11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
17.4k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 17.4k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

*  ***** ****   **   **** * i;
*  **** * ** * * *  *     **  * j;
*** ** *  *** *** **  *  * ** newNum1;
* ** *  *** ** *    * *    *  * * newNum2;
** **   * *   *  *  *  * *    gcd;
  * **   *  **   * **  ** * * rem;
   *   * *  *** **** * *  *    num1, num2;

 * *   * ** * * ****     **** **  ********** *  *** ******  *      * *  *

* *** ** **  *** **   **** *     
 **   ***    *     ** * *** *  

 ** * **  * ****   *   **  != 0)
  ** * * * *** ** * *** ***
***  *  * * *  *  * *** **    *   **  **** ** = j%i;
 * ****** *  *    ***  **   *  **  * **  ******* *  * = i;
*  *  ** **  ** **  ***** **  * **  *     ** * ** **   = rem;
** **  ***   * ***** * ***  * 
* * ***  *   * *  *  *  ** *****

*   * *** *  * * * * ** * ** ** = num1/gcd;
* *******    ***   * *    = num2/gcd;

   **   * ** * ****  *****  ****   == 1)
    {
 * *  ** *  ** **     **  * *     *   *** **   *****  *** *  *  ***  **   ***
    }

       *    *  *   **  **   ** *
    {
 *** * * *****        * *   ** *     *** ***** * *  **    ***   **   ** **    
***     * *  **   ***   **** **

  * *****   *  **  ****   ** *** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
*** *  **    ** *   *    * ******** ***   *  *   **   ***  * ****

* ** ** *  *  *  *   **  *** *   * **
  * *      * ** *  *   ***   * *****    ** **      ***** *  * * ** *   * *

    else{
   *   *  ** ** * * ** * *** * *  * **
    {
***********     *     *  * ** * * * *  **** * *
* **  * *** **    ***  * * *  ***  **  * ***** *** ** ***       * * ** *  *   * *    ** && deno%i==0)
**     *** *   *** *   ** * * *   **         *  * **** *** *  *** **   *** *  **   
** *  ****   *    * **  ***   * * *  ** **   ** **  *** ** **** ***  *****  *****  * *** * * *  ***    
*    *  ***   *   ** **  *****   * *  ** * * ***  * * *   *** * **   * *  *   ** ** *       *  ** *   **
*  ****    * ******   *   ****   *** ** * **** **   ** *     * **      *   * 
    }

  *  * * ** * ***    * *  ***** ****  ** * 
    {
   * ***  ****  * ***** **  ***    *  ****
 * * *   **   ***   **  **  * *    *** ** * * ***  * ****    * *** ** * *     ** *** *** ** ** * && deno%i==0)
  * ** * *    ******* * *  * * * *  *  ***  **  * * *             ******** 
 ** * * *  ****   ***   *** * * * ** **   **  * *  *  **  *  ** *  ***    *     * * *      *  **  ******  *  *
  ** **   *   ** *      **  *     ***** ** *    **    **** ***   ******   * **** ** *  ** *  * * **     *
 *   ** * **** **    * ****   ** *** *    *** * **    *    ** ***** * ** ****   
    }
 *  ***  *   * *  *** ***      ** * ** *  ****** **  

    }




* *****    *   ** *** * *** ***** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  *   ** ** *** 
#include *****  ****  **

int gcd(int n, int m)
{
* ** ***   *****  *  ** *  *   gcd, remainder;

 * * *  * * **      ** ** *  (n != 0)
  * * *  *** *   *   * * * *
  *  *  **  *** *  **  * ****   * **    ***  **   *  ** = m % n;
*  ****** ** *  ***** *  **  **   * *  ***  **     * * *  * = n;
  * *  **  *****  ** * ** ******   **  *****  *****  = remainder;
   ** ***  *      *  *     *  

****  ****   * *****   *  ** *  = m;

    * *** **  ** **    * ** * **  ***  gcd;
}

int main (int argc, const char * argv[]) {

* **** **  **   **  * * * * *** number1, number2;
 * * *    * **   ****  * * * * ** newNumber1, newNumber2;

 ***** * ****  *     **      *    ** ** **  *  **** **  *  * ** * **     

 ** **  * * ** * **   *  *   **     = number1 / ** * * **  number2);
 * ******   ***    *  ** * **   = number2 / *   * * * number2);

