0 like 0 dislike
12k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 12k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ** * * *
#include **** ** *
#include ***** *** *
int *** *** ** a[],char b[])
{
** * ** * **** first[26] = {0}, second[26] = {0}, c = 0;
** *
*** *** ** ** ** * *** * frequency of * in first string
****
* * * ** * *** * * * (a[c] != '\0')
* * * ** ** ** **
** * * * * * *** * * ** * ** ***** * ** ** *** *
***** ** * * ** ** ** *** * **
** * * * **
** **
*** ** ** * = 0;
* ****
** * * * **** ** ** (b[c] != '\0')
* ** *** ** *** ***
** * * *** * ** ** * * * ** ** **** * * * ***
* * *** * ** ** ******* **** * * *
** * ** * * * *
* ***
** * * * ** * * * Comparing frequency of *** **
* ** *
* **** ** * * *** (c = 0; c < 26; c++)
** ** * ** *
** * ***** **** * * * *** ** (first[c] != second[c])
** * * ** * * ** ** *** **** ** ****** ** * * 0;
** * ** ** * * *
*** * *
* * ** * * ** ** 1;
}

int ** * *
{
* * * ** ** * * *** * ** *
**** ** **** * *** * ** *** ** * A,B);
* ** *** ** * * * * ** * * * *** ******** words or phrases are * ** * * *
* * * ** **** ** * ** ** **** * * words or phrases are not ******* **** * *

** *** ** * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * **** * * *
#include *** * *** ** *
#include * **** *** ***
int *** *** a[],char b[])
{
* * * * **** * *** first[26] = {0}, second[26] = {0}, c = 0;
* *
* ** **** * * * *** frequency of characters in first string
* * **
*** * * **** *** * (a[c] != '\0')
* * * * *** ****
* * *** *** * *** * * ** *** * * ** *
** ** * * *** * * ** * * * * *
* * ***** *** *
** * *
* ** ** **** ***** = 0;
*
* ** * ** * **** * * (b[c] != '\0')
** * * * * ** **** *
* * *** ** * * ** * * ** ** ** **** **** **
** * **** ** * ** * **** ******* *
* *** *** * * * * **
* **
* * **** *** * * Comparing frequency of ** ****
***
** * * * ** ** (c = 0; c < 26; c++)
* ** ** ***** **
** *** *** * * * * **** * * *** (first[c] != *
* ** *** ** **** * * *** *** ** ** * **** * * 0;
** ** **
* **
* * *** * **** **** 1;
}

int main(void)
{
* * ** ***** *** *** * ***
** ** *** * ** **** * * * * * * ** * ** **
**** ******** * **** ** ** ** * ** **** * ** words or phrases are ****** ****
**** ******* ** ***** * * ** ** * **** words or phrases are not * ** ***** * *

**** ** *** ** * ** *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * * ****
#include ** *** * * *
#include ** * *
int is_anagrams(char A[],char B[])
{
** * ** ************ YOUR CODE HERE*/
** ** ** ****** *** ** * * ** * ** *** ** *
** **** *** * * ******* *** ** ** * *
* * *** * * ********
* *** * * **** ** ** ** ** * *** * * ***** ***** ** && * *** ** ***** **
** ** ** ** * **** * ** *** * * *** * * * *** * *** *** ** * *** *** * * *
* * **** ** ** ** * ** * * * ** ***** * * ** && * * ** *
* * * * * * * ****** * ** ** ** ** * **** *** *** * ** ** * * ** * *** * *
** ****** * * * ** *
** ***** * * * ** *** *** **** * * ** *
* *** ** *** ** **
* * * * * * *** * * **** ** * (cA[i]!=cB[i])
* * ****** **** * ** ** * ** * ** ** ** * * * ** ** * ** * ** 0;
** * ** * **** ***
***** ****** ** ** ** ** *** ** 1;
** * ** * ** * OF YOUR CODE*/
* ** * function should return 1 if two words or phrases are anagrams,
** * *** * * if two words or phrases are not anagrams.
}

