0 like 0 dislike
22.7k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 22.7k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * ** * *
#include *** ** *** *
#include ***** ** * ***
int ** * * a[],char b[])
{
** ** **** * ** *** first[26] = {0}, second[26] = {0}, c = 0;
***
* * ** ** **** * **** frequency of *** * in first string
*** **
* *** * * ***** * (a[c] != '\0')
* ** **** * **
* * * ** ***** * ** *** * **** ** * **
* *** * * ** * *** * ** ** ** *
* *** * * **
*** *
*** * * * * = 0;
** * *
** *** ** * * ****** (b[c] != '\0')
** ** ** *** * *** *
* * * ** **** * ** * * * * * * *** *** *
***** * * ** * *** * ** **** *** ***
* *** **** * * * ***
*
** **** *** *** * * Comparing frequency of * *
** * *
** ** * * ** (c = 0; c < 26; c++)
** * * * * * * ** *
** **** ****** * * * * * *** * (first[c] != second[c])
* *** *** ** *** * * * * * *** * ** ** * ***** * 0;
** ** *** ***** *
* * **
* * ** *** ** 1;
}

int **** **
{
** * ** ***** * * * **
**** ** * * * *** *** ** A,B);
* ** ** *** ** ******* ** ** *** ** ** * * ** words or phrases are ****** ***
** * *** ** * * * * ** * words or phrases are not * * *** ***

* * ******** * **** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** ** ** *
#include * * * ** * *
#include * ***** ** *
int * ***** a[],char b[])
{
** ** ** ** * * first[26] = {0}, second[26] = {0}, c = 0;
* *****
**** ** ** *** *** ** * frequency of characters in first string
** *
* * ** *** ** * * (a[c] != '\0')
*** * ** * * * ***
* *** ** ** ** * *** * * ** * * * * ** ** **
** * ** *** ** ** * ** * * **** ** * *
** * * *** * ****
** * ****
** * **** *** * = 0;
* ****
* **** *** ** * **** (b[c] != '\0')
** ** *** * *** *
* * **** * ** *** * ** * **** * *
* ***** * * ** *** ** ** * ** ** * **
*** *** ** * *
* *
*** ***** * ** * * * Comparing frequency of * *
*** ** *
** *** * (c = 0; c < 26; c++)
****** ** ** * *** *
* * * ** * * * ** * (first[c] != ****
** * * * * *** **** * ** ** * *** * ** ** 0;
* * ** ****
* ******
********* ** * ** *** * 1;
}

int main(void)
{
*** * *** ** *** ***** ** **
** ** *** ** *** * ** * * **** * * ***
** * * **** ** ** **** ** * * * * ** words or phrases are *** * *
* * *** * ** ** * * **** * words or phrases are not * ** ***

*** * ** *** ***** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** * * * *
#include ** *** * *
#include **** * * *
int is_anagrams(char A[],char B[])
{
*** ** ** ** * *** YOUR CODE HERE*/
* ** *** *** ** *** ** ***** ** ****
***** **** ** * * * ** *** *** ***** **
*** * * ** * ** **
**** * ***** ** ***** * * * ** ** ** * ** **** ** * && * * ** *
* * *** * ** *** * * * * ********* * ** * **** **** ** * ** * * **
* * *** **** *** * * **** ** * * ***** ** * **** ** * **** && *** * *
*** * **** ** * ** * * ******** *** * * * * * * * ** ******* * ** * * **** * * ***
* * * ** ** ** * *** *
* ** * ***** * ** * * **** * * *
* **** ** * *
* * **** * ** * **** *** * ** * * * (cA[i]!=cB[i])
* *** ** * * ** **** ** * * * * *** * * ** ** * * *** ** *** 0;
* * * * * ** *
** ****** *** 1;
* ** ******** * * ** * * OF YOUR CODE*/
* ** ** ***** function should return 1 if two words or phrases are anagrams,
** ******* * **** * *** if two words or phrases are not anagrams.
}

