0 like 0 dislike
19.8k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 19.8k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * * * * *
#include ** ****
#include ** ****
int *** a[],char b[])
{
* * * ***** ** ** first[26] = {0}, second[26] = {0}, c = 0;
** * *
* * * * * ** frequency of ** * in first string
***
***** * * *** (a[c] != '\0')
* * * **** * * *
* ** * * ***** * * * * * * ** * ****
**** ***** * * ** ** * ** **
* * * * *** ** * **
** * *
* * * * * * = 0;
** * * *
* * * * * * ** * (b[c] != '\0')
* * * ** **** *
* * **** ** * * * * * * ** * * * ** *
* * ** **** * ***** * *** **** *** * * ***
** * **** * *
* *
*** * *** * ** * * Comparing frequency of *** *
* ** ***
**** * ** *** ***** * (c = 0; c < 26; c++)
*** **** *
* ** ** * *** ** ** ** ** * * (first[c] != second[c])
* **** * ** ***** * * ** * * * * ** 0;
** * * * ***** ***
* * *
* * * * ** 1;
}

int * *
{
** ** ** ** * ** * ** * *
* ***** ** *** * * ** A,B);
*** * **** ***** * *** * * * ** ** * words or phrases are * *** * * ** *
* * ** * ** * ** * * ***** ** words or phrases are not * *

* ** * * ** * ** * * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * **** ** * *
#include * * * *** ** ***
#include * * ** * ** **
int * a[],char b[])
{
*** *** ** * * * first[26] = {0}, second[26] = {0}, c = 0;
** *
* **** * *** ** ***** * frequency of characters in first string
*** *
** ** ** * * ** * (a[c] != '\0')
* ** * ** *
** * * * ***** **** * ** * *
* * * **** * ****** * *** * * ** * *
* **** * *** * ****
* * **
* * ***** ** * ** = 0;
* **
* *** * ** **** (b[c] != '\0')
* * * * * * * *
* * ***** ** ** * ** * * * * *** * ****
** * * **** *** ** ***** * ****
** * ****** * **
***
* *** * * ***** * Comparing frequency of * ** **
* ****
* ** *** *** *** * * (c = 0; c < 26; c++)
* ** ***** **** ***
* ** *** * ** ** * * (first[c] != * ** ***
* * ****** **** *** * * *** ** * * * * * * * * 0;
* ** ** ** *
** **
* * **** *** ** * ** * 1;
}

int main(void)
{
*** * * ** *** * * *
* * * *** ****** *** * * **** *** *** * *** *
*** * * * *** *** * * ** ** ** * * words or phrases are * ** * *****
**** ** **** * ** * **** words or phrases are not * *** *

***** * ** * ***** * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include **** * ** ***
#include * * * *** * **
#include *** * ******* *
int is_anagrams(char A[],char B[])
{
*** * *** * *** ** YOUR CODE HERE*/
* ** * ******* * * * * * * * * *
* * * ** * * ** ** * * ** ** * ****
* * * ** * *** * * *
* *** ** *** ** * ** **** * * *********** * ** ** ** && *** *** * * * * *
****** ** * ** * * ** * * *** * *** * * * *** *** **** ** * * * * ****** * **** ***
* * ** *** *** *** ** ** * * ******* * ******* ** ****** * && * * *****
**** * ***** ** ** * **** ** * ** * * * ***** * ** ***** *** ** * * ****** * * * **** * *
* * * *** * ** ** *
*** * * * * * * ** * * * * *
** * * * * * * ** ** *** *
* * * * * * ** * ** * **** ** * ** * * (cA[i]!=cB[i])
* ** * ***** *** * * ** *** ***** * * *** *** * **** *** ** ** * * * 0;
* ** ** ** ** * **** *
* ******* ******** * * 1;
** *** **** * ** OF YOUR CODE*/
*** * ** ** *** function should return 1 if two words or phrases are anagrams,
*** * ** * ** ** if two words or phrases are not anagrams.
}

