0 like 0 dislike
12.8k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 12.8k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * * * * *
#include * *** * *
#include * ** *****
int * * a[],char b[])
{
*** *** *** **** * * first[26] = {0}, second[26] = {0}, c = 0;
** * **
*** * ** **** *** * ** frequency of ** *** in first string
** * **
**** * * * ** * (a[c] != '\0')
* ** ** *** * * * **
** *** * * ** ** * *** * * *
* ** ***** ** * * * *
* * *** ** * *
* *
** * ** * *** **** ** = 0;
*** *
* *** * ** * (b[c] != '\0')
*** ** ** * ***
* * * ***** ** * *** * **** * ** ** * * **
* *** *** * ******* *** * * * ***** **** ****
* *** * *** ** *
** *
* ** * ***** * Comparing frequency of *** *
* * *
*** *** ** *** ** * (c = 0; c < 26; c++)
**** *** * * *
* ** * * * ** * * *** * ** * *** * (first[c] != second[c])
** **** * * **** * ** **** * *** * * ***** * *** * * 0;
** * ** * ** **
*
** **** ** * * * 1;
}

int * ***
{
* ** * * * * ***
* ** *** **** ** * **** ** ** * * A,B);
** **** * * * ** ** * ***** * ** * * * words or phrases are * ***
* * **** * ** * * * * * *** words or phrases are not * * **** *

* ***** ****** * * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** **
#include *** ** **** *
#include ** ** ***
int * * ** a[],char b[])
{
** * * **** * first[26] = {0}, second[26] = {0}, c = 0;
* * * *
* ** * *** *** * * ** *** frequency of characters in first string
*
**** ** ** * ** * (a[c] != '\0')
* * ** **
* * **** * ** ** ** ****** * * ** ** *
** * * * ** ** ****** **** * *
*** *** ***
* *
*** ** ** * * = 0;
** *
* ** ** ******* **** ** * (b[c] != '\0')
** * ** * * **
* * * ** ** * * * *** ***** * ** * *** *
** *** * ** * * ** **** *** * * *** *
** * * * ****
** *
*** ** **** * ** Comparing frequency of **
** *
* ** ** **** * * (c = 0; c < 26; c++)
** * * ****
****** **** * ** * *** * * * ***** * (first[c] != *
** ***** * *** **** * ** * *** * **** * ** *** ** * ** ** * 0;
** *** ** ** *
* ** **
* ** **** * * * * 1;
}

int main(void)
{
* ** * **** * * *** *
* * ******** * *** ** *** * *** * *** ** *
*** ** * * * ** *** * * *** ** ** * ********* ** words or phrases are * ******
*** ** * * * * * * * ****** ** * words or phrases are not ****** * **

* **** **** * ** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include *** ****
#include * * ** ** *** *
#include * * * **
int is_anagrams(char A[],char B[])
{
** ******* * * *** YOUR CODE HERE*/
** **** * ** ** **** * * * * *****
* ** * ******** * ** * * **** ** ** * * ***
* ** * ** * * * *****
***** * * * * *** * * ** ****** * * * ***** && * * *** **
* ***** * ** * ******** * * *** *** * ***** ** ****** * **** ** *** *********** * *
* * ***** * * ** * * **** *** ** * ** * * ***** ********** && * * ** **
* * ** * * *** ** * * * * * * * *** * * *** * * * ***** ****** *** *
* ** ** ** * *
** ** * * * * ** *** ** * *
** * ****** * ** * * *
*** * *** * * * ** *** ** **** *** *** * (cA[i]!=cB[i])
* * * *** * *** **** * *** ** **** **** * **** * ** ** ** * * ** 0;
** * *** * * * * *
** ** ** * ** 1;
*** * * **** * * ** * OF YOUR CODE*/
* *** ******** * function should return 1 if two words or phrases are anagrams,
**** ** ** ** **** if two words or phrases are not anagrams.
}

