0 like 0 dislike
12k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 12k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * **** **
#include * ** * * *
#include ** * *
int * ** ** * * a[],char b[])
{
* *** * ** * * first[26] = {0}, second[26] = {0}, c = 0;
*
**** ** * * * ** * frequency of **** in first string
* **
**** **** * (a[c] != '\0')
* * * * **** ** *
* * ** * * *** * * * * **** ** ******* *
** ****** * * ** * ** * *
** * * * *
* *
** * * = 0;
****
* ** * ** * * **** ** * (b[c] != '\0')
** *** * *** ** **
* * **** * * ** * ** * * ** **** * **** *
* ** *** * * ** ** ** * * *
* *** ** ** ** *
* *
** ** ** ** *** *** Comparing frequency of * * *
** *
* *** * *** ** * (c = 0; c < 26; c++)
* * ** * * ***
* ** * * * * ** * * * * * * * ** (first[c] != second[c])
** * * ** * * ** * ** ** ** * * * *** * * ** ** 0;
* ** ** * * ** ** *
* * **
** * ** * **** * ***** 1;
}

int
{
*** ** *** * * * * * * *
* ** * ** * * * * *** ** *** A,B);
** ** ** ** ** * * * ** * * ** * ** ** words or phrases are * * ** *
* *** * * **** * *** **** * ** words or phrases are not * **** *

* * ** **** * * ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ********
#include * * ** *
#include * **** *
int * * * a[],char b[])
{
* ** ** ** **** first[26] = {0}, second[26] = {0}, c = 0;
* *
** *** *** ** ******** ** * * * frequency of characters in first string
*
* * * * * * * **** (a[c] != '\0')
** *** ** * *
**** *********** * ** **** * * * **** * ** * **
* * * ** ** * * ** ** **
** ** ***** *
* *
* ** ** ** * ** * ** = 0;
* **
* * ** *** * * * ** (b[c] != '\0')
* * ** * ***
* **** * ** * * ***** * ** * * * **
**** ** ** *** * ** *** * ** *
**** ** * ** ** *
* *
* * ** ** * * ** Comparing frequency of **
* * ***
**** * * * ** **** (c = 0; c < 26; c++)
** *** ****** * *
** ** * *** * *** * * *** * * * (first[c] != ** * **
* *** * **** *** * *** * ******* * * ** * ** 0;
** *** ***
* ** *
****** * * **** * **** 1;
}

int main(void)
{
* * * * ****** ** * * * **
** * * **** * ** * * * ** ** ** ** ***** *
* **** *** * * * * ** *** ** * ** words or phrases are * * * * * *** ***
* * * *** *** * ** * * * * words or phrases are not ** * * *** **

* * ** ** * ****** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** *** * ***
#include * ** * *
#include ** ***** * *
int is_anagrams(char A[],char B[])
{
* ****** ** * ** * YOUR CODE HERE*/
** *** * * *** * ****** **** * * * **** ***
*** ** *** ******* * * ** * ** ** ******
** ** * ******* * ** *
* *** ** *** * ** *** * * * ******* ** ** *** *** *** * ** && * * * *** *
* ****** ** **** * * * * ***** * **** **** * * * * ** *** * * * * * * ** **
* ** * * * * ** * *** * ** ** **** * * * * **** ****** *** ** * * && * ** * * **
* * * ** * * ***** **** * ** * * * ** * * * ** *** * **** *
** ***** * * *
* *** * **** ** ** * * * * * *
*** ** *** * *** * ** * * *
* * * * ** ***** * ***** ** * ** **** ***** (cA[i]!=cB[i])
* * * * ** * * * * **** * * *** * * ***** * ** ** * ** ** * 0;
** ** ** * *** **** *
** ** * * ** * ** *** 1;
* *** * * * * * OF YOUR CODE*/
** ****** * function should return 1 if two words or phrases are anagrams,
* * * * * * if two words or phrases are not anagrams.
}

