0 like 0 dislike
7.4k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 7.4k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * ** ** **
#include * ** * ** * **
#include * * ****
int ********* * a[],char b[])
{
* * ** ****** * first[26] = {0}, second[26] = {0}, c = 0;
* ***** *
* * **** * ** *** * ** * frequency of * * in first string
*
* *** * * *** * ** (a[c] != '\0')
*** **** * *****
** * **** * ****** * * * ** ** ** * * **
* * ** * ** * ** * ***** * *
* ******* **** ** **
*****
* ****** ** * ** * = 0;
******
****** * * ** (b[c] != '\0')
* * * * * ** *
* * *** * * ** * * ** *** ** * * **
* ** **** **** ******** ** ** ** * **
*** ** * *** * **
* *****
** ** ** * ** ** Comparing frequency of **** *
**
* *** * * * (c = 0; c < 26; c++)
* *** ** * *****
** * **** ** * * ** * ** **** (first[c] != second[c])
*** * * * ** * * * * ** ** *** * * ** * *** * 0;
* ** ** * * * * * *
****
** * **** ** * **** 1;
}

int ** **
{
* ** ***** *** * * * * ** ****
** ** **** * ******** ** * * A,B);
* **** * * * * * * ** * * words or phrases are ** ** *
* * ** * * ** * * ** *** words or phrases are not * * **** ***

** *** ** * ** ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * *
#include * ** * * **
#include * * * ** **
int ** ** * a[],char b[])
{
* * ** * ** **** first[26] = {0}, second[26] = {0}, c = 0;
****
**** * ***** *** * ** ** * * frequency of characters in first string
* * **
** ** * * **** * * * (a[c] != '\0')
********* *** *
** ** *** * ** * * ** * * * * **** * *** *
** ** * * * * * * **** ** * ** ***
****** * * ****** *
* * **
***** *** *** = 0;
*
** ****** * *** * ** (b[c] != '\0')
** * * * **** * *
* * * * * * * ** * * * **** ** * * **
** *** * *** ** * **** * * * * *** *
*** ** ** **** * **
** **
*** *** * * * Comparing frequency of *
******
** * ** * ** (c = 0; c < 26; c++)
* **** * ** ** *** *
****** * * * * ** ** **** * * (first[c] != **** * *
** * **** * *** * ** **** ** ** * * **** **** * * * * 0;
** * ***
* * *
* * **** *** ** * * * 1;
}

int main(void)
{
* ******* * *** ** ** *
* *** ** * * * * * ** * *** * * * ** *** *
* ** ** * * *** * * **** words or phrases are *** ***
** ******* ** * *** * words or phrases are not ** ** * **

* ** *** ** ****** * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** ** ** * *
#include * *** * * **
#include * *** * * *
int is_anagrams(char A[],char B[])
{
* * * ** *** * ** ** * *** YOUR CODE HERE*/
* * ** * * * * * * * **** *
** **** *** ** * * *** * * * * * ****
* * ** ** * * *** * **
** * ** ** ** **** ** * * * * ** * * * * *** && **** * ** **
*** * * *** ***** ** **** * * *** * * *** ** * ***** ***** * * *** * * *** * * ***
** * *** ** ** * ** * ** *** * *** * **** **** ** ** * *** ** && ** ** *** *
** ** * * * ** * * *** * * * *** ** * * ** ** * * * * * *
* * * * * * ** ***
*** ******* * * * ** *** * * ** *
*** ** ** *** ** * **
** * * * * * ** * * * ******** * ** * ** *** * (cA[i]!=cB[i])
*** ** ***** *** ** ** * * * * * ** ***** * * * * **** **** * ** * * 0;
** * **** ** ****** *
** * ** * * *** ** * ** * 1;
* ** ***** *** * ** ***** OF YOUR CODE*/
**** ** * * ** function should return 1 if two words or phrases are anagrams,
* ******* if two words or phrases are not anagrams.
}