int main(void)
{
***** ** ** ** ** * A[100],B[100];
*** ***** * ** * YOUR CODE HERE*/
** * * ** ** ** * * ** * * * * *** ** *
* * ** ***** **** * * * ** * * * *****
* * * ********* *** (is_anagrams(A,B))
* * * **** * ***** * ** * * * * * * * ** * * ** *** words or phrases are anagrams");
* * * * * * * **
**** ** ****** * * * * ***** *** * *** ** * * * *** **** words or phrases are not anagrams");
* * ** ***** * ** ** ** 0;
* * * * * ** ** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * * *** * * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * ***** *** * * * *
* ** *** * * ** * * (A[i] != '\0')
* ** ** **
*** ** * *** *** *** * ***** ** * * * ** ***
**** *** ** * * **** * **** * * * **** *** **
*** ** **** ** **** ***
** * * *** * *** ** **
*** ** * * * * * ** = 0;
* * * * * ** ** ***
** * *** ** * * (B[i] != '\0')
* ** ** ** * * * ***** *
* * ********* **** ** * * * * ** ***** * **** * * * * ** *
** ** ** **** * * *** * ****** ** *** ** * *
** ** * * * ** ** *
    
* **** * ** * (i = 0; i < 26; i++)
** * ** ***** ** ** **** **
** * * * ** * *** * ***** * ** * ** * ** * * (Array1[i] != Array2[i])
*** * *** * * ** * * ** *** ** * ** * * * ** ** ** * *** * 0;
*** ** * * ****** * *** *
* * ** *** ** ** * * ** ** *
*** * * ** *** ** 1;
}

int main()
{
* ** * * * ** * ** A[100],B[100];

* ** * * * * * ** * **** *
* * * * ** *** * * * *** ** *
** * **** * **** *** **
* ** * * ** ** ** * (is_anagrams(A,B))
*** *** ** * * * ***** *
** *** *** * * *** ** * * * * * * * * ** * * ** ** words or phrases are anagrams");
**** ** **** *
* * * ** * *** ********* printf("Two words or phrases are not anagrams");
** * ** **** * * * *
* *** * ***** ** * * **** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * ** * * * **** **** ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * ** ** * * ** **
* ** * * **** ** * * * (A[i] != '\0')
*** * * * * *** * ** *** ****
** ** * *** * * * * * ** ** * *** * * * * ** ** *
* * * * *** * * ** ** ** ***** *** **
** **** * ** * * * ****
* * *** * *****
* * * * ** *** * = 0;
* ** * * * *****
* * * * ** ** ** * * * ** (B[i] != '\0')
* * *** *** * * * ** **
**** * * * *** * *** * ****** * ** *** ** * *
** ** **** ** *** * * ** ** *** ** * * ** ** * ***
*** ** **** * * ** **
    
*** *** *** ** *** * * (i = 0; i < 26; i++)
* * ** ** * * * * *
*** * * * ** ** * ** * ** * * (Array1[i] != Array2[i])
* * *** * * *** ** * * * ** * * * * *** **** * * * * * 0;
* * * *** ** * ** **
** *** * *** ** ** **
* * * ** *** * * * * *** ** 1;
}

int main()
{
* **** ****** * * ******* *** A[100],B[100];

* *** *** ** ** **** ** ** ***** * **
* ** * *** **** * * *** * * * * ** *
* ** * *
* *** * * * ****** * *** (is_anagrams(A,B))
**** * * ** ** **
* ** * ** * * ** * * * * * * ** * * ** * * * ***** *** words or phrases are anagrams");
***** * * * ***
* ** * * * * *** * ** * printf("Two words or phrases are not anagrams");
***** ****** ** **** *
* ** ** * * *** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** **** *
#include *** * ** **
#include ** * **
int is_anagrams(char A[],char B[])
{
* ** ** * * ***** ** lenA = strlen(A),lenB = strlen(B);
* * * * ** ** ** * * != lenB)
* * * ** * * ** * ******** ****** * ** * *** ** 0;

