0 like 0 dislike
15.6k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 15.6k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * * ** ***
#include **** ** *
#include * * *****
int *** * ** a[],char b[])
{
** * *** ** * first[26] = {0}, second[26] = {0}, c = 0;
* * **
* * **** ** * frequency of ** * in first string
** * *
* ** ** * * * *** ** (a[c] != '\0')
** * *** * * *** ***
* *** ** ** * * * ** **** ***********
* * * * * *** *** **** *** **
** * ** * ** * * *
* ** * *
* ** **** * * = 0;
**
* * ** * * ** * * * (b[c] != '\0')
** ** *** * ***
* * ** **** * *** ** *** * ***** ** ** * ****
** ** * *** * * ** **** * **
****** * *
*** **
* ** *** * * * * Comparing frequency of ** *
** *
** * * ** * (c = 0; c < 26; c++)
** *** * *
* ** ** * ** * ***** *** * * * (first[c] != second[c])
** *** ** *** * *** ** * **** * * ** * * ** *** 0;
** ** * ** * * * *
* ** **
* * ** * * * * 1;
}

int *** ***
{
** ** * ****** **** * ***
***** * * ** ** * *** * *** A,B);
* * * ** * * **** ** **** *** * * words or phrases are * ** * *
* *** ***** ** * *** *** * words or phrases are not * * **

*** ***** * ******** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *****
#include * ** ** **
#include ** **** * * *
int **** ** a[],char b[])
{
* *** **** * *** * * * first[26] = {0}, second[26] = {0}, c = 0;
*** ****
* ****** ***** **** * ** frequency of characters in first string
* *
* ** *** * ** ** (a[c] != '\0')
** *** ***
** **** * **** ** * ** * * * ** ** * **
* * * * * * * ** ** ** *
* *** **** ****
*** ***
** * ******** ** = 0;
** **
**** * * * *** * (b[c] != '\0')
* * *
* ***** ****** * ***** * * * * ** * ** ** **
*** * * * * * **** **** ** * * * **
******* ******* * * *
* ***
** ** * * * ** * * Comparing frequency of * **
* * * *
* * * ** * * * ** ** (c = 0; c < 26; c++)
** ** *** * *** ** **
**** ** * *** * **** * * * (first[c] != * *
** ** * * * ****** * *** **** **** ** ** 0;
* ** * ***
** ** **
* * *** ** * ********** 1;
}

int main(void)
{
*** * * ***** ** *** *** *
* ***** ** * * ** * * *** * ** ***
** * **** ** **** * * * ** ** * ** ** * ** * * words or phrases are *** * **
* *** * ******* ***** * * words or phrases are not * *** * * ***

* ** *** *** * * ** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include *** ** * *
#include * * ** *
#include ** ** ** **
int is_anagrams(char A[],char B[])
{
*** * ** ** * * * ** YOUR CODE HERE*/
* *** * ****** * ** ** ** *** * *
***** *** *** * * *** ** ** ** * **
* ** * * * *** *
* ** * * * ** **** * ** ** *** ***** * * * * ** ** ** * * * && ***** *** **
****** * * * * * * ** * ** ** ** * **** ** *** * * ****** * ****** ***** * **
** * *** *** ** *** * ** ** * * * * * ******** * * *** *** && * *** * ** *** *
** ********* * * ** * * * ***** *** * *** * ** *** * ** * * *** * * **
* * ** *** * * ***
** ******* * * * *** * * * ** ** ** *
** * * ** * **** **
* ** * ***** ** * ** * ** * * * * *** *** **** (cA[i]!=cB[i])
* * * ****** * ***** * * * * * * **** *** ** ** ** ** *** * 0;
* **** * ** * * *
* * * * *** * ** ** ****** 1;
* ** *** ** OF YOUR CODE*/
* * ** * ** * * function should return 1 if two words or phrases are anagrams,
* ** * ** * *** ** if two words or phrases are not anagrams.
}

