0 like 0 dislike
12k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 12k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include *** * * *** * *
#include * ** *** * *
#include * * * * **
int * ** ** a[],char b[])
{
*** ** ** ** ***** ** first[26] = {0}, second[26] = {0}, c = 0;
* * *
** * * *** * * *** ** * ** * frequency of *** in first string
* ***
**** * **** (a[c] != '\0')
** * * * ** * ** *
* **** *** * * * * ** ***** ** ***
** **** * * * * * ** * ** * * *** **
*** ** *** * **
* **
* * * * * * ** * = 0;
** * **
** ** * ** * ** (b[c] != '\0')
** * ** *** *** * *
* * *** * * * **** ***** **** * * * * *** ****** *
** ** * ** * ** * * **** * ** ***
* * * * *
** *
* * * *** Comparing frequency of *** ***
* ** *
***** *** * * * * (c = 0; c < 26; c++)
** * * * * * *** *
** * * ** ** * * * * **** * * ***** (first[c] != second[c])
****** * *** ** *** ** ** * * ** *** ******* 0;
* * * ** ** **
* * *
** * * * * *** * 1;
}

int * * *
{
**** * **** * * ** * *****
** * * ***** * ** * * * ** * * *** * A,B);
***** * * * * * * * *** ** ** * * ** * * words or phrases are * * ** * *
* * ** ** * *** * * * * ** * words or phrases are not ** * ****

**** * *** ** * *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * **
#include ***** **
#include ******* *
int *** ** * a[],char b[])
{
* ** **** * first[26] = {0}, second[26] = {0}, c = 0;
** *
* *** **** * ******** ** * ** frequency of characters in first string
* **
* * * * ** * (a[c] != '\0')
* * ** * * *** *
***** ** *** ** * * ** *** * *******
** ** ** *** *** * ****** * * * *
* * * * **** * *
* **
* * * ** * *** * * = 0;
* *** * *
* ** ** * ** (b[c] != '\0')
* *** * ** **
* *** * * ** *** ** ******* *
* ** ** ** * * * **** * * **** *
* * ** * ** * * ** *
***
****** ***** ** * * Comparing frequency of * *
* * *
* * ** ***** *** * * (c = 0; c < 26; c++)
****** ** * ** *
** * * * * ** *** ** * * * * *** * (first[c] != ** ** ***
* **** *** * * * * * * *** * * * ** ** **** ** 0;
* ** ** ** **
* * *
** * ** ** ** *** 1;
}

int main(void)
{
*** ** * ****** **
* ***** * * ** *** * * *** * **** ** ** **** *
***** *** ** * * * ** * ****** * words or phrases are * ******
*** * * ** ** * * * * * ** words or phrases are not * ** ** **

* **** * *** ** * ** * * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * ** ** *
#include *** * ** ** **
#include * *** * * ** *
int is_anagrams(char A[],char B[])
{
** * ** * ** * YOUR CODE HERE*/
* ** **** *** ***** *** ** * ** * ** *
*** * ** * * ** * ***** * ***** * * *
* * ***** ***** **
***** * * ************ * ** ** * **** * * ** ** * ****** * * && * ** * **
* **** * * ** * * * * **** * *** * * *** ****** ** * * * * ** **** * *
* * ** * ** * * *** * *** ** * **** * * * * && ** * * *** *** **
** * **** * * * ******* ** * ******** **** * * ** ** * * * * * ***** * **
* * *** ********* ***
* ** * **** *** * ** * * * * *
* *** ** ** ****** ******
*** * *** * ** * ************** * * **** ****** (cA[i]!=cB[i])
* * * * *** ** ** * ** * *** ******** * * * *** * ** * * * * * ** * 0;
*** ** * * *** ** ****
*** *** *** * ** * 1;
* * **** ** * ****** OF YOUR CODE*/
* ****** * *** function should return 1 if two words or phrases are anagrams,
** ** ** ** * * *** if two words or phrases are not anagrams.
}

