0 like 0 dislike
17k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 17k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include *** * * **
#include *** *** *
#include * * ** ***
int * * *** a[],char b[])
{
* * *** * first[26] = {0}, second[26] = {0}, c = 0;
* * * *
** * * * ** ** * *** *** * **** frequency of * * in first string
* * *
** * ** * * * (a[c] != '\0')
* ** * ** *
****** ***** * * ** * **** *** * **** **
** * * * * ** * ** * * * * ** * ** *
* ** * ** *
* * *****
* ** * *** * = 0;
*
*** ** * * (b[c] != '\0')
* * * ** ** **
* * *** * *** * * * ******** *** * *
** ** * *** *** * *** ** ***** **
* *** * * *
**
* * *** * * * * Comparing frequency of ***
* ****
**** * * * * ** (c = 0; c < 26; c++)
* *** * * ** * ***
** *** ** * ** * ** ***** ** ** (first[c] != second[c])
****** ** * ** * * ****** ***** * *** * *** * 0;
** *******
***
*** * *** ** **** 1;
}

int *** ***
{
** *** **** ** * * * ****
**** ** * * *** ** **** A,B);
** * *** * **** * * * *** words or phrases are **** * ** **
* * *** ** *** ** *** ** words or phrases are not ***** * * **

** *** * *** **** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** *** *** **
#include ** * ** * ***
#include * * ** ** ** *
int ** * ***** * a[],char b[])
{
* *** * * * * first[26] = {0}, second[26] = {0}, c = 0;
* *
**** * ** * ** * * * * frequency of characters in first string
*** * * **
*** **** * **** * * *** (a[c] != '\0')
* ****** ** *******
*** *** ** * * * * ***** ** *** * * *
* * ***** *** * ***** *** * * *
** ** ** ********* *
* * **
* ** ** ** *** * ** = 0;
** *****
* ***** ***** * * ** (b[c] != '\0')
** * * * ** **
***** * **** * **** *** ** * ** ** * * * *
* * ** * * * * *** * * *
* *** ** **
*
* * ** **** * *** Comparing frequency of ** **
**** *
** * * **** ** * (c = 0; c < 26; c++)
*** *** * ** * * * *
** ***** * * ** * ** ** ** ** (first[c] !=
** * ** *** * ******* * ** **** * ** * * * * 0;
* * * ***
*****
* * * * ** ***** 1;
}

int main(void)
{
** ** * ** ***** ** * * * ** *
* *** * * ** * ** *** * * ** * ** ** ***
** ** * * * *** * * * * ** ***** ** ***** words or phrases are *** * ** ** *
** *** ** * ** * * ** ** * words or phrases are not ** * *

** * * ***** *** * ** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** ** * * ****
#include * *** ** * **
#include * * ** ** **
int is_anagrams(char A[],char B[])
{
* * ** ** ** * * ** ** YOUR CODE HERE*/
*** * * ** * ** * * * *** * * *
*** * ** * * * ** * * ** * * ****** **
** * * ** ** *** * ***
* * ** **** * ** ** * **** *** **** * *** * * ** ** * && *** ** ** * **
** ****** * *** * ** **** * * * ** * **** * ** ** * ** * **** * ***
* * * * **** * ** * * * * * ** * ** *** **** && * * * ** *
* * **** * * *** ** ** * * * *** ** * * ****** * * * * * ** * * *** ***
* ** * ** * ** *
* * **** *** * * *****
*** *** * **** *** ***
* ** ** *** * * ** * * ***** * **** * ** (cA[i]!=cB[i])
** * **** ** * ** ** *** ** ** * ** ** * *** *** * **** ** ** * * 0;
*** * **** *** *** *
* * *** * * ** ** 1;
**** ****** **** OF YOUR CODE*/
** ** ********* ** function should return 1 if two words or phrases are anagrams,
*** * * ** * * * * if two words or phrases are not anagrams.
}