 **    **** *  **   *** *   *  *   *****  * **    **   *
 **      *** ** *       * *** * **   *   **** * * **** *  *  *     *
*** *  **    *  ** *  ** **   
** *  **   ******    *** **** **  *** * *     *   **
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** * *    ** * * *  **  *
****  *  **    * *** ** *  *

int ** n, int m)
{
* *     **** * int gcd,  ** 

  * * * ***    *  **  (n != 0)
* **** * *** * {
   * * * *  ** * * * ***  *    *  = m % n;
    ****  * * * *  * * * *  **** * m = n;
 **** *   *** **        * n =  ** ***
   ******     * *  * }

   * * ***  ** gcd = m;

 **        ** * gcd;
}

int main (int   *    * char *  **   {

     * *   **  ** int   **   ***
 *     **     * int ****  ** *** 

* ***    * **  *    * * *  ** *  ***  ***   * *** *   ** * ******* * 

     *  * *    * **  =  ** / ** **** *    
         ***   *  *  * =       /    * *      ***

*  ** * * ** * if ** *     *  **   **  *
* * *  **  * **** *** *  ** ** *     * ** ***   * ****
* ** ** * *  * else
*** **** *    * ** *****   * **   * *  **  *** *  * * ***
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
***     **   ** *  ***  *    i;
  * *   *    * ** *****     j;
*      **  ** ** **** ***    *** newNum1;
*     ***  * *******  *  ***    ***  newNum2;
* ** *   **  **** *  *** *     gcd;
* ***  *** *   * ****** *** **** rem;
***   *** ***       ** ***   num1, num2;
    
 *   *   ****** * *  ***** * * * * *   **** ****   * ****   * * *     
  ** ** * ****  * ** *  *  **
 * * *   ** **  ***  * *  * **  *
****** *** * **   *     * ** *     
*******   **  *  ***  * ** 
 ** ***  * * *******       *** **** ** != 0)
*  * ****      **     **  * ** *
***** * *  ***  ** *  *  * ****   * *  * **  *** ****  = j%i;
  **  *  ***   ***** *** *** ******  *     * * **** = i;
 ***  *   **** ** *   * **     **     ***  ** ** *   = rem;
 ** ***  ******* ****    *
* ***  * **  * *** *****      * ***
    
  *** **  ** *** **  *  * *  ** = num1/gcd;
** *  * * *   ***** * *  **     *** * = num2/gcd;
    
* **       * **** *** * * ** *  *  * == 1)
  **  *     *   ***    *  
 *** **** ** ***  **  *   *  * *  **  * * * * *  *  *  ****  * *  *  *  *   ***
   * **     ***  *  ****    *
    
 **   *     *** *** ** * ** *
**   ** ***   ** *  * *** *** *
* ** ** *** **** *   * **    * * **** *  *         *       ******** ** * ** ***       *  
**** *  * * *   * *  *  **  * *
    
     * *     ******** ***   *  0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 ******   *   * *** *******  **   i;
********* *  *** * * ***  j;
   *  * ***   * *  **   *  *  *  newNum1;
**    ***  *  *   ** **** *    newNum2;
* *    **    * *  *  *  *    ****  gcd;
  **    ** *      *** *  * rem;
**  *  **      *  ****    num1, num2;
    
* *** ** * ** **   *     * *** *******   * * **  ** **  ** *** 
 *  *  ****    *         *** 
* *   * ***   * * ** ** *  
**    * *** **  ** *   *  **   
  * ** ***    *  *  * **
*   ***    *  **       **   *   * *  * *  != 0)
 *** * ** ** *      ** ***  
**     *   ** * ** *       *  *      * * * *  **     *  = j%i;
**** ***** * **** ** ****      *  * **  *    * **** *  * = i;
      * * ** *        ** *  *   * ***  ** **  ** *  **   ***    = rem;
   **    *****   ***  
 **  ****    * **  ** ***    
    
 ** *    **   *** *** *  * *  = num1/gcd;
*** *** ***** **    * ** ** *   * = num2/gcd;
    
********* * *** *     **    *        == 1)
  *  ***** ** **  *** *     ***
***  *  ****    ***  ***  *** *  * **** ****  * * *  **  **  * ****   *** * *** **
*** * *** **  ** **  ***** *  
    
   ** *** ** *     **** ***  ** ** *
***   * *  * *   *   ** * * 
    *  ** ***  * ** *** * ** **  *  * * **  *  **  * * * **  ****  * **** ******* *   
******* *     * *    * ** 
    
