0 like 0 dislike
15.6k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 15.6k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * *** * * * **
#include * ** * **
#include ** *** *
int ** * a[],char b[])
{
** * * * * * first[26] = {0}, second[26] = {0}, c = 0;
* * *
*** *** ** ** *** frequency of * * in first string
* * ***
*** ** **** * * ** * ** * (a[c] != '\0')
** * * * * * * **
** **** ** * *** ******* * * *
* ***** *** * * ** ** ** * ** ****
** ** * * **
** *** *
******* *** * * = 0;
* ** ***
* * * ** ** * (b[c] != '\0')
** *** * *** ****
**** ** * ** * ** * * * *** ** *** * **** ** *
** ** *** ** *** * ** * *** ** *** *** **
*** * ** * * * ***
* *
*** * * **** *** * Comparing frequency of * *
* * *
* *** * *** * * * (c = 0; c < 26; c++)
* * * * *
* **** * *** * * ** * **** * * *** (first[c] != second[c])
* * ** ***** * * * * ******* *** ** * *** ** *** *** 0;
*** * ** *****
*** * *
****** **** * * *** * ** 1;
}

int * *
{
* *** *** **** * ** ** *
******* * ***** *** * * * * *** A,B);
* * ***** *** *** * ***** * * * * * *** words or phrases are * * * *** **
* ** ** ** ** * *** ** ** words or phrases are not * ** *

** ** *** ****** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * *
#include ** ** ** **
#include * * ** *
int *** ** a[],char b[])
{
* *** * * * first[26] = {0}, second[26] = {0}, c = 0;
* * *
**** **** ** *** * * * ** frequency of characters in first string
* *
* *** ** ** * **** * (a[c] != '\0')
* **** * * *** *
**** *** *** * ** * * **** * ** ** ***
*** ** * * * * * * *** ** **
* ** ** * ** ****
** **
** *** ** ** ***** = 0;
* ****
* * ** ** *** ** * (b[c] != '\0')
** ** * * ** *
* *** *** *** * * * * ** ********* ** ** *
* ** * * *** * * * * **** *
** ***** *** * * ***
*
** * ** * * Comparing frequency of * ** *
* *
* ***** *** ** **** (c = 0; c < 26; c++)
***** * * * *** *
** * *** *** ** **** * * *** (first[c] != * **
** * ** * ***** **** ** * *** * * **** *** *** * ** 0;
* **** * * **
* ****
*** * * ** ** * 1;
}

int main(void)
{
* * * * * * * ** *** *
*** **** ** **** * * ** *** *** * *** * * ******
* **** * **** *** ** * * *** * * ** * ** * words or phrases are * ** * **
** *** * * ** ** * ** *** *** *** words or phrases are not ** * **

* * ** ** ** ** * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** * **
#include **** * ** * *
#include ** ** * * * *
int is_anagrams(char A[],char B[])
{
**** ** * * ** * * ** YOUR CODE HERE*/
* ** *** * ** * * ** * * ******** ** *
* *** * ** * *** ** ***** *** ** **
**** * * * *** ** * ** ** *
* * * *** * ** * * * * * * * ** * * ***** ** ** ** *** && *** ** * ** *
* * * ** ****** * ** * * ** * ** * * * ** **** * ** * * * * *
*** * * * **** * * ** * ** *** ******* *** * * ** *** * **** && ** * ** **
*** * ** * **** **** ***** *** *** ** **** * **** *** ** * * ** ***** *
** * * ** * **
* ****** **** *** * * ** * *
***** ***** ** * * ** *
* * * * **** * * * *** * * ***** * * * * (cA[i]!=cB[i])
* **** ** ** **** **** ******** * * * * * * * * * *** ** * 0;
* **** *** * ** ****** *
*** * * *** * ****** 1;
* ** * ** *** * **** OF YOUR CODE*/
* ** * *** * * * *** function should return 1 if two words or phrases are anagrams,
* ** ******* * if two words or phrases are not anagrams.
}

