *  * ** * **  ** *  ** **
 * ***  * *** **   * * *   ** *  *      *   *****    **
** *****    **  *** * **   ** * ** **      *  words or phrases are   *** ** ** **
* *  *  **  * ****    *****    ***  words or phrases are not * ** ** **  *  

**   * ** *    **  * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  * ** *** *   
#include  * **** ** * *  *
#include ** * *  * ***
int is_anagrams(char A[],char B[])
{
*  *** * * **************  * YOUR CODE HERE*/
 **   *  *** *  * * *  ***** *   *     ** *  
   ** *    ***     ** *** *** * *** **   * *  
 * *   **     *     *  ***  ***
 *  **  ** *   *   *  * **** ***** *  **       *   **  *** **  **  *  ****   *   ** ** && **    ******    ***
  *   ***** * *  *  * * * ** *    ****  * ** *******  *   *** ****** *    ** **      * **   ***     **
**** * ***  *     ******** * ****  ***   * *  * ** *  ** ****  *****  **  *  &&  **  *  **  * ***
  ***    * **    ** * ***    **** ** ***   * * ** * **  *****   ** **** *   * **  *     
****     **         * * ** 
** * * *   ******* ******** **    *  *    *** *
  ** * ** * * *      *  *   
    * *****  **** *   ** ***   ***    **   * * *  ** (cA[i]!=cB[i])
     *** *  *    * *** * *** *  ** *   ******** *   * *  *    ****    *****  **    **  **   0;
  *   * * *   * * * *   * *
   ******  *  ****   **  **   1;
   * * * * **  **     ** **** OF YOUR CODE*/
  *   * **** *  * ***   function should return 1 if two words or phrases are anagrams,
* **   * * ** ** **** ** * if two words or phrases are not anagrams.
}

int main(void)
{
  *** *  **** * *  * A[100],B[100];
 * **    * * *   *** * * YOUR CODE HERE*/
* *** ***  **** ** * *********   * ** * ****  * *  *** 
 **    * * *  **** * **  *  * ***** *** *********
   *** ** *** **  **   *     (is_anagrams(A,B))
   *   ***   * ** * **** * **   *   * ** ****     ***** *** * * **  ** words or phrases are anagrams");
** * * *** *** ** *  *    * ***
  *** **** *  * * *   *  *   ** ** * *   *    *  * *** *    * *  **   words or phrases are not anagrams");
***  **  * **   **     * *  * 0;
**   *  **  * * *  OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
**** **  *** *** ** *   ** *   Array1[26] = {0}, Array2[26] = {0}, i = 0;
*  * *****    *   * *  ** *
   * *   **   ** ****   *****  * (A[i] != '\0')
* ******         **  *   *
*****  *  *  **  * *** *   ** *   * ** *  ** *      * ******    **
* **   ****     * **   *   *** * * *  ***  *   * *** * * **
*    *  **   *  * *    ***
** **  **  *** * ** *   
* * ** *  ** *   * **  * **** = 0;
* ** *  ***  * *   ** *   *
*** *** ** *** * * ******  **   * (B[i] != '\0')
* *        *  *  * * **  * *   
  * * * **** ** * * *****  * *      ** *  *  *   *  * * * *** *  
 * ** ** ** ** * *  *   *****  * ***  * * ** ***   **    **    *
  *  ***** *** *  * * *** 
    
 ***    ******  ***** *     ** (i = 0; i < 26; i++)
  *  **    ****   *   **   
 *       * ***    * **  ** ****** **  **  * **  *****   ** *    * * (Array1[i] != Array2[i])
* *  *    ***** *****     * *  ****** **   ** ********* * **  **  **** *  *** * 0;
  ** * *  *  *   * ***    **
*  * * ** ***** ***  * **     
*** *********** *** ****** ***   1;
}

int main()
{
*  ** * *   **     * ***    **** A[100],B[100];

