0 like 0 dislike
15.6k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 15.6k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * ******* **
#include * * *** *
#include *** * * **
int ** *** a[],char b[])
{
**** * * * *** * * first[26] = {0}, second[26] = {0}, c = 0;
* ******
* ** * ** * frequency of ** * in first string
* **
* ** ** *** ** * * * * (a[c] != '\0')
* * * * **** *
*** ****** * *** * * **** *** *
* * * ****** * * *** *** *****
* ** *** *
***
***** * * ** = 0;
** ***
** ***** ** * **** * ** (b[c] != '\0')
** * ** * ** ** **** *
* * * * ******* ***** * * * * * * ***
* *** *** ** * * * **** * *
****** ** * *** * * *
*
** * * ** * * * Comparing frequency of * *
** * *
* *** * * (c = 0; c < 26; c++)
* ** * ** **
* * *** **** ** *** * * * **** (first[c] != second[c])
* * * * * ** * ** * * * *** * * ****** * * * * ** * * ** *** 0;
* ** * * ** * * **
* ** *
*** ** * * * ** * 1;
}

int * * *
{
** * ** ** * *
** * ** ** *** ** * ** * *** **** A,B);
** *** * *** * *** * * * * * ** **** words or phrases are * * * *******
* * *** * ** * * ** ** *** * words or phrases are not *** * ***

* * * * *** ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *** *
#include **** ********
#include * ******* ***
int * *** *** a[],char b[])
{
* * *** *** ***** first[26] = {0}, second[26] = {0}, c = 0;
** ** *
* ** ** ** *** ***** * frequency of characters in first string
** * *
* ***** * * * * (a[c] != '\0')
* * * * * * * *
* * * ** ******* * * ** ***** ** **
**** * *** * ******* * ** **** *** * **
****** * *** *** * *
* ** *
** *** ** ** *** = 0;
** ***
** ** * * *** * ** (b[c] != '\0')
* * * * * *
* ** * ** * ** *** ** ** * * * *** **
* * ***** * ** *** * * ** * ** * *
** ** ** * * *** *
*
*** * * * ** ** * * Comparing frequency of * ***
** ****
***** ** * **** * * * (c = 0; c < 26; c++)
*** ** * ** ***
** * * * **** ** * * * **** **** ** (first[c] != *******
* ** * **** * * ** *** ** * ** ** ** *** * ** 0;
******** * * ** ***
* ** * *
** ** * 1;
}

int main(void)
{
** ** * ** ** **** * * * * *
** ********** * ** * ** ****** ** ** *
* * ******** ** * ** * * ** **** words or phrases are **** *** *
** * * * *** * * * *** * **** * * words or phrases are not * **** *** ***

* * *** *** ** *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * *
#include * *** *
#include * * *** * *
int is_anagrams(char A[],char B[])
{
** ******** *** YOUR CODE HERE*/
*** ** ** ** ** ** * **** ** * *
**** * * *** ** ** ***** * ** * ***** * **
* * ** * ** *
* **** * * ** *** ** * ** ** * * * * ** * ** * * && * * ** *
** ** * *** **** * * * ***** ***** * **** ******* *** * * ** ********* * *
*** *** * * ** ***** ** ** * *** * * ** * ** *** *** * ** ** * * * && * * * * * * ** ** *
*** * *** * ** * * * * ** * * * * *** * ** * * ** * * ** ** ********** *
** * *** *** * *
***** * * *** * ** * ** *** * ****
* * * ** ** * * *
* ** ** *** * ** *** ** ** ** ** ** * ** * ** (cA[i]!=cB[i])
*** ***** **** *** * * ** ** ***** *** * * ** ** * * **** * * *** 0;
* *** * **** *****
** * * * ** * * * * *** *** 1;
** ** ********** * OF YOUR CODE*/
* *** * * * **** function should return 1 if two words or phrases are anagrams,
* * ** ** *** * if two words or phrases are not anagrams.
}

