0 like 0 dislike
16.3k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 16.3k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * *** * *** *
#include *** *** **
#include * * ** ** *
int ** ***** a[],char b[])
{
* * * ** ** *** first[26] = {0}, second[26] = {0}, c = 0;
** ***
** ** * * * * *** frequency of **** * in first string
** **
* *** ** * ** ** * (a[c] != '\0')
*** ** * * ** * *
* ** * ** * ** ** * * ******* ** **** ** **
* * ** * **** *** * ** *
* * *** * * * *
* * **
* * * * * * = 0;
****
** * * *** * * (b[c] != '\0')
* * * ******** *
* * * **** *** * * * ** ** *** ** ** * **
** *** * * ********* ***** * *** ****
** ***** * * ***** **
****
** **** ***** * Comparing frequency of ** ***
* *
**** ** * ** **** ** (c = 0; c < 26; c++)
*** ** * *
* ** * *** **** * * **** (first[c] != second[c])
* * ** **** ** *** * * ** * **** ***** ****** * * 0;
** * ** **** *
** * *
*** * ** * *** * * * 1;
}

int * *
{
* * * * * **** **
* ** *** * *** * * ** **** * * ** * A,B);
* * ** ** *** * *** * ***** **** words or phrases are * *** * **
* ** ** ** * * * * * words or phrases are not ** ********

* **** * ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *
#include *** * ** * *
#include * *** * *** ** *
int * ** * a[],char b[])
{
** * ** * *** **** * first[26] = {0}, second[26] = {0}, c = 0;
****
** ** ***** * * *** ** *** frequency of characters in first string
** *
* ** * **** * * * * * (a[c] != '\0')
* * ** * **
* * * **** * * * * ****** * ** * * **
*** * *** ****** * ** * ** * * * * **
** ** * * **** **
*** *
*** * * ***** = 0;
* * **
** * * ** * * * * * (b[c] != '\0')
* ** ** * * *
* ***** ***** * ** * * ** ** *** * * ** ** *
****** *** * * * * * **
*** * **** ****
** ** *
* * * **** ** * Comparing frequency of * * *
** *
** *** *** ** **** (c = 0; c < 26; c++)
** *** * *** * * ** *
** ** * ** * ** ** * * *** ** *** (first[c] != ** *
*** * * * * *** ** * * * *** ***** * * *** * ****** 0;
*** ****** * * **
** * *
***** ** ** ** 1;
}

int main(void)
{
*** * *** * * ** * ***
**** *** * *** **** ** * * * * * * * ** **
** ** ** ***** * *** ** * * * * * *** * *** * words or phrases are ** *
** * ** * ** ** * **** ** ** ** words or phrases are not * ** *

* * * **** * ** * *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * **** *** *
#include ******* **
#include * *** * **
int is_anagrams(char A[],char B[])
{
*** * * ** ** ** * ** YOUR CODE HERE*/
* ** * * * * ** * * * * ** * ** *
* * * ** * ** ** ** * * * *** *
* * **** * * **** *
* * **** * ****** * ** * ** ** * * * ** * * * *** * * && * * *** * **
* *** ** ****** * ** ** **** * * ** *** * * ** *** * ******* * ****
*** ** * * * *** *** * * ** * *** *** ** *** * **** *** ** && * **** * * *
* ** ***** ** ** * *** * *** * ** * * ***** * ***** * * * * * * *** *
* * *** ** * *
* * * ** ** * ***** * * **********
**** * ** * * ** * * *
*** ** ** **** * *** **** * ** ** *** * * (cA[i]!=cB[i])
* ** *** * * ** * ** ** ***** ** * ** *** * ** * ** ** *** ** 0;
** * * ** * ***** * * *
* * * *** * ** *** **** * ** 1;
**** * **** * * **** * OF YOUR CODE*/
** * *** * ** * *** function should return 1 if two words or phrases are anagrams,
* * ** **** ** *** if two words or phrases are not anagrams.
}

