0 like 0 dislike
12k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 12k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ** ** * **
#include * * * * ** *
#include * *** * *
int **** ** a[],char b[])
{
** ** **** * * * first[26] = {0}, second[26] = {0}, c = 0;
* *
* ** ** ** ********* * *** frequency of * * * * in first string
*** *
* * *** * * ** * * (a[c] != '\0')
*** * * * * * ** **
* * * ** * * * * * *** *****
* ***** * ** * *** ** * * * *** * *
** ** * * * ** *
* * **
****** * * ** = 0;
*** **
*** ** ******* * ** * * (b[c] != '\0')
***** ** ***** * *
* * *** * * **** ****** * ** *** * *
**** ** * * ** * * ** * ** * * *
*** * ** ****
**
** ** ** * * * * Comparing frequency of ** *** *
* ******
*** * * * **** * (c = 0; c < 26; c++)
*** * * *** **
* * ** * ** ** * * ** * * **** (first[c] != second[c])
* **** ** ** **** **** ** ** ** * * * * * ******** * 0;
**** * * * ** ****
*** **
* * **** * ** ** 1;
}

int * * ****
{
*** * **** ** * * * ******** *
* ** **** ** * * * *** * *** * * * * A,B);
* *** * * * ** * * * ** *** ** * * **** * words or phrases are * **** **** *
*** * ***** ** ** ** * * **** * * words or phrases are not ** ****** * *

* * * * * ** ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** ******* *
#include * * * **
#include * * ** * *** * *
int ** * a[],char b[])
{
** * * * *** * ** first[26] = {0}, second[26] = {0}, c = 0;
***
**** *** **** ****** frequency of characters in first string
*** *
* *** * **** ****** (a[c] != '\0')
** * ***** ** ** *
*** * * * ****** * **** **** ***** * * *
* * * * * *** *** * * * **** * * *
* * * * ** * *
* * *
* ** * ** * ** ** * = 0;
** *
* * * *** ** * * * * (b[c] != '\0')
** ** * * * ** ******
** *** * * * ** * **** * **** * * *
*** **** * * ******* * * ** * * * * *
* * *** * ** * *
*****
** * * ** ** * * Comparing frequency of **
* **
* ** * ** * * * (c = 0; c < 26; c++)
*** ** * * ** **
* * * ** * * *** * * *** * * (first[c] != * *
* * * **** * * ** * * * ** ** ** ** *** * *** * * ** 0;
* ** * ** ** * *
*****
** **** ** ** * * * 1;
}

int main(void)
{
*** *** * **** * *** ***
** * * * * *** ** *** * ** * * ** *
*** *** * ** * ** * * * * **** words or phrases are ** * ***
* ** ** * * ** * * ** *** words or phrases are not * * **

* * * * * ** *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * **** * * *
#include ******* * *
#include ** *** ** ** **
int is_anagrams(char A[],char B[])
{
* ****** * * *** *** ** * YOUR CODE HERE*/
* ****** ** * * ** *****
** ** ** *** ** *** * ** * ** *** **** **
***** * * *** * * **
* *** * * *** * ** **** * * *** ***** * ******* ** ** ** **** * && ** * ** *** ** *
* **** * * * ** * * ******* ** * * * ** * * * ** * ** * ** ***** ** * **
* * * * * * * * * * * ** * * ** * * * * ** ** ** && * ** *
*** * ** * *** ** * ** * **** * ** * *** * * **** ******** *** * **
* *** * * *** ** * *
** * *** * * ** * * ** * * *** **
** ** * * * ** **
* * * ** * * * **** ***** * ******* * * (cA[i]!=cB[i])
*** *** * *** **** *** ***** * ** * * ** * * **** * * * * * * * 0;
**** ***** * * ** * *
**** * * * ** * 1;
** *** * ****** ** OF YOUR CODE*/
** * **** * * * ** function should return 1 if two words or phrases are anagrams,
* ** * if two words or phrases are not anagrams.
}

