0 like 0 dislike
13k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 13k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * ** **
#include ** * *** *
#include ** * *
int * * * *** a[],char b[])
{
* * ** * * *** first[26] = {0}, second[26] = {0}, c = 0;
* *
** * * * * ** *** ** ** ** frequency of * * in first string
**** *
*** *** * ** * * (a[c] != '\0')
* ** *** * * ****
** * * * * ** * ****** *** *** * *
*** *** ** ** * * * * ** *** *
*** *** ** *** * * *
** *
** *** * *** * * = 0;
*
* ** *** * ** (b[c] != '\0')
* *** *
** **** * * * * * * * * * ******
*** * * * ** * ** *** * * * * *
*** ** ** ** * * **
*** **
* *** * ** Comparing frequency of *** *
****
* ** **** *** * * (c = 0; c < 26; c++)
* **** *** *
**** **** ** * * **** ******* (first[c] != second[c])
* * **** ** * * ** ** * ** ** * * * * ** 0;
** ** * * *
*
***** ******* * * 1;
}

int * **
{
* ** ** ** * * * *
** ** * * * ** * ** **** *** * A,B);
* ** * ** * **** * * * ** ****** ** ** * * words or phrases are ** * ******* * *
* ** * ** * * ***** * ** ** *** * words or phrases are not *** **

*** *** ** * ** *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ***** ****
#include *** **
#include * * **** **
int * *** ** a[],char b[])
{
** ** **** ** ***** first[26] = {0}, second[26] = {0}, c = 0;
** * *
** *** ** * * * * * * frequency of characters in first string
** ** *
* * * * **** ** * * (a[c] != '\0')
* * ** ** * ********
*** ******** * * * ** ** ** **** * * *****
*** ** * ** * ** * ** ** * *
* *** * ***
*** ****
* * * * * ** * * = 0;
* * * *
* * ** ** * ** (b[c] != '\0')
* **** * *** *
**** *** * ****** ** **** * * * ** * * * *** ** **
** * * * ** ** * ***** ** *
* * *** * *
***
** * ** ** * * * ** Comparing frequency of ****
* *
**** *** * ** * ** (c = 0; c < 26; c++)
** ** *** * ** *
* * ** * **** ** ** * * ** * **** (first[c] != ***
** * ** * ** *** * ** ** ** *** * *** * 0;
*** * * ** ** ***
* *
* * ***** * * * * * 1;
}

int main(void)
{
** ** ******** * * ****
* * * ** * ** * * * * ** * * * * ** * ** * ** *
* * * ** * ** ** * ** * ** ** * words or phrases are * *** * ***
*** * * * ******* *** * *** **** * words or phrases are not * * *** * *

** ** * **** ** * * * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * ** * *
#include * ** ** *****
#include * * ** * *
int is_anagrams(char A[],char B[])
{
**** * ** *** * ** ** YOUR CODE HERE*/
* * *** *** ** * * * * * * * * ******* *
* * * ***** * * ** ** * **** ** *** ** *
*** * ** **** * * * **
******* ***** * * **** ** * * * * * *** * * ** * * * *** && * ** * * **
** * * ** ** * * *** * *** * *** * **** * ** * * *** * ** ** * * * * **
* * ** * ****** ***** ** ** * ** *** ** ** *** ***** ** && ** ** * *** ****
* **** * * ** ** * * *** **** * * ** ** ** * * **** *** ******* **** *
* ** * * * * * ** ** **
* * *** ******** * * **** ** *** **
*** * * * * * * * *
* * * * * *** ****** * **** ** * * * (cA[i]!=cB[i])
* ** *** ** ***** *** * ** *** ** ***** * * **** ** 0;
* ** ** * ** * * **
** ** ** *** * ** ** 1;
* * ** *** * * ** * OF YOUR CODE*/
***** ** **** *** *** function should return 1 if two words or phrases are anagrams,
* * *** ** * * if two words or phrases are not anagrams.
}

