0 like 0 dislike
24.5k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 24.5k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * ** * * *****
#include ** ***** ***
#include * * *** *** *
int **** ** a[],char b[])
{
** ** * * ** first[26] = {0}, second[26] = {0}, c = 0;
* * **
* * ** *** *** ** ** frequency of * ** * in first string
* ** ***
** ***** * * * * (a[c] != '\0')
* ** *****
* * ** ** ** * * ** * * ** *** * * * **** * **
* * * ** *** * *** ** * * ** *
** * ** ** *
* *
* * ** ** * = 0;
* *
** *** **** * ** ** (b[c] != '\0')
**** * ** * **** *
* * *** **** * *** ** * *** * * ** * ****
** * * ***** ** ** * ** * *
* * ** * *
* **
* ***** * ** * Comparing frequency of ** ***
** *
*** ** **** * ** ** (c = 0; c < 26; c++)
** *** ** *
*** *** * ** * * *** * * ** ** * ****** (first[c] != second[c])
*** * *** *** * ** ** ** * * * * ** * *** *** * 0;
** *** ** * ** * * *
* ** **
** * * * ** *** ** 1;
}

int **
{
* * ** * * ** * *** ********
** ** * * *** ** * * * ** ******* A,B);
** *** * ***** *** **** * **** words or phrases are * *** ** **
* * * * * ** * ** * ** words or phrases are not ** ** ****

* *** *** * * * **** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** *** * *
#include * * ** **
#include * *** * * **
int * ** a[],char b[])
{
* * * * * * first[26] = {0}, second[26] = {0}, c = 0;
*** **
* *** * * * **** * * frequency of characters in first string

* ****** ** * ** (a[c] != '\0')
* * * ****** * ** ***
* *** * * * * ** **** * **** * ** ** **** *
* * * ** *** ** *** ** ****** ** * ** ***
* **** * * ** *
******* *
* ** ** * *** = 0;
** *
** *** * * **** **** (b[c] != '\0')
* *** * * * ** **
* * *** ** * * **** * * ** ** *** ***
** ** * * ******* * *** ** *
* *** *** * ** *
*
* * **** ** Comparing frequency of **
* *
* * *** * * * ** ** (c = 0; c < 26; c++)
* *** * *** **
* * ** * * * * * ** **** **** (first[c] != * **
* ** * * ** * * ** * * ** ** ****** ** * * 0;
** *** ***** * ******
** ** ***
* * ** *** ** * ** 1;
}

int main(void)
{
* ***** *** * * *** ** ** *
* * *** * * ** **** * ** * *** * ** **********
*** ** **** *** ** **** * * * ** * words or phrases are * ** * ** * *
* * * * * ** * * ** ** *** words or phrases are not **** * **

*** * **** ** * *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** * * * * *
#include ** ** * *********
#include ** ******** *
int is_anagrams(char A[],char B[])
{
*** * *** ** *** YOUR CODE HERE*/
* * *** * * ** **** ***** *** * * * * ** **
****** ** * **** * * * *** * **
* *** * * * ** * *
*** * *** ** * ** ******* *** ** * * ***** * ** * * * **** ** && * ******** * * *
* ** ** *** ** ** * * * **** * * **** * ** ** * * * * ** *****
* ** * *** * ** * **** * ** * * *** ** * * * * * ** && ***** ** **
* ** * **** * * ***** * *** * **** ** * * * *** *** * ******* * *
** * *** ** **
* ** * * * * * * ******* * * * * ****
* ** ** * * ** *
** * ** * *** **** * * * *** *** ** ** * ** (cA[i]!=cB[i])
* * * ****** **** ** * ** **** ** * **** *** * ** * * ** **** ** * 0;
** *** * * * * **** * *
**** * * **** **** * ** *** 1;
* * ****** * *** OF YOUR CODE*/
* * * **** **** ** * ** function should return 1 if two words or phrases are anagrams,
**** * * * **** if two words or phrases are not anagrams.
}

