11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
1.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 1.9k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

* * * *** *  ***     ***  i;
  * ** **** **     *  * j;
  * * * **  * ***** **  *  * * newNum1;
 ******  **  * **   ***** newNum2;
**** ** *   * * ** ****   *** *** gcd;
  **** * * * *   *   * * * rem;
 ** ***   ****  *   * ** **  * *** *** num1, num2;

 ****  **   * *** *******     * ******   ** ** **   *  * * ** ** ** 

 * *  * *  * *      *****  ***
 ****  *   ** ** ** *** *  **    

*  *  * * *   * *   **   ***  != 0)
  *** ** * ** ** * ****  * *    *
*   *  *    *  *   ***        * *  *  **    ***  *  *  = j%i;
** * * * ****** * * *   ***  * *   *  *  *  *     = i;
       *  *******   * ***   *        * ******  = rem;
*  * *  *    ***  * * ****** **** 
*  **  ***    ** **     * ** * **   *

* ****  * *** * *  ** *    ** * = num1/gcd;
****   * * ***   ****** *  *  = num2/gcd;

  *   * *  * *  ** ***  ******* *     == 1)
    {
    * ***     * ***          ** **** * ******** ***  **   * **** *  ***   * **   **  **
    }

     ***    *** * * **** * 
    {
***** *** ** *  *   **   *  ** ** ***   ****  **  * ****  *   * * * *      *     **** **  *
* **  *** ****** **  *   ** 

 **  **        * ** * ** * *  ** **** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * ** *       *  *** ***    **** **  ***        ** **** **** * ***  *    *     

**   ****  *  *  * *** **   * **   * * ***
*  ***  **** *  *  *  * *  *   *  ***  *  ***  * *  ***  **    *  *   * **  * *

    else{
*  ***  **  *  *  ** * ** *   **** * *  *  
    {
 *        *     *** *** *      *   *  ****** 
* **** * *   * **     ** **  * *** *  ** *       *  *        * ************ *** && deno%i==0)
 ** ** ***  *   *  ****         *** *   *** **  *  **** **** ***   ** *  *** * *
 *   * *   * * ***   *      ****** ** *  *   **  * *  ** ** **   * * * *    * **   *  *  ********* *
   *  *  **  * ** ** ** * **    ***** *        *** *   *****  ****   ** ** ** ***   *  ****  ***    * *       **  * *
 *** *** ** * *  * * * *    *****    ***        ****      **   * **  * *  ***
    }

*   *  *  *  * ** **    * ** **  **** * *
    {
 *    *****  *    * *  *  ****   **** ** *  * 
 *  *  **  **  ** * *    *  *  * ****  ** * ****     * * *   *   *     *   *** * ** *  ***  && deno%i==0)
 ** **********  **   * *** ****  ***  * * **  ****    * ***  *   *  *** **     ***  **** * * * 
 *   *    *  *    ***  ***  **     *  * **  **  *   * * *  *  *    ** **  ***** *    *****   **** 
*  *  **** ** ***** * ****** **     *  ** *   * **  ** * ** *  * *  *** *       **** **   * *  * * 
** *  * **** * *** **** ************   **** ** *****  ** * *    *   *   
    }
*  * **     ***** * * *  **  * **     *******   * **  ***

    }




* *   **    *   **   * ***       *  0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     **  *  **    *   
#include *   **** **  

int gcd(int n, int m)
{
 *  ** ** ** ***** ***  ***** gcd, remainder;

 *  *  *** **  *** * **  * * (n != 0)
* ***** ***   ** *  * **
*         ***    *         * ** * **  **** ** *    * ** = m % n;
   *****  ** *** *** ** *******  **** * * *  ******  *** = n;
****  *  ** * ** **      *** ******* *  ****  **  * = remainder;
 * ** ***  **  **  *  

 * **     * *   **** * ** *    * = m;

*  ****   * **  *   *  *  *     *  * gcd;
}

int main (int argc, const char * argv[]) {

** ***   ***   *   ** *   * *** number1, number2;
 *   ****     *   * ** **  newNumber1, newNumber2;

*  ***  **    ** ** **   *   * *****  *  *   * *   **  ** *****  ** **** * 

  *  *  ********* ** ** ***   *   * = number1 /  * * *    number2);
 * * * * * **** * ** *  *      *  *  = number2 /   ***  * number2);