int main(void)
{
** * ** * * *** * * * A[100],B[100];
***** * *** * *** * YOUR CODE HERE*/
* **** * ***** * * ** ** * ** ** *** ** *
* * ** * ** * * ** * * ** **
* ****** **** *** ** (is_anagrams(A,B))
* ** * * * ** * *** ****** ** *** * **** * * * * ***** ** * * words or phrases are anagrams");
* * * ** *****
**** ** ** ****** * * * ***** * * * * * ** *** * * *** words or phrases are not anagrams");
* ****** *** ***** ** * * * 0;
** * * *** ***** ** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** ** ** ** * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ******** *
** **** ** ** * *** (A[i] != '\0')
** ** ** ***** * *** *
* * *** *** * * * ****** * *** ** *** * * * * * *** *** * *
** ** ** ***** * * * * ** * * * * *** * *
** *** *** ****** * * * **
** * ** **** ******* ****
* **** * ** ** ** * ** = 0;
* * *** ** ***** ** *
* ** * * *** * * ***** (B[i] != '\0')
** * * ** ****
* * * * ***** *** **** ** **** * ** *** ** ** * *** * ******
****** * * ****** * ** ** ** **** ** * * ***** *
**** * * * ** * * ***
    
* * ** * ** ** * ** * (i = 0; i < 26; i++)
****** ** ***** *** *** *
******** * * * * ** *** **** *** * * ** ** (Array1[i] != Array2[i])
* * *** * *** * ** * * * * * * * * **** ***** **** * * * * 0;
* **** * *** * * *
****** ** * ** * * *
* ******* * *** *** * 1;
}

int main()
{
** ** *** ***** * * ** * * A[100],B[100];

** * * ********* ** * *** **
* ** * ** ** ****** ****
* * * ** ** *
* *** * * * **** * * * (is_anagrams(A,B))
** * ** * **** * **
* ******** * * * *** ** * * * * * ** ** ** ***** * words or phrases are anagrams");
** * * * *** **** *
* ** * * * ** * **** printf("Two words or phrases are not anagrams");
* * * * * * * **
*** * * * * * * ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** ** **** *** *** * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* *** * * **** * ****
* * **** *** * **** * * (A[i] != '\0')
* * * * * ***** **
*** ** * ** * * ** * ** * * ** * ******* ** * ** ** * *
* * *** ***** * ******* **** ** ** * * ** * *
* ** ** **** ** ** ***
* ** ** * ** * * **
**** * * * ** * ** *** = 0;
**** * ****** ** ** **
** ** *** * * ** * * (B[i] != '\0')
** ** ** *** *** **
*** ** * ** * ** **** * * ** * ******* ** * ** * *
** **** * ** * ** ** * * * *** * *** ***
* *** * * * **** * *
    
* ** * **** * * * ** * * * ** (i = 0; i < 26; i++)
* ** **** ** ** **
*** * * **** ** * *** *** * **** ** * * * *** ** (Array1[i] != Array2[i])
***** * * ** * ** * * * * ** *** ** **** ** **** * ** ********* * * 0;
* ** * * ** ** * **
*** * ** * * * *
* * * * * * **** * 1;
}

int main()
{
* *** *** * ** * ****** * A[100],B[100];

**** ** * * * * * * ** ** * *** * ** *
****** * * * ** * ** * ** ** * * * *
** ** * *** * *
*** * * *** ** ** * * ** ** (is_anagrams(A,B))
* * * ** ** ** ** *
*** * * ******* ** * * * ***** * * * *** **** ** words or phrases are anagrams");
* * * ** * * ** ** ** * *
******* *** * *** * **** * printf("Two words or phrases are not anagrams");
** * **** * ** * * *
***** * * * * **** * * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ****** **
#include * ******* *
#include * **** *
int is_anagrams(char A[],char B[])
{
*** ** *** * * ** ** lenA = strlen(A),lenB = strlen(B);
** * * ** * ****** ** != lenB)
*** * * * * * **** * ** * * * * * * * *** *** 0;