int main(void)
{
* * * * *** * ** A[100],B[100];
* * * * * ** ** *** * YOUR CODE HERE*/
* * **** * * ** * *** *** * * * * * **** *
***** * *** * *** ** * * * ** * * * * ** ** * *
*** ** * *** *** ** * ** (is_anagrams(A,B))
* ****** *** ** * *** ** * * * * ** * * *** * * ** words or phrases are anagrams");
*** ** * * *** * **** *
** * ** *** *** * * * *** ***** ** *** **** ** * ** words or phrases are not anagrams");
* * * ** ** * * * ** * 0;
* *** *** * *** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** *** * ** ** * ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * ***** ** *** * *** ***
* ** ******* ** * ** (A[i] != '\0')
** * ******* *** ** *** *** * *
** ** * * * ** * * ** * *** *** *** ******* * *
* *** ** ** * ** ** ***** * ******** ** * * *
*** ** * * * * **
* * *** * **** ** * *
* *** ** *** ** *** = 0;
* * ***** * * *** *** **
* ** ** *** ** * * *** (B[i] != '\0')
* * * **** * ** * * *
*** ** * * ***** * ** * * * * * * * * *** * * *
** * **** * * ** * ** * * ** * * **
** ********** * * * *
    
* *** **** ** * * (i = 0; i < 26; i++)
* ** * ** *** * ***** *
** *** * * * **** ** ***** *** * * ** (Array1[i] != Array2[i])
*** ** * * *** * * * ** * * ****** * * *** **** ******* * * ***** ** 0;
**** * * * ***
* ** ******** *** * *
* * ** ***** ** ** * * 1;
}

int main()
{
** * *** *** ***** * * **** A[100],B[100];

****** * * * * * *****
*** ** * * *** *** ***** ***
* * *** * * ***
* * **** ****** ** (is_anagrams(A,B))
* * ****** * ** *
* * ******** * * *** * * ** ** *** ** **** *** * * * ** * * * words or phrases are anagrams");
* ******** * * * * * *
* ***** ** * * ***** **** printf("Two words or phrases are not anagrams");
* ** * * * * ***
** * ** * ******** *** *** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** ** ******* ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
*** * * ** ** * *
* **** * * * **** *** (A[i] != '\0')
* *** *** ** ****** **
* * * ** **** **** * ** * * ** *** * ** ****
* * *** **** * *** * * ** ******* * ** *
**** ***** * ** ** **
** ** * * * * * * *
* * ** * * ******* = 0;
* * *** ** ** ***
**** * * ** *** *** *** (B[i] != '\0')
* ** ** ** * *****
* ** ** * * *** ** **** ***** *** ** * * * *** **** ****
** * * ** ** ** * ** * ** ** ** *
** ** ** ** *
    
** **** * * * ** (i = 0; i < 26; i++)
** * * ** ** * *****
** * * * * ** **** * * * * * * * ** (Array1[i] != Array2[i])
** * * *** * **** ***** * *** ****** * * * *** ** * *** * ****** 0;
** ****** * *** **** * **
* * * * **** ** * **
*** *** * ** * ** * ** 1;
}

int main()
{
* ** * * **** ** ** * * A[100],B[100];

**** * * ** * ** * * **** * * * *****
** * ** * **** * *** ** * * * ** ** **** * ****
* * ***** ** *** **
* * * * ***** *** * (is_anagrams(A,B))
* * * * **** * ** **
** * ** * *** * ** *** *** * ***** ****** * words or phrases are anagrams");
* ** *** ** * ** ** **
***** ******* * printf("Two words or phrases are not anagrams");
* *** ** ** * * * **
* ** ** * ** ** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** *
#include * ** * * * *****
#include ** ** *** **
int is_anagrams(char A[],char B[])
{
* ** ***** * * * ** **** lenA = strlen(A),lenB = strlen(B);
* * * * *** *** ** * * != lenB)
* ***** **** * * * * * * *** **** ***** * * 0;

