12-28 Exercise 3: Anagrams function

0 like 0 dislike
24.5k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited | 24.5k views
0 0
STRUPES!
commented by (323 points)

79 Answers

0 like 0 dislike 
Hidden content!
#include  ******* * * 
#include ** * *** ****** 
#include   *  * * **   
int **   ***** * a[],char b[])
{
 ** **  *  *    * **    *** first[26] = {0}, second[26] = {0}, c = 0;
  *  *  *
*   ** * ** *  *** *  **   * * * frequency of  ***  in first string
    *   
* ***  *** * ******* * ** (a[c] != '\0')
  * *  *   * ** *  ** 
 * * *  **  * *** *   ** * ** ******  *    *   ****  **** * *
 **   *  **  **    * *   **  ****  * ***  * 
       *** * ** *
*** *  *
*   **     ***   ** *   *   = 0;
  *  **  
 **  * ** ***  **  * ** *****   (b[c] != '\0')
 ** * ***  *    *** ***  *
* ** * **** * **  * * **** *    * *     * *       * ** *
*** *  * * *  **** ** *  * * * ** ** ** * *
** *** **   * * **  * * 
    * **
    **     * *  ****     Comparing frequency of  * * *
**** 
 ****   ** *  * ****     (c = 0; c < 26; c++)
*  ** *    **    * *
     *  * ****   *  **  ***   ******  ** * * (first[c] != second[c])
***     ***  ** **   **  * ** *   ****** ** * ** ***** ** 0;
   *    *   *   **     ** 
* * *   
** **  **** * * ***     *   1;
}

int ***  *
{
       *** * *** **    ** * **
* **    ***   ***   *   ****** **** **  *    A,B);
****   * * ***   ***    **      *  *** *   * *  * words or phrases are *   * *  **  
**   *** * ** **  ***  * * *     * words or phrases are not    *   ****

**   * ***** *** * **    0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *  ** * **  
#include * * *       **** 
#include     * ** *  * ***
int * * *    *  a[],char b[])
{
   *** **  * *   ** *  first[26] = {0}, second[26] = {0}, c = 0;
* ** *  
 **** ****** **  *  *   *   * ***  frequency of characters in first string
   ** ** 
 *   *** * * **  * **  *  * (a[c] != '\0')
 ****  *   **    **  ** 
** *** ***    ** ** *       **** * **   * *  *  
 **    ***** ** *    *** *    ** ** **** ** ***  
*   *  * **  * ** * **
***   * 
   * ****   *  **   *  = 0;
 ** *    
*** ** *   ****  **   **  (b[c] != '\0')
* *   *****      * ***  
 *  *  ** *  *** **   **** **  * *  **   * ***   ** *  *** *
       ****** ***    *******      ***   
**  * *    ** *** **** 
**  *   
 *  *   ****     *   **  * **  Comparing frequency of * * * * 
*** * *
*** **   * *    * *   *  (c = 0; c < 26; c++)
*** * ***  *  *    *
  **** **  ****   ** ** *** * * ** *  (first[c] !=  ** **  
  * *****   * ** *   ** * *  *  * *    *  * * **  ***   * * * *  ***   *   0;
 *  *  ****** **   *** *   
**** **
* * *   ***  **     ** **   1;
}

int main(void)
{
**  ***    **   ** *** ******* * * 
 **      **  * *  **  *  *  *  * * *    *  ***  ****** 
  *            * *    ***   * * *  ** ** * * words or phrases are ** * *  ***   * 
***        **   * **   *  * *  *    words or phrases are not   **   ** **  *