**** * * * *  *   *****    * ****  * *
  ***** *    * ** **    ** **  * *** *  
* *****    * *****   *    *
* ******* *    ** * **  **   ** (is_anagrams(A,B))
 * *  ******* ** **  * *   *
 **  * ***  *** **   ** *  ***  * *** ***      *  *   **    *** ***    words or phrases are anagrams");
   * * * ** * *** * * ** **
* ***  ** * *  * **  *     * printf("Two words or phrases are not anagrams");
 * *** * ** * *** ** ****  
  *      ** * * ***    ***** *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
*   **    ****  ***  *  **** *  Array1[26] = {0}, Array2[26] = {0}, i = 0;
 **  * ** *** *  **    *   *
    *****   * ****  *******   * (A[i] != '\0')
***** *  **  * *  **  **  
*  *   *  **  * *** *  * *      ** *  * * *  ********     * ****
 *  * ** * ******* **    ******     *  **** *  * **** *     ** 
 ****   * ** *    *  * **
***   * *   *** *  ** * ** 
 *   * *  *  *  * *** * *   *** = 0;
**  *** ** *** *   *    *
* **  * * *    * *  *  ***** * (B[i] != '\0')
** ** *  * *   *  *   ***** 
**  *  * ****  * *** * * ** * ** ** *  ** ** * *  * * * *** 
  *** *    *** * *  *   ***   * ** **   **  * * *  
   ** * * ** **  ** *    
    
****  **    **** ******* **   * (i = 0; i < 26; i++)
** * **   ****** *   **  *  
 * * * **** * *  ***  **    *** *     *** * *** *****      *** (Array1[i] != Array2[i])
* * *** *** * * * ******   *     ** *  *   ***  **    *   **         ** * ** *  ** **  0;
 *   **   * ***** **   ******  **
*  **      ***  *  ***  * * *
*    ** ****      * * * * 1;
}

int main()
{
    **    * **** **   *  * **   *  A[100],B[100];

 *** *  *  ** **** * *  *    *   **  ******* ***  *
**  *     ** *         *  *  *   ***  * *  **   * * 
*  **       *  * **    * 
* ** ****    * **    * *   (is_anagrams(A,B))
*****  * * *   ****   * * **  * 
   **    * *  **       ****** ** ******  * **  ** ** *   *    ****   * * words or phrases are anagrams");
* *** **   **  *** * * * * ** * 
*      * * **********   * *** *  printf("Two words or phrases are not anagrams");
  ****  **   *  * * **    *
*  * * * * ***** ** *******  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** **     * 
#include   ***** *** *
#include   *** **** *    
int is_anagrams(char A[],char B[])
{
** *** **   * *    ****** * *   **   lenA = strlen(A),lenB = strlen(B);
*   *** *  **   *** ****  * * **  != lenB)
****  *     ***** **    *     *** **** ** **   **  ***    * **  ** *** 0;

 * ** * *  **** **   *** * **** i,j,k,a[26] ={0},b[26] = {0};
  ** *** *  ***      **    * *  *** = 0 ; i < lenA ; i++)
*    ***  ***   ***      *** 
*    *    ***  ***** ** ****  **  **        * * * * = 0 ; j < 26 ; j++)
*** **  ***   *   ** **  * **** * ** * ****  ***  * ***
 ** * *   *** *    *   ****   ****    * ***  **** * **    * *** * * *  * *** * * ******* == A[i] || 'A'+j == A[i])
 ** *****  * **** ***  *** * ** ** *** *      *    * ** *   ***  *  *     ***    *  *** *** *   *** ** 
**  **      * * *   * *** **  * ***  **  *  *    *  
*    *   *   **  *  ***    
**** * *     *****   * * ** = 0 ; i < lenB ; i++)
* ** ** *   ******** *   * 
  *** * *  *** *     *         * *****    **      *     **  = 0 ; j < 26 ; j++)
 ***  *      * * ***    ** *****  * ** * * *** **
 *   *  *  *   ***** * **     **     *    * *   *   **    * ** *   ***  *     ****** == B[i] || 'A'+j == B[i])
    ** ** **    *   *** * *  * **    * *   *  * ***   * ********** *   *** * ** ****** *      *
*  ***** * **** *** ****  * * *** * ** ** ******* *  **
 **  *     *   ** **  ****
* ** ****** ** *       * **  * *    = 0 ; j < 26 ; j++)
   *** ***** ***  ****** 
 *    *  *****  *    * *** * **  ******** *  * * ****   != b[j])
    *** ****    **    **  * *   **  **  ***   *  * ***   **  * *   * ** *** ***  * ** * 0;
**** * *  * ****   **     *
***** **  ***  *  * *   ** * ** 1;

}

int main(void)
{
 * ***  *****  * *     A[100],B[100];
*****  * *   ***   * *   ***  **   %s",A,B);

