12-28 Exercise 3: Anagrams function

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Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
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}
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prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
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#include  ** **  * 
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}
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prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
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prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
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#include <stdio.h>

int is_anagrams(char A[],char B[])
{
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}
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#include <stdio.h>

int is_anagrams(char A[],char B[])
{
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}
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#include  * * * * *  * * 
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int is_anagrams(char A[],char B[])
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{
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}
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prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
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#include *** *  ** * *** 
#include  ** ***** ** **
#include * ****  *   * * 
int is_anagrams(char A[],char B[])
{
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int main(void)
{
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*** * *     *    **** printf("Two words or phrases are not anagrams");

*   * * **     *** **  0;
}
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#include *****  **   * 
#include ** * ** ** *   
#include      ***   ** * *
int is_anagrams(char A[],char B[])
{
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}

int main(void)
{
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** *** *** *  *** ** *  **     * * *** 
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 *   **   *  ****     (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*     ** * * * * ***   * printf("Two words or phrases are not anagrams");

* *  *  * ** **  * 0;
}
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Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
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Hidden content!
#include ***  *** *     *
#include *******   ** **
#include   * ***  *  *   
int *  *** *     A[],char B[])
{
 *  **   * *  **    ****   YOUR CODE HERE*/
* *   ** * *   *** * *   * ******** *
 * * * *  **  *** * * * *   ** *     *  * ** *   * ** 
 * *  * *  ***  * * ** **  ** *
    * ****    *    ******  *****   * * **  **** ***** **** * *
  *** * * *   *  *  **   ********  **** *   *** ***   * **   *  * * * 
  * ***  *  * ** * ** *   
 * * *** * *  *  ** ** **  * **     (A[i] || B[i])
 *****   *  ****  *    *** ** *   ***** * * ** 0;

***     * **  * * * **  *  ** (i = 0; i < 256; i++)
*   *  * * *****     ** *   * *****  * * ***  ***    *    *    ** 
 *** **  *   * *  * *  *** ** **  ** * **** * ****  *    ****   **** ****  0;
* ** *  ** * * * * * ***  ** 1;

  **  * ** ** * ***** * OF YOUR CODE*/
 ** **  ****  *   *** *  function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int  **  *
{
 **  ** ** ******  *   **** 
** *** *  **  *   *  *     YOUR CODE HERE*/
**  ** ***       *** **  * * ******     * **** ****
* *        ******** * **  ****  **    **** * * ****** 

**** *   *   ***** *   *  OF YOUR CODE*/
   **  * * **    *     * * ****   *   * *  * *  * words or phrases are  * *** *    *
* ***  ** *****  ** ** ** *    **    * * words or phrases are not  ***   **  * **  

**    ** ***      *** *     0;
}
answered by (-196 points)
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prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
commented by (4.3k points)
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Hidden content!
#include *** * *  ***  ***
#include * *   **
#include      *  * *** 
int  *  **** A[],char B[])
{
*  ***   *    ******  *** YOUR CODE HERE*/
* * *  ******     ******  **  *  *     * *  *
*     *   ** * *     ** **  *  *******  *  ** * *    
****** * **  *** *** **** **
** * *********  * * * **    *   ******  **  *** *     *****  
*  *    * *     ** **     *  * *****    * ** **   **  ** * ***
*   *    * * *** ***    ** **
    *   ******  *****  * * ** (A[i] || B[i])
    *** *   *** *  *     * *  * **    **    0;

*   **   ** ** **  *  * * *  *   ** ** (i = 0; i < 256; i++)
***  **  *  ** * ** * * *    **   * *  **** *  **** **** *  ** **
    *      * *** * **  ***   *** *  *   *  **   ** * *  ** **** ***  * *  **   0;
 * * * **   * ******* **     ** ***  1;

    *  * *  **** *  * *  **   OF YOUR CODE*/
***      **     *  * **  * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int  ****
{
*    *** *   ***** * ** **  ** *  
 ** * ****  **  *   *     YOUR CODE HERE*/
****  **   * *  *   * ** *  * * **  * ** ** *  **** 
*** * * **  **     *   ** * *  *    * *** *  * *   

* * ** *    ***   **** *  OF YOUR CODE*/
 *  *  *  **  * **   *** * * ** **  * *  ** * *  *   *   words or phrases are  * *  * ***  
  *   *    *  * **  *   ***  * **  words or phrases are not    *  *** *  

 * * ** *  ** ********  * * 0;
}
answered by (-196 points)
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prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
commented by (4.3k points)
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