0 like 0 dislike
3.7k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 3.7k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ** * *** *** *
#include * ** **
#include * * ** *
int a[],char b[])
{
* * * * * ** * ** * first[26] = {0}, second[26] = {0}, c = 0;
* ****
** ** **** ** ** * ***** * frequency of **** in first string
**
** *** * ** * (a[c] != '\0')
** ** **** *** ** *
***** * ** * ** *** *** ** * * * * ** *
* * * * ******** *** * ** * ****
* * * ** * *******
*
** ** ** ******** = 0;
* *
**** * * * (b[c] != '\0')
**** * *
* * *** ***** ** *** *** * * *** ** ** *** **
**** ** * ** *** ** * * ***** * * ******
*** * *** * * *** *
* **
** ** ** * * *** * Comparing frequency of ** *
* * ***
** ***** ** * * * * (c = 0; c < 26; c++)
* * * * * * **
* ** * * ** * * ** **** * **** (first[c] != second[c])
** ** ********* * * ** * * ** * ** * * * * * * * * * 0;
* ** * *** **
** ***
* ***** ** * * 1;
}

int * *
{
* * *** ********** * ** * *
*** * * *** **** * ** * *** A,B);
****** * * * * * * * *** * * * * * * words or phrases are * ** *
**** * * * * ** *** ** * * words or phrases are not * *** * **

** * ** * * * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * * *
#include * * **
#include ********* **
int * * * ** a[],char b[])
{
** * * * * first[26] = {0}, second[26] = {0}, c = 0;
* **
** *** * * ** ** ** ** frequency of characters in first string
* ** **
** ** ***** ** (a[c] != '\0')
** * ** * * * * * * *
** *** *** * * ** **** ** ******* **
** *** ** * ** * * * ** **** *
* *** * *
** * ***
**** * **** * ***** = 0;
**** *
** *** *** ** * *** *** (b[c] != '\0')
* ** ***** *** ****
* * * * ** *** ***** * **** *** *
** *** * ** * **** ***** * * ** ** *
* * ** ** * *
*
**** * *** *** * Comparing frequency of ** ****
***
* * ********* * (c = 0; c < 26; c++)
* **** * **** * *
** * * *** ** * ** ** ** * * (first[c] != ** *
*** ** * * * * * ** * ** **** * * ** * ** * * * * 0;
* * ** ** *** **** **
** ***
* * * * ** 1;
}

int main(void)
{
** ** * ** * **** *
** ** *** * ***** * ** * * ** *** **** * **
* ** * * * ** * ** * * * *** ** * * ** ** words or phrases are *** * ***
* * * ** ** ** * * ** ***** words or phrases are not * **** ***

** * * * * *** * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * ** *
#include * ** ** *
#include * * ****
int is_anagrams(char A[],char B[])
{
* ****** **** ** * YOUR CODE HERE*/
** * * * ** **** * ** **** **
** * ****** *** ** ** ** * * **
* * * ** ** ***
** * * * ****** ***** * * * * * ****** ** * *** * *** * * ****** && * * * **** * *
* ** * ** ***** * * * * **** ** ** * * ** ********* ****** *** ***** ** * *
* * ** * * ***** ** * ** * *** ** * * ** ***** * *** && * ** *** **
** ***** ****** *** * * * ** * * * * **** * ** ** ** * * ***** *** *
* * * ** ** * *** * ***
**** *** ***** ** ** *** ** * *** ** *
* * ** ** * *** ** * *
** * * * * * * *** * ** * ****** ** ***** (cA[i]!=cB[i])
** ** * *** * * * ******* * *** * * ** ** * * ** * * ** * * * ** ** 0;
** * * *** * *** * ** * **
** * * **** *** ***** *** 1;
** **** * * * OF YOUR CODE*/
*** *** ****** * function should return 1 if two words or phrases are anagrams,
** * * * ** * * * if two words or phrases are not anagrams.
}

