11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
10.1k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 10.1k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

** ***   *  ***    **   ****  i;
*         ***  * * **   ****  j;
*    *  *  **    ** * **  newNum1;
 *   ******     * ****  * ** * newNum2;
*   ** **      ** * *** *  ***  gcd;
  ** ***** *  ***    *   * * rem;
** *   ** *   * ****** *** * ****  num1, num2;

   ***  *     ** * * **    * *  *  *  *** ****  * ** ** ** * ** **   ***

**** *     *    *   **  ** *
*** ***    *** ******  ****     

*  **  ** *    ****  *   *   *** != 0)
 *  **  ***  *  **   ****  * 
*  *****   ****   ***  ** *  *  *  *  *** ********** *** * * = j%i;
    *  ** ** *  ***** ***** **  ***    *  ** ** **** **** = i;
****   *    *******   ***  ** * ****   **** **   * ** *    = rem;
* **  * ****   * ***** *  * 
   ** **   * ** **    *  **** *  *

  **  ***  * *****  * ****** = num1/gcd;
* ****  ** ** *   *** ***** = num2/gcd;

   * *  **  *   *  ****  * *  * ** ** == 1)
    {
   *  * ***  * **    * ** * *** *** ***** ***   * ** *    **  **  *** **    *****
    }

*  ** *   *     ** **  **     
    {
** *        *     *  ****** **    **   *   *      ***    ** ** ******   ******  ****** ** 
**     *    * **** * *  *

 **  *  *  ***  ****  * * * ** ****  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
 ** ***   *     ** * * *  *  *  * ***    *   ** *  **    *   **   * * **

*   ***** *     * *  * * *  * ***  
 ***     * *  *  ** ***  **** ***  **   * * *** * * ***** **** * **   *** * 

    else{
** *      *** * * ******** **   *** *
    {
 **  *** *   *  ****       **   ** *  *** *
* **  *****   * ***  **   *   *   * ****  *****   ** ***** ***** * *******  *   *   && deno%i==0)
*   ****  ** **  ****  * *    * * ** * * *** *   ** ** *     * * ****   *   **   *** 
 **  *** *      *       ****    * **** *  ** *   ** *    * ** ****   * *  ****  *****     *    
*      **    *** * *    **  *    *    **   * **        ****  *     ** ** * * *    *     * * * *** *  
 *** *** *  **** ***  *   *   *  * *      * **  ****  **  **  ** ****   
    }

**   **   ******   * **  ** *   *  **  *  
    {
* *** **  * *  * * * **  **  *  *      * 
    ** ****** * **  *    *******   ***  *  ****  **  * * *** *  ****  ***  *** ****  * **   && deno%i==0)
*  ****** ** **** *****  * *** ***   *   ***  ***  ** *  *** * ***     **   ***** *
  *    ** * * *  *   *   ** ***    * *  **  ******* **   *    *  * ** **      ***       ** * *   *   * *   *** ** **
 **  **    ****  ** *    *    *  * ********  * * ** *   **   * * **   *   **  * **  ***** *   **  * **  * ** **
*       * * **   *  *** **  **    ** * *** ** **  * ** * **  *   ***     ***    * **
    }
*  ***  ** **   * *** *      ** ** ****   ** ** * *    

    }




*   ****** * *    **  ** * ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *** *  *********
#include  **  ***  *  *** 

int gcd(int n, int m)
{
  * **   ***   *     *  **  gcd, remainder;

  *  ****   *  * * ***  *****    (n != 0)
* ******  ***  **** *** ** ** 
*****   *  *** * * ***  ** **  *   **    *  * * * * *   ** = m % n;
       *  ****** **     **   * *** * *** *  *** ** * = n;
*    * *  ***       *** ** * *** * ***       *       ******* = remainder;
  *     *  * ***    *** *  *** * * 

     * **  ** **  ** = m;

  **    * *  **   *   *  *  *  * gcd;
}

int main (int argc, const char * argv[]) {

  * *       * * **  ** * **   number1, number2;
*   *****  *  *    *    **  * newNumber1, newNumber2;

**  *    ***********  *  *  **** *******  **   **  ** **  *    ** *  ***    

   ** * *     * * * *  * * *   *** = number1 /  *  ** number2);
     *** **   ** **   * **   * * = number2 / * **   number2);

