0 like 0 dislike
21.7k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 21.7k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include **** * **
#include ** ** * ** ***
#include *** ** *** *
int **** * a[],char b[])
{
** *** ** * ** ** first[26] = {0}, second[26] = {0}, c = 0;
** *
*** * * * * ***** * frequency of * *** * in first string
*****
** * ** ** ***** * * ** (a[c] != '\0')
** * * **** **
* * * * * **** ** * * **** * ** **** *
* *** * * * *** * * **** ***** ***
* ** **** *
* * *
* * * ** * * ** = 0;
* * ** *
** * * *** * * * (b[c] != '\0')
**** * * ** * * **
** *** * **** * * *** **** ** * *
*** * **** * *** * * ** ** * *
* ** * ***
* * **
** ** * ********* ** Comparing frequency of ********

** * ** * * * (c = 0; c < 26; c++)
* ** *** * * **
**** ** * * * * * * ** **** ***** (first[c] != second[c])
* ***** * * * ** * * * * * * ** * * * * * * * ** ****** * 0;
** ** * *** * **
* *
** * *** **** * 1;
}

int * * *
{
**** ** ** * *** ** * ***
* *** ** ** ** *** * * * * A,B);
* * * * **** * * **** * ** ** * words or phrases are **** * *
*** * * ** * * * ** words or phrases are not * * *** * *

****** * *** * * *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * **
#include * * ***** ***** **
#include * * ** ***
int ***** * *** a[],char b[])
{
* *** * * * ** *** * first[26] = {0}, second[26] = {0}, c = 0;
* *
* * * * * * * frequency of characters in first string

** **** * ** ** (a[c] != '\0')
**** ** * * **
* * * *** * **** * * ** * ********** * *** * *
** ** *** * * ******* * * **** ** *
* * * **** * * *
** ***
* * ***** ** ** * = 0;
*** *
* *** * * *** * (b[c] != '\0')
** * * ** **
* * ** * **** **** * *** * ***** * ** * *
* * ** * * *** * ** * * ** ** * *
*** * ** ** * **
**
****** * *** *** Comparing frequency of ******
*
* * * * ** ** * ** (c = 0; c < 26; c++)
* **** * ** *
* * * * ******* * * ** * * (first[c] != * *
* * **** * * * ** **** ** ** ****** * **** * ****** ** * 0;
** * *** * *
* ***
* **** * * ** * 1;
}

int main(void)
{
** *** ** ** * ** ** **
**** ** **** * * * ** * * * *** *** *
* *** * *** * * ** * ******** ****** words or phrases are ** **
* * ** * * * *** * *** words or phrases are not ** *** ** *

*** *** ** ** * * * * *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** ** * ****
#include * * * ******
#include ** ***
int is_anagrams(char A[],char B[])
{
* * **** ***** ** * * ** * YOUR CODE HERE*/
* * **** ** * * *** * ** * * * * *
** *** *** * ** * * * * ** *** **
** **** ** * * * * ***
* ** * ** * ******** ** * ** ** ** * * * * *** && ***** ** ** ** *
***** * *** ** * ** * * * * **** ** *** * *** ** ** * * *** **** * * *** * **
*** * ** * ** ** *** * ** **** ** * * ** *** *** && ***** * *** ***
* * ** ** ** **** ** * *** **** * *** *** *** ** * *** * * * **** * ** * *
* * * * * *** * ***
* ** ***** * * ** ** * * * ***
* ** * *** * *** * *
* ** * **** *** * * ****** * *** ** * * (cA[i]!=cB[i])
* * * * ***** * ** * * **** * * **** ** ** * ** * * * *** * ** ** *** * 0;
*** * * * **** ****
* ** **** * *** * * *** **** 1;
*** ** * **** OF YOUR CODE*/
* * ** * ** ***** * function should return 1 if two words or phrases are anagrams,
**** * ** * if two words or phrases are not anagrams.
}