int main(void)
{
* * ** *** * A[100],B[100];
***** ** ** * * * * * ** YOUR CODE HERE*/
* * * ** * **** ** * *** ***** * * ** * ***** *
*** *** * * * * * * * * **** ** ** ** ***
* * ** * * * * ** ** * (is_anagrams(A,B))
* ** *** * ** * *** ** * *** *** **** *** ** * *** *** * words or phrases are anagrams");
* * * *** * * ***** **
** * ** ** * ** * ** ** * * * ** * *** ** **** *** * words or phrases are not anagrams");
** ** ** * * * * **** 0;
* ***** *** **** *** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* *** * *** ** * * ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
** ** **** * ** *** ** *
***** ** ** * ** * ** * ** (A[i] != '\0')
* * * **** *** **
*** * * * **** * * * ** * * * * * ** * **** * ***
* * * * * * * * ** * * * ** *** ** ** *
* *** * * *** * * * * *
* ** * ** * **** *
* * * * ** ***** ** *** = 0;
* * *** * *
*** *** *** **** * * * * * (B[i] != '\0')
* ** * * *
*** * * *** * * * * ** * ** ** * * * * ******* *
**** * * ** * * * * ** *** * * * ** * * **
* * ***** * ** *******
    
** ** * * * * * * * (i = 0; i < 26; i++)
* ** ** *** ** * * ** *
* * *** * ** * * ** **** ** * *** ** * * * ** (Array1[i] != Array2[i])
** * * * **** * ** * ** * **** * * *** *** * ** **** ** ** 0;
* ** ****** * ** * **
***** ** * ** * * *
* ** ** * * ** * * ** **** 1;
}

int main()
{
* ** ** * ** ** ** *** ** A[100],B[100];

* ** ** * * *** ** * ** * ** *
* ** *** ** * * * * * *
** * *** * * *** * *** **
* ** ** * * * ***** **** * (is_anagrams(A,B))
****** * * **** * * **
* * ** * ** * ** * *** * ***** ** ** ** * *** words or phrases are anagrams");
* ** * * * ****** * **** *
*** * *** * * * * * printf("Two words or phrases are not anagrams");
* *** *** * ** **** * *
* * ** * * ***** ** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** ** *** ** * * *** * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
** ***** ***** * **
* * * ** * * ** (A[i] != '\0')
** *** ** ** ** * ** * *
* * ** * * * * **** *** * * *** * *** *** ***
* ** ****** ** **** * * * ** * ** **
***** *** ** *******
* * *** * ** * * **** ** *
*** * * * * * ** = 0;
** * **** ******* *
* **** * ******* * (B[i] != '\0')
* *** ** ****** ** *** ***
******* *** *** * ** **** ******** * * * * ****** * * **
* ***** * * * * ***** * * * *** * * ******** **
** *** * * * **** ** ** *
    
* * * * * (i = 0; i < 26; i++)
* * ** *** * **** *
** ** ** ** ** ** * * * * * * ******* (Array1[i] != Array2[i])
* *** ** * *** ******* ** *** * *** ****** * ** *** ** 0;
* *** * * * ** *
* * ****** *** ***
* * * * *** ** **** ** * 1;
}

int main()
{
** *** ***** * * **** *** A[100],B[100];

*** ***** ** * ***** ** ** * ** * ****
* ** ** ** * ** ** * ** **** * ** *** ** ** **
*** * *** * **** *
* ** *** * ********* * ** (is_anagrams(A,B))
* * * * * * **** ** **
**** * * * * * * **** *** * * ** ***** * *** * words or phrases are anagrams");
** * *** *** ** *
*** * ** *** * **** * printf("Two words or phrases are not anagrams");
******* * *** * * ** * **
*** ** ** ** ** ** ** **** *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * ** **
#include * * * ***
#include ****** ***
int is_anagrams(char A[],char B[])
{
* * ** * * * * * * ** * lenA = strlen(A),lenB = strlen(B);
** ** * * * ** ** * != lenB)
* ** ** * * ** *** ** ** ***** * * * ** 0;

