2 like 0 dislike
14.2k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 14.2k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

*** ** * * * * ** ** * i;
* ** *** ** * * **** * j;
**** *** * ** * * ** ** newNum1;
***** *** ** * newNum2;
*** * ** * ** * * gcd;
** ****** ** * ***** ** * rem;
* * * ***** *** *** *** * num1, num2;

* ** ** * **** * ** ** *** *** * **** *** ** * **

* ** * ** ***** * *
** * * ****** * ** *** **

*** ** ** ** ** ** * * * != 0)
*** * * * ** * ** * * ***
** **** ** ***** * ** * * ***** ******* * *** * = j%i;
*** * *** ** * * ** * * *** ** ** ** * * = i;
****** ** * * ** * * * ** * * * ** * ****** = rem;
* * ** * *** ** *** *
* ** * * ** ** * **

***** * * ** * * ** = num1/gcd;
* * ** * **** **** * * **** = num2/gcd;

* **** ** ** *** * * == 1)
    {
***** ** ****** ** ** * * * * ** *** ******* * * *** *** *******
    }

** ** *** * *** *** ********
    {
* **** ** * * ** *** * * *** * ** * * ** **** ****** *** *
** ******* *** * ** *** *

** *** ** * * ***** ** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * * *** ******** * * * *** *** * ** *** ** ***

** * * ** * ****** ** *** * **
*** * ** ******* *** ** ** ** *** * ** * * ***** ** * * * * ** * *

    else{
*** ** * * ** ** ** *** *
    {
**** ******* * * *** * * ***
** *** *** ***** ** * * * * *** ** *** **** * ** * * * * * * && deno%i==0)
**** * * ****** *** ** * * * * * * ******* * ** * *** * * * **
**** *** ***** ** * ** ** * ** * ** ** ** * * * ** * * * ***** ** *** ** * * *
**** *** **** * * *** * *** * **** * ** * * ** ** * ** * *** ** *** ** ** **
* ** * ** * *** *** ** * * ** * * ** * * * * * * * *
    }

** ******* ** * ** * * *
    {
* *** ** **** * ** ** * ****
* * *** * ** ** *** *** ** * * *** * * ******* ** * *** * *** * **** * * * * && deno%i==0)
* * ** * * * * *** * ** ** * ** ** * * ** **** * ** * ****** *
** * * **** * ** * * * ** * ** * * * * * * ** ** ** * * * **** * * *******
* ** ** * ***** * * ** ** * * ***** * * ** ***** * **** ** * ** ** ** ** *** *
*** *** ** *** ** * ** ** *** *** * ** ** ** *** * * *
    }
** * *** * ** ** * * * ** * * ***

    }




** * * * * **** * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * *** ***
#include **** * ** * *

int gcd(int n, int m)
{
* * * ** *** ****** gcd, remainder;

* *** * * * ** * **** (n != 0)
**** * ** *** *** **
** ** * *** * ** * ** **** ** *********** = m % n;
** ** ** ** * * *** * * ******* * * * = n;
**** ** * ** ** *** *** ** *** * * * * * = remainder;
* ** * *** * * *

* * * * * * * ** * = m;

** * * **** * * ** gcd;
}

int main (int argc, const char * argv[]) {

** * ** * ** ** ** number1, number2;
*** * * * ** * * newNumber1, newNumber2;

** **** *** ** *** ****** ** ** * **** *** * * * **

** * * **** **** ***** = number1 / *** ** number2);
* * **** ** **** * * **** * * = number2 / * * number2);

* * * * * * * ** *** * ** * ** * ***** **
** * * *** * ** ** * * ** **** * * *** *** * **
***** * ** *** ** ** ** * ***
** * * * *** ****** ** * ***** * ** * * * * ** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* ** * * * * *
* * ** * * ** *** *

int * * n, int m)
{
* * * * int gcd, ** *

** *** * (n != 0)
* * * * {
* ** * ** * ****** * * * = m % n;
** ** * *** * *** * **** * m = n;
*** ** * * ** * * ** * * n = ** **
*** ** * * }

** * *** *** gcd = m;

** * **** ** gcd;
}

int main (int ** char * ** * * {

**** ** *** int * * ****
* *** ** int *** ** * * **** *

** ** * ** ****** ** *** ** * ** ** ** ** *

* * ** * * * * = / ** * * *
** ** *** * ** = *** * / * ** ** ** *

* ** * ***** if *** ** * *** ** * *
* ** *** * * ** **** ** *** ** * **** **
***** * ** * else
**** ** * * ** * ** ****** * ** ** *** ** ** * *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** **** * ** * ** **** * i;
* * *** * * *** ** * j;
***** * * * * * ** newNum1;
* ** **** * * newNum2;
* * *** ** *** gcd;
* * ** ** ** rem;
** *** * * * * ** num1, num2;
    
******** ** * * * ** * ** ***** *** ** ****
** ** ** *** ** ****** *
** **** ** * * * * *
***** * ** * ****** * *
* ** * * **********
* *** ** *** * * * * *** != 0)
** ** * * * *
* * * * * * ** * * * *** * * *** * *** * * * * = j%i;
* ** ** *** *** * * ** **** *** = i;
** * * *** **** ** ** ** ** ** * ** ***** **** = rem;
* * *** *** * * * * * *
** ** * **** ** * * *******
    
* ** ** * * * * * ** = num1/gcd;
** *** **** *** ** * * * = num2/gcd;
    