int main(void)
{
* * * **** * A[100],B[100];
** ** *** * * * ***** YOUR CODE HERE*/
*** * * ** *** * * ** * ** * * *** *** *** ***
* * * * * * * * * * * * * * *** **
*** * * * * ** ** * ** ** * * (is_anagrams(A,B))
* ** * *** * * * * *** ** **** * ** **** *********** words or phrases are anagrams");
* ** * * * * * * ********
** **** * ** ** ** * * ****** *** ****** * * * * *** ** * ** * * words or phrases are not anagrams");
* *** * *** *** * ** * ** 0;
* ** * ** ** * **** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
*** * * * ** *** * * ******* Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * ** * ***** * ** * *
* * * ***** *** *** *** (A[i] != '\0')
* * * * ** ****
* ** * ** ** * * * * *** * * * * * * * * ** * * * * *
* ** * *** * * * * ** * **** ** ** *
* * * * * * ** * **
* **** ** ** * * ** * **
*** * * * * * * * = 0;
** ** **** * * *
* ** ** * ***** **** * * (B[i] != '\0')
** * ** * *** *
* **** * *** ** ** * * * ** * ** * * ** * *
* *** ** ** * ** * * * ** ** * ** * * **
** ******* *** **
    
* **** * *** ** * *** ** (i = 0; i < 26; i++)
* *** *** * ** * ***
*** **** *** * ** ** ** * * ****** * * ** *** * (Array1[i] != Array2[i])
* ** * * *** * * ** ***** * *** ** * * ** *** ** *** *** 0;
* *** * * **
* * ********* * ****** ***
* * * * ** * * ****** 1;
}

int main()
{
* * * ***** ** * A[100],B[100];

** *** * * * ** *** * * * *
* * ** *** ** *** ** ** ** **
*** * ** ***
* * * * *** *** * (is_anagrams(A,B))
* * * * * * ** *** *
** * * * * ** ***** * ** * ** * * **** **** words or phrases are anagrams");
** * ** * *** * *
* ** * * ** ** ***** printf("Two words or phrases are not anagrams");
* *** * * * *** *
* * * * ** *** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ***** * * * **** * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* **** * **** * ***
* * *** * ** * * *** (A[i] != '\0')
***** ** ** ** **
* * * ******* * * ** * *** * ** * * * *****
** ** * * * * ** ** * * * *** ** * * ** * *** ** * *
* ****** ****** * * *
* * ** ** * ** * * ****
*** *** ** * ** * = 0;
** ** * * * ** *** *
**** ** * *** * * ** (B[i] != '\0')
*** ** * ** **
* * ** **** * * * **** * * ** * ** * ** *** ** **
* ** ** *** ******* * * * * ** *** *** * *** ***
* ** * ** ** *** **
    
* ** ********* * * * * * ** (i = 0; i < 26; i++)
*** ** * ** * **
** ** * *** * * * * ** * *** * (Array1[i] != Array2[i])
**** * * ** * * * ** * * ** ** ** * ** * ** * * * ** ** 0;
* * *** * ** ** * *
* * * ** * * ****
*** **** ** *** * **** * * * 1;
}

int main()
{
*** ** ** *** **** ** ** A[100],B[100];

*** * * *** ** * * * ********** * * ** ***** ** * * ** * *
** *** *** ** ** *** *** **** ** *
* * ** * ** *** * *
* * * *** ***** ** **** * (is_anagrams(A,B))
* ** ** * * *** *
* * ******* * * * *** ** **** * * * ** ** * * ** * * *** words or phrases are anagrams");
****** ** *** * * * ** ** *
* * ** * ** ****** * * * printf("Two words or phrases are not anagrams");
*** **** **** * ** **
* ** **** * * ** * *** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ****
#include ** ** *** ** *
#include * ** **
int is_anagrams(char A[],char B[])
{
* ** * ** *** *** ***** lenA = strlen(A),lenB = strlen(B);
*** * *** * ** ***** != lenB)
* * * **** ****** * ** * **** * * ****** ** *** *** * 0;

