0 like 0 dislike
11.4k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 11.4k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
int p;
**** * * ** * ****** *
* ** * * * * * ** * *
    {
*** ** ** * * *** ** * ** ** *** ** ** ** ***
    }
*** ** *** * * ** *** ** * if(q==2)
    {
* *** * ****** ** ** *** * * *** *** * * * * * ** ** * *
    }
***** ** *** *** ** **** if(q==3)
    {
* ** * * ** ** * * * ** *** * * * * * *** * ** ** * * ******** *
    }
* ** * ** * ***** ***** ** * if(q==4)
    {
* ** * *** ** ***** * * **** **** * * * ** ** * * ** * ***** *
    }
** *** * *** ** * * * *** if(q==5)
****** **** * ** * **
**** * ***** *** * ** * ***** *** * ** * *** ** ***
* *** ***** **
* ****** * ** * ***** if(q==6)
* * * * *** * ******** **
*** ** **** ** * * * ** ** ** ** ** ** * * * * * **
** ** * ** * * * ***** *
*** ** *** *** * **** if(q==7)
* ** ** *** * ** * * **
* * * *** *** * ** * * * ** * * * * * *** ** * **
* * * *** ****** * ***
** *** * * * **** * if(q==8)
*** **** ** * *
* ** ** * * * * * ** ** * ** ** ** * * *** * * ** ** * ****** *
** ******* **** ****
* * * * *** * ** ***** **** if(q==9)
* * * * **** * ** *
* * ** ** * * ** *** ******* *** ** * ** ** **** ** * ** *
    }
* **** * *** ** ***** ** if(q==10)
*** * * ** * * ** * *
** * * ** * ** * *** ** * * *** ** * * *
** * * * **** * *
*** ***** ***** *** * * if(q==11)
** * * **** ** *** * ****
* * **** **** * * * * ** ** * *** * * *** * * ****
    }
* ** * *** * *** ** * ** if(q==12)
* * * * ** * ** **
* *** * *** * *** *** ** * * ***** * ** ** * * * * * ** **
* * **** ** ** * * *
* * * * * ** * *** ** * ** 0;
}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: error: 'q' undeclared (first use in this function)
 scanf("%d",&q);
             ^
prog.c:5:13: note: each undeclared identifier is reported only once for each function it appears in
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** ***** * *** * * * * a=0,b=1,c,d;
****** **** * * * *** * * **
**** * ***** **** * * *** *** ****
*** * * ** * * * *
** ** * * *** * * * * * ** * * *** ****** * **
* * *** *** * * ***** ** * **** * **
* **** * ****** * * * *** * *** ** ** * **** * *
****** * * * ** ** *
* ** ** **** ** ** **** * * * ** * **** * *
** * ** * *** *** ** * **** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * ** * *

int number;

int GetFibonacciNum(int integer){

* * ** * **** *** * * values for Fibonacci sequence
* * ** * * * * * * F[integer];
* * ** **** * * * ***
** ** ** * *** * *
*** * ***** * * * *** i;
**** * * * *** ****** * * F[integer]
* **** * ** * * ****** * * * ** **
* ** ** * * * ** **** ** *** ** * * ** **
** * * * * ** ** **
** * *** ** ** * * ** F[integer];
}
///
int main(){
* **** ****** * ** * ** * * **
* * * ***** ** * * **** * &number);
******* * * * * * **** ** * *** *
* * ** *** **** = * ** * * *** **
** ** ** *** * *** * ** **
* *** *** *** * ** * *** * ** ** number);

*** *** ** * * ** 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
* * ** ** ** * * * input,n=0,F1=0,F2=1,FN;
** ******* ** ********** * ** ** * ****

** *** ** **** ***** * * (n;n<input-1;n++)
**** * ** * ** * *
*** * ***** *** * ** * * ** * * * **
** * * *** *** ***** *** ** ** *** ***** * *** *
** * * * ** **** *** *** ****** *** *** *
* ** *** * * *** ** *
* * ** **** * * * * * ** (input==0)
******* * * ***** ** ** * *
**** ** * ** * ** ** *** * * **** * ** * *
* ****** **** ** ** * *
* * * ***** * ** ****** if (input==1)
** *** ******* * ***
** * *** * ** *** * ***** * * **** * **** * **** ** ****** ** ******
    }
* * *** * ** *** ** *
    {
*** * * *** **** * * * * * * * * * * ** * * *** ** *
    }
** * * ** * * * * 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
 int a,i=0,j=1,k,c=2;
*** **** * *********** *** *
 while(1){
** ** * * * * *** * * **
** * * ** **** *
** * * ** * ** * ** *

