0 like 0 dislike
7.4k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 7.4k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ** ** * ** *****
#include *** ***** * *****
#include *** * ** *
int * * * *** a[],char b[])
{
** ** *** * **** first[26] = {0}, second[26] = {0}, c = 0;
******
* * *** * ** ** *** * frequency of * ** in first string
**
** * *** ** * * * (a[c] != '\0')
** ***** * *
*** * **** * ** *** * ** ** * *** * * *
* **** * ** * ** *** * * * ** * **
*** * *** * * *
*
* ** ** * **** *** = 0;
** * **
* * ***** ** ****** * * (b[c] != '\0')
*** ** * * ** ** **
* *** ** * * * *** *** * ** * * * * * * *
** * **** ** * * * ** * ** ** *
* ***** ** *
* * *
* ** * * ** ** Comparing frequency of *
** *
* * ** * ****** * (c = 0; c < 26; c++)
***** *** ** *
* *** * * **** ** * * ** ******* ** * ** (first[c] != second[c])
* ** ** ******* ***** * * * * *** *** ** * ** * **** 0;
**** * *** **
*** **
* ** ***** *** * * **** 1;
}

int ** *
{
*** ** * * *** ** * ** * **
* ** **** * * ***** * * * A,B);
***** * * *** * ** * *** *** ** words or phrases are * * ***
** ** ** * ** * words or phrases are not ** *** *

* * * *** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** ***
#include ** ** * *
#include *** * * *** *
int * **** *** a[],char b[])
{
* ** *** * *** * * first[26] = {0}, second[26] = {0}, c = 0;
* ****
*** *** * **** * * * * **** frequency of characters in first string
* * *
*** * ** * ** ** *** ** (a[c] != '\0')
* **** ** ***
* *** ***** ** *** * * * * ** *** ** *****
* * ** * ***** *** * * *** ** ***
** * ** ***** * ****
* **
* * ** * * * * * = 0;
** **
* **** **** * *** *** * (b[c] != '\0')
* ***** ** * ** **
* * ** ** ** * ** * * * * ** * * **** *** ** * **
* * * * * ** * * * * **** **
** ** ** * * **
* ** *
* ****** ** **** ** Comparing frequency of **
*** *
** * ** * * * (c = 0; c < 26; c++)
* ***** *****
* * * * * **** ** *** ** * (first[c] != * ** *
* * * ** ***** ** *** ** ** * * * * * * * * * * ** 0;
* ** ****** * ** * **
******* *
* * * ******* * ** * * 1;
}

int main(void)
{
* *** **** ** * **** *
* * * * ** ***** * ** ** ** *** * * * ** *
** ** **** * * * * ***** * *** ** *** * ** words or phrases are * *** * * **
*** * * * * * **** * * ** *** words or phrases are not * ** ***

* ** * ** * ***** * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ****** * * *
#include * * *** **
#include * ** * *
int is_anagrams(char A[],char B[])
{
** * **** * * * ** ** YOUR CODE HERE*/
**** ***** ** ** * ** *** *** * *
** ** * * * * * * * * ** * * *** ** *
** * * * ** * *** **** **
** ** ** ** ***** ******** * ** ** ** * ** ** * *** && * * ** **
******* ** *** ** *** * ** ** * **** * * * *** * * * * * * ** ** * * ** * **
*** *** ** *** *** * ** ** ** * * ***** ** * * ***** * * ** && ***** **** ***
* ** * * ** * ****** ** ** ** * ***** * * * * ** * * * ** ** **** ***
** *** **** ** * *
*** * * ** ** ** * ** ** *** ***
** *** * ** ** **
* * * * * * ** * *** * *** * * * * * * (cA[i]!=cB[i])
* *** ** * *** * * ** ** ** ** * * * ** * ***** *** *** * * ** * 0;
****** *** * * ** * * ****
* ** *** * **** ***** * ** * 1;
**** * * * **** * * * * OF YOUR CODE*/
* * ********** * * * function should return 1 if two words or phrases are anagrams,
* * * ** ***** * if two words or phrases are not anagrams.
}