int main(void)
{
* **** * * * ** * A[100],B[100];
* *** * ** * YOUR CODE HERE*/
* * * * * * ** *** * ** * * * *** * * * *
* *** *** **** ** **** *** *** ** ***** * **
* **** * ** * * * (is_anagrams(A,B))
* ** * * * * ** ** ***** * *** * * *** * *** ** * words or phrases are anagrams");
*** ****** *** * * * *
* * **** ** ***** **** **** *** ** *** ** * * * *** **** words or phrases are not anagrams");
*** * ** * ****** * ** * 0;
*** ** ** ****** ** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
*** * * *** * * *** Array1[26] = {0}, Array2[26] = {0}, i = 0;
**** ** ** **** * * ***
** * * ** * **** * * * * * (A[i] != '\0')
** ** *** **** * * * *
* * ** * ******* * * * **** **** **** ** * **
* * *** ** * * * * * ** **** ** **
* * ** * ** ***** *
* *** * * * **** * **
** * ** * * = 0;
** ** * * **** * ** **
* *** ** * * ** ***** (B[i] != '\0')
** **** * ** * ***
* * * *** * * * * * **** * * * ** ***** *****
* * * * *** **** **** ** * ** * ** * * ** ***
** ** ** ****** ** * *
    
** *** * ***** * ** * ** (i = 0; i < 26; i++)
* * ** ** ** *
***** *** * **** ** * *** *** * * * * **** (Array1[i] != Array2[i])
***** ** ** * * ** ** ** ** * *** ***** *** ********* * * * ** * 0;
* ** **** *** * * **
* ** * ***** * * *** * **
**** * * * ****** *********** 1;
}

int main()
{
* * * ** * * A[100],B[100];

* * * * *** * ****** * **
* * * ** * * ** ** ** * * ** *
* ** ** * ** ** ** ** ** **
* * *** * * ** (is_anagrams(A,B))
* * ** * *** ** **
** *** * *** * ** * * * * ** **** *** * ********* ** words or phrases are anagrams");
**** * * * *** * * *** *
** * **** *** **** * ** printf("Two words or phrases are not anagrams");
******* ** * * * ** ** *
* **** *** * **** * * *** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * ** * **** *** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ******* * * ** *** * *
** *** ***** ** * ** **** ** (A[i] != '\0')
** ** * * ******** * ***
**** *** ** * * * *** ** **** ***** *** * * ** * **
** * *** * ***** * * * ** * ** ** ** * ******
*** ** ** * * * * **
* * * **** * **
* ** * * * ** * * * = 0;
* * *** **** * * *
** * ** *** * * * (B[i] != '\0')
** * *** *** ** * * ** **
* * ** **** ******* * ** ** ** * ** * **** ***
* ** * ***** * ** ** *** * ** ** * * * ** * *****
**** * ** *** * * * *
    
**** ** * * * (i = 0; i < 26; i++)
* ** * * * * *
** * * **** *** ** * * * *** * * *** * ** (Array1[i] != Array2[i])
*** **** *** * * * * ** ****** *** * ****** **** * ** ***** * * * 0;
** *** ** * * **
*** ** ** * **** *** *
** * * **** *** * * 1;
}

int main()
{
*** ** ** * ** * * ** *** ** A[100],B[100];

* * ** *** ** * * *** * *** ** *** ****
* *** * **** ** * ** * ** * * ** * * ** ****
** * * ** ***** *
* * * ** * * ** * * * * (is_anagrams(A,B))
* ** * * *** * *
** *** * *** *** * * **** *** ** *** * * *** *** * words or phrases are anagrams");
* * ********* ****** * ******
* * ** * * * * ** printf("Two words or phrases are not anagrams");
** ** ** **
* * * * *** ** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * *** * * *
#include * * * *** * *
#include **** **** * *
int is_anagrams(char A[],char B[])
{
* ** * ** * **** ***** * lenA = strlen(A),lenB = strlen(B);
*** * ** ***** * ** **** * != lenB)
* * ******* * ** * ** *** ** *** ** ** 0;