int main(void)
{
* * * * * * A[100],B[100];
*** *** * **** * * * YOUR CODE HERE*/
* ** ** ** *** * * ** * ** * ***
*** ***** * ** ** *** ** * * * ** **
* **** **** * *** * *** (is_anagrams(A,B))
* ****** * * * * **** * ** ****** ** * ** * ** ** * * words or phrases are anagrams");
** * * * ** *** ***
** * * * **** **** * *** * * * ** ** * * ** words or phrases are not anagrams");
* * * * **** *** * 0;
** * * *** * ** **** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * ** * ** * ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * ** *** * **
* * * * * * * * (A[i] != '\0')
* * * *** **
***** * ** * * * * * * ** ** * * * * * ** **** ********
* * * * * * * ** * **** *** * ** ** *
* * * **** ** *** * *
*** *** * * ****
* ** ***** * * ** * = 0;
* * ** ** * * **
* * *** * **** * ** ** (B[i] != '\0')
**** **** * ** ** *** **
* * * * ****** * **** **** * * * *** * ** ** *** **
* * ** * ** * * ** ** ** * * *** * *** *
******** ****** * *** *
    
* * *** ******* * * * * ** (i = 0; i < 26; i++)
** ** * * * *** ** *
* * *** * * *** ** * ** *** * ** * ** ** * ** (Array1[i] != Array2[i])
* * ** * ** * * ** ***** ** ** ** * * ** * ****** ** *** 0;
*** * ***** ** **
* * * * **** *
* * * * * ** * ** ** 1;
}

int main()
{
* * * ****** * ** * *** A[100],B[100];

* ** *** **** *** ** ** **
* ** * ** * * ** * * * ** * * ***
** ******* ** **** ****
*** **** * *** ** *** * (is_anagrams(A,B))
*** * * * ** * *
* * ** ** * ** ***** * * * *** * ** **** ** * * * ** *** words or phrases are anagrams");
***** * **** **
** ***** * * ** **** ***** printf("Two words or phrases are not anagrams");
* ****** * ** **
* * **** ** * ** * *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* *** *** * * * ***** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * *** ** * * **
* * ** ** ****** ** * ** * (A[i] != '\0')
** * * * ** ** *** * *
* * ** * * * * ** ** ** ** * * ** * * * * *** *
* * * * * * **** * ** ****** * *** * *** **
* * * * ** **** * * *
*** ** **** ** ** ***
* * * ** **** * ** ** = 0;
** * *** * * *
** *** * ** * ** **** ** ** (B[i] != '\0')
* *** ****** * * * ** *
*** * ** *** * * ** ** * ** * * ** ** * * * ** ***
** *** ****** **** ** * * * **** **** ****** *
** * * * *
    
*** ** *** * * * *** * (i = 0; i < 26; i++)
* * * *** * * **** *** ****
*** ** * ****** * * ** * *** ** ** (Array1[i] != Array2[i])
** *** * * * * ** *** ** * ** * * ******* ******* ** ** *** * *** ** * * 0;
* * * ** * * * ** ***
* * * * * ** ** *
* ** ****** ** * * ** ** 1;
}

int main()
{
* *** ** ***** * *** ** ** A[100],B[100];

* * *** * * ** ***** ** * * *** ** *** * *
***** *** * ** ***** * * * *** ** *** ***** *
* * ** * * * * ***** *
* * * * * * ** * ** * (is_anagrams(A,B))
** *** * ** * ***
***** **** * ****** ****** * ** *** * ** ** words or phrases are anagrams");
* * *** * ***** * *** *
** ** ******* * * printf("Two words or phrases are not anagrams");
* **** ** ****** *
* * ** **** ** ** * **** * **** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** * * ** ***
#include ****** **
#include * ** ** * * **
int is_anagrams(char A[],char B[])
{
***** ** ** * * * ** *** lenA = strlen(A),lenB = strlen(B);
* * * * * ** *** *** * * != lenB)
** * ** *** * * **** * * * * **** * * ** * 0;