int main(void)
{
* * ***** ****** **** A[100],B[100];
* * * * ** * ** YOUR CODE HERE*/
*** *** * * * ** ** * *** * * * * ** * * ** **
* ***** ****** * * * *** * * ****
** ****** * ** ** * (is_anagrams(A,B))
* **** * * ** * * **** * *** * * * * *** ** words or phrases are anagrams");
* * * * **** ***** *** * **
* **** ** ** * **** *** * ***** ** * *** * * words or phrases are not anagrams");
* * **** ** ** * **** * 0;
* * *** * * * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** * ** *** ** * ****** Array1[26] = {0}, Array2[26] = {0}, i = 0;
******* * * * ** **
** ********* ** **** * *** * * (A[i] != '\0')
** **** *** ***** * *
* ** *** * * * ** * * * * * * * * * * *** ** ***
** ** * * *** * *** ** ****** * * *** *
* **** * ***** *
* * * * * * **** * *
** * * **** * ** * = 0;
* * * ** * * ** *
** ** * ** * * ** (B[i] != '\0')
* *** * * *
** * * ** * *** ** ************ * ** * *** *** **** *
****** * ****** *** ** *** **** *** ** *
* * ** ** * * ***
    
** * * *** * ** ** * (i = 0; i < 26; i++)
** ****** * * ** * * * *
** ** ** * * * * ** * * *** * * ** * * (Array1[i] != Array2[i])
* *** * ** * * * ** ****** * ** * * * ** ** ** * * * ***** *** *** 0;
* * *** * * *** * *
* **** * * ****** ***
* ** *** * * ** * **** 1;
}

int main()
{
* * * ** * ** *** * * A[100],B[100];

** ** * ** * **** * *
* * * * ***** ** ** * ** * * * *
*** * * * * * ***
* * * *** * * ***** *** * (is_anagrams(A,B))
** ***** ** ** * *** **
********* ** * * ** ** * **** * ***** **** *** * * * words or phrases are anagrams");
* ** * ** ** * ** * ** *
** ******** * * * * printf("Two words or phrases are not anagrams");
*** * ** *** **** * **
* **** **** * * * **** *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** ** ** ** ** ** * *** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * * * ** * * * **
* * ** *** ** (A[i] != '\0')
**** ** ********** * ** **
*** ** ** ** *** **** * ** * * * * ** ** * **** * **
* *** ********* ** * *** ** * * * * * *
** * ** * * ** *** * **
* *** ** *** **** *****
* ***** ***** * ** * * = 0;
*** * * **** ****** ** *
* * * * ** ***** *** ** (B[i] != '\0')
**** * ** * ** ** ***
*** ** ** *** * * * ** * * * ** * * * *
*** * **** * ** ** * * * ** *** ****** * * *
*** ***** ********* *** **** *
    
*** **** * ** ***** ** * (i = 0; i < 26; i++)
* * * ** ** * * *
* ** *** ** * * * * * ** ** **** ** * (Array1[i] != Array2[i])
* ** ** * ** * ** * ** * *** *** * *** * * ** ** **** ** 0;
** *** * * **** * ** **
*** ** * **** * * *** * **
* *** *** * * ** **** * 1;
}

int main()
{
* *** * * * * *** * **** ** A[100],B[100];

* ** * * ** * * *** ** **** **** * **** * * *
* ** * * * ** ** * * ** * ******** *
* *** * ** * * * ** * *
*** ** * * * * * * (is_anagrams(A,B))
** * * * ****** * ** *** *
* ** * * ** *** * ***** * * * * *** * ** * words or phrases are anagrams");
**** * ** * * * * *
**** * **** * * * ** printf("Two words or phrases are not anagrams");
* ** ** * *** *** *
*** *** ******* ** * *** *** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** *
#include * * ** * * * * *
#include **** * ***
int is_anagrams(char A[],char B[])
{
** * * * * ** ** ****** lenA = strlen(A),lenB = strlen(B);
* *** * *** ***** ** *** *** * != lenB)
* **** *** ** * **** * * ** * ** *** * *** 0;