int main(void)
{
*** ** * *** * A[100],B[100];
* **** * * * ********* YOUR CODE HERE*/
* * **** * ** * * * * ** ***** * ****** *
* * * * * * * *** ****** ** * * **** ***
*** ****** ** * *** * ** (is_anagrams(A,B))
* ** *** * * * * * ** **** * ** * ** * * * * * * * words or phrases are anagrams");
* ** ** * ** ** ** * **
** * *** * *** * * ** * *** *** ** * * ** ** *** **** * words or phrases are not anagrams");
**** *** ** * * **** *** 0;
* ** ** ** *** ** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * * **** ** * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
****** * ** * ****** * ** *
* * ** * * ** *** * * (A[i] != '\0')
* ** * *** * ***
* * * * * *** * ** ** **** *** * ** *
**** ** *** * * **** * ** ** **** * *** * *
** * ** *** **
* * *** * * ** * * *
** * * * ** * *** *** = 0;
*** * *** ** ** *** **
* ** ** **** ** ***** *** (B[i] != '\0')
* *** * *** ** **
**** *** * ** * * ** ****** * ** * * ** * ** * * ** **
* * ** * *** * * * * * * *** * ** *** * *
** * * * ** ****** *
    
* ***** * * ** * * *** (i = 0; i < 26; i++)
* * ** * * *** ** ***
** ** ** * * * * ** *** * ** *** ** ***** ** * (Array1[i] != Array2[i])
* ** * * * * * ** *** * ***** ** ** * *** **** * * ** * *** ** ** * * 0;
** * ** ****** *
* ** * **** * *
* * **** ** * * **** * 1;
}

int main()
{
* * * ** ** *** ***** A[100],B[100];

*** * * * * *** * *** * * * *
* ** * * ***** * ** ** **
* * * ** * * *
* * * * * *** ** * * (is_anagrams(A,B))
** * * *** * ** * *
* * ** * * * * * *** **** * * **** *** * ** ** * *** words or phrases are anagrams");
* ***** *** *** ** **
** *** * * * **** * ** printf("Two words or phrases are not anagrams");
* * * * ***** * *** ***
* * * ** * * * *** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** *** * ** *** **** *** Array1[26] = {0}, Array2[26] = {0}, i = 0;
** * *** ** ** *** *
* ** * ** * * * ** ** * ** (A[i] != '\0')
* * ** ***** ** * * * *
** * * * * * ** * **** ** ** * * ***** *** ****** *
**** * * * * * * ***** * **** ** * * *** ***** *
**** * *** * * * * ** *
*** * * * *
* ****** *** *** = 0;
* ** ** * * * * * **
** ** ** ***** * * (B[i] != '\0')
***** * ** ** * ** ***
*** * * * ** ***** * ** *** ******** ***** * * * * ** * *
**** * * *** ** * ** *** *** * * ** * *
******* * ** *
    
** * ** ** ** * * *** ** ** *** (i = 0; i < 26; i++)
* * * * * *** *** **** **
*** ** *** ** ** * * *** ** * ** * *** * * * * (Array1[i] != Array2[i])
* ** * ****** * * * *** * ** ** **** ** * * * **** 0;
* * ** * *****
* ** *** *** * *** * *
* * * **** *** * * * * * 1;
}

int main()
{
*** * * * **** * * A[100],B[100];

** * ** **** ** ** * *** * *** **** ***
****** ***** * * * *** * * ** *** ***** **** *
* ** * **** ** ****
* ** * * * * (is_anagrams(A,B))
****** * ** ** *** * *
** ****** **** * ********* ***** ****** ** * * * words or phrases are anagrams");
****** * *** ***
** * **** * ******** * ** printf("Two words or phrases are not anagrams");
** * **** * * * ** *
** * *** * * ***** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** * ***
#include * * ** *
#include *** *** * *
int is_anagrams(char A[],char B[])
{
* * * ** ******* * ** * lenA = strlen(A),lenB = strlen(B);
**** * ** ***** * ****** *** * != lenB)
* ** * * * * * ** * *** * * * * ** ** 0;

