2 like 0 dislike
16.1k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 16.1k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* ** ***** * *** * ***** i;
**** ** * ** *** * * j;
*** * * * ** * ** ** newNum1;
* *** * *** * ** ** ** newNum2;
** *** * * * * * ** ***** gcd;
** * * * * * * *** * * ** rem;
* ** * ** ** ***** * ***** num1, num2;

** *** ****** ***** * * * * * ****** * * ** * * ***

** ** ****** *** **** ** *********
** * ** * *** * * * **

*** * * **** ** * != 0)
* * * ** * ** *
* * * * * *** *** ******* * * ** ** * * * ** * ***** = j%i;
****** ** ** ******* *** **** *** * * *** *** = i;
*** * ** * * * * **** * * * *** * * * = rem;
** * ** * ** **** *
** *** *** *** * *** **

*** ** *** * ** ** ** = num1/gcd;
* * **** * * * * * ** * = num2/gcd;

***** ** * ***** ** * * == 1)
    {
* * ** * * * ** ** ****** * * ** * ******* * * * ** * * * ***
    }

* ***** * *** * *
    {
* ** * * ** * ***** *** * * * ****** * * ****** ** * * * * ****
*** * * *** ** ** **

* * * * * ******* * **** * * ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* ** * * ** * ** ** * *** ** * **** * ** * * * *****

* *** ***** * * *** ***
*** * **** * *** **** *** * * * *** ** *** ** * * ** * * ****

    else{
* * ** * * * ** ** ** ******* * *
    {
* *** * ** * **** ** ** * * ***
**** * * * * ** * * * * *** ** * *** * * * * ***** ***** **** ** ** && deno%i==0)
* *** ** * ** ** ***** * * * * ****** * * * * * ** ******
**** * **** * **** ** * *** * ** * * **** ** * ** * * * ***** ****** * * ****
* ** * * ** *** * **** *********** * * * * ** ** ** **** ****** *** * * ** **
** * * *** *** ********* * * ** * * * * * ** * ****** ** * * * ** *
    }

** *** * *** ** * ** *** * * * *
    {
*** * * * * * ** ** ****** ** ** ** *
**** ***** * * * *** ** *** *** ** ** * * * * ** ** * ** ** * * && deno%i==0)
**** ** **** * * * *** ** *** ****** * *** * * * * * * ***
*** *** *** * * ** **** * **** * *** * * ** ***** *** ** * * * * * * * **** ** ***
* * ** ** ** * ** ****** * ***** * **** * ************ **** * * * ** * * * ** * ** ** *
** * *** * *** *** ** ** * * * ** * ** * * * * ******
    }
** *** * * **** * * * * * * ** ** * * *** * **

    }




* ****** ** *** * * * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * **** * *
#include *** * *****

int gcd(int n, int m)
{
*** * *** **** * ** *** **** * gcd, remainder;

** * ****** * * * * ****** * ** (n != 0)
** ** * ** **** ** *
** * ** * ** ** *** ** * *** * *** **** = m % n;
* *** ** ** * * ** * ** **** * ** * * * * = n;
* * ** ** * *** * ****** * * * ** ****** * = remainder;
** * *** * *** * * * *

* ** * * *** **** * = m;

** * * ** *** *** gcd;
}

int main (int argc, const char * argv[]) {

** *** ** *** ** * ** number1, number2;
** ** ** *** newNumber1, newNumber2;

* * * * * * ***** ** ** ** *** * * ** * * *** * ** * * ****

* ** ******* ** *** = number1 / * *** number2);
** * ** * * ** * * ** = number2 / * ** ** number2);

* * *** *** * *** *** ** *** ****** * *****
* * * ** ** * ** * * * * *** *** ** ** * ** ** **
**** ** * * * ****
***** *** * * * **** * **** * * **
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * * ** * ****
* * *** * * ****

int ** * n, int m)
{
***** * ** ** int gcd, *

* ** * * * ** * (n != 0)
****** ***** {
* * * *** * *** * * * * = m % n;
* * * * * ** *** * ** m = n;
* ** ** ** *** ** * * ** n = * **
** ** ** *** }

**** * * gcd = m;

***** ** * *** gcd;
}

int main (int *** ** ** char * ** * {

** ** * int **
** **** * * int * * * *** **

*** * ***** ** * * ** *** * *** ** *** * * *** ** *

* *** ** * * * * * = *** * / **** * * *
* *** * ** * ** * = * / ** * * ** * *

* * ** ** if ** * ** ** ** ****
** ** * ** * **** * ** ** * ** ****
******** ** ** else
** * * ** * *** ** * ** * *** * * * * **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
**** **** **** * * ****** * i;
*** * ** ***** * **** ** j;
* * * *** ** * * * * *** newNum1;
**** * * ** **** * newNum2;
** ** *** ** ** * gcd;
**** ** ** * rem;
**** *** *** ** * num1, num2;
    
** *** ** *** ****** * * * * * * * **** ** * ** **
* ** ** ***
** ** ** * *** * * * ***
***** *** * * *** **** *** ***
**** * **** * * *** *
** * ** **** * ***** * != 0)
* *** * * * *** ****
*** * * * ** * *** **** * * * * *** * ** = j%i;
*** ** ** * *** * *** * * * * ** * ***** * = i;
* * ******* *** * ** * *** ** ** * * * *** = rem;
*** * ** ** **** **
** * * * * ****
    
