0 like 0 dislike
7.5k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 7.5k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * **
#include ***** * * * *
#include * *** ** ***
int ** * * a[],char b[])
{
********** **** * ** ** first[26] = {0}, second[26] = {0}, c = 0;
* *
*** * * * * * * * ** *** ** * * * frequency of * in first string
** * *
**** ** **** * (a[c] != '\0')
** ***** ** * *
****** ** * *** ** * * *** * *** ** *****
* * ** ****** * * ** * * ** *
* * * * * * ** *
*** **
*** *** * = 0;
** * *
* * ** * * * ** ** * (b[c] != '\0')
* * ** ** *** *
* ***** **** * * *** * * * * * **** **
*** * **** * *** * ** * * *
** * * * *
** * **
* * ** ***** ** Comparing frequency of ** ***
* * *
*** **** * * * (c = 0; c < 26; c++)
*** * * * * * * **
* ******** ** ** ******* * * * (first[c] != second[c])
*** * * * * ** ** * * ***** *** ****** *** ** ** ** 0;
*** * * ** * * **
*** * *
* ** * ** ** *** 1;
}

int * *
{
* *** ** * *** ******
* * *** * ** * *** * * ** ***** A,B);
** * * * *** *** * ****** * * * * ** * words or phrases are * **** *
*** * * * * * * * * * ***** words or phrases are not * ** *

* * ** ******* * *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * * *
#include ** ** * * *
#include ***** ** *
int *** * ** * a[],char b[])
{
*** * *** ** * *** * ** first[26] = {0}, second[26] = {0}, c = 0;
***** *
** * ** ***** * ******** frequency of characters in first string
*** *
* ****** ******** * * (a[c] != '\0')
*** * * * ****
*** * * * ** * * * ** *** * ** ** *
* *** ** ** * * * *** * * *
*** **** *** ***** *
* * *
* *** * * * * ** = 0;
* *
* * * * ** *** * ***** (b[c] != '\0')
* * * ** * * * *
** * * ***** * *** *** * * * *** *** *** *
*** ** **** * * ** * * ***** ** **
* * *** *
* * *
* *** ** * ** ** * Comparing frequency of *******
***
* * * * ** * (c = 0; c < 26; c++)
* **** * ** * *
** * ***** ** ** ***** **** * ** (first[c] != *****
*** * * * **** *** * * * ** * ** * * * ** *** 0;
** *** ** * ***
**** *
* * * * ****** 1;
}

int main(void)
{
* * * * **** ** * ** ***
** *** * ** ** * ** ** * ** ***** * **
* * *** * ** * * * *** * ** ** * * words or phrases are * * * * ****** *
* * ** * *** * *** ** * words or phrases are not * * ****

* *** ****** *********** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * * **** *
#include * * ****** * *
#include * * * * ******
int is_anagrams(char A[],char B[])
{
** *** ** ****** YOUR CODE HERE*/
* * * * **** ****** *** **** *** ****
*** * *** * * * ** ** * * * *
** * * ** **** ** * **
* *** ** * * ***** * * **** ** **** ****** *** * ** && * ** * ** * ** **
* ** * * * * * *** * * * *** ** ***** * * * * ******* ** * * * * ** *** ** * *
* *** ** ** * * * * * * * *** * * **** ** ***** * * ** *** && *** ******
* ** ** **** * ** * ** ** * * * * ***** *** * *** **** * ****** * *** * ****
** ** ** * ** *
* ** * *** ** * ** * * * ** ****
** *** * ** * * **
** * ***** ** * *** ***** *** **** ** * * * (cA[i]!=cB[i])
*** ** ** * ***** **** * *** * * * ** * * * * **** * * ** ** ** * ** 0;
***** ** * * * * * *
* * *** *** * *** 1;
* ** ** * ** OF YOUR CODE*/
** ** * * ** *** function should return 1 if two words or phrases are anagrams,
** * *** *** ** * * if two words or phrases are not anagrams.
}