int main(void)
{
** ** *** * * ** A[100],B[100];
**** * * ** YOUR CODE HERE*/
** * * **** * *** ** *** ** ****
* ** ** * * * * ** * ** * *
*** **** * * * ** (is_anagrams(A,B))
* ** *** * *** **** * *** * * * * *** * * ** * * *** * words or phrases are anagrams");
** * ** ** **** * * * *** *
* ** *** ** * ******* ** * * ***** * ** *** ** ** * words or phrases are not anagrams");
* ** * * ******** ** ** 0;
* * * ** * * ****** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * * * * * ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
*** ** * * * * *
* ** *** *** * * * * (A[i] != '\0')
*** ** * ** * * *
* ** *** ** * ** ** * * **** ** * ***** * * * **** *
** ** ***** * * * ******* ** * * * * *
** ** ** *** *** * ** ****
*** * * * ** *
* *** * *** * * * = 0;
*** * * * ** * * * ****
** * * ******* * * (B[i] != '\0')
*** *** ** **** ** **** *
*** * * ** ** ** * ** **** *** * * ****** ** * ** * *
**** * * * * *** *** **** * * * ** *
* *** * ** * ** * * **
    
* ** ** * * * * * *** ** * (i = 0; i < 26; i++)
* ** * *** * * ** ** **
** **** * * **** ** * ** * * ** * *** ** * * * (Array1[i] != Array2[i])
** ** ** *** * * *** * ******* * ** ** **** * * **** ** * * * * * *** 0;
* * * * * ***** **
*** ** * ** * * **
* * ** ** **** * 1;
}

int main()
{
* *** ** ** * * * * * * A[100],B[100];

** * * *** * ** * **** ***** *
* * * * * ** * * * * * ** *
* * * * * ** * ** *
* ** * ** * ** * ** *** (is_anagrams(A,B))
* * ** * * ** * * ** ***
** * * ** ** ** **** *** ** ** *** ** ** * ** * words or phrases are anagrams");
* *** **** * ** * ** **
* * ** * * ** * * * ** *** printf("Two words or phrases are not anagrams");
* * ****** *** * **** * * *
* * * ******* * ** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * ********* * *** Array1[26] = {0}, Array2[26] = {0}, i = 0;
** * * * ** ** *
* * ****** * * * ** *** (A[i] != '\0')
** * *** *** * *
* ** ** * **** ** *** ** ****** * *** * **** ** * *
* *** ** * * * * * ** * * * * *** ** * * * *
* * * ** *** * **
* ** *** * *
* * ** ** * ** * *** = 0;
* *** * * ***** * *
***** ** * **** ** ** * (B[i] != '\0')
* ** * ** *** ** * *
*** * * ** * ********** * *** * *** * * **** ** *** * * *
*** *** * ** *** ****** ** ** **** *
** * * * *** ** ** *
    
* ***** ** **** ** ** * (i = 0; i < 26; i++)
* * ** * * * ** * * * *
*** * * **** * * ******** ** * * * ** (Array1[i] != Array2[i])
* * * *** * * * * * ** * ** **** *** * ***** **** ** * * * 0;
* ** * ** *** * ******* **
**** ** * * ** * * ** *
*** * * * *** * * * * ***** 1;
}

int main()
{
** ** * ****** * * **** * A[100],B[100];

** *** ** * * **** * ** * * * * ***** *** ** *
* * * * * * * *** * * ** * * * * *
**** **** *** ** * * **
*** * *** *** * ** * ***** (is_anagrams(A,B))
* ***** * ** * * * ****** * ***
* * **** ** *** * ** * ** ** ** ** * * ** **** * words or phrases are anagrams");
* * ***** * *
** **** ***** * ***** * printf("Two words or phrases are not anagrams");
** * * * * * *** *
* * * ***** * **** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** *
#include * * * * **
#include **** ** *
int is_anagrams(char A[],char B[])
{
*** * **** * * **** *** lenA = strlen(A),lenB = strlen(B);
*** * *** ******** * * != lenB)
*** **** ** * * ** * ** ** * * * *** 0;