* * ** ** *** ** i,j,k,a[26] ={0},b[26] = {0};
* ***** ** * *** * * * ** = 0 ; i < lenA ; i++)
*** ** **** * **
* **** *** * *** ** *** ** * ** *** * ** = 0 ; j < 26 ; j++)
*** * * * ** * * ** * ****** * **** ** **** *
* ** * * ** * * * * * *** ***** * * * * * ** * * * * *** * * *** *** * == A[i] || 'A'+j == A[i])
***** *** * **** *** * ** * ** ** ** **** ** ** ** * * ** * ** *** **** ****** * *** **
* ** * ** * * * * * ** * * * * **
**** * * ** * ****
** ***** ** ** *** = 0 ; i < lenB ; i++)
* ** * * * ** * ** *** *
** * ** *** **** * ****** ** * * * * * * * = 0 ; j < 26 ; j++)
* * ** * ** * * **** * **** *** *** ***** *
* ** * * *** * ** * * *** **** * * * * * * *** *** * ** *** * == B[i] || 'A'+j == B[i])
** *** * ** *** * * **** *** **** ** * ** ** ** *** *** **** ** * * * ** **** ******
* * * * *** * ***** * * ** * ** **
** *** * ** * ** * ***
*** * **** ******** * * * * = 0 ; j < 26 ; j++)
** **** *** * * * *
*** ** * ** * ** * ** * * * * * ** * != b[j])
* ***** * * * **** ********** ** ** * ******* * ** * * * * 0;
* ** *** * ** * ****** **
******* *** * ** * ** * 1;

}

int main(void)
{
***** *** * * *** ** A[100],B[100];
*** ** * * * ** * * %s",A,B);

* ** * ***** **** (is_anagrams(A,B)) **** ** * words or phrases are anagrams");
* ***** ** * *** * ** printf("Two words or phrases are not *** * *****

****** * * * ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * ***
#include **** * * ** *
#include * **** * ** **
int is_anagrams(char A[],char B[])
{
* * * * * ** * * * * * lenA = strlen(A),lenB = strlen(B),i,j,k;
** * * ** *** *** * * a = 0,b = 0;
** ****** * ** *** ***** ** * != lenB)
* * * * ** * ** * ** *** **** ** *** * * *** * 0;
* ** **** ***** **** = 0 ; k < 26 ; k++)
*** * * * **
** ** ** * * *** * * * * * * **** * * ** = 0 ; i < lenA ; i++)
* *** ** ******* * ** ** * * * ** **** *
*** * ** ** **** * * **** ** ** * * ** ******* **** ** ** * ** * ** == A[i] || 'A'+k == A[i])
* ** ** ** ** **** **** ***** * * * ***** * * ********* *** ** ******* * * ** * ****
* * ***** **** * * * * ** ** *******
* ** * ** * ** **** * * ** * * * **** * * *** = 0 ; i < lenB ; i++)
* ** **** * * ***** * **** *** * *****
*** ****** *** * *** ** * ***** * ***** ** * * *** * * ** ** ** * ** == B[i] || 'A'+k == B[i])
* ** * * *** ***** ** * * *** *** * * ** *** ******* *** * ** *** ** **** ***** ** * ****
* ** * * *** * * * *** ******* * ** *** **
** *** * * * *** *** * * * * * * * * ** * != b)
* ** * *** * *** * ** * * **** ** ** * *** * * *** ****** 0;
* ** * ** ** ** * * *
* * * * ** * ***** * * * ****** ** * ** *** * ** *** ** * * ** *** 1;
}

int main(void)
{
** * ***** * * A[100],B[100];
**** **** *** * *
** * **** ** *** ** *** **
** * * ****** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* *** ** ***** * ** printf("Two words or phrases are not anagrams");

*** * * * ** ** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *****
#include ** ********** *
#include ***** *** * *
int is_anagrams(char A[],char B[])
{
* * *** ** ** ** YOUR CODE HERE*/
* * * *** * * ***** ** i,count[256]={0};
**** ** * *** * * ** * * *
*** ** *** **** **** * **
* *** *** ** ** *** ** ******* ******* * ** ******* ** * * * *** * * ** * *
** * ** *** ** **** ****
** *** * ** **** * *** ** *
* *** ***** ** * *** ** *
*** ***** * * * * ** * ** ***** * * ** * * * * *** *** * * * * **** *** ****
*** ** ***** * * *
/*
** ** * **** ** * * * * (A[i]!=0 || B[i]!=0){
* *** *** * *** * * ** ** ****** * *** *** * ******* *** **** **
* * * ** * * * * * ** * ** ***** ** ** * *** 0;
* ** ** * * **** * * *
*/ * ** *** **** * * * * ** * * 0;