int main(void)
{
* ** **** ** **** A[100],B[100];
* * ** * ** * *** YOUR CODE HERE*/
* ** * ** *** * *** ** ******* *** *
* ** **** ** * ** ** * *** * * * ***** **
** * * * * * * * ** (is_anagrams(A,B))
* * * ** ** * ** * * ** * * * *** * **** * * * * * words or phrases are anagrams");
** * * *** **** ***
** * ** **** * *** * * ********** * * ** ** * words or phrases are not anagrams");
* ** * * **** * * * 0;
* * * ** * * ** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * ** * * **** ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* *** * * * * * ** *
* ******* * * * ** **** (A[i] != '\0')
****** *** *** ***
************ ** ** * ** * * * ** ** ** ** * * *
** ** * ** *** *** * * * * ** ******
* * *** **** *** * * *
* ** ****** ** **
*** ** * * *** = 0;
* * ** * * ** * *
** ** ** * * ** (B[i] != '\0')
* ***** * * * ** * *
* ** *** * *** * ** * ** * ** ** * **** * *
* * **** *** ******* * ** * *** ** *** ** *
*** * ***** * ** ** *** *
    
** * *** * * ***** * * ** (i = 0; i < 26; i++)
** ****** * *
** **** * *** * ** *** *** * * *** ** * * (Array1[i] != Array2[i])
** ** * *** **** * * * * * * ** * * * *** ** *** *** ** * * * 0;
*** * ** * ****** *
*** ** * ** * ** ** **
* * * * * ****** ** * * *** 1;
}

int main()
{
* ** * ** ** * **** * * A[100],B[100];

** **** *** ** ****** *
* ** ** ** * * ****** *
***** * * * *** * * *
** *** ** ** ** * * * * (is_anagrams(A,B))
* **** *** ******
** ** * *** ** * ** ** * ****** * * * ** * * *** words or phrases are anagrams");
* * ** * *** * *
* * *** ** ** ***** ****** printf("Two words or phrases are not anagrams");
** * *** ** * *
* ****** ** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * * *** * * ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
** *** * * ** * *
* ***** *** ** ** ** ** ** *** (A[i] != '\0')
* * *** ** * * * **
* * * ** *** * ** * ** *** ** * * * * * ***
** ** * * ** *** * * *** **** **** * **
**** * ** ** * * * *
* ** * ** *** **** **
** * ** * * * * * * ** = 0;
** ** * * ** *** *** * *
* **** * ** * ** * **** (B[i] != '\0')
*** * * * **** * *
*** * *** * ** ** ** * * * * ** * **** ***** * * *
* * *** ** ** * ***** ** *** * **** *** *
*** ** * * * * ** **
    
** * * ******* * * * ** * (i = 0; i < 26; i++)
* ** * * * **
* * * ****** * * * ** * * * ** * * * ** (Array1[i] != Array2[i])
* * * ** * ** ** * ** *** * *** ***** ** **** ** * *** * * * * * * 0;
***** ** * **** ****** ** ***
* * * ** *** *** *
* ** * **** * * 1;
}

int main()
{
**** ****** ** * * *** A[100],B[100];

* **** *** **** ** * **** * * * * * ***
* * ** * ** ****** * * ** * * * ** ***
* ***** * * ******
* * ****** * **** * * (is_anagrams(A,B))
* ** * *** ** * ***
* * *** ***** *** * ** ** * * **** * ** ** * ** * ** words or phrases are anagrams");
* * * * *** * * * **
* *** **** * *** ** *** * printf("Two words or phrases are not anagrams");
* *** ******* *** ** * *
**** * **** ** * * ***** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * **** ** *
#include * ** * ** * ****
#include * *** * **
int is_anagrams(char A[],char B[])
{
*** ***** ** **** * * * ** lenA = strlen(A),lenB = strlen(B);
** ** *** * *** * *** ** != lenB)
**** ****** * ** **** ** * * * *** * ** * * * 0;

