0 like 0 dislike
12.7k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 12.7k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ** * *** *
#include * * *
#include **** ** * ****
int * ***** * a[],char b[])
{
** ** * ** *** * ** first[26] = {0}, second[26] = {0}, c = 0;
* * ** **
** * ** * * * ****** frequency of *** * in first string
* * **
* * * * * * *** (a[c] != '\0')
** ** *** ***** * * *
* ***** **** * * ***** ** * * * **** ** * ****
** * ******** * * * * **** *** * * **
** * * *
* **
* * * ** ** ** * = 0;
***
* * ***** * * **** ***** (b[c] != '\0')
** ** ** ** * * * *
**** * * ** *** * * * ** ***** *** ***
* * ** **** * * * *** **** * * **
** ** *** * ** *
*** *
** ** * ** *** * ** Comparing frequency of **
** * **
* * ***** ** ***** ** (c = 0; c < 26; c++)
******* ** * * ** *
*** ** * ** *** *** * **** * * (first[c] != second[c])
* * *** ** ** * *** ** ** * * * * * * **** 0;
** * * * **
* * * *
* * * * ** ***** * *** 1;
}

int **
{
* * ***** ** *** *
* ** ** *** ** * * ** * A,B);
* **** ** ** ** * * * ** * ** ** * words or phrases are ** * ** ***
**** * * ** * * ** * * words or phrases are not *** * * * **

** * *** *** ** ** * ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * ****
#include * ** * * * ** *
#include *** *** **
int * * *** * * a[],char b[])
{
** ** * ** **** * first[26] = {0}, second[26] = {0}, c = 0;
*
*** * * ** * ** frequency of characters in first string
* * *
* *** **** ** **** (a[c] != '\0')
*** *** * * ** **
*** * **** ** * * *** ** ******* ** *
*** ** ** * ** **** ** * * * ****
** * ** ** * * *******
**
* *** ** * * = 0;
** *****
* ** * ** *** (b[c] != '\0')
* ** ***
** * ** * ******** **** **** ****** * *** * ** ***
***** ** * * **** * **** ** * * **
* * * *** ****
* *****
* ** ****** * * Comparing frequency of ****
* * ** *
*** * ** * * ** (c = 0; c < 26; c++)
* * * ** **
* * ** ** * * * * ***** * **** ** * (first[c] != *** **
**** *** *** ** * ** ** ******* * *** * ** *** * 0;
* * ** ** ***
** *** *
***** ** ** * ** * ******* 1;
}

int main(void)
{
* * ** ** ** *
** *** * *** ** ** * * * * ** * ** ** *** ** **
* * ****** * *** * * * **** * ** ** words or phrases are *** * * *
*** *** * *** * ** *** * words or phrases are not * ** ***

***** **** ** ** * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** * ** **
#include * * * ** *
#include ** * * * ***** **
int is_anagrams(char A[],char B[])
{
* * * * *** YOUR CODE HERE*/
* *** * ** **** ** * ** ** ** ** *
****** ******* * **** * ** ** * **** * *
** * ** *** **** ** *
** ** ** *** ****** * **** * *** * ** ** * * * * * && * * ** ****
** * ** * * ** ** * * *** ****** ** * ** * * ***** * *** * * * * * * *
* * * ** ** * * * * ****** **** ** ** * * * * * ** * *** && ****** ** * ****
** **** * ** ** ** **** ** *** * * * **** ***** *** *** **** * ****** ***** ** * ******
****** * * ** ** * * *
**** **** ** ** **** *** * * * ** * *****
* ** ** ** ** ***** * *
** *** * * * * *** * * * ****** * ** ***** (cA[i]!=cB[i])
* * * * * * ** ***** * ** * ** * ** ******* ** ** ***** * *** * ** 0;
* * ******** *** ** **** ** **
* * *** ** * ** *** ** *** ** 1;
* * ** **** * ** OF YOUR CODE*/
* ** * ** function should return 1 if two words or phrases are anagrams,
** * *** * ** * if two words or phrases are not anagrams.
}