int main(void)
{
* * * ******** *** A[100],B[100];
* * ******* * **** YOUR CODE HERE*/
*** * ** * ** ** *** * * ***** **** *
* ** ** * *** **** * * * ** ** * *** *** **
* * * * * **** ** * * * (is_anagrams(A,B))
**** ** * * *** **** ** * ** ** * **** * ** ******* * words or phrases are anagrams");
** *** ***** ** *** *** *
** *** ******* * * * * ** * * ** * ** ** * * ******* * words or phrases are not anagrams");
** * * ** *** **** * *** *** 0;
* * * ** * * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * ** ** * * *** * ** ******* Array1[26] = {0}, Array2[26] = {0}, i = 0;
* *** * * * * ** ****
** * * ***** * ** ** ** * *** (A[i] != '\0')
* * ** ** ** **** ** *
* **** * ** *** * ** * * * * ** ** * * * *
*** * * * * * * *** * **** *** *
*** ** * * ******* ***
** * *** ** ***** ***** *
* ** ** ** ** *** = 0;
* * * * * *** * *
** * * * * *** * * * (B[i] != '\0')
*** ** * **** * **
** * ** * * * * *** ** * **** **** ** *** * * ** * *
** ** * * *** * ** * ** ** ** * * ** **
** ** ** ** *** ** ***
    
* * ** * * * * ** *** * * * (i = 0; i < 26; i++)
* * ** ** ** * ** ** **
* * ****** ****** ** * * * * * ** * ** ** (Array1[i] != Array2[i])
* * * * * * * * **** *** ** *** * * ** * ** * ** ** * * 0;
* * * *** * ***
* * * * ** * *
* ********** * ** ** * *** * 1;
}

int main()
{
* * *** * *** ** * * A[100],B[100];

* ** * * * * * *** ** * * * *
* * * *** * * *** *** * ****
* ** * ** * *** ** * *
* * ** ** *** *** * * * (is_anagrams(A,B))
***** ** * ** **
* * * * * ****** * * ** *** * *** ***** * * * * words or phrases are anagrams");
** * * ***** *** * * *
* * * **** * ******* **** printf("Two words or phrases are not anagrams");
*** ** * * * *** ***** ** *
**** * ** ** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * * ** ******* *** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * ***** * * ** *
* * *** * * ** * ** ** **** (A[i] != '\0')
* * ** * ** * * ***
** ** * *** * ** * *** ** ** ** ** ***** ** **
** *** * ** ** * * * ** * ** ***** * *
* **** **** * ** **** *
**** *** * ** ** **
* ** * * * *** *** = 0;
**** ** ***** ** *** * *
* * *** *** ** *** * * * *** * (B[i] != '\0')
* ** **** *****
** * ** ** ******* *** * * * ******* * ** ** *
* * *** *** **** **** * * * * **
* * * ******** *
    
*** ** * * * * *** (i = 0; i < 26; i++)
* *** *** * * **** **
* *** * *** * ***** **** **** ****** * **** *** (Array1[i] != Array2[i])
* * * * *** * ****** * * * * * ** * * *** ** *** * **** 0;
**** *** ***
** * ***** ** * * ****
* * *** * ***** ** 1;
}

int main()
{
***** ** * *** * **** A[100],B[100];

* * * * ** * ** * ** **** *** ******* ****
* * * * * *** * ** ****** * * ** * * * *** * * *
** * * ** ***** ** **
* * * *** *** ** * * ** (is_anagrams(A,B))
** ** * *** * ** *** * *
** * * * ** * * * ** ** ** **** * * ***** words or phrases are anagrams");
* ** *** * * * *
* * * * * * * printf("Two words or phrases are not anagrams");
***** ** **
* ** **** * * *** * ** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *
#include ** ** * *
#include ***** * ****
int is_anagrams(char A[],char B[])
{
* *** * * ***** * *** lenA = strlen(A),lenB = strlen(B);
** ** * * * ** * * * != lenB)
** * * *** * ** * * *** ** * * * *** ** *** 0;