   * * * *** ** **   **    * *   *  *** * ** *  * * 
 *   **      ** **   * **   *  *  *******  **** *     ** *  *  
* ******** * *   * **  *** **
*   *** ****  * ** *  ** * * *  * * **    **  *     
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** * *** ****     ****  
 *****  **         *

int  * *** n, int m)
{
*   *** *** *  ** int gcd,   *** *

**   **   *   *      (n != 0)
****  **      **  {
 *  **     ****   *   *      **   *   *  * = m % n;
     ** **   *   * ** * **  m = n;
*  ***  *** ***  *    ** **** * n =   **** *
 * *  *         }

 *** *** **   *  ** gcd = m;

****  ***   * ** * ** * gcd;
}

int main (int  *  **  char * * * * {

  *   * *** *** ** ** int * *   **
 ** ****  * **** int * **    *****

*     * * * **   *  *  *   * * * *     *    * ***     *            **

** *** ***  ****    * ** *   = *** /   ***   *     * *
*** **   * ** *      ***** =  *  / ***   **    ** * *

** *  * * * *  **  if    **** *    ** ** *
  *   **  * ******  **   **** **     ** * **   **  **** 
***  *  ***  else
** *   **   **  *    * * *** *** ** ****  *   ***   
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
* *  * ** *  **    * * ** ** ** * i;
*    *  *  * ****** *   ** *  * j;
 ***    ***  * ****    *    newNum1;
  **     ****   *** ** *   ** newNum2;
**   *  * * **      ***  * * **  gcd;
  *  * * * * * *** **   *****  rem;
*****  * *   *** ** * * ** ** num1, num2;
    
*  *      * *   **  *     * * **  *  **  * ***    *  *   **  ** *   *** 
*    *  * ****  * ** ** ***
*** ** * **** *** * ***   ***
   *  * **  ** ** **  ** *       **
****  *      * **      ******
*  * *   **  *  ** * **** *  != 0)
 * **    * * * * **** *** *
**  *  *** *  ** *     *  ***  * ****** ** *  **    = j%i;
** **    **** ****** *   ** * *** *   ****  * *  *     = i;
 ** * *** * * * **** **  ** *  **** *****  **  **   ***** *    = rem;
  *   ** **  * *  ****   
*  *  * * * *  ****   *    * ***
    
**** * * *** * * ** * *   ** = num1/gcd;
   ** * * *  **** * *** * ** ***     * = num2/gcd;
    
****      ** ** *   *  ****  * ** == 1)
* **    *    **** * *** 
    **  *  ** *** * *** * **   *    *  * *  **  ** *  ** ** ******  **********  
*   ** * * * *** *  *  ***  *
    
 * *   **  * *   ** *    
 * **  **      *  * ***  *** 
 *** * ** *  * *    ** ** *  ** **      **      *****  **** ***  ** ***  **    *
 ****  *   *  *  
    
* *  ***** **   *     ********  ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 **       *****  * *** ****    i;
** **** ** * ****   * *****  ** * j;
 **  ***  **   * **   * * *   * newNum1;
*  *** *  *** *   *  *   *  * **  newNum2;
* *      *   * * * *      *   ** gcd;
 **  ****   **  ** ****  *** rem;
****** **   *    ** *  * **  *  num1, num2;
    
 **** * * *** ** * ** ****** * * **** *  ***    * ** **  * *  **  *      *
  * * *   ***     *   * ***
**  * *     *  * * ** *** **  
 ** **    *****  * * ******** * 
* *   * *      *   * ***
    ***    * * ** *  *    ***     != 0)
  ***** **** **  ** ** *
  ****** * *  *** ***** **  * ** *  *  * ** * ** * ** ** = j%i;
*** ***** *    * * *  **** * * ** * **  * * ** *  * **  = i;
   **  *  ** *  * ** * * ***  **   ***   *   * ****** * = rem;
* * *    ***     *  *** ** *
    *** **  *  ***  *  *   ******
    
**** * *   ***** * *  **  ***    = num1/gcd;
 * *    ** *****  *  *****  ***** = num2/gcd;
    
* *  *** *** **   * ***** ** == 1)
 ** **     ***    **** **** * 
* *  * * ***    **  ****   *  *** ***   *  **   ***  *   *   * *    *    **  * *
  *  **  ***   **    * *  * 
    
 **   * * ***  * *****  * *  *
  **   **   **    ** *   
* ** * *  ***   ** * **** ***  ******* *  *  ******   ** **** * *   **  *    ***  
*  ** **  * * ***** ** **  **** 
    