* ** ** ** ** * **** ** * i,j,k,a[26] ={0},b[26] = {0};
*** * * * * *** * * ** = 0 ; i < lenA ; i++)
** * ****** ******* * * ** *
* * * * ** * * *** * *** * * * ***** = 0 ; j < 26 ; j++)
*** * ** * ** * * * * ** ** *** * * * ** *
* *** * * * * ** ** * * ** * **** *** * *** * * ** * ** * == A[i] || 'A'+j == A[i])
* ** * *** * * ** * * ****** * ** ** ** * * * *** ** * *** * ** **** * * * *** *
** ** * ***** ** * **** **** *** ** * *** * ** **
* * * * ** *
* ** * ** * ***** * *** * * * = 0 ; i < lenB ; i++)
**** *** * * ***** * * *
* * * ** ***** ** ** * * ** ** * * ** * = 0 ; j < 26 ; j++)
** ** * *** * * ** ** **** * *** * ** *
* ****** ** * * * * ** * ******* ****** * *** * * * ** * *** **** == B[i] || 'A'+j == B[i])
* * ** ** *** * * * * ** ** * * * ** * ** * * **** ** * ** ** **** * * * **** ** *
* ** ******* ** *** *** * * ** ****
* * **** * * **** *
*** ** ** *** * * * * ** = 0 ; j < 26 ; j++)
** * *** * ** * *** **
* ** * *** * * ***** * ** * * * ** ***** * != b[j])
* ****** ** * ** ** * * ** *** ** *** ** ** * * ** ** * * ** 0;
******* ** ** ** ***
* *** ** * * * ***** 1;

}

int main(void)
{
****** * * * * * * A[100],B[100];
** ** * ** * *** %s",A,B);

* ** ***** ** *** *** (is_anagrams(A,B)) * ** * words or phrases are anagrams");
* ** ** * ** * printf("Two words or phrases are not ***** ***

* ** ** ** ** *** *** **** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * *** **
#include **** ******* * * *
#include * ***** *
int is_anagrams(char A[],char B[])
{
** * ** * * * ** ** ** lenA = strlen(A),lenB = strlen(B),i,j,k;
** ****** **** ** * * * a = 0,b = 0;
* ***** * * * * * ** != lenB)
******* ** * * *** * * ** *** ** * ** * ** ** **** *** 0;
* * ** *** * *** ** * ** ** = 0 ; k < 26 ; k++)
* ** ** ** **** **
* * **** * **** ****** * * ******** ** = 0 ; i < lenA ; i++)
** ** *** * * * ** *** *** *** *
* *** * * * * * ********* ** * * * * **** *** ******* * ** == A[i] || 'A'+k == A[i])
*** ** * * * * * ** ****** ** ** *** ** * * * ** * ** * ** ****** * ** **** ** *
* * * * ** *** * * ** ** * ** * *** *****
* ** * * * *** * * * ** ** **** ** * * ** * * *** = 0 ; i < lenB ; i++)
*** * * * * ***** * * * **** ** ***
*** **** * * ** * * * *** *** ** * ** ****** * * ** * ** * * == B[i] || 'A'+k == B[i])
* ** * * * * ***** * ** * ** ** *** * **** * * ** *** * ****** * **** ****
*** * * * ** * * * * ** ** * * ** *
* * * *** *** * *** ** * * **** * * ** * * * * != b)
*** ****** * ** ** * * * * ** *** * *** * *** ** * ** * ****** 0;
* ** *** **** * ** ** * ** *
* ** *** * * * * ** ** **** *** * * *** **** * *** * * ** 1;
}

int main(void)
{
* *** * * ** * A[100],B[100];
* ** ** *** ***** ** ** ** ** **
* * ** ****** **** ** *
****** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * *** **** ** ** ** * printf("Two words or phrases are not anagrams");

* *** * ** * *** * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * * **
#include * * **** * * **
#include *** ** ** *
int is_anagrams(char A[],char B[])
{
* ** ** *** **** *** YOUR CODE HERE*/
* *** * ** * * ** *** i,count[256]={0};
* ** ********* ***** * * * * *
*** * *** * ** ** *
* ***** * ****** * ** * ** * * * * * * ******** * *** * * ** *** * **
* ** ** ****** * **
** * ** **** **** * * ** * ** **
* * ** ** * *** *
* ** * * ** ** * * ** * * ** ** * * *** * * * *** ** * * ** ** *** * *
** ** * ****** * * * * *
/*
** * * ** * * ** ** (A[i]!=0 || B[i]!=0){
* ** ** * *** ** * * *** ** * * ** ** * ** ** ***** * * * ** *
** * * * * * * *** * * **** * ** *** *** 0;
** ** ** ** *** * ********
*/ *** * * **** ** **** ** * ** ** 0;

