11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
16.4k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 16.4k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

*   ****  ***  *  ***** ******    i;
 *    **********     ** **  * * j;
 **  * *   *    **    *  ** newNum1;
* * **   *  *   ** * ****  ** newNum2;
 ** ** **    * * * **  **  *  gcd;
*     * **** * *   ** *  *  * rem;
**   **** * ***** * * ***   *   num1, num2;

**   ** *  *** ****    *   **   ***** **     *  *      ***  *  **  ** **

  *  *    *** *  ** * **  ***** *
     ** * ***  *  * * * *    *  *

  *    ***  * **     *      **  *  != 0)
**  *  *    *  **  *  ****
****  *****    * *** *******  ** *     * * *  * *** * **  * *  = j%i;
* *   ****    * ** *  ** * * ** **  *** * * *****  **   = i;
 *   *****   **  *  * ** ** *  ** * **  * ** * * **  * ***  = rem;
 *     *  ** *  ***   *   ** *
*     ***    **** ***    *   ***

******  **  * ** * ** * **  *  = num1/gcd;
** *  * *      *  * * ****  * *  = num2/gcd;

 *   **    *** *     * **        == 1)
    {
*  ***** *   *    **  *** *   * **   * * ** **** ***   **   * * *  * * * ** * ** ** *  * *
    }

 *  * * ***  ****** * ******
    {
 *******   ** *** ** **    ***        ***  * **      ** * * ** *****  *** *  * *** *
 *   *  **  **** *    * 

  * ** *    **   * *  **  * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
*** *  ** *  ** * * *******    ***   * ** ****   *    * ***** * * * **

* **  *    * **     *   **    * *  *** 
****** * * *   ** * ** *****           ***** ***** ** *    *    **   * **  * * 

    else{
 * **  **   **  * * *  *  *  * * ***
    {
** * * ** *** *      * * ** *   *  * ** ***
* *        *** *  *   ** **    **** *     *    * ***  * ** *****   **  *  * **  ***** *    ** && deno%i==0)
**   * * * *** *     *    *   * ***     *** * **  * *    **    **  * * 
* ** ****** ***   *  *  **********     * ****   **   * * * **   ****  **  **   * ***      *  **** *   *      
 * ****  **** ****       **  **  ***  ***  *** **  * *  *   ********* * * * ** *    *** * *    * ***  **  * 
 *    *  **** * * * ***  *  **  *   *     ** * ****  *     ******   *  * ****** 
    }

*******    **  ** ** *  *  * * *  *** *
    {
*   * ** **** *   *****  **    * *** ** **  **
**   ** ****** *** ***  * **  ** **  ** *** *    *      ** ** *     * * ***  ****** * * && deno%i==0)
 **  *    **  ** * ***  **   *** *  *      * ***  * * *  * * ** **** * * * *
*     *  ** **    * *** **       **   * *  ** ** *   ** ** ** ** *  *******  *** * *  **  ***      
** ** *     *  *** *   * * * ** * * ***   ** **  *   *  **  *       * *** ** * ** * ** ****** ** * *     **    
       ** **    **  * *   *** * *** * * *** ***  * * * *  * *  ** *** * *  * 
    }
****     *    *         ** **     * **  *     ** * *** **

    }




* ***   **   **  ***   ***    0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **   * *****
#include  ** **   *  ****

int gcd(int n, int m)
{
*  ***   ***  *  *****  * **   * gcd, remainder;

*   **  * ** *****  *** * * * (n != 0)
*   * *  * ***  ** *  * **
   *** ** **   *  *    * ** ***        ** ********    * = m % n;
*     **   *   *       *     *   ** **   ***  *** **** *  ** **    = n;
  *  * **    *     * **  *    * ** * * *******  * **  = remainder;
 *  *    ****    * * *  **  

** *     *  *****    * ** * **   = m;

  *  * **** ** ****  ** ** gcd;
}

int main (int argc, const char * argv[]) {

* **      *  ***     ** ** number1, number2;
* * *  * ** * * ***     **     newNumber1, newNumber2;

   ******** * **      * *   *   ***  * ** ***** * * ** **** **  **** *

*  ** * ** *****  **  *** * ***    = number1 /   *      number2);
* * ** ****    *      *     *** = number2 / *   *  ** number2);

 * *   *  ***** *  * ****  **   ** *    * **   
 **  **    ** ***   * *   * * **** *  *  ***    **  *   *  *  *   * 
   * **      ***  ** *  *   **** **
* **    ** **** **  ** *     **  * *** *******  *  * * *  
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**    *  *  * *  **  *  * *  
*   **    * *  *  **  

int ****  n, int m)
{
**   **  * **** int gcd,  *  *  

* *** * ****    (n != 0)
* * *** ***  *** {
  ***     *****   ***  *  * *    * ** = m % n;
****** *  * *    *  * *  *  **  m = n;
**    *      *    ** * * ****   n = ****  * 
* *** *  *** * }

* *   ***** gcd = m;

  ** *     * *       gcd;
}

int main (int    * * char *  *   {

   * *** * *  ** int   ***  * *** 
*  ***    * *   * int ***      *  *   

***  *   **   * **  **   * *   * * * * *   **  ***** * * 

* **      * *       *** = * *  /  **** *   *    *
   ***  *  *  * * *        =  *  *  /  **  *  *   *****

