0 like 0 dislike
3.5k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 3.5k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include *** * *
#include * * * *** *
#include ***** * ***
int * ****** a[],char b[])
{
* * **** * * ** *** ** first[26] = {0}, second[26] = {0}, c = 0;
***
*** * * * * * * * **** frequency of * * * in first string
****
*** * * * * * *** ** (a[c] != '\0')
*** * * * ** * *
* ** ***** * * ******* * * ** * ** * *** ***
*** ** * *** * *** * * ** ***
* * * *** * * ** * *
*** * *
** ** ** * ** ** * = 0;
*
* * *** ** ******* (b[c] != '\0')
**** ** ** * * *** *
* * ** * * **** * * ** *** *** **
** *** * **** * **** ******** **** ** *
* ********** * *****
* *
** ** *** ** *** Comparing frequency of * ** *
** *****
* ** * ** **** * *** (c = 0; c < 26; c++)
* * * * * * *
* * ** **** * ** * * * * (first[c] != second[c])
* * * ** *** ******* ** ** *** **** * ** *** * * * **** * * 0;
** ** * *** *** **
* * *
* ** ** * **** * ** 1;
}

int * ** *
{
* * * * ** ** * * ** *****
* **** * ** ** * * ** **** * * ** ** A,B);
** ** ** ** *** ** ****** * * * * * **** * words or phrases are ** ** * **
** * * *** **** ** * * * * * words or phrases are not ** *

* * ** ******* 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ***
#include ***** * *
#include * ** *
int ** *** * * a[],char b[])
{
* ** ** * * *** first[26] = {0}, second[26] = {0}, c = 0;
** * *
** ***** * * * * *** frequency of characters in first string
*
** * * * * ***** *** (a[c] != '\0')
** ** ** * * **
*** * ***** ***** * * * *** **** ** ** **
* ** **** * *** ** * * * * ** **** *
** *** **** * * **
** * *
** * ** *** ** = 0;
* *
** * ** ** * * ******* (b[c] != '\0')
* *** * * ** * **
* * * ** **** **** * *** ******* ** * *
* **** * * *** * ******** *** * *
* *** * ***** * ** *
* * **
** * ** * ** Comparing frequency of * *
* *
* *** *** * **** ** * * (c = 0; c < 26; c++)
** ** * ******** **** *
* *** ** ** * ** ****** ** * * * * (first[c] != * **
**** *** *** **** ** * * * ** ***** * ***** * ** ** *** 0;
* * * * *** *** * *
**
* *** * * * ** 1;
}

int main(void)
{
* * **** * ** ** * *
** * ***** **** ** *** * * ** * * * * ***
***** ** * * * **** * *** * * * words or phrases are * **** *****
* *** ** * * ******* ** * words or phrases are not *

** *** **** ***** *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * **
#include * * * * * * ***
#include * *** **** *
int is_anagrams(char A[],char B[])
{
** * * ***** *** ** YOUR CODE HERE*/
* ***** * * ** ** * * ** * **** **
** * * * **** * **** ** * * * * ** ** * * *
** * * * ** * *
* *** **** * *** **** * * * ** * ** ** **** * * *** * * * ****** * && * *** **** ****
***** * *** * ***** * * ** * ** * ** * * * *** * * * ****** * * * ******
* ** * **** ** * * *** *** * ** *** ** * ** ***** * ** * ** && * * ** ** ***
*** ***** ** ** *** * * ** *** ** *** * * * * * * * * * ** * ***** * **** * **
* * **** * *** * *
* **** * * * ***** ** * ** * **** *
* ** * ** * *** ****
* ** **** * * ** * * *** * * ** * ******* (cA[i]!=cB[i])
**** * * * * ** * * * * ** *** **** **** * *** * ** * * * * *** **** 0;
*** *** *** *** * * ***
* ** ***** * * * ****** 1;
****** ******* OF YOUR CODE*/
* * * *** ** ** function should return 1 if two words or phrases are anagrams,
* * ***** ** *** * * * if two words or phrases are not anagrams.
}

