2 like 0 dislike
12.4k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 12.4k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* * ** ********* * * ** i;
* * ** **** * * *** * *** j;
* ** * ********* * * * *** newNum1;
*** * *********** ** newNum2;
***** * ******* *** * gcd;
* **** * * ** * rem;
* *** * ** ***** num1, num2;

* ** * ** * *** **** ** * *** * * **** * * *** ** * * *

* * ** * * * *** * * * * *
* **** ***** ** * * * *

** ** * **** *** * * ** *** != 0)
* **** * * ***
** * * ** ** * *** * ** * *** *** ** * = j%i;
* ***** * ** *** **** * * ***** * ** * = i;
* *** * * ** ** ** * ** ** *** * * ** ** * = rem;
* ** **** *** * ** *
** ** ** ** **** ** * * *

** ** *** ** ** ** * * = num1/gcd;
** ** **** ** * ** * **** * = num2/gcd;

****** ** ***** * *** *** * ** == 1)
    {
* * *** ** *** ** * ** * * ** * ** * ***** * ** * ** ***** ***
    }

* **** * * *** ** *** *
    {
* ** * ** **** *** ** ******** ** ***** * * ** *** * * * *** * * * * *****
** ** * * *** * **

**** * * * * *** *** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** * **** * ** * ** ****** * *** ** ** * ******* * * * ***** * *

** **** ** ** ** * ** * *****
* * * * ********* * *** * ** ** * *** * *

    else{
* ** * * **** **
    {
* *** * * ** *** * * ***** * * * **
*** * * * * * ***** * * * * ** ** * ** *** ** * * * *** * * && deno%i==0)
* *** * * * *** ** * * *** * * * ** * ** ** ** ** *
*** ** ** ** *** * * **** ** *** **** *** * * * * ** * * * ** * * * *
* ** ** *** *** *** * ** * * ** * *** * * * ** * * * * * ** * * ** *** *** *
* * ** *** * ** ** ** **** ***** * *** ** ** * ** * ** * * **
    }

******* ** *** *** * *** ** **
    {
* * * ** ** *** ** **** **** * ** ****
** ** * *** * ** * * * ** ** *** * **** * * * * ** ******* && deno%i==0)
* * * * **** ** * * * ** ** ****** * **** ***** * ** * * ***** *
** * ** * * * * * *** ****** ** * * ** * *** ** * **** * * *** * * * ***
* * ***** *** ** ** **** * * * ***** ******* ** *** * ******* * * **** * * *** **** ***
** *** * * * * *** ** ** ********* * * * * ** * * ******* **** **
    }
*** ** **** **** * * * ** * * *** * **** *

    }




** * ***** ** ****** **** * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * ** **
#include * * ** *

int gcd(int n, int m)
{
** * * ****** ** * * gcd, remainder;

**** ***** **** ** (n != 0)
* * * ** *** * *** ** *
** * ***** * * * ****** ** ** **** *** *** * ** * = m % n;
*** * ** * * * * * *** ** ** ** *** ** * * = n;
*** * *** ** * ** * * * * * *** * * ** = remainder;
****** ** * * * * ***

****** ****** * ****** * = m;

* *** ** * * ** * ** * * gcd;
}

int main (int argc, const char * argv[]) {

** * * * * *** * ** * number1, number2;
* ** * * ** ** * ** ** newNumber1, newNumber2;

** * * * * ** * * *** * * ** *** * ** ****** ** ** ** ** * *

* ** ** * * * * * = number1 / ** * * number2);
* *** * ** * *** * * *** = number2 / * ** * number2);

* **** * *** **** * * * * *** *
** ** * * *** * * * ** ** ******* * * * **
* ** * ** ** * *
* * ** * *** ***** ** ** *** ***** **** ** ** ** **
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
** * * ** ** ** ** * *
* * * ** * *** *

int * * * n, int m)
{
** ** * int gcd, * ***

* * *** ** ** * (n != 0)
* *** *** * {
*** * * ***** ** *** ** * = m % n;
* ** ** ** * ** * * ** * * m = n;
* * * **** **** ** n = *
*** *** ** }

*** ** ** gcd = m;

** ***** * gcd;
}

int main (int **** * ** char * * {

** ** *** ** *** int ***** * * *
* ** * int * * * *** *

** **** *** ** * ** **** ** * * * ***** * * * * ***

*** ** * ** * ** = * * * / * * *
* * ** * ** = * / * * *

** * * * *** ** if * * * ** * * *
* ** ** * *** * * * * ** ** * * ** * * ** *
* * ***** else
*** * *** * * * * *** * *** **** * * ***
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** ** *** *** ** * * ** ** i;
** * * ** * ** * *** **** *** j;
* * * ***** * ****** * * * * newNum1;
* ** **** ** * * * * ** * newNum2;
**** *** * * * * * ** * gcd;
* *** **** * ***** * * * ** rem;
** ** ** * ** * *** num1, num2;
    
** * * * ******* * ** *** * ** ***** * * ** * ** *
*** ** **** ****** *
** * **** *** * ** **** *
* *** * * ** *** * *
* * ** ** *** * * * *
* *** * * ** * ** * != 0)
* *** ** ** * *** * ** *
** **** **** * * *** ** * ** **** * *** * = j%i;
* ** ****** ** * * * **** ** * ** * *** * ** ** = i;
** *** *** ****** ** * * ** **** ** * = rem;
** *** * ** * * *
** *** * * * ** * *****
    