int main(void)
{
*** * * ** **** * ** A[100],B[100];
* ** * ** ****** *** * YOUR CODE HERE*/
**** *** ******* * *** ** **** * * **** ** *
** * ***** * ** * ** *** *** * *
** * * * * * ****** * (is_anagrams(A,B))
* ** * ** ** * ** ** *** *** * *** * ** ** * * * ** words or phrases are anagrams");
**** ********* ****** * *** *
*** ** *** * * * * * * ***** ** *** ****** * * ** **** words or phrases are not anagrams");
* * * * * ** ** **** 0;
* * * **** * *** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * *** * * ** ** * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* *** ** * * * ** **
*** * * *** * *** * * * * *** (A[i] != '\0')
* ** * * * * *
***** ***** ** * *** * * * *** * * *** **** **** *
** **** * **** * **** * * * ****** * *
** ** * **** * *** ** *
* ** * ** ********* *
* * * *** * * * * ** ** * = 0;
****** * * * * * **** * *
* * *** *** * * ** ** ** (B[i] != '\0')
***** **** * * * * ****
** * ** * *** * * *** * * **** * ** * * ** ******** * *
** ** * ** **** ** * * ** ** ** * ** ** ** * ** * *
* * * * * *** ****** **
    
* * * ** * * * ** (i = 0; i < 26; i++)
**** * * ** ** * * ***
** * ** *** ** **** *** * * * ** (Array1[i] != Array2[i])
** * ** *** *** ** ***** *** * ** * *** * * * ********** ** * ** ** ** ** 0;
* ***** ** * *
****** **** ** * * ** *
** * *** ** *** * ** ** 1;
}

int main()
{
* * * ** * **** * * * * * * * A[100],B[100];

* * *** *** *** ** * * ** *
* * * * *** * * * * * ****
* ****** ** * * ** *
* * **** * *** * ** ** ** (is_anagrams(A,B))
*** **** * * ** * *
* ** ** ** *** ***** *** *** *** * * ** * ** ** * words or phrases are anagrams");
* * * ****** ** ***
* * * ** * * * **** * printf("Two words or phrases are not anagrams");
* * * * *** *** *** *
* * ***** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
*** * * * * * * ** **** Array1[26] = {0}, Array2[26] = {0}, i = 0;
** ** * * ** ** ** *** *
*** * ** ***** *** ******* (A[i] != '\0')
*** * ** *** * * * *
** * ** * * ** *** ** * **** *** ** * * ** * ** ** ** **
********** ** * * ** * **** **** ** ** *** * **
** ** * * * **
* ** *** * ** * * * **
* ** * ** * *** ** ** = 0;
******* ** * *** ** ***
***** * * **** * * ** (B[i] != '\0')
* ** ** ** * ****
* * ****** ** * ** ** ***** * * *** ** **** ** *** * ** *
* * * **** ** ** * * ** ** * * ****** ***
* ** **** * ** * * ****** * *
    
* * *** * ** **** **** (i = 0; i < 26; i++)
* * *** * * *****
* * ** * * * ** * * * * *** * * (Array1[i] != Array2[i])
** ** ** * * * * * *** *** * *** ** * * ** * *** *** ** * ** ** * 0;
****** * * * **** ****
* * *** *** *
** **** ** * * * *** *** * 1;
}

int main()
{
** * * * ********* ****** * A[100],B[100];

** * ** * * ****** * * *** * ** * ** * * **
** ***** * * ***** ******* ** * * *
* ******* * ****** **
** * * ** **** *** *** (is_anagrams(A,B))
** *** * * **** * *
*** *** ** * ** ** *** *** ** ** * * * * ** * * *** words or phrases are anagrams");
** ** * **** ****** *** **
* * ******** * * *** * printf("Two words or phrases are not anagrams");
*** ** * ** ** **
*** * ** * * * * *** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * *
#include * * ** ** *
#include * * ** *
int is_anagrams(char A[],char B[])
{
* * *** * ***** * ** ** lenA = strlen(A),lenB = strlen(B);
** * ** * * *** ***** * *** != lenB)
** ***** * * * * * * * *** ** * * ** 0;

