0 like 0 dislike
16.9k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 16.9k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * ** **
#include ***** **
#include * ** * * *
int * ** * a[],char b[])
{
** ** * * * first[26] = {0}, second[26] = {0}, c = 0;
** *
* * * * * * * ** ** frequency of ***** in first string
*** **
*** * * **** *** (a[c] != '\0')
* **** * * ** *** *
** *** * **** ** ** * ** ** ** ****** * *
* *** * *** **** * * * ***** *** * * **
* * * * ** * **
** *
*** *** ** ** * = 0;
***
* * * ** * * ** (b[c] != '\0')
*** ******* **
*** ** * *** * ** *** ** * * * ** * * *
* ** *** * ** **** *** * * ** * * **
* ** * ***** ** *
** * *
***** * ** Comparing frequency of ** *
* *
* * * * * ** (c = 0; c < 26; c++)
*** * ** ** *****
* ** *** * * *** ***** * * * (first[c] != second[c])
* * ** * ****** *** *** * * ***** * **** * 0;
** * ******* * **
* ******
** **** * * * * * * 1;
}

int * * * *
{
***** ** *** ** *** ** ***
** * * * * **** * * * * * * A,B);
* *** **** * * * *** * * * * * ** words or phrases are * ****
* ***** ** **** ** * * * *** words or phrases are not *** *

** *** * **** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** *** * *
#include *** *** * *
#include *** ** ** *
int * ** * ****** a[],char b[])
{
*** * ****** * * first[26] = {0}, second[26] = {0}, c = 0;
*
*********** * ** ** ** ***** frequency of characters in first string
** **
* *** * * * * ** (a[c] != '\0')
*** * * * *
* * ** * **** * * ** ** * * * ******
* * ** * ******* * * *** * ** * **
****** *** * *******
** * *
* **** * *** * * = 0;
*****
* *** **** * ** (b[c] != '\0')
* ** * * * * *** ***
* * * * * ***** * *** * ** ** * * * *
* ** * * * ** **** * **** * *****
* *** *** * *
**
** ****** * *** * Comparing frequency of *** *
*
* * ***** ** *** * (c = 0; c < 26; c++)
* ** ** * *** ** *
**** **** * * * * *** * * * ***** (first[c] != ***
** * **** * * * ** * ** ****** * ****** ***** 0;
**** ** * ** * * ***
* **
** * ******* * ** 1;
}

int main(void)
{
* * ** *** * ** *
* * * ** * *** * ** ** * * ** *** * * * * * ***
** * ** ** * * **** ** ** * * *** words or phrases are ******* *** *
* **** * ** * * * * * * * words or phrases are not * **** *

*** * ** *** * ** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** * * ** **
#include * ***** * *** *
#include ** **
int is_anagrams(char A[],char B[])
{
*** * *** * * ** YOUR CODE HERE*/
** ** * * * * **** * * * * * * **** *
* * * ** **** * ***** ** *** * *
** * *** * * * * * * *
* ** **** * *** ** * ****** *** * ** * ** *** * *** ** ** && *** * **** ****
**** *** * * * ** *** * ** * * * ***** * * ** *** ** *** * * *** * * * * *
*** ** ** * ** * * * * * * *** *** ** *** ** * && * ** * *
** * * * * ** * * *** ** * * * * * ***** ** **** * * ** **** *** *** ***** *
*** * * * *** * ** **
** ** * *** * * * *** **
** ** * ****** *
* *** * *** ** * ***** * * * *** **** * ***** * *** (cA[i]!=cB[i])
**** * *** ** ** ** ** * ***** * * **** * **** ***** **** *** * **** *** 0;
** * * ** *** *****
** * ** * * ** * ** * * ** 1;
* **** *** * **** OF YOUR CODE*/
** ** * * * * * * function should return 1 if two words or phrases are anagrams,
* *** ** ** * * if two words or phrases are not anagrams.
}