int main(void)
{
** * * * * * A[100],B[100];
* ***** ****** * ** YOUR CODE HERE*/
** * ***** * * * * * ** * * ***** * * * ***** **
** * ** * * ** * * *** * *** *** * *
** ******* * * *** * * (is_anagrams(A,B))
* *** * ***** *** * * ** * * * ** * ** * *** ** * words or phrases are anagrams");
* * **** * ***
* *** * * * ** ** ********* * * * ** * ****** *** * ** *** * *** *** words or phrases are not anagrams");
* * ** **** ** *** **** * * 0;
* *** * ** * ** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** *** *** * ** ** *** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
** * ** * * * * * ****
* *** * * ** * ** * * * (A[i] != '\0')
* ** * ****** * *
* * * * *** ** * * ** * ** * * * * * * ** **
******* * * * ** **** * * * *** ***** * ** * * *
*** * ** * *** ** * **
**** * ** *** ** *
* ** * * ** * * * *** = 0;
**** * ** * * **** *** *
* **** ***** * * *** * ** (B[i] != '\0')
* * ****** ** * * ** ***
* *** * * * ** * * ** ** * ***** *** *** ** ***
*** *** ** * ** * *** ** * * ***
* ** * **** * * ** * *
    
** * ** **** * * ** * (i = 0; i < 26; i++)
******* ****** ** *
** * *** ** ** ** * * * * * ** ** ** * ** (Array1[i] != Array2[i])
** * * * ** ** ** ** ** **** * * ***** ** * * * * * * ** * ** * ** 0;
** ** *** ** ***
**** ** ** * * *
* ***** ** * ** ** 1;
}

int main()
{
**** * ** *** * ** *** * * ** A[100],B[100];

* * * * ** ** ** * ** * * *
* * ** * * ** * * * *
* *** * *** * * * * * *
*** ** ** * * ** * ** (is_anagrams(A,B))
*** *** * ** ** **
* * * * ** **** * *** * ** * ***** * * *** * ** words or phrases are anagrams");
**** * ** **** * * * * *
* * * * * * * ** * * printf("Two words or phrases are not anagrams");
* **** ** * * * *
* *** * ** ***** *** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ***** *** **** ****** ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
********* * **
* *** ** * * * * * (A[i] != '\0')
** * *** ** ** *
* * ** * ** ** * * * * ** * * ** *** ** *
* ** * ********* ***** ** *** * * * *
* ******* * * * * *
***** * **** * ** * ***
**** * *** *** * ** = 0;
* *** * *** * ***** ** ** *
* ** ** * * * **** * * (B[i] != '\0')
* *** * ** ** * * ** **
* * * * **** * * * ** * *** ** * * *** ** ** ***
* *** * * * * * * ** ***** ** ***** **** *
** * * ** * * **** *
    
* * ** *** **** * * * *** (i = 0; i < 26; i++)
* ** * ** **** * ** *
** ** ** **** *** * * ** **** ** * ******* (Array1[i] != Array2[i])
**** * ** * * ** ** * * * * * ******* * ** ** * * ** *** * * * **** ** 0;
* ** **** ****** ** * ***
** * ** *** * **
* ***** * * 1;
}

int main()
{
* ** ** ** ****** A[100],B[100];

* * ******* ** * ***** **** * ****** * ** *
** **** * ******** *** ** * ***** *
* * **** ***** ** *
*** *** *** *** * * ** * * (is_anagrams(A,B))
**** * ** * * ******
* ** * *** ** **** * * * **** ** ** * *********** * words or phrases are anagrams");
* * * **** * ******* *** **
******** ** ** * **** printf("Two words or phrases are not anagrams");
* * ** * *** ******* *
** * ** ** * * * ** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** **** **
#include * * ***** ***
#include * * ** **
int is_anagrams(char A[],char B[])
{
* * *** ** * * * ** * lenA = strlen(A),lenB = strlen(B);
* **** * * *** **** ** != lenB)
* **** ** * **** ** ****** ** * **** * * * * 0;