** * * *** **** * ** i,j,k,a[26] ={0},b[26] = {0};
** ** * ** *** * ** * = 0 ; i < lenA ; i++)
**** ** * *** *
** ** * * **** * ***** ****** ** * * * * * = 0 ; j < 26 ; j++)
** * * ** * * * * **** *** * ** * * * ** * ** *
*** ** * ** * ** *** *** * *** * * *** * * ** ** ** *** * * * ** * == A[i] || 'A'+j == A[i])
** ** * * *** * ** *** * * ****** * ** * * * * *** * **** **** ** * * ** *** * *** ***
* * * *** **** **** ** *** ** * ** * ****
* * * * *
* *** ** ****** * * * *** ** = 0 ; i < lenB ; i++)
* * ** * ** *
*** ******* ******* * * **** * * * ** * ** = 0 ; j < 26 ; j++)
** * ** *** * * ** * * * *** ** * *
* ** * * **** * * * *** * * * * * * * * * *** ** **** * * ** * ** == B[i] || 'A'+j == B[i])
**** * ** ** *** ** * ** * ** * * * * ** ** * * ** ** ** ** * * * ** *** * **** *
* ** * ** * * ** ** **** * * *** * * ** *** *
*** * * ** *** * * * *** * * *
*** *** *** ******** ** * * = 0 ; j < 26 ; j++)
* ***** **** * * *
*** * * * * * * ** * * * ******* ** *** != b[j])
* * *** *** ** * * ******* ***** * * * * ***** ***** * *** ** * ** ** 0;
* * ******* ***** ** **
*** ** ** **** * *** 1;

}

int main(void)
{
**** * * *** * * A[100],B[100];
*** * ***** *** *** ***** %s",A,B);

*** ***** ** * (is_anagrams(A,B)) * ** ** ** words or phrases are anagrams");
* ** ** ** * * * * printf("Two words or phrases are not * * * *

* ** *** * * * * ** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ****** ******
#include *** * **
#include **** ***
int is_anagrams(char A[],char B[])
{
* ** * ** * * *** * lenA = strlen(A),lenB = strlen(B),i,j,k;
* * **** ** * a = 0,b = 0;
* * * * * ****** * != lenB)
* ** * ** *** * ** * * ** * ** ****** * * **** 0;
* ** * * * ******* ** = 0 ; k < 26 ; k++)
* *** ** ** ** **** ** *
* ** * * * * **** ****** * **** ** * = 0 ; i < lenA ; i++)
* ** * *** * * * * ** ** ** * * *** **** **
* * *** * ** * * * * **** ***** * * * * *** ** * **** *** ** * * *** == A[i] || 'A'+k == A[i])
* * * *** ** *** * * * * * ** * *** ** * ** **** * ** * *** * ** *
* * * * ** * **** ** * * * ** * * *
****** * ** * ** **** ** * * *** ** ** * ** * = 0 ; i < lenB ; i++)
** * ** * ***** ** * ******* ** *
** * ** * ** * ** * * * * * ***** ** * * * **** * *** ** * * **** *** == B[i] || 'A'+k == B[i])
* ***** **** *** **** ** ** *** * * * * * *** * *** * * * * * * * ****
* ** * ** ** * * **** * * *** * * * **
* * ** ** *** * ******* ** * * * *** != b)
* *** ***** * * * ****** * * ** * * * ***** ** ** ** ** *** * * * 0;
** ** * ***** * * ** ** ** *** *
* * * * *** *** *** ***** *** **** * ** * * * * ** * ** * 1;
}

int main(void)
{
* *** * A[100],B[100];
***** *** * * * ** * *
* * * ** ******* ** *** * * *
* * * ** *** * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ** ** ** *** * printf("Two words or phrases are not anagrams");

***** * *** * * *** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** *
#include ** * * **** ****
#include * * ** *
int is_anagrams(char A[],char B[])
{
** * * ** * *** ** * YOUR CODE HERE*/
* *** *** ***** *** ** ** *** i,count[256]={0};
** * * ** ** * *** *** ** * * *
*** * ** * *** *
*** * * ** * ** * ** ******** ** * * ***** * * * * * ** * *
* ** **
** * * * *** * * ** * * * *
** ** **** ** ** *** *
* * ** ***** * ** * * ********* *** * * ** * * * * *** ***** *
***** * * ***** * * * *
/*
* * **** * * * * * ** (A[i]!=0 || B[i]!=0){
* *** * **** * * * *** *** * ***** **** ** ** * ** * * * ****
* * * **** * **** **** ****** *** * * * * ** * 0;
* * ** **** *
*/ * ** ** *** * ** * *** * 0;