* ** * * *** * ** ** * ** i,j,k,a[26] ={0},b[26] = {0};
* ** ** * * * ** * ** * * = 0 ; i < lenA ; i++)
* * *** *** * ** **
* * ** * ***** *** *** ** * ** *** ** **** = 0 ; j < 26 ; j++)
** **** * ** **** *** * *** * * ********* *** *
* * * * ** ***** * **** ** * ** * * *** * * *** * ** * ** ****** * * == A[i] || 'A'+j == A[i])
* * * ** * ** * * *** * * *** * * * ** * * * ***** **** ****** * * * * * * ****
* * * * * * * * ** ** * * * * **** **
*** ** *** ***** *
* * **** **** ** ** * * * = 0 ; i < lenB ; i++)
*** ** * * ** * * ** ***
* ** * * *** * ** * ** ** *** * ** * * * *** ** ** * ** = 0 ; j < 26 ; j++)
****** * *** ** ** * ** * * * * * ** * * ***** ***
**** * ** * ** * * * * * * *** ** * ** ** ****** * * * * ** ** ** == B[i] || 'A'+j == B[i])
* * * *** * * * ** **** * *** ** * ** * ** ** * ***** * ** * ** * * **** * * ***
*** ** * * *** * ***** * * ** * * * *
** ** * * *** *
* * * ** * * *** * ** = 0 ; j < 26 ; j++)
* * *** ** ** * **** *
* * *********** ** * * ****** ****** ** * * ** ** ** != b[j])
*** ** *** * **** ** * * * * ** * ** * ****** * * *** ** ** *** * *** ** * 0;
* * * * * * ** ***** *
***** * * ** *** * ***** ** 1;

}

int main(void)
{
** *** * ** *** * * A[100],B[100];
** * ** * * * ****** **** %s",A,B);

**** ** ** * *** * ** (is_anagrams(A,B)) * ** * words or phrases are anagrams");
** * * ** printf("Two words or phrases are not * **** **

*** ** ** ** * * * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *
#include * * ** ** **
#include * * **** * *
int is_anagrams(char A[],char B[])
{
* * * * ** ** * * **** * ** lenA = strlen(A),lenB = strlen(B),i,j,k;
* * * * ** * *** * a = 0,b = 0;
**** **** * *** ** ** != lenB)
* ***** ****** * * ** * * **** ** * 0;
** *** * * ** = 0 ; k < 26 ; k++)
* ** ** ** * ** * **
** * * * *** * *** * ** ** ** ********* * *** = 0 ; i < lenA ; i++)
* * * ** *** *** * * * * * * ***** * * **** **
*** ****** * ** * ** * ** ** * ** * **** * *** * ** * * ** ***** ** == A[i] || 'A'+k == A[i])
* ** ** *** * ****** *** ***** * *** * ** * * * ** ***** * * * **** * * * * * ** * ** *** *
******** *** * * **** * * * *** **** *** **
*** * * * * * **** * * ** * * *** ***** **** ** = 0 ; i < lenB ; i++)
* * ** * ** ** ** ** ********* ** * *******
* *** **** ****** ** ** * *** * * ** ** * * ** * ** * ** ** * ** ** == B[i] || 'A'+k == B[i])
* * ** * ** * ** * * **** ** *** ** ** **** ** ****** ** * * ** * * *** * ** * * *
** ** * * * ** ** * *** ****** * ** ** *
**** * * * * **** * * * ** * * * * * != b)
** *** * * ***** * ** * ** * * ***** * *** * *** * * ** * ** * * * 0;
* * *** * * * * *** ** * *
* ** ****** ** * * ** * ** *** *** ** * * * *** ** *** * * * * * *** * 1;
}

int main(void)
{
** * * ** * * ** *** A[100],B[100];
** ***** *** ** ***** ** * *
** *** ** **** ** * **** *** * * **
**** * * * **** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** * ** *** *** * * printf("Two words or phrases are not anagrams");

**** * * *** * ** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *
#include * * ** *
#include ** * ****
int is_anagrams(char A[],char B[])
{
******* ****** * *** * YOUR CODE HERE*/
*** * *** **** ** **** * *** i,count[256]={0};
*** * *** * * *** ** * * * *
* * * * *** ** * **
*** ***** * ** ** * ** *** *** * * * **** * ****** * * * *** *
* **** * * * ** ** * ** * ***
*** * *** * * * * * **
* * * * ** ** **** **
*** **** *** ** ** *** ** ** ****** * ** * **** ** * ******** * ***
* * ** * * ** * * * *
/*
* * * * * * * *** * ******* (A[i]!=0 || B[i]!=0){
* * * * **** * * ** * *** * * * * * ** *** * ** * ** *
*** ***** *** * **** *** * ** * * *** ** 0;
* * ** ***** * * *** *
*/ ** ***** *** * * ** ** ******** 0;

