0 like 0 dislike
17.3k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 17.3k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ** *
#include * ** *** **
#include ****** * *
int * ***** a[],char b[])
{
** ** * * ** ** * first[26] = {0}, second[26] = {0}, c = 0;
***
*** ** ** * * * frequency of * * * in first string
* * * *
* * * * **** **** * * (a[c] != '\0')
* ** * ** * **
* * ** ** ** * * * * * * ****
* ** ***** * * * *** * * * *** * **
** ** * *
** * *
***** *** * = 0;
* ***
* * *** ** * * * (b[c] != '\0')
* ** * ** *
*** * * ** * * *** ******* * *** * * ** * ** * ***
* ****** *** ** ** * ** * * ** *
* ** ** * * * ** * **
****
* * * ****** **** *** Comparing frequency of ** * *

** ** ** ** * * (c = 0; c < 26; c++)
* *** ** ** ** * ***
* *** *** ** *** * * ** * **** (first[c] != second[c])
** * ********* ** * ** ** ** ** ** * ******* ** ** **** 0;
** * * ** * ** **
* *
* * * *** ** ** *** 1;
}

int * *
{
* * * ***** **** * * * *
**** * * * *** * *** *** ** ** * *** * A,B);
** ** ** * * ** ** * ** * * * ** ** * * words or phrases are *** *
* ** ** * * * * * * * *** ** words or phrases are not * * ** *

* ** ****** **** * * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * *** *
#include ******* *
#include * ******
int * *** * a[],char b[])
{
* *** * *** ******* first[26] = {0}, second[26] = {0}, c = 0;
* ** *
** * **** * * * ***** * frequency of characters in first string
** ** *
** * ** * * *** (a[c] != '\0')
* * ***** * * **
** * ** * ** *** * * * ** *** ** ***
* ** * * * * ** * *** *** * *
* *** *** * * ***
* * *
*** * * * ** * *** = 0;
** ****
* ***** * * *** ** (b[c] != '\0')
* * **** ******* * *
* * * * * ** *** ** * ** * * ** * ***
* * *** **** *** ****** *** * *** ** *
**** * ** ** **** ***
** ** *****
* * * * ** * * ** Comparing frequency of **** *
**** ***
**** * ** *** *** (c = 0; c < 26; c++)
**** **** ** ** **
** *** * *** **** * * (first[c] != ** **
* *** * * * * ** * * *** ** **** * * * * * * 0;
* * ***
** * *
* ** *** * * * 1;
}

int main(void)
{
** * ***** ** *** * **** * *
* ** * ** * * * * * ** * * *** * *
* * * **** *** * * * * * ***** ** *** * * * words or phrases are *** * * *
* ** *** * * * ** ** words or phrases are not ** ****

* * ** * * *** * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * *** ** *
#include * * ** ***
#include ** * * * *
int is_anagrams(char A[],char B[])
{
** ******* * * ** * ** YOUR CODE HERE*/
*** ******* ***** * * * *** * * *** * **
*** ** *** * ****** ** * ****** *** *
* ** * * ** * ** ****
** * * ** ** * ** * **** **** * ** ********** ******* * * && ** * ** ** ** **
** ** **** * * * ** * ** *** ** * ***** * *** * *** * * *** * ** *** * ****
*** * * ** ** * * **** ** *** ** ** **** **** ** *** * **** * ** && * * * *** ***
* ****** * *** * * * ** ** *** ** ****** ** ******* * * * **** * * * ***
** * **** *** ** *
** * * * ** ** * *** *
**** **** * ** * * **
** ** * ** * *** *** * * * *** (cA[i]!=cB[i])
* **** ** ** * * ***** * ** ** *** **** * *** * ***** * * ** ** ****** * * ** 0;
**** * * * ** ** *
* * *** ****** *** * * ** 1;
* * * ** * * * OF YOUR CODE*/
* * ** *** * *** *** * function should return 1 if two words or phrases are anagrams,
* ***** * ****** * if two words or phrases are not anagrams.
}