* ** ** *** ** *** **** i,j,k,a[26] ={0},b[26] = {0};
* ** * **** * **** * = 0 ; i < lenA ; i++)
*** *** ****** * *
**** *** *** *** * * * * * * = 0 ; j < 26 ; j++)
* ** **** * *** * ** ** * ** * ** * ** ***
* * ** ** * ***** *** ** * ** ** * * ** ** * ** *** * ** * ** *** * **** == A[i] || 'A'+j == A[i])
*** * *** * * * ** *** * ** * ***** * ** * * * * *** * * * ********* *** ***** * * *
*** ***** ** * ** * ** * ****** * **
* ** * * ** * ** **
**** **** *** *** ** = 0 ; i < lenB ; i++)
* ** ** * ** **** * * * *
* ** * * **** * ***** ** ** * * * **** = 0 ; j < 26 ; j++)
**** * ** ** * ** ** ** * * *** * *
* * **** * * * ** ***** *** *** ** * * ** * * ******* ********* ** == B[i] || 'A'+j == B[i])
** **** ** * * *** * * * ** * * * *** ** ** * **** *** ** * ** ** * * ** * ** * * * * * *
** ** ** * **** * *** * * ****** ******* * ***
* ** * ******** * * * ***
* * * * * * ***** * *** * * = 0 ; j < 26 ; j++)
*** * * * ** ** * ** ****
* * ** ** ** * * * ** ***** ****** **** * * * * != b[j])
**** ** *** ***** * ** **** * ****** * * ** ** **** ********* * 0;
* **** ** **
*** ** ** * **** 1;

}

int main(void)
{
*** ** * *** * A[100],B[100];
** * * ** * ** * %s",A,B);

** ***** ** ** (is_anagrams(A,B)) ** * words or phrases are anagrams");
*** * **** * *** printf("Two words or phrases are not * * *** *

* ** * * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** *** *
#include * * *
#include *** * *
int is_anagrams(char A[],char B[])
{
* * **** *** ***** * * * * lenA = strlen(A),lenB = strlen(B),i,j,k;
* ** ** ** * * ***** * a = 0,b = 0;
* ** ** ** * * *** ** ** != lenB)
*** *** * ** * ********* ** * * * * *** ** * * * 0;
* **** * * * ** ** = 0 ; k < 26 ; k++)
* **** * **** * *
** *** * ** * ** * ** * ** ** *** = 0 ; i < lenA ; i++)
* *** *** ** * * * * * * * * *
*** ** ** * **** * ** ** * **** * * * ****** * ** ** * ** == A[i] || 'A'+k == A[i])
* ** ** * ** ** *** *** * * * ** ** * ** *** * *** * *** * ** * *** ***** * *** *
** * * * ********* ** * * ** ** **
** * *** * *** * * * ** * ** * * * * * * = 0 ; i < lenB ; i++)
***** * * * *** * ** * * * * ** * * ***
* *** ** *** ** * * *** ** * ** * * * ** **** * ** ** == B[i] || 'A'+k == B[i])
* ***** ****** ** ** * ** * **** ** ** * ** * * * * * ** *** **** ********* ** **
*** ** * * ** * *** ****** ** * * ** *
* * **** * **** * ** ** **** * * * != b)
* * * * * * ** * ** * **** *** *** ** * * ** *** * * 0;
** ** ** * * * * *
* * ** * * * * **** * ** ** * * ** *** ****** * * ****** 1;
}

int main(void)
{
** * ** * * *** A[100],B[100];
* ** *** * * * * ** *** *
*** *** *** ** * * *
** *** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * ******* ** * *** printf("Two words or phrases are not anagrams");

*** ** *** **** ** **** * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** **** *
#include ***** * **
#include * ** * * * * *
int is_anagrams(char A[],char B[])
{
** * * * ** * * * * ** * YOUR CODE HERE*/
*** * **** * ***** i,count[256]={0};
* ***** * * * ** ****** * *** **
** **** ***** ***
* ***** ** ** ** * ** * * * * * * ** *** ** * * * * * * * * * * * * *
** ** ** *** **** * *****
* * **** ** * * ** ** * *
* ** * **** * * *
* * * *** ** *** ** *** * ** * * *** ** ** * * ** ******* **
* * ** * ** **** * ** *
/*
** ******** * ** *** (A[i]!=0 || B[i]!=0){
* * * * * **** * * ** *** * * ** ** * ** ** ***** * * * ** **
* * ** ** ** *** ** * * *** ***** * * * ** * * 0;
* ** * **** * *
*/ ** **** * * ** * * *** *** 0;