* **   **     *** * *    (is_anagrams(A,B))    * **** ** words or phrases are anagrams");
 ** **** ***  * * ***   printf("Two words or phrases are not *          **

** * ****  *****  * *     0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ***** *  *      
#include    *   **  *  
#include   ** *  *      
int is_anagrams(char A[],char B[])
{
*   **  * * ** *   ** *  * lenA = strlen(A),lenB = strlen(B),i,j,k;
     ** **** ** * *   *     a = 0,b = 0;
** *  *   *    * **  ** **     != lenB)
*   **   ***   * *   *   **** **   *****  *   *  *****     0;
   **      *  *  ***     * **       = 0 ; k < 26 ; k++)
 **** **    ** ***   * * * ** * 
*   * * **** ****  *   ** * **  *        ******** **  ** * * * = 0 ; i < lenA ; i++)
   ** * *  * * *   ***  * **  **      *  **       
 *  ***    ** ** ** *   * * **      ***  **   **  **  **      ** *  **     *** * * *      == A[i] || 'A'+k == A[i])
**  * *     * * ** *   *  *     ***   *    * * *** ** *** **  * * * *   ***** * *   * *   * *  *  
**    *  * *   ********** * *  * **  ** **  *  **   *
* *  *   ** **** **   *  ***  * ***   * *   * *** * *      = 0 ; i < lenB ; i++)
* ** * * * ** *   ** *     *** ** * ** ***  * ****  *  
 *  *  *    * ** ***  **** *    * ******  *   **  * **** * *  *     ** *  * **** * **  == B[i] || 'A'+k == B[i])
***  ***   * *  *** *  *   *    *  *  *  ** ** * **  * * **** ** * **  ** ***********  ******  * ** *   
 *   *   *  **  * * *** * ** * *   * ** ** ** *   *  * 
   *** * * *  ***      ***** * * **** * **   **   *  * != b)
**  *    *** **    *  **    **    *  * * **    * *  **** *  *  *** * ** **  * *     0;
 *  *** * * *  *      ** * *  *** * *
*** * *  *** *         **** ** * *   * *   **** **   * *  ** ** * * ** *   ******** 1;
}

int main(void)
{
  * * * *** ** *   A[100],B[100];
 ** * ***   * ** ***** ******    **  *
* * * ** ** * *   * **  ** ***  *** * 
*     *  ***  *** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* **** ** *  ** *      *** printf("Two words or phrases are not anagrams");

** ** ** ** ***   ********* 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  **  *   *
#include    * * *** ** **
#include **    **  ** * * 
int is_anagrams(char A[],char B[])
{
 *** **  ** ** ***  ***  YOUR CODE HERE*/
** ***  * *  *   * * **   *   i,count[256]={0};
* **   **   **   ******* **     *****
 *   ***  **  * *  * *   ***  
* *   *  ******* * * *    * ***** *  ** * ****** *   *** * * * *  ** ***  ***  *** *
**** *  * ** *   ******  
*** **  ***  *  * * * ** ***     * * *
 ** *   ** ** **  * * ** **
*    * ****    ** *** * **  ** ***   ***   ****    ***  *    * *   *******    **    *   ** *
*  ****  *  ****   *    *
/*
 *  ** ** * ****     *    ** * (A[i]!=0 || B[i]!=0){
  *** *  * * **  *      * ****  ** * * ******* ** *        *   ***  *  
  ***   *******    *  * *  ***  ***  *     *  **   * ****  *  0;
   *** * **** * ***   * 
*/  **** *   **  * ** * ** *** **** *** 0;

  ***  * * ** *     ********  (i = 0; i <256 ; i++)
*  * ** ** **** * **  *** ** *** *    * **      (count[i] && i!=' '){
** **   ** * **** ****    *  * *******  * * * * ***  *   *    *  *  **** **       ** ***** *    * **  *   * 
 ** ****      **  ***   *** ** ***** *** ***  * *** ****  *  ***   ** * ***** * **  * 0;
       **  ***   ** **  * * ***  * * **   ***    * **** * 


* *    ****  ** * *** * **   **** 1;

****  ** ** *  *  * ****  OF YOUR CODE*/
  **   *   *** ******** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* ** *    **   *   ***    A[100],B[100];
* *  *  ** **   ***  * *   YOUR CODE HERE*/

