0 like 0 dislike
10.3k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 10.3k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * * ***** * *
#include ** * ** * *
#include * ********* * *
int ** ** ** * * a[],char b[])
{
*** * * ** * * *** first[26] = {0}, second[26] = {0}, c = 0;
*** ** *
* ** * * * *** ** frequency of *** in first string
******
* **** * * ***** (a[c] != '\0')
**** ** ** * *
** * ** * ** * ** ********** ** ** *******
*** ** * * * *** *** ***** * * * *
* * *** * * * ****
* ****
* *** *** * * = 0;
* **
** * * *** * * * (b[c] != '\0')
***** *** * **
* * ** * *** * * ** * * ********** **
* *** * * * **** * *** * ******
* *** ****** * **
*
** * * * *** ** * Comparing frequency of ** *
* *****
* ** * * * * ** (c = 0; c < 26; c++)
* * * * * * *
* * *** ** * ** * ** ** * ** ** * **** (first[c] != second[c])
* ****** ** *** *** * ** * ***** * * * *** * * 0;
* * ** * ** * **
* ** *
** * ** **** *** * 1;
}

int *** ***
{
* * *** * * * ***** ** ** * * *
***** * *** * **** * ** * ** ** * * * A,B);
* **** ** * * * ** *** * * * * words or phrases are * **** *
* *** * * * ** ** ** * *** words or phrases are not * * * *** *

* * * ** * ***** ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * **
#include *** **** * *** *
#include *** * ** *
int * ** * **** a[],char b[])
{
* ** * * ** first[26] = {0}, second[26] = {0}, c = 0;
***** *
* *** **** ** ** * * * ** * frequency of characters in first string
**
* * * * * * **** *** *** (a[c] != '\0')
* * *** * * *
* * ******* * * * * * ** * **** * * **
*** **** * *** * ************ *
*** * ** *** * ****
* * **
* ** ***** * = 0;
** *
* * ** * ** ** * * (b[c] != '\0')
** ** ** * * * * * *
* ** ** ***** * ** * * * * ** ** ** ** * * * *
*** *** * * ****** * *** * * *** *
* **** * * * **** * *
*****
**** * ** ***** Comparing frequency of ** * *
******
*** *** *** ** ** ** (c = 0; c < 26; c++)
* * **** *** * ***
***** * ** ** * *** * **** * (first[c] != * * *
** * * ** **** * * * * * *** * ** *** * *** ** ** * ** 0;
** * * *** *
** * **
*** ***** ***** 1;
}

int main(void)
{
*** * * ****** * * * * * **** **
* **** * * ** ***** ** **** * ***
** ** ** ***** ****** *** * * words or phrases are * **** ** *
* * * *** ** * ** * * * * words or phrases are not * *** * *

* * ** * ** * ** * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** *** *
#include * ** * * * ***
#include ***** *** * *
int is_anagrams(char A[],char B[])
{
* * * * * YOUR CODE HERE*/
** * * * ** * * ** * * * * * ** * * * ***
*** * * * * ***** ** * * * ** ***** *
** ** ** * *** * ** **
* * * * **** * *** * * * ** * ** * * ** *** *** && ** * ***
** *** * **** * * * ** * *** ***** ** *** * * ** * ***** ** ** *** * **
** **** * * ***** ** * * **** * ** * ****** * * * * * * *** * * ** && * * **** **
* * ** ****** * *** ****** * ** ** * * ** * ** ** ** *** * * ** *
*** ** **** **
* * ** ** * * *** * **** * ** *
* * * *** * * ***** * *
*** * *** * * * *** * * ** ** * * * * * ** (cA[i]!=cB[i])
***** * *** * **** * ** *** * **** * ** * *** *** ** * ** * * 0;
**** * *** ** ** **
* * ** * ***** * * * 1;
* * ** *** * OF YOUR CODE*/
* * *** * ************ function should return 1 if two words or phrases are anagrams,
** * * * if two words or phrases are not anagrams.
}

