0 like 0 dislike
7.4k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 7.4k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ** *** ** * * **
#include * * * *** **
#include ** * *****
int *** * * a[],char b[])
{
** * ** **** * * first[26] = {0}, second[26] = {0}, c = 0;
**
* * * * ** * ** ** frequency of * in first string
* * **
* * * * (a[c] != '\0')
* *** ***** **
* * ** * * * * * ** * ** *** ** ***** * *
** * * *** * * * * ** * * * ** * * * * *
** * * ** * * **
***** *
***** ** ******* * = 0;
*** *
* * ** ****** ** ** (b[c] != '\0')
* * * * ** * *
****** ** * ** *** * ****** ** *** ** *****
** * *** * *** * ** ** ** **
** ** * ** ****
****
** * * * ** ***** Comparing frequency of *
* **
* * * * * ** * * (c = 0; c < 26; c++)
** * * ** ** ** * ***
* * ** * ******* * * ** ******* ** * (first[c] != second[c])
* * * * ** ** * ** * * * ** * ** * * * * * * * * * 0;
* *** ** * *
* ***
* * **** ***** * * 1;
}

int ** *
{
*** *** *** ** * * ** ** ** **
*** ** *** ** * * ** * * * ** ** A,B);
*** * * ** * ** ** * *** * * ** words or phrases are ** * * *** **
* ** ******* * * **** *** * *** words or phrases are not ** ** * *

*** * ** *** * *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * *****
#include * ** **** *
#include ** ** ** * **
int * ** ** * a[],char b[])
{
*** ** * * ***** first[26] = {0}, second[26] = {0}, c = 0;
*** *
* * *** ** *** * ** frequency of characters in first string
* *
*** **** * * ** (a[c] != '\0')
** *** * * *
** * * * * ** * * * * * ** *** ** *** * ***
*** ** ** * * * * * ** * * *
** **** *** *
* * *
*** * * *** *** = 0;
**
* **** * * **** (b[c] != '\0')
* * ** **** ** *** ***
* * ** ***** * * * ****** **** * * * ********
* * * *** ** ** * * *** ******* **
* *** * * * *
* * *
** * * * *** Comparing frequency of ** **
* *
* ** ** * **** (c = 0; c < 26; c++)
** *** * ** *
**** * ***** * ** *** ** * * * *** * (first[c] != ** *
* *** ** ** **** ** * ** * * ** * * ** * * ** *** 0;
* ** * *** **
* **
* ** * * * * ** 1;
}

int main(void)
{
* * * **** ** * * ***
**** **** *** ** * ********* ** *** * * * *** ** * *
**** * * * * * *** ** * ** * words or phrases are ** *** *
** * * * ** * * ** ** words or phrases are not ** * * **

*** ** * * * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * *** * * * *
#include * * **** * *
#include ** ** ** *
int is_anagrams(char A[],char B[])
{
** *** ** * ******* **** YOUR CODE HERE*/
** * ** ** *** *** * *** ** ** * * * *
* * * *** *** * ** *** * * * ** *** *
* ** * ** * *** ****
** * * * ** ** *** * * * ** * *** * *** ** * * && ** * ** ***
** * *** ** * ** ** ***** ** ** *** * ** * * * *** ***** * * * * *** ****
* * ** *** * * ** * * * * ** * ** * * ***** * ** ** && * *** ** *** * **
*** ** * * * ** * * * * * ** ** **** * ** * ** *** * ** ***** * **
* * * * ** *** * * **
******* **** * *** * * *
** * *** ** * ** * *
*** * * *** * * ** ***** * * *** *** * * ** ** * * * (cA[i]!=cB[i])
* **** * ** ** ** ** *** **** *** * * ** * * * ** ***** **** 0;
* * * * * *
* * * * * * * ** * * ** 1;
**** *** * * OF YOUR CODE*/
* **** ** **** *** **** function should return 1 if two words or phrases are anagrams,
*** * **** * **** if two words or phrases are not anagrams.
}