* **** ** * ** * ** (i = 0; i <256 ; i++)
* ** ** * ****** **** ** ** * * ** * * * (count[i] && i!=' '){
* * * * * ****** * * *** * * * *** ** * *** * ** * * * **** * ** * ** ** **
* * ** * * **** ** * **** ** *** * * * ** * ** * ***** * * * ** ***** 0;
** * ***** * ** ** ***** ***** *** * * * *


* ****** * ****** ********* 1;

* * ** * * * ** ** OF YOUR CODE*/
*** * * * * **** * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * * **** * * A[100],B[100];
*** * *** * *** ***** YOUR CODE HERE*/

* ********** **** *** ** *
*** ** * * ** *** ** * **

** * * ** * ** ** * * * ** = '\0';
  // ** * * ** ** * = '\0';
* **** ** ** **** **** * * i;
* * ** ****** * * * **** ** ** * **** *
* * ** **** ***** * ** *** *** * ******** **** * ** ** * **
*** ** *** ** *** * ** * ** ** **** *** ***
*** * * ** ** * * *
**** ** ** * *** ** *** ****** *** * ** ** * * ** ** ** ** * * *
******* * * *** ****** ** *** * *** * ** *** *** **** *

* * * * * ***** OF YOUR CODE*/
**** * ***** * **** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
**** * ** ******** * * * * printf("Two words or phrases are not anagrams");

* * * *** ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** ******
#include ** ** *
#include * ** *** ** *
int ***** * ** A[],char B[])
{
* *** *** * * ** YOUR CODE HERE*/
*** * ** **** **** ** * * ***
* * ***** **** ** **** ** * * **** ** * **
* ** ** * * ** *
** ** * *** * ***** * ** *** ** ** * * *** *****
* * ** *** * * ** * * ** * * * ** * * * **** ***
* ** **** ** ** ***
* ** * *** **** *** (A[i] || B[i])
**** * * * ** * ** * ** * * * * 0;

* * * * ** * ** *** ** * ** (i = 0; i < 256; i++)
* * * * **** **** * * * * * * * ** * * *** * * *
** ***** * * * * *** ** * ** * * *** * * * **** *** ** * ** * * ******* *** *** 0;
** * * *** *** ** ** * 1;

* ** * ** ** * OF YOUR CODE*/
* * * **** ** **** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * * * * *
{
* **** **** *** * * **
** ****** ** ***** YOUR CODE HERE*/
* **** * ** ** ** *** * *** * * * * ********
* * * * * * * ** * * **** ** *** * * **** *

* **** * ** ** OF YOUR CODE*/
** * * ** * ** * ** * *** words or phrases are **** * * * *
* ****** ** **** ** * words or phrases are not ********

**** * * * * * * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * ** *
#include * ** ** ****
#include ** * *****
int * ** *** A[],char B[])
{
**** ** * *** ** ** YOUR CODE HERE*/
* * * ** ** * **** * * * * * *
*** **** *** * * * * * ***** *** ** **
* *** * ** * * ** *
* * * **** * * * * **** * *** * * ** ** * **
************ ** **** * *** *** * ** ** * * ** *** *
** *** ** ** ** ******
* ***** *** * * ** ** (A[i] || B[i])
** * * * *** ******* ** ** **** * ***** * **** 0;

** ** *** ** ** * *** ** * ** * (i = 0; i < 256; i++)
* * ***** *** *** * * ** ** * ****** * ** *
* * **** ** * ***** * * **** ** * ** ** ** * ** **** * * * * * *** 0;
** ** ** * ** ****** ** * 1;

** * ** * * ** * ** * OF YOUR CODE*/
* ** * * * * * *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int **** ***
{
* * ***** ** ** * ** **
** * **** ***** YOUR CODE HERE*/
* ** *** * * * ** * * * * *** ** * * *** *
* *** * * ** ** ** ******

* ** ** * * * OF YOUR CODE*/
* ** ** * * ** * * * *** * *** * * * words or phrases are ** ** ** *
* *** *** * * * ** * ** words or phrases are not * ****** *

* ****** ** ** * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.171
©2016-2024

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 1.5k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 2k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 1.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users