***** *** * * ****** * **** * == 1)
** *** * ** * *** * ***
** * *** * ***** ** **** * * *** *** *** * * * * * **
* ** * ** ** ** *
    
* ** **** ** *** ** *
* *** * ***** * * * * **
* * **** ** * ** * * ****** * * **** * ** ******* *** ***** * ****
* * *** * * ** ** ****
    
** * ****** ** * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
**** *** ** * ** * * ** * i;
* * ** ** ***** * * * * j;
*** * * ** * * ** newNum1;
** * ** *** * ** ** ** *** * * newNum2;
* * ** * * *** * ** * * ** gcd;
* * * * ** * *** * rem;
* *** ** * * ** * ** num1, num2;
    
* * **** * *** * * * * * **** * * *** * *** *
** * ** * ** ** *** *
* *** * *** * **** ** *
**** **** ** ** *** ** *** ** ** *
* * *** * *** **** *** *
* ** ** *** **** * * * * * != 0)
* * * *** ****** * ***
****** *** ** * * * ** ***** * * ** * * ******* ** = j%i;
** * ***** ** * * **** **** ** * ** ** *** * = i;
*** * * * * * * *** ** ** ** = rem;
** * * **** * * ***
* * *** * *** ** ** ***
    
** * * * * *** * ** *** * = num1/gcd;
** * * ** ** * ***** * ***** = num2/gcd;
    
* *** ** * * * ****** *** * == 1)
**** * ** ***** *
** * ** * * * * ** * * ***** * * * * * * * * *** ** **
** * * **** * **
    
* *** *** * * ** * ***
* **** ** ** * * * ** *
* ** ** * * ** * * *** * * * * **** ** * * *** ** * ** * ** *
**** **** **** * ***** *
    
* **** ******* ** * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
**** * *** *** * ** ** ** ***** * * * ** ** ** **** ***
* ***** * **** * ************ *** *** ** ** * * *
    {
* *** ** * *** *** *** ** *** * * ** * * * * ***
* * ***** ***** * ** ** ** ** * ** * * *** * ** *
* ** ** * * *** ****** * *
* * ** ** * * *** ** ** ** ** **
*** ** *** * * ** *** * ** ****

**** * *** ****** * * * * *
* * * * * * * * * * * * * **** ** * *** *** ** *** ** * * ** ** *** * *** * * * *** * *
* * * * * * * ** * * ** ** * * ** *** *** * ** ** * * * **


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
** ** ** * * * * * * * ** a,b,GCD;
** * ** * * * ** * ****** ** * * ***
** * *** ***** **** *** ** *** * **
* ******** * ******* * ******
*** * * ** ** ********* *** * *** * **** * * * ** *
**** * **** *** ** ** *
* * ** * ** * ***** ** ***** ** *** ** * * *** ** ** ** *** ***
** *** * *** * * * ** * 0;
}
* * * * * ** *** * gcd(int a, int b){
*** * ** ***** ** ** * ** * **** * *** ** ** (!b) return (a);
* * * **** * * * **** ***** * * ** * *** * gcd(b, a % b);
*** ** * * ** * *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * *
#include **** ** * ** **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
** * * *** * * **** gcd, remainder;
*** * * * * * ********
* * *** ** ****** *** (n != 0)
* * ***** *** * *** *
* * ** ****** ** **** * * **** * * ** * * ** = m % n;
* **** * * * * * *** ** ** ***** = n;
** * *** * * ***** * * *** *** * ** = remainder;
* * ** * ** * * * *
* * ** ** * * ** ** * * *
* ** * ** ** *** * * * ** * = m;
** * * ** * * ** * *
** ** ** * * * * * * * ** gcd;
}
int main (int argc, const char * argv[]) {
* ** *** ** *** ** * number1, number2;
** *** *** ** * * ** newNumber1, newNumber2;
* *** *** * *** * * *
* * * ** *** ** **
**** * * * ***** * * * * * * *** * * * ****
* * ** * * ** * *** ** *
* ** * **** * *** ****** = number1 / gcd(number1, number2);
* ** * * ** ***** = number2 / ** * * number2);
*** ** ** ** ** * * * * **
*** * * **** ** * *
*** ** *** * *** ** * ( * * **
**** * ** * ** * ****** ** *** * ** **** * ** * ** * * *********** newNumber1);
* * ** * ****** * * * *
* ** **** *** * * * *
** ** *** ** * * * *** ** * *** * ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** * ** ** ** * * *** * a,b,c,d,e,f;
* * ** * * ** * ** * * ******** * ***** * ** * * *
* *** ** * **** *
** *** * * ***** ***** **
** ** * * ** * ********* ** * ****
    {
** *** ** ** * * **** * ***** * *** ** **** * *
** * * *** ** * * * * * ** ** ** * * * * * **
* * * * * * * ** *** * * * * ** * * * *** *
    }
*** * ***** * **** ***
    {
** * *** ** ** **** *********** * ** * **
** ** * * * **** ** * * * ** * * ** ***** * ** ***********
**** ** * ** ** * **** *** ** * *** ** *
* * * * ** * * * ******** ****** * * * **** **** * ** ** **
    }
***** * ** ** *** * *** * * **
    {
***** * ** * ** *** * **** *** * ** * * * ** *****
* * * * * * * * * * * ** *** * ** * * * ** * ** *** *** * * **
** ** ** ** * * * * * ** ***** * *******
* * * * **** * * **** ***** * ** ** * * * * *** * *** * * * * *
    }
* * **** ** * ** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.77
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 14.6k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 14.4k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 18.4k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 14.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users