***** * ** *** * ** *  * * *   *  * *** *   **    *
  ***   ** * **    **** ** *    *  *****   *  *** *   ***   **   ** * 
 * *      *    * *  ***       *
** **  *  *    *  ** * ** **  ** **** *  ** *  *** * **  
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ***     *  **** **    **
* *      *  *** *  *   *

int     n, int m)
{
  ** ****   *    int gcd,   * ** 

* * *    ***     **  (n != 0)
* *** *    ** {
*****       **   ** *** * * * *      * = m % n;
   *  ***     *  * *  * *** * m = n;
****** **** **    ***   *   *   * n = * *  
    *    * *** }

  **   *  *   gcd = m;

* *  *  **  **  *  * gcd;
}

int main (int * ** *** char * * *** {

 *    **   *    * int ****  * * *  
** *****  **** *  int    *  * *****

**  * * *** **    *** ** * *  *       * ** **    *** ** 

*   *   *  *       * **  * = *  /      * *    **  
 * ***  **  **   **   *  = ** *** /  **  ** *     ******

* *     ** ***  if   * ** * ** * *  
  *   *   *  * *   ***   ***** **  * *** **  *  * * 
***** *  * *  * else
**  *  *  *   ** *  ***** ** **** **  ** *       *  **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
***   * **  * *****  ** ** ** * i;
**   *  ** ***  ***** **  **** j;
**  **  * ** *   *   *  * *  newNum1;
*   *  *  ****** *   ***       newNum2;
  ** * **  * *  **   * * **   **   gcd;
  **    *   * **    **  *  ***  rem;
***   ***  * * *   * * ** *  *  num1, num2;
    
**     *  *   * * * **  * * *   **    * ***** * * ****  *** *** ** *  ** * 
   ** * **    ** ***** **    
 **   *  ***** ****  * **   * * 
 **** **  **** * ** **** ***  * 
 * * ****  * ** * * *  * *   *
* * **   **  *****  * ****   *   * != 0)
**  ***  *    *** * ***** 
  **     *     * **  **** *     **   *  *** *      ** = j%i;
* ** ***  *** ********* ****** * ** **** *  **  * = i;
**** * * *  * *   * **  *   *  *  *  ** *** * ** = rem;
**** * *** *  * *   * *   
 *  *  ****** *     ** * 
    
   * *****   ***   ** *  * * *** = num1/gcd;
*****  ***  ** ** * *  *  ** *  * = num2/gcd;
    
*  *   * *   ** *** * ** *  *  == 1)
**** *** **** * ***  ***
    * *     ** **  ***   **** **** *** *   ***   *  * * * *  * * ** *** * ****** 
* *  * *  *  * ***  *  *    *
    
* * *******  *  **** *****
* * * ** ** *     *   ** 
 *  *   ****   * *  ***  * * * *       *      *** ***** *    ****  **   ** ***** ** * * *  *
*** * * *****  * **  **** **   * 
    
 * *** *  **  ** *  ** ******   * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
* * *** *********  *******     *  i;
* ** * **    *  *  ***  * *** j;
*  * ** *****  *   * * ***** newNum1;
  * *** *  ***  *      *  ** *  * newNum2;
  *****  **  **    *  * ** * gcd;
 * ** * *  **    ** *****  * * *   rem;
** ** ** *     *         *  num1, num2;
    
   *****  *** ***  ******* ****** *****  *  *   * ** *  *  ***  **** **
 *** **  ** **  *** ** *  **   * 
 *    * **   *  ****** *** * ***  ** * *
 * *    *  * * ****  **  *** *   *
  *  *** ***   * ****  ** * ****
      *** ** ** *  ********  != 0)
**** ******* * **   ******* *
***   *  * *  ***** * *   * * **** *    *** **  ***  *   = j%i;
 ***** *  **  * *  * * *  * ** *   * * *** * *    *  = i;
**    *  ** * **   ** * ** *******   *  * ** *    ****** *** = rem;
  *  * ***    ** **********  * * 
* * **  ****          * **   * 
    
 *  * ** *** *    *  *   *       * = num1/gcd;
*  ******* **     ** ** * *** = num2/gcd;
    
* ***         * * * * * * *  * ** *  == 1)
*        * ** ****  * *   ******
**   **    * * * **  **  *    *** ** ****  ** *  * **  *      *** ******* **  * * *  *
 * *  *   *** ***  * *    * **
    
*** ** * ******* * *** *
 *  * ********* * ***     *  
**        **** **  *  * * ***  *** **  *    * ****    * **   * * * ***   **   ***** *  
*  ** *  *** ***** ** ***  **
    