int main(void)
{
**** * * *** * A[100],B[100];
* *** ** * * ** YOUR CODE HERE*/
* **** * * * ** *** * * *** ** * * * * * ** * *** **
* * ** * * **** ** * * *** ****** *** * ****
* * * ** * ***** * *** (is_anagrams(A,B))
* * ** * ** * *** ** * * * * **** ** * ** ** * * words or phrases are anagrams");
**** * ****** ** ** **
******* *** ** ** ***** **** * **** * ** ** * * * * * words or phrases are not anagrams");
*** ** ** * ** * ** * *** 0;
** **** ** * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
**** ** * * ** ****** Array1[26] = {0}, Array2[26] = {0}, i = 0;
** ** ** * *** * **
* ** ** *** *** ** ** * (A[i] != '\0')
** ** * * * ** *
* ** ** * * **** * ** ** * *** *** ** * * ** ** ** ** *
* ** *** ** ** * * ******* * * *** ** *
* ** * * ** *** **** *** **
** *** * * * * ***
* ** ***** * ** * * ** = 0;
*** **** * **** * **** * *
* * * ** *** * * ***** (B[i] != '\0')
* ** *** * ***
* ** * ** * * ** *** * **** * * *** ** * * * * * * ***
***** * * * * *** * ** *** ** ***** * *
***** * ** **** * *** * ***
    
* * ******* * * * ***** (i = 0; i < 26; i++)
** * ** * * * * ** **
**** ** * ** ** * ** * * *** * * * * ** * * (Array1[i] != Array2[i])
* ** * * * * ** ****** * ** ** * ** * * ** *** *** * ** * *** 0;
* **** ** *** * * **
** * *** ***** *
******* ***** * ***** **** 1;
}

int main()
{
* *** * *** * ***** * * A[100],B[100];

**** * ** *********** ** *** * ** **
** * *** ** * * ** ** * **
* * * ** * ****** ** * *
* **** * * ***** * (is_anagrams(A,B))
******** * * * ** ** ** *
* ******* *** *** * * * * * * ** * ****** * ** * * ** * words or phrases are anagrams");
* **** ** * ** **** ***
* * * * *** *** ** ** * printf("Two words or phrases are not anagrams");
**** ****** ** *****
** ** * ** * * *** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * ********* ** *** *** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * *** * *****
*** * *** * ** ** ** * ** * (A[i] != '\0')
*** * * *** ***** * *
* * *** *** * ** ** * *** *** ** ** * ** * * * ** ***
*** ** * * * * ***** * * * ***** * *********** *
* * ** ** * *
* * * ** * * * * * **
***** * * ** = 0;
* ** * * *** ** ****
* ** *** * * *** * ** * (B[i] != '\0')
**** * ** * * * ** ***
*** *** ** * * * ****** * ** ** ** ** * ** ** ***
* *** ****** ***** ** * * * * ** ** * * *
** ** ** ** ** ** ** *** *
    
* * *** ** * * * (i = 0; i < 26; i++)
** * * ** **** ** **
** * * * ** * ** *** ** ** ** **** * * (Array1[i] != Array2[i])
* * * ** * ** *** **** ** * ** * * * ** * * *** ** * * ** 0;
* * * * * * **
* *** **** * * * ** **
* **** * *** ** ** * * * * 1;
}

int main()
{
** * * * ** ** * *** ** * * A[100],B[100];

** ** ***** ***** **** *** *** **** * * *
**** ***** ** *** ** ****** * ***
* * *** ** * * ** *
**** * * *** * * ** (is_anagrams(A,B))
** * * **** * ** * * ** * *
* * * * *** *** ** * * ****** * * ** ** * * * * words or phrases are anagrams");
** * ****** ***
* * * ** *** * * * printf("Two words or phrases are not anagrams");
***** ***** ** * ***
**** * * * ** *** * * ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** * **
#include * *** ** ** * * *
#include ** *** * * *
int is_anagrams(char A[],char B[])
{
** * * * * ** * **** lenA = strlen(A),lenB = strlen(B);
* * ** *** * * ** * * * != lenB)
* * ** *** ****** * * * * ** * ** * ** 0;

