0 like 0 dislike
19.2k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 19.2k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * * ** *
#include *** ** * ****
#include * ** ** ** **
int * * * ** a[],char b[])
{
* *** ** * ** first[26] = {0}, second[26] = {0}, c = 0;
* ** *
** * * *** *** ** * * ** frequency of * in first string
* * **
* ***** *** ** (a[c] != '\0')
**** ** * * * **
*** * * ** * * *** * * ***** * *
**** * ** ** * **** **** * * ***
* * * * * *
* ** *
* **** ***** * * *** = 0;
* ****
* **** ** ** * * (b[c] != '\0')
* * **** * * *
* ****** * * * ** * ** ** * * * *
*** ** ** * * * ** **** * *** * * *
*** *** **** ***
****
* * *** ** * Comparing frequency of ** ***
******
* * * ** * ** *** (c = 0; c < 26; c++)
* *** * * * *
*** ** ****** *** * * *** * *** * (first[c] != second[c])
*** ****** * *** *** * * **** *** * * * **** * 0;
* *** ** * **** **
** * *
*** * * * **** * 1;
}

int
{
* * *** ** * * * *
* ** * ** ** * *** * * * * *** A,B);
** * * * *** ** ** * *** * words or phrases are * *
*** *** * ** * ***** *** * * * * words or phrases are not ** ***** * *

* ** ** * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * ****
#include **** ** ** ** **
#include ** *****
int * * * ** a[],char b[])
{
* **** **** ** first[26] = {0}, second[26] = {0}, c = 0;
** * **
* * ****** *** ** * ** * frequency of characters in first string
* *
** ** * *** (a[c] != '\0')
* * * ** * ****
* *** * * * * * ** * ** * ** ** * *** *
* * * * * * **** * *** ******
* * * * *
**
** * ** * ******* = 0;
*** **
* ** **** ** * ** * *** (b[c] != '\0')
** *** * ** *** *
* * ***** * * ****** * * *** * * **** ***
* **** * **** * ** *** ***** * ** **
** ** ** * ** * *
* *
* * * ** * *** Comparing frequency of ****
** **
** ** ** * ** * * (c = 0; c < 26; c++)
*** *** * ** * **
* **** * ** * *** * * * * *** * (first[c] != * *
* ***** * * *** ***** * ** ** ** ****** ***** * * * ** 0;
*** ** * * ** *
******
* ***** *** ** * * 1;
}

int main(void)
{
* **** *** ****** **** * *** *
* * **** * ** ***** ** * ** ** * ** ** ** *
* ** *** ** * * * * * * ** * ** **** words or phrases are ******** **
* * ** ** ** * * * * ** words or phrases are not ** ********

*** * * *** * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * * ** *
#include * * * *
#include *** * * * **
int is_anagrams(char A[],char B[])
{
* * ** * * ** **** YOUR CODE HERE*/
** ** ** * * ** * ** ********** *** * * * *
*** ** ** ** * ** * * * ** *** * * *
**** * * ** * *
* * * * ** * * * * * * ** * *** * * ******* * * * * * **** && * ** ** ** *
* ** ** ** * ** ***** * ** * *** ***** * * *** * * * ** * ******** * * * * ***
* **** * * * *** *** * * ** * * *** * ** * * *** ** && * *** * ** ** **
** ********* * ****** ** * **** * * *** * * ** * * * ** **** ** * ******** * * **
* ** * **** ***** ** * **
* * * ** **** * * * **** * **
* *** **** * **** **
* ** * * * * * ** * * * * * * ** (cA[i]!=cB[i])
* * * ** ** * *** * ***** * * ** * * ** * * * * * * ** * ** ** 0;
* *** * * **** *
* * *** * ****** 1;
** * * **** *** * *** OF YOUR CODE*/
*** ***** *** ** * * * function should return 1 if two words or phrases are anagrams,
* ** * * * * * ** * if two words or phrases are not anagrams.
}