int main(void)
{
** * ** ****** A[100],B[100];
*** * ** ** *** * * *** YOUR CODE HERE*/
*** **** ** * * * * ** ** * *** * **
*** * ***** * ** ** ** * * ** * ** ** * *
* ** * * *** **** * (is_anagrams(A,B))
* ** * * ** ** *** * * * * * * * ** * ** ** * * ** ** * words or phrases are anagrams");
* ** * ** * ** * * * **
* * * ** * * *** * * ** ** * ***** * * *** ** words or phrases are not anagrams");
**** * *** ** *** * ** 0;
* * *** ** * ****** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** *** *** ** ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
** * ** *** * * *
* *** *** *********** * * (A[i] != '\0')
** * * * **** * * * ***
* * **** * ** * **** * * ***** * * *** * *
* ** ** ** * * * ** *** * * * * * * *** * * * *
**** * * * * * * * * ***
* ** ***** * * ** **
*** * * * * * * = 0;
****** *** * * ** ** **
*** * * * ** ** * * * * (B[i] != '\0')
**** *** *** ** *** **
** ** ** *** **** ** ***** ** *** ** * *** ** ** ** * ** *
* ***** ******* * *** *** *** * ** * ***** *
* * ** ** ***** *
    
* ** ********* * * * (i = 0; i < 26; i++)
* ** * ** * * * * **
* **** * ** ** * **** **** * * *** *** * * * * (Array1[i] != Array2[i])
* ** * **** **** * * * ***** *** ** * * ** ** ** ** * * ** * * ** * 0;
* ** * ***** ** *******
* * * ** * ** **** *
* * **** ** ***** * 1;
}

int main()
{
* * *** ** * * ** * **** A[100],B[100];

** **** * ** * * * * * *
* * ** *** ** *** *** ** * *
** * *** * * ** ** ** *
** *** *** * * (is_anagrams(A,B))
*** * * * *** * * **
** * *** ** * *** ***** * * * * **** * * * * * * words or phrases are anagrams");
***** ** * *** * *****
* * * **** * *** * * * ** printf("Two words or phrases are not anagrams");
* ***** ** * *** * ** *
** * * ** * * ** *** * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * **** *** * ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
** **** *** ** ****** *
** ** * **** * * ** (A[i] != '\0')
** * ******** ** * *
* *** ** *** * ** **** ** *** * ** * * *** * ** ** ***
* ** ** **** * * ** ** ** **** * * ** * **
* ** * ***** * * **
* ** ** * * ** *
** * ** * * * ** * = 0;
** *** * *** * **** *
* **** *** ** * ** ** * ** (B[i] != '\0')
* **** *** ** ** *** **
* ********** * *** * *** ** *** * **** *** * ** **** * **
**** ** *** * *** * ** * ** * ** * * * **
** * *** * *** * *
    
** * ** * ** ** *** * (i = 0; i < 26; i++)
* ****** ** **** * ***
*** * ** * * ** *** * **** *** *** ****** *** (Array1[i] != Array2[i])
** *** * * ********* * * **** * *** * * * ***** * ** ****** ** 0;
* * * **** * *
*** ** * * * * ** *
* * * ** ** * * ** *** * 1;
}

int main()
{
** ** * **** * * ** * A[100],B[100];

* * ** * ** *** * * * * * ******** *** * **
* * *** *** * ** ***** * * ** ** ** **** *****
* * * **** * *** **
* * * ** *** ** * * * (is_anagrams(A,B))
* * ** * * ** * ***** *
*** * ** * **** * ** * ** *** ** ** ** * * * ** **** ** words or phrases are anagrams");
***** ******** * * *
* * * * * * ** * printf("Two words or phrases are not anagrams");
** ***** * ****** *** * *
** *** ** ***** * **** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** ** * **
#include * ** *** **
#include *** * *
int is_anagrams(char A[],char B[])
{
*** ** * * * *** * ** lenA = strlen(A),lenB = strlen(B);
** ** ** * * * *** ** **** != lenB)
* * * * ** * * * * * * * * ** *** ** **** 0;

