11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
15.2k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 15.2k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

*    **  * *    **  *  ** i;
**     **   **   *** ** *  * *  ** j;
 * *** *   *     * *   *     newNum1;
 *** *  * * *   ***  *    *  * newNum2;
 **  * *   **   **  *  **** *  gcd;
*  *     *  ** ** * *  *   rem;
    *** * ** * ** *** **     num1, num2;

 * **  *  *   ***** *      *      **   *     *    * *** **  * * *** * 

* **  * *    *** * *   *  * * 
**  ***    * **   * **  * * **  * * **

  *   *  ***** * * *   * *   * ***** != 0)
 ****   * * *** ***    *  *
* *  *  *  **  ***   **    *****    *  **  * *  * * *      = j%i;
* * *** ** * **    **** *** * * ****  **  * ** = i;
*** * * * ***  **     *  ** *  *****  * **    ****  *      = rem;
 * *   *  **  *  *  * ** *
*   **  *   *******    ******** 

****  * ***     *  **    * ********** = num1/gcd;
* ***   **    * ****** ****  = num2/gcd;

*** * ** * * *    ** **  **  ***   == 1)
    {
* *  *     *****  *   *** *** *** * * *   * *      **  *   * **   * *   ***     *  ***
    }

      ****  * **** ****  * * ********
    {
   ********      * * ******  *    ***   ***     * **   *  ** ** *** * ** ** ** ** ** 
**  *    *    *  * **** ***

   *  ** *** * *  *  * **    *  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
 *  * ****** *  *  * **** ** *  * ** ***** *  **   **   *   *      

 **  *  **  **** **    **     *   *   *** 
 *  *  **    * **   ***  ** *    **** * ******  * * *     ** * *     ***    *  

    else{
  * **     *   *  *****  ***   ***********
    {
**  ** *  ****   * * *    **** *  *  ***  *
**  *** *  * *     * *****   *** * *    * ** * ****** **  **   *    *      * && deno%i==0)
** * *  * *  ** *** *  *  **  *  ** *  ****   * *  * ***** *** *  *  **   *
     * ** * *  **  *  **     * **** ** ***** * ** ** *       ***  *** **** ** **  ** *    *  *** *
**  *    * ** *  ***  **  *   *  **  *** *    ***** *** *  *  * ***   *   * * * **  * *** * *    ** 
   *      * * * ** *  *     * * **** *  * * *** ***** ***    *   ***      *   * *  
    }

 **    *** *** * **    **** ** *** ** * 
    {
 * **  * * * * ***   ** * ** * * *
* ****  * * * ** *** *** *******   **     *  **** *  *  *        **      ** ** *   ****  * * && deno%i==0)
  ** **  **  * **  *  * *     *  *** ** ** *      *  **  *  * * ** * * * *         
  * *  **  ***  ** ***  *   *****    ** **   * *    ** ** **    *   * *   **  ** ** ** *** *** 
** **    *   *****   * *   * **     ***  *  **** ** * * *  ****   ***** **** ******        * ***   *  ** * *   *** 
  * *  *****  ** ** * *   ****** ***      * *   * ***  ***      * **   *** ** *  * *
    }
* *** * ***** *     *** **  ******** *** ****  ** **  **   *

    }




**  ** * * **  **  *** * * *   0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ***** * ** * **  
#include  * *    **  **  **

int gcd(int n, int m)
{
 *  *  **   ****   *****  *   *  gcd, remainder;

 *  *  ***   *** * *  *  *** (n != 0)
*  * * ****    * ** * *** 
***     **** ** *  *** **** *** ** *        **** *       **  = m % n;
 ** **   * *  ****** ***  ******  *  ******* ** * = n;
  * *      *     ** ** *  * ** ** ** * ***    *  = remainder;
* **    *     *   **   **** 

*  *** * ****  *  ******   = m;

 * * * ***  ****  * **   *   **  gcd;
}

int main (int argc, const char * argv[]) {

  ***    *   * * ****  ** **  number1, number2;
 * *  ****  **    **  * * newNumber1, newNumber2;

* **  **   *** ************ **     * *** ****  *    * *** *   ***  ***** * 

  * *  *  ***  *  * * *   * **    ****  = number1 /   * ****  number2);
*   **   * *   * * * * * * * * = number2 / *  *** ** number2);