int main(void)
{
* ** ** * ***** A[100],B[100];
** *** * * *** YOUR CODE HERE*/
*** * ** ** **** ** * * * *** ** * ** * * *
* * * * * *** * * * ** ** * ** * **
*** * ** * ** * * * ***** * (is_anagrams(A,B))
* *** ** ****** * ** ** * * *** ** ** * * words or phrases are anagrams");
***** * * ** * * *
* *** * * ** **** * **** ** * * * ** *** ** * ** words or phrases are not anagrams");
* * ** * *** * * **** ** ******** 0;
* *** ** * ** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** **** * * **** ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
** * * * * * * ** **
* ** * * ***** **** * *** *** (A[i] != '\0')
* ********* ** * *** ** * *
***** * *** ** **** * * *** * * *** * *** ** *** *
* * * **** * * * * * ***** ** * * *
* ** * ** * * **
** * ** ** * **** ***
* ** ** ** = 0;
* ** ** **** *** *
**** * *** ****** ** **** ** (B[i] != '\0')
* ***** *** * ** * ** * ****
** * * ** * ** * ** ***** * * * *** * *** * * * *** *
*** ***** ******* * * ** ** * * * * * ** * *
* ** * ** * * *
    
** ** **** * * * * (i = 0; i < 26; i++)
** * ** * *** * * *** *
* *** *** * * * ** * *** *** ***** * * * ******** (Array1[i] != Array2[i])
* ** ** ** * * * * * ** ** *** * ****** * * **** * 0;
** *** ****** * * *****
* ** ** ** * *** ** * * **
* * ** ** ** ** **** 1;
}

int main()
{
**** * ** **** ** * * **** A[100],B[100];

** * * * ** ** * ** *
*** ** ** * ** * * * *** * * ** *
* ** * ****** *
* * * *** * * ** * * ** (is_anagrams(A,B))
* * * * **** *** ***
** ** * * ** ** ** ***** * *** * * * * *** * * *** words or phrases are anagrams");
********* * ***** *
**** ** *** * * ** ** printf("Two words or phrases are not anagrams");
* ** * *** ***
* *** ** ** ** *** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** * * * * * * ** ** *** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ** * * *******
* ** *** * * (A[i] != '\0')
* * *** ** **** * *
** ***** *** * ** * **** ***** ** ** ** *** * * * ******
* ** * *** *** ** *** * * * * ****** *** * * ** *
***** * ** * * * * * *
* *** *** * ** **
* * * ***** *** * = 0;
* * * *** * ** *
** *** * **** *** * ** * * **** * * (B[i] != '\0')
* ** * ** * *
** * * **** ** *** * ** ** *** * * ******** * **** *** *
*** ** *** ** ******** ** ** *** * * ** ** ***
** *** * * *** ***** *
    
** * * ** * *** *** * ** (i = 0; i < 26; i++)
* *** *** ** *** ** *
** *** ** * * * ** *** * * * * ** * ** ****** * (Array1[i] != Array2[i])
* * *** ** * * ** *** ** ** *** * ** * *** ** * *** * *** ***** *** 0;
****** **** * * ** *
***** * *** ** ****
* *** * * * *** * **** 1;
}

int main()
{
** * * * * ** **** ** A[100],B[100];

** *** * ** * ** * ** ** * ** ** ** * *
** **** * ******* * ** **** * ****
** **** * * * * *** *
* ** ** *** * * *** (is_anagrams(A,B))
** * **** ** ** ***
* ** ** * *** * ** * **** * ** * * ** * * ** *** * * *** ****** words or phrases are anagrams");
* ** ** * * *
** ** **** *** ** * *** printf("Two words or phrases are not anagrams");
** * * * * * * *
*** * * ** * *** **** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * *
#include *** * ** * **
#include * * *** *
int is_anagrams(char A[],char B[])
{
* ** ** ********** * ** ** lenA = strlen(A),lenB = strlen(B);
****** * * **** **** * != lenB)
* ** ** ****** ** **** * *** * *** *** * * * * 0;