* * *** ** * *** **** * i,j,k,a[26] ={0},b[26] = {0};
******** * ** *** * ** = 0 ; i < lenA ; i++)
** * * * ** * * * *
* ******* * * * ** ***** * *** * ** *** ** * * = 0 ; j < 26 ; j++)
***** ** ** ** * * * * ** * * * **** * * **
* **** ***** *** ** ** **** * ** ** **** *** * * ** *** *** * **** * ** **** == A[i] || 'A'+j == A[i])
* ** ** * * * ** * ** * ** * ** * * **** ** **** *** *** **** *** **** ** * **** **** *
* * ******** * * * * * * *** *** *** ** **
* * * * ****
** *** ** ** ** * = 0 ; i < lenB ; i++)
** * ** * ***** * *** *
** ** * * ** * ***** * * * * *** *** = 0 ; j < 26 ; j++)
* * **** * ** ** * * * ******* ** * **
* * * ** ***** * * * * **** * * * *** * ** **** **** **** *** == B[i] || 'A'+j == B[i])
* ** ***** ** *** * * *** ****** ** ** * * * * *** *** * ** **** *** * ** * ***** ** **
* *** * *** * * *** * **
** * * ** *** ******
* * * *** ****** ** = 0 ; j < 26 ; j++)
* * ** * * ***** *
** * ** * * * ** * * *** **** * * * ** != b[j])
*** * ** **** ** *** * ** * * **** * ** * ****** *** ** * **** * * ** 0;
* ** ** * * *** * * **
**** * **** ** **** *** ** ** 1;

}

int main(void)
{
** * ** * **** A[100],B[100];
** * **** ****** * * * *** %s",A,B);

* ** * ** * *** (is_anagrams(A,B)) * ** * words or phrases are anagrams");
* * ***** * *** * printf("Two words or phrases are not * ********

****** **** * * *** * * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * *
#include * * * * * **
#include * *** ** ** **
int is_anagrams(char A[],char B[])
{
* * * ** * * ** lenA = strlen(A),lenB = strlen(B),i,j,k;
** *** * * ** * *** * * * ** a = 0,b = 0;
** ** ** * * ** * *** * != lenB)
** ***** ***** **** * * * * **** * ** * * * 0;
**** * *** ** *** ** * = 0 ; k < 26 ; k++)
*** * **** * ** * **** **
** * * *** *** **** * *** * ** ** * * * *** = 0 ; i < lenA ; i++)
******* **** * * *** ** **** *** * *** * *
* * *** * ** * * * * * ** *** * *** * ** * * * ** * ** * * ** *** == A[i] || 'A'+k == A[i])
* * ** * ** * * * * *** * * * * ** * ** * ** * * *** **** ** ** *
* * * **** * * * ***** * * *** *
* ***** * ** * * ** * * * ** ** * ** * *** = 0 ; i < lenB ; i++)
* ** * ** * * * *** * * * ** ** **
* * * ** ***** * ***** *** * * ** * *** * ** *** *** * ** *** * * == B[i] || 'A'+k == B[i])
* ***** *********** *** **** **** *** * * * ** * * * **** * * * * * ** *** ** * * ** * *
* * ** *** ** * **** * * ** * ****
** ** * ** * *** ***** * * * ** != b)
** * * ** *** ******* * * * ** * * ** * * ** ** * * * ** ** 0;
* * * ** *** * * * * *** * * *
***** **** * * **** ** ** **** * * ** * ** ***** * * * * * 1;
}

int main(void)
{
** *** * *** * * * A[100],B[100];
* * **** * * ** * * ** *
****** ******** ** * **** **
* * * **** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* **** *** ** printf("Two words or phrases are not anagrams");

* * * * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** ** *
#include ** ** ***** **
#include ** ** ***** *
int is_anagrams(char A[],char B[])
{
** * *** * **** * * YOUR CODE HERE*/
** * * * * **** **** * i,count[256]={0};
****** * * *** ** *** * ***
* *** * *** * * ***
* ** * * ** ** * **** * * *** * * * ** * * *** * * * **** ** * **
*** ** ** ** * * * *****
* *** ** **** * *** **** ** ** *****
*** * * *** **
***** ** ****** ** * * * * * *** ** **** ** * * **** *** ** *
*** ** * * ***** ** *
/*
** * ** * *** ** * * * ** (A[i]!=0 || B[i]!=0){
** ** ** ** * *** * **** ** ***** * ******* **** ** * *
** * * * * *** * * * * ****** * * * *** * ** ** 0;
* * * * ** * * * ** *
*/ ** * ***** *** * ** * * * ** ******* * 0;