****  *   *  *  * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   *  *  ** *
#include  * ****  *  *
#include ***    *** ** *   *
int is_anagrams(char A[],char B[])
{
 * **    *  ******** *  *  YOUR CODE HERE*/
* ** *     ** **   * * * *  *     **    * ****  
* *     *** ** **** * * * ****    ** **   **   * ***
*  *        ***      *   *
*   *    ** ** *****  *  ****   **  ****** ** *    ****  *   *     * * &&  **   ***  * **  
  ** *   ***  *** * *  *  ***  *      ****   *  **   * *** *  ** *    **  *****  *  *** *  **
 * *****    *  *     **  * ** **** ** *     * *  **  ** *  ** * &&   ** *     * * *  
  *   ** *     ** **  *    ** * ** *     *** *** **  **  ** **  **         ***   *   ** *** ** * * *   *    
 ** ****   *** *   ** * *
*  ***    ***  *   *  ** ** *  * *    **   
*      * ** *******  ** *   * 
 ** *  * *  *******  * * *    *        *  *    * *   *      (cA[i]!=cB[i])
* *   *       *    ** *  *     *****   * * *     * **** **  ***  * *  ***  * *** *  *   0;
**** ** * **   *    *** ** **
 * ** * ******* **  * ****    * 1;
 * **  * * *     *  *   OF YOUR CODE*/
* *** *   *  * ***** *  function should return 1 if two words or phrases are anagrams,
 *  *      * **** *      if two words or phrases are not anagrams.
}

int main(void)
{
  ***  ** * **   A[100],B[100];
* *   * *  **    * *****  ** YOUR CODE HERE*/
* * **** *  **    * ***  *         *** * **     *  
**  ******     ** * ** **** * * * ** *  ** *  ** 
     * **   ** * **  *** ** *   ***** (is_anagrams(A,B))
***  **   * *     * * * ****  *   ***  ** * *     *  *****   *    ** ** words or phrases are anagrams");
 *   **              **** **     **
* **  ******  **** **  *******   * ** **  *** * **  * **   *  ***  words or phrases are not anagrams");
*** ** *      *   **  * * **** 0;
  * * * *    *  *  ***  OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
 *    **  *  ***     *        Array1[26] = {0}, Array2[26] = {0}, i = 0;
  ** *** ****** *    *  **
  ****  **   * *  *     ********* (A[i] != '\0')
*  *   ** **  ** ****   **  
  ** * * * ** * **   *  ** ** *  * **** * ** * **      * * ** ***
 ** **  *   ** * **  ** * *   * * ** *** **   **  *      * *  ******
*  ** * *     *    *  *** **  
    * ** ** **  *   * * * **
  *** **      *****  *    **  = 0;
  * *  *  **  *   **** * *
*   *** ** *  ***    ****     (B[i] != '\0')
  *  *  ** *  *** *** *    
* * *            *  ******    * **** **  * ** *   *  **  * **** 
 **   * **   ** * ****    **  *   * * **** *  **   ** **
 **  ******* * **   * * 
    
   ** * *  **** ****** * **** (i = 0; i < 26; i++)
  * *  *****    ******  ****
  ***   *   ******  * *  **   *  * *  * **** ****     * (Array1[i] != Array2[i])
 *** ** * * ** **  ** **    * * ** ****    *  ** *    *** *** *****   *  * *  ****** 0;
 *** ** *    **  **   *    *
 ** *****   ** * ** * *   
 ** ** * *** *  ** *   **    **  1;
}

int main()
{
   * ***     *  **      ***       A[100],B[100];

 *   * ** ****   *  *  * ** *    * ***  *   * 
 *** *  ****  *** ***   * *  *  ******* ****
    * **   ** *  * ** ** *  ** 
*   *  * * *       ******  * * (is_anagrams(A,B))
* *     * ***  ****   *** * *
  ***  ****** ***   *   *    * ** * **** *** ** *** *****  words or phrases are anagrams");
*   ***  **  *   * *
*** ****  * **   * * **  * **   printf("Two words or phrases are not anagrams");
**  *  * ** ****   ** **  
  *   *** **  ****  ***    **   0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
**  ** ******* *  ****   Array1[26] = {0}, Array2[26] = {0}, i = 0;
      * *       ** ** *** 
** **  ** **  *    **  ** * ** (A[i] != '\0')
 ** *        *  *       ** 
**  ** **  *  * * ** *   **    *    * *  * *  ** ** ** * * *  **  
  *  *  *  **  *** ****  *  * * *  * ** ** * **  * * 
 *    ***  * *    *  ** ** **
* * ** ****  *  ***    *  *  *
 *** *  *****    ** * ** = 0;
***   * *** ****  *  * ***
 ***** * **   *******     ***     (B[i] != '\0')
  * *    ***** *****  **  
 * *  * *       ** ******* *  * ****   ** **** ** *   *****     **   *
 ***  *   ****  * **** ** * *** *   *      **  * **** *  ***   *
 **       *     *  *   * ** **
    
