11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
18.5k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 18.5k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

** **    ***** * **  **** **  ** i;
**   * ****  *  **** * *  j;
*   **** *  ***  **  * ** **  newNum1;
****  *   ** * * *    *    *** newNum2;
   ********* *   ******** * *  *  gcd;
  ****   * *** ****   **  **** rem;
* *  * **  *    *  ** *    ***  num1, num2;

**  *** ***   *  **  * * **   ***   ** ***    * ****** **  ***   **

****   **   * **** *****  ** 
  ***    *   **** ***  *   **

 ****** *  **** *   ****   *    * != 0)
**    * *  * * ***   **   **  
*  *  *  **  ** *** *** ** * ****** ******   * *  * *  *  = j%i;
* *  **  ** ***** * **** ****** * *  ***   * * * **  *   = i;
**  *   *  ** *  ****** ***   * *   ** * * *  ** *  = rem;
  ** **        * * *     *****
  *   * ***** *    * **       ****** 

  * *** ***  *  *  ***** *    = num1/gcd;
 ***   * *** *   *  ***    = num2/gcd;

*  * ***** ** **   * * **  *** **  * == 1)
    {
 * ************ *   **    *  * **     ** *** ****** * * ***** *  ***  ** *   * **
    }

  *** *    **  ** *     
    {
 *  *   * * ***  *****   ***** ** * *   **    **  *  ** ** **  * *** ***  * * *
*** **  *  ***  *  * *   ***  * *

     * ** *     *   * ***  *  *  ** *** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
*** * * ***  * * ***** *   *** **  *    ****** **  * * * *  * *    *  *

* *    **   *** * *  *        ***     
 ***  **  **  **** * * ***   ********  * * **   ***     ***********    *** ** * ** 

    else{
*    **  ** *  ***   ** *** **   **  **     * 
    {
***   ******    *       **** **********  ** *
*  * ****** *    **    *  ****  *    ***   *  * ****  ** ** * *  * * ** **       ** ** && deno%i==0)
 *   * * * * ** **** * *  **  **** **  **  **   ** ***   *    *  * * *   * ***  ***
**  *  ** * *******  * *** * *  * ***  *** * ** * **    *     *** *** *  *   * ******  ** *  ***  *
***      *    ** *  ****       ** ** ** *  ** ** * ** *    *  ***    * * **    * ***     *  ** **    **    
 ******* *** *  *  ** **  ***  * * **   *     *    * *    * ***   ** ** * * **   
    }

   *****   * **    *  *        ** * ***
    {
 *      * * * * * ** *  * *   *     *  * * 
*  ** * *  ** **  *  **   * * *** ****      *** * *  *** *** ***    * * *** *     **  * ** **** && deno%i==0)
 *** ** *  * ** ****   * * * ****** * *     **  * *  ******   ******* *** **    * 
 *    ** *** * * **  ***** **       ******** *  ***        *  *  ***   * *    *            * *  *  *  ** * *
 ******* *  ** ******  ***   **   ** *  ***** **    * ********    *       **   *** * **    ** *    *** ***  
 * *     **  * ***  *  ***   *  *  * *   *    *** * **    ** ***     * ***  * * 
    }
*    *  *** * * **   ** **     ******* **   ** *   *   ** ** 

    }




 *  ************ *** * * *     * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   * *   * ****
#include **** * * * **

int gcd(int n, int m)
{
     * ***   ***  *** ***  * ** gcd, remainder;

**** *      ** *  * **  *  **  ****  (n != 0)
* ***  * ** * *  *    ** 
     ** ** *  * ** **   * *** **  **    **  * *   * * *****  ** = m % n;
      * * * ***   **  * * * **** **    * **    * ***  = n;
    ** **********  *  *** * *****  **   *** * * *** = remainder;
* *  * ** ** *** * * * * *** ***  

 *** *    *** *   *** * ***  = m;

* ***  *   ********   gcd;
}

int main (int argc, const char * argv[]) {

   ** *   *   *    *****     number1, number2;
*** ****   ****   **  *  *  *   newNumber1, newNumber2;

     ****    *  * ** * *  ** *  * *  * **      * *    ** * **   ** **   * * 

*  * **** ** *** ** * **    * = number1 / * **  *  number2);
***  **  *  **  *  ** ****** *    = number2 / **       number2);

