0 like 0 dislike
3.5k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 3.5k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * *** * *
#include *** **** *
#include * * * * *
int ****** * * a[],char b[])
{
* * * ***** * first[26] = {0}, second[26] = {0}, c = 0;
* * *
** *** * * ** * ** *** * frequency of ** * in first string
* *****
* * ** *** *** ** (a[c] != '\0')
***** * * *** * *
*** **** ** ** ****** ** * * * ** ** ** *
* * *** * ***** ** * ** *** ***** *
**** * *** ** *
* * * *
* * ** * * ** ** * * = 0;
* *
** ** *** * (b[c] != '\0')
** ** ******* *
*** * *** **** *** * ** * *** * * * *
** ** * * * * *** **** * * * * * ** * ** **
* ***** *** ***** *
* * **
* * * **** ** Comparing frequency of * ***
* * *
** * * ** (c = 0; c < 26; c++)
* * ** * * *
*** ******** * ****** ** * *** (first[c] != second[c])
**** * ** * * ** * ** * ******* **** ** * * **** * * * * 0;
********* * *** * **
* *
** ** * * ****** 1;
}

int *****
{
* ** *** * * *** **
**** ** * ** ***** ** * *** * * A,B);
* * *** ** * ** * * * * *** ** * * words or phrases are ** ** * * *
***** ** * * ** * * * ** * words or phrases are not * ** * **

* * ** ** * * * **** ** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * **
#include ** * * ** * *
#include ****** ***
int **** a[],char b[])
{
* ** *** * * ** first[26] = {0}, second[26] = {0}, c = 0;
*** *
*** * ** ****** *** ** frequency of characters in first string
*
**** * * * **** ** * (a[c] != '\0')
* * *** ** *****
** * * * ** * * *** * * * ** ** ******* *
*** * * * * *** * **** ** * ** * **
* * * * * *** *
* *
*** *** *** ** * = 0;
**
*** * **** ** ** ***** (b[c] != '\0')
* * * * *******
* * * * ** ***** *** *** ** *** ** ** *
* * *** * * ***** *** ******** * *
**** * * * ***
* ** **
**** * ** ** * Comparing frequency of *** **
*** * *
* * * * * * * * * ***** (c = 0; c < 26; c++)
* ** * ** **
****** * * * ** *** *** **** * (first[c] != ****
** * ** ****** * * * *** *** * **** * * *** * * 0;
**** **** ** * *
***
**** **** * * * 1;
}

int main(void)
{
** ** * **** * * ***** *
* * *** *** ** *** * ** ****** * *** ** * **
** * **** * * * * * * * * * * * words or phrases are * * * *
** * ** *** * ** *** * * * * * * words or phrases are not * * * * *

* ** ** **** * ***** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * ***** *****
#include ** **** ** * *
#include * * ** **
int is_anagrams(char A[],char B[])
{
* * *** ** * ** **** ** YOUR CODE HERE*/
* * * * * * ** ** * * ** * ** * ***
*** **** ** * ** * * * * ** * *
* * ** ** ** *** ***
* * ** ** * *** ** * * ** * * ** *** * * *** ** * && **** ******* **
**** * * *** * ** * * ** * * ** * **** *** *** ** ** * ** * *** ** **
* ** * * ***** ** * *** ** * ** ** ** * *** * *** * * && * ** ** ** * **
* *** *** * ** * ** ** ** **** ** * * **** * *** * ** *** * * ** * ** *
* ** * ** * *** *
* * * *** ** ** * * * ***** *
* ***** * ** ** ** *
* *** * * ** ** ** **** * * ** * * ****** (cA[i]!=cB[i])
*** ***** ***** * *** * * * ** ** *** * ****** * ** **** *** * ** ** 0;
* * * * * * *** *** *
** ** ** *** ** **** *** * 1;
** ** * ***** OF YOUR CODE*/
***** * ** ** * *** * * function should return 1 if two words or phrases are anagrams,
*** **** * * if two words or phrases are not anagrams.
}