int main(void)
{
* * *** ****** *** *** A[100],B[100];
* * ** * ** * * YOUR CODE HERE*/
* **** * * * * ***** *** * *** ** **
**** * *** * **** * * * ** * * * * ** * *******
* ********* * **** ** * * (is_anagrams(A,B))
****** * * ** *** ***** ** * ** ** ** ** *** ** words or phrases are anagrams");
* ** * ** * * * * *
* * * ** * *** ***** * ** ** * ** *** ****** * words or phrases are not anagrams");
* * ** * *** **** ** **** 0;
** ***** ** ** * ** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * * ** ** * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
** * * ***** * *
* ** * * * * ** *** (A[i] != '\0')
* ** * * ********** * **
* ** **** ** ******* ** * ** * *** ** ** * * * * **
* ** * * * * * ** * **** * * ** *** *
*** * ** * ** *****
* * * ***** **** * * * *
* **** **** *** = 0;
** * ** * ** * * *
* ** * *** * ** ** ***** (B[i] != '\0')
*** ** ** * * * **
* ** *** * ** * *** * * * * ** * ******* * * * ***
* *** **** **** ** * * * **** * ** * * *
* * ** * ** * ** * * ***
    
*** ********* ** ** * *** (i = 0; i < 26; i++)
* **** * * * * * * * *
* * * * * ** ***** ** ** * ** ** **** ** ***** (Array1[i] != Array2[i])
* ** * ** * ** * *** * ***** ** ** ** *** *** **** * **** **** * 0;
* ** ** *** ** ****
**** **** ** * *
** ** **** * *** * **** ** * 1;
}

int main()
{
*** * *** ** A[100],B[100];

* ** * * *** *** * * ** * *** **
**** * * * *** *** ** **** ** ** ***
**** ** * *** ** * ** * **
* * *** * ** *** * (is_anagrams(A,B))
** **** *** *****
** ** * * * ** *** * * * ** * * * ** **** ** ** * ** words or phrases are anagrams");
*** ** * * ** * ** ***
*** ** ** * ** ****** printf("Two words or phrases are not anagrams");
** ** * * ** *
* * * **** *** * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** ** * ****** ** *** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * ** * * *** *
** * * * ** *** * ** * * (A[i] != '\0')
* * **** ** *
* * ****** **** * * * ****** **** *** ***** * * * ** * ** **
* * **** * * ** * **** * ** *** * *** * ** **
*** *** ** * * ** * ** *
* * **
** * ** **** ** = 0;
** * *** ** *** * ***
* ** **** ****** * * (B[i] != '\0')
* * ** * * ** * *** *
*** * * * *** * ** * * * **** ** * *** * *** * **** * *
***** * *** * *** ** *** ** ** ** ** ** * * ** ***
**** ***** * * * * *** ** *
    
* ** *** ** * * (i = 0; i < 26; i++)
** ** * ** ** **** ****
* * *** *** * * * * * * * **** *** * **** (Array1[i] != Array2[i])
* * * ** ***** ** * * * ** * * * *** **** ** * * * ** * *** *** * * 0;
* * *** ** * * * ****
* * *** * ** **
* * * * * ** * * * ** * 1;
}

int main()
{
*** * * * ** * * * ** * A[100],B[100];

* *** * * * ** * * * **** * **** * *
**** * * ** ** * * * * * **** ******* * *
** ** * * **** ** *** ***
** * ******* *** * * (is_anagrams(A,B))
**** * * ** * ** *
* ** ** **** * * * * **** ** ** ** * *** ** * * words or phrases are anagrams");
* * * * ** ***
***** * *** * ** * **** printf("Two words or phrases are not anagrams");
*** ** **** *
** * **** **** ** ** * * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** **
#include * ** *
#include * * ** *** ***
int is_anagrams(char A[],char B[])
{
** * * **** * ******** *** lenA = strlen(A),lenB = strlen(B);
** * * *** * * * ** * != lenB)
* * * * * **** ** * * * ** *** * * * ** *** 0;

