0 like 0 dislike
12k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 12k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * ** ** ** *
#include * * ** *** **
#include * * *** ****** **
int ** **** a[],char b[])
{
* * ** * * ** first[26] = {0}, second[26] = {0}, c = 0;
****** *
** * *** ** ** * *** * * **** frequency of * ** in first string
* * *
******* ** ** ** (a[c] != '\0')
* **** ****** *** *
* * *** * *** * *** *** ** **** **
* * * * * *** * * *** ** * *** * *
** * ** ** * *
*****
* * ** * **** * = 0;
* ** *
* * ** * * *** (b[c] != '\0')
** * * **** *
** ** * *** * ** ** ** **** * *** * *** **
**** * **** * * *** * ***** *
**** * ** * * *
**
* * ** * * * * * Comparing frequency of **
*****
** ** * * *** * * ** (c = 0; c < 26; c++)
* * **** * * *
*** * * ** ** ** * * *** * * * ** ** ** * **** (first[c] != second[c])
*** * * * * * ** ** ** * * * * ** **** * ** ** 0;
* ***** * *
* **** *
*** ** * **** * * 1;
}

int ***** **
{
* ** *** *** * * ** * *** **
* * * ******* ** ** ******* * ******* A,B);
* * * ** * * ** * * * *** **** * words or phrases are *** *** *
* * ***** ** *** **** ** * words or phrases are not ** *** ***

*** *** * * * ** ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * *
#include ***** ** ** **
#include * ** *** * *
int *** * * ** a[],char b[])
{
****** ** ** * * ** * first[26] = {0}, second[26] = {0}, c = 0;
** * **
* * * *** **** * ** * * ** * frequency of characters in first string
* ** *
** * * ** * ***** (a[c] != '\0')
*** * ** *** ***
* ** ** **** ****** * * **** * *** * ** **
* *** **** ** *** * **** *
** ***** * **
** **
** ******* **** = 0;
* * * *
* * *** * ** * * *** (b[c] != '\0')
*** * * ** * * ** *
* **** ** * ****** *** * * **** * ***
**** ** *** * * *** **** * * *
* **** * * ** ** *
*** **
***** *** * * * Comparing frequency of ** ** *
*
* ** ** * ********* (c = 0; c < 26; c++)
** * ** * **
* ** * *** * * *** **** * * (first[c] != *** *
* * * * ** * * ** * * * * *** * ** * * *** * * * 0;
** * * * * *
** ***
* ****** * * *** ** ** 1;
}

int main(void)
{
* ** * * * *** * * * * *** *
* * * *** ** * * ** ***** * *** * * **** * *
* * * *** * * * * **** ***** ** words or phrases are ** ** **
******* ** ** * ** ** * words or phrases are not *** *

** * * * ** ** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * *** *
#include * *** * ** * **
#include * * ***** * *
int is_anagrams(char A[],char B[])
{
* * * *** ***** YOUR CODE HERE*/
*** * * **** *** *** * ** *** * * * *
*** *** *** * * * **** *** * * ** **** ** *
***** ***** ** * * ** *
*** ** **** ******* ** ******* *** * ** ** * * * * * ** *** * && *** **** *
* * * * * **** *** **** * * * * *** *** ** * * *** * ***** * ** *** * *** * ** ***
**** *** * * *** ** * * *** * * ** *** * * * * * ** * * * ** && ***** *** *** **
*** * * *** * * * ** *** * ** * * * * * * * * * * *** * ** * ** * ** * * *
** * **** *** ** * * *
** ** * *** * * * **** * * *
* * ** *** ***** ****
** * * ** * * * ** ** ********* ** * * * (cA[i]!=cB[i])
* ***** * * ****** ***** ** *** ** * *** ** ** **** * * ****** *** * 0;
* *** * * * * * * ***
*** * ** * ** * ** * * 1;
* **** * ** * * ** OF YOUR CODE*/
**** * *** * ** * function should return 1 if two words or phrases are anagrams,
*** *** * * * * if two words or phrases are not anagrams.
}

