2 like 0 dislike
15.1k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 15.1k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

** *** * ** *** ** * i;
*** ****** ** * ** j;
* ** *** * ***** * * ** * newNum1;
* ***** ** ** ** newNum2;
** * * ** *** ** * gcd;
* ** ** *** *** ** ** rem;
**** **** ** * * * * * num1, num2;

* **** * *** * * * * ** * * **** **** * *

* * * ***** *** *
** * ** * ** ** ** * *

** *** * ****** * ** ** *** != 0)
* * * ** * *** * *
* ***** **** * * *** * * ** **** * * * *** ** = j%i;
* * * *** * * ** *** * *** ** * * = i;
** * ** * *** ** * * * **** * * ** * * * * *** ** = rem;
* ******** **** * *
** *** ** ** * * ***

* **** * ** * * ** **** = num1/gcd;
** * ** ** * ****** *** ** * = num2/gcd;

* * ** * * **** ***** * * * ** == 1)
    {
* ** * * * ** **** ** * **** ******* * * * * ** * ** **** ** * * *
    }

** * * * * * ** ** **
    {
* *** ** * * ** * * * * ** * **** *** ****** * ** * * ** ** * *
** ** **** ** ** * *

* * * ** * * *** * * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
**** * ** * *** ** * ****** ** ******* * * * ******** * *

* * * * * *** * ***** ****** ** **
*** ** ** ** ** ** ** * * ** * ** * *** ** * * ** * ************ *

    else{
** *** * *** * ** ** * *
    {
* * *** * ** * ** * **
* * * * * * ** **** * * * * **** ** *** ** ***** * * * * * *** ** && deno%i==0)
** * * ** *** * * * * * * * ** * ** *** **** * * ** *** **
* ** * * * * * * * * *** ** **** *** * * * *** * ** * * ** * * ***** *
* ** * *** * * ****** **** **** * ** *** *** *** * *** *** * **** * * * ** ** * * * * * **
* * ** ***** *** *** * * * *** * * * ***** * * *** * * *
    }

* ***** ** * ****** ** * * *
    {
*** *** * * * * * * ** ** * *
** ** ** ** *** ** *** ***** * * **** * ***** * * * ***** ** *** * ** && deno%i==0)
* ** * * *** * * *** * ** * ** * * ***** * * * **** *** * *
* **** ** * * * * * ** ** ** *** * * * * * * * * *** *** ** * *** * ***** *** **** ***** ** **
* * * * * * * **** * **** * * * *** **** *** ** * *** * ** ** * * * *** * *****
**** ** * ** ** ** * * * * * * * * * * ** **
    }
* ** * * * * * * * ** * * * * * ** ****** * * *

    }




* * ** ** ***** * ***** * ** * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ***** * *
#include ** *** **

int gcd(int n, int m)
{
* **** * * * ***** gcd, remainder;

* *** *** * * ** ** (n != 0)
** * ***** ** *** ** ****
* ** *** * ** *** * ****** * ** * = m % n;
** *** ** * ** * * ** **** ** * * * = n;
**** * * ** * *** * ** ** **** ****** **** * **** * = remainder;
* ***** ** ** **** * *

* ** ** * * ** ** * * ** * = m;

* ** * * *** * * * * * * gcd;
}

int main (int argc, const char * argv[]) {

** * * *** * ** * number1, number2;
** * **** *** * ** newNumber1, newNumber2;

* * * ** ** * ** * * ***** *** ******* * * **** *

** * ** *** ** ** ** * * * * = number1 / ** number2);
**** ** ** * ** ** * = number2 / *** **** number2);

** **** ** * * ** * *** **** ***
*** ** * * ** * * *** **** ** ** *** * *
* ***** ** * *** *** *
** ** * * * * *** *** * * * * ** * *** ***
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
*** * *** * *
* * *** * * *

int * * n, int m)
{
* ** int gcd, * *

* * ** * ** ** (n != 0)
*** * * {
* **** * * * * * ** * * * * = m % n;
* ** *** * * * * * * m = n;
* * * ** * ** * ** * *** n = ** * ***
* * * **** }

** *** gcd = m;

* ** * *** * * gcd;
}

int main (int ** ** char * * {

* * * * * * * int * * ** *****
* * **** ** ** int * ** ***

* ** * ** * * * ** * **** *****

**** * * ** = **** / ** * * *
*** ****** * * *** = ** ** / * * ** **

* ** * **** * if * *** * *** * *
* *** ** ** *** * ** * ** * ***
* ** ** * * else
* * ** ** ****** * *** * *** * * * * *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** **** ******* ** * i;
* * * * * * * * ** *** j;
* * ** * *** ** * newNum1;
* ** *** *** ** ** newNum2;
**** ** * * * * * * gcd;
***** * ***** * *** * **** rem;
** * ***** ** * * * * * num1, num2;
    
** * * **** * ** * * * **** * ** ** * * *** * * *
* * * **** * ** ****** *
******* * ** * * ****** **
** ** ** ****** **** * *
* * ** *** * * ***
* ** * * ** *** * * ******* != 0)
*** ***** *** * * ***
** * ** * ** * ***** ** * * * * *** ** = j%i;
* ***** * * ** * ** * ** * * * * ** ******** ** = i;
*** *** ** ** ** * * * * ** * * = rem;
** **** * **** ********
* **** * *** * * * * * *
    
** * * * ** ** * ** = num1/gcd;
***** * ** ** *** **** * **** = num2/gcd;
    
** * ** ** * ** ** ******* == 1)
** ** ** ******** * * * *
****** **** * * * ** **** * * *** ** ***** ** * ** ** *** * *** * *** * *
** * ** *** * ** ** * ***
    