int main(void)
{
* *** * * * **** * A[100],B[100];
** * ** ** * YOUR CODE HERE*/
*** * * * ** * * ** *** * ** ** * **
******** ** * * * * ****** * *** **** **** ** ** **
* * ******* ** * (is_anagrams(A,B))
* ******* *** * ****** ** * * ** ****** * * * *** words or phrases are anagrams");
** * **** *** * **
* * * * ** * ** * * ***** * * ***** *** * **** * * words or phrases are not anagrams");
*** ** * * * * * **** * * 0;
* *** * * * * ** * *** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * **** *** ** **** * ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
**** * *** * ** ***** * *
* * **** *** * * ** * (A[i] != '\0')
* **** ** ***** * * ***
* * * * ** * ** ** **** ** **** ** * **** ** * *** ** **
** * ** * * * **** * * **** * * * ** *
* ** * ** ** **** *
** * *** **** * *
** * **** ** * * *** = 0;
***** ** **** ******
* * ** *** * *** ** * (B[i] != '\0')
* * ****** ** ** * * * *
** ** * *** ** * ** * *** ** * * * ** ** **** * *
* **** **** * * * * * *** * *** * * ***
** * *** * ** *
    
*** * * * * ** * **** (i = 0; i < 26; i++)
*** ***** ** * *
*** ** * * **** **** ***** ** * *** ** ********* (Array1[i] != Array2[i])
* ****** **** * *** ** **** * * **** * * * * ** * * * * * * ** 0;
* * ** * * ****
*** * **** * **** **
* * * *** **** ** * 1;
}

int main()
{
** * * * * *** *** * * * A[100],B[100];

**** * ** * * *** ***** * * *
* *** * * * **** *** **
** * * * * * * ***
* * * * * *** * **** * (is_anagrams(A,B))
* * *** ** *** *
* *** * ***** * * ** *** * *** ** * ** **** words or phrases are anagrams");
***** * * **** **
*** ** ** ** * *** printf("Two words or phrases are not anagrams");
* ** * ** * ** ** ** *
** **** * * * * * ** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
**** * * *** * *** * **** Array1[26] = {0}, Array2[26] = {0}, i = 0;
**** ** * *** * * * ** *
* * ** * * ** * * *** ** (A[i] != '\0')
* *** ** *
* **** ****** * **** *** ** * * ** * * ** * * ** **** ** *
* ** ** ** *** * * *** * *** **** ***
*********** ***** * * **
* * * * * * ***********
* ** * * * ***** * = 0;
** ** * ** * *** * * *
** **** ** ** * * ***** (B[i] != '\0')
** * ***** ** * ** *** *
*** *** * ** **** ** * * * *** * ** * * ***
*** *** * *** ** ** * ****** *** **********
** * * * * * *
    
* * * * * ****** ** (i = 0; i < 26; i++)
*** * ** * *** ** ***
* **** * *** * ** * * * ** * ** *** * * * (Array1[i] != Array2[i])
* * * * * ** * * ** * * *** **** * * * * * * ** * ** *** ** *** * ** *** 0;
** ******* * ***** * * ****
* ** ****** ** * *
* * * * ** ** ** * * ** * ** 1;
}

int main()
{
* ** * ** * * *** * * * A[100],B[100];

* ** * * * * * * * *** ***
**** * ** ** * ******* *** ** * **
* *** * * ** ** *
* * * *** * * * ** (is_anagrams(A,B))
***** ** *** ** * * * *
* ** *** **** * * * * * * * * * * * ****** ** words or phrases are anagrams");
******* * * ** ****
* ** ********** ** ** printf("Two words or phrases are not anagrams");
* *** * * * **** * * **
* ** * ** * * * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * * * **
#include * ** * * **
#include * * ****
int is_anagrams(char A[],char B[])
{
** * ** * **** * * * ** lenA = strlen(A),lenB = strlen(B);
** **** * * ** * ** * != lenB)
* * * ***** ** * * * * ** * * * * 0;