** *** *** * * * i,j,k,a[26] ={0},b[26] = {0};
* *** * * * * * *** *** * = 0 ; i < lenA ; i++)
**** * * * ** * *** * **
** * * *** **** * *** * ** * * * **** * ** = 0 ; j < 26 ; j++)
***** ** ** *** ** * ** * * *** ** * * * **
** ** * **** ** *** * * *** * * * * * *** **** ** * * ** ******* * * == A[i] || 'A'+j == A[i])
* ** * * *** * * *** * ** * * * * * * ***** *** * ** * ** * ** * * *** * * ****
* ***** * **** ***** * ** ****** ** ** *** *****
* * **** ** ** **
**** * *** * * ** * * = 0 ; i < lenB ; i++)
** * ** * * * *
** * * ** ** ** * **** *** ** ** * *** = 0 ; j < 26 ; j++)
* * * * * * ** * ** * * * *** * **
* * ** *** *** * * * * * **** * * * ** * * * ** * ** *** * * *** *** == B[i] || 'A'+j == B[i])
* * ** **** * * * ** ** * * * * * ***** * * ***** * * ** ** * * * * **** ** * ** * * ****** ***
**** * * * * * * ** * ******** * ** * * ** ** *
*** *** ** **
**** * *** * * * * = 0 ; j < 26 ; j++)
* * **** * * ***** ***
** * *** ** *** ** ******* * * * != b[j])
**** ***** * * ** *** ** ** * **** * * ****** ** * ** *** 0;
******* **** ** * * * ***
* * * ** * ** ** **** 1;

}

int main(void)
{
** *** *** * A[100],B[100];
* * * ******** * ***** ** %s",A,B);

* * * * * ** ** (is_anagrams(A,B)) * ** *** words or phrases are anagrams");
* * * **** **** printf("Two words or phrases are not **** *** *

** * * **** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** *
#include * * **** * *
#include * * * *** **
int is_anagrams(char A[],char B[])
{
** * * * * * **** * * *** lenA = strlen(A),lenB = strlen(B),i,j,k;
**** *** *** * * a = 0,b = 0;
* * * *** * ** * * * != lenB)
** * * ** *** * * *** * *** * ***** * * * 0;
* * *** * ** * *** * * * = 0 ; k < 26 ; k++)
* ** * * ** ** **** * ****
** ** ****** ** * * ** ** * ** ** ** * ** * = 0 ; i < lenA ; i++)
** * ** * * * ** * ** * ** **** * **
* * ** ** ***** ** *** ** * * ** * * * * ** ***** ** ** == A[i] || 'A'+k == A[i])
* ** ** *** * ** ** * * ** ** **** * ******* ** * ** * *** ***** * ** * * ***** ***
* ** * * *** ****** **** * * ** ** ** ******
** * * ** * * * *** * * * **** * ***** *** ** * = 0 ; i < lenB ; i++)
* ** *** * * ** * * *** * *******
** ** * ** ** **** * * * ******** * * * ** * * ** * * ** * ** * * ****** == B[i] || 'A'+k == B[i])
** * ** *** ***** *** ** * * * ** ** ** ***** *** * * ** ** * * ** ** ** *
* ** * ** * **** ** *** * ** ** ** ** *** * **
* * *** ** * ** * * * ** ***** ** **** != b)
* * *** * * **** * * * * ** ** * * * ** ** ** * ** *** ** 0;
* *** * * ****** * ***
* * ***** * *** **** *** * * ** ***** ** **** ** *** * * * 1;
}

int main(void)
{
** ** * * * * A[100],B[100];
* ** *** * ** * ** ***
***** * * * * * * *
* * * * ** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * ** * printf("Two words or phrases are not anagrams");

* **** * * * *** *** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ***** *
#include ** ** * *
#include * ** * *
int is_anagrams(char A[],char B[])
{
*** * * *** * * * YOUR CODE HERE*/
* ** ******* * ** *** ** * i,count[256]={0};
* *** **** *** ** * * * * * ** *
*** ** ** * *** * ** *
** * * ** *** ** * * * *** * * ****** * * *** *** * ** * * *
* * ******* *** *** * *
* *** * * * * * ** ** ** **
* * *** * * ** *
* * * * ** * * ** * * ** ** ***** ** * *** ** *** **** * * ** ** **
* ***** * * * * ** * **
/*
* *** * ** * ***** * * * (A[i]!=0 || B[i]!=0){
* * ******* * * * ** **** * * ****** * *** * *** **** ** *
** * * ** ** ** * * * ** ** * *** ** **** * * 0;
* * *** ** * * *** *
*/ * *** ** * **** * *** * ***** **** 0;

