11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
8.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 8.9k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

*****  * * *   ** **** * i;
  ** *   *******  *   * * *** j;
 ***  *  **      ** **  newNum1;
 **  * *   * * ***  * *  *    newNum2;
*** **  * ** ** * *  **  *  * gcd;
 *  *  *  ***********  * rem;
* ** ** **  *  **     *** *  num1, num2;

**  * *      ** * ** * * **    ***   *** **  * *** **     *****     **

 ***   **       *  ** *   *  *  ****
    ***** *  *   *    * **   *

 *  *    * *  *** * *  *  **  * != 0)
** ***  *  **  *  * *  ***  * **
   ****  * * * ** **** ** **  *  * *   * **  * *  ** ** = j%i;
 ** *    **** **  *  * *  ********   * *   ****** * = i;
   ***** * * ***  ** ** * **  * ******  ** * ** *    = rem;
  ** *  *    *  * ********  **  
* * * * *  *  ****    ***  ** *  

  *  *  **   *** * ** **  **  *  * = num1/gcd;
*****    *    *   **    * ** *  * = num2/gcd;

  ******  **    * ** *  **  == 1)
    {
  *         ****  *          ***   ****  **** *    * ***  ******* **   * ***
    }

*      **** * * **       **  
    {
  ** * *   *  *   *** *   ** **********   ** * * * * * *****      * *  *  *** *  *** ***
**   ****      ***    *  * ** 

 *  **    *** *   ***  * **   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* *   * * ** *  **  * *** ** *  **** *  *****  * * *  *******  **  **  *

**** ***     * **    *   *****  **** 
* *  * * * * *  *** *   * ** **** *  ** * * *****       **  * **  *   *

    else{
** * ***     ****     *   * ** ** ***  
    {
 ******  *  * **** ** * ** * *****    * ** *
** * **** * * *** * * * ** **     *   * **   **   *****   * ****  **   **  **** *   * *  && deno%i==0)
 ** ** *  **** *   *      ****  *  *  **   **     ** * **      **  **  *  ** ** *
*  *   *        **     ** *  * *****       ***  * * ** ********   *  **  *   ** *  **** *   * **** **    *
     * ** **  *  * *   * **  ** *  * *      * **  * ** ******  * **  **  **  **    * * * *******  *  * * **   * 
 * **   **  **    *    ** * **  * **** *  **  *        *      **      * ** **  ** *  *
    }

**   *** *    *  ** **  *   ** **  * * ** * *
    {
  **** * * **   *  * * * ** * ***  **   * 
      * **   ******* * ***** * * *****    ***** * *** * **   ***  *      **  ** *  ****  && deno%i==0)
     *   ***  * ** * ****  **** *** *  ****  * ** **     ***** * *** * * *  **
    * * **** ****** * ***** * ** *   * *  **  * **  *    * *  **        ***  ***  **   *  **  ******* * *
 *** *  **** *  * ** ** *   ** **  * **** ***   ** **** **  **     **  *  * * ** * **   *    ***  * *   *  
******** ********  ** ***   *****  * ***  *     *   ******  *  *** *  *** 
    }
*** * ** ***    * **         ** ***** **   * * ****

    }




**    * *   ******** ** * * **    * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** * *****  * *    
#include  *  ***** *****   

int gcd(int n, int m)
{
   *  *  * ****** **  * * * gcd, remainder;

 *     **   *    * ***  * **  *   (n != 0)
      ****   * *      *  *
  * *** ** *   *   ****  ** ***  *** ***  *      * *   * **   * **  = m % n;
    ****  ******* *     ***  ****  * *  *  * * *** = n;
*    * *  *  ***** *         *** *  *  *     *** ****   *  = remainder;
 ***  ** *  ** * ** *     *  

*            ****    ** ** * ***  * = m;

* * **** *  **           ** *** gcd;
}

int main (int argc, const char * argv[]) {

** ** *  *  ******   *** ***   number1, number2;
    ** * *    * **     ** **   ** newNumber1, newNumber2;

*      ****** * *  *  ** *  * ******* *    * ****** ** ***    * * ****    ***  **** 

* ***  *         * * * * *    * **     = number1 / *   * **   number2);
   ** *** ** *    * ***** * *** * * = number2 / *** *  * number2);