* * ** *** *** ** * * i,j,k,a[26] ={0},b[26] = {0};
** * *********** **** ** *** = 0 ; i < lenA ; i++)
* *** * * * * *** *
* *** ** * * * ** * * * * ***** ** = 0 ; j < 26 ; j++)
* * * * ** *** ** ** * * * *** ***
***** ** * ***** * * * *** *** **** * ** * * * ** == A[i] || 'A'+j == A[i])
* ** * **** * * ***** ***** * * * * ** * * * * ** ***** *** *** * * * * * * **
* ***** *** * *** * * *** * * * * ***
* *** ***** ** * * * * **
* ** *** ** ** *** ** * ** ** = 0 ; i < lenB ; i++)
* * * *** **** ** *
* ** *** * **** ** ** * *** ***** * ** = 0 ; j < 26 ; j++)
* * * * *** * * * * * * * * *** ** ** ***** *
* **** * ***** ** ** * *** ** ** * ** * * *** * ** ** **** ** ** == B[i] || 'A'+j == B[i])
* ** *** * **** ** *** ** * ** ** *** * ** * ** ** ** * * * * * *** * * *** *
* * * **** ******** *** * ** ** * * * *** *
***** *** * * * ** * * **
* ** * * ** ** ** * * = 0 ; j < 26 ; j++)
**** *** * ** ** * **
*** ** ****** *** ** * * * *** * ***** *** * != b[j])
* * * *** * *** * ** * *** ** ** * * * * * * * ** *** * **** ** 0;
* * ***** ** * ***
*** *** **** * * * **** * 1;

}

int main(void)
{
*** ** * * * * *** ** A[100],B[100];
* * * *** * ** * **** * %s",A,B);

*** * ** ** ** (is_anagrams(A,B)) **** * * * words or phrases are anagrams");
*** ***** * printf("Two words or phrases are not * * ** *

* ** *** *** *** ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *** ** *
#include *** *** ** *
#include * **** * *
int is_anagrams(char A[],char B[])
{
****** * * * ** ** * lenA = strlen(A),lenB = strlen(B),i,j,k;
* **** * **** **** *** a = 0,b = 0;
*** ** * * **** ** * ** * != lenB)
* ** * * ***** * ** **** ** ** *** *** *** * ** 0;
*** * * * * * ****** * **** = 0 ; k < 26 ; k++)
* * ** ** ** * ** *** **
*** ** * * ** **** *** ** * *** **** ** **** * = 0 ; i < lenA ; i++)
* ** ** * * *** ** **** ** ***** ** ** *** * *
** * ** * *** *** **** * * ** ** ** *** ** *** * * *** * * * == A[i] || 'A'+k == A[i])
** ** ** ***** ** *** * * **** * * ** * * * ** * ** * * * * *** * ** *** ** *** ** ***
* * * * * ** * *** * * * * * ** * * * **** **
*** * * * * * * ** * * ** ** * * * **** ** * = 0 ; i < lenB ; i++)
** **** *** *** *** * * * * ** * ** *
** ** * * * ** * *** *** *** ** ** **** * * *** * ** *** ****** * == B[i] || 'A'+k == B[i])
**** **** ******* **** * * *** **** * ***** *** ***** *** ** ***** ** ** * **** * * **
* * * * ** * * ** * * * * *
* * *** ** * * * ******* * **** * * **** != b)
* ** * ** * ** * * ** * ** ** ***** ** * * ********** * ** * * 0;
** * * ** * * *** **
*** * * * ** * ** * *** * ** ** *** ***** * *** ** * ** *** * * ** ** 1;
}

int main(void)
{
* * * ** ** ** * ** * A[100],B[100];
** ** * *** ** * ** * * * *
* * ***** ** * ** ***
* ** *** * * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * *** * printf("Two words or phrases are not anagrams");

* * * ** *** * ** * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** * **
#include ** ****** *
#include * * * *** **
int is_anagrams(char A[],char B[])
{
**** ** * * ** ****** YOUR CODE HERE*/
*** ** * *** ****** * * i,count[256]={0};
** * ** * ** *** * * * **
****** ** * ** * *
* ** * ** * **** * ** ** **** ** *** * ** * ** ** * *
* * * ***** *** * *** * **** *
* *** * * ** **** * *** ** * *
* *** *** * * ** ***
* * ** * * ** * * *** * *** * *** * * **** * * ** * **** *** * * * * * *
** ************** ** **** *
/*
* * * *** * ** * ** ** (A[i]!=0 || B[i]!=0){
**** * *** **** * ** ** * *** * *** * * * ** * * * * * *
* **** ** * * * *** ***** * ****** * * **** * * 0;
* * *** * * ***
*/ **** * ** **** *** * *** **** 0;

