0 like 0 dislike
3.5k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 3.5k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * **** **** * *
#include * * * **
#include * **** *
int * ** * a[],char b[])
{
** ** * * * * ** first[26] = {0}, second[26] = {0}, c = 0;
** ** *
* * ** * * * **** * ***** * frequency of * * in first string
* **
* *** ** ** *** * (a[c] != '\0')
** ** * ** ****
** ** **** * ***** ** ** *** * *** * *
* ** * ** * **** ** ** * ** * *
*** * *
** ****
** * * * * ***** = 0;
* *
* * * ** * * ** (b[c] != '\0')
** ** **** * * *
* *** ** * ****** * * * * ** ** ** * ***
******* * * * *** *** * * ****
* * * ** * **
* **
** * *** ** ** Comparing frequency of ** *
****
* ** * ** * * * (c = 0; c < 26; c++)
* * **** *** * ***
* * *** * ***** * *** * ******** (first[c] != second[c])
* * ** * * * *** *** ** * ** * ** **** 0;
* ** ** * * **
* * * **
* ********* ******* **** 1;
}

int * ****
{
** * ** * * ** ** * * * *
* * * ** **** ** **** * ** * A,B);
* ** * * * * ******* * * ** *** words or phrases are *** * **
** * ****** ** * * ** * words or phrases are not * * ** * *

** ** * **** ** * ** **** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * * * *
#include * * * **
#include * ** **** *
int ** * * a[],char b[])
{
* *** * ** ** first[26] = {0}, second[26] = {0}, c = 0;
* *** *
* ** ** * * * **** * ** frequency of characters in first string
***
* * * * * * (a[c] != '\0')
* ******* * * **
*** ****** * * * * * * ** **** * ***** ******
* * * * * ** * ** ** *
***** ** **** *
**
*** *** * **** * * = 0;
* * **
*** * * * * * * ** (b[c] != '\0')
* *** * * ***
* * * * * ******** * ** * * * **
* ** * * ***** * * * * **** **
* * * * **** * * * *
*** * *
*** * *** *** * ** Comparing frequency of * *
**
**** * * * * *** * (c = 0; c < 26; c++)
** * * *** * ***
* *** **** * * * * ** * ** * * * (first[c] != * * *
** ** * * *** * ** *** * * ** * * *** * * * 0;
* ** ** **** * *
** * **
* * * * **** 1;
}

int main(void)
{
* * ** * *** ** ***
* **** * ** * ** * ** * * * * ** ** *******
* ***** * **** *** ** ***** *** ****** ** * words or phrases are ** ** * * *
* * ** ** * * * ** * *** * words or phrases are not ** * * *

*** ** *** *** ** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * ** ** * * *
#include * * * ** *****
#include **** ***** * * *
int is_anagrams(char A[],char B[])
{
** *** ** *** * * YOUR CODE HERE*/
** ** ** * * * ****** * *
* * ** * * ** * **** ** ** * * *** *
* * ***** ** * ** *
** ** * * ** *** ** *** * ** * * *** ** * * ** * **** * && *** ** *
**** * ***** * *** * *** * **** *** ** *** ** * * ** * ***** *
*** ** *** ** * * ** ** * ** * * **** *** ** * * && ***** ***** ** ****
* * * * **** * **** * * * *** ** **** * ***** **** * **** ** * ** *
* **** **** * * ** ***
* **** * * ****** *** ** **** **** * *
** ** * * * ** ** ** * **
* ** * * **** **** ** * * * * * * **** (cA[i]!=cB[i])
* ** * ** * ** *** **** ** *** **** * * * **** *** **** ** ** ** * * ** ** 0;
*** * ***** *** *
* *** * ** *** *** *** 1;
** * *** * ** * * ** OF YOUR CODE*/
** *** * ***** function should return 1 if two words or phrases are anagrams,
* * * ** *** * * ** ** if two words or phrases are not anagrams.
}