int main(void)
{
** **** * ** ** A[100],B[100];
* * ** * ** YOUR CODE HERE*/
*** ** ** * ** * * ** ***** ** *** * * * * *
* * *** ** * * **** ** *** * * *** *
***** * * ** * *** ** (is_anagrams(A,B))
**** ** *** **** * * * * ****** ***** * * ** words or phrases are anagrams");
*** * *** *** * *
* * * ** **** * ** ** * **** **** * * * ** * * **** words or phrases are not anagrams");
* * * * *** * ** * 0;
* **** ** *** * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
**** * ******* * ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * ** *** **** * **
* ***** * ** *** **** ** (A[i] != '\0')
* *** * * ** * * *
*** ** ** * * ****** ** ** *** ** ******* * *** *
* * * * ** * ** *** * * *** ** *** * ***
***** **** ******* * * *****
* * * ** * *** *
***** * * * *** = 0;
* *** * * * * *
* ** *** ** * * (B[i] != '\0')
** * *** * * ***
** *** * * * * * * * * * ** ** * * * * ** ** ** * ** *
** * *** * * * ** *********** *** * ** ** ***** *****
*** *** **** * * * ** ***
    
** * ***** * * **** * (i = 0; i < 26; i++)
* * **** * * ****** * *
*** * ****** **** * * * * * * **** * * * ** * (Array1[i] != Array2[i])
*** * ** ** * ** * * ** * * *** * *** ** * * * **** ** 0;
* *** * * ** * ***** ***
* **** * * * * **** **
**** ** ** *** * * * ** 1;
}

int main()
{
*** * * *** ** ** * ** A[100],B[100];

* * ** **** ** * * ***** *
*** ** * ** * ***** * *
* ** ** ** *** *** **
* ******* *** * **** * ** (is_anagrams(A,B))
* * *** * ** * ** ***
* * ** ***** * *** *** * ** * ** ******* ** * ** * * words or phrases are anagrams");
* * * *** **** ** ** ***
* * ******** ** ****** printf("Two words or phrases are not anagrams");
* **** ** ** ** **
** * ** * * **** * ****** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** * **** ****** *** Array1[26] = {0}, Array2[26] = {0}, i = 0;
*** * *** ** *** **
* *** *** ** ** * ***** (A[i] != '\0')
*** * * * ** ****
* * * *** * *** ** ** ** * * *** * ** ****** *** *
** ** *** ** * * * * ** **** ** * **** * **
**** * ******* * ***
* * * * *** *******
** ** * * * *** = 0;
** *** **** *****
* * ** * * * * * ** * (B[i] != '\0')
* * ********* ******** * **
** ** * * ** ** * ***** ** * * * **** ****** * * * ***** ***
** * ** **** * ***** ** **** * ** ** * ***
*** * * * * ** ** ** *
    
****** *** **** ***** ** (i = 0; i < 26; i++)
*** * * * ** ** * *
** * * * * * ***** ** ***** * ****** * * ** * (Array1[i] != Array2[i])
* * ** ** ** * *** * *** *** * * * ***** ** * * ** * * * * 0;
**** * * ** ** * ****
* ***** * * **** *
**** * * * * * *** *** 1;
}

int main()
{
* ***** ** ** *** * ** A[100],B[100];

**** ****** * ***** *** **** * * *** *** * *** *
* ** * **** **** * **** ** **** * * * ** * * ***
*** ** **** *
* * * * * * * ***** (is_anagrams(A,B))
*** * *** * ** * * * *
** * * * * ** * ** * * ** * ** * * ** * * * * * * ** * * words or phrases are anagrams");
* ** ** * *** ** **** ** *
** *** * ***** * **** * ** printf("Two words or phrases are not anagrams");
* ***** * ** ** * *
*** * * * * * ** ** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** *** ***
#include * ** * * *
#include * **
int is_anagrams(char A[],char B[])
{
* ****** * * lenA = strlen(A),lenB = strlen(B);
*** * * ***** * * * *** *** *** != lenB)
* * **** * * *** * * * * ** ** * * *** * 0;