*** *** * ** * ** * ** i,j,k,a[26] ={0},b[26] = {0};
*** * * ** *** * * = 0 ; i < lenA ; i++)
* ** * * ******
*** * *** * * * ** ** * ** * * * ***** = 0 ; j < 26 ; j++)
*** * ** ** ** ** ** **** * *** ** ** *** ***
*** ** ** ***** **** * ** * ** * ** * * *** * *** ****** * ** ******** ** * == A[i] || 'A'+j == A[i])
** ** ** *** * * * ** * ***** *** *** *** * * ** *** *** * * * *
* **** *** * ** * * ** ** * * * ** * **
* * ** *** * *** * ** **
* * ******* *** ** ** * ** * = 0 ; i < lenB ; i++)
* ** ********* ** **** *
**** * * ****** * * * *** ***** ** * **** * * = 0 ; j < 26 ; j++)
* **** * * ***** * * ** * ** * *** *** *
* ** *** ** * * *** * * * *** * * * * * * ** * ** * * ** == B[i] || 'A'+j == B[i])
** * *** *** * ** * * * ** * * * * ** ** * * * *** ** * ** * * * * **** * * *** **
** ***** ** ****** ********* * *** * ** * * ** ****
* * * * ** ** * ** **** *
* * * * ** * * * = 0 ; j < 26 ; j++)
** * **** **** **
* * *** ** * * ** **** * ** *** ** ** ** * ** != b[j])
****** * **** ***** **** * * * * ** ** *** * *** * * ****** * *** * * * * * 0;
** ** ***** * ****
*** **** * *** ** ***** * 1;

}

int main(void)
{
* * * **** ** ** *** A[100],B[100];
* * * ** ** ** *** *** %s",A,B);

** * * *** * * *** *** (is_anagrams(A,B)) * * ***** * * * words or phrases are anagrams");
** ******** * * printf("Two words or phrases are not * * * ** * * *

** *** *** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ******
#include ****** * * * * *
#include ** * * * *
int is_anagrams(char A[],char B[])
{
* **** *** ** * * lenA = strlen(A),lenB = strlen(B),i,j,k;
*** ******* * * * * ** a = 0,b = 0;
******** *** * **** * != lenB)
* * ** * ** *** * * * * ** *** ** ** * **** ** 0;
* *** ** * ****** * **** = 0 ; k < 26 ; k++)
** ** * ***** ** * **
*** ** * * ** ****** *** ***** ** * * * * ** * * *** = 0 ; i < lenA ; i++)
* ***** **** * *** * *** ***** * ** * * **** **
* ** ** *** * * ** * * * * * * ** *** ** * *** * * **** * ** *** == A[i] || 'A'+k == A[i])
* ***** *** *** * ** * * *** ** * * * ** ** *** ** * ******** ***** * *** * * ** ** ** **
* * *** ***** * * *** *** * * * ** **** *******
** ** * ** * * * * **** * *** **** = 0 ; i < lenB ; i++)
* ** *** * *** ** * * *** *** ** ** ** ** *
* ** ** ** ** * * * ** **** * **** * ** **** * ** * * ** ** == B[i] || 'A'+k == B[i])
* *** * * * * * * ** ****** * * *** * * * * ** * *** * ** ** * * * * * * ** * ** * ***
* ** *** ** * * * * * ****** ** * ** *
** **** *** *** * * * ** * * ***** != b)
**** ** * * *** * **** * * * *** * ** ***** **** ** **** ** 0;
* * * ** * ***** * * **********
* *** * * * ** ** *** * ** *** ***** ** * * *** * * *** **** 1;
}

int main(void)
{
* *** ** * A[100],B[100];
* ** * ** * ** * *
** * ** ** * *** ***
* * * * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * *** * ****** *** printf("Two words or phrases are not anagrams");

**** ** *** *** * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** **** **
#include * * ** * **** *
#include * *** * *** *
int is_anagrams(char A[],char B[])
{
* * **** * * * * YOUR CODE HERE*/
* ** * * ** * i,count[256]={0};
** *** * ** ** * **
* * ** ** * * *
* ** ****** * ** **** ***** ** ***** * ** **** * * ** * ********* ***
* *** * *** **** * * *
** *** * *** * * * **** ** * * *
* ****** * *** ** ** *
* * *** * *** ** * *** ** ** * * *** * ***** ** ** *** * *** ** ** **
** **** ** * ** **
/*
* ** * ** * **** (A[i]!=0 || B[i]!=0){
* * **** * * *** ****** *** * * * * ** ** ****** ** * ****
** * **** * * ** * ***** * * ** *** 0;
***** ** ** * * *
*/ * * * * * * *** * ** ** 0;