 *   * ** ***  **    **  **   ** ****  **
 ******* ** *****  *  * * *   * **

**   * * **   *   *    ** *  ****   *   = '\0';
  //  * *     ***   = '\0';
 ***       ** ******    *  *** i;
**     **  *  *  ****** *    * ** *** *  **
*** * ** *   *   ** *** *  * *  *** * *   * * * ** * **  *** ** ***  *   ** *** *******  **** **
**  *  *   **  *      ******* *   * ** * **   ***** *  * *  ** 
 ***   ***       * **   *    *     *** 
    **** *  *     *  ****  ****  * ***  * * *****   * ***         ***  * *  * *   *****    *  *
** * * *   *** * * ****     ** **** *  * ** ****** ** * **** *** * 

***   * *   *** * *  OF YOUR CODE*/
 * *     *   *******  ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
***    ***     * * *  printf("Two words or phrases are not anagrams");

** **   *     *  ** * *** *   0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include        *  ***** 
#include   * **  *   
#include * ****  *   
int   * **   A[],char B[])
{
 * **** ******   *****    **** YOUR CODE HERE*/
* * ***  ***  ***   * *  *   * ***** * 
* ** ****     ***** *    * * * * ** ******  *  *** * 
  *            **   *** *  *
*  *   ** *   ****    ****    * * *       ***  *   *      *   * 
  ****      **  * **  *  ************ * *** ***    ** *******  
 * *  * *   ** ** * * *  *** 
 **   **   *  *****   (A[i] || B[i])
 * *  *** **  *****  *  **   **  * *   ***  0;

    * **  **  ***  * *  ** *  (i = 0; i < 256; i++)
  ** * * **** ************  *  *        **   *  * **   **     
**  **** ** ****   ***** *   * ** **   *  *  ** *    *      *    ** * ***  0;
 ** ** ** ***       ***** * *  1;

 ****    **  *** *  *** * OF YOUR CODE*/
** ***    *  **  * **    * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int **** * **
{
 ****    ** *      ** * ******  *
* ****  **   ***  *  ** ** * YOUR CODE HERE*/
  * * *  *     * *  *   *** ***   * *    *   ** *   *   ** * *
 *  ************ **   ** * ***        ****     ** *  

* *** *  *       *  ***  * OF YOUR CODE*/
  * ***** * *  *  **    * *** *    * ******* **  words or phrases are   *** **  *
   * * **  **  ***   * ****  ** ** *  *  words or phrases are not     * *** * *

 **   *     *  *** *** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *** **   **  * *
#include * * **** *     
#include *  ********
int ***** **  A[],char B[])
{
 * ******   ********   YOUR CODE HERE*/
 *    *   **   ** *   ** ** *  ***
**** *** **  * * *  * ***  ***  * **  **  ** *** 
*     **** **  ***   ***  **  ***
****  *       ** *   ** * *  ***  *    * ** * **   * *  
    ***  ***  *  ***  * **  * * * * ** *** * ** ** *****    **
 ****  **** * *  ** *   ** * *  
* **   *** ***   ***  *  *  (A[i] || B[i])
********* * *  ***  *   **  *** * *** ******** 0;

 *   *          * ****  *** * (i = 0; i < 256; i++)
** *  ****  **     * *  *  * * * *   * ** * ***** ***   ** *
*****  * *** **** * * *   *  * ** *    **     * *** **  * ****   *  * **** * *        0;
 ****  ** ** *   **  *      1;

 *** * *   ** * ****  *  OF YOUR CODE*/
 *  * **  **  *   **  * *  function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * * **** 
{
 **     *********  *     **** **
* * * **   **  **  * *     * YOUR CODE HERE*/
***   **  *     ** * *       **    **  *** *** ** ***   **
 ***  * *  *  **  ****  *  ** ***  *  * *     *** **  

*  ** *** * **  *** OF YOUR CODE*/
    **  ** * * ** ****    *  * **      *****    words or phrases are * **** ****
* ****  *  *** * *****     *  * * words or phrases are not *    **    

 **     * **  *  * *  ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.153
©2016-2025

Related questions

0 like 0 dislike
47 answers
12-07 Exercise 3: Function to delete an element from an array
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 7.8k views
0 like 0 dislike
45 answers
12-07 Exercise 2: Function num_digits
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 8.1k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 7.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users