int main(void)
{
* **** * * * ** * * A[100],B[100];
* * ** **** ** * * **** YOUR CODE HERE*/
** *** * * * ** * ** *** * ** * * **** *** * *
* ** *** * * **** ** * * * **** *** *** *
* **** ** *** * * **** (is_anagrams(A,B))
* * * *** * * * **** * ** *** * * * * * * * *** * words or phrases are anagrams");
** * * * * ** **** * * ** ** *
*** * * ** * ** ** *** **** *** *** *** * * words or phrases are not anagrams");
** ** ***** *** * * * * 0;
** * *** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
*** *** * * ** *** * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
*** * * * **** ** * *
** ****** ** ** (A[i] != '\0')
** * * *** ** * ****
**** **** ** * ** * * * * ** * *** * *** * * * **** ***
*** ** * *** ** * * * *** * **** **** *
* * ***** * * * * ** ***
*** * * ** * * **
*** * ** ** * ** *** ** * = 0;
******** * * * * * *
* * * * * ** ** (B[i] != '\0')
* ** *** *** ** * * ***
** ** ** * * * *** ** ******* * *** ** ** * ** *
* ** *** ***** ** * ** ** * * * **** * ** *****
** * * * * ****** * ***
    
* ** **** * ***** * (i = 0; i < 26; i++)
* * ** *** ** * * *
* * * *** *** ***** ** * * * * * ** ** (Array1[i] != Array2[i])
* * * * * * ** *** **** ** * * * * * * ****** ** * ** 0;
* * ******* * ** *
* ** ** * * * * *
*** * **** * * * ** **** 1;
}

int main()
{
** *** **** *** ** ***** * A[100],B[100];

*** * *** * * * ** ** ** *** *
*** ** *** ** ** * *** ** * ** *
** * *** * * * * ***** **
***** *** * * ** * (is_anagrams(A,B))
*** *** *** * * ** *
**** ** ** ** ** ** ******* ** ** *** * ** * * **** * * * words or phrases are anagrams");
* ** ** * * *** ** **
***** ** *** *** * ** *** printf("Two words or phrases are not anagrams");
* * ** ** *** ** * **** *
* * * **** **** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * ** ** ** ** **** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
** ** * **** * * ** *
* **** ***** ** ** * ** * * (A[i] != '\0')
** * * ** ** * *** ** **
******** * * ***** ** *** * *** * * **** * ******* * ****
* ****** * * ** * *** * * ** ** *** *
** ******* *
** * * * * * * *** * *
**** * ** ****** * = 0;
* * * *** ** * * *
* *** *** * * ** ***** (B[i] != '\0')
* * * ***** *** * ** *
* * ** ** * ** *** * * * *** ***** ** * * * * *** *
** * * ** *** *** * * ** * * * * ** ** *** *
**** * * **** ** ** * * **
    
** *** * *** * * * (i = 0; i < 26; i++)
** ** * ***** * **
*** ** *** ****** ** *** ** **** ** *** (Array1[i] != Array2[i])
*** * * *** * * * * * * * * *** *** * ** * * * *** ** ** 0;
** * **** * ** **** * *
* ** * * ***** * * *
* ** ** * * ** * * ** * *** 1;
}

int main()
{
* * *** **** **** * ******* A[100],B[100];

* ** * * * ** ***** * * ********* **** * **** *
* *** * ** ** *** **** * * *
** * * ** ** *
** ** ** * ***** * * (is_anagrams(A,B))
* * * * * * **** * ** *
**** * ** **** * * ** * **** * * ***** * * * words or phrases are anagrams");
** *** * * ** ** ***
* ***** ***** *** * ** printf("Two words or phrases are not anagrams");
********* * *****
** *** ** * * * *** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** ** *
#include * ****** *
#include ** ***** *
int is_anagrams(char A[],char B[])
{
* * ** * ** * ** *** lenA = strlen(A),lenB = strlen(B);
****** * ** **** * *** != lenB)
**** * * ** ** * * * **** *** * ** * * ** ** * 0;