*  * *** ***  ***      *  **  * *      **    **  *   
*  *** * *  *      * * **  * **     * *  *   ** * ******      ** 
**** **   **  ***** * *   *
 ** ****       * *****  *     * **   ** *  ** **   **   * 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   *  ** * *   ******  
* *    *  **          *

int * ***  n, int m)
{
 *  *  * * * int gcd, **     

**** *   *  ***     * (n != 0)
  ****  * **    {
 *   * ***    *  ***   ** *   * ** = m % n;
**  *  ** ******  **   *  ** m = n;
  *   * *       * ***  **   * n =   * ** 
 *** **  * ** *** * }

   * *   **  ** gcd = m;

*  ***    **   **    * gcd;
}

int main (int *    * char * **   * {

   *** *    **   int    *  * ****
******* * *** int * ** ** *        *

*** *****  **   * *  *  **  ** **** *** * *    *    *****     

 *   * **    * *    ** * = *  * / * **  *  *   ** 
  *   **       **    ** * = **** /   ** * **   **   

**   * *   *   if * *   ** *   * **     
 **   **    * ** **  ** *    * *  ***  *  *  *       *
* ***  * ****   * else
  *   ** * *  *        * ***  *   **  ***  * ** *  *     **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
*    ** ** ** *******   *  **  *   i;
  *** ** *     ** *      * * * j;
 *  *  *  *****  *   **    **    newNum1;
* * **          ****  *    *  newNum2;
 *  ** ** ******  * * ** * gcd;
* ***** * ***  *** *  **  * ** *  rem;
    * *   ***** *  ***** num1, num2;
    
     *  ** ** *     *  *  **  *****    * *** * **  *  ***  * **  *    *
   *** ***  ** *  *  * **** *  
  **** *   ** ****  ******* ** * 
*    * *  **  *** * ** * **  *
* *  ***     *****   * * * ***
*  *    ** *    **  * *  ** * **   != 0)
*  * * *** *  *   
***  ** *  ***  *     * ***  * *     * **** ***** ** ** = j%i;
*   *    *     ***  *   * * * ***** ***** *  *  **  = i;
 *  **** ***  * * *  ***   **  **  ** ** **** *  *  = rem;
   **********  * *  **  *  *
*** **   **  *  * *****    *   
    
*   ** **   **  *   * **** * * * * = num1/gcd;
***  ** * ** ** * **** *   = num2/gcd;
    
* *  **   *** ** * * * *  * *  * * *   == 1)
  *   ****   *   ***   ** * * *
***  * **  *****   *  *** * ****** * *      * **  ***** *** *  **** * ****
   * **** *****  * *   *  
    
*   **      ** *   * ****     
******   ***  *  *  ** *  *   
******  *     ** **  ** *   ** * ** *  ***** *  **  ***  *    ***  *  **     ***
***   *****  *  ****   *****
    
* **      **  ***  *****  0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 * *      *** *    **** ** * * i;
*** **** * **   *** * ** *  j;
 *  **  *  *** ** * ** ** ** * ** newNum1;
   **        *   * ** ** ***** *** newNum2;
*    ** * **  *  * ** ** **   gcd;
* * **   ** * **  * *  rem;
 * **   ** ***  *    *** *** **** num1, num2;
    
* ** ** **** *  *  *  * **  * ** **** ***  **** *         **** *    *
 ***     **  * ****   **
     **  *   ** * ** *   *     
* ** *** **** * * * * *   
     * *****   *** **      *
**   *   *****  ** *  **  *** != 0)
 **** * ** * **  * ***  
 *  *   ** * ******** **** ****  ****  *      **      * = j%i;
* * **     *  * *  ** *    **** *  ** ** *  ***** * *  = i;
  **  ***   *    ** * * * *****  * *** **     *  = rem;
 *** ***   ****  * **** * 
*    *    **  **    *****  ** * * 
    
 * **  * **  **  * *   *** *  = num1/gcd;
**  * * **     * *** *  ***  *** = num2/gcd;
    
  **  *  ** ***   **     **  * ** == 1)
**    * * * * ** * ***    ** **
*    ***  *  **** * **  ******   **  * * **    ** * * * *  **** *******   * * **     **
* ** **     ** * * *  *  *  * 
    
    * * ****  *** ** **     
*  ***  * * * *  * *     *** ** **
*** * *** * *   ******** * *   * ** * ** ***  ****    * *  *  ** *      * ******   ** ***  *****
*** **   ****  * ** **   ****
    