int main(void)
{
**** * * * *** * ** * A[100],B[100];
** ** * ** *** * * YOUR CODE HERE*/
*** ** * * *** * ** * *** ** ** ***** * * **** *
* * *** ** ****** * * *** * ** **** *** *** *
**** *** * * *** ** * (is_anagrams(A,B))
* * ** **** * * ** *** ***** ** * * ** * * ** ** words or phrases are anagrams");
* * * * * * * ** *
** * * ** ** * * ** * ** * * * * * * words or phrases are not anagrams");
* ****** ** ** * * * 0;
** * *** ** ** * * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** *** * ******* ***** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ***** * *** * *** ***
** * * ** ** **** * (A[i] != '\0')
* ** *** ** *** ** *
** ** ** *** * * *** ******* *** ***** ****** * * *** *
* ** ** * **** ***** * * ***** ** * ******
* * * * **** * * * ***
* ** ** * **** *
* * * * * ** *** = 0;
* ******* ** ** **** * *
*** ** ****** * * * * **** (B[i] != '\0')
*** * * * * *** * ***
* * *** ** ** * * **** *** * *** ** * * *** * *** ***
** * *** *** * **** * * * **** * ** * * ****
* * ** * ******* * * *
    
***** *** * ** *** (i = 0; i < 26; i++)
* * ** * * *** *** *
* * * ** * ** * ******* **** *** ** *** * * ** (Array1[i] != Array2[i])
* * * * * *** * * * * *** * * * ***** ** * ** ** ** * * * 0;
***** * * ** * ***** * *
* *** ** *** ** * *
**** *** * *** * * * 1;
}

int main()
{
* * * * *** * * ** ** A[100],B[100];

* *** * *** * * * * ** *** ** **
* *** * * * * *** *** * **
** **** * * * * ***
* ** ** *** ** * * (is_anagrams(A,B))
*** * *** *** ** *
* ** * * ****** **** ** *** **** * ** ** **** ** **** * ** words or phrases are anagrams");
* * *** * * **** * * *****
** * ** *** * ** ** * printf("Two words or phrases are not anagrams");
***** ** * * * *
* ** ** * * * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * *** ** * * * * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * *** *** * *
* * ** ** ** * * ** ** (A[i] != '\0')
* * *** * * * * *
* ** **** *** ** * ** *** *** ******* * * * * *
*** * ****** * * * *** * * * **** * * * *** * *
* * **** ** *
* ** ** ***
*** * ** * ** **** ** = 0;
* ***** * * ** ** * *****
**** *** * * * * * * * ** (B[i] != '\0')
** *** **** * * * * *
* * * ****** *** * ***** *** * * ** * ** * * ****
** * ** *** **** * * ****** * ****** *** * * *
** * ** * ***** ***
    
* * ** ** *** ** * * * (i = 0; i < 26; i++)
* * ** * **** * ** * **
** ** ** *** * * * ** **** ** * ** * * (Array1[i] != Array2[i])
* * *** * ** * ** * ** * **** ******** * * ** ** ** ** * ***** 0;
*** * * **** * * * *** ** * **
** * ***** ***** **
** * * * * * ** ** * * 1;
}

int main()
{
** ***** * * * ** * *** *** A[100],B[100];

* * * ***** * * ** ** * * * ** *****
* *** * * ***** ** ** * ****** * *****
* ** ** ** * * ** ** ***
** ******* * * * * (is_anagrams(A,B))
** *** * *** *** **
* * **** * * * ** * * * * ** * ****** * ** ** * ** ** words or phrases are anagrams");
****** *** * * *** ****
* * ** * * * *** ** * *** printf("Two words or phrases are not anagrams");
* * ******** * ** * *
* ** * * * * * * ** * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** *** ***** **
#include ** * * **
#include ***** * * ***
int is_anagrams(char A[],char B[])
{
** * * * *** * * ** * lenA = strlen(A),lenB = strlen(B);
*** * * * ********* * * * != lenB)
** *** * * * * * * *** * ** *** ** * **** 0;