* ** **** * * ***** ** ** i,j,k,a[26] ={0},b[26] = {0};
* * * **** ** * = 0 ; i < lenA ; i++)
* * * * * ** * * **** *
**** * * *** ** * **** ** * *** * ***** * * * *** * = 0 ; j < 26 ; j++)
* * ** **** * * **** **** * ** * *
* * * * *** ** ** * ** **** ****** * ***** * * ** **** * ** ** * ** == A[i] || 'A'+j == A[i])
** ** * * ** *** * *** * * ** * * * * * ** * ******* * *** *** ****** ** ***
* ** * ** ***** ***** * ** * * **** * **
* * * * * ** *** *** **
* * * * * * * * * = 0 ; i < lenB ; i++)
* * ** * * * ****
** * *** **** * * *** * *** * ** ** *** * *** * = 0 ; j < 26 ; j++)
* ** * * ****** **** ** * ** **** **** *****
* * * * * **** ** *** * ** * ** * * ** * ** **** * ** *** * *** == B[i] || 'A'+j == B[i])
* * * * ** * * ** * * **** *** * * ** ***** * ** * ** * **** *** *** **** ***** * * * **
** ******** ** * * * * * * * *** * * **
* ** ** ******** * **
* ** * * *** ***** * = 0 ; j < 26 ; j++)
* ****** ** *** * * *
* ** * ** *** * ** ** ** * * * * * * * * ***** * != b[j])
** ** * * * * ** ** * * * **** ***** * ** ** * * * **** **** ** 0;
* * ** ** * ** ***** *
** * * * *** ** * ** *** 1;

}

int main(void)
{
** ***** * ** * * * A[100],B[100];
* * ** * * * ** ** ** %s",A,B);

* ** ****** ** ** * ** * (is_anagrams(A,B)) * * **** * ** words or phrases are anagrams");
* ***** * * printf("Two words or phrases are not * * * **

* * ** ** ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * **** *
#include ** ****** * ***
#include * ********* **
int is_anagrams(char A[],char B[])
{
** * ***** * * ** * ** lenA = strlen(A),lenB = strlen(B),i,j,k;
* ** * ** * ***** * a = 0,b = 0;
* * * * * ** ** * ** * != lenB)
* * ****** **** * *** * * * * ** ***** *** * 0;
***** ** ** *** * ** = 0 ; k < 26 ; k++)
* ** * * * * ** * ** * *
**** ****** *** * **** * **** * * ** * * ** * * * = 0 ; i < lenA ; i++)
** ***** ** ** * *** *** ** **** * **** * * ** * *
**** * ** * * * *** *** ** ** * * **** * * * * ** ** * * == A[i] || 'A'+k == A[i])
**** * * * * *** * **** ** ** * **** ** * **** ** ** * ** * ** ** * * ** * **** *
*** **** * * * ** ** *** ** ** ***** * ** ** ** **
** *** **** * ** ** * * * ** * ** ** **** = 0 ; i < lenB ; i++)
* * * ******* ** * * * ** ** ** *
* **** * * ** ** * * * * **** * * * ** * * ** ** ** * ** *** * ** ** == B[i] || 'A'+k == B[i])
** ** ** ** ** * *** * ** ** **** ****** * ** *** ** *** * ** * ** ** * *** *
** * ** ** * ** ** *** * * * *** * * * *
* * ** * * * * * ** * * *** **** != b)
** * * * * *** * * * ** * * * * **** * * * **** * * ** * * ** ** * 0;
** * * *** * *** * * * **** *
***** * ****** * **** * * * * * * * * ** * * ** * * * **** * 1;
}

int main(void)
{
* ** * * * A[100],B[100];
* **** ******** * ** ** *
* * * * ****** *** *** * ***
*** * * ** *** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*** *** **** printf("Two words or phrases are not anagrams");

* * *** ** ** * ** *** * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** ***** **
#include ** ** *
#include * * ****
int is_anagrams(char A[],char B[])
{
* * * **** * * * * YOUR CODE HERE*/
* * * ** * * **** ** i,count[256]={0};
* *** ** ** * ** * ** **
* * *** * **** *
** * *** * **** * ** ***** ** * ** ** ** **** ** ** ** ****** ***
*** ** ** * * ** * *
** * * * * * ***** ***** *** * * ** *
** * ** ** ** * * ** * **
**** ** ** * * * *** ** * * ******* * *** * ***** * ****
* ** * ** ** **** *
/*
** * * ** * *** * * * (A[i]!=0 || B[i]!=0){
*** *** * ** ** ***** * ** *** ** ** * * * * * * * ** **
** ** ****** ** **** ** *** * * ** * ** 0;
* * ** ** ****** *
*/ ** *** * *** ** **** ***** 0;