  * * **  ***  * ***  ** * * *    *   * *    **  ****  
          **    *    *** * ** *   *   *** **** *   * *  *  *******
   ***  *       **    * *  ** 
*  ****  * *  ***   * **  **  ** *  ***  *** *** * ** ** * 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  *  **** * *    *  
 *  * *   **  *  *  * **

int ****** n, int m)
{
 * *            * int gcd, * **

* ****  *******  ***  (n != 0)
 **   *  ** * * {
* ****   *  * * * *  * ***** * * *    = m % n;
* ****      **  *     *  ** ** m = n;
 ** *   * * ** ** *  *  ** ** ** n = * * **
** ***  * ** ** }

* *    *        gcd = m;

*  ***** *** * * gcd;
}

int main (int  ** ** char * * * * {

*   **** ** int *  *  **  
* *  *  ** **   int *  ***  * *  ** **

*     ** * * * **  *****  **   ** * * ** *   * *  *   **

 *     * * ** * *    ****  =   ** / *  * * * *  * **  * 
 *     ** ** * *  *  *  *   * =   *  / ** **     * * **

****  **    * * if    *   ********* 
 *** * **   ***   * *** *** * * *  * *  *   * ** * * *  **  *
**** *  *       * else
   **  *   ***  ***      *  **** ********  ***    * ***  
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
* *    *  ** ** ****** **    i;
 * **   * ** ***   *    ****** * j;
** * * * **** ** *** *  *  **  ** newNum1;
** ********      ****   ****  *  * ***  * newNum2;
  *** *      **  * **  **   gcd;
     *** *    *   * **  ****   rem;
   ***   ******* *  * **     * num1, num2;
    
*  * *** *  *** * **  **   * *** * *** * * **** *  ****   **  *  *
*****     **  * * **  * *
 * **   *  * **  **   ** ** *** *
*** *   **  ** **  **    * * **
 ****** * **  *   * *  **** 
 *       * **   * * ***  **  *** *    != 0)
 **  *  ***     *  ** ** *  * *
****  ** ** **  ** **  **  *   *** *   *   * *  **** **** ** = j%i;
  *****  *** * * * ****  **   **** *    ***  *****     = i;
  ** **  * * * * *  *    ********* * **     *  ***  * = rem;
* **    **** *  ***    * 
 *      *  **  ** * *      **
    
*  * *   * *  * * *  *  *  ** = num1/gcd;
****** *  * **** *   ******  *    = num2/gcd;
    
** *   **     **** *         * == 1)
*  ** *** ****  *  ** *  **
     * * **** *****  * *     **    * * ***  ** * ***  **     * ** *  *   ** *** **
     * *     ** ** ** ** *  *
    
 *    ***    **** *  * *  * *  
 *** ***  ** *  *  *  * * *
****  *** * * * * ** * *  **  * ** * ** ** *    ***   *****    *   *** *     *   * ******
**       *** * ***** * *  
    
* * *** *** *  * * *** **  *   *  0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
****  ****** *  *  ** * ** * *  i;
* ** ***** * *   *  *    *  j;
*    *    ***   **     *  *  **  * newNum1;
*  * *  * ** ** *  *   ****  newNum2;
*** * ** *** ** * *** * *   *  gcd;
****  * ****  *  **  *** ** * rem;
 *   *  * *  * ** ** ** ** * * num1, num2;
    
** * * *  ** **  ****  **  * * *    *  *  *      *****    * * *   ***
*   **      *  *****  *  * *
* ******  **   * *****     * 
* ** **     *** *** * ****  **** *
***** * ***  **  * *** 
   ***  *** *   ** * * *   ****    ** != 0)
*  * **   *** ****   * **  
 * ***  *****  * ****** **  ** * * **  *** ***     = j%i;
 ** ** *** *  *   ***   * *  *  *** * ***    ********* ** = i;
**      **** * ***  ****   *     *  ****   *  **  = rem;
  * * *     ** * **   **** *   * 
   * * *** ******  **  ****** 
    
**  **   **    **   ***  *  ** * = num1/gcd;
*      * ** * *  ** * *     ** ** **  = num2/gcd;
    
 *  ******* *****  ** * **  * == 1)
**  **  **** ** * * *  **  * 
*** * **  * * **** *   ****   *****  * ***        *   *    *  * * ** * *  ** ******
   ***     ** * * ** *    *
    
* *****  ** * *   ***  * **  *  * 
*    ***  *  * **** *   *  
***    *** *     **** ****   ****   *   * *  *   *** * ******* ** ** ***** ** ***  * ***  ** *   
**  ***   * *   *  * ***** *** *
    