int main(void)
{
* * * * ** ***** * A[100],B[100];
* ** * * * *** YOUR CODE HERE*/
* ** ** ** * * ** * * ** ** * ** * **
** ***** ** ** * ** * * * ***** ***** * * * ** *
******* * **** *** **** * ** (is_anagrams(A,B))
* * ** * *** * **** ****** *** * ** * *** *** ** ** * words or phrases are anagrams");
* **** ** * * * * ** * ***
*** **** *** * * * ** * ******* *** *** * * * * ** words or phrases are not anagrams");
* ** ** * ** * * **** ***** * * 0;
*** ** * * * ** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * * * * ** *** * ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * *** ***** * *
***** *** * *** ** ** ** ** (A[i] != '\0')
* ** * * ** *
* ** ** * * ** * * * **** * * * ** ******* ** *
** *** **** ********* ** * * * * * *
* * *** ** * *** **
** ** * ** ** * * **** **
* * * ** * * ** * = 0;
* * * * ******
* ** ** * *** * ** *** (B[i] != '\0')
**** ******** ** *
* * * ** * * ** * *** * * * * * * ***** *** *
* * * * * ** *** **** ** *** * ** * *
** * *** * ****** *** * *
    
** *** * ** *** ** **** (i = 0; i < 26; i++)
*** * **** * ** * ** **
* * * * *** ** ** ** ** * * * * ** * * * * **** (Array1[i] != Array2[i])
* ** * ** ** ** ** * * *** *** **** ** * * * *** *** * * 0;
*** ** ** ** *** * * *
*** * * * ** * *
** ** ** * ** * ** * ** ** * * 1;
}

int main()
{
** * ** * ** * ** **** * A[100],B[100];

** * * ** * * * ** * *** *
** * ** *** *** *** * **** ** * *
** * * *** *** *
** * *** * * ** *** ** (is_anagrams(A,B))
***** ** *** ** * *
** * * * * * * * **** * ** ** * ** * *** * * words or phrases are anagrams");
* ** **** * **** * *
* * * * * * * *** *** printf("Two words or phrases are not anagrams");
* *** ** ** *** ** *
** * *** * ****** * * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * ** **** *** ** ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * *** **** * * **** **
***** * * **** ******* (A[i] != '\0')
* * * ******* * * *
* ** * * * ** * ** ** * ******** *** * * *
* ** * * *** * * * * * * * * * * * * *
* * *** **** * * * ****
* *** ** * * * **
** ** **** * ** *** * = 0;
*** * **** * ** *
*** ***** * * *** * * (B[i] != '\0')
* *** *** ** ** ** *
* *** * * ** **** *** * * ** ** * * ** * * * * *****
**** * * *** **** *** *** * * ** ** ***
* * ** * *** *** *
    
* * * ** ***** *** * ** (i = 0; i < 26; i++)
** * ***** * *** * ** *
*** * ** * * * ** * **** ** * * * ** *** (Array1[i] != Array2[i])
* * * * * * * ** * ***** ** * * * * ** * ** * * * ** * * ****** *** ** * * 0;
* * ** * * * * *****
*** * * * *** *****
* * ** **** ** * *** 1;
}

int main()
{
* ** ** * ** ** ** * * ** A[100],B[100];

* * **** ** *** **** **** **** * *** * * * * *
* **** * ** *** ** *** * *** *** **
*** * ****** *** * **
** * * * *** **** * (is_anagrams(A,B))
* * *** * * * * * * **** *
* ** * ***** * * ** *** ** ***** ** ** * * ** * ** * words or phrases are anagrams");
*** *** * * ****
* *** * * *** * * * * printf("Two words or phrases are not anagrams");
*** * * ** * * * **
* ** * ** * ******* ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** * *
#include ** **** * **
#include *** * ** * **
int is_anagrams(char A[],char B[])
{
* ** * * ***** ** * ** lenA = strlen(A),lenB = strlen(B);
** * * * * *** * * != lenB)
* * * * *** *** * * ** ** * *** ***** * * ** 0;