* ** * * * * *** ** * ** (i = 0; i <256 ; i++)
* * ** * * ** ** * * ** *** * *** ** (count[i] && i!=' '){
** ** * *** * * * ** *** ** * * **** * * * ** ** * ** * **** * **
** ** ** ** * *** * * * * * ** *** * * ** * * **** ** * **** *** * * ** 0;
** ** *** ** ****** ** **** * * * * * * **** **


* ***** *** * * **** *** 1;

** *** * * * OF YOUR CODE*/
* * **** **** * * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
***** * * A[100],B[100];
** * *** * *** *** ** ** YOUR CODE HERE*/

** ** * *** *** *** *** * * *** *
* **** *** * **** ** ** ** * **

***** ** ** * ****** * * * *** = '\0';
  // * *** * ** = '\0';
***** *** * * ** * ** i;
****** ** **** **** * **** ***
* * * * ** *** * ** ** * ***** ** ** * * * **** * * **** **
* ***** * ** ** ** ** * ***** * ** ** ***** *** *
*** * * * ** * * * * **
* *** * **** ** * **** ** **** * * ** **** * ** * * * * ** **** ***
* * ******* * * *** ***** * * ** * *** ***** ***** *

** ** *** ** ***** * OF YOUR CODE*/
*** * ** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** * *********** printf("Two words or phrases are not anagrams");

** * * * ** * * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * **
#include * * **
#include ** * * ********
int * ** ** A[],char B[])
{
**** *** ** * ** *** * ** * YOUR CODE HERE*/
**** * * **** **** * * **
**** * * * * * ** ** ***** * * ********** *
** * * ***** ** **** * *
***** *** **** ** *** * *** * * *** *** * ** ****
* *** * * * * * ** * * ***** * * **** * ** * **** * *
*** * * * *********
* **** **** * ** * (A[i] || B[i])
* ****** * * * * ** * * 0;

* ** ***** * * * * (i = 0; i < 256; i++)
* * * ** *** * ** * ** ** ** ** **** * * *
* * ** ** ******* * ** * ** * * *** **** * ** ** * * ** ** ***** * 0;
**** ** * ** * * * * * 1;

* * * ** ****** OF YOUR CODE*/
** ** * * ** * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * ** *
{
* * ** * * * * * *
** * * ** * * * * * YOUR CODE HERE*/
*** ** * ** * * ******* *** ** * * ***
* ** * * *** * * **** *** ********** **** *

**** ** * ** **** *** * OF YOUR CODE*/
** * * * *** * **** * * ******* ** ** * ******* words or phrases are ** * * * *
* * * **** * * ** * ** * words or phrases are not * ** * *

* *** **** * * *** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** * *
#include * *** ** **
#include * ** * *
int *** ** * * A[],char B[])
{
* * * *** ** * * * * YOUR CODE HERE*/
**** **** ***** ***** * * * *
* ** *** * ***** * * ** * * * * * * ** * ** *
***** ** ***** * ** *
** * * *** * *** ** ******* * *** ** *** * * *
* * * ** *** ** * * *** * * * *** ** * ******
**** * * ** ** ** * * **
**** * * * * **** * ** * (A[i] || B[i])
* *** * * *** ****** *** *** * 0;

** ***** * **** * *** (i = 0; i < 256; i++)
***** * * * *** * * * ** ****** * * * * *
* ***** * *** * * ***** * * ** * * ** * *** * * **** **** 0;
**** ***** * ** * *** ** *** * 1;

* * *** ** * * OF YOUR CODE*/
**** * * ****** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *
{
*** ** ***** * ** * *
** ** ** * * **** * YOUR CODE HERE*/
* * **** * * ** ** * * ** * * * ** * *** ***
* *** * *** * ** ** ******** * * ** ******** *

* * **** * * * * ** * OF YOUR CODE*/
* ** *** * * * ** * ** * ** * words or phrases are * * * *
* ** * * * ********* * * ** *** words or phrases are not *** ** **

** * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.81
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 5.9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.3k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users