* * ** ** * ** (i = 0; i <256 ; i++)
* * * ***** **** * * * * * ** ** * * (count[i] && i!=' '){
** **** * * ****** * **** * *** * * ** ** * * * **** * * * * * *** ** *
*** * *** * * ** ******* ** * *** ***** *** * ** * ** * * * ******* * ** **** * 0;
* * * ** * * ******* * * **** ** *


** * * ** * * * ** ** * 1;

* * * * ** **** OF YOUR CODE*/
** ** * * * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * *** * *** A[100],B[100];
***** * ** * * * * YOUR CODE HERE*/

* ** * * * *** ** ** * ** * ****
*** *** **** *** ** * *** ****

* ***** * ** * * *** = '\0';
  // * *** * = '\0';
* ** ** ** * ***** * ** i;
* *** * * ** *** * * ******** * * ** *
* ***** * * * ** * ** * ** * ** * ** * *** * * ***** * * ***** *** **** * **
* * * ***** * * * * * **** * ** * ** *
* ****** **** **** * * * * * * *
* **** * * *** ** *** * * * * ** ** *** ** *** * * * ** * ** **
* ** * ** * * * ** *** **** * * ***** *** * *

** *** ** * * OF YOUR CODE*/
** **** * * *** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** **** * * * * * printf("Two words or phrases are not anagrams");

** ***** * ** ***** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** ** * **
#include * * * **
#include *** * * *
int *** ** A[],char B[])
{
* ** * *** * **** YOUR CODE HERE*/
* ** ** * ** * * ** * **********
*** ****** ** ** ** ** * *** ** ****** * * *
* * **** * * ** *
* * **** *** ** * * *** * ** *** * *** ** ***
* ** * * *** ** * ******* *** * *** * *** *** ** *** **
*** * ***** * *** *
* * ** ***** * *** (A[i] || B[i])
** * * ** * * ** ** * ** * * * * * 0;

* * * ** ******* * ** (i = 0; i < 256; i++)
** ** * ** ** * ** *** * ** ** ** * * **
* ** ** ** * * ****** * * * * *** * ** * ** * * * * * * 0;
** * **** **** * ** **** *** 1;

* * ** *** ** * * * OF YOUR CODE*/
* **** * * * ******** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *** *
{
***** * * ** * *** *
* ***** * * ** * YOUR CODE HERE*/
* * *** * * * ** **** * * ** ** ** * ** * *
** * * ******** *** * ** **** **** ** *** * ** *

* * * * ** * * * * OF YOUR CODE*/
***** ** *** ** * ** ** *** * * ** ** * ****** words or phrases are ** * * *
* *** ** ** ** * * ** * * ** * words or phrases are not * * **** *

* *** * ** * *** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * *** * *****
#include *** * * *
#include * * ** *** *
int * * A[],char B[])
{
* **** * * ** ** YOUR CODE HERE*/
* ** * * *** * * * ** *
* *** *** * * ** * * *** * * **** * *
* ** * * * ** ***** * ***
**** * * *** **** * * *** * * ** * ** *** *****
** *** * ***** *** * ** * * ** * *** * *** ****
* ****** ** ****
* * ** ** * *** * * (A[i] || B[i])
*** * * ** *** * ** **** ** ** * ** 0;

* * ** * ** * * * * (i = 0; i < 256; i++)
* * * **** **** ** *** ** * * *** * ** **
* ** * ** ** ** **** **** ** * * ** ***** * * * ***** 0;
*** * * * *** * * **** ** 1;

** * * ** * * *** **** OF YOUR CODE*/
** * ** * * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *** *
{
* ** * *** * ** * * ** * *****
** ***** *** *** ** * YOUR CODE HERE*/
*** * * * ** *** ** * *** ***** * * *
**** * * * ** * **** **** ** * * * ** ** **

** * * * ** * OF YOUR CODE*/
***** * * *** ****** * * * *** ** words or phrases are * **
*** * * ******** *** ***** words or phrases are not **** **** *

* * * * * * * * * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.66
©2016-2024

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 1.5k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 2.1k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 1.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users