12-28 Exercise 3: Anagrams function

0 like 0 dislike
10.3k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited | 10.3k views
0 0
STRUPES!
commented by (323 points)

79 Answers

0 like 0 dislike 
Hidden content!
#include * ****      *
#include     * ***   *  
#include  *** **  ** * 
int * ***** * a[],char b[])
{
**  **   *     ** **  first[26] = {0}, second[26] = {0}, c = 0;
 *    
***     * *** ** *   **  *   frequency of *     in first string
*** * ****
 ***  *  *    **   ****  ** (a[c] != '\0')
  * *  *   **    
* * ***  *****   * *** * *  ********** * *  *   *      
        **   * * ** *  **  *** *** *  ****
      * **  * *** ** *
*  *   
 * *    *** * **  ** * * = 0;
 *** * **
 * *   *    *  *       **  (b[c] != '\0')
*  * **** ***       * *
  *  *  ***  * *       * * *   ****  *   ***  **  ***  
 **  *     *** * *  *** **   **   ** ***** 
***       **  ***  *
** * 
 ***    *  ** * Comparing frequency of ******* 
 * * **
 *****  *  ***  ** * * (c = 0; c < 26; c++)
*  * ** **   *   *** 
    ***   ** ** *       * * **   *    * **  (first[c] != second[c])
   **       ****   * ** ** ** ** * *  * *  ** ***   *     0;
 * ** * * **   *      
    ***   
* ** **  *    **    * * *** 1;
}

int *  ***** 
{
 * * ** ** *  * **  ** ** ** *  *  
*     **  ** *** *   ** *  *    *  **  ** ** A,B);
* * *** * ***  **      ** ***   **  ***** *   *** words or phrases are * * ***   ** 
***   ** ** *  *  *   * * **   * * ** words or phrases are not  ***  ***  

* *   *  ***  *  *  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * *   ****   
#include * **  *****   *  *
#include *    * *  **** **
int  *** *    a[],char b[])
{
 **   * *  ***  * first[26] = {0}, second[26] = {0}, c = 0;
 ********
*** ***     **  * ***      *  frequency of characters in first string
 * ******
****  *  * *  *  * *** ***  (a[c] != '\0')
** ** ** *  **    **   *  
 *  ** *****   **** ** *** *  **    **  *   ** *    *
    ** * ****  ** * *   * * * *   * *   **   
** *  ******** ****
 * *   
 ****  **  ** *  * * *      = 0;
* ** ***
 *** *****  ** **  *  **   * (b[c] != '\0')
* ***     *    *  *** 
* * ** *   *    **  ** ****   * **  ** * **   *** 
**** ** * *  ** ******  ** *   **    ***
*     *** *  *   * **  
* *      
*  *    *  **  * **  Comparing frequency of **  ** 
*  * 
*  ****      ** ** ******* (c = 0; c < 26; c++)
  ** * ***  **    * ***
    ** ****    ** *  *** **   *     **    *  * (first[c] !=  *     **
*   * * *     *  *  *** *    *  ****   ****   * * **   ** ** 0;
 * *  *** *  ***  * *
 *  * **
   ** ** ***** *   * ***** * 1;
}

int main(void)
{
***   *  *  *  ******   **      * 
   *  * * ** * **      *** * *    **  ** *   * **   *
* *  *** * ** * *    *  *** **  * ****  **   * words or phrases are   **** *  **
*     * *** * *   *   *  * ****          words or phrases are not * *** ***** * *