int main(void)
{
** ** ** **** * ** A[100],B[100];
* * ** *** **** *** YOUR CODE HERE*/
* * * * *** * * ** *** ****** ****** **** * *
* * *** *** * **** *** * * ** *
*** ***** * * * * (is_anagrams(A,B))
** *** *** **** * ** * * * * ** *** * * words or phrases are anagrams");
* *** * *** ****** ** **
* ** *** **** * * **** * ** *** *** **** words or phrases are not anagrams");
* * ** * * ** *** **** 0;
** ** *** ** * ** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
*********** ** **** *** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * ****** * * ** ***
* * * * * * * * * * * (A[i] != '\0')
* ** ** * ** *** * *
** *** * ** ** * * ***** * ****** ** *** ******* * ** ***** **
* * ** ** * * ** * ** ******* ** **** * ** ** *
* * ** **** *** * ***
*** * ** ** ** **
* *** ** * * * **** = 0;
** * * * **
*** *** * ** * ** * * *** (B[i] != '\0')
* * * * *** ****** ** *
* * * ** * * * *** ** ** ******* *** ** **** * * **
****** ******* * ** * * * * * * * ** * ** *
* ** * * * * * * ** ***
    
**** ** *** ** ******** * (i = 0; i < 26; i++)
** * ** * ** ** *** **
* * * * * * * * * ** *** ***** * *** (Array1[i] != Array2[i])
** ** ** *** ** * * * * * **** ** ** * ** *** * 0;
** * * ** * ** ** * **
** ** * * * *
* ** * **** ** ** ** ** * ** 1;
}

int main()
{
********** * ** * *** ** **** ** A[100],B[100];

* ** * * * ** **** * *** *** * *
** ** ** * * * * * * * *** *** *
*** * * *******
***** * * * ** * * (is_anagrams(A,B))
* * ********* ** ******
* ** * * * *** ** ***** * * * **** ** * * * * * ** words or phrases are anagrams");
*** ** ** * **** **
*** * ** *** * *** *** printf("Two words or phrases are not anagrams");
*** * *** * * * *
** * * ** * *** ** * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* **** * *** ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
** * ******* * ** **
** * * ***** **** * *** (A[i] != '\0')
* * ***** **** * * * *
* * * *** * ** ** ****** *** * * * *** ** ** *
* * ** ** ** *** ** * *** * *** * ****
* ** * * ** *** * *
* * * *** ** ** * *
* * *** *** ** * ****** = 0;
* ** ** * * ** * *
* * * *** ** ** * * * * * (B[i] != '\0')
** *** * * * * * *
* *** * * * ** *** ** ** * * * * * * ****** * * *
** * **** ** *** * ** * * **** **** *** *** * *
* ****** ** * * **
    
* * * * * *** * ***** (i = 0; i < 26; i++)
**** * *** *** * * ** *
** ** ** * * * * * ** ** * ***** * ** ** (Array1[i] != Array2[i])
* **** ****** ** * *** ** * *** * ** *** * ** * * * ****** ** * * 0;
* *** ***** * ** * ** **
* **** ** *** * *** ***
* * ** **** * * *** * *** 1;
}

int main()
{
*** ** ***** * ** A[100],B[100];

** ** * * * *********** * ** * * ** * * ** *
*** ** ***** * * * ** * ** * * * ** * ***
**** ** * * * * *
**** ***** * ** * * * (is_anagrams(A,B))
* * * * ** * * **
* ****** *** * ** ** ******** * * * * **** ** * ***** * words or phrases are anagrams");
* ***** ** ** * * **
* ** ** * * * * * * ** printf("Two words or phrases are not anagrams");
** * ****** *** ** *
* ****** * ***** ******** *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** * *
#include * ***** * * * **
#include * * * * **** * *
int is_anagrams(char A[],char B[])
{
** * * ** * * * * lenA = strlen(A),lenB = strlen(B);
** ** * * ** * * * * ** != lenB)
*** ***** ******* * ** *** **** ** * ****** **** * 0;