*** *  * *   **** * **  **** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** * **  ******* ***  *  *    *  * ****  *  ** ******    *  
*    ***  ****   * *  * ****  * **     *   *   * *   * *
    {
*  *** **     * ** *  **   * ****** **  *     **  **    * *  * * * ****** *
** ***  ** *  ***   *   *  *  ** * **  *  * **   **  ** *  *  * 
* ***  *  *   *    **    *     * ****   * ** 
* *****  **  **  * * ** * **  * * **** *** ** 
  * ***   *** *   * *********     *  ***** ***   * 

** * ** * * *   ** **      *  * *
**  *** ***** *  *    **** *****  **  * *  **  * *  * ** *  *  ***   *  *  **   ** * * ** ** * *** *
 * ******    ****   *  ****   **  ****      ***** ***   *  * *** *** ** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*    *** ****     * **      *  ***  a,b,GCD;
* ** ** ** *   *** * ******     *   ***** ***  ** *  **  ** * ***  
  * *  **       **** ******* *****
**       * ***  ***  *     ** 
  *** *   *** *  *  * *** ** ****  *   * *   ** ****  * *** * ** * *     **
*  *     *  *     ***  ** * * * ** 
*   *   * *  *** *** ** **   **   ** **  ** ***   *** **    * *  **** ***  **    * 
****   * *      *  ****  * 0;
}
   **  * *    **   ****  ** *  *  gcd(int a, int b){
     ***  * * * * ** ***   *  * * ** **  ****   *      *** (!b) return (a);
* **  *  * ***** ***   * *   *  *   * **** *** *  *   *** gcd(b, a % b);
******* *  * ** * ** *  * **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   *   **  *  **** **
#include  **** *******  

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
 *      *  *  ** ***** **   gcd, remainder;
 *** * **** *  *  * *  ** *  * 
 **   *  * *** *     *  ****  (n != 0)
 *** * **** *  *    **** *  * 
*  *      *  ** **   *  ** * ** *  **  * **  *  ***  *     *  = m % n;
  ***** ** **   *      **** *    **** * ****  *     * = n;
     ** *  **  *** ********      *****  **     ** ** * = remainder;
*   * * ***  * **    ** *  *
** * * *   **    * *   ***
* ***    *****  ** *** **   = m;
 ** *** * **  * *  ** * ****  * 
****  ***    ** * **  *   ***   gcd;
}
int main (int argc, const char * argv[]) {
* *** * **   *******   *  ** ** number1, number2;
  *      *   * ** ** ***** * **  newNumber1, newNumber2;
 **  ****** **   **   *****
   *  * **   * *     ****   
****   **   *** *  * **** *  *   *** **** **** *   ****    * ******* 
    *      ****** **  *** **   
 ******* **    *    *   ****  * *** * = number1 / gcd(number1, number2);
 ** ** *******  **** ******* **  ** = number2 / * ** *** number2);
 ** *   *  * ** **** * **
        * * *  *      *  ****   
  * ***   **** ** *  **   *** (  ** ***
 ** ** ****    ** ***** **  * *  **   ** ****  ****    *  ** * *** ****  *  * newNumber1);
* **** ***   ****  ** * * **
*  *** ***** **  ****   *** 
* * ** *     *** *  ** *****   *** **  *  **  newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
 *   **  *  *   ***  * ******  * ** a,b,c,d,e,f;
   * ** ******   *  **  *   ** *  ****   *  **   ***  ****   * ******
* *   *   ****** **  *** * **** 
  * ** * *     * *   ***     * 
 * **  *    **** * * * * **** ** *   **
    {
  ** *   ** * **  * * ***  ***  * * **    *   * * *   
 **   *** *  *  * *  ***  *****  ** *  * * ****     ***     * **   
 *** *  ** ***** *    *  ** ***      *  *   * *   *  ** ***
    }
 *   * *  **   * *** ** * * * ***** 
    {
** **** * ** * **  ***** *  ***  * * ******** *    ***  *
* ** ** ** ** * *     * *  ******  ** ** ***** * **   *****  *******  *
*  **   *    **  ** *  * * ****    ****  ****** *   *** ** * ***
 **  *** *  **  *  * ** * *     * **       *    ** ****** *** *  * ****  * ***   *****  *****
    }
 ****  * *  ****** * * *** **** 
    {
****  * ****  ** ***   **      * * ****  *       ***    *  *
*  ** ** ** *    ***   *  **    *****      * ** **** **  *** *  *    ** * **  * **
 * ***  *** *   ** * * ** **  **  *** ** **  * *  *  **    
**  *  *  *** **** *   *  ****   * ** * *** ****** * *** ********  ****** 
    }
* *  ****  ** *** *** **    **      0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.123
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 10k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 10k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 12.5k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 9.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users