*** ** ** **           *  * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *     * *** *
#include **** *      *
#include *** * * * ** 
int is_anagrams(char A[],char B[])
{
*  ** * * **  ** *   ** *    YOUR CODE HERE*/
 *** ****   * ** *  ***   *******  *  **  * **  *
 ****     *   *  ****     * *  ** *****  ****** **   
* **    * **   * *  ***** * * *  
   **** *******  ***  ******  *     *   **  *    *  ****   **   *    &&   * * *  *
** *     * ** *** **  ** ** ** * ** **   ** * ** * *****     ** * ** ** ***** * **  * * *****
* * * **   * * *     *  ***** ***** * *       *** *     * *  * **  *   * &&  *  **      * **  *
* ** * **       *  *    ** * * ** *     *  * * ****** *  * *******     **** * * **  *****    **    *  * ***
  * *       **   *  * ** *  * 
 ******* * *     ** * * * ** * *         **
   *     **    ***** *  ***
 * **  *   * *  * **  ******  * **   *  ***     (cA[i]!=cB[i])
* ** **  * *** ***  *     *** *  ** ********** **  *   **  **   ** *     *****  *   **  0;
   ** **   ** ******* **   * * 
 *  ***   * * * ***** *****     1;
 ** ******     ** *** * *** OF YOUR CODE*/
    *  * * **  *  ** * **  * function should return 1 if two words or phrases are anagrams,
  *   *         ****    if two words or phrases are not anagrams.
}

int main(void)
{
* *  *  ***   * * * * A[100],B[100];
 *    ****         *  * *  YOUR CODE HERE*/
    **** * *  **    ******* **** *   ** *    ***  ** *   **
   *** ***  * *   * *  ***  *      **     * * * **
****   **      ****  **  * (is_anagrams(A,B))
*** *** *     *** * * **  *  * ** ***    ****** *    *   *   words or phrases are anagrams");
* * ** **  *  ** **** * *  *
** *   * * **  ** *  *   ***  *    *****  *   **   * ** *  ** **** *** words or phrases are not anagrams");
* *    * ** ***         *      *** 0;
**    ****  * * ***** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
***    **  **   ****  ** * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
 **   ****  * *** ** * * **
 **  *** * *    * ** * * **** (A[i] != '\0')
 **    *  *  **   *  * *
 *  *  ** * * ** *  *    * *  ****   *  ** **   *     ** *       * *  **
* ** ***   ***** * ***** *  *   * * * * * *   ** ** ** * ** *   
** *** **  ** *    **** *  
  *** *  *  ** * * ** * *  
****** * ***  ***  *  ***** = 0;
    *  **** **  * *  ***     
*  ******     **       **  *    (B[i] != '\0')
 *   **  * ** *** **** *
**** ** *****   *   ** ***** *  **** ** * **      ** **    * *  *  
** * * ** * **** ***  ** * *** *      *   *  * *  **
* *   *     **  *  **  * **  *
    
   **** ***  ** * *  *  ***  *  (i = 0; i < 26; i++)
 *****  ***    * * **  ** **
  * * * ******    **  *  **  *  **** * **  *  **     ** (Array1[i] != Array2[i])
* ******   *    **    *   * ** * **    *** ** * ** * * *******  * * **  * ***  * *** ** 0;
  *   *   **  * **     ** 
*******   **  **     **
**  * * ****  * **** *   * * *  1;
}

int main()
{
   ***  ** * *   **  * **  ***** A[100],B[100];

   *     **  *  **  * * *  *    * * * *     *
  ***    ***  * ** ** **    ** ****   *
  *** ** ***    * ********** *
* **     *   ***** ***    *  (is_anagrams(A,B))
 ***   *      * ****     ** 
    ** * *  *  *  *  ***     * ** *** *  ** * ** *  *    words or phrases are anagrams");
*    **** *   ******     *  *   *
  ****  **  * *  **** ***   *   printf("Two words or phrases are not anagrams");
 *** **** * * * *  * *   ***  * 
*****     *     **** **   * * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
**  ******** *  ** ****   Array1[26] = {0}, Array2[26] = {0}, i = 0;
*  *  *      *** **   ** 
    ** * ***  ******* * **  * (A[i] != '\0')
 **   ** * ** * * *  *  ***** 
*** ***** *** *   *    ** **    **    * ** **   *  *    ****
  ********* *  ******   **  **  *** *  * *  *   ** * ********
* *   *  *  *    ** **** ** * 
 *    * ** *  *  *   ***** * *
  * * ******** * *   ** * = 0;
*   *  * **    **    * *  ***  
* *  *   * * ** *** **  ** * (B[i] != '\0')
* **  ** ** * * ** *
  *  * * ********   *   *   *  *  ***  * * *** *    ****  * 
  *** **** * *  *  ** **  **  *** ******   *   * *  ** *** **
  * *******  **  ******** 
    