* * * * * * * * * ** * * i,j,k,a[26] ={0},b[26] = {0};
** **** ** *** **** ** * = 0 ; i < lenA ; i++)
* * * ******* ** * *
* ** * ** *** * * * * **** *** * ******* *** = 0 ; j < 26 ; j++)
* ** * ********* ** * ***** **** ** ***
* **** ** *** ** * * *** ** *** ** ** * * * ** ** * ** * ** ** * ** == A[i] || 'A'+j == A[i])
* * ** ** ** * * *** *** ** * ** ** * * * * * * * ***** * * * ****** *** **** *** * * ** **** ** *
* * ** ** ** *** ** **** * * * * * * ** **
* * * *** * * *** *
* * * * * **** * * ** * = 0 ; i < lenB ; i++)
** **** ** ** ** ** *
*** * * ** *** * * * * * ** *** *** ** = 0 ; j < 26 ; j++)
* * * * ** **** * * ** * *** * * *
** ** * * *** * *** ********** * * ** * * * *** ** * ** ** == B[i] || 'A'+j == B[i])
**** * ** *** * * *** *** * * * * ******* * * * **** ** *** * ****** ** * ********
* * ** * * * *** ****** ** *** * *
** ***** * * * **** ** *
*** * ** *** *** *** ** = 0 ; j < 26 ; j++)
*** * *** * *
******* * *** * * * * * * * * * * ** ** != b[j])
*** ** * ** * * ** *** * ***** ****** *** * ***** * ****** **** * ** 0;
** ** ** * ** * * *
*** * *** * * *** *** *** * 1;

}

int main(void)
{
*** * ** *** A[100],B[100];
* * * * * * * ** *** *** ** %s",A,B);

* **** * *** ** ***** (is_anagrams(A,B)) * * **** words or phrases are anagrams");
* * * **** * **** ** printf("Two words or phrases are not * ** ****

** **** ** *** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * ***
#include * ** *** * **
#include * ****
int is_anagrams(char A[],char B[])
{
** ** *** * *** * ** * * lenA = strlen(A),lenB = strlen(B),i,j,k;
* ***** **** ** * * * * ** ** a = 0,b = 0;
* ***** * ** * * * ** * * != lenB)
** **** **** ** **** * * ***** * ** *** * 0;
**** ** ** *** * * * = 0 ; k < 26 ; k++)
* * ** *** **** ** * ****
*** *** * * * **** ** ** * * **** * ** **** = 0 ; i < lenA ; i++)
* * *** ***** ** * ** * * * * ** * ** *****
*** * *** **** ** * ****** ***** *** * ***** * ** * * * ***** * * == A[i] || 'A'+k == A[i])
* *** ** * **** * * * * * * * ** ** ** **** * ** *** ** * * ** * * **
*** * * **** ** ***** **** * * ** * *
* ** ** * * ***** ** * *** * *** *** = 0 ; i < lenB ; i++)
**** ** * * ** * ** **** * *
* * * * * * **** * * *** * ******* * * ** * *** ** * *** * ** == B[i] || 'A'+k == B[i])
** **** ** * * ***** **** * * **** **** ** * *** *** * * * ****** *** *** * *** ****
**** *** * * ** * *** * * * * * ***** **
* * *** ******** * ***** * *** ** * * ** != b)
*** *** *** *** ** * ** * * * *** * * * ** * * ** * * ** * * * ***** * 0;
* *** * * * * * * ** *** * ****
** * ** **** * ****** ** * * **** * ***** * *** * * * *** *** * * 1;
}

int main(void)
{
* * **** ** *** ** A[100],B[100];
**** * ** *** ** * *
*** * ** *** ** * * ** *
** * *** **** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
***** *** ** **** *** printf("Two words or phrases are not anagrams");

** * **** * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** ** ** **
#include * ** *** **
#include *** **** *
int is_anagrams(char A[],char B[])
{
* ** *** ** * * **** * * YOUR CODE HERE*/
** * * * * * * ** i,count[256]={0};
* ** * ** * ******** ***
* * * *** * * **** *
** * ** *** ** * * * * * ** ** ***** *** **** ****** ** * ***** *** **
*** *** ** *** * ****
***** * ** ** * ** * ***** *******
******** * * *** * * **
* ** * * * *** * ** * * *** ** * ** * * * * * ** * *** *** **** *
*** *** * ***** *
/*
* * * * * * * (A[i]!=0 || B[i]!=0){
*** * * ** **** ****** *** * ** ** * ***** *** ** ** ** * * ** * * ** ** *
** * ** ** ** * * ** *** ** ** * ** * 0;
** * *** * * * *** *** * *** ***
*/ * * * ** *** * * * *** * ** * * 0;