***  * ****  * ** ****   ** **   *   *    *  *** ** 
  ***    *  **** * **  **   *  ***  *   ** *     **      **
****   *  **          * * *****
 **  *** *   ** *  **  *****   * ** *  **  * **  ** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* ***     * **     *   
** **  ***  * * **  

int       n, int m)
{
* ***      * **  * int gcd, **** * 

*******  ****   *** * (n != 0)
 ****      * * {
 ** **            * **         ** *** = m % n;
**** *    **** *  *  ***  *  *** *  m = n;
  * ***** *   ** **     n =  *      
 *** ****  ** *  }

  ****   ** gcd = m;

*   * ***  ** *    ** gcd;
}

int main (int  * * ** * char *  *** {

 * *    * ** int  *****  * 
 * *  *** **   * int  ** * **   * * 

      ** * *         **** ** * *    *   *     **  *       ** *

 ** *  *****      *  = *  **  / ***   ** * *
*  *  *      * **    * *  = * ** / **  ***      *

******* *  * * ** * if **  * *  **   **     **
* ****  **** *  **         **  **    *  *  * * * * 
*  * **   * *  * else
* *  *  ****** * * ***   * ** ** *   ** * *  *   *  * 
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
* * *  *          * *  *   i;
 **   * *** * *  ****  *  **  * j;
  *     *  * ** ** ****  *  **   newNum1;
****** ***   *  **  *  **  *  newNum2;
* * *  * **  * ****    * *  gcd;
** * *  *  ***** *        * * rem;
   *    *  * *  ****     *  * num1, num2;
    
*  *  *   ****   *** **  ****   * ** **   *  **  ****** **  * *** *   
**  *  * *  **   ** *** ***   
** ** **   * *   *    **** *
*           *** ** **  *  ***   
* * *** * * ***  *      *****
    **        *     * **** *   * != 0)
  * *  ***       * * * *   
 * ** *  * **     * *   **  *  ** * * *  *  ** *   * ** *    = j%i;
    *   ** ** **  ** ***  **   *    * ** * * **  = i;
*** **** * *** **   *    * *  *  ** **      *   * = rem;
* ** *  ***  *******  * ***
 * * **** ** *** * * ** * ** 
    
* *       *   ** ****     *   **  = num1/gcd;
***** *  ***    *****  *    * * *   = num2/gcd;
    
  *  * * *   *** *** *** **      == 1)
*** *  ** * * * *** **   **  
  *  * *   **   * *** * **** **  *******  *        * *       ****** *  *
  ** * * **   **  * ** **  ***
    
*  *  * * *   *     *  **    
 *  *  ***** * *   ** ****  *** 
*   * * **  ****  ***  *  * *  ** * **   **    **  *     *** ***     *   ***     * *   * 
 * * ** * ** * ****** ** **
    
 *     ***  *** ** ****          0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 * *  *  *   ** * *** **** *  i;
**   ** *  *****   *   **  ** j;
 ****  *   * ** ** * * **** ** newNum1;
**** ***** **** *  * ** * newNum2;
 *  * *   *  ** ** * * *** ** gcd;
* *  **** **    **** **  * rem;
* **** *  * ** * **  * * * * num1, num2;
    
 *    *** *** *  ** ** **   *  * ***  *    ****** *  *  *     * *
** *** *  *   *   ** * *** *
* *** *  *  ** *   * ****  ***     ***
** *** ** *  * **   ** **  ** *
 * *   ** * *  ***** ***** 
 *  * ** **    * *        ****** != 0)
**    *  *** **  *  *  ** 
      *****   ********   * ****  * * *    * * *    * * *  = j%i;
*  * *  **    *** **  *  **  * *   **     * *     *  = i;
****  *   *    * * ******* ** ** **  *  **      ** * **  = rem;
***  *** *   *  ** * * * * *   *
******      * ****  ***** **
    
 **** *    * *   *  *  ** * = num1/gcd;
  ** * **  * * * *  *      = num2/gcd;
    
  * *****   *** *   *** *  **** ** *  == 1)
* *  ***** * * * *** *    
 * * * ****  * * ** *  *       **  *  * ***     ** *****  **  *****  * * ******** ***
 **    ** * *   *   ** *   ** 
    
* * *   ** **      *** *     
****** **  *    **** *  *  *
* * *** *  ** **  * ***  ********     *    ** *   * ** *   ** * * * ** * ***   **
 *  *  ****  *      *  ***
    