** * * *** ******* **** * i,j,k,a[26] ={0},b[26] = {0};
*** ** * * * * ** ** *** = 0 ; i < lenA ; i++)
*** ***** * * * **
* *** * ** ** ** ** ** * * * * * * * ** ** = 0 ; j < 26 ; j++)
**** * * ***** *** * ** ** *** *** ** ****
*** *** * *** ** * *** *** * ** **** * ** * ** * * * * **** * * == A[i] || 'A'+j == A[i])
* * ******** ****** ********* * * ** ***** * * ** * ***** *** ** * **** * ** ****** *
** ** ** **** *** * ** **** ** * ***
* ** * ** ** * *
***** ** *** * * *** *** ** *** * = 0 ; i < lenB ; i++)
* ** ** * * *** **
* * * * ** *** * * ** * ** * ** = 0 ; j < 26 ; j++)
** * * ** *** * * ** * ** ** * * ** ** * *
* **** * * **** * ** ** * ** * *** * * ** *** * * * ** * * *** * * == B[i] || 'A'+j == B[i])
** ** * ***** * ** ****** * * * * * * ******** ** **** *** ***** ** * ** * *** * * *
*** * * *** ** * **** * ******** *** ** ** *
* ** ** *** *** *****
* * ** ** *** ** * *** ** * = 0 ; j < 26 ; j++)
**** ** **** * * ** **** *
** ********** ********* * *** **** * ***** ******** != b[j])
* *** ** * * *** **** *** * * * ***** **** * ****** ****** ** * * 0;
* * *** ** * * * *
* ******* ** * ***** 1;

}

int main(void)
{
* ********* *** * A[100],B[100];
* * * * * ** ** * * %s",A,B);

* ** * ** * * ** * (is_anagrams(A,B)) * *** * * words or phrases are anagrams");
** * *** * * ** printf("Two words or phrases are not ** * * * * *

** * ** *** *** ** *** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ****** ***** **
#include * * ***** * *
#include * ** ** * **
int is_anagrams(char A[],char B[])
{
* * * ** ** **** * * * * lenA = strlen(A),lenB = strlen(B),i,j,k;
** *** * * ** ** * a = 0,b = 0;
** * ******* * * * **** != lenB)
* *** ******* ** * * * * * * ***** * **** ** * * * 0;
** **** * * ** ** ** * = 0 ; k < 26 ; k++)
*** ** * ** *** ******
* * *** * **** * *** * * ****** * ** * * = 0 ; i < lenA ; i++)
** **** ** ** * ** ** *** * * ** ** ** **
*** **** * * * * ** * * * ** * ** * * * * *** ** * **** *** ** == A[i] || 'A'+k == A[i])
* *** * * ** * ** * * ** *** * ** ****** *** ** * * *** * *** * ** * ****** ***
*** * * * ** *** ** ** **** * ** * ****
** ** *** * * ** ** *** *** *** ** ** * *** * = 0 ; i < lenB ; i++)
* * * * **** * ** ** * * * * **** * **** * *
* * *** * *** **** ** ** ** * ** * * * * ** * ** **** ** * == B[i] || 'A'+k == B[i])
***** * ** * * * * *** ** *** *** ** * * **** * ** ** ** * **** ** *** ** *****
* ** *** * * *** * ***** * * ** ****** * * *
*** ** * ** *** * * * *** * **** * ** * ** * * * != b)
* **** * * ** ** * * * ** ******** * * * * ** *** * **** * ** * * 0;
* ***** * ** * *** * * *
** ** * * ** ****** ** * * * * ******* *** * * ** * * *** * 1;
}

int main(void)
{
* ** * *** *** * A[100],B[100];
* * * ** ** * * ***** ******
** ** **** * *** *
*** *** ** * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** * *** ** * printf("Two words or phrases are not anagrams");

* ***** * * ***** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** ** * * *
#include * * * ** ** * *
#include ** * ******* *
int is_anagrams(char A[],char B[])
{
* *** * * * * * ** **** YOUR CODE HERE*/
*** ** * * * * ***** i,count[256]={0};
** * * * * * ** * * *** ** *** *
****** ** ** ** * *
**** *** *** ** ****** * ** *** ** ** ** ** ** * * ** * *** *** *
** * * * **** ** * * *
*** **** *** * * *** * *** * ***
* *** **** * *** * *
* *** ** *** ** * *** * * * * * * **** * *** ** ** * * * * *
* * ** ** **** * **
/*
*** * ** ** * * * ** (A[i]!=0 || B[i]!=0){
* *** ** * ***** * * * ** **** * * **** ****** *** ** *** *
** * * ** * **** ** * ** * ** ** * * * * *** 0;
* ** * ** ** * ** ** *
*/ ******* *** * ** * *** * * 0;