int main(void)
{
* * * ** * * * A[100],B[100];
* ** * * * *** * YOUR CODE HERE*/
* **** *** *** * ** * ** ** ******
** ****** ** ***** ** ** * ** ** * * **
**** ** * *** ***** * * (is_anagrams(A,B))
** * ** * * * * *** * * ** ** ** ** ** * *** * * **** ** words or phrases are anagrams");
**** ** ** * *** * * **
* * ******* *** ** * ** **** *** * * * ** **** * ** words or phrases are not anagrams");
* * * * * ** * * * * ** * 0;
** * ***** * * ** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
**** * ** *** **** * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
******* * ** **** *
** ** * * *** * * ** (A[i] != '\0')
** * *** * *** * ***
* * ***** * * * *** * * * * * ** ** *** *******
*** * ** * * * *** ***** ** * * ***** * *
** * ** * * * * *
******* * * ** * **** *
******** * * ******* = 0;
* ** **** ** * *
** * *** *** ** * * (B[i] != '\0')
** * * ***** ***** * *
**** * ** ** ** *** *** * ** * ******** * ** *** * * *
* * * ** * * *** * ** * * ** * *** ***
** * * *** * * * * * * * *
    
* * **** *** * * * (i = 0; i < 26; i++)
** ** * *** * * * ** *
**** ** *** * ** * * **** ** ** ** * * ******* * * (Array1[i] != Array2[i])
*** * ** * ** ** * ** ******* ** * *** * * ** ** * * *** 0;
* ** **** ** * * * *
** *** * * * * * * **
* * ** * ** * * *** * * *** * 1;
}

int main()
{
***** *** * * *** * * A[100],B[100];

** * * * ** * **** *** * *
* ** * ***** * * ** ** * ** *
* * * * * ** ** * * *
** ** ** **** * *** (is_anagrams(A,B))
** * * **** *
* ** *** * ** ***** ** * *** ****** ******* *** * * * words or phrases are anagrams");
** * * *** * ** ** * ***
* * * * ***** * * * *** printf("Two words or phrases are not anagrams");
*** ** ** ** * ******** ***
**** * *** *** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * * * ***** ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ** * *** * * * * *** **
*** ** ** * ** * * * (A[i] != '\0')
* * ** * ** * ** **** *
* * * * * ** ** **** * ** * * *** ** ** * *
* *** ** * * ** ******* * * * ** * *
********* *** * * * * * *
** * * * *** **** *
* *** ** ** * ***** * ** ** = 0;
* ** * ** * ** *****
* * ** * ** ****** * * (B[i] != '\0')
* *** * * ******** ***
* * * *** ** * ***** * * *** * * ** * * * *** ** * **** *
* *** ****** * ***** * * * * * ** * *
** ** ******** * ** * *
    
* * **** * ****** * *** (i = 0; i < 26; i++)
* **** *** * *** * *
*** * * ** *** * * ***** * * * * *** * ** *** (Array1[i] != Array2[i])
* * ** * ** ** *** ** *** *** * ** * ** ** * ** * ** ** ** * ** * * * 0;
** ***** * * * ** ** ******
** * * * ***** ***
**** ***** * * * ** 1;
}

int main()
{
*** * * ** ** **** ***** A[100],B[100];

* **** **** * *** ** ***** * *** ** ** ***
** * * *** * * ** ** * ***** * * ***
**** * **** ** **
** *** * * ** * * *** (is_anagrams(A,B))
**** * * * ****** * * **
** ** ** * * * **** ** * *** *** * * * *** ** words or phrases are anagrams");
* * ** * ** * ** **
* * *** ** * * ***** * * printf("Two words or phrases are not anagrams");
** ** *** * *** *
*** ** *** * * ** ****** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ******* ** * *
#include ** * * *
#include ** * *
int is_anagrams(char A[],char B[])
{
*** * ***** ***** * * ** lenA = strlen(A),lenB = strlen(B);
*** ** *** * * ** **** * * ** != lenB)
* * * * ** * * * * ** * ** * * * * * ** 0;