 **** * *  * *    *   **  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
******** **** * *** * *  *    ***    **** ** *  * *** *   ** **
  **  **** * ** * *   *** *   *    ** ******  *  ****** * 
    {
  ***** **  * * *      *  ****   ***   *   *   * * *  * ******     *   *** * *
*   ***     * *  **** **     *  ****    **** **  ** **    **  **   **
 **** ****** ** ***  **     *  ** * *  **
*  * * * * ***** **   *   *   * ****   * **** ** 
 **** ** *   * ** ****  *  ** *       ** ***  ** *

**   * **  *  *  **  ** *   *  
 * ** ***  *** * * *  *  * * *   * *** *    *     ** ** ** * ***** **    *  ** *   ** *  *   ***
*   ***** ***** *** * ****     *** *    ** * *** ***** *  **  *  **** *  ** ** 


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*   *   *****  **  * * ** *  a,b,GCD;
**** *  * **  ******  ***   **** *   **       ** **    *     * *
* * *    **  *****   * **  * **  **
** * * * ** **  **** **    * 
* **** * *   * *    * **  * ** **   ** **  **   *    **  *  *  **  *   
* **   *  *    * **  * **    *
* ***  * * ** *    * *  *  ** *  * ***** ** ***      *    ** *      ****** *  
   **  **    *   **  *  * *       * * 0;
}
****** ** *   * *   **  gcd(int a, int b){
 ** *** ************* ***** * ** *  ***   ** * **** (!b) return (a);
 *  * * * *** *   * *  **** ***  **   *** ***** * ** *  * ** ** gcd(b, a % b);
*  *** *        *  * *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  * *   ** * *
#include   ** ***** ** **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
** * ** * *** ** ***  *  * ***  gcd, remainder;
 *  ***   *  *  *  ****** 
 *****  * ***  *  *  * **   (n != 0)
*       **       ** *******   *
* *  **** * *** *   * ** ** * ** *     * * ***** *  = m % n;
* **   *** ****   *** **    *     ** ** * ** *  *** = n;
    *** *    * ** *  * **   **** ** * * **  * *  *  * = remainder;
 ** *   *  **** **** *  *
  *  *  *   *  *  * *  **  
 * * ******   *   *  ***  ** **   = m;
**  *  **     ** * * * ***
 *  **  *     ****  **** ***    ** gcd;
}
int main (int argc, const char * argv[]) {
**** ** *      **  *** * * number1, number2;
** ** *** * *     *  *   * **** newNumber1, newNumber2;
*** *      *  **  ****  *
*  ** * * * ** ** *****  *   *
* * **   *     *  *   ******      *       *****  ***   ** * * ** *  **** ***
  ***   *  * *  * * *   
   **  * **   * *  ** *  *** *** = number1 / gcd(number1, number2);
*  ** **   * *  *** **    * *  *   = number2 / * ***  *  number2);
 ** ** *   *  * * * * ** 
*   *** *** * * **  * **** 
     *  * ***  **** *****  ** * ( *** * 
**    * * ***  **   ***  ***  **   **** ******* ** *  ***  ** **  * **    newNumber1);
* ** * **     ***** * **  * *
 * * *   *    *    *  
*****  ***  ** ****** *  * ** * ** ****  ** * ** * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*** ******   **** ** * *  **    a,b,c,d,e,f;
     **  *  ***     *  *   *   *  **   ******** *  *   * *    * 
* * ****   ** *     **   **   *** *
 ********* ** ****** * ** *   **
  ** *****   *** * ****  **   *  * 
    {
  **     * *  *  **  ** ***  ** *   **** *** *** * **
 * *****     *  **  **          * * * **  *  * *  **  ** *   
***  *   ****** *  * ***  *   ****** * *  ****   ** *** ** * 
    }
 ***    * *** ***  ****       * ** *  
    {
  * * *    **  *  ** ** ****  *** ***    ****** ** * * *  *   
  ****    *  **** * *** *** *** * *     * * ******  * ***        **    **  * ** *
 * *   * *  * ** ** * **  ** * **   *****  * ** *   ***  ***
 *    *    *  ***   **  ** ***   * *** *  * *    * * *** ***     * ***  *  * ***  
    }
 ***  ** *   ** * *   * * * * * 
    {
   * **** *** *  **  *******  ** * *****     **    *  **  ***
  *    ** * ***  *    *  *  *   *    **** *  *  * ** *** *  ** **  **  * 
******  ***  ***  * **  *  ** ** **    * * *  *  *   *** 
     * * ***** * * * * *  **    *  *  **  *  *   *  ****** *** *   ** * *
    }
  ** *** ****  ** * *   ** ** ** *  0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.28
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 9.1k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 8.7k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 10.9k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 8.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users