***** ** * * * ** ***** ** i,j,k,a[26] ={0},b[26] = {0};
* **** ** *** * * ** * = 0 ; i < lenA ; i++)
* * * ** ** **
* * * * ** *** * ***** * * ** ** * = 0 ; j < 26 ; j++)
** ** ** ****** ****** **** * * * * * * ** **
** * *** ***** * * ***** ** ** * ******* ** * * **** * **** == A[i] || 'A'+j == A[i])
**************** * * *** * ** * * * * * *** ***** ** **** * * ** * * *** * * * **
* * * * * * * * * * * *** ** * *
* ** *** * * ** *****
*** ************ * ** ** = 0 ; i < lenB ; i++)
* * * *** ***** **** ** * *
* **** * * *** ** * * ** * * ** ** * ** = 0 ; j < 26 ; j++)
**** **** ** ** * * * * *** * ****
* * * * ** ** *** ** * * *** *** * * * * ***** ** *** * * *** == B[i] || 'A'+j == B[i])
**** ****** * * ******* ** ** * ** * ** * ** ** *************** * ** **** ** * **** * * * * * *
* * **** * ** ** * ** ** * * ****** * * ***
*** ** * ***** **** * **
* ** * * *** ******* * * = 0 ; j < 26 ; j++)
** *** * ** **
** * ** ***** *** * **** * *** * ** ** ** != b[j])
*** * ** *** * * * * * * * ** * ** * * * * * ** *** ** 0;
** **** ** ******* * ***
* *** ** ** * * * 1;

}

int main(void)
{
** ****** *** **** A[100],B[100];
** ** * **** * * * * * * %s",A,B);

* * * * ** * **** (is_anagrams(A,B)) * * * * * words or phrases are anagrams");
*** ** ** **** * printf("Two words or phrases are not * ** * * *

******* ** ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ***** * **** *
#include ** * * *****
#include ** ****
int is_anagrams(char A[],char B[])
{
** ** * * * ** ** ** * ** * lenA = strlen(A),lenB = strlen(B),i,j,k;
**** ** *** ***** ** * a = 0,b = 0;
* * *** * * * * * * * * != lenB)
*** **** * *** ***** * * ** ** * * ** ****** * ** 0;
**** * * * * * * * * * = 0 ; k < 26 ; k++)
*** * ******* *** *
* ** * * ** ** * * ** *** ** *** * = 0 ; i < lenA ; i++)
** * * * **** ** * * * * ** **** * * * *** **** *
******* * * * ** ** ** * * *** * ******* *** ** * * * * * == A[i] || 'A'+k == A[i])
* ** * * ** ** * ** *** ** ** ** **** *** * ***** * *** * * * **** * ** ********* **** ** * * ** * **
*** * ** ** * * ** *** ** *** * ** * *
* *** ** ** ** ** * ** ** * **** ***** = 0 ; i < lenB ; i++)
*** * ******* * * * ** * * * ** * * **** **
* * * * ** ******** * ** ** ** *** ** * ** * ** * ** ***** == B[i] || 'A'+k == B[i])
* * * * ** **** ** ** ** * * ** ** * ** * * ****** * * *** * * **** * * ** * ***** * ** *
***** *** ***** *** **** ** ** ** ** * * ** **
** *** ** ** * * * * * * * ** ** * != b)
* * ***** * ** * ** * * * * ** ** *** * * * ****** * 0;
* * *** **** *** * ** ***
*** * * ** ***** * ** *** * *** *** * ** ** **** ** * *** * * * ** ** 1;
}

int main(void)
{
* ** * ** * ** * * A[100],B[100];
** * ** * * *
* * * *** *** ** * *
* * * * **** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ** **** ** * *** ** printf("Two words or phrases are not anagrams");

* ******** ** ** * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *****
#include ** * * ***
#include ** *** ** *
int is_anagrams(char A[],char B[])
{
*** * *** * ******* YOUR CODE HERE*/
** * ** ** * ** *** * * i,count[256]={0};
** ** ** * ** ** *** ******* **** *
* * ** **** ** *
** * * * * ** * * * * * ** * * * * * * ** * ** * **** ** ** * ******
**** * ** * ** *** ***
** *** ***** * * ***** ** *** * **
* * ** * ******* ** *
** *** * ***** ** * * ** ***** * *** ** *** ** ** * **** ** ***
** ** **** ** **** * *** *
/*
* * ** * * * * * * (A[i]!=0 || B[i]!=0){
***** ** * *** * * * *** *** *** ** ****** * ****
* **** * * *** ***** *** * * * * *** *** * * 0;
* * *** * * ** * * ** * ** *
*/ * * * ** * * ** * ** * * ** *** 0;