int main(void)
{
** * ****** * ** * * A[100],B[100];
* * *** * * * YOUR CODE HERE*/
** * *** ** * *** * * * ** ** * ** ** *
** * * * * * **** ** * * **** *
** * ***** * ****** * ** (is_anagrams(A,B))
*** ** ** **** * ****** * * * * * **** * words or phrases are anagrams");
*** * *** *** ** *** *
** * * ** ** **** * **** * ** * * * ** ** words or phrases are not anagrams");
** ** * ** * *** *** 0;
* * ** * * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** * ** * * * ******* Array1[26] = {0}, Array2[26] = {0}, i = 0;
*** ** ** * * * * *
* * * * * * * *** ** (A[i] != '\0')
* * ** * * * **
*** * *** ** ***** ** ** * * ** ** *********** ***** **
* * ** ** * ****** *** *** ** * * **** * * *
*** * * *** ** ** ** * **
* ** ******* * *** **
** ******* * ***** ** * * = 0;
* ** ** * * * ** **
***** * * * * *** ** (B[i] != '\0')
* ******* ***** ** *
* * * ****** ** * * * * ** *** * * *** * *** **
**** *** * ****** * * ***** * * **** ** *** **** **
* ****** * ** **** ***
    
* *** ****** * * ** * (i = 0; i < 26; i++)
* * * * * * **** *
** * * * ** ** ** * ** ** ** * ******* (Array1[i] != Array2[i])
** *** * * *** * *** * * ****** * * * * * ** ** *** ******* * ** ** 0;
* * ** ** *** * *
**** * *** ***** * * **
** *** * **** *** *** 1;
}

int main()
{
* *** ** ** * * ** ** ** A[100],B[100];

* **** *** * ** *** * * * *
**** ** * * * **** * * * **** ** *
*** * * **** ** * ***
*** * ***** *** ******** * (is_anagrams(A,B))
* * * * ** ****** *
**** * * * ** ***** ** ** *** ** *********** * words or phrases are anagrams");
* * * ***** * * * ***
** ** * *** * * * * * * * * * printf("Two words or phrases are not anagrams");
***** *** ** ********
* *** * **** * * **** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * ** * **** ** * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ** * ** * *** * ** *
*** **** * ** * * ** * (A[i] != '\0')
**** ** ** * ** *
** *** ** * * * * *** *** ** * ***** ** * ** * * *
* ** * * * * * **** * * *** ** *** *
* ** * ** *** ** ** * * *
* * *** *** ***
*** * * ** ** *** **** = 0;
*** * * * * ** ****
** ** ** * * ** ** * (B[i] != '\0')
* **** ** * *** *
** * ** * * ** * ** * ** ** **** ** * **** * *
* ** * * * ** * * ** **** ** *** *****
* * * ** * ** ** *
    
** **** *** ****** * *** (i = 0; i < 26; i++)
* *** ** ****** * * ****
* **** * * * * * * *** ****** * ** * * * * (Array1[i] != Array2[i])
*** * * **** * * ** *** ** * * * * ***** * ** ** * ** * * **** * *** 0;
* * **** **** * ** ****
* *** **** **** *
** * * **** * * * * ** * 1;
}

int main()
{
* * ** * * * * * ** A[100],B[100];

* * ** ** ** * * * ** * * *** ** *
** ** * *** ** ** ** ** * ** * * *** *
* * * * *** **
* *** * ** * ** * (is_anagrams(A,B))
* *** ** * * * * ** *
** **** *** ** * * * ** * * ** * * * * *** * ******* words or phrases are anagrams");
* * **** * * ****
* ** * * * *** ********* * printf("Two words or phrases are not anagrams");
**** * ** **** ** *
** * ** * ** * * *** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** *
#include ** * * ********
#include * *** ***
int is_anagrams(char A[],char B[])
{
* * ****** * * ** ** * * lenA = strlen(A),lenB = strlen(B);
* * ** ** ****** *** ** != lenB)
*** ** ** * *** * * *** * ** ****** 0;