** ** ** ** ******* * (i = 0; i <256 ; i++)
* * * * ***** ** * *** * * * * *** **** * ** * (count[i] && i!=' '){
** ** ** ****** * * * *** * * * *** ** **** ** ** **** ** * * ** * ** * ** *** * ** *
* ** ****** * **** ** *** *** * ***** * * *** * ***** * *** **** *** * 0;
* *** * ** ** ** *** * * * * * * ****** *** * *


* ****** ***** * ** ** 1;

*** ** * * ** * * *** OF YOUR CODE*/
*** * * ** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * * * ** *** A[100],B[100];
* * *** ******* * * YOUR CODE HERE*/

* * ***** *** * * * * **
* * * ** * ****** * ** **

* *** ** ** *** ** *** *** = '\0';
  // * * ** = '\0';
** **** * * ** * ** ** i;
* ** ** ** **** * **** * **** * *
******** *** * ** * * * ** * * * *** ** * ** ** *** * * **** ** * * * *
* ** * * ** *** * * ** * * ** **** **** *
* * * ** * * * * ** ** *****
**** *** ** ** * * * *** * ** *** * *** ** *** * * * * *** *** ** *** *
* ** * *** ** ** * * ***** **** *** * * * *

* * ** *** *** ** * OF YOUR CODE*/
** ** * * ** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** ******* * * printf("Two words or phrases are not anagrams");

* * ** * * *** *** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *** * ***
#include * ****
#include * * ** * **
int * **** * *** A[],char B[])
{
* * * ** * ** * YOUR CODE HERE*/
****** *** *** *** *** * *
*** * **** * * * *** * ** * ** *
** *** * * ** * *** * * *
*** * ** * ** * * * *** * * * * ** ***
* * *** ** * * * ** ****** * * *** * * *** *
* * *** * ** ***** **
* * * *** * ** * * (A[i] || B[i])
* *** ** * * * ** * * * *** 0;

* * *** * ** ** **** (i = 0; i < 256; i++)
** *** ** * * * ** * * ** * **** * * **** * ***
*** ** ** *** ** * * **** * * * ** * *** ** ** ******* ***** ** 0;
* ***** * * ** * ** * 1;

***** *** * ** OF YOUR CODE*/
* ** **** * * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** *
{
* ***** ** * **** *
* * ** ****** * *** YOUR CODE HERE*/
* * ** * ** * * ** * *** *** * *** * ** *
*** * ** **** **** ****** ******* ** * * ** *

***** *** * **** ** OF YOUR CODE*/
**** ** ****** **** * ** * * ****** *** * ** * words or phrases are * * ** *
** ** * * ** * * * * words or phrases are not * * * ***

* * * ****** **** * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** **** **
#include * * ** *
#include * * ****
int * ** A[],char B[])
{
* ** * *** * ** * YOUR CODE HERE*/
*** ** **** * * * * *
* ** * * * * * ** **** * * **** * * * **
** * * *** ** * **** * *
*** * * * ** * *** * * *** * * * ***
*** *** ** * *** * * * * * ** ** ****** ***** ** ** *
* * **** * *
* * * *** ** ** ** * (A[i] || B[i])
* * * ** ******* * * ** * * * * 0;

** * *** ** * *** * * ** * ** (i = 0; i < 256; i++)
** * *** * * ****** * ***** ** * ** * ** **** * **
* * * * ** ***** * * ** * * * * *** ** * * *** *** ** 0;
* ** *** * ** * * * ******* 1;

*** ** ********* * OF YOUR CODE*/
** * * ******** *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
** * * * ** ** ***
** ******** * * * * YOUR CODE HERE*/
*** ** * * **** ******* * * * * * ***
* ** * * * ** * *** ** * * * *** *

** * * * *** OF YOUR CODE*/
* ** * *** * * * ** * * * ***** ** words or phrases are * *** **
* ** * * ** * ** *** words or phrases are not **** *

* *** * * ** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.29
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 5.9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.3k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users