int main(void)
{
** ***** * *** A[100],B[100];
* * ** * * **** *** * * * YOUR CODE HERE*/
* ***** *** ** * ***** * * * *
* ** * * *** *** * * ** *** **
* ** * *** * * ** * ** (is_anagrams(A,B))
**** * * *** ***** * * ****** * * ** ** * ******** * ** words or phrases are anagrams");
** * **** * * *** * *
*** * **** * * * * * ** ** *** * * * * **** * ** *** * words or phrases are not anagrams");
**** **** * * ** * *** * * 0;
** ** * ****** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
*** * * ** ** *** * * ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
** *** * *** * * * **
* *** ** * * *** ** * (A[i] != '\0')
* * **** ** ***
* * * *** ** ** * * * * * * * * ** *** *** **** ******* **
* ** * * ** ****** * * ** ******* * ** * * ****
****** ***** ***
* **** ** ** * **** * * *
** ** *** * ** ** * * * ** = 0;
** ** ** * ** ** * *
* ** * * ** ** *** (B[i] != '\0')
*** ** ***** * **** * *******
* * * * * **** * *** * ** ** *** * ** *** *
* * * ** ** * ** ** * * * **** *** *
* ** **** * * * * * **
    
* * ** * * ***** (i = 0; i < 26; i++)
* * ** * *** * * ** *
**** * ** * * * * * *** ** ******** *** ***** (Array1[i] != Array2[i])
**** * ** * ** * * ** ** * ** * ** * **** **** * * * * ***** ** * 0;
** ** * * *** *
*** ** ** ****
* * * * ** * * **** ** 1;
}

int main()
{
** ** *** *** ** * ** * * * A[100],B[100];

*** * * ****** *** ** * ** ** ** **
** * *** ** * * * * *** **
* * *** * * * **
**** ** **** ** * ** * (is_anagrams(A,B))
* ** * ******* ** * *** *
* * ** * * ** * * * * ** ** * * ****** * *** * * words or phrases are anagrams");
**** ***** *** *
** *** *** *** ** * * * * printf("Two words or phrases are not anagrams");
* ***** * ** * * * * * ** *
* * ** *** * * *** **** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
*** * * ** ** ********* Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ** * * **** * * * * *
* * **** ** **** * **** (A[i] != '\0')
* * * ** * * ** ** * *
* * ** ** ** ** *** * * ** * ****** * * ** ** *** * *
** * * *********** ** *** * ***** ** *** * * * *
** * * ** ***** ** ** * *
* ** * * ** ***
* ** * * *** * = 0;
**** ** **** * ** **** * *
** *** * * * ** * * (B[i] != '\0')
* ********* * *
* * *** * * *** ******** *** * * *** * * *** **** *
* ** ****** * * **** * * * * ** ** * * * **
****** *** ** *** * **
    
* * ***** * * *** (i = 0; i < 26; i++)
* * ** * ** **** ** * *
*** * ** * *** ** *** ** ** * ********* * *** * (Array1[i] != Array2[i])
******** ** * * *** **** * * ** * * **** **** * * ** * * * 0;
* *** * ** * * ** *
*** * * ** * ** * *
** *** **** * * * * * 1;
}

int main()
{
*** * * * *** **** *** ** A[100],B[100];

** * * * * *** * * * **** * ** * * ** *** * *
* * * *** * * *** * * ***** * ** * * *** **
* *** ** ** ** **
*** ** ** * * *** (is_anagrams(A,B))
** **** * ******* * ***
*** * * * * * *** ** ** **** * ** * * ** *** * ** words or phrases are anagrams");
***** ** ** * **
** ** * ***** **** printf("Two words or phrases are not anagrams");
** * * **** * *
* ** **** * * * * * ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * *** * *** *
#include ** * * * *
#include ** ** ** ** *
int is_anagrams(char A[],char B[])
{
*** * * * * *** * **** ** lenA = strlen(A),lenB = strlen(B);
** ** *** ** ** * *** != lenB)
* ** * ** * ** * * * * * * * * * **** 0;