int main(void)
{
* * ** * * * A[100],B[100];
** ******* *** *** ** ** YOUR CODE HERE*/
* ** ** **** ** * ** * **** * ** *
* * ********* ** **** * * ** * **** *
* ** ** ** **** * * * *** * (is_anagrams(A,B))
* * *** ** ***** * *** ****** * ***** * * * * ** words or phrases are anagrams");
* * * * ** ***** * *** ***
*** * ** **** * * * ** * ** * * ********* ** words or phrases are not anagrams");
* * *** * * *** *** 0;
** * *** ** **** * ** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * ** * * * * * * *** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ** * *** ** *
* * * * ** * * * * (A[i] != '\0')
* * **** ** ** *** * ** * *
*** **** * * **** * * ******* **** * ** *** ******** *
** ** * ** * * **** **** * ** *
** *** ** *** *
* * * * * ** * * * * **
* * ***** * * ** ** = 0;
*** ** ** * *** **
* ** * * ** * ** ** ** (B[i] != '\0')
*** * * * ** *** * ** *****
* ** *** **** ******** **** ******** * *** *** *** * *
* ** * ** *** ** **** *** * ***** ** ** ***** ***
* ***** * * ** ** ** * *
    
** ** * ** *** (i = 0; i < 26; i++)
******* * *** ***** *****
** ** ***** * ****** * * * **** * * *** (Array1[i] != Array2[i])
* * * * ** *** ** **** **** **** ** * * ** * * ** **** * * * * * * * ** 0;
** ***** * * *** *
* *** ** ** * * * ** *
* * ** * * * * *** ** * 1;
}

int main()
{
* * * * **** * * ** A[100],B[100];

** ** **** **** * ** **
* ***** * * *** ** ***** ** ** *
** **** * * * **** * *
* * *** * * ****** **** * (is_anagrams(A,B))
***** * ***** * *
** ** * * * *** * * * ** * ** ** * * **** *** ** * words or phrases are anagrams");
** * * ** * * * ***
*** * ** ** * * ** *** * printf("Two words or phrases are not anagrams");
* *** * * * * ****
*** * *** * * *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * ** ***** * * ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * ** * ** * *
* * **** *** ** ** * (A[i] != '\0')
**** ******* * * ** *
** * ** ** * * ** * *** * ** * *** * * * * ** ** ***
** * ** * *** ** ** * * * *** ** *** **
* * * * ***** ** ** ***
* * ** * * ** *** *
**** * *** * ** ** = 0;
* ******* * * * * * *
* * * *** **** ****** *** * (B[i] != '\0')
* ** * * * *** * * **
*** ** *** * * *** ** * * * * ** * ** ** * *** ** *****
* *** ** * ** ** * ** * * * *
* ** ** * ** **** *
    
**** * ** **** * ** * (i = 0; i < 26; i++)
**** * * *** * * ****
* *** ** * * ******** * *** ** * (Array1[i] != Array2[i])
* * **** *** *** * * **** * ** ** ** * *** * * *** ** ** *** * * * 0;
* * * ** ** ** ** * **
** ** * *** * ****
*** * * * * * * ** * * 1;
}

int main()
{
*** ***** ** * A[100],B[100];

** * *** * ** * * * ***** ** ** * * * * *
* ** * * ** * * * ** ** * *** ****** **
* ** * * * * *** * ***** * ***
* ** ** ** * * ** * * ** * (is_anagrams(A,B))
*** * * * ***
* * ********** ** * ** * * * * *** * ******* * **** words or phrases are anagrams");
* * * * ** * *
* * ** * * * **** ** printf("Two words or phrases are not anagrams");
** * * *** * * *
* ** * * ** *** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** ****
#include *** ** ** *
#include * * **** * *
int is_anagrams(char A[],char B[])
{
* * ** *** * ** * * lenA = strlen(A),lenB = strlen(B);
* ******* * * * * * * ** != lenB)
* ** * * * * **** * * *** * * * **** * 0;