int main(void)
{
*** * * *** ** * A[100],B[100];
* * ** * * **** * **** YOUR CODE HERE*/
* ** ** ** ** * *** *** * ** ** *** **
* * * *** * *** ** ******* ** **** *
** * * ** ** * * **** (is_anagrams(A,B))
* * ** * * * * * * * *** ** * **** * * ** * *** * ** * * ** words or phrases are anagrams");
*** ** ** ******* **
** ** ** ** * ** **** *** *** * ** **** *** * *** ** words or phrases are not anagrams");
* ** * * ** ** ***** * ** * 0;
***** * **** ** **** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
****** *** * * ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
** ** * ** * * *** * ****
* ** ** ** **** * ** * (A[i] != '\0')
** ****** **** * * * ***
** * * *** * * * * ** * ** ** *** * *** * *** ** ***
**** * ***** ** *** *** *** * **** * * * ***
** ** ** * * * *** *
* ** ** * * * *
** ** * * **** ** ** * *** = 0;
* * * **** **** * * **
* ** *** *** ** ** ** (B[i] != '\0')
* ** * *** *** *
* *** * * * * * * ** * *** ****** ** * ** **
** ** * * ** * ** **** ** ***** * **
*** *** **** ******
    
*** ** * ***** * * * *** (i = 0; i < 26; i++)
* * * **** ** * * ** *
** ***** ** * * ***** * * ** * * *** * *** (Array1[i] != Array2[i])
** * *** * * *** * * * * * * * ** **** ** ** *** **** * 0;
** *** * * * * *
* ** * ** * * * ** *
* * * * * ** * * * * * 1;
}

int main()
{
* ** * **** * * *** **** A[100],B[100];

** ***** *** * ** *** ******** *
* ** * ** *** * *
** ** ** ** * *** ****
* * *** * * * (is_anagrams(A,B))
* ** **** ** * ***
* * * * * * * *** *** ** * **** * ** * * words or phrases are anagrams");
** ** * * ** * * *** **
* * ** * ** ** *** * ** **** printf("Two words or phrases are not anagrams");
* * * ** * * * * ** *
* * * * * ** **** ** * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
**** * * ***** ** ***** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ** *** *** **
* * * **** * * * * * (A[i] != '\0')
* ****** * * **
** ** *** ** * * *** * * * *** * **** ******* ** *** * *
** *** *** * * * **** * * ********* ***
* * **** ** * ** *****
*** ****** * * ** * *
* ** ** *** **** * * = 0;
* ** *** * * ** ** ***
* ****** ** * *** ** (B[i] != '\0')
* * * * * ** * * * *
* ** * * ****** * *** ** ***** ********* * * *** *
*** * * ** * *** **** * ** * ** * ** *
* ** *** * ***** * * * *
    
* ** ** ** * ** ** * (i = 0; i < 26; i++)
* * *** ** * *** * **
* * *** ****** * *** *** ** * * * ** ** * (Array1[i] != Array2[i])
***** ** * * * ** * ** * * **** *** * * *** ** ** * * ** *** ** * 0;
* * ** * * * * * * * *
* *** * * * *
*** * * ** * ** ****** ** * 1;
}

int main()
{
** * ** **** * ** ** A[100],B[100];

* * *** * ** *** * * * **** *** * ****
*** * * ** * * * * ** ** ** ** * * ** ***
* * ** ** * ** ** *
** * * * ** * * * *** (is_anagrams(A,B))
* ** * * ** *** * *
* ***** * * ** * *** **** **** * ** * * **** * ** words or phrases are anagrams");
** * ** *****
* * *** *** ** ** * ** ** printf("Two words or phrases are not anagrams");
* ** * * * * ** *** * *
** ***** * ** * * ***** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** ***
#include * * * * *****
#include * ****** * *
int is_anagrams(char A[],char B[])
{
* * * * * * **** lenA = strlen(A),lenB = strlen(B);
* * * ** * * ** ** * != lenB)
* * **** * * *** *** * * ** *** * * *** 0;