* *** * *** ***** * * *** i,j,k,a[26] ={0},b[26] = {0};
**** *** * * *** * * = 0 ; i < lenA ; i++)
* * * * * * ** **** *
* * * *** * * * ** ** * ** * ** ** * = 0 ; j < 26 ; j++)
* *** ** **** ** *** ** * * * *
** * ** ** * * ** *** * *** * *** **** **** * * ** *** ** * ** == A[i] || 'A'+j == A[i])
* * * ** ***** * ***** * * * * * ********* ********** * * * * *** * ** * ** *** * * *** *
* *** ** ** * ** ******* ****** *** ** ** **
* * ** *** * * ****
* * * *** ** ** * *** ** ** = 0 ; i < lenB ; i++)
*** **** ** **** * *
* *** * ***** * *** * * *** ***** *** *** *** = 0 ; j < 26 ; j++)
** * * * * * * ** ** ** ** ***** * *
* ** * * * * * * *** * ** * *** * ** ********** * * **** *** ** *** ** *** * **** ** == B[i] || 'A'+j == B[i])
* * ***** * *** * ** ** ** * ** * * * * ***** * * * ** *** ** ** ***** * *
* * * *** ** ****** * * * * ***** ** * *****
** ** * ******** * ***
* * * * ** * ** * = 0 ; j < 26 ; j++)
* * ** * ** ** *
* ** * * * * * ** * * * * * **** * * **** * != b[j])
** *** * ** ** * * ******** * * * **** * * * *** *** *** * *** 0;
* * *** *** ** * *
** ** * ** * * * * * 1;

}

int main(void)
{
* * * ** ** * *** * * A[100],B[100];
********** * **** *** ** ** * ** %s",A,B);

* ** ** * ** * ** (is_anagrams(A,B)) ** * **** ** words or phrases are anagrams");
* * * ******* * printf("Two words or phrases are not * *** **** *

* ** * ** * ** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** **** ******
#include * ** ** ***
#include ** * ******
int is_anagrams(char A[],char B[])
{
* * ***** * *** ** * **** lenA = strlen(A),lenB = strlen(B),i,j,k;
** ** ** * ** * ** * * a = 0,b = 0;
* **** * *** * * * ** * != lenB)
*** ** **** **** ** ** ** ** ** * ** * * * ** 0;
***** ** * ** ** = 0 ; k < 26 ; k++)
* * ***** * * *** **
** **** * * * ****** **** ** *** *** *** = 0 ; i < lenA ; i++)
* * * * ** * * ** ** *** **** * ** *
* * ** *** *** *** * * *** **** ** ** * * * * * * ** * * *** * * *** * ** * == A[i] || 'A'+k == A[i])
*** *** * * * ** * *** ** * ** ** * * * ** ******* * * ** ** * *** * * *
** * ** ** * * * *** ** * * *** * * **
*** ******* *** ** ** * * * ** *** * = 0 ; i < lenB ; i++)
* * * * * * * * * ** ***** * ** **
* * ** ** *** ** * *** ** ** *** ** **** * **** * ** * *** * * ** ****** ** == B[i] || 'A'+k == B[i])
*** * *** * * *** *** * *** ** * * * ** * ****** ** ** ******* * ** *** ** ***
** *** * ** * *** **** * ****** ** **** **
**** ** ** * ** * * **** ** * * * *** != b)
* * * ** * ** * ** * * ******* ** * * * * ***** * * * * 0;
* * * * * * * ******
* *** *** ** **** * * ** ** *** * ** ** ** * ** ***** * *** * ** 1;
}

int main(void)
{
* * * * * * * A[100],B[100];
*** *** * * ** *** **
* * * *** ** * ** ******* *
* * ** * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** ** * **** * * printf("Two words or phrases are not anagrams");

** ** *** * * * * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * ** * *
#include * **** * * *
#include * **** *
int is_anagrams(char A[],char B[])
{
** * * ** * ** * * * YOUR CODE HERE*/
** * **** ** ** * * i,count[256]={0};
* ** *** **** ** * * * ***** *** **
* *** **** * **** * *
*** ** ** * * ****** * * * * *** ** * * ***** *** ************* ****
**** * * ******* **
*** * * *** ** ** * * * * **
*** *** *** * ** *** ***
* * * * ** * *** ** **** * ** * * ***** * **** * * * * *** * * *** * ***
******* *** * *
/*
** ** * ** * * *** (A[i]!=0 || B[i]!=0){
** * * *** *** **** * ** *** * ** * * * ** **** *** * * ** ** * * **
* * ** ** * ** * **** * ** ** * ** ****** 0;
***** * * *
*/ ** * **** * ** * ** * *** ** ** 0;