* ** * ****** ** *** *** * i,j,k,a[26] ={0},b[26] = {0};
* * ** **** * *** *** *** = 0 ; i < lenA ; i++)
*** *** **** * *** * * *
* **** ***** ** ** ** * * *** *** *** * ** *** = 0 ; j < 26 ; j++)
* *** ** ** ***** * *** * * * * ** * **
* ** ** ** ****** ** * * ** * * * * ** ** ****** * * * == A[i] || 'A'+j == A[i])
********* * *** ***** *** * ** *** ** * * ** * * * * * **** * ******* *** * * ***
* ** * * * * ** * * ** **** ***
** * * * * * *** *
* * * *** ** * ** * * * = 0 ; i < lenB ; i++)
** * **** * **** * ** ***
* ****** ** * * * * *** ** * ** **** = 0 ; j < 26 ; j++)
** ******* **** ** * * * *** *** ****** ******** **
* * ***** * * * * * *** ** * *** * *** * * ** ** ** * * == B[i] || 'A'+j == B[i])
* ***** ** *** **** *** ** *** ******** * *** * **** * ** ** ***** * ** ** * ***
** * * * ** **** *** *** * * *** * * *** * * * *** **
*** **** **** **** *
* * * * ** * * * * * = 0 ; j < 26 ; j++)
** * ** * ******* ***
***** * * **** ***** *** ** * ** ***** *** ** ** *** != b[j])
* **** * * * * ** * ** **** * ***** ** * * * * ***** 0;
* * *
****** ** ** * *** ** 1;

}

int main(void)
{
* * * * ** ** A[100],B[100];
** * ****** ** * * * * * %s",A,B);

** * * * * (is_anagrams(A,B)) **** ** words or phrases are anagrams");
*** ** * * ** * **** printf("Two words or phrases are not * ** *** **

*** * ** * * * * ** ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * **** * * * **
#include * ****
#include ** **** *
int is_anagrams(char A[],char B[])
{
* * ** * ***** * lenA = strlen(A),lenB = strlen(B),i,j,k;
* * ** * *** * * * * a = 0,b = 0;
**** ***** ** * * * * ** ** * != lenB)
**** ***** * * * * ** *** ** * * * * ****** * 0;
* * * * **** * ***** * * = 0 ; k < 26 ; k++)
* * ***** * ** *****
* * * *** * * * **** ** * * ***** *** = 0 ; i < lenA ; i++)
** **** *** ** ** ** ** * ** ** * ** ** **** *
** ******* * *** * * ** *** * *** * * * ** *** ** ** ****** * * * ** == A[i] || 'A'+k == A[i])
** ** ** * * ** ** **** * **** * **** * * * * ** *** * * ***** * * * * * ** ****** *
** * ** * ** * **** ** * * * ***** * * *
* * ** *** ****** * * ***** ** ** * ** = 0 ; i < lenB ; i++)
** * * ** ** ** ** * * ** ** * **
** ***** * *** ****** * ***** *** * **** * **** * *** * ** * * ** *** * * * ** == B[i] || 'A'+k == B[i])
** ** ** *** * **** * **** ** * ** ** ** *** ** ** * ** * *** * * * * ** *** ** **
* ** *** *** * **** * ** *** ***** * * ** * ***
*** * * * * ** * * * * * ** * != b)
***** * * * ** * * * *** * *** ** **** ******** * *** * 0;
* **** ** ** ** * * * ** * * * **
*** * ** ** * * ** * * ******** * **** ** ** ** ** * ** ** 1;
}

int main(void)
{
*** *** * * *** A[100],B[100];
* * *** ***** ** * * **** **
**** * ** * * * ** ****
*** **** *** * ** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ** * * *** ** printf("Two words or phrases are not anagrams");

* * ** * ** ** * ***** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * *** ** *
#include *** ***** * *
#include * **** *** ** *
int is_anagrams(char A[],char B[])
{
* ****** ** * ****** YOUR CODE HERE*/
* * **** * ** **** * i,count[256]={0};
** **** ** * ******* ** **
* * ** **** ** * *
** * * * ****** ** * * * * * *** * ****** * ** * * ** * ** ****
* * * * ** ** *****
*** * * *** *** ** ** * * *** *
* * ***** * * * ** ** *
*** * * ****** ** * * ** ** ********* ** * * * * * * * * ** ** ** * ** ** * **
******* * * * * * *
/*
* ** * *** * * * * (A[i]!=0 || B[i]!=0){
* ** * * **** **** * * * ** ** * * * * ** * * * * * * ** ***
* * * ** * * * **** * * *** ** ****** * * 0;
* ** * * ****** **
*/ * *** * * * ** *** * * 0;