** * *** ****** * i,j,k,a[26] ={0},b[26] = {0};
* * *** * ** *** *** * = 0 ; i < lenA ; i++)
* * ************ **
*** * *** * ** * * ** ** * * * ** * = 0 ; j < 26 ; j++)
* * *** * ***** * * * ** * ** * * * * * ** * **
* * * * ** **** ** * ** * * * ** * **** **** * * ** **** ** == A[i] || 'A'+j == A[i])
* ******* * ***** *** * * * ** ** ** **** ***** ***** ** * * ****** * ** ** ****** *** *** * ** *
*** * *** * ***** *** * ** ** * ** ** ** *
*** * ** * ** ** *** * ********
* *** * *** ** = 0 ; i < lenB ; i++)
** * * * * * ******
***** * **** *** ** * * **** ** * *** ***** = 0 ; j < 26 ; j++)
* ** ** * * * * * **** ** *
* * ** * * * ** * * * * ** * * *** ****** * **** * == B[i] || 'A'+j == B[i])
* * * ** * * * *** **** * * *** * **** ** *** ** * * * ** * *** * * * * ** *** *
* * * *** ** * ** *** ** * *** *** * ** ***
* *** * * * * * *
* ** * *** ** * * = 0 ; j < 26 ; j++)
*** * ** * ** ****
****** ** * * * * * ** ***** * * *** != b[j])
* * ****** ** **** ** ** *** ** * **** * ****** * ** * ** ** 0;
* ** * ****** **
* *** *** ** *** * **** 1;

}

int main(void)
{
* **** * * * A[100],B[100];
* ** ** *** **** * %s",A,B);

**** * ** ** * *** * (is_anagrams(A,B)) * **** * *** words or phrases are anagrams");
** *** * * ** * ** ** printf("Two words or phrases are not ** * * * *

* **** ** * * * * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** ** *
#include ***** * ** ****
#include *** **
int is_anagrams(char A[],char B[])
{
* * * * * ******* * ** *** * lenA = strlen(A),lenB = strlen(B),i,j,k;
* * **** * ** * *** ** * a = 0,b = 0;
* * * ***** **** **** * != lenB)
* * * * * ** * ** **** * *** * * * 0;
** ** ** * * * * * = 0 ; k < 26 ; k++)
** * *** ** * * *****
**** * * *** ***** * * * * * ** * * ** * * * = 0 ; i < lenA ; i++)
* ** ** ** * *** * * * * * * * **** ** *
* ** ** * **** ** *** ****** *** *** * * ** * * **** * * * **** == A[i] || 'A'+k == A[i])
* * * ** *** ** * ** ** ** *** *** *** **** * * **** * * *** * * ***** * * *
* * * * *** ** * * ***** * *** ** *
* ** ** * * ** ** *** *** * ** ** * **** ** = 0 ; i < lenB ; i++)
* * * * * * * * * ***** * * **** ******* * *** *
* * * ** ** ** * ** * ** ** ***** * * ** *** * * * * * * ****** * * == B[i] || 'A'+k == B[i])
** *** *** * * ** * * *** * ** * ** *** *** *** * ** *** * * * * *** * * * *
* ** **** *** ** ****** ** *** * * * * * **
* ** * * * ** ***** * * * ** ** ** * * ** != b)
* * * ** ** * **** * * * *** ** * ** *** ** **** ** ***** 0;
* * * ****** *** *** **** *
**** *** * ** ********* * ** * ******* * ** ** * ***** * ** ** * 1;
}

int main(void)
{
*** * * * * A[100],B[100];
*** ** ** ** ***** * ** ***
* ** *** ** * ***** ****
* * * * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * ** * * *** * * printf("Two words or phrases are not anagrams");

* ** * ** *** * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ******* ***
#include * **** * ** * **
#include * *** ****
int is_anagrams(char A[],char B[])
{
*** *** ** *** ***** *** ** YOUR CODE HERE*/
* * *** *** * ** * *** i,count[256]={0};
** *** * *** ** * ** * ** **** *
* * * * * * ** ***** *
** * * ** * * * * * * * ** * ** * * ***** * * * * * ** * * * * **** ** ** *
** * * * * ********
** * * ** * ** *** ** **
* * * * *** *** *
* ** * * * * **** **** * ** ** ** ** * *** *** * * * * ** * **
*** * ** * *** ** ***
/*
*** * ** * * * ** * * (A[i]!=0 || B[i]!=0){
** * *** * * ** * * ** * * * * *** ** ***** *** **
* * *** ****** * * * * * ** ** *** *** 0;
***** * ** ** ** * ***
*/ * * ***** * * ** * ** **** * 0;