* ** * ** *** *** * ** * (i = 0; i <256 ; i++)
** * * * *** * *** * ** ** * * ** * ** (count[i] && i!=' '){
*** **** ***** * **** * ** * *** ** ** * * * * * * **** * *** * **** ** * * * * ** * * ** *
* ****** *** *** * * * **** * *** ** * * *** * *** * * ** ** *** 0;
* **** * * * ***** * * ** * * ** ** **** *


* * * ***** * * * *** 1;

*** * *** *** * OF YOUR CODE*/
** * ** ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* ****** ** **** A[100],B[100];
* ** ** *** ** *** *** YOUR CODE HERE*/

* * * ** * * * * ** ** ** ** *** *
* * * **** * * ** **** ** * **

** ** *** *** ** = '\0';
  // **** * * ** * * = '\0';
** *** *** ** ** i;
* *** * * * ***** *** * ** * ***
* ** ** ** ****** * * ** *** *** **** * ** * * * ** ** *
**** * ** ** * ** *** **** * * ***** * * * ** ** * ***
** * * * ** *** * * *** * * *** *
*** **** *** **** * * ** ** ** ** ** * *** ** * ** * * * ** * ** **
* *** ** ** ** * ** ** ** * * ***** * * *

** ******* ** *** ** OF YOUR CODE*/
**** ** ** * *** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * * **** *** printf("Two words or phrases are not anagrams");

*** * * * *** ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * *
#include * * ** * * * *
#include ** * * *
int * * **** A[],char B[])
{
***** **** * * ** YOUR CODE HERE*/
** **** ** ** * * *** ** * * *
** * * ** **** * * **** ** * *
* * * ** * * ** * *****
** *** * *** * * *** * * * * ** * * *** ** * *
** * ** * *** ** * ** * * * ** ** * ****
** * **** **** *** *
* *** ***** ** *** ** ** (A[i] || B[i])
** * * *** *** ** * ** ** ** ***** * 0;

***** * ** ** (i = 0; i < 256; i++)
* **** ** **** * * ** ** **** ** *********** ** * ** **
**** * * * *** *** * * **** * * ** * **** ** *** * * * ** ** 0;
* * *** * ** ** 1;

** * * * *** OF YOUR CODE*/
* * * ** ** ** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * ** *
{
* *** ** * * * * ***** **** ***
** * ** ****** * * **** YOUR CODE HERE*/
* **** * ** ** * * * **** *** * ** * **
* * * * * *** * ** ** *** * * ** ** **

** * ** * *** ** OF YOUR CODE*/
***** * ** *** * * * * * * ** * * * words or phrases are ** *** ** ** *
** * * * **** * ** ** * *** words or phrases are not * *

*** * * * ** * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * **
#include * ** ** * * ***
#include * *
int ** * A[],char B[])
{
** ** * ***** * * * *** YOUR CODE HERE*/
* ** ** * * * ** *** *** * ** *
**** *** ** * ** * ** * *** *
* * * * ****** * ** * **
******* * * * * * * **** * * ** * ***
* *** * * * * **** * * * ****** * ***** * *********** ** *
* * *** * ** **
* * ** ******** * * *** ** (A[i] || B[i])
* * ** ** ** * * *** *** ** ** 0;

** * *** * * * * * * * (i = 0; i < 256; i++)
** * ** * * * **** ****** * * *** ** * *
*** ** * ** * * *** ** **** * * * * ** * * * * ** ** * 0;
* * * ** * * * * * ** 1;

** * * * * * * OF YOUR CODE*/
* ** *** * ****** *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int **
{
*** ** * * ** **** *
* * * *** * ** * YOUR CODE HERE*/
*** * ****** * ** *** ***** * * ** *** * ** *
* * **** ** * * ***** ** ** * * **

*** *** * * * OF YOUR CODE*/
******* * ** * * ***** * * *** ** *** words or phrases are **** **
***** ***** *** **** * ** * * words or phrases are not ** * *** **

**** ** *** ** * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.74
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 5.9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.3k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users