** * * * * *** * * ** i,j,k,a[26] ={0},b[26] = {0};
* ** ******** * * ** ** ** ** = 0 ; i < lenA ; i++)
** **** ** ** ** *
* ** **** ******* * * * ***** *** * ***** * *** * * = 0 ; j < 26 ; j++)
**** ** * **** ****** *** * * * ** * *** *
* * * * ** ** ** *** ** * * * ** ** *** * ** ** * ** * ** == A[i] || 'A'+j == A[i])
** * * ** * ** ** *** * * ** ******** ** ** ** ** * * * ******* * *** ** * ******
* * *** ** **** *** * **** ***** ** * *
* ** * * ** ****** **
******** ** * * **** = 0 ; i < lenB ; i++)
* ****** * * *** * **
**** ** *** ** * * * * * * * * *** ** *** = 0 ; j < 26 ; j++)
** ** * * * * * **** ** * * ** ** * *** **** * *
* *** * ** ** ** **** * **** **** ** **** ***** * ** *** * ** * ** *** *** ***** == B[i] || 'A'+j == B[i])
** *** * ** * ** ** ** * * *** ** * *** * ** * ** * * ** * * ** ** * **** ** * ***
* * ** *** ** * * * ** * ***** *
** * * *** * ******
* *** ** ** ** **** ** * * = 0 ; j < 26 ; j++)
** * *** * * ** ********
* * * * * * *** * *** ****** ** ** ** ** != b[j])
*** * * * ** *** **** * ** * ** * ** ****** * ** * ** ** 0;
*** * * * * ** *********
* ** * * * * * ** * 1;

}

int main(void)
{
* ** * ** * * A[100],B[100];
**** ****** ** * * %s",A,B);

* ** ** * **** ** * * (is_anagrams(A,B)) * *** ** words or phrases are anagrams");
* ***** ** **** **** printf("Two words or phrases are not ** * *** *** *

*** **** * **** * * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ****** ****
#include ***** ** *
#include * ** * * ***
int is_anagrams(char A[],char B[])
{
* ** * ** **** *** * **** * lenA = strlen(A),lenB = strlen(B),i,j,k;
* ** * ** * * * * * a = 0,b = 0;
* ** * ** * * * * != lenB)
* * ** *** * ** * ** ****** * *** ******* * * 0;
* * * * * **** ***** * = 0 ; k < 26 ; k++)
*** * ** ** * ** * *
*** * * ** *** ** ** * * * * *** * *** = 0 ; i < lenA ; i++)
* ** ** * * * **** ** * *** * ** **** * * ***** *
** ***** ** * ** * * * * * ** *** * * ** * **** * **** *** ******* * * == A[i] || 'A'+k == A[i])
** * * ** ** ***** * * * * ** * ***** * * * ** * *** *** * * ***** * ** ***** **** *******
* * * * ** ** * * * * ** *** *** * *** * **
** * ** * *** ***** * **** * * * * **** = 0 ; i < lenB ; i++)
* **** * * ******** **** * * ** ** * * * *** *
* ********* ******** ** * * ** * * ***** **** **** *** **** * ** == B[i] || 'A'+k == B[i])
** * *** **** ** ** * **** * *** * * ** * ***** ** * *** **** * * * * * * *** *
** ** ** * **** * *** *** **** ** *** * * *
* * * * ** * * ** * ** *** * * **** != b)
**** *** ** *** ** ** ****** * ** * ** * * * * * * * ** * * ** * ** ** ** * 0;
* **** * * * * * ****
*** * **** *** * * * ** ** ** ** * ****** * * *** ** *** * * 1;
}

int main(void)
{
* * ** ****** A[100],B[100];
** ** * * *** * *
****** ** * ** * * ** *
**** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * * **** *** printf("Two words or phrases are not anagrams");

* * * * * ** *** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** ** ** * *
#include ****** *****
#include * ****** **
int is_anagrams(char A[],char B[])
{
****** * * ** * * * YOUR CODE HERE*/
* *** * ** ** * * ** i,count[256]={0};
*** ***** * ** *** ** * ** * ** *
** * * ** ** ** **
** * * ** ** ** * ** * *** * * * * ***** ** * * * * * * ** *
** * ** ** * * * ** **
*** *** **** *** * ** * ** *
** * ** ***** ** *** *
** ** * ** * * * *** ** * *** ** * * * ****** * **** **** * ** *
*** * * * ** * ****
/*
** ** **** * * (A[i]!=0 || B[i]!=0){
* ***** **** *** *** ** ** ******** * ** * * **** * ** * ** **
*** * * ** *** ** * ** * **** *** * ** *** * 0;
* *** ** * * *** * ***
*/ ***** * ** ** * * ** * ** **** ** 0;