  **  * *    **  * * *     * (i = 0; i < 26; i++)
**** *  **   * *     * * * *
  ***     ** ******    *  * *   ****   *** ** ***    * (Array1[i] != Array2[i])
*    *  *   ***   **  ** * * **  * * * * * *     ***  *      ***  *  ****  ** *  *  * ** **   0;
 * ** *    *     *** ** * ***
** **   ** * ***  *  ****
**   **   *   * **** ** **  ***** 1;
}

int main()
{
         **  *    * *****  * **  *  A[100],B[100];

* * *** *  * ****  *   * * * * * * *** *** 
 * **     ***** * ***** * * * *** *   * **  *  
** *****     *       *  * 
**     **********   ***    (is_anagrams(A,B))
 ****   *** **  *  *    * **
 *    *    * *      *******   * *      *  *  *    **  ***    ***  * words or phrases are anagrams");
******* ***  * * * * ** * *
*   ** **    *** * * **  * *** printf("Two words or phrases are not anagrams");
**  **  *    *  **  ***
   ***** ** * ****  **   * ***  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *****    *****
#include    **    *    **
#include *  * *  * * * 
int is_anagrams(char A[],char B[])
{
 * **** ** ** *   *  *  *  ** lenA = strlen(A),lenB = strlen(B);
  * ** ** *****  *     *  **  != lenB)
*  *  *    **** * * ** * *   **** ** **     * *  0;

*   * ** *  *  * **  *     * i,j,k,a[26] ={0},b[26] = {0};
 ** * *  ** **** *  *  * ***  = 0 ; i < lenA ; i++)
   *   * * * *  ***** ***
    ** ***  * * * *    ** *    **  **  * *   * *** * *  = 0 ; j < 26 ; j++)
    *   ****    *** **  ** *   *   ** *    *****  ****
** *   **      * ** * * * * *    *      *   * * **   *  *  ** ****  **   *  **    *    == A[i] || 'A'+j == A[i])
   *    ***** * * ** ***  *   ** * *  ***   *  ** **** *** *   *      **     ****  * * *      *  * ***  *  * *** ****** * 
  * ** * *  ** ***** * **     *     **** ** * * *     ****  
  *****   ******** ***   ** ***** **
*  * **** **   * * **  *      ** = 0 ; i < lenB ; i++)
 *** ** *  *  * *   *     *
* * * *  **  *******    * ********  * ***** * * *** * *******  = 0 ; j < 26 ; j++)
** *   * ****    *   * * * *  ***   * * * ***  * **  *     *  * *
**** *  * **  * ***    * ****  * **  *  ***  * **  *    ** *  ***  *  ***  * *  * * *  == B[i] || 'A'+j == B[i])
   *  ** **  **  ** * *    *  *** **  *  *     ****** *  ** * **  *** *   *** * *   *** *   * ***   ****
** *    ** *  * *   **** *   *** **   * * * *  **  ** **
** * **  * **  * *  ***  *     
 **** *   ** **   ****  *** * = 0 ; j < 26 ; j++)
*    * **  *  ** * *   *    * *
 ********     *  *    ****     **  *  * ** **   *** * ***   != b[j])
 ***  *  * *  *  *  *   ***** * ** **  *  *  *** **  **  *   ** **  * ***    *   *    * 0;
* ** ********** * *** *** * * 
******  *   *   *   *  *  *  *  1;

}

int main(void)
{
 *****  **  *** ***  A[100],B[100];
****   *  ******   * * ***  * %s",A,B);

*  ***** ** * *  *  * *    (is_anagrams(A,B)) * ** **** ** words or phrases are anagrams");
**  **  **  * *  **        printf("Two words or phrases are not  *   ***  *  *