******** ** * ****** * ** (i = 0; i <256 ; i++)
* * ** *** ** * * ** * **** ***** ** * * * (count[i] && i!=' '){
* * * ** * * ** * * ****** * * * * ********* ** * * ** * ** * * **
**** * ** * ** * * **** * ** ** * *** **** * *** ****** * **** ** * 0;
* ** ***** * ** * **** ***** * ** ****


* * * ** ** * ** * * * * 1;

* * * * * * OF YOUR CODE*/
* * * ** *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * *** A[100],B[100];
**** * *** * * YOUR CODE HERE*/

***** * * *** *** *** **
*** ****** ** **** * *** **

** ** * * * * **** *** * = '\0';
  // * *** * * * * = '\0';
*** ** ** **** *** * i;
* * **** **** ** *** * * ** * ****
***** *** * *** * * ** * ** *** * * * ***** ** * *** * * ** * **
*** ***** * *** ** ** * **** *** *** ** ** **** * *
** * * *** * *** * * * * * ***
* ** * * * ** ** ** * ** * * * * ** * ** * ** *** ** ****** * * ****
* * * **** * *** ** ** ** ** * ** * * * * * ****** *

* ** * * * *** * OF YOUR CODE*/
**** **** * ** **** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * * * * * ** * printf("Two words or phrases are not anagrams");

* **** * ***** ******* * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** * * ***
#include ** * **
#include ***** ** ****
int ** *** ** A[],char B[])
{
*** * *** YOUR CODE HERE*/
* * * ****** ** *** ****** * *
* ** ** **** ******* * * * * * * ** *
* ** * ****** *** ******
** ** * * ** * * * * * * * * ** * * ** ** **** * **
** * * ** *** ** * * * **** * * * * ******* *
* * ** ***** **** *** *
**** ** * ** **** ** * (A[i] || B[i])
* * * *** * ***** * ** *** ********* **** 0;

**** **** **** ***** * (i = 0; i < 256; i++)
* **** * * * * * * ** ** **** ** *** * * ** * * *
**** * ******* ** * * * * * *** ** ** * ** *** ** * * ** * **** ** * *** * 0;
* ** * ** * * * 1;

* * *********** * ** * OF YOUR CODE*/
** * ** *** ** * * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * * *
{
* *** * **** * ** * **
* ***** * * ***** * *** YOUR CODE HERE*/
*** * ** ** **** ** *** **** * * * ***** ** ***
*** *** * ***** ** *** * * *** ** *** ***** ** * *

* *** ** OF YOUR CODE*/
** * ***** * * ** * * ** ** ** **** * ** words or phrases are * *** ** * *
** * ** *** ** * **** * ** words or phrases are not * ****

* * *** ** **** ** ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include *** ** ****
#include * ** * ** *
#include ** ******* *
int * ** ** ** A[],char B[])
{
******* **** * *** * ** YOUR CODE HERE*/
* *** * * ** * ** *** * **
* *** * * *** ** * ** * * * * * ** **** *
*** * * ****** ** * **** *
** * ** * *** ** ** * ** * ** * * **** * * ** **
* * *** * *** ** ** ** *** * ***** *** ** * *
* * *** *** * * * * *
* * * *** * * * * *** (A[i] || B[i])
*** *** ** *** **** ** **** ** * * 0;

* * * ** * **** ** * (i = 0; i < 256; i++)
* ***** *** * *** ** ** * * * ** **** * *
* * * * **** **** *** * * ***** * ** * *** ** * ** ** 0;
* ** *** * * * 1;

* * **** * ** * * * OF YOUR CODE*/
*** * * ****** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
** ** ** * *** * * * ** *
*** * *** ** * **** ** * YOUR CODE HERE*/
*** ** *** * ** * * ** * * * * ** ** ** *** *
** * ******** ** * * ****** * * * * ** ** ** **

* ** *** * *** * ** OF YOUR CODE*/
*** * ** **** * *** * ** * words or phrases are * ** * **
*** * ** * ***** * * * words or phrases are not * * ** ***** *

* ** ** * * *** * *** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.184
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.1k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.3k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users