** * * * **** ****** * i,j,k,a[26] ={0},b[26] = {0};
* ****** **** ***** * * * ** = 0 ; i < lenA ; i++)
* * ** * * **** **** ***
* *** * * * ** ** * ** * ** *** * * * ** ** = 0 ; j < 26 ; j++)
*** *** * ** ** * ** * * * ***
** * ** * ***** ** *** ** ** * ** ** * * * ** * *** * ** ** == A[i] || 'A'+j == A[i])
*** *** ** * * ** ** * * * ** * * *** * ** ** ** ** **** ** *** ** *** * *** * * *** *
* * ** *** *** * * **** * ** ** ** **** *
* ** ** **** ** *
** ** * * * ** ** **** * * = 0 ; i < lenB ; i++)
* * ** * ** * * ** * * ****
* ** * **** * * ** * * **** * * * *** ** = 0 ; j < 26 ; j++)
** * ** * * * ** * ** ** * **** ** * * ** *
** ** ** **** *** * *** * ** *** * ** * * * ** * * * ************* ** * *** == B[i] || 'A'+j == B[i])
*** * ** ** *** * * ** *** ******** * ***** **** * * * * * * ** * ** * *** **** * ** * *
* * * ** ***** * ** *** * * * * * ** *
* * * *** * * * *
**** ** ** ** * * * ** ** = 0 ; j < 26 ; j++)
* ** * ** ** * *
* ** **** * *** * * * ***** * * * != b[j])
* ** * ** *** * * ** ** * * *** *** **** ** ***** * * * 0;
* * * * * ** **
* ** ** ** * * *** 1;

}

int main(void)
{
** **** * *** *** *** * A[100],B[100];
*** ** * * * * * ** %s",A,B);

*** ** * **** *** (is_anagrams(A,B)) ** ******** * * words or phrases are anagrams");
* *** * ** *** * * printf("Two words or phrases are not *** ** *

* * * * *** ***** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * **
#include * *** **
#include * ** ** *** **
int is_anagrams(char A[],char B[])
{
** ***** * * * ** * lenA = strlen(A),lenB = strlen(B),i,j,k;
**** ***** * * * * * a = 0,b = 0;
** * ** ** * ** ** ** != lenB)
***** * * *** * * *** ** * * ** * * * 0;
** * * ** ** ** *** * * = 0 ; k < 26 ; k++)
* * * **** * * * **
* ** ** ** * * * *** * *** * * * ** * * *** = 0 ; i < lenA ; i++)
* ** * * **** ** * * * *** * * * ** * * **
*** * * ** * * ***** * *** * * ** *** *** ****** *** * ** * == A[i] || 'A'+k == A[i])
* * ** *** *** * * ** **** * **** * ***** * ** * **** *** * ** * * ** *******
* ** ** * ** ** ******* ** * * * * ** ***
** ** **** *** ***** **** ** ** ** *** * * = 0 ; i < lenB ; i++)
* *** *** ** ** ** ** * * ****** ** *
* **** * **** * * * * **** * ** * *** **** ***** * * * * * * == B[i] || 'A'+k == B[i])
* **** ** ****** *** *** * * *** * * * * ****** ** ***** * **** ***** ** *** * * ****** * *** *
** * * * **** ** **** ***** * ** ** ** ** **
**** *** **** *** ** * * * * ****** ** * != b)
**** * *** * ** * ** * * ******* **** * ** ***** *** *** * 0;
*** * ** **** **** *** ***** * ***
* * * ***** * * * * * ***** *** * ** ***** **** * * * * * ** **** 1;
}

int main(void)
{
* * * ********* A[100],B[100];
* ** *** * ** ** * **
** * **** ***** * * * * *
* *** * * * * *** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * ** * ** ** * printf("Two words or phrases are not anagrams");

* *** ** * *** ** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ***
#include ** ** **** *
#include * *** *** *
int is_anagrams(char A[],char B[])
{
* * ** * ** ** * YOUR CODE HERE*/
* * ** *** * *** * i,count[256]={0};
**** * ****** ******* ** * * *
* * ** ** * ** * **
**** **** * **** * * * ** * * ** * ** *** *** * * **** *** ** * * * ** * * ****
**** * * ** ** ***** *
** *** ** **** * * * **** **
** * * * * * *
* ***** *** ** ********** ******** * * ** ****** * ** * ** ** ** * **
* ** * * *** * **
/*
* *** ** * * * ** * * (A[i]!=0 || B[i]!=0){
******* * ** ** * ** * * * ***** * ***** * * * * * * ** *******
** * * * **** * *** * * * *** * * ** * 0;
*** * ** * ***** * * *
*/ * * * ** * ** * *** * * * *** 0;