**** * * * * ***** * * (i = 0; i <256 ; i++)
* * * * * **** * ** ** * ** *** * (count[i] && i!=' '){
**** *** ** * * * * * ** * **** * ** * ** ** * * * * *** * * ** * * * *** ** * *
**** * * ** * ** * ** ** * * * * * *** ** **** ** **** * ** ** 0;
* **** * ** * * * *** * *** * ** * *** *


*** ** **** *** * * ** 1;

* * * *** ** OF YOUR CODE*/
****** * ***** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* *** ** * * * * A[100],B[100];
** * * ** * * * * YOUR CODE HERE*/

**** *** * * * * * *** * * *
** *** *** * * *

* ** ** * * * *** ** = '\0';
  // * **** * = '\0';
* * * *** * ******* ** * * i;
* * ** * ** * ********* * *** ***
***** * * ** * * ** * * **** * ** * * * * ******
** * **** ** *** * **** * * ** * * * ** ***
** ** *** * * * ** * ** *** *
** * ** * *** **** * ** ** ** ** ** * * **** ** ** *** ****** * ** **
***** * * * *** ** * ***** *** ***** **** * * **

** *** * ** **** OF YOUR CODE*/
* **** * ** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** * ** * ** *** * printf("Two words or phrases are not anagrams");

** *** * * *** * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** ** *
#include ** ** *
#include * * * ** ** **
int * **** ** A[],char B[])
{
* ** * YOUR CODE HERE*/
** * ** * * ** * * ** *** ******
** ** * * ** * * ** ** **** *** ** * ** ****
**** * * ** ** * **** *
** ******* * ** * * * * * * * * * *** * * ** ** * *
**** ** * *** * * **** * ** ** * * ** * *** *** * * ** **
* * ** * ** * **
* * * * * *** * ** *** ** (A[i] || B[i])
*** *** * ** ******* * * * * * ***** * *** * * 0;

* **** ********* * ** (i = 0; i < 256; i++)
******* * ** * ** **** * ** * * *** * *** ** *
** *** * ** *** * **** * * * * ******* * *** * * * * ***** * *** * 0;
* * * * * ** * ** ** * * ** 1;

**** ****** * * * OF YOUR CODE*/
*** ** * * * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * ***
{
* ** * ** *** * * ** **
* * * * * * ** * YOUR CODE HERE*/
* * * **** *** ** * ** ** * ** ** **
* ****** *** ** **** **** * * * * ** * * *

**** * ***** ** **** OF YOUR CODE*/
* ** * * * * * * **** ** ** *** words or phrases are * * ** *
*** * * *** *** * * ** *** * words or phrases are not *** * *** * *

** * * * * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** ** ** * *
#include ** * * ** **
#include *** * **** *
int ** ** * A[],char B[])
{
* * *** * *** * YOUR CODE HERE*/
* * * * * * ** ** * ** *
*** ** *** * * ** ******* * * * *
******* * **** *** * **
* **** * ** * * * ** ** * **** ** ** *** ** ** *
** *** ** *** * ** * ****** * **** * *** ** *
*** **** * ** * * *
* ** * ** *** ** *** (A[i] || B[i])
* **** * ** ** *** ** * ** * * * ** 0;

** ** **** *** * ** *** * (i = 0; i < 256; i++)
* * * *** ** * * **** * * *** * ** *** * * **
** * * * * * * * * * * ** ** * * * ***** * * * * * *** **** 0;
* ** * * * * * ** * * 1;

* *** * *** * ** * *** OF YOUR CODE*/
* **** ** ***** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *** *
{
***** **** **** * * * ** **
* ** * * *** **** YOUR CODE HERE*/
* ** ** * * ** ** **** ** ** *** **** *** ** ***
* **** ** * ** * * ** * ** * *** * * *

* ** ** * * **** * OF YOUR CODE*/
* ** ***** *** ** * * * ** * * * words or phrases are ** ** * **
****** ****** *** * * * **** words or phrases are not * ** * **

**** ** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.51
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.8k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.7k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 8.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users