 *  ** *  ******* * *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
*** * ** ** ** * *  * * ***    *  * *****   **** **  *  **   **  ***  
*   *  **  *  * ** * *  * ***   * * *           ** 
    {
** **    **** **  * **  **     ***   * ** *   *  * * *  * * ** **** *  * **
   ****  **  **** *******   *   *****     *  ***    * **     **
      **    * *    * *   **** * ****** * *  * 
*****   *** *** *   *      ***** * 
*  *      *  **     *    ** **    ** ******

 **   **  *  ** * *** ** ****  ***
* **  * ** ** *  ***  *  * *****    ** **  * * ** ***  *  * ****  * *******  **      ** * ** ***
* *  **   *** ** * **  ***** * * *     **   * *** **   * ****    *   *** * 


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
  * *  * *   *  ** *** *        a,b,GCD;
*       *****   *     *  *** *     * *** * ***** ** *  *   **   ***   
** * *   *   * *  **  *  *** *** 
 *     *      * *  ** *  ***  *
 *  * * ** *       * *** * * * **    * * ***      * * * *   **  *   **** *
*  *   * **      *  ****   *  
*** ** ****  * **** *  *  *  *     ** **** ** ** *** * ***  * * ** **  * **   *** 
* * ** ***  * ** **** *  **  **  *** 0;
}
*  * * * *  ** *****  *   ** ***** gcd(int a, int b){
 *****  **  ****  * *   *  *****  ***  * *    (!b) return (a);
   *  ** * *  *  ***     *  * **   ***    * **   *** * *  gcd(b, a % b);
***  **  * *  * ****   *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *** **  *  **
#include  * *** * ***   *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
***  * * *    **   ** ****** ** gcd, remainder;
* **  ****  **** * *  **  *
  *    *   * * *  ** *  *** (n != 0)
****   * ** *   ***  **     *  
*  * **** **** ***** ** * **   ** ****  *   **** *   **   * = m % n;
* * * **  *   **** **** **  *  *   **** *     * ***      = n;
*** ** * *  *********    **   ** ***   **   *        = remainder;
****      *  ***   **
* *****  * * ***     *
** ** *** *     * **  **   * = m;
*       *  ***    *  **  * ** 
  *  *    *****  ** *  **   *    * gcd;
}
int main (int argc, const char * argv[]) {
**  ** *  *  *** **  *   ******  number1, number2;
 ** * *   *****  *  * * *** *** newNumber1, newNumber2;
**  *  *****  ** *  ** **  **
*  ***  **    * **     *  
******  ** ** *  *** * **     * * ** **** *   *  * ***  * ****   *** *     **  *
 **    *** **** *  **  * 
* *    * * **     *     *  *  = number1 / gcd(number1, number2);
* **       ** * * *  ** *  ** **  = number2 / * ** * number2);
*      **  *     ***  **  **  
* ****    *  *    * ****  ****
*  **   * *** * * **** **   (  *   ***   *
 * * **  *  *    **  *   ** ***  **  * ****** *  *   *      *  newNumber1);
 *  **   **   * *  * ** *  * 
 * **** * ****  * * ***   ***
 *    * * ** ** ***    *   * *    *****  * **** * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
****    *  *  * *   *** *  *   a,b,c,d,e,f;
****  **** * ** **  ** *  * * *   *  ** ****  *  * **** *  **  **
  **   *   *   * *   *    *  * 
**** **** * *    *** * *    *  
 ** * **   ** * * * * ** *  **     * *
    {
  *** **      *     **  *****     * * **  *** **      *  
  **  *   *** *    **  *  ** ***   *  ** * ** *  ** *  
*    ***  **** *   ** **   *  * * *  ** * ***       **
    }
 **  ** ** *   ** **    * ***** 
    {
  *** *     *** * *    **  * * * * *** **      *    **  ****   
**   *    * *      * * * ***  * **    **   **  * * ***  * * ******* ** **** ** *  
 * * *    *  **** *     * ** * ****** ***   **  **  *
** *       * * **  *  *  *  *   *** *****  *  *** *  **  *  ** ** **   *   **  ** *  **  
    }
   **   **    ****   *  **** * * 
    {
*  *   * ***  *  *  *  * ** *** **   ** ***** ****  *  ** *
  * ***   ** *  * * ***** ****     ******* *   *    *** ** ** *   *    *
 * ******* **  **    * **    * * * *  ***  *   ***  
 **  * **     * *  *  *         ** ***** * *    * **  ****  * * ******      
    }
***      **       **  ** ** **** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 18.4k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 18.4k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 24.5k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 18.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users