*** * * * *** ****** * ** * (i = 0; i <256 ; i++)
**** * ** * ** ** * * * ** ** ** ** * (count[i] && i!=' '){
*** * ** ** **** ** ** ** ** * ** * *** * * **** *** *** ** **** * ** ** *** *
* ** **** *** * * ** * ** ****** * ** * * * * ** * * * 0;
*** *** * ** *** * * ** ** ** * * ** ***


*** *** *** **** * * * * 1;

* **** * * * * OF YOUR CODE*/
**** ** ** * *** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
** ** *** * ** * ** A[100],B[100];
* * * ** * *** ** * YOUR CODE HERE*/

** *** *** ** ** ** **** *** *
***** *** ** *** * ** * *** * ** **

* * ** ** ** * **** * * ** * = '\0';
  // ** * ** ** * = '\0';
* ** *** ** * *** * i;
*** ****** * * * *** * * ** **
* * * ** *** * * * ****** **** **** ****** * * * *** ****** * * ** ***** ** *
* * * *** ******** **** ** * * ****** ** ***** *** *
****** ** *** **** * ** * * ** **
** * ** * *** * * * * * * * * ***** * * * ** ** ** * *** **
* * * * * * *** * * ***** **** *** *****

** ** ** * * * * OF YOUR CODE*/
***** *** *** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * * ******* * printf("Two words or phrases are not anagrams");

** * * * ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * **** * *
#include **** * *
#include ** ** ** ****
int * ** ** * A[],char B[])
{
** *** * ** * *** ** YOUR CODE HERE*/
**** * ** * ** * ** ***** **** *** *
** * **** * * ** ** * * * ** * ** * **
* * ** ** * * *****
* ** * *** * * **** * ***** * * ** * **** ** ** * **
* **** * ** * ** ** * ** * ***** *
* ** * ** *** * * * ** *
* * * ** ** * * * * (A[i] || B[i])
*** * **** ***** ** * * * * * * * * * 0;

*** * * *** *** ** * * (i = 0; i < 256; i++)
***** ** ** **** * * ** ** * * **** **** ** **
* **** ** * ** * * **** * * * * * ****** ** * **** ** * ** *** * **** 0;
* * * *** * * *** 1;

* * **** * ** ** ***** OF YOUR CODE*/
* ** * ** ** *** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
** * ** ** * *** * * * * **
*** ** * ***** * * ** YOUR CODE HERE*/
*** * * ****** * ***** * * * *** * **** * * *
* * ****** * ****** * * * *** ** * ** *

** * * ** * * *** *** OF YOUR CODE*/
* ****** *** * ** *** * ** ***** **** words or phrases are ****** **** *
* * ** * * ** **** ** * ** * words or phrases are not * ********

* * ** * * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** ** * * ***
#include * * * * ** *** *
#include **** * * *** **
int * * * * * A[],char B[])
{
**** * * ** * **** * YOUR CODE HERE*/
* * ***** ** *** * * ** * ** *
******* * * * **** * ********* ***** *****
**** * * * * *** ******
** **** * * *** ** ** * * * * ** *** * * *** **
**** ** **** ** *** * ***** ** ** * * *** ***
** * * *** *** *
** ** ** ****** ***** **** * (A[i] || B[i])
*** * * * ** **** * ** * * * * ***** 0;

** *** * * * ******** ***** (i = 0; i < 256; i++)
* * **** * * * * * * * ** * * * * *** * **** * **** *
***** *** * ** ** * *** ** ** * * ** * * *** ******* ** ****** * ** 0;
** *** *** ** * * * * * * * 1;

* * ** * * * *** * * OF YOUR CODE*/
** *** ** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
* ** * ** * ** ** ***
** * ** * * ** * * YOUR CODE HERE*/
* * *** ** ** ** * *** ***** ** * *******
** ** ***** ** * * * * ** *** *** ***

** ** ****** *** ****** OF YOUR CODE*/
* * * * ****** *** * * *** *** ** *** words or phrases are ** ** * *****
**** ** *** * ** * * * * words or phrases are not * * *** ***** *

* * *** ***** ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.77
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.8k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users