** *** ** ** ** ** * (i = 0; i <256 ; i++)
*** **** ** * ** * * **** * ***** ****** * *** (count[i] && i!=' '){
* ** ** * * * * ** ** ** * ** * **** ** ** **** * *** * ** **
* **** ** **** * * ** * * ** * ** *** * *** * **** ** ****** * ***** 0;
* ** ** **** *** * * *** * ** * **** * *


* * ** * * ** * **** * * 1;

** ** ***** * * * ** OF YOUR CODE*/
* *** ** ** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* ** * ** ** ** * A[100],B[100];
* * * * * * * * ** YOUR CODE HERE*/

* *** ****** * * * * * * ** ** **
*** ** ** * ***** * ***

* * ** * * ***** * * *** * = '\0';
  // * * ** ** = '\0';
*** * * * * ** **** i;
** * *** * ** ** * * * * ** **
* ***** ** *** ** * * ** *** * * ** *** ** * ******* *** **** *** * *
* **** * * ** * * *** **** * ** ** ** * * **
*** ** *** * * * * * ** ** *
* ***** * **** *** ***** ** * ** * ***** * * * ***** * ******
*** * ****** ** * * *** * **** ** * ****

* *** *** ** * **** OF YOUR CODE*/
* **** * ** * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** * * * * **** printf("Two words or phrases are not anagrams");

* * * *** * **** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** *** *
#include *** **** * * *
#include *** * *****
int * A[],char B[])
{
* * * ** *** * **** ** YOUR CODE HERE*/
**** * ** *** * * *** * *** **
* ******* ** ** ** ***** * *** * *** *** ******
* * * ** * *** *** *
** ** *** *** *** ** ** ***** * * ** **** ** ** *
** ******** * ** ** ******** *** * ** *******
* ** * * ** * * * **
* * * ** **** * ** **** (A[i] || B[i])
** *** * ** * ** ** ** * ** * 0;

* *** ** ** ** (i = 0; i < 256; i++)
* ** ** * **** * *** * *** *** * * * * * * *
* *** * * ** * *** * * * *** * * * *** ** ** * ** **** *** ** * ** 0;
** ** * * * * ** ** * *** ** ** 1;

* * * * ** * *** * * OF YOUR CODE*/
** * * * * ***** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ***
{
*** ** * ** *** ** * ** * ***
** ** * * * *** * * ** YOUR CODE HERE*/
* ** ** * * ** * * ** * * *** * *
* ** * ** * * * ** **** * **** *

***** * ** ** * * * OF YOUR CODE*/
* * ** * ** ** ** * * * ** *** * ** * words or phrases are * * ** ** * *
* * * * ** ** ** * * words or phrases are not * * *

*** **** ** **** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * ** ** **
#include *** * * *
#include * * * *** **
int * *** * * A[],char B[])
{
*** ***** * * ** * ** YOUR CODE HERE*/
* *** *** *** ***** * * * * ** * *
* ** * * ** * * * *** * * *** ** * *** *
* * ** ** * * ** *
***** ** * * * * * * * **** * * * * ** ******* * *
* *** *** * ** * * * ** ** * * * *** ** * * ***** *
** ** * * ** * * ********
*** * ** * ******** * * (A[i] || B[i])
* * *** **** * * ** * * * * *** 0;

* *** ****** * ** *** * * (i = 0; i < 256; i++)
** ** * ***** ** **** * ** * ** ** **
** * *** ***** * ** *** ****** ** ** ** * ** * *** ** ** 0;
* ** * **** * ****** 1;

** *** ** * * ** OF YOUR CODE*/
* * ** * * ** * **** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * * **
{
* * * * *** ** *** ** * *
*** * * *** * * *** ** YOUR CODE HERE*/
*** *** * * ** *** *** * * ** *
* * ***** * * * ** * ** ** ** **** *

** * ** * * * ** * * OF YOUR CODE*/
* * *** * ** * * ***** * * * * ** ****** words or phrases are * * *
* * * *** **** * *** *** * words or phrases are not * *** ** **

*** * * * * *** * ** *** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.120
©2016-2024

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 3.6k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 3.8k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 3.2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users