    ** *    **   ***   ***  * (i = 0; i < 26; i++)
     * *  ***** ***  * *   
* * *    * * *  *** * ***** * **   * * * ****    (Array1[i] != Array2[i])
*  **   **  ** * *****  ***** ***   *  ******** **  **  **** * *  *      * 0;
**** *** ** * *     * *    
 * ***  *** *    *  ** * *  
 **   *** * *   *** ****  * *  * * 1;
}

int main()
{
* * * *** *  ****    **   * ***  * A[100],B[100];

***  ***  **** * **  ***  ***     ***  * * * ***   * * * 
 ** *   * *  ******   *** **   **   * *   * ** ***  *
*  * * ***  *       ***   * **
* * **   *   ***  **  *  * **  (is_anagrams(A,B))
* ****   **   **   ** * * * *  
   ****     **  *** * **** **** ***  ******* ** ** *** **  *** *  *** words or phrases are anagrams");
** ** ****  **** * *  **** 
* ** *  *** ** * *         ** * printf("Two words or phrases are not anagrams");
      *  *  ***   *  * **  **
* * *  ** *  ***   * *  ***   ** ***  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *  *  *    *
#include ***** * **   ***
#include *   **** *  *  * 
int is_anagrams(char A[],char B[])
{
*   * *  ** *  ** *   ***  *  * * **  lenA = strlen(A),lenB = strlen(B);
  * ** **  *  *    ** ****   *** != lenB)
***    ****   *  **   *** ** * *** **    **   * 0;

* ** *   *  *** * **     i,j,k,a[26] ={0},b[26] = {0};
* **    *** *******  **  *    = 0 ; i < lenA ; i++)
 *  ** **   ** * *  *** **
****   ******    ** *** *  *  *  *****    **  **   **** * * = 0 ; j < 26 ; j++)
    * **  *** * **  *** *** *  ** *   *   * **   ***  ***   
 ** **  **** *   * *  *  *  *   *  *  * **          * * * **  * **** * * **** * == A[i] || 'A'+j == A[i])
*   * ***   *   * **   * ****** * ***** * ***   * * * * *** * ** * *   *     ***** *   * ** * ** * *  *  *   *
*  **** ***     * * *** * *  ****  *  **  ******
** *  **   ******* *  **    **
  * ***     **** * **  *    = 0 ; i < lenB ; i++)
** *     * * *  *   *    * 
*  *    ***   ***** *  *   * *   ** ***   ** *     *** = 0 ; j < 26 ; j++)
   * * **** ****** *  *   *  ***   ***   ***   * *  
**** * * * *  ***  *    * ****     * ******     * *    ***  *****  * *   *  *** ****      == B[i] || 'A'+j == B[i])
   ** ** * ***** ** **    *   ** ** * *    **  **  * *   *  *     *  ** * **        ** **  * * * ** **  ***   
* *   *  *  ** * * ** ****  * *  *** ****  *   * *
  * *     ***   * * *** ****   *
  **  *** *   *    ** *** ** ** = 0 ; j < 26 ; j++)
   *** *** *  * **** **  *  * *
**  **     *    *   ** * *  ** *  ** **** *  ** * **  *    *   * != b[j])
** * *  * **  *  *  **   *  *  *    **  ******* *****  * ******* *   * *   *  ** * 0;
*  * *** ****   * *  * *
** * ** ** * **** **** * * 1;

}

int main(void)
{
** ***  * * * ***  *  A[100],B[100];
 ** ***** * ***  *  *  * *******     *  %s",A,B);

     ***  ****** **   (is_anagrams(A,B))  **  ** **** **  words or phrases are anagrams");
 *  * * * *  ** * ***  ** printf("Two words or phrases are not ***   **** ** * 