*  * **  ** * * *        * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ** ** ***  *** 
#include *         * * ***
#include * * ***  * * *
int is_anagrams(char A[],char B[])
{
** * ***   * *     * **   * *  * lenA = strlen(A),lenB = strlen(B),i,j,k;
 *  ***    ** **     ** * *   a = 0,b = 0;
* * *  * * * *  *  * * *  * ****    != lenB)
**  * *   *    * ****** **       * ** ** *  **   *  *  **** 0;
* *  ***  *** *   ***** *      *  = 0 ; k < 26 ; k++)
   *    * * *  **  * **** *
 * * *** * *** **** *   *   *  *********  ** ****  *  *    = 0 ; i < lenA ; i++)
**         * * *** *  *** ****  * * ***      * * *    *  
      *** ** *     * *** *** *  ********    ********* *   *** ***   * **  ****** == A[i] || 'A'+k == A[i])
**** ***  *   **   *  ***** * * ** *** *  ** *    **   * *  ******* *  *     *   *****  *  ***  *  * *  **
***   *  * **** ** **  ** * ***   * ** ** * * * *  ** ***** 
  **** *  * *** ** *  *        ** *** * * **  *  ****  * *  ** = 0 ; i < lenB ; i++)
  *****    * * * ***  *     * ** *  *  **   ***       ***
 * ******  * * **    * *  * **  **     *  **** *** * * ***   ***  * *** * * * *** *** == B[i] || 'A'+k == B[i])
  *** ***      *****  * ****   **  ******    ** *** *   ** **  *  *   *   *   * *** ***    *****  *    ***     *  *
* * *** ** **   * *   * **** *    ** ***  * ** *** ** ** *
***   * ***  * * * *      **** *  *   **    *** * *   *  != b)
*   ** ***** * *  *  *** **     ** *     *******   * ** *  * **  * *  * * **** *     ** 0;
*** ** * ********  *  **  *****   
***** *** * *  * ** * **** ***  * *   * ***       * * *   ****   *** ** **  ** **  * 1;
}

int main(void)
{
** **  ********** *   * * *  A[100],B[100];
* ***  *  *  ** *  * * *    **** *
*  *** *  **    * **** * *    **  
*  ** *  ***  *    *  **  (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*   * * * ** * *     **  *  printf("Two words or phrases are not anagrams");

***  * ********      ** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  *** *
#include  *** *  *     * 
#include *   **** ****  
int is_anagrams(char A[],char B[])
{
***** *     * **    *  *  *  * YOUR CODE HERE*/
   *  ** * ***** **    **     i,count[256]={0};
*** *   * * ****  *****   **    * **** ** 
**   *** *  **** ** *  **
  *   **** **  ***  *      *  * *      ** *  **   *  **** * * * ** ***  *** * **  *  * ** *   **** *
* *  ** *** **   * *   ****   
 *     *** ** **   *  **       
* * * **  *  * **  *** * * 
* ***** * *  *   **  * * **  *     * *   ** * *   **  * ** * ***    * ***** *  ***  **   *  *
 *** *** ** *****      *  *
/*
*** **** ** **   *   ****     ** (A[i]!=0 || B[i]!=0){
  *     *       *   * **   *** ** *   **  *** * *  ** *  ***    * * ** * *** ****
*** **    *  * ****  ** *** * *** *  **     *  **     * 0;
  **  ***** *  *** ** * 
*/    *  * *   *  *  ** ** ** * * **   0;

  ***** *   ** *****  *******    (i = 0; i <256 ; i++)
** * *   * * * **   * *** ** **  ***   * ****   **    * (count[i] && i!=' '){
**  * *    ***    *** *   * * ** *     * **  ****  **   **  **   *  *** **** *  **** * **    * *  ****  *** **  **
 ******** *  *  ******* * * **   *   ** ****   *** **  ** **   * **         * *    ** 0;
 * * * * *****      * *** * * *  * * * ** *** ** * *** ** ** 


** ***  * * ** ** **   *   **  **** 1;

*   *    *  *    *  OF YOUR CODE*/
*  * **  *** *   * * *  * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
*  * * ***    *  * * A[100],B[100];
*  *** ** * *  *  *   ** YOUR CODE HERE*/