** * ** ** ** * * ** ***
*** * ** * ** ** * * * * * *** * * * ** * ***** ****** ** * *** **** *
** **** * * ** * **** * **** ** * * * * * ** **** ***** * ** *
* ** ** * **** *
* ***** * * **** * ** * *
 }


return 0;
}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main()
{
** ** * * * ***** a,b,c,d,e;
* * * * *** *** *** * ***
* * *** ** * ** * * * *** * ** *
    
** ***** **** * ** ** ** ** * *
* ** ** *** * **** ***
** ***** * * ** ** * *** * ******** ** * * ** * ** *** * *
** * * * ** *** *** * * ** ***
* * ** * * * * *** * * *** * * ** ** * *
** * ** *** ******** * *** * * * * *
********** * *** * * *
** ***** ** ** * * * ***
**** * ** ***** ** *** * * **** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** * *** ** *
int main()
{
** * * * **** * * ** * i, n, t1 = 0, t2 = 1, nextTerm,a;

***** ***** ** * ** ** * **** **** * ** &n);

* ******** * * * ** (i = 1; i <= n; ++i)
* **** ***** * * * **
* **** *** ** *** ** * *** * * * ** * * ** = t1 + t2;
**** ** ** ***** ** * * * *** * * = t2;
* *** ** * ** * * *** ****** *** ** ***** ** *** ** = nextTerm;
* *** ** * * * **** * *
* ** ** * * * ** * * * ** ***
*** **** * ** * ** ** *** * ** ** * ** *
* ** * ***** **** * 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
    int n,i,count=2,first_term=0,second_term=1;
**** * **** ** * * * * * ** *** * ** *** * **

    if (n==0)
** * * ** * * * * ** * ****** * * ** * * * **
    if (n==1)
* * * *** ** * * ** * * ** * * *** * ** **** * *** ****** *** ** **
    else
    {
**** **** * *** ** **** * **** ** ** * * * * (count;count<=n;count++)
** ** ** ****** * * * * * * **** * * ***
**** ** **** * ** * ** * * ** * * *** * * * ** *** ** * * * ** ** ** * *
** *** **** ** ** * * **** * ** **** * ** * * **** ** *** **
**** * * ** * * * *** ** * * *** * **** * **** **** *** * * ** * * * * **

** ****** * * * * ** * * * * * * * * * ******* ** * **** (count==(n))
** * ** * ** * ***** **** * ** * * * ** * * * * ** ** * * ** * * * * * * * ** * *
** * * * * **** ** * * ** ** * ** * * *** ****** ** ** * *** ** ** ** **** ** ** * ***** *** * ** * *** ** * * *
******** * ** * **** ** * * ** ** * * * * **** * ******* * *** * **** * ******* ** * * *** ** *** *** * **
* * * ** ** ** *** * * * *** **** **** * *** * * * ** ** ** *** **** ** * **** ***** ***
* **** *** **** * ** ***** ** * ** * * **
    }
** ** ***** * ** * * * ** ** **** * * ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * ** * **** * **** * ** a,b,c,d,i;
** *** * ** * ***** * *** *
* * * * ** ** ** * * * * * ** * **** **** * *
*** * * ***** * ***** * * **
    {
****** ** **** * ** *** * **** * *** *
* ** ** * **** ****** * * ** * * *** *** ** *
** * * * * *** * * * ** * * ** * * * ** ****

** * * **** * *** ***** *
** * * * * * *** **** ** ** **
* ** * * *** * * * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ******** *
int main()
{
int a,b,cb,c0=0,c1=1;
* ** ** ** * * **** *
if(a==0) ** ** * **** ** ****
else if(a==1) * ** ** *
else {
* * * * * * * ** * ** ** ** ** ***** *
* ** ** * ** * *** **** *
** * * * * * * * * * **** * * * * ** ** = c0+c1;
* ** * ** **** * * * * ** ** * * *** ** ** = c1;
* *** *** ** * ** *** * * **** * **** * * * = cb;
** * * * ** ** **
* * ** * ** * **** * * * * * *** **** *
}
return 0 ;
}
answered by (-254 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.235
©2016-2025

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.3k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 13.9k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5.9k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 9.5k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 9.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users