* * * * * * *** ** * ** i,j,k,a[26] ={0},b[26] = {0};
* ** * * * *** * *** * = 0 ; i < lenA ; i++)
* ** * *** * * ** *
** * * * * * *** ** * *** * ** * * * * * = 0 ; j < 26 ; j++)
** * * * ** * ** * * * * *** *** * * * ** * **
** *** * ** * ** ** * **** ** ***** ** * *** ** * ** ** * * * ** *** * * == A[i] || 'A'+j == A[i])
** * ** *** * ** * ** * **** ** ** ** ** * * * ** * * ** * * * *** * * * ** *****
** * * ** **** ** * *** *** ** *
* ** * * * * ** * ****
* ** *** * * ** ** *** * * = 0 ; i < lenB ; i++)
* ** ** ** ** * * **
* ** * ** *** *** *** * ** **** ** ** ****** * = 0 ; j < 26 ; j++)
** * * ** *** ** ***** * * *** ** * * *
*** * * **** **** *** * ******** * ** * ** ** * ***** ***** ** * * ** *** == B[i] || 'A'+j == B[i])
** * * * ** *** * ** * **** * ** *** * ** ***** *** ** * ** ** * *** ** * * ***
* * * * *** ** ********** * * ** *****
** *** * ** **
** * *** * * *** * ** = 0 ; j < 26 ; j++)
***** ** ** * ** *****
*** ** *** * ***** ***** **** * ** != b[j])
** * * * * * ** * *** * *** * *** ** *** * * * ** * ** * ** 0;
*** **** * * ** * * *** *
* * * *** * ** * ** 1;

}

int main(void)
{
****** ** ** * ** ** A[100],B[100];
* ** * *** * * ***** * * * * %s",A,B);

** *** ** *** * ** (is_anagrams(A,B)) *** * ** words or phrases are anagrams");
*** ** * * ** * ** *** printf("Two words or phrases are not * * ** ** *

* **** ** * * * * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * **
#include *** ****
#include ** *
int is_anagrams(char A[],char B[])
{
** * * * * **** * **** ** lenA = strlen(A),lenB = strlen(B),i,j,k;
* *** *** * * * ** a = 0,b = 0;
* * * ** ** ** * * * *** * != lenB)
** * ** * ** * * **** * ** ** * * * * *** * 0;
** * * ** ** ** ** * = 0 ; k < 26 ; k++)
* * *** ** * **** ** *
* * * **** ** ** * ** * *** * ** ** = 0 ; i < lenA ; i++)
* * ** * * *** * * *** ***** ** *** ** ********
*** * * * * ** *** **** **** ** * *** * ** *** **** * *** **** == A[i] || 'A'+k == A[i])
* ***** * * ** ** ******* * * ** * **** **** * ********** * ** * * * * * ** * ** ** **
* * * *** ** ** **** * *** ** * * *
****** * * ** *** *** ******* ** * * * ** ** = 0 ; i < lenB ; i++)
* ** ** ** * ** *** ** *** * * * *** * * **
** *** ***** ** * * ******** * * **** * ********** * * ***** * *** *** ** * == B[i] || 'A'+k == B[i])
* * **** * ** * * * * ** ** * * * * * * * ***** * * * *** *** **** * * * * ***
* * * *** * ** ** ** * * * * **** * * * ***
* *** ** * ** ** *** *** * ***** *** * ** != b)
** **** * * * * *** *** * * * ** * * * * *** ** 0;
** * * *** ** * * * **
** * * * ***** * * ** * ** * ***** * * * ** * * * * * *** * ** 1;
}

int main(void)
{
***** ***** * ** *** A[100],B[100];
* ** *** * * * * * * ****
* * ** **** ** * * **** * *
* * * * * ****** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* *** * * * * printf("Two words or phrases are not anagrams");

* ** * * ** * * *** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ****
#include *** ** ****
#include *** ** ** * * *
int is_anagrams(char A[],char B[])
{
* * * * ** ** **** * * YOUR CODE HERE*/
* * ** ** ** ** *** i,count[256]={0};
*** ** * ** *** * * *
** * ** ** ** * ***
* ** * * ****** ** *** *** ** * * **** * *** ** ** * * ** * ** **
* ******* **** * **
* ** ** *** ** ** *** ** *** * *
* ** * * ** * ** * *
* **** * * *** ** ** *** * * ************ ** *** * * * *** **** *** *** * * *
* ** *** * **** ** **
/*
*** ** * * *** * * ** (A[i]!=0 || B[i]!=0){
*** *** * ** * ** ** ** * * *** ** ** ** * ** **** ** **
** *** * ** ** * ** ***** ******** * ** * * *** ** ** 0;
** * *** ** * ** *
*/ * * * * * * ****** * * * * 0;

