2 like 0 dislike
13.6k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 13.6k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* * **** * ** * **** i;
** * * ** ***** ** ** j;
*** *** * ** ** *** ** ** ** newNum1;
* * ****** **** **** newNum2;
* ** * ** * * * gcd;
*** *** * *** * *** * rem;
* * * * * * *** ** *** num1, num2;

************* * ******* * * * *** * *** * ** *** **** * *

******* * * *** *** * **
** * * *** ** * ** ********

* ** **** * *** ** ** != 0)
* **** * * * * **
* *** ***** * ***** * ** * *** ** * * ** * * = j%i;
* ** ** * *** * * * ** *** * *** * * **** * = i;
* * ** * * * * * * * * **** **** ** * *** = rem;
* ** **** *** * * * * *
* ** * * ** * ** *****

* * ** *** ** * ** **** * ** ** = num1/gcd;
**** * * * * * = num2/gcd;

* * * * * * ***** *** == 1)
    {
*** *** ****** *** * ** * *** *** * ** * ****** * ** ** *** **
    }

** * **** ** * * * ***
    {
** *** ** ** ** * * ** **** * * ** ** *** *** ** * **
******* *** * ** * *** ** *

** *** ** ** **** ** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* ****** * * * * ** ** ** * * *** ** ** *** * *

* ** *** ** * ** ** * * ***
* * * ** ** *** * ** * * ***** **** * * ** * *

    else{
* * * * * **** ** ** * **
    {
***** **** * * * ** ** * * ***
* **** * * *** ******* * * * * * * * **** *** * * *** ***** * * ** **** && deno%i==0)
* * * ** ** * * * * * * ** * *** * * * ** * * ** ***
** ** **** * *** * **** * ** * * ** * * * * **** *** ** ***** ******** ** * *** * ** **
* * * * * ** * ** *** ** ** * ** **** ** * ****** ********* * * **** * *
***** ** ** * ** ** * ** *** * ** **** * ** ** * *** ** *** ** *
    }

***** * **** * * * ** ** * **
    {
* **** *** * * * ** *** ** *
* * ** * * * ** * * *** * * *** * ** *** ** * * * ** * * ** && deno%i==0)
* ** ** * * ** * * **** * * * ******* ** ** **** * ** * ** * *
*** * * ****** * * * * **** * *** * * ** ** * * * ** ** * ** **** ** * * ** * *
** ** **** * *** ****** * * * * * * ** **** * * * ** * * * ** **** * ** *** ** **
****** * * **** * * * * * * * *** ***** ****** * * *** * *
    }
* *** * *** * * ** * *** * * *

    }




** ** * * **** * * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** *** ***
#include *** *** * ** **

int gcd(int n, int m)
{
* ** ** * * ** * * gcd, remainder;

** * * **** * ***** (n != 0)
***** * ** ** ***** *
* ** *** * * ** ** **** *** *** * * * * = m % n;
* ** * ** ******* *** * ** = n;
* * * * * ** * *** * *** ** ***** ** ** = remainder;
** *** * * * ** **** *

** ** ** * ** * ** ** = m;

** * ** * ** * ** ***** * gcd;
}

int main (int argc, const char * argv[]) {

****** *** **** * * number1, number2;
** * * * * * **** ** * newNumber1, newNumber2;

**** * *** * ** *** * ***** * * * **** ** * * * * * **

*** * * * * ***** * ** = number1 / * * number2);
* * ** ** * *** * * * * * *** = number2 / *** ** number2);

* ** **** * * * * ** *** ** **** * *
* *** * * ** *** ***** **** ** * * * * ** * *** *
* * * * **** **
* * ** *** * ** * *** *** ** * *** * ***** * ***
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* ** ** *** ** ** *
* * ** **** **

int ** n, int m)
{
* ** * * * * int gcd, * *** *

* * * * **** * (n != 0)
* ** * * {
** *** * ** **** * **** ** ** = m % n;
** * * * *** * * * * m = n;
* * ** *** * * * * n = * *
* * * * ** }

** * * * * gcd = m;

** ** **** gcd;
}

int main (int * char * {

******** * * * * int * ** * ***
*** *** ** * int * ** * * *** *

**** * ** ** ** ** ** **** ** * ***** * *

* **** * * *** * * = * **** / * * * *
*** * ** * * * = * * * / * **** ** ***

* * **** if ** *** * ** * *
* * * ** * * ** * ** * * ** ** * * **** ***
* * ** * else
** * ** ** ** ** ** * **** * * * * * ** * ***** ***
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** ***** * * *** ** * i;
* * *** * ******** * * j;
* ** * * * * ** * * * ** newNum1;
**** ** * *** * * * * newNum2;
** ** ** * * gcd;
*** ** * * * ** *** ** * * rem;
** * * * * *** * * * num1, num2;
    
* ** * * * ** * **** * ** * * * *** * * ** * ***** * ** * ***
* * * * ** * ** * *
* **** * **** *** *
**** * * ** *** * * *** **
** *** * *** ** * ******
** * *** * * * * != 0)
** **** * ** *
***** **** * ** **** ** ** * * * * * * * = j%i;
* *** * * * ** * ** * * * ** *** * * ** ** * = i;
**** * * * * * * ** **** * ** * * ** * = rem;
* ** **** ** * ** * *
* ** ** *** ** **** ** ** * *
    
* * * *** * * * *** * = num1/gcd;
* ** ****** ********* ** * = num2/gcd;
    