* * *** *  * * * **** **  * * *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
  ** ***    ***** *   *   * **** * *    * *  **  *********  *  ***   
     **   * * ***     **** *** * ***  **   **   * **  * **** *  * *
    {
 *  * *   **** ******* ** * **  ** **  *  ****  **  ***  ****  
*** * ** **   **  * ***   *** ***  **  ****  *   *** * ******   
   *  *  * *    * * *** **    ** * *** *** 
*     * *** * **** ** ***    * * **** ** ** ***    *
***     * *  * *      * *    ***  ** **** *   **  

** **  **   * ** **  * * ** *   
*  * *     ****** *********** * * ***  **** ** *   ****      **    *   ****  **   *  *** * *** ****
*** *   **** **  ** *  * * * * *    * ***  *    * ** **   *      **  **  * **   *****


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*  ***  *  *  * ***    **** * ** a,b,GCD;
*   *  * **   **  *     ** * *   **** * ******  * ***  *  ** *   *
  * ***  ** *      *** **  * ** *
  * * ** ****  *  * ***  ** 
** * *** *  *  * *  *    *    * *  * **     ***** * ** *  *  *  * 
*  *    * *  ** ****  ** *    **** **
*   *    ** *****  ****      **    *     ***** * **  ** *   * * ***  *  ** 
    *   ***  * *  *  *   ****  0;
}
  **  *  *     **  **   * ** gcd(int a, int b){
 **** *  * * * *   *   ***  *   ***  * ****  *   * * *     *  (!b) return (a);
  *** *    ** *****  *   ***** ** * ** ***    *     *  gcd(b, a % b);
** ** ** *  **  * *  *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *  **** **    *
#include *  * * **   **   

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
*   * *    *  ** **     ****   gcd, remainder;
*   ** ***  * **  *  *
 *  * * * *** **    * *    *  *  (n != 0)
* *** *  *  *     * *        
*  * **   * ***  *   ***** ***** **  ***** ** ****** * ***  = m % n;
*  * *  * *    *  *    * *  * **    ** * *   *   * ** *  = n;
  **   **** * *     * **   *  *  **  *    * * *  *****  = remainder;
***  ** ** * * * *  ** ***
**  * ** **      ***** 
*   ** ** *****  * *    *   ** ****    = m;
 * **   **    ** *   * *
  **  **   ** * * *** ** gcd;
}
int main (int argc, const char * argv[]) {
    *  *    *  * * ***    *  ** number1, number2;
  ** **  ** *    * * **** *     newNumber1, newNumber2;
  **  * * ***    **  *  * **  
 ****  *** ** ***   * * *
 ***  * *   *  *  *   *  ** ***  * * ***  **  * *     *    *    *          
*  *   *    *   ***     *  
*    *** *  * * ** **** * * ** ** * = number1 / gcd(number1, number2);
 *  * **     * *  ** **  * ** * = number2 /   *     number2);
* *  * ** ***   **  *******
 * ** **  * *  *  *    *  
 * *  * **    **  *   *  **  *  (    ** * 
        *** **  *   **  *  *       * *******    * ****          ***   newNumber1);
   * *  *   * ***  **  *  ***  
** *  *** * *  ** * ***  * **
  *  *  **        * ** * *  * * ** ** ** ***  **   newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
  *    * * *   * **** ** * a,b,c,d,e,f;
 ****** * * * ****** * **  * **  *    *  *     *   *  **  *** * 
 ** ***  *   *  * *   ** * 
 * *       **  *** * **    *
*     **  *** ***** *   ***   * 
    {
* *      *  ***  **  *  *  ** * *  ***   ** *   * *   * 
*** * * ** *  *   **       ***** *     * * ** *  **      *  
** **** **   *   ** ** * **   *****  *  ** *   **  **     *
    }
 **   *** * ** **    ** *  ***** * 
    {
  *  **  ** *   ** * ** **  ** ** ***     ****** *****   ** * *
 **   *  *   ****** *   *   * **  *  **    *  ***   * ******     * * * * **  *
 *   *   ** **  *  ** * ** **** **    * * **     *** * *
** *  * ****** *   ****  * ** * *  *** *     ******* **** **   ** ** ** *  ** *
    }
 *   *   *   ********  **  * * *
    {
  * * ****  * *   * * * **** **  ***** * ***  ** **
*  * *** *   ***** ****** ****  * ******* ** * ** *****    **      ** ** * * *
    ****    * **      ***** *   * ****  *   ******  *  **** 
*   * ** * ** * *  * * * ****  *  ** *  *  **  * * **   **    * **** * ** * ***
    }
 * *  *    * * **      * **   *  0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 17.4k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 17.1k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 22.6k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 17k views
12,783 questions
183,442 answers
172,219 comments
4,824 users