* * * * *** ** **** * **** * (i = 0; i <256 ; i++)
** *** * **** ***** ** **** * ** * * **** ** * (count[i] && i!=' '){
**** *** ** * * * * * ** * * ******** ** * ***** ***** *** ***** * * * ** *********
** * * *** ** * ** * *** *** ** ** * * ******* ** ** * 0;
*** *** *** * * ** *** *** *** ***** ** * * *** *


**** * ********** ** ** 1;

* * * * * ** OF YOUR CODE*/
** * * * * ** * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
*** ** *** ***** * * A[100],B[100];
* *** * ** YOUR CODE HERE*/

** * * ** ** * ** ****** ** * ***
** *** **** * * * * * ******* *

**** ** ** * *** * * ** ** *** = '\0';
  // ** * ** ** * * = '\0';
**** * * * ** * **** * i;
***** ** * * ** * * *
** * * ** ** * * ** ** * **** ******* ** *** * *** * * *
** * * ** *** * * * * * * * ** * * ** * * *
** *** *** * * ** *** ***** * ** ** *
* **** * * *** * * * ** ** ** ** *** **** * *** *** **** ** *** *** **
** ** **** * **** * * ** ** *** *** ** * ** * **

* * * ** **** OF YOUR CODE*/
* ** * ** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** * ** * ** * * ** printf("Two words or phrases are not anagrams");

** *** ***** * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ***** *****
#include ** ******* *
#include *** ** * *
int ** * * A[],char B[])
{
* *** * * * YOUR CODE HERE*/
* * **** * * ** * * * ** ** * *
* ** ** ** ** ** * * * *** * * ** ** *
******* * * *****
***** **** **** *** ** **** * *** **** * ** *** ***
*** * ***** * *** ** **** * ** ** * ** * ***** **
**** * * ***** ** * ** *
*** ***** ** ***** (A[i] || B[i])
*** ** *** * * ** * ****** ** * ***** 0;

* * * ** * * ** (i = 0; i < 256; i++)
** ** ** *** * * * *** * * * **** *** ** ** *** *
* * * ********** ** ** * * **** *** * * * * * ** ** * ** * * **** * * ** * ** 0;
** * ** * * ** *** * 1;

* * ** * ** * * OF YOUR CODE*/
*** * **** ** * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ****
{
*** *** *** * ** * *** ** * *
* ** ** * ** * * ** YOUR CODE HERE*/
**** **** **** ** ***** * *** ** * ** ** * ** * * ** *
** **** * * *** * * * ** ** * ** * ** *

** ** * * * ** * OF YOUR CODE*/
** *** ***** *** ** * * * ** *** words or phrases are * *** ** *** *
* ** *** * * * * * * * * words or phrases are not * **** ** **

**** * ** * *** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * ** *
#include ** ** ** ***
#include ** * * *
int * * * A[],char B[])
{
* ** * **** * ** ** * YOUR CODE HERE*/
** * * ** * * * *** ** * ** *
** *** * ******* ** ** * ***** * * * **
** * * ** * * **
**** ** *** * * **** ** ** * ** ** ** **** *
***** *** * **** * * * **** ** ** * ** *** * ** ** * *
** **** * * * **** **
* ** *** * ** * * *** ** (A[i] || B[i])
******* * * ***** * ** ** 0;

*** ***** * ** ** * * (i = 0; i < 256; i++)
* * * * * *** ** * * ** ** * *** * * * * *
** * ** * * ** ** * * * * ** *** * * * * ** * ** *** *** *** * 0;
*** ** * *** * * ** *** * *** 1;

* ** *** ** ** * * ** OF YOUR CODE*/
*** **** *** ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** *
{
* * *** * * * * *** ****
* ** *** ** ** ** * * YOUR CODE HERE*/
***** * ** *** * *** **** ** ** ** ** * **
**** **** * ***** * ** * * * ** ** * *** ***

* ******** * **** * * OF YOUR CODE*/
* * * * * **** * * * * * *** ** * * ** words or phrases are ** * * * *
** * *** * ** * * * *** * * words or phrases are not * *****

*** ** ** * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.189
©2016-2024

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 1.5k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 2k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 1.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users