* ** * ** * *** * (i = 0; i <256 ; i++)
* *** * * ** *** * *** * * * (count[i] && i!=' '){
**** * * ****** * ** **** **** * * * * ** *** ** * **** * * * ** ** **** ** * **
** ******* * ** ** * * ** * ** * * **** * * * ** * 0;
* * ** ** * * * ** ** * **** ** * ** *


* * ***** **** ** ** ** ** * * 1;

*** *** * ** ** * ** ** OF YOUR CODE*/
** * * ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
** ** * * ** * * A[100],B[100];
* * * *** * * * ** * YOUR CODE HERE*/

** * * **** * * * * ** **
* * * *** ** ** *** *** * *****

* * * * ** * * ** * * ** * * * = '\0';
  // * * * ** ****** = '\0';
* * * ** ** ****** ****** i;
*** * * ** **** *** * * **
* * ** * ** * **** * * * ** ** **** * *** * * ** * *** *** * *** *
* ** ** ** * **** * * * ** ** * ** ** * *
* **** ** *** ** * * ** *
* ** *** * * * * * *** * * ** * ** ** ** * * ******* * **** *
* * **** ** ****** ** * * ****** ** ** * * ** * ** **

* ** * * ** ** * ** OF YOUR CODE*/
* * * * * * *** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* *** ** ** * * * printf("Two words or phrases are not anagrams");

* * * * * ***** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * **
#include ** *****
#include * *** * *
int * *** ** * A[],char B[])
{
* ** * * ** * * YOUR CODE HERE*/
** * * ****** * ******* * * *** *
* * ** * ***** ** *** * * ** ** ***** *
** *** * *** * * * *
** ********** * * ** ** ** **** ** * * *
* ***** * * ***** * ** * * ** ** * ** *** * ***
**** ** * ******* ** * *****
****** * *** * * * *** * (A[i] || B[i])
** ** * **** * ** ** ****** 0;

***** * * *** * (i = 0; i < 256; i++)
* * * * * * * * ** * ** * * *** ** * ** * * ** ****** **
* * * * ** * * **** * * * ** **** ** * **** ** ** * * ** * ** 0;
* ** * ***** ** ** ******** * 1;

* * ***** **** * ** * OF YOUR CODE*/
* ** * ***** * ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
* *** * * * * ** *** * * *
** * * * * * **** YOUR CODE HERE*/
* ******* ** ** ** * * * * ** ** * ****** *** ****
*** * * * * * ** ** *** ** **** ** **** ****

* *** * * * OF YOUR CODE*/
*** ***** * * * * * *** * * * ** *** words or phrases are * **** *
**** * ** * * **** ** ** * ** ** words or phrases are not * * * **

** * *** *** * * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** ** **** *
#include *** * ** ** *
#include * ** **
int ** * * * * A[],char B[])
{
* ** * ***** * * * *** YOUR CODE HERE*/
** *** ** ** ** ** * * ***** *
* * ****** * ** * ****** * * ** * **
*** * * *** ***
**** ****** *** ** ** ** * * * ********* * *
** * * **** ********* ** ** * * * ******** *****
****** * *** * * ****
* **** * * * * **** * * * * (A[i] || B[i])
* * * * * *** ****** * * **** * ** * * *** 0;

* * * ** * * *** (i = 0; i < 256; i++)
* **** * * * * *** * **** ** * * * * ***
** * * ***** * * **** * ****** * ** * ** * * ****** * * * * * * 0;
** * * * * * *** *** 1;

* ** *** * ** ** * OF YOUR CODE*/
* ** *** * ** * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int **** ** *
{
* ** ** * ** * ** * **** ***
** * *** *** * * *** * YOUR CODE HERE*/
***** *** *** ***** *** * * * * * *****
* *** * * * *** *** ** ** ** * * **

* ****** * ***** * * * ** OF YOUR CODE*/
* *** * * * *** ** ******* * ** *** **** * words or phrases are * * *** * *
* *** * ** * * **** ** * * ***** words or phrases are not * **** * **

***** **** * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 11.6k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 10.9k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 10k views
12,783 questions
183,442 answers
172,219 comments
4,824 users