* *** ** *** * ** ** * i,j,k,a[26] ={0},b[26] = {0};
* * ** * ** ** * * ** * = 0 ; i < lenA ; i++)
**** * * * ** * * ** ** *
* **** * * * **** ** * ******* ** *** * * *** ** = 0 ; j < 26 ; j++)
** ** *** ** *** * * ** * * *** ***** *
* ** * *** *** * * ***** ***** * ** * ** *** * * * * ** * == A[i] || 'A'+j == A[i])
** * * * * *** ** ** *** *** * ** ** * * * * ***** * ** * ***** ** * ** * * *
** * * * * ** ** * * **** *** * ** ** **
* * * * ** * ** * *
* * ***** *** * * **** * * = 0 ; i < lenB ; i++)
** * ** ** * * *
** * * ** ******** ******* ** * * **** * * * ** = 0 ; j < 26 ; j++)
* ** * * *** *** * * * * * ** ** * * ***
**** *** *** ** ** ** * ** * * * ** * * ***** ** * *** * ***** * * * *** * * == B[i] || 'A'+j == B[i])
** * *** *** ** ** ****** * * * ** **** ** ** * *** * ** * ** *** ** * * *** * **** **** *
*** * * * * *** *** *** ** *** * *** * * * *
** ** * ** *** * *** * *
** ** ** ** * * * ** ** = 0 ; j < 26 ; j++)
*** * * * * *** * **
* ** * * ** * *** * ** ** ** **** * * *** != b[j])
** * ** ** ******* ** * *** ** * *** * * * * ** ******* ** * ** 0;
* * * **** *********** * * *
* ** * **** ** ** * 1;

}

int main(void)
{
* * * ** * ** * A[100],B[100];
* **** * ** ** * **** *** %s",A,B);

* * * **** ** * (is_anagrams(A,B)) * * ** *** words or phrases are anagrams");
***** ** *** * * printf("Two words or phrases are not * * *

* ** ** * * ** *** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *** ** *
#include * * ** ***
#include * * ***
int is_anagrams(char A[],char B[])
{
* ****** * ** *** ** * * * lenA = strlen(A),lenB = strlen(B),i,j,k;
* ** * * * ** ** * * * * a = 0,b = 0;
******** * * * * ** * *** != lenB)
* * * * * * **** **** ******** ***** * *** * 0;
*** * ***** * * * * *** = 0 ; k < 26 ; k++)
* * *** * ** * ****
* ***** *** ** * ** ** * * * ** ** * * *** = 0 ; i < lenA ; i++)
* *** ** *** * * * **** ** * *** ** ** ** *** *
** * * **** *** ** *** **** * ****** * ***** *** * **** * ** * ** ** *** ** * ** ** * ** * == A[i] || 'A'+k == A[i])
* ** * ** * * *** * * *** * ***** ** ** ****** ** * *********** ** *******
* ***** * * ** ***** ** **** ** ** * * * *
**** ****** ** * * *** * * * ** ** * * ***** ** = 0 ; i < lenB ; i++)
* * ** *** ** *** * * ** ****
** * * * *** ** * *** * ** *** * ** ** *** ** ** * * == B[i] || 'A'+k == B[i])
* * ** * ** * * * * **** ** * * ** * *** **** **** ** * ******* * * *
* * ** *** ** * * ** ** **** * * * **** *
* ** ****** * *** * * *** * *** * * * ** * ** * != b)
** ********* *** ** * ****** * * ***** * ** * ****** ***** **** *** ** ** * 0;
**** **** ** * ** *** ***
* * ** ** ** ***** * *** * * *** ********* * * * ** *** ** * 1;
}

int main(void)
{
***** * ** *** * ** A[100],B[100];
* * *** * * ** * ** ****
* * * * ** * ** * * **
* *** *** ** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** * * * ** ** printf("Two words or phrases are not anagrams");

* ** ** ** * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * *** ****
#include ** * * ** *
#include * * ** * *
int is_anagrams(char A[],char B[])
{
** * ** * **** * * * ** YOUR CODE HERE*/
* * *** * * ** * * *** i,count[256]={0};
***** * * * ****** * * * **
* ***** * * * * ** *
*** * *** * * ***** ** ** * ****** * * * ***** ** * ** * * * * *** * **** *
** * * **** * ** * **
** *** * ** *** * *
********* ***** * **
*** ** * ** ******* * * * *** ** *** * * **** ** * * * ** ** * * *** ****
* ** * ** * * * *****
/*
** * **** * ** * ** * (A[i]!=0 || B[i]!=0){
* * ** *** ** *** * * * ** * ** * * **** *** ***
*** * * * ** ** ** * ** * * * ** * ** * * ** 0;
* ** * ** * * ** * *
*/ ** ***** *** **** ** *** * *** 0;