* * * *** ** ** ** ** i,j,k,a[26] ={0},b[26] = {0};
* *** **** * * ** * * = 0 ; i < lenA ; i++)
* * * ** *** ** ** *
** ** ** * *** * ** * ** * *** * ***** = 0 ; j < 26 ; j++)
*** * * * **** ******** *** ** *** * * ***
* ** ** **** * ** ****** * ** * * **** ** ** *** **** ** *** * * == A[i] || 'A'+j == A[i])
* * * * * * * * *** * *** ***** **** * * * ** ** ** * * ** * * ** ** *** **** ***
* * * *** ** ***** * ** ******* * ** ** * * ** * *
* ***** *** * * * **** * *
***** * ** * * ** ** ** * = 0 ; i < lenB ; i++)
** * * * **** ** ** *
** ** * ** ******** *** *** * ** * ** ** ******* * = 0 ; j < 26 ; j++)
** * *** * * * * * *** ***** * * *** **
** * ** * ** * * * * ** * ** *** * * * * * *** * * ****** == B[i] || 'A'+j == B[i])
* * * ** ** **** * * * * * *** ** * * * * ** * ***** *** * ** * * ** * * *
* * * * *** ****** * * ** ** **** *** **
* *** * *** * *** * ***
** * * * * *** * ** * * = 0 ; j < 26 ; j++)
* ******** * * * *
* ** * ** * * *** ** * **** * ***** * * * ** * * != b[j])
******* * * * * * *** *** **** ***** *** * ** * * ** *** ** * * * * * 0;
*** * **** ** ** * **** ** *
* ** * ** ********** * * * 1;

}

int main(void)
{
* * *** * *** A[100],B[100];
* * * ** ***** * * %s",A,B);

* * * *** **** * ** (is_anagrams(A,B)) ** ** words or phrases are anagrams");
** *** ** * * *** printf("Two words or phrases are not ***** *

*** *** ** ** * * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * **
#include * ** * * **
#include *** ** ** **
int is_anagrams(char A[],char B[])
{
* * ** * * ********** ****** lenA = strlen(A),lenB = strlen(B),i,j,k;
* **** * * * ** *** a = 0,b = 0;
**** ***** ** * ***** ****** != lenB)
* ** * * ** ** * * *** * *** * ***** ** * * 0;
* * * * * * * * * = 0 ; k < 26 ; k++)
** ** * ** ******* *** *
* ***** ** ** ** ** * * * * * * ***** * * = 0 ; i < lenA ; i++)
**** ** * ** ** ******* * * ** ** ****
**** * *** * * ** **** * ****** ** *** * **** ** * ** **** ** * == A[i] || 'A'+k == A[i])
***** * *** *** ** * **** ** **** * ** **** *** ** * * * **** * *** * *** * ***** **** **
** * **** ** *** * * ** ** * ***** **** *
* * *** ** ** **** * * * * ** *** * **** = 0 ; i < lenB ; i++)
** ** * **** * * *** * *** * ** ** **
* ** ** * ** *** * * ********* * ** * * * * * ** * * * == B[i] || 'A'+k == B[i])
* *** ***** * * ** * ** * * * *** * * * * ******* * *** ** * **** * *** * *** * * * *
* **** * ** ** * * * * *** *** ** **
******* ***** *** *** * * * * **** * ** * *** *** *** * != b)
* ** * * * **** ** * * * **** * * *** * * * ** *** 0;
* * * * ** * ** * ** * *
* ** ** ** * **** ** ** **** * * * ** ** *** * ***** ** * ***** * 1;
}

int main(void)
{
** * **** * ** A[100],B[100];
* * * * * ***** * * * *
***** * * * * * *** ** * *
*** **** * ** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ** *** * ** * printf("Two words or phrases are not anagrams");

*** **** * ***** * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *
#include ***** ** **
#include *** * * *
int is_anagrams(char A[],char B[])
{
*** * ** ** * ** * YOUR CODE HERE*/
*** ***** * i,count[256]={0};
*** ** * * ** ** *** * *
* ** * * ** ** * * *
* *** * ***** *** *** ** ** * ** * ** ** * ***** *** **** * * * *
* * ** ** * * **** ****
* * *** **** * ** * * * * *
** * ** *** * **** **
* *** * **** * ***** *** ** * * **** * ** * ** **** * * **
* ** * * * ** * **
/*
* * *** * * ** * (A[i]!=0 || B[i]!=0){
****** ** * * **** *** * ** * * ** *** ** * *** **** *** *
* *** * **** ** ** *** ******* *** * ** * 0;
** ** * * * * *** * ***
*/ * ** * ** * ** * * * ** 0;