**** *** *** *** ** * (i = 0; i <256 ; i++)
* * ** * * * * ** * ***** * * * *** (count[i] && i!=' '){
* * ** * * * ****** * * * **** * * * * * **** ** * * ** * * * * * ** * * *
* *** * * * * * **** * ******** ** * **** * * ** **** * *** * 0;
**** * ** * * *** * ** * * * * * ** *


** * * ** * * * ** ** *** 1;

* ** ** *** * *** OF YOUR CODE*/
** * *** ****** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* **** ** * * *** A[100],B[100];
* * * ****** * * YOUR CODE HERE*/

**** * ** * * ** * * * * ** *** *
** * * * * **** *** ***** * *

** * ****** * ** **** ** * * = '\0';
  // *** ** = '\0';
* * ******* * ** *** *** * i;
* * ** ** **** **** * * ****
* * * * ** * * ** * ** * ******* ** * * ** ******* ** **** ***
* **** *** * * * * *** * * * * * * * * **
* * * * **** * *** * * **** ***
* **** * ** ***** ************* *** * * *** ** *** ** ** *** * * * ***** ** ***
* **** ** ** * *** * * ** ** * ***** * *

** * *** * * ** OF YOUR CODE*/
** * * ** ** * ** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* **** ** ** * printf("Two words or phrases are not anagrams");

**** * * * * *** * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * *** *** *
#include * * * ** **
#include * * * ** * * * *
int * *** A[],char B[])
{
* * ** * *** ** YOUR CODE HERE*/
* * * ** * * ** * * * * ** *
* * ** * ****** ** *** *** ** ** * ***
* * * *** ** * *** **
* *** ** ** * * *** * * * ** * * * ** *
** *** **** ******** ***** * **** * * ** * * ** * * **
* ** ** * * * * * *
* *** ****** ****** * * (A[i] || B[i])
* * *** * * * ********* * 0;

*** ** * * * * * * *** ** (i = 0; i < 256; i++)
** * ** ** * ** *** ** * * ** * *** ******* *
**** ****** ** **** *** **** ** * *** * ** ***** ** * * * *** ***** * 0;
******* ** ***** * *** * ** * ** 1;

* *** ** * * ** OF YOUR CODE*/
* *** * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * * *
{
*** *** *** *** * ** * **
** ** **** ** * * *** YOUR CODE HERE*/
* ** * * ** * * ***** * * * * **** * ** * *
** * * ** * * ** ** * ** ** * * * *

** ** ***** * OF YOUR CODE*/
* *** ** * * * ** ** * * * * * * words or phrases are ***** ****
** * * **** ** **** * ** ** * * words or phrases are not *** **** *

*** * ** ** ** ***** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ********* **** *
#include **** ** ** ****
#include * ** **** ** * *
int * ** A[],char B[])
{
* * ** ** * * * *** YOUR CODE HERE*/
*** * * * * * * ** **** * ** ***
* ** *** * *** * ** * *** ** * ** ** * * *
*** * *** ** * ** *
**** ** ** ********** ** * * ** * * ******** ** ** *
* ********* * * * * * ** ***** **** ** ***** ** ***
** * ** ** ** * ** *
***** * ***** * * * * * (A[i] || B[i])
* * * ***** ***** ***** * * ** ** ** ** ** 0;

*** * *** ** *** ** *** (i = 0; i < 256; i++)
** *** * ** ** * *** * * ** ** * * ***** * ***
*** *** * *** * * **** * **** *** ** ** * * ** ** * * * 0;
* ** *** * * ** * * 1;

* ****** * * ** **** OF YOUR CODE*/
*** * * * * ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ***
{
* ********** * ** *** ******* *
* **** * * * ** *** YOUR CODE HERE*/
* ** ** * * * * * * * * * ** ***
** ** ** **** * * ** *** *** * *** * * * *

* ** * **** **** ** OF YOUR CODE*/
** * *** ** *** * * * * * ** ** * words or phrases are * **
** *** * * * ** * *** * **** words or phrases are not * * ***

** ** ******** *** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.111.23
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.6k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.7k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users