* * **** **** ** * i,j,k,a[26] ={0},b[26] = {0};
*** ** ** ***** = 0 ; i < lenA ; i++)
* ** * * *** * *******
** * * ****** * * ** * ** ****** ** *** ** ** = 0 ; j < 26 ; j++)
** *** * *** * ** * ******* *** * * **
** * * * * ***** * ** ** * * * *** ** ** * ** * * *** * * * ** == A[i] || 'A'+j == A[i])
*** * * * * * *** * ** * * ** * * *** * * ****** *** ** * * ** *** *** * * ***** *
* * * *** * ** *** * ** * ****** **
** **** * *** * *** *
* ** * * ** * * ** * * = 0 ; i < lenB ; i++)
** * * * ** * * * * *
* * * ** * ********** * *** ** ** ** ** * * = 0 ; j < 26 ; j++)
** ** * * * *** * *** * *** * * * * ** ***
** * ** ** * ** * ** ** * ** * * ** *** *** ** **** ** *** ** ****** *** * == B[i] || 'A'+j == B[i])
* *** * * ***** * * *** * ** ** * *** * * ** ** ** **** * * * * * *** * * * *
** * * ** * ** *** * * ** *** *** **
** * *** *** * ** ** * * *
* ** ** ****** * = 0 ; j < 26 ; j++)
* * ** ** ***** * * **
* *** * * * * **** * *** * * ** *** ** ** != b[j])
** * *** ** ** ** * * * * * * * **** ** * * * * ** * * 0;
** ***** *** * *** *
*** * ** * * * * ***** * 1;

}

int main(void)
{
* * * * **** *** A[100],B[100];
*** * * * *** ******* **** * %s",A,B);

* ** * ** * * ** *** (is_anagrams(A,B)) * * ** * words or phrases are anagrams");
* ** ** ** * printf("Two words or phrases are not ** * *****

** ** * **** * ***** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ***** *
#include * * ** * * ***
#include ***** ** **
int is_anagrams(char A[],char B[])
{
* **** ** * **** *** *** * **** lenA = strlen(A),lenB = strlen(B),i,j,k;
* * * * * * * * ** a = 0,b = 0;
** ** * * * * * ** * * * ** *** != lenB)
* *** ** *** *** * * ** * * * * * ** *** ** 0;
******* * * * * * ** = 0 ; k < 26 ; k++)
*** * *** ** ****** * * *
*** **** * * * * * * ** * ** *** * = 0 ; i < lenA ; i++)
* * * * * * ** * * *** ** **** ****
* * * * ** ** ** * *** * ** *** * ** * *** * ** * ** == A[i] || 'A'+k == A[i])
** ****** * * * * ** ** ** * * * ** ** * ** * ** ** * * * * **** *** * *
* ** **** * ** *** *** * * * **** * ** * ** *
* ** ** * **** * ** ** * ** * * * * = 0 ; i < lenB ; i++)
* ** * ** * ** ***** *** *** ** **
* * * ***** * ** * ** ** * * *** * * ** ** ** *** * == B[i] || 'A'+k == B[i])
** * ***** *** ** *** * ** * * ** * * ** * ** * * * ** *** * ** ** * * ****** ***
* * ** * * ** *** **** * * * ** * *** *
** * **** *** * * * ** * * * *** * * != b)
* ** ***** ***** ** *** **** ** * *** * *** * * * ** * ** *** * ** ** 0;
** ** * *** *** * *
* * * * * ** * * * * **** ****** * * * ** *** * ** * ** ** 1;
}

int main(void)
{
* ** * * * * A[100],B[100];
** *** * * ** * ** * ** ****
** ** *** * * *** * * ***
***** ** **** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * *** ** ** printf("Two words or phrases are not anagrams");

* * ** ** *** * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ****** **
#include *** ** *** ** *
#include * * * * * *** *
int is_anagrams(char A[],char B[])
{
** ********* * * ** * YOUR CODE HERE*/
* * * *** *** * * * * i,count[256]={0};
* ** *** ***** ** * * * ** *
** *** *** * ** * * *
* * * ** ***** * * ** * * ** * * **** * * **** * ** * * * ****
* *** ** * ** * ** * **
** ** ** **** * * ** ** * * **
** * * * *** * ** * *
*** * * **** *** * *** * * * **** * * ***** * * * * * * ** ** * *** * * *
* * ** * * ** ***
/*
* ** * *** * ** **** * * (A[i]!=0 || B[i]!=0){
** * ** ** * *** ** ***** * * ** ** *** *** * * * * ** * * *****
* * * * ** ** * * * * ** * * * ******** * 0;
**** *** **** * * ***
*/ * *** *** * * * ** * ** 0;