* ** * * * *** *** * (i = 0; i <256 ; i++)
* * ********* * **** ** * *** ** ** * * (count[i] && i!=' '){
* * ** * *** **** ** ** * ** ** ** ***** * *** * * * * ** ***** *****
** ** * *** * *** ** * * * * *** * **** ** *** ** * **** ** ** * * ** * * 0;
* ** **** * *** *** * * * ** * * ** ** *


* * * ** ** ** ***** * 1;

* ***** ******** ** * OF YOUR CODE*/
* ** **** * * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
***** ** ** **** A[100],B[100];
* * *** ** ** * YOUR CODE HERE*/

* * ** ** * **** * * * ** * *** *
* **** *** ** * ***** * * **

* ***** *** * ** ** * = '\0';
  // * * * * = '\0';
** * ** ****** * * * * i;
** * * * *** * ******* * *
****** ** ** * * * * ** *** ** * * ** ** * *** * * * * * ** * * * * *
** * ** * * * ** * ** ***** *** ** *** * * * *
*** * * ** ** * * * * **
** * * ************ ** ** * **** *** ** * ** * * * * ** * * * *
** *** ** * ** * * ** * ** **** * *** * * * * *

*** * * ** *** ******* * OF YOUR CODE*/
* ****** * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ** * *** ** * ** * printf("Two words or phrases are not anagrams");

* *** ** *** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** *
#include * *** * *****
#include ** * * *
int ** * ** A[],char B[])
{
** * * ** *** ** * YOUR CODE HERE*/
* ** * ** ** ** **** * * **
* * **** * **** * ** ** ** * * * ** *
** * ** * * ** ** *
**** * * *** ***** * **** ** * * ** **** * * **** *
**** * * ***** ** ** *** **** ** * * * * * ** ** *
** *** * * ** ** ** *** * *
** * * **** * ** *** * (A[i] || B[i])
* * ** *** * ** * *** * *** *** 0;

**** * * * ** * (i = 0; i < 256; i++)
** ** * ** * *** **** ** ** ** * *** ** **
** * *** ** ** *** ** * * ** *** **** * * * * ** * ** * 0;
** ** ****** * *** * * 1;

**** **** * *** OF YOUR CODE*/
** **** ******* ***** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** *
{
* * *** *** * * ** * *
* *** ** *** ** * ** ** YOUR CODE HERE*/
** ** ****** * * ******** * * * **** * * *
** ****** * * * ** ****** ** * * * * * *** * **

* ** ********* * * * OF YOUR CODE*/
* ** *** *** ** ***** * * **** * ** words or phrases are **** * * ****
** ** *** **** **** *** words or phrases are not ** ** *

* * ** *** * ** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * ****
#include * ** * *
#include * ** * ******
int ** * * A[],char B[])
{
* ****** * * **** * YOUR CODE HERE*/
**** * ***** *** ** * * * * **
* ** ** * ** ** * * * * * * **
* ** * ** * * *** *
* *** *** * *** ** * * * ** ** *** * * **** * ***** * *
* ** * *** *** ** **** * * * * **** ******* **
** * *** ** ** ** ***
*** * *** * * *** (A[i] || B[i])
*** **** * *** * * * ** ***** **** 0;

* **** **** ** *** (i = 0; i < 256; i++)
*** ** ** **** * ** * * * ***** * * *** * * ** *****
* * ** * **** * ** ** * ***** ** * * *** ** * * * *** ** ***** ** * *** * * 0;
*** * * * *** * * * 1;

* ***** ****** OF YOUR CODE*/
* * * ** * * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *** *
{
** ** * ** * ** ***
** * ** *** ** **** YOUR CODE HERE*/
* *** ************ * * * ** * * * * * * *
** * *** * * * ** * **** * * *** *** *

* ** * ** * OF YOUR CODE*/
* * *** ** ****** **** ** **** * * words or phrases are ** * * ****
***** * ** ** * **** ***** * words or phrases are not ** ** * *

* * *** ****** * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.120
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.2k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.6k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users