** * * * * ** * * **** i,j,k,a[26] ={0},b[26] = {0};
***** * * * ** * ******* ** * = 0 ; i < lenA ; i++)
* * ** **** ** ****
** **** *** * ****** ** * * **** * * * = 0 ; j < 26 ; j++)
** * * * * * ** * * *** * ** ** ** * *
* ** *** * ** ** * *** * * ** * * * * * * **** * *** ** * == A[i] || 'A'+j == A[i])
* ***** * * * *** ** ** *** * * ***** ********** ** **** * * ** ***** * ****** *** ** *** **** ** ** *
** ** **** * ** * *** * * * ** *******
* * ** ** * ** * *
* * ** * * * *** ** * *** = 0 ; i < lenB ; i++)
** * * * **** * *** *
* * * ** **** * ** * ** * * ** * * = 0 ; j < 26 ; j++)
* ** * *** * ** *** ** *** ***** * * **
* ***** * ** ** * * * * ** ******* ** *** ** * ** ** * **** * * * ** == B[i] || 'A'+j == B[i])
** * ** **** * *** * *** * ***** ****** * ** * * *** *** * * ** * * ** ** ** * * ** * *
*** * * * * ** * * *** * * * * * * *****
* *** * ** * *** *** ** * *
***** * ***** * ** ** = 0 ; j < 26 ; j++)
** * * * * ***** *** ***
* *** *** *** ** * *** ** ** ** *** ** *** * **** *** != b[j])
* ** **** * ** ** ***** * *** ** * ** ***** * ** * * ** *** **** 0;
* * **** ** * *
** * ** * *** * * * * ** 1;

}

int main(void)
{
*** * ** * * ** A[100],B[100];
*** * * * * * *** * %s",A,B);

** ** * ** * * (is_anagrams(A,B)) *** * * words or phrases are anagrams");
** ** **** ** printf("Two words or phrases are not * **** * *

* * ** * **** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** * * * * *
#include ** ** ***** **
#include *** * ***
int is_anagrams(char A[],char B[])
{
* ** *** ** *** lenA = strlen(A),lenB = strlen(B),i,j,k;
** * **** * * ** ** *** * a = 0,b = 0;
* ****** *** ** ****** ** ** * != lenB)
* * * * * * * ** * * ** **** * * * *** **** ** 0;
******* ** ** ** * * * * *** = 0 ; k < 26 ; k++)
** * * * ***** * ***
** *** ****** * * ** * ** * * ** * ***** ** * *** * = 0 ; i < lenA ; i++)
** * * * * * ** * ******* ** * ** * *
** ** ** ** * ** **** * ** *** ** **** ***** ** *** *** ** ** * * ******* == A[i] || 'A'+k == A[i])
* * * * * ** * * * * ** ** *** * * * * * * * * ** * ** *** ** ***** * *** **
** * * *** * *** * ** * * * ** * * ** **
*** ** ** * * *** *** * * ** **** ** ** = 0 ; i < lenB ; i++)
** * * * *** ** * ****** *** *** **** * * ****** *
* ***** *** *** *** ******* * * ** ** * *** * * * * * *** ** * * ** * == B[i] || 'A'+k == B[i])
* ** ***** * * * * ** ****** * ** * ** ** ** *** * * * * *** ** ** *** ****** * ***** ** * *** *
** ** * ***** * ** * * * **** *** **
* ** * * * * * * *** ** * *** ** * != b)
* * * ** **** * * **** * * * ** * **** * ** * ** ***** * *** * * *** 0;
** * ** ** * **
***** ** ** ** * ***** * **** ** * ** ** **** * * ** * *** * * ******* * * 1;
}

int main(void)
{
* ****** *** * ** A[100],B[100];
** * * **** * ** *** **
** ***** * * ** **
**** ** ** *** *** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** ** *** ** **** * * printf("Two words or phrases are not anagrams");

* * ** * * **** * ** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** *****
#include * *** ****
#include * * **
int is_anagrams(char A[],char B[])
{
** * * ** * * * * YOUR CODE HERE*/
** * * ** * * * *** * * i,count[256]={0};
** * * * * * * * ** * **
***** ** ** ** ** ***
** * ** ****** * * *** * ** * * * *** ** * **** * ** **
** * * * ** ** ***
* ******* * * *** * ** * *
** * * ** * ** **
*** ** ** * * * * ** *** * *** * ** * * * ***** ** * ** * ** *** *** **
*** ** ***** *** *
/*
* * * * * * *** (A[i]!=0 || B[i]!=0){
* * * *** ** * ** * ** * * ** * *** * * * * * * ***** *** ** * * *
**** * * * * * * * * * **** ** ** * * ** *** * * ** * 0;
* * * * * ***** ******
*/ ** ** * * ****** * ** *** * 0;

