2 like 0 dislike
11.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 11.9k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

**** ** ** * * ** ** i;
* * * ** *** ** * * j;
* ** * ** ** * ** ** * newNum1;
* *** ** * *** * * * ** newNum2;
****** * ** * gcd;
* ** ** * ** * * rem;
** ** *** **** num1, num2;

* ** * ** * ** ** ** **** * *** * * * * ** * ** ****

* * * * **** * **** **** ** *
* * ** * ** * * * *

* ** * * ** * ** ** * * != 0)
* ** *** * * **
** * * ** ** * *** ** *** ** **** **** = j%i;
* * * ** * * ** * * * ** *** *** *** ** * = i;
** ** * * * * * **** ** * * * * = rem;
* **** * *** ** * *** *****
** ** * ** ***** *** *

**** * * * ****** * * = num1/gcd;
* * ** ***** ** * * **** * * = num2/gcd;

** * *** ** ** * * * *** ** == 1)
    {
* * * ** ** ** *** ** * * * ** ** * *** *** ** * * *** *** **
    }

* * * ** * * * ***
    {
* * ****** ********** ** ** * *** ** ** * * ** ** * **** ** **
* * ** * * * *** * * *** *

* * * * * **** * ***** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * ** ****** * ** ******* * * ** *** *** *** *

* ** ** ** ** *** ** * ** * ** *
** * * *** * *** *** ** * ** * * * ** ** * * ** ***** *

    else{
* ** * ************ * ** * * ** ** **
    {
* * ** ** ** * * ** *** ***
*** * * * ** **** * ** ** * ** * ** * ** ** ** * * ***** * ** **** *** && deno%i==0)
* * ** **** *** ** * ** * **** ** * ***** ** * * ** * * * * * ****
****** * ** *** ** * * ** ** ** * * * ** * ** *** ******** *** *** * *** * * ** ** * * *
** *** ** * *** *** * * ****** * **** * * ** ** * *** ** *** * *** *** **
* * * * * * * * * * * **** ** *** ******* *** ** ** *** * **
    }

**** ***** * * ***** ** *
    {
* * *** * *** * * ******** * * *
* * *** ** *** * *** ******* ** ** * ** ** * * * *** * *** * *** ***** ** && deno%i==0)
***** *** ** *** * * * * ** * *** * * ** ***** *
* * ** *** ** * ****** * ** ****** *** **** * *** * ** ** * *** * **** * * **** ** *
* * ***** ** * **** *** * * *** ** **** ** *** ** * ** ** ** ** ****** **** ** * * **
**** ** ** **** ** * *** ** ** ****** * * * * * * * * **** * ** ** *
    }
* * * * ** * ** * *** * ***** * * * **** * *

    }




* * ** * **** ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** ** *
#include * ** * *** * *

int gcd(int n, int m)
{
* * *** * ** * gcd, remainder;

****** *** ** *** ** * **** (n != 0)
** ***** * *** ** *** *
* * ** * * ***** * ***** * ** * * * *** * = m % n;
*** **** * * * **** *** ***** * ********* ** ** = n;
*** * * * * * * * **** ** * *** * = remainder;
**** **** ** ** ** ** ** * *

* * * ** * * ** *** * = m;

* * * **** ****** ****** ** gcd;
}

int main (int argc, const char * argv[]) {

* **** * ***** ****** number1, number2;
*** * *** * *** ** * newNumber1, newNumber2;

* *** ** ****** ** * * * * * *** ** ** * * * * ** ***

* * * * *** * *** * ** = number1 / ** ** number2);
**** **** * ** * * * = number2 / * **** number2);

** ** **** ** * ** * *** * ** * ** * ***
* ***** * * * ** *** ** * *** * * * **** *
* ** * * ** ******* *
**** ******* * * * *** *** *** *** * ** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* *** ***** * * * **
* * *** *** ** ** **

int ** * * n, int m)
{
** * ** * ** * int gcd, * *

* *** * *** (n != 0)
* ** * ** * {
* * * ** * * **** * *** * = m % n;
* * ** ** **** ** m = n;
** **** * * * * ** * n = *
* * **** ** }

* *** gcd = m;

* * ** * * * * gcd;
}

int main (int ** ** char * *** {

** ** * int * *
**** ** * int * * ****** **

**** ** * ** ** ** *** * * ** * ** **** ****** * * ** *

** * * ** ** * = * / * *** ** *
* * * *** ** *** ** = *** / * ***** *** *

* ** * * * * * if *** ** * ***
** * * *** ** ** * ** * *** ******* ** ** *
* **** **** else
** ** ** * *** **** * *** * ** * * * *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* *** ***** * * * ** i;
* * * ** ** *** j;
** * **** ** * **** newNum1;
** * * * * ******* * ** * newNum2;
*** ***** ** * *** * ** * gcd;
* ** *** ******** rem;
* ** ** * * ** * * * * ** num1, num2;
    
* ** ** ** ** * ** ** ***** ****** * ***** * * * ******
** ***** ** * *** * **
**** ** * ** * * **** *** * *
* * * ** *** ** *** * ***
**** ** ** * * * *
*** ** **** * ** != 0)
* * * * * * *
**** * * ** *** * * * ** * * ** ** ** = j%i;
** ** * * ** **** * ******** ** ** * = i;
*** * **** * * ** *** *** **** * ** * **** * = rem;
**** ** * **** * * *
* ***** **** ** * * ** ***
    