** * * ** * ** * (i = 0; i <256 ; i++)
** * ****** * ** * * *** ***** *** ** (count[i] && i!=' '){
*** * ** ** * * ** * *** ** * *** ** * * ** ** ** * *** ***** ** ** *** **** ** *
* * ** * ***** * * * * * * ** *** * * ******* ** ** ** * * * * * ** ** ** 0;
**** **** * ** * * ** * * *** * *** * ****


* ****** * * * * *** * * 1;

** *** *** * *** * ** OF YOUR CODE*/
* *** ** **** * *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* ** * * * **** A[100],B[100];
*** *** * * * ** ** YOUR CODE HERE*/

** ** * ** ** **** * *** * * ** **
* **** * ** * ** * ****

* *** ** * ** * * * ** * ** = '\0';
  // *** * *** ** * = '\0';
* ** ******* ** ** i;
* * ** ** *** ** **** ** * *
**** * * ***** * ** * ***** * ** * ** *** * *** * ** **
** * * ** * * *** * * * * * * *** ** * **
*** ** * * **** * ** * * * * **
*** ** * ** * ** ** ** * * * ** * * ** ** ** **** *** ** *** * *
***** ** *** ******** *** * ** * * * **** ** *** *** ** *

* ****** *** * * OF YOUR CODE*/
* * * * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * ** ** printf("Two words or phrases are not anagrams");

* * * ** * ***** ** * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** * * *
#include * ** * * ** * * *
#include * * * ** **
int ** * * ** A[],char B[])
{
* ** ***** **** * YOUR CODE HERE*/
** ****** **** * ******* * * *
* *** * *** *** * **** * *** **** ****
* **** ** **
******* ** * *** *** * * * *** ** ** * *** *
** ** * **** *** * *** * ****** * * * * * ** * *
*** * ** * ** * ** * *
**** ** * * ***** (A[i] || B[i])
* *** ** * * ** **** *** * ** * ** * * * 0;

* *** * * ** **** * * * (i = 0; i < 256; i++)
* ** * * ** * * ** ** ***** * ** ** ** * * ** *** * *
* ** * ** ** ** * * ** ** ** * * * ** * *** * * ** *** * ******* * * * ** 0;
**** * * * * ** * *** * * **** 1;

** * *** ** ** * OF YOUR CODE*/
* * ******* * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * ***
{
** ** ** * * * * **
**** ** * **** *** * * YOUR CODE HERE*/
* *** **** ** * ** * * **** * * ***
* * ** ****** * ***** * * ** * *** ***

*** ** * ** ** ** **** OF YOUR CODE*/
** *** *** *** ** ** ** * * * * * words or phrases are * **** * * *
* *** ** ** * * * *** * words or phrases are not *** * * ***

*** ** ** * * *** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include *** ** ***
#include *** * ** * * * *
#include * ** * * *
int ** * ** * A[],char B[])
{
** *** ** * * ** YOUR CODE HERE*/
* * * * * * * ** * ******* *** * * *
* * ** * * ***** ** ***** ** *** *** *
* * *** * * * * ** ****
**** * ** *** **** ** ********* *** ** * ** *****
* * ** * * ** ** ** * ** * ** ** * * * **
* * *** * * * * **** * *
* ** * ** * * ** * (A[i] || B[i])
* *** ** * * * * ** ** * ** * *** 0;

* ** *** ** * **** (i = 0; i < 256; i++)
*** ** ******** ** * ** *** *** ** * * *
* * * * * * * * * ** * * ** * * * ** * ** ***** **** * ** * * 0;
* * * * *** **** * * ** ** 1;

* ** ******* * * *** OF YOUR CODE*/
***** *** *** *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
**** * * ** *** ** ***
* ******* ** **** ** * YOUR CODE HERE*/
* * * * * * * * *** * ** * ******* **** **
*** * * **** * * * ** ** * ** * *** * ******

* * * ***** * * * ** OF YOUR CODE*/
* *** * * * **** ** * * *** ** ** ** * words or phrases are *** * *** ***
* **** * ** * * * ** * words or phrases are not * * ** **

** *** * * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.76
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 10.1k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.9k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 9.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users