*** ** * * ***** * **** i,j,k,a[26] ={0},b[26] = {0};
**** ** ** ** * ****** * = 0 ; i < lenA ; i++)
*** ** * * ***
**** * ** * * * * * ** * *** * *** * ** * * = 0 ; j < 26 ; j++)
* ** ** * ****** * ***** * * * *** * * * * *
* ** ** ** * * * ** * *** * *** *** ** * ** *** * * **** ** *** * ** == A[i] || 'A'+j == A[i])
* ***** ** ** * ** * **** * ***** ** ** **** * * *** *** * * * * * ** * * *
** ** * * * *** * * ** * * * ** * ** ***** * * *
* * * * ** * * *
* * * * * *** * * *** * * * * = 0 ; i < lenB ; i++)
** * ** ** *** * * ***
*** * *** * * ***** * *** * *** ** * * * * = 0 ; j < 26 ; j++)
* ** * * * *** * ** **** * * * *** ** * * *
* ** * *** * ** ** * * *** * *** *** * * * * *** *** ** * **** ** == B[i] || 'A'+j == B[i])
* ** * * * ** * **** ** * *** *** * * ****** *** *** * *** * ** * * ** * * *
** * * ** *** * *** * ** ***** ****** * * ***
** *** * *** ** * * * *
* *** * * ** ** * * * * = 0 ; j < 26 ; j++)
*** * * ***** ** * *
* * ** * * **** * ** * *** ** ** ** ** != b[j])
* * ** **** * *** * ** * * * * * ** *** ** ** * ** * * ** **** 0;
* *** *** ** **** **
* * * * ** ** * * ** 1;

}

int main(void)
{
****** * *** *** ** A[100],B[100];
** * ** * *** * ** * * ** * %s",A,B);

* ** ** * **** * * (is_anagrams(A,B)) * * * * words or phrases are anagrams");
* ***** * * **** * printf("Two words or phrases are not * * * *

* *** ** ** ** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ***** **** *
#include * * * ** ***
#include * * * ****
int is_anagrams(char A[],char B[])
{
* * *** * * * * lenA = strlen(A),lenB = strlen(B),i,j,k;
*** ** ***** * **** a = 0,b = 0;
* ***** * * *** * != lenB)
** *** ** * * ** * * *** ** ** * * * ******* *** 0;
** **** ** ** ****** ** *** = 0 ; k < 26 ; k++)
* * * ** ** * ****
** * ** *** * * * * ** * * ** ** * ***** ** ** = 0 ; i < lenA ; i++)
* * * *** ******* * *** * **** **** * **
** * * **** * * * ** *** * * *** *** * * * * ** * ** ** * ** ***** * *** * == A[i] || 'A'+k == A[i])
* ** * * * ** * *** ** * * * * ** * ** * ** ** *** ******* * ******** ** ** ** ** * * * **
* * * *** * ** * * * *** * ****** * *
* * **** * ***** * ***** * * **** * * ** * = 0 ; i < lenB ; i++)
* * * * * * * *** * *** * *** *
** * ********* * ** ** * * * * * * * ** * *** *** ** ** == B[i] || 'A'+k == B[i])
** ** * ** ** ** * ** ** * ****** **** * * * ** ** **** * * ** * * * ** *** * * ****
* * * ** **** * * * ** ***** * * **** * ** *
* ***** **** * ** * ** * ** ** ** ** ** != b)
* * *** * ** *** ** ****** ** *** **** * * * ** * ** ** 0;
* ***** * * ** ****
* * * * ** ** * ** ******* **** * * * * * ******** * ***** ** * ******* 1;
}

int main(void)
{
** * * * **** A[100],B[100];
* ** ********* * ** ******
* ** * ** *** ** * * **
* * * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ** ** **** ** * * printf("Two words or phrases are not anagrams");

**** * * **** * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * **
#include * ** * *****
#include * ** ****
int is_anagrams(char A[],char B[])
{
** * * ** * ** * YOUR CODE HERE*/
** ** * ***** * **** * i,count[256]={0};
* **** * *** * ** * **** *** ****
* * * * * ** * *** **
* ** *** * * * ********* * ** * **** ** * *** *** * *** **** *** * *
* * ******* * *** * *
** ***** ***** * ** * ** ** ** *
* * *** * * * * * ***
** * * *** * ** ***** ** ** ****** * * * ** ** ** ** ****** * ** *** * *
** ** * ** * *
/*
** * * * * * ** * * ** (A[i]!=0 || B[i]!=0){
* * *** * * * * ** * * * * ** * * ** ** * ** * * ** *
* * * *** * *** * ****** ** * ***** * ** **** ** 0;
** * * * * *
*/ * * ** * ** * ** * * ** *** ** * * 0;