** * ** * * **** ** ** * (i = 0; i <256 ; i++)
* ** * ** * ** * * **** ** ** * * *** ** * (count[i] && i!=' '){
** *** *** * * * * * * ** *** **** ** ** * *** ** ** * * * * * * * **** **** ** *
* * * * * * * * *** ****** ** * *** ** *** * * * *** * * * * *** * ** 0;
* * ** * * * * * * * * *** * *** * *


*** **** *** ***** * * 1;

** * **** * OF YOUR CODE*/
* * * * * ** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
*** ** **** A[100],B[100];
** *** *** * ** YOUR CODE HERE*/

** *** ** ** ** * * * * *
* * ** * * *** * * * * ***** **

**** *** *** * ** * * **** * **** = '\0';
  // * ** ** * = '\0';
*** ** * * * * ** ** i;
* *** ** ** * * * * ** * ****
**** * * *** ** ** * * ** * * * * * * ** ** * ** ****** *** * ** * * **
* ** * *** ** * **** * **** * * *** * **
* * * *** ** * * * * ** * * * *
* ** **** ** * * ** ** * * * * ***** ** * * * * ** * ** ** * *** ********* *
* * * * * ** * * * *** * * ** ** ** * *

* ** * * ** * OF YOUR CODE*/
* * * *********** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * ** ** * * printf("Two words or phrases are not anagrams");

** ***** ** **** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** *
#include * * *
#include ** * ** ** **
int * ** ** * * A[],char B[])
{
********** * * ** ** * YOUR CODE HERE*/
* * *** ** *** ** **** ** * * * ***
*** *** ** *** ** ** *** **** * **** **
*** *** ***** ***
** ****** ** * * ** * * * ** * * * * * *** ** * ***
* * ****** *** **** * * * ** ** * **** * * * ** **
** * * * *
* ** * ** ** * ** ** * (A[i] || B[i])
* * * ** ** * * * * * ** * * **** 0;

*** ** *** *** ** * * (i = 0; i < 256; i++)
* * **** * **** * ** * * ***** ** *** **
** * ****** * * *** * ** *** **** ** * **** *** ** * * *** 0;
*** * ** * ** ****** *** * 1;

* ** **** * ** * OF YOUR CODE*/
****** * * * * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *****
{
** ******* ** * * ** ** * * ** **
***** ******* *** * * * YOUR CODE HERE*/
* *** * * ** ** ** * *** * ** ** **** * *
** ** *** ** * *** ** ** * * * * **

* * * ** * * * * *** OF YOUR CODE*/
* ** * * **** **** * *** * ** ***** * * words or phrases are ** ******
* * **** * ** ** * ****** * words or phrases are not * * *** *

* * * ** *** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ***** **** *
#include ** *** * * **
#include * ****** * *
int ** * * A[],char B[])
{
* *** *** * * *** ** *** YOUR CODE HERE*/
* *** ** **** * * * ** * ** ***
* ** ** * *** ** * * * * * * * ** **
* * **** * ** ** **
***** * * **** * ** * * ** ** ** * ** **
*** ******* **** * *** * ** * *** *** *** ** ** **
*** ** * *** ** * *
** *** **** * * ** **** (A[i] || B[i])
****** **** *** ****** ****** ** *** 0;

* *** **** * **** **** * (i = 0; i < 256; i++)
****** **** ***** *** *** * ** * * ** ** * ** * **
* * ** * ** * ** * * ** ***** * * ** ***** ** * * * ** * * *** 0;
* *** * * ** ** ** * * * * 1;

* **** *** * *** * * OF YOUR CODE*/
*** ** ** * * *** *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** ***
{
* ** ** *** * ** *** *
** *** * ** * ***** ** YOUR CODE HERE*/
* ** *** * * * * * ** * * * * *** * *
*** * *** **** * ***** * * *** ** ** * * * *

* ***** * * *** ** * OF YOUR CODE*/
* ** * ** * * ****** * * **** ** words or phrases are * ** * ***
* * *** * ** *** * * * words or phrases are not *** ** **

**** * * * * *** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.70
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.8k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.7k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users