** * ** ** * * ** * i,j,k,a[26] ={0},b[26] = {0};
** ** ** * * ****** = 0 ; i < lenA ; i++)
* * * * *** ** *
** ** * * ** * * ****** * * **** * ** * * = 0 ; j < 26 ; j++)
* * * ** ** * *** *** ***** ***** ***** *
*** * *** ** * * * ** ** ** * * *** **** * ***** * *** * * == A[i] || 'A'+j == A[i])
* ***** * *** * ** * **** * * * *** * *** ** * ** **** * * *** * * *** ** * * * * * ** ** *
* * * ***** * *** ** ***** * ** **
** ** ** * * * ** ** **
***** ** * ** * *** ** * = 0 ; i < lenB ; i++)
* ***** **** * * * *
** ** * *** * * * * * ** ** ****** * * * * * * * * = 0 ; j < 26 ; j++)
** * * ** ***** * * * ** * * * ***** * ** * *
** *** * *** *** ** *** * * ** ** * ** * **** ** * * * ** ** **** == B[i] || 'A'+j == B[i])
** * ****** * ** *** * ** ** *** *** *** ** * *** ** ***** * ** ****** * ** * *
** *** ** * ** ******* * ** *** * * ** **
** ** ** **** ** **** * * *
** ** * * * ** * * *** * * = 0 ; j < 26 ; j++)
* * ** * * * * * *
* ** * ** * * * * * ** ** ** *** **** * * **** **** * != b[j])
** * * **** **** ** * ** *** ** * * * ** * ** * * 0;
******** * * * * ** *
** * ** **** **** *** ** 1;

}

int main(void)
{
** * ** ** ******* A[100],B[100];
**** * ** * * * * ** * %s",A,B);

* * *** ****** *** (is_anagrams(A,B)) * ** **** * * words or phrases are anagrams");
****** * * * *** printf("Two words or phrases are not **** * * *

* * *** ** *** * * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * * * *
#include * ** ** ** *
#include * * * ** * *
int is_anagrams(char A[],char B[])
{
** * * * *** * *** lenA = strlen(A),lenB = strlen(B),i,j,k;
*** * *** * * *** a = 0,b = 0;
** * ** ** *** != lenB)
*** * * * **** * *** * * *** *** * * * ** * 0;
** * ** * * ** ** ** * * * * = 0 ; k < 26 ; k++)
* ** * * * * * * *
* * * * * * ** ** * ** ** *** * * *** * ** = 0 ; i < lenA ; i++)
*** * ** * * * * * * ** *** * * *** *
** ** ** * ** * *** * ***** * **** ** ** * ****** *** * == A[i] || 'A'+k == A[i])
* *** * * *** ******* * **** ** *** ** ** * * *** **** * ** *** * * ** * *
* ** * * ** * * *** * **** **** * * **
*** * * * ** * * ** * ** ** *** = 0 ; i < lenB ; i++)
* *** * ** **** ** * **** ** ****
* * * **** ** * * ** **** * *** * ** **** *** * *** * * * * == B[i] || 'A'+k == B[i])
* **** ** * * *** ** * ****** * ** * * ** ** ** **** * * * * * * * ** * * ** *
* * * * ** ** * * *** * ** **** * * * *
* *** **** * * * ** ** ** * * **** * * != b)
**** * * * * * * ** * ** * ** ***** * * * * * * * **** * * *** 0;
** **** * * * * * * * * *
*** ***** ** * * * * * ** ** * *** * * ** ** * * *** **** ** * *** 1;
}

int main(void)
{
* * * * * ****** * A[100],B[100];
* * *** ** *** * *** * * *
** * ** *** * ** ** *
** * * ** * ** *** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * * *** *** *** printf("Two words or phrases are not anagrams");

*** ** *** * **** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * ** * *
#include ** ** *
#include ** * **
int is_anagrams(char A[],char B[])
{
** * **** ** * ** *** YOUR CODE HERE*/
* * **** * ** *** i,count[256]={0};
* * ****** * * * * ** * *
** **** * * *** ** ***
* ** * ** *** ** * * * * * **** ** * * * * *** * * ********** * ** *** *
* * * ** * *** * * ****
* * * *** *** ** * * *
* * ****** * *
** * * * **** * * * ***** ****** ** *** ** ** * * ** ** * ** * * ** * ** *
*** * * ** * *** ****
/*
* * * ** * * (A[i]!=0 || B[i]!=0){
* ***** * * * * * * ******** *** ** ** ** * * *** ** *** * *** * *
*** ** * ** * *** ** ** **** ** ** * * * * **** 0;
* * ** * * * ***
*/ ** * * * ** * * **** **** ** ** * * 0;