*** **** * * ** * * **** (i = 0; i <256 ; i++)
** *** * *** * * * * *** * * * (count[i] && i!=' '){
*** * ** * * * ** * * * ** ** * * * * * * **** * * ** ** *** ** **
* * ** ** ** ** ** ** ******* * * ******* ** * * * * * * ** * 0;
** ** * * ******* ** ** *** ** *** *****


* ** * *** ** * * * * ** ** * 1;

* * * ***** * **** OF YOUR CODE*/
*** * * *** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * **** * ** * *** A[100],B[100];
** * * *** *** *** ** YOUR CODE HERE*/

** *** **** **** * *** ***
* ** * ** * **** * * *

* * ** * *** * * * **** * = '\0';
  // **** *** * = '\0';
* * *** * **** * * ** i;
*** * **** * ** ** ** * * * * * *** *
* * * * * * *** ** * * ** ** ** ** *** **** ***** ** ** ***** **
****** **** ** ** **** * *** *** * * ** ** * *** **
*** * *** ** ** ** * * * *** * *
*** * * * ** *** ** * ******* * * * ** ** ** * ** *** * * * * *** ** *****
*** *** * * * *** * *** * ** ***** * ** *

* * * ** ** *** ** OF YOUR CODE*/
* ** * ** * ** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
**** * *** printf("Two words or phrases are not anagrams");

* ** * * * *** * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** **
#include * ** **** *
#include * ** *** *** ****
int * ***** * A[],char B[])
{
* *** * * *** *** ** ** YOUR CODE HERE*/
*** * *** **** * * * **
** ** * * ***** ***** * * ** *** *
* * * * * * ***
* ** ***** * ** * * *** * **** * *** **
** * ** * * * ** * ** * * * ****** * ****
* ** * ** **** ** *** * *
* * * * ** * * * * ** * (A[i] || B[i])
* ** * * ** ** * * *** ** ** * * 0;

** ** * ** * * * *** *** (i = 0; i < 256; i++)
*** * * ** * * * * ** ** * *** ** * *** ** * **
* * * * ** **** *** ***** **** * * ** * * ** ** ** *** 0;
** * ** **** ** ** * ** 1;

* * ** * * **** ** * OF YOUR CODE*/
** ** **** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *** * *
{
*** * * *** * **
* * * * *** * ** * YOUR CODE HERE*/
* * * **** * ** * ********* ** ***** ** ** *
* *** ** * * * * * * ** * * * ** ***

** * * * * ****** OF YOUR CODE*/
** **** ** * * *** * * * *** words or phrases are * ** * * ***
*** * * * * *** * ** * * * words or phrases are not ** * *

* ** * * * * * * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include **** * ***
#include ** ** ** **
#include ** * * *
int * * ** ** A[],char B[])
{
** ** **** * * YOUR CODE HERE*/
* * ** * *** *** * ******
****** * * * ** * * * * * *** ** **
** * * * ** ** * * * * *
* ** *** ** ** * *** * ***** *** * ** ** *** * ** * ***
* **** ***** *** * ** * ** ** ** ** * * * ** *** *
* **** * * ** * *
* *** * * ** *** * * ** ** * (A[i] || B[i])
* *** * *** * ***** * * *** * ** * 0;

* ** ********* * * * * (i = 0; i < 256; i++)
* ** **** ** * ** * ** * * ** * ** * *** * *
* * * * * *** ** ** * * ** ** * * * * * ****** ****** * ** *** ** 0;
** ** * ** * * ** **** ** * 1;

***** * * * ** ** * OF YOUR CODE*/
** ** **** * ** *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * ***
{
* *** ***** ** ** ** * * *
*** * *** **** * YOUR CODE HERE*/
* ****** * * *** * ** **** ** * * ** * ** * ** *
***** ** *** * * * * ** *** * ** * * *

* * * * *** OF YOUR CODE*/
** * ** ** * * *** * *** * * words or phrases are * * ** ***
* **** *** * * ****** *** * words or phrases are not * * ** **

** *** *** * * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.216
©2016-2024

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 3.6k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 3.8k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 3.2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users