** *** ** ** ***** * * ** * i,j,k,a[26] ={0},b[26] = {0};
* * **** *** *** ** * * *** * = 0 ; i < lenA ; i++)
***** * * * *** *****
* * ***** * * ** **** ** ** ****** ** * ** * ** = 0 ; j < 26 ; j++)
* ** * * * ** *** **** * **** * * **** * * * *
* * ** * * * *** *** * * * ********* * *** ** * * *** * * * == A[i] || 'A'+j == A[i])
* * * * * * ** * * *** * * *** * * ** * *** * ** **** *** ** * * ** * * * * *
* ** ** ** * **** * ** * * ****
* **** * **** **** *
* * * * ***** *** *** = 0 ; i < lenB ; i++)
****** * ** * ** * * ** * *
*** * * ** *** * * * * * * ***** *** *** *** = 0 ; j < 26 ; j++)
* ** ** ***** *** ** * * * ** * * ** * *
* * **** * * * * * ***** * ** ** *** ** * *** * * * == B[i] || 'A'+j == B[i])
* * * * * *** ** * ** * ** * * ** * **** * *** ** * **** *** ** * * *** * **** * * **
***** *** * *** * **** * * ** *** * * *** *
*** * *** *** * * *
** * *** *** * * = 0 ; j < 26 ; j++)
* ** * * * * *****
** * **** ***** **** * * ** **** ** ***** ** != b[j])
* ******* * * * * * * * * * ***** * *** * * * * * *** * * 0;
* * ** * * *****
* ** * ***** ** ** * ** 1;

}

int main(void)
{
* ** * **** *** * * A[100],B[100];
* * * ** *** * *** * %s",A,B);

* * ******* ** * (is_anagrams(A,B)) **** * * ** words or phrases are anagrams");
*** ** ** ** **** printf("Two words or phrases are not ***** *** *

* ** ** * * * ** ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * *** *
#include *** ** **** * *
#include * *** *
int is_anagrams(char A[],char B[])
{
** * * * * * lenA = strlen(A),lenB = strlen(B),i,j,k;
* ** * ** ** * * *** * a = 0,b = 0;
**** *** ** * * *** ** != lenB)
** * *** ** *** * * * *** * ** * * * * 0;
*** ******** * * = 0 ; k < 26 ; k++)
* * ** * * * ** * ****
* ** * ****** * ***** ** ***** ** ***** * * * ** = 0 ; i < lenA ; i++)
* ** ** * * * ** ** * *** ** * *** *
* ** * * *** ** *** * * **** ** ** * *** * ***** * ** ******** == A[i] || 'A'+k == A[i])
* * ** * *** * * * * ******* *** * **** * ** ** * *** *** * **** *** * * ** * **
* * * ** *** * ** * ** * * * * ***** ** * * ***
** **** ** ** **** * ** * * * * * ** * * * = 0 ; i < lenB ; i++)
*** ** *** * ** ***** * *** ******* ** ** *
*** ** * * * ** * * * * * * * * * ****** * == B[i] || 'A'+k == B[i])
** **** *** * * * * *** *** ** * * * * * * **** * ** ***** ***** * * * * *** *** * * *
**** ** * * * * * * * * *** * * ** *
** * ** ** * * *** * ********** ** *** *** ** != b)
* ** * *** * * *** * * * * * * ****** ** ** * ** *** ** * * 0;
* ****** * *** **** *** ****
** * **** * * * **** **** * * * *** * ** * **** *** ** * ** * ** ** * 1;
}

int main(void)
{
***** ** ** ** * A[100],B[100];
**** ** ** **** ** *** **
** * * * *** ** ** * * *
*** * * ****** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
****** **** * *** * * printf("Two words or phrases are not anagrams");

**** * * **** * ** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * * * **
#include *** ** * *** ***
#include ** ** * * *
int is_anagrams(char A[],char B[])
{
* * * * * *** * * YOUR CODE HERE*/
* * *** * * * * ** ** i,count[256]={0};
*** ***** ** ***** *** * ** * *
*** ** * * * ***** ** *
* ** * * ** * **** ** **** * ** *** ** * ** *** ** * **** * * * ***** * * * * ** *** **
*** * * * * * * ** * ***
* * * *** ** ** ** ** *** * ***
*** ** ** * *
* * * * * * * * **** * * * ***** ** * ** *** * * * ****** * * **
* ** *** * ** **
/*
** * * * * * ** * ** **** * (A[i]!=0 || B[i]!=0){
* * * *** * ** **** * *** * ******* * * * *** * *** ***** **
*** *** * * ** * * ** * * ** ** ** ** * * 0;
* ** * * ** ** **
*/ * ** * ** ** * *** ** * ** * 0;