*   ** * ** * **** **  * **  *      0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
**  * ***  * * ***** *  * *      * *  * *  * **** **  **
 * * *        **  * ****   ** ** **** * *   ****  **   *   * 
    {
    * * **  ***     * *** ** **   ** ******  **   * * * *** ** **  ******* *
   **** **  * *  *  ** ** ***** *******   ** *   **     * ***
*     * *       * *   *  *  * *   * 
*  ** **  *   **    * * *  ** * *** *** * *
     *  * * *** ** ***   *  * ** **** ****      

**** *****  **    ** * *** * ***  **
 ***  *****  * **      ****  *** *   *  **** ** ***  *  **   **** * * * ****     *** * *  *   * *    * ****  * 
 *   * **    * ****  * *   ***      *  **** ***  **  ***** ****  *****    *  


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
   * ****     ** * ***   * a,b,GCD;
 *  *  ** *  * * *   *     ***  *  *** ***  *   * *          
*** *******   ** *   **  * *  ****  ***
* *  ** **  **     *** * *   *    *
* *** ****** ****         *****      *** **  *** ** *  ***   ** *** ** 
  * *** * ****  ***  ** * *  ** *
 **** *  * * * ***     *  * ** *****  * *** * *      ***   * ***  ******  * * 
 *  *** *  ***** ** ** **  **   ***  0;
}
    **    *   ** ** *  *****   gcd(int a, int b){
 *  *     ***  * * * *  ** **  ** *      * * * **  *** **   (!b) return (a);
 **   * ** **** ***  * ***  *  * * **      ** *      * **  *    **  gcd(b, a % b);
****  **** ****  ****   ** *  ** ***
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include      *  * *  *
#include *****  *  * * *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
**     **  *  * * ** **** gcd, remainder;
 * *** **    * *   * ** * ****
   *   **   ***    **  * *  *  * (n != 0)
 * *  *** ** ***  *     *** 
* *   *  *       *  *  **    * ** * *** ***  *      **  *  ** * = m % n;
   *    **  * * *  *      **   *  ** * * * ******   * ** = n;
 * *   ***   *     *    *   **  ******** * *    *   = remainder;
 ** ** * *    * * ***  * *  
**** ***** * ** *  * *** ***
**** ** ***   *  ** ***   **  = m;
  *       *  *  ** ** ******
 *     *   ********* ***      gcd;
}
int main (int argc, const char * argv[]) {
**      ** *****  *  * **    number1, number2;
   * *      *** **   *  * ** newNumber1, newNumber2;
        ***  *    *   **  * *
*    *** * * * *  *** **
  *** ** **** * *  * * **    *   ****      ***   ** * * ** * * * *   *
  * *    *** *****   * ***
*   ** **  * *   ***      ****** *  = number1 / gcd(number1, number2);
      * *   *  ***  ****      **    = number2 /    ***   number2);
**  *******  *   *** *
  * ** ** ****  ****  ** 
 ** * * *   * ******* *   *  * ( ***  ***
** * ** ***   *****   **  ** * * ***   ** **  **  ***      * **** * ** * newNumber1);
* *      **   *** ** ***   *
*  * ** **   *    **** * * * 
* *   * **  * *    * ***   **** ***    *** *** ** ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** ** * **  ** * **** ** ** *    a,b,c,d,e,f;
*******  *  * ** ** ** **     **   **     ********* ** ***    *** 
***        ***** **  **  * *  
** *       **  * ** ** * **
**   **    ***  * **  ** ** * * *** *
    {
      **    ***** ** *** ** ** *  ** *  * * **  ** ** *
*   ** *** * * *  *** * * *  *********   ***** * ***  *
 *  ** * * **    * *  * * * *  *     ** *** * *  ** ** 
    }
***** *    **  * *  *** *** ** *
    {
**  ** **** * ** **** ** ** *   *  *** ** *  ** *  ***  * * 
    ***      ***   ***     ** * **   ***  **  *  **  * * *  ** *       *
** *  **** ***  * *  * ***  * * * *** ***  **  ** **  
*    **   * **  *   *** *    *** * *  * **   **  * ** ** * ** * ** **  * *
    }
 *  *    *  ** *    *   **  *
    {
 **  * * ****  * ***** *  **    *    ** ** ****  *     
* * ***    ******* *  **  *    ** *  * *   *  * **** *  *   * ***  *  *    *   ***
  ***** **  ***** * *  *  ** *  *  *       ***** *   **
** *  * *  ***  ****** **  ****** **  **  **  *   * *****   ***** * *  ** *** **  
    }
*  ***** **    * *  **    ** * * *  0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.194.127
©2016-2024

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 2.4k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 2k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 2.5k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 1.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users