**** ** ***** *** * * (i = 0; i <256 ; i++)
* * * ****** ******* * ** * * * *** ** ** *** (count[i] && i!=' '){
* * ** * * ***** **** ***** * *** * *** *** **** * * **** ***** ** * * * ***
* * ** * ** ** ** * * * * ***** *** ** ***** * * * * * * *** ** *** 0;
* * *** ** * ** * * ** ** *** ** * **


** *** * * * * *** 1;

** ** ***** * ****** ** * OF YOUR CODE*/
* ** * *** ****** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
***** * * * *** * ** * A[100],B[100];
*** ** * * * *** * YOUR CODE HERE*/

*** *** ** * *** * *** * * ***** *
*** * * * ***** * *** * * * * *

*** * *** * * * *** ** * = '\0';
  // ** * * ** * ** = '\0';
* *** ** **** * * ** ** * * i;
* * * * *** *** * ** * **** **
** * ******* ** *** * * * ** ** ** * * * ** * * * *** * * * * * * ** *
* ** ** * *** * * **** * ***** * * ** * **** *
* * * * * * ** ** *** * * *
* *** * ** ** * * * * * ** *** ** * * * * *** * * * *** * **
* * ** * *** **** * **** ** *** ***** * *** **

* ****** * * OF YOUR CODE*/
** **** ** * *** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
**** * ** * ***** printf("Two words or phrases are not anagrams");

******* *** * * * **** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *********
#include ****** **** ******
#include ** * *
int *** * * * * A[],char B[])
{
** * * * * * YOUR CODE HERE*/
* * ***** ** * * * ** * ** ****
** * * * * ** * * ****** *** * * **
* * ** ** *******
*** ** ***** * ** * ** ** ***** *** * * * *
* * *** ** * * ** **** * ** * *** *** ** * * * ** * *
* * ** * * **** ***
* ** * * * * * * * (A[i] || B[i])
** **** * * ** * * *** * **** **** * 0;

**** ** * * * ** (i = 0; i < 256; i++)
**** *** * * * ** ** * ** * *** *** * ***** *** * * ** ***
*** ****** * * * ** ** * * *** * *** ** ** * * ** **** * * 0;
*** ** *** ** **** *** 1;

* * * ** OF YOUR CODE*/
** * ** * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
* * *** ** *** *
* * * ** * * ** *** YOUR CODE HERE*/
* ** * * * * * ** ** * ** *** * *** **
* * * * * * * * ** * ** * * * ** * *

** * * * ** ***** OF YOUR CODE*/
* ** * * *** * * * * ** * words or phrases are ** ** * *
* *** * ** * ** *** *** * words or phrases are not * * ** *

****** ** * *** * *** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * * ****
#include * ** *****
#include ** * * *
int * ** * * A[],char B[])
{
** * * *** * * YOUR CODE HERE*/
* *** * ** * * *** * * * *** *
* ** ** * * * ** ** ****** * ** * * * **
**** *** ** * * ****
* ** ** *** * ** * * * ** * ** * * *** *
* * ** * * * *** ** * *** ** * * * * * ****** *
* * ** ** ****
** * ** ** **** * (A[i] || B[i])
* * * ** * ** *** * ** * * 0;

* * * ** * * **** * ** * (i = 0; i < 256; i++)
** * ** *** * ** *** ***** *** *** ** * * ** **
**** ** *** * *** ******* *** *** * *** * * * *** ** * * * * *** 0;
* *** ** * ** ** * ** 1;

**** *** * *** *** * OF YOUR CODE*/
** ** ** * * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
* * ** ** * * *** *
** * * * * *** * * YOUR CODE HERE*/
** * * * *** ** *** * ** * *** ** ** *
** * *** ** *** ****** ** * * * *** ** * **

*** ** * ** * **** * OF YOUR CODE*/
* ** ** * **** ** * *** * * *** * *** ** * words or phrases are ** * * **
* * *** * * * ***** * words or phrases are not *** * * *

***** ******* 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.201
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 7.8k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.1k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users