* ***** * * * **** ****** (i = 0; i <256 ; i++)
* *** ** * *** ** ** * **** ** *** ***** (count[i] && i!=' '){
* * *** * * ** ***** * *** * * ** *** * *** ** ***** * ** ** *** * * ** ** * **
* * *** ** * ** * ** *** * * ** **** ** ******* * * **** ** * **** 0;
* * ***** * ** **** * * ** ** * ** *** ** ** ** *


*** * * * ** 1;

* ** ******* * ** OF YOUR CODE*/
**** ** ** ***** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
*** * ** * ** A[100],B[100];
* * ** * * ** * YOUR CODE HERE*/

* * * ** * * * * * *** * ** * **
* * ** *** *** * * * ** * ** * **

** * ** * * * * * ** * = '\0';
  // * * * ***** * = '\0';
* * * * * * ** * i;
* * * ** * ** *** * ** * * ** * ***
** * *** * * ** * ** * * * * ***** * ** *** ** ** ** * ****** * * * **
* * ** * * ** ***** *** ** * *** * * * ***** *
* * *** ***** * * * * *** * **** **
* * * *** *** * *** * * *** * * * * * *** * * * ** * * **** * ** * * **
* ** ** * * * * ** ** * ** * * ****** * *

*** * *** * ** **** * OF YOUR CODE*/
* ** * *** ** ** ** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** *** * ** * * **** printf("Two words or phrases are not anagrams");

* ** * * **** ** ** * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *
#include *** **
#include *** ***
int * * * A[],char B[])
{
* * ** * * *** *** YOUR CODE HERE*/
* * ** **** ** *** ** ***** * *
****** ** * * * * * * * * *** ** * * ***
** * **** ** * * * * *
**** ** * * * * ** *** * ***** * * * * * * ** **
* * ** * **** * * * * *** ** ** ** * * **
** **** * ** ** *
** * *** ** * *** * (A[i] || B[i])
**** * * *** * **** ******* ** ** ** 0;

** ** ** * *** * (i = 0; i < 256; i++)
* * * * * * * * ** * * * *** ***** **** *
* * ** * * * ****** * *** ** * * ** * ** ** ** *** ** * ** * ** *** 0;
**** ** * * *** ** * ** * ** 1;

* *** ** * OF YOUR CODE*/
** ******* * ******* function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int
{
*** *** ** ** **** ** ** **
* * * **** **** * ** YOUR CODE HERE*/
* *** ** * * * * ** ** *** * * * * * ** *
** * ** **** * ** * *********** * * * ** **

* ** ***** * * ***** OF YOUR CODE*/
**** * **** ** ** **** ** * * * * * ***** * words or phrases are ** *** ** **
***** ** * ** * * words or phrases are not * * * * ** *

* * * ** ** * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * ***
#include * * ** * *
#include ** *** **** *
int *** ** ** A[],char B[])
{
* *** * **** YOUR CODE HERE*/
** ** *** **** * * * * * * * ** *
*** * ** **** **** **** ** ** * **** ** *
* ******** * * * ** *
* * * * * *** ***** * * ** **** * **
** *** ** * * *** ** *** ** * * **** * * * **
*** **** ** * * * *
* * * ****** ***** (A[i] || B[i])
******* * **** * * *** *** *** * * * 0;

*** * * ******* ** (i = 0; i < 256; i++)
** * * *** * ** ** * * ***** * ** * * * ** * *
** * ** ** * *** * ******* **** *** * * ** * * ** ***** ** ***** **** 0;
* ** ** * *** ** 1;

** ** ** * ** ** OF YOUR CODE*/
* * * **** *** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
* *** **** **** ***** ** *
* * ** * ** **** * **** YOUR CODE HERE*/
** * * * ** *** ** * ** *** *** *
** * * *** ** * ** * ****** * **** ** **** ***

* * **** * ** * OF YOUR CODE*/
* ***** * **** *** * **** * ** ****** * words or phrases are ** ** * *** ***
* * ** ** * ** * * ** * * * * words or phrases are not * * *

** * ** * ** * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.129
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.3k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.6k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users