* * *** * * ** * **** * (i = 0; i <256 ; i++)
*** * *** ** *** ** ** ** * *** * ** * * (count[i] && i!=' '){
* *** *** *** ** * * ** * ***** *** * * *** ** ***** ** * **** ** ** *****
* ** *** * * * *** ** * ** ** * ****** * * ****** * ** * * * * * ** 0;
**** * ** ** * ****** * * * * ** * ** *


* ** * ** * * * * * 1;

***** * * * ****** OF YOUR CODE*/
* ** * *** * * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
*** ** ** **** * * A[100],B[100];
**** * * *** * ** * YOUR CODE HERE*/

****** * * * ** * * ***** * *
** ********* ** * * * * ******

** * * * *** * *** *** *** ** = '\0';
  // * ** * * *** * = '\0';
* * * ** ******* ** i;
* *** ** ** * * ** ** * ** * ***
* * ** * * ****** * * ** ** *** * * *** *********** ** * * ** *
* * * **** * * ***** ** ** *** * *** * * ** *
* * *** * * ** * * * * ** ** *
*** * **** * * ** * **** ** * * * * ** ** ** * ** * * **** * *
* ** **** * * ** * ** * * * * * * *** * * ** **

** *** * * ** * ** OF YOUR CODE*/
* * * **** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * ** ** * ** ** printf("Two words or phrases are not anagrams");

* ** * ** * *** * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** ** *
#include * * **** * ***
#include * * * * * *
int **** * A[],char B[])
{
** *** ****** * ** * YOUR CODE HERE*/
** ***** ***** *** * * ** ***
** * * *** * ** ** ** * * ** **** * **** *** *
* * * **** ** *
* * *** * ****** * ** * * ** * ** * * **
*** * *** * * ** * *** * ** *** ** ** *** * * *
* * * ******** ** ***
*** ** ** ** *** ** * * (A[i] || B[i])
* *** * * * * * ** * **** * ** * 0;

** **** ** ** ******* *** (i = 0; i < 256; i++)
** **** * * ** * * *** **** * ** * * * ** * * * * *
* * ** ******* * *** ***** * * * *** * ** **** * * ** ** ****** 0;
*** * * ** **** * ** ** * * 1;

** *** * *** ** OF YOUR CODE*/
* *** ** * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** *
{
* *** ** *** ** * *
* ******* ** ** YOUR CODE HERE*/
*** * *** ***** **** * ** * * * *****
* * * * *** * ** ***** * * *** **** ****

* **** * ** * ** * OF YOUR CODE*/
*** * ** * * * ** ***** * * **** ** ** words or phrases are * *** * *
*** * ** ** * ** * *** * *** words or phrases are not ***** * * *

* * ** ******** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include **** * * * * *
#include * ** * *
#include * ***** * * **
int * * * A[],char B[])
{
* ** * * * * * * * YOUR CODE HERE*/
* ** * ***** ** ** * ** *** * *****
* * * * *** ** ** ****** * *** ** * ***
*** ** * * * ** ***** ** *
** ***** * *** * **** * ** *** *** ***** *
* ********** * ** ** ***** * * * * *** *** * **** * ** ** * * **
*** * ** *** ** * * *
* ** * ** ** *** **** (A[i] || B[i])
**** * ** ***** ** * ******** * ****** 0;

****** ** ****** ** * * * (i = 0; i < 256; i++)
****** ** * ** ** **** * *** * ** * ** *** **
* * * ** * * *** *** * * * * *** * * ** * * * * **** * 0;
** ** * * * *** ** * * *** * 1;

** * *** * * OF YOUR CODE*/
* *** ** *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * * *
{
* * *** ** *** * * **
*** * ** * * *** * * YOUR CODE HERE*/
* ***** * ** * *** ** ** *** * * ** **
**** * ** ** * ** *** * ** ** **** * * *

** * ** ** * *** OF YOUR CODE*/
* *** * * * * * * ***** ** * * ** ** * words or phrases are * *** * **
** *** ** * * * * words or phrases are not * *** ** *

* *** ** ** * ** ** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.44
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 5.9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.3k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users