** * * ** **** ** ** ** ** * == 1)
* * * * ** *** * *
* ** ** * * * **** * * * *** * * * *** * ** ** * * * ***** ** *
** *** * * ****
    
** * ** **** ** *** * *
* ** ** **** * * * *
* ** **** ****** * * ***** *** * * ** ** ******* * ** * ** *** *** * *
**** * *** *** *** **
    
* ***** **** *** ** * * * *** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
***** * ** * *** * ** ** i;
* ** ***** *** * ** ** j;
*** ** **** * *** newNum1;
* * * * * ** newNum2;
* ** * * * * * *** * * gcd;
** * ******* ****** * rem;
* ***** *** * *** num1, num2;
    
*** * ** * ** * ****** ** * ** ** ***** ** *** * * *
**** * ***** * * ** *
* ** ** * *** *** **
**** * * * ** * * ** * ** * * *
* * * * * * ** * * ****
* *** **** ** * ***** * * != 0)
* *** ** * * ******* *
**** * * * ** **** ****** ** ***** *** * ** *** = j%i;
**** ** **** *** * ** ** ** * * ** ** ** ** **** = i;
** ***** * * * ** * * * *** * ** ** *** * ** ** **** * = rem;
****** **** * ** ***** * *
** * * * * * ***** * *
    
* * ** **** ** = num1/gcd;
* * * * **** * *** * * * = num2/gcd;
    
** * * * *** * ** ***** * * == 1)
***** * * * *** **** **
** * * ** * * ** * * * * * ** ** * * * **** * * * * **
** ** * *** * * ***
    
* * * ****** * ***
* * * * * * ** * *** *
****** ** ** ****** * ** ** * * ** ** * *** * *** * ** * ** * *
* ** * * * ***
    
* ***** * * ** ** * **** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* ***** *** * * ** ** ** * * ** *** ***** * * * ** *
* * *** *** * ***** **** * ** * * **** * * *
    {
* *** *** * *** ** ** *** ** * * ** * ** ***** ***** * **
***** ** *** * ** ** ** **** ** * * * * *
****** * * **** * * * ** * * **
* * * *** * ** ** * * * **
** ** ** ** * * ***** *** *

* ** ** * * ** * ** * *** ***
* * ** ** * * ***** * * ***** * ****** * ***** ** * * * * * * * ***** ** *
*** ***** *** ** ** * * * *** * ** * * **** *** ** * * * * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* ** * * ** * * * ** a,b,GCD;
* * * ** ** * * * *** ** ** * * ** * ** * * * *** *** *
*** * * * **** * * ** *
**** * ** ** * ** ***** *
*** ** ** * **** ***** * * * * * * *** * * * ** **
** * ** * * * *** * * ** * *
******* ** * ** ** ** *** ** *** ** *** * * ** * * **** **** * * **
** ****** * *** ** * **** *** * 0;
}
* ** * *** * *** ** gcd(int a, int b){
** * * **** ** ** * * ** ** * *** ** ** (!b) return (a);
** ** * ** * * **** ********** * ** * * ** * gcd(b, a % b);
* ** **** * * **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** * * *
#include ***** ** **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* **** * * *** gcd, remainder;
* ** * *** * * *** *
**** ** * *** * * * * ** (n != 0)
* * * ** ** * *
** * *** * * * ** * * * * * ***** ** * ** * = m % n;
**** *** * *** ***** **** *** ** ** * ** = n;
** *** * ***** * ******** * ** * *** = remainder;
** ** ** ****** ** * ***
**** * **** * * *
***** ********** = m;
* ** *** * * *** *
*** *** * *** * ** *** ** gcd;
}
int main (int argc, const char * argv[]) {
** *** * ** **** ** ** * number1, number2;
* ** * * * ** * **** ** newNumber1, newNumber2;
* *** ** * * * ***** **
**** **** **** *** ** *
* * * * * * ****** * *** **** * ** * * * **** * ****** *
* ** * ******* * ** * *
* ***** * ** *** *** * * * = number1 / gcd(number1, number2);
* ** ** ** * ** ***** * * = number2 / ***** number2);
*** *** * * * ** * ***
** * ** * * * * *
** * ** ************ * * ( * * *
* ***** * ** **** *** * * ** * ** **** * ***** ** * * ** newNumber1);
** * *** ** ******* * *
* ** *** ** * *** ***
* *** **** * * * **** * ****** ** * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * *** * * * **** * * * * a,b,c,d,e,f;
** * ** ** * ** *** * * * ** * ** * * * * * *
*** ***** * ****** **
** * * * *** ** ** * **
** ** *** * *** *** ***
    {
* ***** ** *** * * * * * * * * ** *** **
******** * * **** *** * * * *** *
*** **** **** **** **** * ***** ** * * * * *
    }
* * ***** ****** ** ***** * ****
    {
******* **** * *** ** * * ****** **** *** * *
*** * ** * * ** ** * **** * ** ** * * ** * ** *** ** *** * ***** * *
* * ** * * * ** * ****** * **** ** **** *
* * ** ***** * * * **** ******* * ** ** ******* ***** * *** *** **
    }
* * * * ***** *** **
    {
*** * *** ** ** ** *** ** ** * * *** * *
*** * * * * * *** * ********** *** * * *** *** * ** ** * * * * * * * * ****
* * * * *** **** **** * * *** * ** * **** **
** **** * * * ** ***** ***** ** * * **** * * * ** *** ***** ** * ***
    }
** *** * * ****** * *** * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.66
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 13.9k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 13.7k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 17.4k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 13.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users