*** * * * ** ** * = num1/gcd;
** * **** ** ******* * * = num2/gcd;
    
* * ** ** ** * * **** * == 1)
* * **** ** * * * * *
* * ** * * ** * ** **** ** * * * *** * ******** *** * ** * *** **
* * * * ***** *****
    
*** ** ** * * ***** **
* ** **** * ****** *
*** * * ** * * * * * *** **** **** * ****** ** * * * *** * ** * * **
* ** ** * * ** ** ** **
    
*** ** ** * * * ** * * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * * **** * * *** ** i;
* * * ** ** * * * *** ** * j;
***** ** * ** * * newNum1;
* * ** ** *** ** * * newNum2;
******** ** ** * * * * ** gcd;
***** * ** * *** * *** *** rem;
* **** **** ** * * * * num1, num2;
    
**** ** **** ** *** * * ***** * * * * * * * * * * *
* *** ** *** ** *
* * * * * ** * ***** **
***** *** * * * *
*** * * ** * * **
*** * * * * * * * * * != 0)
*** *** ** ** **
*** * * * ** ** *** *** *** ** * **** *** = j%i;
* **** ** ** ** *** * * * * *** **** = i;
* * * *** *** ** **** * * * * ** * * * **** = rem;
* * **** * ** * * * **
***** * * ******** ** ** ** *
    
* **** * * *** * **** = num1/gcd;
* * ** * * **** ** * * * * * * = num2/gcd;
    
* ** **** ** * ** ** ** == 1)
* * * ****** * * *
* * **** **** * ** * * ** **** *** ** ** * * ** * * ***
**** ******* ** ** * * * ***
    
* * * *** * * ***
* ***** * * * ** ** ****
** * *** * * * * * ** ** ** **** * * * * ** * ** * ** * **** * *** ***
** **** * * * * *** * **
    
***** *** * *** **** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* * ** * ** * * * * ** *** ** ** * * * * * * * **
** * * * ***** * * ** * * *** * ** * ***
    {
*** ** *** ** * ** **** ** *** * * ****** * * **** * ****
***** ** *** * * ***** ** * ******** * ** *
* ** * * ** **** **** * ** ***
* * *** * * * * ****** * * *
* * ******* *** ******* ** *** * * *** * *

******* **** * * * * * ** *
* * * ** * * * * * * * * * * ** * * ** * *** *** * * * ** * * * * ** ***
** * *** ** ** **** * ** * * * * ** * * *** * ***** * ** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* ** * ** * *** * * *** * a,b,GCD;
* ****** * *** **** * ** * ** ***** ** * * ** * ** * *
* * *** ** * ******** ** *
* * * * *** * *** * ** ** **
* * ** ** ** * ** *** * *** * * * *** ** * ** * ******
* * * ** **** * * * *
* *** * ** * * * ** * ** * **** * **** ** ***** ** * * * ** * ** *
** * **** * *** * **** **** 0;
}
* ** * ** * ** * * * gcd(int a, int b){
*** * ** ** ** ** ** * * * * ** ** * * * ** *** (!b) return (a);
*** ** * ** * ** ** ** *** ** * * ** * * * * * gcd(b, a % b);
* *** ** ** * ** * **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ***
#include *** * ****** **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
** * ** ** * * ** gcd, remainder;
*** ********* ** *
* *** **** ** * ** * (n != 0)
** ** * * * * ** *
* * * *** * *** * ******* * * * * * *** * * ** * = m % n;
* *** * * * **** ** ** * * ** = n;
******* ** ** * * ** * * * ** * **** = remainder;
* ****** * * * * * ****
* **** ** * *
***** **** * * * * *** = m;
*** * * ** * * * * ** **
*** * ** * *** * * * **** gcd;
}
int main (int argc, const char * argv[]) {
**** ** *** ** * * * number1, number2;
* * ** ***** * * * ** newNumber1, newNumber2;
*** * ** * * * *******
*** * * ** ** * **
** ******** * ** ** ** * * ** *** * * * ** * **** ***
* * * ** * * * *
* ** ** ** * * ** * * * ** = number1 / gcd(number1, number2);
* * ** ** * * *** ****** * ** = number2 / ** * ** number2);
** ** *** ** ** * **
**** * *** ** * ***
**** ** * ***** ** ( * * **
* ** ** ******* * ** *** *** *** * * *** ** *** ******* * * newNumber1);
* ***** * ** ** ** **
** *** * * ***
* ****** * * ** ** * ****** * * * ** * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
****** ** * * ** * ** * a,b,c,d,e,f;
* * **** * *** ** * * *** ** * *** **** **** ** *** *
* *** **** ** * *** ***
* * * ** *** * **** * **
* * *** * *** *** *
    {
** * * * * *** * * * * ** ******* ** ** ***
* *** *** * * * * *** ** ***** * **** * * *
** * * *** **** ** * ** ** **** ****
    }
*** ** ******* * * ** *** *
    {
* * * * * *** * *** ***** ** * ** ** **** ** ***
* ** * ********* ** * ** * * * ** * * **** *** ** ** *** * * ****
* *** *** * * * ** * * ***** ***** *
* ** ** *** *** * * *** * ** * * ** * ****** * * *** ** **
    }
* * * * * * *****
    {
* * * **** *** ** ** ** * ******* * * * *
* ** *** * ** * * ** ** * * * * *** * ******* * **** ****** ** ** *
** * * ***** ** * *** * * **** ** * **
** *** * * *** * *** * ** ** * ** * * ** * ** * ** *** * *
    }
* ** ** ** * ** * * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.98
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 12.5k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 12.4k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 15.7k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 12k views
12,783 questions
183,442 answers
172,219 comments
4,824 users