*** * ** *** *** i,j,k,a[26] ={0},b[26] = {0};
* * ** * * * ** * * ** * *** = 0 ; i < lenA ; i++)
**** ***** * * ** * * ***
** *** *** * ******** * ** * * *** * **** = 0 ; j < 26 ; j++)
**** ** * * * * * * *** * * * ** * **
** ** * **** * * * * * ** ** **** * * * *** * ** * * ** * ** * **** * == A[i] || 'A'+j == A[i])
**** ** * * * * ** **** ** * ** * * ***** * * * *** *** * * * **** * * * *** * *** * ** ** *
* **** ***** ** * **** ** ** * ** * * *** *
** * ****** ** * * **
* * ****** *** ** ** = 0 ; i < lenB ; i++)
* ** * * ** * ** * *
* *** **** * **** * *** * * * ** ** ** * * = 0 ; j < 26 ; j++)
* * ** * ** *** * * * * ** * **
* **** * ** * * **** *** ** * * *** ** **** ** * ** * * * ** * * ** ** ** *** == B[i] || 'A'+j == B[i])
** * ** ** ****** * * **** * *** *** * **** * * ** * *** ** ** * * * * * * * * ****
* * * ** ***** * * ** ** *** *** ***
** * ** ** *** * *
** * ** * ** ** **** * ***** = 0 ; j < 26 ; j++)
**** ** * * *** *
* ** * * ** * * * * * ** *** * ** * ** != b[j])
* **** * * * ***** * * * * *** ** * * ** * *** ** * * 0;
** ***** ** **
* * * ** * *** * ** ** 1;

}

int main(void)
{
* * * * ****** * A[100],B[100];
* * * * * * *** * ** *** %s",A,B);

** * * * (is_anagrams(A,B)) * * * words or phrases are anagrams");
* ***** **** * *** printf("Two words or phrases are not ** ** * *

** ** ** ** *** *** ** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ***** **
#include ** ** ** * * * ***
#include *** * * * * *
int is_anagrams(char A[],char B[])
{
** ** ***** *** **** * lenA = strlen(A),lenB = strlen(B),i,j,k;
** **** * ******** a = 0,b = 0;
** * ** * * ******** * * != lenB)
** * ** * * * * ** * ** ** * * * * * ** * *** 0;
* ** * * * *** * = 0 ; k < 26 ; k++)
**** * ** ** ** * *
** *** * * ** * * * * *** *** * ** * = 0 ; i < lenA ; i++)
* * ** ***** * *** * *** **** *
** ** * * * **** * * ** *** ** * *** ** * ****** * * ** * *** * * * ** == A[i] || 'A'+k == A[i])
** *** ** * ***** ** * * ** * * *** * * **** * * ** *** ***
* * ** ***** * * ** ** * * * **
*** ** ** * ** * *** ** * * ***** * *** *** ** = 0 ; i < lenB ; i++)
**** * ** ******** * * ****** * *** * ** *
* *** ** * * * ********* * * *** **** *** *** * * ** *** * * * * * == B[i] || 'A'+k == B[i])
* *** * ** ** ***** * ** * ***** * * * * ** ** ***** * * ** ** * ** *** * * *
**** * * ** ** *** * **** ** *** *** * * *
********** ****** ** *** * ** * ** ** *** != b)
* * * * * * ** ** * * ** ***** * * **** ** * * * * * * ** 0;
** ******** **** * ** * * *** *
** ****** ** * * ** **** * *** ** ******* * * * * ** * * * * *** 1;
}

int main(void)
{
*** ***** * * ** A[100],B[100];
*** * * * * **** * * *
* *** * ** * * ** ** * ** ***
*** * * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * ** ** * * printf("Two words or phrases are not anagrams");

* *** * * ** *** * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** *** ** *
#include ** * *** **** *
#include * ****** *
int is_anagrams(char A[],char B[])
{
** * *** * * ** ** YOUR CODE HERE*/
* * * * ** * * * **** * * i,count[256]={0};
* ** * * ** * ** ** ** *** *
************ * * ****
**** ** * *** ** * * ***** * ** * * * ** **** ** ** ** ** ***
** * * * * ** ** * *
* ** ** *** *** **** * * ** *
* ** *** * ** *** * * *
* *** * * * * ** * ** *** ****** * * * *** * ** * **** *** **
****** ******** * ** * **
/*
* *** * ** * ** *** *** (A[i]!=0 || B[i]!=0){
* * *********** * ***** * * * *** ** ***** * **** *** * *
* * *** ** ** * *** * * * * *** * ******** *** ** * 0;
* *** ********** * *
*/ ** ** * ** ** * *** *** *** 0;