**** **** ** ** * * * = num1/gcd;
** ** ** * * * * * * = num2/gcd;
    
* *** ***** ** * ** * ** == 1)
* ****** *** * ** * *
*** * **** ****** * ** *** ** ** * ***** * * ** * **** * ** * ** *** *
* ** ** * ** *
    
* * * * ** ** * * ** * **
** * * ** **** *** * *
* ***** ** * * * ** * ***** * * * * * * *********** * * **** *** ***
*** **** *** * * * *
    
** *** *** * ** * * * *** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
*** * ** ** ***** **** ** i;
** * *********** * *** *** * j;
* ** ** * * * * * newNum1;
* * * *** ** newNum2;
* ** * ** * *** *** gcd;
* *** * *** * ** ** rem;
**** * * ** * * * * ** num1, num2;
    
*** * * ** * ** * * ** * * * * * * ** ** ** ****** **** *
** * ** * * ***** *
**** * * * ** ** ***** * ***
* * ****** * * * ** * ** *
* ******* * *** *
* * ** ***** * * *** **** != 0)
* ** ** ** ** *** * *
*** * * * * * ** *** ***** * ** * *** *** * ** = j%i;
* ***** ** * *** * * * * * ** ** * ** *** = i;
* ****** ** * *** * * ** *** * **** ** ** ** *** = rem;
**** *** ** * *** **
* * * ** ** *** * * ***
    
* * * * * ** * * ** = num1/gcd;
* * * * * * ** ** * = num2/gcd;
    
** ********* **** * * * * == 1)
** *** * ** * ** ***
* ** * * * ** ** * ** ** ** ** ** * ** * * * * * **
* *** * * ** * ** ***** *
    
* ** ** * ** **** *
*** * * ** ** ** *****
* ***** ** *** * * * * ** * ** *** * ** * * * ** ** *** * * *
** ****** **** **** *
    
* *** * *** * ** ** **** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* * ** **** ******* * * **** ** *****
* *** * * *** * ** *** * **** * ***** * * * ** * **
    {
* ** * ** * *** **** * ** * * * * ** *** *** *
* * * * ** * **** *** * * * * *** *** * *
**** *************** * ** **
** * * * ** * * *** * **
* ** * **** ******* ** * ***** ** * * * * **

* ** *** * * ** ** **** * *
* * * * * * * *** *** **** ** *** ** * ** * ** ** * ** ** ** * *** * * * *
* ** ** ** * * ** **** *** **** * **** * * * * * ** * **** ** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
** ****** * *** * ******* * a,b,GCD;
* *** *** * * * ** * ** ** *** ***** * ******* * **
* ** * ** * ** * ** * *
******* ** * *** ** * **** *
* **** ** * * * * * * * ** * * ***** *** * ** **
* * ** *** * * ** **
*** ** * * **** * **** * ** ** ***** ** **** * *** ** * ** ***
****** * * * * * ****** * ** 0;
}
* *** * ** ** ** * gcd(int a, int b){
* * **** * * ******* * ** * ** ** * * * (!b) return (a);
* *** * * ** ** * * ** ********* * * ** * gcd(b, a % b);
* * ** **** ** * **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** ***
#include ** *** * *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* ** * * * * ** gcd, remainder;
* ***** *** ** *
* * * * ** * * *** * (n != 0)
**** * ** * ** * ****
* * * ******* ** *** ** * * ** *** * * * *** * = m % n;
*** *** * * * * * * * * * ** **** * = n;
*** * *** * * * * **** *** *** ** ** *** *** = remainder;
** * ** **** *** * *
* * * ** * ** * * **
* * ** * * ** ** ** * = m;
* * ** ** ** ** ** **
* * * * ****** * * * *** gcd;
}
int main (int argc, const char * argv[]) {
* * ***** ** * *** * * *** number1, number2;
** ** *** * *** * * * newNumber1, newNumber2;
** *** * * **
* * ** ** *** ** *** **
* ***** *** *** * ** ** ***** * * ** ** * * * *** * * *
*** ** * *** * ******* * ***
* ****** ** ** *** * ** * = number1 / gcd(number1, number2);
* ** * ** * ** * ** * ** = number2 / * * ** number2);
* * * *** *****
** *** * * ** * ** **
***** ** ** *** ** * ** ( *** ** ****
** **** ** ** ***** * ** ** **** *** ** *** ** * ** ***** newNumber1);
**** * ** * *** *******
**** ** * **** * * *** *
** ** ** * * * **** * *** * **** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * * ** ** * * *** * ** ** a,b,c,d,e,f;
**** * **** * * * *** * ** ** * * *** * ** * * **
* * * * **** * *** ***** * *
* * **** * **********
* ** ***** *** * *** *** * *
    {
** ** * * * *** ** * * * * * ** * * * *
* * * ** ** * * * * * * ** **** ** *****
*** ** ** * *** * *** * ** * **** * * ****
    }
* *** * ** ** ** * * * ***
    {
*** * ** ** ** ****** * ** *** ** ** ** **
** * ****** * ****** ** ** **** ***** *** *** * ****** ***
** ******* ** * *** ***** * ** ** * ***** *** **
* ** ** * ** * ***** ***** * * ******* * ** ***** ****
    }
* * * ** ** **** **
    {
** * * * * * * *** *** * * **** *** **
** * ** * **** ** ** ** ** * *** * * * * ** * * * * *** ***** ** **
*** ** **** * * * * ** * ** * * * * *
*** * ** * *** *** **** *** * * ****** * ** ******* ** * *** * *
    }
** * * ** ******* ** ** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.173
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 12.2k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 11.8k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 15k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 11.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users