** *** *** ** * * *** i,j,k,a[26] ={0},b[26] = {0};
*** * **** * *** * = 0 ; i < lenA ; i++)
* ** ** ** * * ** *
**** **** * * * * * * * * * * * * *** = 0 ; j < 26 ; j++)
* ******** * * * *** *** *** ** * ** **
** ***** ** ** * * *** * ** ***** * ** * *** * * * * ** ** *** == A[i] || 'A'+j == A[i])
* ******** * * *** * * * *** ** ** ** * * * * ** ** ** * * * *** ** * * ** * * * *
** ** ** * ** * * **** ** ** *** * *** *
*** ** ** ****** ***
* * * * * * * *** = 0 ; i < lenB ; i++)
* * ** * * * *
* * **** * * ** ** * * ** ** * * **** * ** * * = 0 ; j < 26 ; j++)
**** ** ** ** * * * ** * * **** ***
* ** ** ***** ** *** * * * * ** * * * * ** * * * * * * == B[i] || 'A'+j == B[i])
** ** * * * * ** ** ** ** *** ** * * ** ***** ** ** * ** * * *** * ******* *
** * ** ** *** * * * * ** * ** * * ***
* * ****** ** * * * *
** **** * * * * = 0 ; j < 26 ; j++)
*** * *** * ** * *****
* ****** ** *** ** * * ** **** * *** * ** != b[j])
* ** * * * ** *** * * ** ** ** * **** * ** * * * * 0;
* * ***** ** * * * ***
* * ****** * **** ** 1;

}

int main(void)
{
* ** ** * * ** * *** A[100],B[100];
** * * * *** * ** ** %s",A,B);

* * ** ***** * *** (is_anagrams(A,B)) *** * ** * ** words or phrases are anagrams");
** * * ** * ** printf("Two words or phrases are not * *** * ** *

*** ** * **** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** *
#include * **** *
#include * * ** * **
int is_anagrams(char A[],char B[])
{
* * ******* *** * ** *** lenA = strlen(A),lenB = strlen(B),i,j,k;
* **** * ** * * ** a = 0,b = 0;
* ****** * * * **** ** * != lenB)
* * * ** * ** **** *** *** *** * ***** * 0;
* *** ** * ** * **** * = 0 ; k < 26 ; k++)
* * * * ****** ** ** ** *
* * * * ***** * * * ** * * * * ** * * * = 0 ; i < lenA ; i++)
* * **** * *** *** * * * ***** * * * * *
* ** * ** * * *** ***** **** * * ** * * ** * * * *** ** * ** * ** *** * == A[i] || 'A'+k == A[i])
** * * * ***** * * * * *** * * * * * * * * **** ** * **** * * * * * **** *
* ******* * *** * ** ** * * * ***** ***** * *
* **** * * ** ** * *** ** * ** ** ** * * *** * = 0 ; i < lenB ; i++)
*** * *** * * ** * **** * ** *** *** * * * *** *
** * ** *** **** * *** ** ** *** * * * * * ** * *** * * ** ** * == B[i] || 'A'+k == B[i])
** * * ** **** * ****** ** *** *** * ** ****** *** * * *** *** ** **** ** * ***** *
** ** * ** * **** * **** ** ** * ** * ****
** ** * * ** ** *** ** * * * ** * *** * != b)
* *** * * ** * * * *** **** ** * ** **** * * **** ** * ** 0;
* * ** * * * *** **
** ** * * * * * * ** ***** *** *** * ***** * * ***** * * ** * * 1;
}

int main(void)
{
**** * * * *** A[100],B[100];
** * ** * * ** ****
* * ** ** * * * * * *
******* ** * * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * ** *** *** printf("Two words or phrases are not anagrams");

* ** ** * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * * * *
#include *** * *
#include ** ** * ** * *
int is_anagrams(char A[],char B[])
{
* * * * * ***** * * YOUR CODE HERE*/
** ** ***** *** *** ** i,count[256]={0};
*** * **** * * *** * * ** *
**** **** ** ** * * *
* * * * * * * * * ** * *** * *** **** *** ** * ** * * * **
**** * * * ** * * **
* ** * * * ** * *** *** *** ****
*** * *** * * * * * ***** ***
* ******** * * **** ** ** ******* * * * ** * *** ** **** * **** *** * *
* *** * ** *** * * *
/*
** ** * * * * ** * (A[i]!=0 || B[i]!=0){
** *** * * **** * * * * * *** *** ***** *** * *** * * * *
*** * * * ****** ** * * * * * ** * * *** 0;
***** ** * * *
*/ ** * * *** * ** * * **** ** 0;