*** *** *** * * ** *** ** (i = 0; i <256 ; i++)
* * *** *** ** * * ** * ** ** * ** ** * * (count[i] && i!=' '){
** * ** * * ** **** *** *** * * * **** *** *** * ** * * * ***** * *** ******* * * * **
* ******* * * ** * ** ** * * * * ****** **** * **** * *** * ** *** * * * 0;
**** * * ** *** ** * ** ** * * * * ***


*** ** * ** * * 1;

*** * * ** * *** OF YOUR CODE*/
******* * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
** * ** * ** * A[100],B[100];
*** **** * ** ****** YOUR CODE HERE*/

*** * ** *** ** **** ** * * *
*** **** * ***** * **

* * * * ** ******* *** = '\0';
  // ** ***** * ** = '\0';
* * * * *** *** * * * i;
* * *** * ** * * * ** * **
******* * ** * ** *** * * ** * ** ** **** *** *** * ****** ** * * *
** **** ** ** * * * *** * *** * * * **** ** *
** *** * ** *** * *** * * *** * ** *
* *** * ****** ** * ** * ** *** **** * *** * * *** ***** ** * * ** * ** *
* * * *** * ** ** * ** * * * ** * **** ** ** ** ***

* ** *** * * ** * OF YOUR CODE*/
*** **** * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * * ** * **** *** printf("Two words or phrases are not anagrams");

* ** * * * **** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ************ ***
#include * * *
#include *** ** *
int * * ** * A[],char B[])
{
* ** *** * *** *** YOUR CODE HERE*/
* **** * ****** * * * * * ** *
******** * * *** ** ** * ** ** * ** ** **
* * * ** *** * *** * ** *
* * * * * * ** *** * ***** * * * *** *
* * * * * * ****** * * * ** ** * **** *** ***** **
** * ** **** * * * *** *
** * * * ******* * (A[i] || B[i])
* ***** * ** * *** *** ** * * 0;

* * * * * ** *** (i = 0; i < 256; i++)
* *** *** * * * * ** * * ** * * ** ** * **** *
***** *** * *** *** * * * ** ** ** ** * ** **** * * * 0;
* *** * *** **** ********* * 1;

* **** ** * OF YOUR CODE*/
** * * * * * ** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * ** ** *
{
*** *** *** ** * ** **
* * * ** * ** * ** YOUR CODE HERE*/
* ** ** * ** ** ** * **** ** ****** ** ** ** ***
* * *** * ** **** * * ** *** * *** ** ** ** *

* * ***** * *** OF YOUR CODE*/
**** ** * * *** ** ** * * * ** * ** *** * words or phrases are ** **
* * * **** ** words or phrases are not **** * * * ***

* ** * * ** ** * ** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include *** * * * *
#include * * * ***
#include * * ***** *
int * * ***** * A[],char B[])
{
** * ******* * ** ** * * * YOUR CODE HERE*/
* * *** **** * * * * * * * ** * * *
** * * * ** * * ** ***** ***** * ** * **
* *** * *** * * * **
*** * * * * * ** * *** * * ** * ** * * * **
** * **** * * * * * * * ** ** ******
* * * * ** * * *** *
** * * * ** * * (A[i] || B[i])
*** * * * * **** ** *** * * * * *** 0;

* ** ** * * * ** * * * (i = 0; i < 256; i++)
*** * ***** *** *** *** * * * *** *** * *** *
* ***** * * * *** * ** * * * ** ** *** ** * * * *** ********* * 0;
**** ** ** ** * 1;

*** * ** ** **** ** *** OF YOUR CODE*/
* * * ** * * * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * ****
{
* ** * * *** * * * * ** ***
* * * * * * *** YOUR CODE HERE*/
* *** * ** *** * **** * * * **** * ***
** * ** ** ** **** * * * *** * *** * *

* **** ** ****** OF YOUR CODE*/
** * * ** ** ** * *** *** * words or phrases are * * * *
* *** * ** * * ** * * * **** *** ** words or phrases are not ** * ** * *

* * **** * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.26
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.4k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.8k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users