** * * * * ** * ** **** * (i = 0; i <256 ; i++)
* * *** * * *** *** ** *** ******** **** * * ** (count[i] && i!=' '){
* * **** * ** ** *** * **** ** * * ** * ** * * * * * ** ** * ** ** * * * * * ** ****
*** **** * ** ** **** * * * * * * ** ** **** * ** ** * * *** 0;
**** ******* * ** **** * *** * *******


* * ** ** **** * ** ** ** * 1;

* * *** * * *** * * OF YOUR CODE*/
**** * ** * * ** *** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * * **** ** * A[100],B[100];
***** **** * **** **** YOUR CODE HERE*/

** * *** **** ** ** * * * * ****
* * ** * * * ***** * **

* ** * *** **** * ***** * = '\0';
  // *** ** *** * = '\0';
* * * * **** *** * * i;
* ******* *** **** * *** * **** *
** *** ** ********* * **** **** ** * ** *** ****** ** ** * * *** ** ** * ** * *
****** * * * * **** ******** ** *** * ****
* * *** *** ** *** * * ****
** ** * * **** * * ** *** * * **** *** * *** * ** * * * ** *
* ** * **** ** ** * ** *** *** **** * * ****

* * ** * ** *** OF YOUR CODE*/
* * * * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** ** * *** printf("Two words or phrases are not anagrams");

* ** *** * ** * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** **
#include ** * * *
#include ***** ****
int ** ** * A[],char B[])
{
** *** ** * * *** ** *** * YOUR CODE HERE*/
* * * ** * ** * * ** * *
* ** ** *** * *** * *** * ** * * * ** ** **
***** ** ** * ** *
*** * ** * *** * ** * * **** ** * ** ****** ** ** *
***** ** * *** *** * * ** ** * * ** * *
** * * *** ** ** * * **
* * * ** * ***** * (A[i] || B[i])
** *** **** **** ***** *** **** ** * 0;

*** ** * * * * * * * * (i = 0; i < 256; i++)
** **** * ** ***** * * ** ** ** * *** * ** **
**** *** ** ** ** *** * *** * **** ****** * * * * * *** 0;
* * * ** ****** * 1;

* *** * ** *** OF YOUR CODE*/
** * * * **** * * ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *
{
** * * * ** *** * **** *
** *** ** ****** * * * YOUR CODE HERE*/
* *** ** ** * * *** * * **** * ***** * * *** * *
*** * * * *** * *** ** ** * * * * * * * **** *

**** * ** * ** ** ** OF YOUR CODE*/
** * ** * * * * * * * * * * *** * words or phrases are * *** **
** * * * ****** * * *** words or phrases are not * ** *

*** ** *** * ** ** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** * ****** *
#include ********* ** *
#include ***** ** ***
int ** * A[],char B[])
{
** ** **** * * * * * YOUR CODE HERE*/
* * *** * ** **** * * * **** ***** *
* ********* *** ** * ** ** ** *** * ** * ** **
* * ** **** ** ** * *
** ******* * * *** * * * *** ** * * ** *** **
* * ** * * * * ******** ** * ** ** ****** * **** *
* ** *** * * * * * *** * *
* ** *** * * **** (A[i] || B[i])
* *** ** * * *** * * ** * * ** ******* 0;

* **** * *** ** * (i = 0; i < 256; i++)
* * ***** * * * ****** * **** * * * *
* ** *** ***** * * ** *** * *** * * * ** ****** ***** * * ** ** * * *** 0;
** * * * ** * **** 1;

* *** * ** OF YOUR CODE*/
* * * * *** ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
* * **** * * * * * * ** *
* * * *** ****** * YOUR CODE HERE*/
* * **** ** ** ** * * *** * **** *** ** ** *** *
* *** ** * * ***** ** * * *** * **

** *** * * * OF YOUR CODE*/
**** * *** * * * ** * * * * * ** * ** words or phrases are * *** ** *
* ****** * * ** * *** * * * words or phrases are not *** *** *

* * * ** * * * *** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.175
©2016-2024

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 1.5k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 2k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 1.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users