* **** ****** * **** * i,j,k,a[26] ={0},b[26] = {0};
* *** * ** * * * ** = 0 ; i < lenA ; i++)
*** ** * *** *** * * * *
* ** * ** ** ** ***** *** ** * ** * ** ** = 0 ; j < 26 ; j++)
* * * * *** * ** ** * * * ** **** * **
***** * ** * ** ** ** ** * ** *** *** * * * * ** * * * * *** * == A[i] || 'A'+j == A[i])
* * * * *** ****** * * * * * * ** * ** ** * ** *** ** ***** * ** * ** * ** **
**** * ** * * ** * * *** ******* ** *
* *** * *** ** ** *
* ** * * ** * * ** ** = 0 ; i < lenB ; i++)
** * * ** * ** ***
** **** * * * ** * * * ** ***** * * * * * = 0 ; j < 26 ; j++)
* ** * * ** *** ****** ** * * * * * *****
** ** * ** * *** *** *** ** *** * ** ** * * * * *** *** * ** * * * ** == B[i] || 'A'+j == B[i])
** ** ** * * **** ** ** * *** ** * * ** ***** ** * * ** ***** ** **** *** *
*** * ** * ** * * * * ** *** * ** ** * ** *
* * * * *** ** *
** ** ** * * ** ******* = 0 ; j < 26 ; j++)
** **** * * ** * * ** *
* *** * ** **** ** * *** ** * * * * *** ** != b[j])
* * * *** ** *** ** ** * *** * *** * * * * * * * **** **** * 0;
** * ** ** * ** ** *
*** ** * * * * ** * ** 1;

}

int main(void)
{
* ** * * *** * *** A[100],B[100];
* ** * ** ** ******* * * %s",A,B);

* * *** ******** ** ** * (is_anagrams(A,B)) ** **** words or phrases are anagrams");
* * * * * **** printf("Two words or phrases are not ** *******

*** ** ***** * ** ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *** * * * *
#include ** * * * **** *
#include * * ** **
int is_anagrams(char A[],char B[])
{
** * ** * * * *** ** * * lenA = strlen(A),lenB = strlen(B),i,j,k;
** ***** * ** * * ** * ** a = 0,b = 0;
** *** ** * * ** **** ** ** != lenB)
*** *** ** **** ***** *** ** ** **** * * 0;
* * * *** * **** = 0 ; k < 26 ; k++)
** ******* **** *****
*********** * ** *** ** * * * * *** ** * ** **** = 0 ; i < lenA ; i++)
** ** * * * ** * * * * ** ****** *
*** * ** * * **** *** *** * * ** *** ***** *** ** * * * ** * * * == A[i] || 'A'+k == A[i])
* * *** *** * *** * ** * * ***** ** * * ********** * * * * * ** * **** ** *** * ** *
* * * * * * ** * ** ** * * ** * *
* ****** * *** * * ** ** * ** * * ** = 0 ; i < lenB ; i++)
* * ** * *** * ** ******** * * ** * * *** *
** * * * ***** ** * * *** ** * *** *** **** * **** ** *** ***** ** * * * == B[i] || 'A'+k == B[i])
** ******* * ** ** ** * ***** **** ****** * * * *** *** * ** ** ** ** **** * * ****
* * * * *** * ******* * * * * **** **** *****
* * * * *** * **** * * ** * * * ** * ** ** * != b)
*** ** * *** * *** * * * ** * ** * * ** **** ** * * **** * ** 0;
**** * * ** ** ** * ** ** * * *
***** * ** * ** * * **** * **** * ** ** ****** **** *** * ***** 1;
}

int main(void)
{
*** * ** * ** * A[100],B[100];
*** * *** * * * ****
** ***** ******* *******
** * ** * **** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*** * * ** * printf("Two words or phrases are not anagrams");

* ** ** * * **** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * ** *
#include *** ** ** * *
#include * ** **** *
int is_anagrams(char A[],char B[])
{
** * **** * * ** *** * YOUR CODE HERE*/
*** * * ** ** * * ***** i,count[256]={0};
* * * ****** * ** *** *
** ** * ***** ***** *
** * * ** * *** ** * ** ** * * * **** * ** **** ** * ** **** * * * ** **
* ** * * *** ***
** * **** * * * * ** * ** * * * *
** ***** ** ** ****
* ** ** **** * ** * **** *** * ** * * ** **** * * * **** * **** * * *
* * **** **** * * *
/*
*** *** * * ** ** * *** * * (A[i]!=0 || B[i]!=0){
* * * * * * * ********* * *** * ** ** ** ** * ** *
* *** ** *** ** ** * ** **** * * ** 0;
** * **** *** * ** *
*/ * *** * ** * * * * ** * * * *** * 0;