*** * ** ******** *** (i = 0; i <256 ; i++)
* * * * ** **** *** ** *** ***** *** * (count[i] && i!=' '){
*** * * ** *** * **** **** * * * ** * * * * * * *** * * * * ***** * ** *****
* * * * * ** * ** * * ** * ** ** * **** *** * **** * *** * * 0;
* * * *** * ****** ** * * ******* * *


* ***** * *** * * * ** * 1;

*** ****** * * *** ** OF YOUR CODE*/
** * ** * ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * *** * ** *** ** A[100],B[100];
******* * * * *** ** YOUR CODE HERE*/

** **** *** * **** **** ** **** **
* *** **** *** ** * ** ** *******

** ***** * * * * ****** = '\0';
  // ** ** * * *** = '\0';
* ** * * * * *** i;
* * ******* ***** ** * **** ***
* * ** * * ** * *** ******* * ** * * * * * * * * ** * * ***
* * *** * * * ** * * * ** * * * ** *** ***
** * * * * * ** ***** ******* * * *
* * *** * ********** * ** * *** * *** * ***** ***** *** ****** * * * ** *
* **** ** * * ** * * ***** * * * **** ** ***** * * * *

** * ** * ** * * OF YOUR CODE*/
* * * * * * * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*** *** * ** * * ** printf("Two words or phrases are not anagrams");

** * ****** * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** *** ** ***
#include ** **** * *
#include ***** * **
int *** * * * A[],char B[])
{
** * * * * * * * ** * **** YOUR CODE HERE*/
* * * * * * **** * * * * * * * *
* * * ** * ** * * ******** * * **** * * ****
* * * **** * * *** ** * *
* * * *** ** * ** * * * ****** *** * * ** * ** *
*** ** ** ******* *** ******** **** * * ** *
* * *** *** ** * * *
* *** * ** **** *** ** (A[i] || B[i])
* **** * **** *** *** ** * 0;

*** * * * * **** * *** * (i = 0; i < 256; i++)
* * ** * * * * * *** ** ** * * * ***** *** *** * *
* ** * * * ***** ** * * * ** ** ** * ** * * * * * * 0;
** * * * **** * ***** * * * * 1;

** **** ** ** * * OF YOUR CODE*/
*** *** ** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** * **
{
*** * ***** * ** *** ******
** *** * * ***** **** ** YOUR CODE HERE*/
** * *** * ** * ***** ** *** ** ** ****
* *** * **** ** * * ** * * ***** **

* ** ******* ** * OF YOUR CODE*/
* *** *** **** * * * * * *** * words or phrases are **** **
** **** * * * * ** ** ** * * words or phrases are not * * ***

* * ** * *** ** *** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * *
#include *** *** **
#include ***** **** *
int * * ** A[],char B[])
{
** **** *** *** ** YOUR CODE HERE*/
* **** * * ** * * * ** ** ** *
** * *** * ** * * *** ** ** ** ** * * * ** *
* * *** *** * * *
* ** * * ** ** ** * **** ** **** * *** * * **
* ** * ***** ** **** ** * ** *** * * * **** * **** *
* ************ ** * * * * ** *
***** ** * *** * ** ** (A[i] || B[i])
**** **** * ** ** ***** ** 0;

* * * * ********** * (i = 0; i < 256; i++)
* * * *** * **** * * ** * * * * * * *
* * *** * * * * ** * ** * * *** ** *** * ** ** * * * * * **** * * 0;
* ** * * ** **** ** 1;

**** * * * ***** * OF YOUR CODE*/
** ***** ** **** * * *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** **
{
* ** *** * * * * * * ** **
** ** * ** * ***** * * * YOUR CODE HERE*/
* ** * *** * * **** ** * ** ** *** * *** * * *
*** * * ** ** * *** **** * ** ** *

*** *** *** * * OF YOUR CODE*/
** * *** ** * * ** *** ******* ** ** words or phrases are * ***** * ***
**** * ** * *** * ***** ** words or phrases are not * **** *

* ***** * * ***** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 13.1k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 12.2k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 11.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users