* * ** ** * * **** ** * (i = 0; i <256 ; i++)
** * * **** * * * * * ** ** * ** * ** * (count[i] && i!=' '){
* *** * * ** ** ** * ** **** * * * * ** * * ** *** *** ** * ** * ** * * ** *
*** ** *** * * ** ** * * * * ***** *** *** ****** * * * ** * * *** 0;
* * ******** ** *** * *** *** * ** ** ***


*** * *** * *********** * * **** 1;

** * * *** ***** * OF YOUR CODE*/
** * *** ** * ***** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
** * ** * ** * *** A[100],B[100];
* * ******** *** * * * YOUR CODE HERE*/

* ***** **** * * * * * * * **** *
** * *** * * * * * ******* *****

*** * * * * ** * *** = '\0';
  // * *** * ** * *** = '\0';
* **** ** **** *** * * * i;
** ** * *** *** * **** * * * ** **
** ** ** **** ** * * *** * * * *** * * * * ** *** * *** * ** * *
* *** ** **** ** * * *** * * ** ** **
* * ** * * * * **** * * * **** * ***
*** **** **** ** ** * *** ** *** *** * * ** ** * * * *** ** ** * *
** ** ********* * ** * *** ** * * * ** ** * **

*** *** * * * * OF YOUR CODE*/
** ** ** * * ** * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** ******* * * * printf("Two words or phrases are not anagrams");

* * *** ** * * * * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** ***** *
#include * * * **** *
#include ** * *** ***
int * * ** A[],char B[])
{
*** * * * * ****** ** YOUR CODE HERE*/
***** * * ***** ***** *** *** ** **
*** *** * * **** * *** **** *** * *** *
*** *** ** * ** * * ***
** *** *** * * *** ********** *** * ***
* * * ** * * * * ** ** * * *** * *
** ** ** * ** ** *
** * ** * *** (A[i] || B[i])
** *** ******** * * * ** * *** ** * * **** 0;

* * ** * **** **** ** * (i = 0; i < 256; i++)
* * * ** * ** * * * * ** ***** ** *** * * * ** **
** * * ** * ** * * * ****** **** ** * *** *** ** * * * 0;
* * *** * ***** * * ** * 1;

* * * * * * *** OF YOUR CODE*/
*** ** * * ** ** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *** *
{
** ** * **** ** *** *
*** **** ****** **** YOUR CODE HERE*/
* ******** *** * **** ** ***** * * *** * **
* * * * *** ** * * ** **** * * ********

* * * * * * * * OF YOUR CODE*/
* * **** *** * * * * ** * * *** ** words or phrases are ** ** ***
**** * ********* *** ** *** words or phrases are not ** * ***

***** **** ****** * ** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include *** ** * **
#include * * * * *
#include * ** * *
int * * * A[],char B[])
{
***** * * * * * * YOUR CODE HERE*/
** * ** * **** *** * ** * * * **
****** ******* ****** * * *** * ** * **
* ** * * * * ** *
** * **** * * ** ** ** ** *** * * * * * ** **
** * ** *** * * * * * ** * ** *** * ** ***** ****
** * ** ***** ** *** *
** * * *** ** *** *** * ** (A[i] || B[i])
** * * * * * * * * ******* **** * *** * * * 0;

* ****** ** * (i = 0; i < 256; i++)
* * * *** *** * * ** * ** * * **** **** *** ****
* ** *** ** ***** *** ** *** ** * ** * ******** ** * **** * * ** 0;
** * *** ** ** * ***** ** 1;

* * * * * ** ** OF YOUR CODE*/
* *** ** * ** * ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *
{
* * ** ***** * ** * ** **
*** * * ** *** ** * * ** YOUR CODE HERE*/
*** ** * ** * ** ** * **** ** * * * ***** *
** **** *** ***** **** * * ** ********* *

** * * ***** **** OF YOUR CODE*/
* * *** * *** * * * *** * ** ** * * * words or phrases are * *** *
* ** ** * *** * ** ** * * words or phrases are not * * **

* ******* ****** *** * * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.184
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 7.8k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.1k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users