*** * *** ** ** ** *
** * * *** ***** *** *
** *** ** * * * * *** **** *** ** **** **** * * *** * *** * * * **
* * *** * * * ** *
    
*** * ** ****** ** * * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** ** *** ** *** * * * i;
* * **** ** * * ** * * * j;
* *** ** ** ** ** * *** newNum1;
* **** * * **** * * ** ** * newNum2;
* *** ** ***** ** * * *** gcd;
** **** ** *** ** ** * ** rem;
* * **** ** * * * * * num1, num2;
    
* **** * * * * * * * * ** * * ******* *** * *
* * * ** ** * ** * * ****
* * * ** *** ****** ** ******
*** *** **** * * * ** *
* ** * ** ** *****
* * *** ** * * * * * != 0)
** * ** ****** * ***
* * ** * *** * * **** * * * * ** * * = j%i;
* * * ** ****** * * * * * ** *** ** = i;
** * * * * ***** *** * ** * ** * * * ** = rem;
** * *** **** ***
* ****** * ** * ** *
    
*** *** ** ** * * **** = num1/gcd;
***** ** ** ** * * **** * = num2/gcd;
    
* * * ** *** * * * *** == 1)
** * ** **** ** * ***
* * * * * ** *** * * * ** * *** *** * ** ******* *** *
* *** ******* ******* ** **
    
* *** * * * * * ***
* ** * *** ** *
* ** * **** * ** * * **** * * * *** * ** * ***** ** ** ** **
* * ** **** ** ** * ** *
    
*** * * * * * **** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* ** **** * *** ** ** **** *** * * ** ************* ****
**** * * * * **** * * ** * * **** ** ****** ***
    {
* * * * ** * * ***** ******* * * ******* ** * **** * *** **
* **** ** ** *** * * *** ** **** * ** * *
* ** ***** * **** ** * ** ***
* *** * * ** ** * ** ** ** * *** **
** ******** **** ***** *** * * ** **** * ***

* * * ** * *** * **
* ***** * ** * ****** **** ****** * ** ** ** *** * * * * **** * **** * * **** **** *
* * ** ** * * ** * * **** * * ** ** * ** * * * ** *******


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* ** * ** * * *** * a,b,GCD;
** * * ** * **** * ** ** ** * * *** * * * *
* * **** *** ** * *** *** ** * ** *
**** ** * ** * * ** * * * *
* *** ** **** * *** ** * ** * *** ** ** ** * ** ** * ** ***
* * ** * * * * * ** *
*** **** * * *** * * *** * *** * **** * * * ** ** * ***** * * *
* ** ********* **** *** ** * 0;
}
** * ** * ** * * ** * gcd(int a, int b){
* * * * * * ** * **** ** * * * ** ** * ** * * (!b) return (a);
*** **** **** * **** * *** * ** * * * *** gcd(b, a % b);
* * ** ** ******* * ****
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** *** *
#include * * * * **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
** ***** ******** *** gcd, remainder;
** *** * * ******** *
** * * **** ** * * **** (n != 0)
* **** * * **** * **
* * *** * * * ** * *** *** ** ** * * **** = m % n;
** **** * * * ** ** * ****** * ** * ***** = n;
**** ** ** * * ** *** ** ** ** *** * * *** * = remainder;
* * ** * **** *
** ****** * ** * ** ***
* **** * ** * * *** * *** * = m;
* * ** * * ** * * *** **
* ** * * *** **** ** * gcd;
}
int main (int argc, const char * argv[]) {
***** ***** ** ** * number1, number2;
*** ** * *** * ** * * ** * newNumber1, newNumber2;
*** *** ** ** ** **
* ** ** * *** ***
* *** ** *** ** ***** ** ** * * * ******** * * * * *
* ****** ** * ** **
** ** * * *** * * * * * = number1 / gcd(number1, number2);
***** * * * * * *** * ** ** *** = number2 / * ** * * number2);
** * *** *** ****
** * *** * * ** *******
** * **** * * * *** *** * ( ** *
****** * ***** * * *** ** * ** ** *** * ** ** * * ** ** ** ** newNumber1);
*** ***** * * * * * ***
* * ** * *** *** *
* **** ** ***** * ***** * *** * * * * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** *** ** **** ** a,b,c,d,e,f;
* * ** ** ** ****** * * ** ** * *** * * ** * *** * ** *
**** ***** * * * **
* *** * * * ** * **
* * * ** *** * **
    {
** * * * * * ***** ** * ** *** ** **
* * ** * * * ******* * * ** *** * * * *** * * * *
**** * *** * **** **** * *** ** ** ** * *
    }
* ** * * * * * * ** * *** * ** *
    {
* ****** * ***** **** * ** ** ***** * *
* *** * * **** ** ** ** **** * * *** * ** *** * * ****** **
* * * *** **** ** ** *** ***** ***** *
* *** *** ** *** * ** ** * * ** * * ***** *** ** ** ** ** * * *****
    }
* * * * * * *** ** * ** *
    {
*** ** ****** ********* *** * *** * ** ***
* * ** ** ** * ** *** *** *** ** ** **** ** ** * *** * *
** *** * ** * * *** * *** * ** * ** ** * **
*** * **** * * ** ****** *** ** ** * * * * ************ * *** *
    }
*** * * ** * * *** ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.166
©2016-2026

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 15.4k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 15.1k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 19.4k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 14.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users