** *** ** *** ** ** * (i = 0; i <256 ; i++)
* ** ** * **** * * *** ** * ** *** ** (count[i] && i!=' '){
* * * ** * **** * ** * **** * **** ** * * *** * * *** *** *** * *** * ** * * * **
*** ** * ** * ** *** * * * * *** * * ** ***** ***** ** * ** *** * ** * ** 0;
** ** * * * ** ** * * ** * ** *** * * * ***


* * ** ****** *** * 1;

****** * * ***** * * OF YOUR CODE*/
** * * ** * **** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
** *** * * ** * * A[100],B[100];
* ** ** ** ** * * YOUR CODE HERE*/

* * * ** *** * ** * *** *
** ** ** * * * *** * * * *** *

* *** * * ** * *** * = '\0';
  // * * * ****** * = '\0';
** * * ** ******* ** i;
* * * * * *** ** * *** ** * ** * *
* * **** * ***** ** * * * * ** *** * ** * * * **** * ** * ** **
** **** * * *** ** * * ** * ** * * ** **** *
** ** * ** * * * * * * * *
* * *** ******* * * ** ** *** * * *** ** ** ** * * ** * ***** ** ** ***
* **** * ** ** ** * * * **** * *** *

* * * ** ** * * OF YOUR CODE*/
* ****** *** ** *** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
**** * **** ** * * printf("Two words or phrases are not anagrams");

** ** * ** ** ***** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * **
#include ** ** * *
#include ** ** * **
int *** ** * A[],char B[])
{
** * ***** *** ** * **** YOUR CODE HERE*/
** * *** ** * * ****
* *** * ****** ** ***** * ** * * * * ** **
** * * * ** * ** * *
** ***** ***** * * ** **** * ***** * * * ** * *
*** *** * *** ** * * * * *** ** ** * ****** *
* ** * * * ** * ***
** ** *** ** * ** * (A[i] || B[i])
* * ** ** **** ** *** * ***** ** * * 0;

** * * * * ** * ** (i = 0; i < 256; i++)
*** * * ****** **** **** **** * ****** ***** * ** *
***** * * *** ** * * ** ******** * *** * *** **** ** * ** 0;
* * ** * * * *** **** 1;

* * * * * * * ** OF YOUR CODE*/
**** * * *** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *** * *
{
* ***** ** * * * *** *
* * * ***** ** ** * YOUR CODE HERE*/
**** * * ** * *** * * * ** * *** *** * * * *
* * ** * * * ** * ****** * * * * ** ** ** ******** *

**** ** * * * ***** ** OF YOUR CODE*/
* ** ** ** * * ******** * * *** ** words or phrases are * * * ***
** * * ***** * * * * * words or phrases are not *

* * *** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * ** *
#include * * * * *** *
#include ****** ****
int * *** * A[],char B[])
{
** * ** ** * * YOUR CODE HERE*/
** * ** ** *** * * * * ** *
* * * ** * ** ** *** * * ** ** * ******
** * * ** * * * ** *
* * * *** **** * *** * **** * * * *** *** ** ***** *
* ** ***** * * * * * * * ** *** ** * * ** ** *** **
* * ** * * *** **
* * ** ** * *** * * (A[i] || B[i])
** ** ****** ** ** * ** * ** ** ** * * 0;

** **** * *** * **** * * * (i = 0; i < 256; i++)
** * **** * * **** * * * ** * ** ** * *
** ** ** *** ** * **** * ***** *** * ** * * ** ** ** * ** * 0;
** ** *** *** * * * ***** 1;

****** *** * * OF YOUR CODE*/
**** * ** *** * * *** *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * * ***
{
**** ** * *** *** ** *
** * ** *** *** * ** ** YOUR CODE HERE*/
* **** * * * * * * ** ** * ** **** ** ****
**** * **** ** * *** *** ****** * ** * ***

* ** * ** *** OF YOUR CODE*/
** ** ** ** * * *** ***** *** * * **** words or phrases are * * * ** * *
*** * ** ** *** * ****** words or phrases are not * *** ** ***

* ** ** **** ***** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.193
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 5.9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.3k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users