* * * ****** ** ** ** (i = 0; i <256 ; i++)
** * * *** * * * * **** * ** ****** ** ** * * (count[i] && i!=' '){
* ** *** ** ** * ** ***** * * * * * ** * ** * * * * * ** * * * * * ** ** * *
**** *** ** * * ** * * ** ** * * ** * **** *** * *** *** *** **** * 0;
***** * * * * ** * * ** * ** * *** **


* **** * * ** *** **** 1;

* *** * * * * * OF YOUR CODE*/
*** * * *** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
** **** *** * **** * A[100],B[100];
* * *** **** ** * YOUR CODE HERE*/

**** ** ******* ** * * ** ***
***** * *** * * ** ****** *** * *** ** * *

***** ** * * ***** * = '\0';
  // * * * ***** = '\0';
** * *** * * **** *** ***** i;
* ** * * * * * *
* **** *** * ** ** * * **** ** * ** * * ** *** * * *** * * * ******
* * * *** ** * *** ** * ** ** * ** * *** ** ** **** *
* ** ** ** ** ** * * ** * ** *
** * ******** **** * * * *********** ** * ** * * * * **** ** ** **
* *** * ** * * ** * * * ** * * * ** * *** **

* * ** ** * * OF YOUR CODE*/
***** * * ***** ** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * *** *** * **** printf("Two words or phrases are not anagrams");

** * ** * ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ****** * * *
#include * * * ** *
#include *** **** * *
int * * * * A[],char B[])
{
** * * * * *** ** YOUR CODE HERE*/
** ** *** * * * ****** * ** **
*** * * *** * * ** ** * ** * *
***** ** ** * * *** *
* * ****** * * ** ****** * * * * ** ***** ***
* **** *** * ** * * ** * ******* ** ** * ****
** * *** * **** * * *
* ** * ** * *** * * (A[i] || B[i])
*** **** ** * ****** ** *** * * 0;

****** ***** * ****** *** (i = 0; i < 256; i++)
* * ** ** * * * * * ** * * ** ** * *** * ** *
*** * ** ****** * ****** * * *** * ** * * ** ** * * * * *** ** * ** 0;
* **** * ******* ** * **** * 1;

* ** * ***** * ***** * OF YOUR CODE*/
* **** ***** **** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** ***
{
* * ** * * * ** *** ***
** ** * * **** ** YOUR CODE HERE*/
* *** ** * * ** * ** ** * * * * * *
* **** **** * ** * ** * **** ******** ** ***

* ** ** * * * * OF YOUR CODE*/
* ** ****** ** * * * ** * *** * ** * * words or phrases are ** ******
** * * ** *** ** ** * words or phrases are not * *** *

**** * * * * ***** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** *
#include * * **** *** * *
#include * *** *
int * * A[],char B[])
{
* * * * *** *** ** * YOUR CODE HERE*/
** * *** *** * *** * ** * ****
***** * **** * * * * * * **** * * *
* *** ********* **** * **
**** * * *** ********* * * * ****** ** * *
* * ****** ** * * * * * ** * ** * * ** ** ** * ****
* ******* * * * *
* ** * ***** * * ** * * (A[i] || B[i])
** **** * * ****** * ** ** * * ** ***** **** * 0;

*** ** ** *** * * (i = 0; i < 256; i++)
* * **** * * *** ** * * * * * **** * * *
* * ***** ** * *** ** * ** ** * ** *** * * **** ** * * *** 0;
* ** ** ** * ** * * 1;

***** * *** *** *** * OF YOUR CODE*/
** *** * ****** * * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * * ***
{
*** **** * ** ** * * * ***
* * ** *** * * YOUR CODE HERE*/
** * ** ** ** * *** ** * * * **** * * **
** * ** ** * * * ** * * ** ** * * * * * ** * **

* * * *** ** ** * OF YOUR CODE*/
** **** * * * ** ** ** * ** * ** words or phrases are * * * * * **
**** * ***** * ** * * words or phrases are not ** **

* * *********** *** * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.146
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 7.8k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.1k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users