* * * * ** ****** (i = 0; i <256 ; i++)
* ** ** ** * * * * * *** * * ** * *** (count[i] && i!=' '){
* * ** * * * * *** *** * ** *** * * ** * ** * * * ** * * *** * ** * ** * * ** ***
* ** ** ** ***** **** * * *** ***** ** ** **** * * *** * * *** 0;
* ** * * * ** * **** * *** *** * * *** *


** * **** * * ** * * ** 1;

** * * ** * * ** OF YOUR CODE*/
** * *** * ** * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
** * * **** A[100],B[100];
* * * ** *** YOUR CODE HERE*/

* * * *** * * * * ** ****** * *
**** * * ** *** * ** *** ** *

* * *** ** ** ** *** *** *** ** = '\0';
  // * ** ** ********* = '\0';
* *** ********** ** *** i;
** * * * * ***
* ** ** * * * ** ****** * * * **** ** * * * *** ** ** *** *** * *
* * * * * ** * * * *** * * ** ** ** * ** *** *
** ** * * *** *** **
* **** * ****** * *** * *** ** *** * ** * * * * * ** ********** ****
* ** ************ *** * * * * * * ** * * * ** * **

* ** ** ** * ** *** OF YOUR CODE*/
* * ** ** *** * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
**** * * * * printf("Two words or phrases are not anagrams");

** ** *** *** * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ******* *
#include **** * ***
#include ** * **
int * *** * A[],char B[])
{
* *** ******* *** YOUR CODE HERE*/
* ** ** * * * ** ** ******
* *** ******** *** * **** * **** **** ******
* *** * * *** * * ** **
* ****** * ** *** ******* ** ** **** * ** ***** * * *
* **** * * * * * * ** ** * * ** ** ** *
***** * * ** * * ***
* * * ***** ** * * (A[i] || B[i])
* * * * ** * * * * * ** * * ** ** * * 0;

** * * * *** * **** * *** (i = 0; i < 256; i++)
** *** ** *** ** * *** **** * * *** * * ** ** * *
* * * *** ** * * *** ** **** * * **** ** * * ** * * * ***** 0;
** * * * ** ** * ** * 1;

** * ******* * OF YOUR CODE*/
******* **** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** ***
{
* * * *** * ** * * * *
* * * * *** ** * YOUR CODE HERE*/
** * ** * *** * ** * **** * * * * *********
*** ** ** * * * * * *** * * * ** ** ** ** * **

* **** *** ** ** OF YOUR CODE*/
****** ** * * * * * * ** ***** ** **** *** * words or phrases are ** **
** * * **** ***** * ******* words or phrases are not * * * *

** * * ** * * * *** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * * *
#include * ** ** ****
#include *** **
int ** A[],char B[])
{
*** * * * * * YOUR CODE HERE*/
* * *** * * ** * ** ** ** *
* * *** ****** *** ** **** ** *** **** ** *
* *** ** ** ** * *
** * ***** * * * * * * * * *** * *** ** * ** *
* * * * *** * * ** ** ***** * ** * ** * ***** * ***
* * * * * ** * * * *** *
** ** * ** * * ******* (A[i] || B[i])
* *** * *** * * *** ***** * *** * 0;

** * ** * * * * ** (i = 0; i < 256; i++)
******* * **** * ***** * * ** * *** ** * ** ** **
** **** ****** ********* * * * ** * * *** ** *** ** *** * ** 0;
* * * * **** * **** 1;

**** * **** ** * ** * OF YOUR CODE*/
** ** ** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** *
{
**** ** * * ********* * ***** *
* * ** * ***** * * ** * YOUR CODE HERE*/
** *** ** * * * * * ** * *** * * * **
* ** * **** ********** ** * * * ** * ** * *

* * *** * ** * * ** * * OF YOUR CODE*/
* ******* * **** * ** * * ** ** * words or phrases are ** **** **
*** * * **** ******* *** * *** * * words or phrases are not * ** * * ***

**** * *** * * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 12k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 11.3k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 10.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users