    *** **   ***   * * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *  *   *   
#include       *  ** **
#include  *      * *  **
int is_anagrams(char A[],char B[])
{
** *  ** **    *  *  **      lenA = strlen(A),lenB = strlen(B),i,j,k;
 *   ***  *** * **    **    a = 0,b = 0;
*   ****    *  ** **** *    *** *   != lenB)
 *   *   ***  **  *      ***  *    * ****  *** *     ***  0;
  *** ******      *  * *  * *  * = 0 ; k < 26 ; k++)
 *  **  *   ****  **** ***  ** *
 **   ***** * * ** * * *  *   * * ****   ** * **  ** = 0 ; i < lenA ; i++)
 * * *    *** ** * *        ***  * ***  *  *    *  * *   
****** **** * *******   * ***  * **** * *   *******    *  *  ** * * * *  ***  ***** **  == A[i] || 'A'+k == A[i])
*** **  *    * *** * ** ** * * ****** *** * **  **  ***  * ***  * * ** **  *   **  * *  *  * ** * ****     **   * * * 
 ****   *****     ***  * ** * **  * ** *   *   * *  
*  * **  ****   ** *  **  **  ** ***  ***** *    ** **  *** = 0 ; i < lenB ; i++)
  * **  *    **      *   **** * * *  ** * *** *     *  
**** ******  * *  ***  *   * *** ** * **** ****  ****   *** * *  ** * **   * *** *  == B[i] || 'A'+k == B[i])
       * *** * **** **** ***** ** *****  * ** ***  **  *  ******* *       *        **   *****   * *   *  ** 
***  * * *******       * *  * *** ***** *  *** *** *
 *** * * **  * ****    *  **  *  * *** *   * *  *   != b)
  *        ** **    ** **  *  **  ***   * * * ***** ** * *  *** *****      ** *   0;
*     *    * *  * * * * **     ** 
*    * *  * *  ** *   *  *    *   * *  *** ******   *  ***** * *   *      *** ** 1;
}

int main(void)
{
      **** ***  ******  A[100],B[100];
  * *    *  **  **   ** *   *  ***   
**  ******  *   *** *      *** *
****    *     * *     (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
 *    *  *  ***** printf("Two words or phrases are not anagrams");

*  ***** * ***     ***   *  0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * ** **  *  *
#include *           ** * * 
#include   * *****  * 
int is_anagrams(char A[],char B[])
{
**** * *****    ** *  * * YOUR CODE HERE*/
 ***     ****  * ***   *    *  i,count[256]={0};
 * *** *  *  ****   * **  ***   *    *****
*  **  **   **    ***
  **   *   * * ***  * ****  ****  * ** * * **  *  **  **  * ** * ** * * * ** * ** *  * ***** *****
* *** **    * * * *  * *** 
 ***  * ** *    ****** * ** ****   **
* **  *** ***   * ******    ***
* **   *        ***  *      *       *  *       **  **     *  ****   *** **   ** * ** * * *** *
****** *    **  *    
/*
**   * *  *  *      * ** (A[i]!=0 || B[i]!=0){
*    ***   * * ** *** * * * *  *  ** *** *   * *    *  **** * **       *    
* **     **  ***  ***  * *  ** ***********      *     **** 0;
*  **   *  *     * *  *  *  *
*/   ***  **   * **  ** *  ***     **  0;

* * * *  *  **** *  **  **** * (i = 0; i <256 ; i++)
  *** * ****  * **  * **** ***** ***    ****      *** (count[i] && i!=' '){
**  * ** * ** * ****  *    * **   * ******  **   * *****  *  * ** **      ***  * * * **  ** ** *  ** *
 *    **     **   *** *  *  * *     *** ***     **      *****    * ***** * *****  0;
* ****   **   * *  ***** ** * * **   **** ***** 


  * * **  **** ***   *  ***  *  1;

* *  ** ***   ** ***    * OF YOUR CODE*/
 ****   * ****       function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
  **    *    * **  *** A[100],B[100];
**  *  ** **       *  * *    **  YOUR CODE HERE*/