*** *** *** ***** * * (i = 0; i <256 ; i++)
** ** ******* *** ** ** * * * * * *** *** ** * * * (count[i] && i!=' '){
****** ** * * *** ** * * **** ***** * ** * *** * ** ** * ** * ** **** * * *** *
* ** * * **** * ** * * ** * **** * * ** * ** * ** * * * * 0;
* ** **** * * * ** ** **** *** *


* * * ****** ******** * *** * 1;

* * * ** ** ** * ** OF YOUR CODE*/
* * ** ***** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* ****** * * * **** A[100],B[100];
* * * * * * *** * *** YOUR CODE HERE*/

* ** ** * * **** *** ** *** * *
** ** * *** *** ****** ** * ** *

* * * * * ** * * * *** * = '\0';
  // * ** ** ****** = '\0';
** *** ** ***** ** ** * ** ** i;
*** ****** * * * * * * * * * **
*** **** ** ****** ** ** * * **** ** ** * * **** * *** ** **** *****
* * * ** * * * ** ** ** ** * ** * * * * ** ****
** ** * * ** * * ** * *
* ** ** * *** * * ** ** * * *** * *** ** * ** * ** * * * *** *
* * ** * *** *** * * ** *** ** * *** * ** ** *****

** ***** * ** * ** * ** OF YOUR CODE*/
** ** ** * *** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * *** * * * printf("Two words or phrases are not anagrams");

***** ** ** ** ** * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * **
#include * ****** ***** * *
#include ** * **** **
int * * A[],char B[])
{
** ** *** ** * ** * * YOUR CODE HERE*/
* * * * * ** **** * * * *** ** *
** ***** * *** ** * * * *
***** * * **** * ** ** *
********** ** * ** * * ****** ** * **
******* * ** * *** ** ***** * * ** ** * * ** ** **
**** * *** * * *
* **** ** ** ***** ** (A[i] || B[i])
* * *** ***** * * *** * * * *** ** ** ** 0;

****** *** * * **** (i = 0; i < 256; i++)
** * ****** * **** ***** ** ** *** ** * * * * *
** ** ** * *** *** ********* * ** * ** ** * * * * * *** * * ** 0;
* * ** ** * ** **** * * * 1;

* * * ******** ** **** OF YOUR CODE*/
* ******** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
** * * ***** * ***** * * *** * *
* * * ** * *** * ** * * YOUR CODE HERE*/
** ** * ** * * * ** *** * * ** *
* * *** ** ** **** ** * * ***** ** *** * ** *** * *

* ** **** * ** **** OF YOUR CODE*/
* ** *** * *** ** ** * ** ** * **** ** words or phrases are * *****
** *** * ** **** * * * * ** words or phrases are not * * * * **

* * * * ** * * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * **** ** *
#include ** ** * ** *
#include * * * ** **
int * ** * A[],char B[])
{
* * * ** * *** * ** YOUR CODE HERE*/
*** **** * * ** ** *** ** ** ***
******* * ** * ** ** * * * ** * ** *** ****
* *** ** ** *** ** ** *
** * * ** * * ** *** * * * *** * * * ********* * ** *
** * ** **** * ** ** * ** ** ** * ** * ** *
*** **** * ** * * ****** **
* * * * * * * (A[i] || B[i])
** * *** * * *** * ***** * * * 0;

* * * ** ** * * * (i = 0; i < 256; i++)
** * **** *** ** *** ** * ** * * * **
** * * * * * *** ** * * *** ** ** * ** * *** ** *** ** * ** * ** 0;
**** * * ** * ** *** * * 1;

***** *** ** * * * OF YOUR CODE*/
* * * ** **** ** ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *
{
* * ******** * * *
** ** * * ** * * * YOUR CODE HERE*/
** * * * *** ****** ** ** ** * **
* * * * * ** * ** ** * * ** ** ********

* * ** * *** **** ** ** OF YOUR CODE*/
* * ** *** * * * * * * ** ** ** * words or phrases are * * *
** *** * * * * * ** *** * *** words or phrases are not *** *** ****

** * * ***** *** * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.167
©2016-2024

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 3.7k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 3.9k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 3.2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users