*          * *  **     ****  ** *  *     *
*  *** * **  * * ****     **     ** * 

* ** ** *     *  ***** * * *  * = '\0';
  //  *** ***** * = '\0';
 * ***** *   ** * *** ***   *   i;
**   ** ** ******* *   *********    *** ** **  ** 
*  **      *   *    *   ***  *  *  *  *****  ** * * **           *   * * * ** *   * * **
***  * * ** *  * * **    *     * *** * * **    *** *    * **    * *  * *
 *  * * * **  *      *   **   ** * 
*  * * * **** **** *  ** ****  * ** *  * **     * * * *** *  *** *    *******  *        
*   *****  *** **   *  * *  ****  *****  * * ** **  ** *    ** *

  ****  ***     * * OF YOUR CODE*/
*   * ** ***    * * ** *** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
  * *  *     * *** * * printf("Two words or phrases are not anagrams");

**    ***  **   **       *   0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  **    
#include  * *  ** **  
#include   * *  ********  *
int ** **   * * A[],char B[])
{
 **   *******  ***** * * YOUR CODE HERE*/
  * *    *** ****   *  * * * ***   **   
* *  *  ******  ** ****    **  * ** *  *  **   ** ** **  *
* *** * **** ****  ** ** ***** 
   *** ** ** * **  ** * * ** *  * * ** *   * ** *** ** * * **  
 * *    * *    ** ******** ** *  * *        * ***    * * * *  *
 *** * **  ***    *   ****  *
  ** *  * * **  *    *  ****  * (A[i] || B[i])
  *  **    *  ** *****    *    *     *  0;

 **  *** ****   ** *** ***   (i = 0; i < 256; i++)
**   * * ****    * **    * * * *** * *  **  *** *** *   **   *  *
 *** *   *   *  ** *  *  * ***    *  *** **  ** * ** *** *      ****  *    ***    *  0;
  * ** * ** *    **    *  * * 1;

   ** * ** * ** *** * **  OF YOUR CODE*/
***    ** *      * **  function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int     *  
{
* *   ** ***   *** *  * *   * * *
* *      *    ** * * * *  *** YOUR CODE HERE*/
 * ***     ***  *   ********** *** *  *******  * **  **
* * *** ***  ** ** * **    *  *  *  *     **** **  ** 

 **  *** ** * *** **    OF YOUR CODE*/
* * ****   **** **     * ******  ** * *   *** * *** words or phrases are  * *   **    
 **   **** *   * *** * ** *  ****   * *   * words or phrases are not  ** * **  *  

 * * **   ***     *     *  0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  **  *   **  
#include * * *  * ** *
#include *** *  ******  
int   *  ** *  A[],char B[])
{
*  * *  * *  * ****   *  **** YOUR CODE HERE*/
 * * ******* **  *   **      * **** ***
* * * ** *  **   * ****  *  *      * **** *    ****  
* ** *  ***  ** **  ***    ***
 ***  * *  * *    *** *** *   * ** ** * * **   ** *** ***   * 
 *  * *** * * *  * *** * *   **** *     ** **** *   *** *** **  ***
*  **** * **   * *** **   ** **
   **   * *   ****      *   *  (A[i] || B[i])
* ******* ** * *   *   *   *******    ** ***** 0;

**  * *  ***********   * * ***  (i = 0; i < 256; i++)
****  * ** * ****** **   *** **     *  * *    **** *       *   
 * ***  **    ************* *  *  **  *   * *  * *  *  *  *** **        **   *** ****  ***  0;
*** *** ***     ** *    * ***** 1;

**  *     ******  *  **** ** *  OF YOUR CODE*/
  **    * *   ***** *   **   function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *  **
{
****   * ** *  ** ** ** *  **  **  *
 **  ***** ***** *   ** YOUR CODE HERE*/
 **  *** *   * ** ***   **** * **** *  *****       ** *
*  ***** *** ** *******   * **     *   *  *     *   

  ** ***    *   **    *** OF YOUR CODE*/
* *** ***  **    * *         ** ***** *  **   **  *  words or phrases are *** ***  ***
* * * ** **  **     * **    ***  * *  *  words or phrases are not   * ***   ***  

 *   * ** * *** **  *** ***** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

0 like 0 dislike
47 answers
12-07 Exercise 3: Function to delete an element from an array
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 13.1k views
0 like 0 dislike
45 answers
12-07 Exercise 2: Function num_digits
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 12.2k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 11.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users