***** *** * ** **** *** * * (i = 0; i <256 ; i++)
** * ** * ** * * ** *** * ** *** * *** ** (count[i] && i!=' '){
** *** **** *** **** *** * **** *** ** * * **** ********* * **** *** **** * * * * *
*** * *** *** ** ** ** *** * * **** ** ** * * * * * * * * *** * 0;
**** ***** * ** * * * * ** ** ** * ** *


* * * ** * * * * ** 1;

* * ** * * **** *** * * OF YOUR CODE*/
* * * * * * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
** * * * ** * A[100],B[100];
* * * *** * * **** * YOUR CODE HERE*/

* ** * * * **** * * * * *
* * ** * ** **** *** * *** * **

* * *** ***** *** * ** * = '\0';
  // * ** * * = '\0';
* ** ** * ***** * * i;
* *** * * * * * **** ****
* *** ** ** * * * *** ** ** * *** ** *** * ** *** ** * * ** * *
* *** ** * *** **** * * ** *** * *** * ** **
* *** *** * * * * **** * *** ** *** * * *
* * *** * ** ** * *** ** ** **** * * ** * * ****** * ** ** * ** * * *****
* **** **** ** ***** * *** **** ** **** ** * *

*** ***** * ** * OF YOUR CODE*/
* * * * ** * * ***** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * *** * ** *** ** * printf("Two words or phrases are not anagrams");

** ** * * * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * * *** *
#include * * * * ***
#include *** ** ** ** * *
int * ** * * A[],char B[])
{
*** * ** * ** YOUR CODE HERE*/
** * ** ***** * * * * * * * *
** * * * ******* * *** ** ** * * *** **** *
* * *** *** * ** * ** * **
* ** *** ** *** ** ****** **** * ** * * * * * ** ** * **
*** * * * * * *** ** * ****** * ** ** ** **
*** * ** ** * *****
** * **** **** ** ** (A[i] || B[i])
** **** * ** **** * * * * * * * 0;

*** * * ** * ** ** ** (i = 0; i < 256; i++)
* * * **** *** * ** ** **** * * * * * ** *
* * * * * ** * * *** * * * * ** *** * ** **** ****** ** * ***** * 0;
* *** * ** * * * * * *** * 1;

* ** * * * ** * * **** OF YOUR CODE*/
** * * ** * *** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ****
{
* * **** * * * * * * **
* * * *** * * * *** YOUR CODE HERE*/
*** * * * * **** ** ** * * * ***** * *****
* *** *** * *** * **** ***** * * * * * *

* *** ********* OF YOUR CODE*/
** *** *** * * * *** **** * * * * * * ** * words or phrases are *** **** *
* ****** ** ***** * **** words or phrases are not * *

* * * * ** ***** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** **** ***
#include * ** *** ****
#include ** * ***** *
int * *** * A[],char B[])
{
* *** ***** * * * * * *** YOUR CODE HERE*/
** ** **** ** ** * * ** ** **
* * *** * * ** ***** * ****** *
* * * * * * * * ** ***
** * ** * * ** **** * *** * ***** **** ** *** ***** * ** *** * ** *
* * * **** *** ** * ** * * ** * * * ** * *
* * * * * * * * ** *
** *** *** ** ** * ** ** (A[i] || B[i])
*** ****** ** ** ** *** ** * * *** ** 0;

* *** **** * * * ** (i = 0; i < 256; i++)
* ** * * * *** ** * * ** * *** * *** * ** * ***
* ** * *** ** * *** *** *** * ******* * * * ** ** * ** * **** **** ** *** 0;
**** ** * * ** * *** * *** 1;

****** * ** ** ** ***** OF YOUR CODE*/
* ** ** * **** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *
{
* **** * * * * ** * * **
*** * * *** ****** ** * YOUR CODE HERE*/
* ** * *** * * ** ** * * *** ***** ***
*** *** ** * *** * * * * ** * * *

**** ** * ** *** OF YOUR CODE*/
* * * * * * ** ** * *** * * * ** ** words or phrases are * * * ** **
** * * * * ** ** * * * ** ***** ** words or phrases are not * * ****

* * * ** * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.62
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 4.9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 5.5k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 4.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users