***   *******  * * *  *  ** *** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
 ** *  *  *** * *   *  * * ***       * *  ***  **  * * 
  ** *  ** **  *  *  *  ** *  * *        *   * **   *
    {
 *     * *  * *    *****  * *   ****** **** ** *  ** ** **   *  ** **  *  *
* ** *  * * * *    * *  *****  *** * **  ***  **** * *  **  
  * *      **  ***     ****    *** *** ***
****  * *    ***  *    *  * * * *  * *  ***  
 *  **   ***      *    ****  **  * *    * 

*  ** * **** ***   *      *    
 *   **     * **  ****  *   *** * **** ** **  ***    **  ** * ** *   **  *** * *    *         **   * ******
*** *** * *  **    **  *****  **  ** * *****    * ******** **   ** *       ****  *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
 * * **   ** * ***** * ***** * *  a,b,GCD;
* * ***   * *** * * *  *  ** ** ***  **       *  * **  ** 
******* * ***  **** *   ***  * * * *
    *    * ****  **   * **  *
*  * * **     * *   ***  ** ****  *  * **  ****  * ******  ***** *  **** *
* ***  * *** * *  ****    
 *** * *  * *** *   *    ** ***  ** * * *  *   * * ***  ** *   *   * *   
** ***  ***   ***   ***  *  ***     0;
}
 * **  *  *     *   * * gcd(int a, int b){
* ** * *****  ** *    ***    * ** *  *  *  ** **  **  (!b) return (a);
     *** ** **    ** ** ** * ** * *  *  *   ***   ******  *   gcd(b, a % b);
 *****  ********  *** ** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** **** **    
#include *        ****   

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* *** *    **   **  *** *  **  ** gcd, remainder;
 *  *    *  *** *  *** 
****      *    **** **** * (n != 0)
* **   *  *  **** **** ** * **
   ** ****  * **  *     ** *** *  * * **  *  **  * ***     ***  ** ***   = m % n;
  ** * ** **** * **   * ** ** *   * * ***** * ** ** = n;
 **  ***  * ***** ** * **** *******  **** *        ** * = remainder;
  ** *     * ******* * ***  *
*  ** *  * *      **   * 
 **** * *  *  * *   **  * **   *  = m;
*       * *****      ***  ** 
 **  ****   *    *  *** * gcd;
}
int main (int argc, const char * argv[]) {
**** * ** ** *** * **      ** number1, number2;
  ** **     *****  *  *   newNumber1, newNumber2;
*    **   * *  * ** *
    * ***   *    *  * *** **
    ***  **    ***** *** *   *   *    ****     **    **  *   *********  
     ** ** * *** *** *****   **
 ****   * * ******* *  * * **  * = number1 / gcd(number1, number2);
* *   ** * * **     ***   ***   **   = number2 /          * number2);
* ** ***   *   * * ***  **** *
**** ** * **    *   * * **
 * ***** *   **  * *   *   ( * *****
** * *   ****  ****  **    *****  *********  ** * *  * *  ***** **  **     newNumber1);
** ***  **** ***  *    * **** 
 *     ****  *  *  *   **
 *   * ** ****  *  *** *      * *** **  *  *   newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** *  **** *** *    **** ****  a,b,c,d,e,f;
 *    **     ** *** ***    * ** ** ** *   *   ** *   *   **  * 
**** *   * *** ** ** *  *  * *  **  
** ** * *   * *     * ** *
* ****  *      *****  ***    * * **
    {
* *****     ** **       ***** ** * *  * ***** ****
   **  * * **  **** **  *** * *** *  ** * *  *  * **** * ** *  *  
 * **     **   *  **     * *   **** *   *      *** *
    }
*****  *   * **   ****  * ** *    * * 
    {
*  * **        * *  *  * * * **     * *    * **    
  **    ***** ** *  * *  **    * * * **  * *     *** *  * *  * * ** ** **  ***  *
* *****   **   *   ****  *** *** **  *****   *      **  **  
   *  ***** * *****    **  *** ** *** ***** * *******     ***** **** **  **  **   ** 
    }
*   *    *** * ** *  *  **
    {
 * ** ** ** **  *  ***** * *  **  *    ***   *  * ** *   * ***
 *  *    *     * ** * *** **     ****** **  *    * **  *  * ****  *  **  *********
 ** *** **      *** **       * ** **   *** *   ** *  ** 
 *  *****  *  **     * ****     **  ***  ** *  *** *   *  * * *   *  *    *******
    }
**  ** **   ****   ***  **  0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.168
©2016-2026

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 15.5k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 15.2k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 19.7k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 15k views
12,783 questions
183,442 answers
172,219 comments
4,824 users