*** * ** * ** * ****** * = num1/gcd;
* * ** * * * *** ** * = num2/gcd;
    
* ** * * * * * * == 1)
***** * * *** * * *
* * * ** * * * * * * * * ** * **** ** * * ** * ** ** * *****
* ** ****** *** * * *
    
** **** * ** * ** *
* * * **** * * ** *
* * * ** * *** * *** ** * *** * **** * *** ** * * ** ******
* * * **** * *** ** * *
    
* ** ** * ** ** ** ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * * ** * * ** i;
*** ** * ** ** ***** * j;
* ********* * **** ** newNum1;
* * * ** ** * * ** * newNum2;
*** **** ** ** * *** * * * gcd;
* ** ** * ** * ** ** * * * rem;
** * ** * * ** * num1, num2;
    
* ** * * *** * * *** * * ** ** ** * * * * * ** *** **** *
* ** * * **** **** * * ** *
** ** * ** * * * * * * * *
******** ** * ******* * **********
** ** * ** **** *
** ** *** * * ** * ** *** *** != 0)
* ** ** ** * **** ** * ***
** ** *** ***** * * ** * * **** * ** * = j%i;
* **** * ***** *** * ** * * ** * ** * = i;
**** *** * ** ** *** ** ** * **** * = rem;
* * *** * ** **** *** * *
* * *** ****** * * *** *
    
* * *** **** * ** * * = num1/gcd;
* ** ** *** ***** ** = num2/gcd;
    
*** * *** * ** * ** * ** * == 1)
** *** ***** ** **
* * *** * **** *** * ** ** ** ** **** * * *** **** * *
* * ** *** * ** * *
    
*** * * * * ** ** ***** **
** * * ** * * * *****
* ** **** ** ** * ** * * * ***** * ** ** * ** * **** * * * ** * * ******
** * ** ** * *
    
** ** * * * * * * *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
**** * * *** * ** * ** * *** * ** ** * ** * **
* * *** *** *** ** *** *** ** * * * ** ******
    {
** *** * ** ** * * * * * ** * ** * * *** *** ***
***** * **** * * * * *** *** ** *** * **
** ** * * ** ** *** ******* *** * **
**** ** * * * **** * ** ** * *
* * * ** * ** *** * * ** ** *

** ** * **** ** *** * *
** ** * * * ** * *** * * *** * **** ** *** *** * *** * * ** ** *** ** **** ** *
* * * **** *** * ** * ** ** * ** * * **** * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* **** ** * * **** * a,b,GCD;
***** * * * *** * *** ** ****** ** ** * ** **
****** * * * ********** * **
* * * * * * ** * * ****
* ** ***** ** ** * * **** ** * ***** ** ** * ** * *** **** * *
* * * * * * ** * * *** * *
***** * * * ** ** * * *** * ** * **** ******* * * *
* * ***** * * *** * * * * 0;
}
** ** * * ** *** ***** * gcd(int a, int b){
*** * **** ** * * ***** ***** ** *** * * ** (!b) return (a);
** * **** ***** * * * * * ** ** * ** ** * ** gcd(b, a % b);
** **** ** * * * *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** ** **
#include * * * * ** *** **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* * ** * * * * **** gcd, remainder;
** *** **** ***** *
** *** * * * **** * *** * (n != 0)
* * ** ** *** ***
* *** * * * * * *** ***** * ** * * * = m % n;
** ** * ** * *** * * * ** ** ***** ** *** = n;
* ** * * ** ****** **** ** ** * * ** * = remainder;
***** * ** * *
**** * * ** * * ** *
* ** ***** ** * ** * = m;
* * ** ** * * * ** ***
* * ** * ** * * ** ** gcd;
}
int main (int argc, const char * argv[]) {
* ** * * * * * **** number1, number2;
***** * ***** newNumber1, newNumber2;
* * * * *** ** * *
* *** * *** * * **
* ** * * * ****** * ** *** *** * * *** * * * **
* ** * * ** * ** * *
* ** * * * * ** *** = number1 / gcd(number1, number2);
** * *** * **** * * * = number2 / * ** * number2);
*** * * * ***** ***** *
* * * ** *** * * ***
* ** *** ** * **** * * ( ** * *
** * *** * * **** *** * **** * * * * ** * **** * * ** * *** *** * newNumber1);
* * * ** *** *** **
*** ** ** * * ** * ***
* ***** * **** * **** * * ****** * * *** ** ***** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * * * * * * * *** a,b,c,d,e,f;
** * * * * * ** * * * **** * **** ** **** *** *
** **** * * * * ** * **
* * **** ** ** * * * *
** * *** * * ***** ** *
    {
** * * ** *** ** * *** * * * * ** * ** * * *** * * * *
** *** * * * * ** *** *** ** ** *** ** ***** * **
* *** * ** ** * * * **** ** * * ******** **
    }
* **** ** * * * **** * *
    {
***** *** * * * ***** ** ** *** ** *** ** * ** **
******* *** * * * *** * *** * ** *** ** ******* * ** * * **** ***
** ** * * ** * * * * * ** *
* *** * *** ** ***** ** * *********** *** * * ** * * ** ** ** *
    }
* *** *** ** ** **
    {
* ** * * * * *** * * * * * ***** * *** * **** * ***
****** ** ***** ** * *** * * * * * * ** * * * ** * ***
* ** * ******** **** ** * *** ** * *** * *
* ** * *** ** * *** ** * * * * * * * * *** **** ** ** *****
    }
** * **** * * * * ** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.165
©2016-2026

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 16k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 15.9k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 20.8k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 15.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users