****** **** ******** * * * (i = 0; i <256 ; i++)
** ** * * * ***** *** ***** * * * * ** * ** ** (count[i] && i!=' '){
*** *** ** ** **** * * ** *** ** * * ** ******* ** ** * ** *** *** * ** * * *
** * *** * ** * * ** * **** * *** * * ** *** ** ** * ** ********* ** * * * 0;
* ****** * * *** * ** *** **** * ** **


* * * ** * * *** ** *** 1;

* ****** **** * OF YOUR CODE*/
*** * * * ***** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
**** * * A[100],B[100];
******** **** **** *** * YOUR CODE HERE*/

* ** * * ** * * * * ** ** * *
* * * ** * * * ******* ** * ***

* ** * ** ***** * ***** * * = '\0';
  // ** * * = '\0';
* ** * * * * ** * i;
*** **** ***** * * ****** * ************ *
** ** * *** * * * ** * * ** ** *** ****** * * *** ****** * **
** ***** * ** **** * ** ** ** * * ** ** ***
* **** ** *** ****** * *** *** ***
* * * * * *** * ****** *** *** **** * * * ***** * ** ** *** * ****
** ** ** **** **** ** * * * * * **** * * * * *

** ****** ** ** * * OF YOUR CODE*/
*** * ** * *** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
**** *** * **** * ** * printf("Two words or phrases are not anagrams");

* * **** * * *** ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** * ***** *
#include ********* **
#include *** * ** *
int * * *** A[],char B[])
{
* * ** **** ** * YOUR CODE HERE*/
****** * ** **** * ** *****
* *** * * * *** ****** *** * ** * *** **
****** * * ** *** * *** * *
**** ** * ** * *** *** * * * *** * ** **
** * *** *** ** * * ** * * * * * * *** ** ** *
* * * ** * ** **
* ** * **** ** * ** (A[i] || B[i])
* * **** * ** * **** * * *** ** 0;

*** * * ** ** * * (i = 0; i < 256; i++)
* * *** * **** ** ***** ** ** * * * *** ***** ** * * *
*** ** * * * * *** * * * * * ** * * * * * ** ** * * ***** * * * * 0;
** **** *** * * ** 1;

* **** *** * ** * * OF YOUR CODE*/
***** * *** *** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * ***
{
**** * *** * *** * *
** * * ** * * *** ***** * YOUR CODE HERE*/
**** ** ***** * * * * * * * **** * ***
* ***** ******* * ***** * * *** * * * *** *** ** *

* **** *** * * OF YOUR CODE*/
** ** **** * ** ** * **** *** ** ** * words or phrases are * * **** * * **
*** * ** * ** ** *** **** ** ** words or phrases are not * *** * *

* * * ** * * * * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ***** * * *** *
#include ** **** ** *
#include * * * ** *
int ** **** A[],char B[])
{
****** * ** ** *** * YOUR CODE HERE*/
***** * * * ** **** * * *
* * ** * * ** ** *** *** * * *************
*** *** *** ** * * * * **** *
* ** ****** *** * ** * *** * *** * ******
*** * ****** *** * **** **** * ** **** * *****
***** *** * * * *
* ** ** ** *** ** (A[i] || B[i])
*** * **** ****** *** * * ****** 0;

** * * ***** * ** **** ** (i = 0; i < 256; i++)
** ********* * * * * * ** ****** ** * * ***** * *
* ** *** ** * * * **** **** ****** *** * * * * *** * * * **** 0;
* *** ** ** ** ** ** ** * * 1;

* * ***** ***** OF YOUR CODE*/
* * *** ** * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * ** **
{
* **** * *
* ** * * * ********* *** * * * YOUR CODE HERE*/
* * *** * * * ** *** * * ** * *** * ** * **
** ** ** * * ** ** * * ** * ***** *

** * * * * * OF YOUR CODE*/
***** * ** ** ** * ** * ** ****** * words or phrases are * ** ****
* ** *** * * ** * * ** * words or phrases are not * ****

*** * * * * * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.39
©2016-2024

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 3.6k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 3.8k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 3.2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users