  ****** ****  ** *  **  * ** **** ** *
   * *  * * *  **   * * ******  ** *   * * ***

*      ***    *   ** **  **   ** * * **** = '\0';
  // **  *   *    ** = '\0';
 * * *   *  *  *****  **  ****  i;
   *   *  * **  * *  * * *****    ** *  *
   ******  **** * * **   *  *** *  **** * * ** *  ******* * * * * * * ***  *****  * 
  * * **    *   * * *** *  ****  ** **  **  **** ***** ****  
   *    *    * * ** **   ** **  **  *
  *   *   ***** ***** ****    *** * ** * *    * ** * ** *  *  *  ****  * ** * * ***
 * ***   * * * *  * *     *** **   ********* * *     ** *   *   *  

  * ** ***  ***      * OF YOUR CODE*/
 * *  ** *   ***** * **  ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
  ** * ***** ** *** *   printf("Two words or phrases are not anagrams");

  *  * *  *  * ****   ***  0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** *  ** *  
#include   * *** ** *   *
#include        *  * **  
int **      *** A[],char B[])
{
* **  ** ****** * *   ** YOUR CODE HERE*/
 * *     *  * ***     *      *****   **
      ******* ** *** ** ***   *   *  * **  **   *  *  **   
*******   *      ** * *** ** *
* *** *  ** *  **    *** *    ***** ** ** ***   **** * * ** **       ***
      * * * * *   **** *** *  * * * * * * ** ** * * *
     * **   *  **   * ** 
  *   *     * ****  *** **** (A[i] || B[i])
**  * ***** ***   **** ***  *      *** **  0;

  **  **  * ***  ** * ****  ** (i = 0; i < 256; i++)
   * * * * **  **      **  * ***   **    **** ***  ** *****   
**   **  ** *    *  ** **** *  * * ** *  * ***        *  * *  **  *   *  0;
* *  **     *    *   ** **   1;

    ***  *****   **      OF YOUR CODE*/
   **   **   *** *  *    function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int **  *   
{
* * * * * ** ** *** **    ** ** *
 *** * * **  ** *   **** * ** YOUR CODE HERE*/
* ***   *  * *   *   * ******  * ** **     * **   **
*****   ** *  *   * ** * **** **    * *          ****

 *     ***    **   *   OF YOUR CODE*/
   *  *** ******* *   *  **** * *    *****  *****  words or phrases are *            
  *    ** * * ***    **** *  *** words or phrases are not      * *** 

 ** **  **  * * ***  0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **    *  **    *
#include *       ** * *  * 
#include  *** *** **  *
int *** * **  A[],char B[])
{
 ****   * * **  * *     *  YOUR CODE HERE*/
*******   *** *    * ***  **  **** **
 * *  * ****** * *  *      *  * **    *   ** *   *     **
***   **** **   *** *** * ** 
  * * **** **     * ** *  * *   ******* **   ** *  *  * *  **  ****
**    * *   *    *** * ***  *   * **  ***   **  * *** *   *  *  
*  *** * *  ** *** *   **  
* * * *****   ** **    (A[i] || B[i])
****  **      ******  ** * **   **       * *  ** * 0;

 *       * *   ** *   ** *     (i = 0; i < 256; i++)
** * ** *****   *****  ** *   * *        * * ****  * * **  *    *  * *
* ***  ****     ***  *  *   *  *    ** *  *****    ***     * **    ***      * *   0;
     *   *  * * ** * * **  1;

*  *   * ** ***    * *  OF YOUR CODE*/
     * *  *** *  *  *  ** *  function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *     **
{
 ***      **  * ***** **  ** *   
**  * * * ******* **   YOUR CODE HERE*/
 * * ** * * *  * *  **** **** ****  *   * * *   *         
* ***    * ** **   ** * **  **  **       *   * **    * 

*       ***  * * **  OF YOUR CODE*/
 *     *   **  *** *    ***        * *  **** * words or phrases are    **  ** *
   * ** **** * * ***  **   ***** *   words or phrases are not  * * ****** 

* *  * ***  **** *  * *** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.161
©2016-2025

Related questions

0 like 0 dislike
47 answers
12-07 Exercise 3: Function to delete an element from an array
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 4.9k views
0 like 0 dislike
45 answers
12-07 Exercise 2: Function num_digits
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 5.5k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 4.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users