  **   ** * ******* if * *  *** ***    ** * *
*  ***  ** ** *    * * *   *** * *    **    **  * * * *
* *     * *       else
***  *  *** * * *  ** **    ***  * * ***  ***  ** ** *****
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
*** **  * * ****  *   **  **   i;
 *******   *  * *   **  *  j;
*** ********* *  **** **  newNum1;
**  *** **      *    * *** * newNum2;
**** *** *   *  * **** ***    gcd;
 *   * *   ** *  ** *   * **   rem;
****   *   *  ** *    * * * num1, num2;
    
*  * * **** * *  *  **  *     *** **    *   * **   ** *    ** *** * * * * ** *  
 * *       * ******* **** *  * 
** ***  **** ***   *   * *  *  
**    ****** **  * *  *  **  
* * * *** *  ***  * *** *
 * ***  **  * ** * ** *****    != 0)
 ** **     *  ****  ***** ** 
  *  *    ***** * *** *    * * ** ** ** * * **  *    *  *  *   *    = j%i;
  *  * **** * **     *    *  ***     ** **  * * *  *  *   = i;
**  *** *      * * ***     *****  * * *  **     *  **  * = rem;
      *******  *      *** *  
*** **       * * * ** ** 
    
       **     **   *  *   * *** * **   = num1/gcd;
*    *   **      ** * ** *  = num2/gcd;
    
*    ** *  *   ** *  **   **  ** == 1)
**** ** *   ****** ***  ** 
 * **  *   ****** *  *     ** ***   *****     *  ** *     * * *** **** *  *  
*   **  *   *  * ***  *   ** 
    
****   **  * *  ****  *
  *** **  ***    * *  *    * *  *
*   *** * ** * ** *** *  * *  **  ** **   *  ****  ***** **** ** *  * **  * *
**  **   ** *   ** * ** **    
    
*  *  ****    **   * *  *  * * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 ** ** *  * * ******* *** *** * i;
      * ***   *   * *  *   *  j;
**   *    **** ****   **    newNum1;
*   ** * **** *  * * ** * ** newNum2;
* ****   * **** *  *  * *   *  gcd;
 * **     *  *  ** **  * ** rem;
* * ** *  *  *    ***    ** ** **  num1, num2;
    
 ** **** * ***     * ** *   *  ***        *   * **  * **** ***  *
** *  ** ***  *   * * **   **
*       * **  ****  **** * *
 * * * **  *    *  **     **   
 ** *  ***** * * **  ** *   *
   *  * ****       * * ** * *  *  != 0)
*** ****** *   * *  * ** *  * ***
 *** **** * ** *****  *  *** *    *  *** * *   * ** *  *   * = j%i;
*****  ** *** ** ***   * **   *     * *   ** * * *  ***   = i;
 *        *** **  **** * **    * * ** ** **   **  * ** ** = rem;
* ***** **   *     *  ***   * **
***  *** ****  *** *   *   ******* *
    
    **** *****  * * *    = num1/gcd;
  **  * * ******* *  * *  * = num2/gcd;
    
 * * * **       *  * * ****** *   == 1)
*   ****  *   *    *  **      
   ***  * * * * **    ***  ****  *    *******  * ***  * *    *  **  ** ****
    *   ** *  * ** * * **** 
    
 * ** *  *  * *   **  **   * 
** *  * *  * *** * *** *** 
* * ****     ** * ***  *  ***** * *  **  *   * **  ***  * *** * ***** *   *    *  *  ** ***
  * *** **  *****  ** *
    
**  * **  ** **** **** ** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
**   *    **** *     ** *****  ****  * **** **   * *********   
 *   *** *   **  *  ***** ***** * *  ****   ****  *    ****   * *
    {
 *      ** ** **  * * ** ** * * **  * ** **  * * **     ** *  ****  * * **
* * ***     ***** ** * **  * ** ** *  *  **  * *** *  *   ** *** * *   
 **** ***     * *** * **** ** * **  ** 
**  ** ****  * * * *****    ***  **  * * ** *
*     * *  *     * * *  * ****   *  * * ** **   

****   * * * ****  ** *   * *** 
 *    **** * ****   * ** ******    *  * ** *** ****  ***   **********  * *** *** *     *** ***** ** 
 ***** * *   ***  **** **   **** * *  ****  * * **  ** *** *** *****  *  ** * 


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* *  ** *  * * * **     ***   a,b,GCD;
* ** *   ** *****   ** ** **  * **  *  *  ****  * ** **
  *  ***  * * *******  *  ****** *
  * ** *   *   ***  *   ** ** **
    ** * ** *  * * * *   ** * *  *  *****     * *  **  *   *   *****  ** ***
 ** *** **   **  *   ** **** 
   * **    *  *** ** ***   * **    *      * **  ***   *  ***  * * * ****   
***  * *  **  *   * * * *     0;
}
** * * ***  **  ** * **     *  gcd(int a, int b){
**    *  ** **   ** ***  * ** * **  *  *  * **  **   (!b) return (a);
****** *  ** ** *** ****  *  **  ***  * * ******   ** * *  gcd(b, a % b);
*    *  **      * ** ***   *** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    *   *  ** 
#include    *** * ** **   

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
  ** ** *   **         *    * * gcd, remainder;
 *   *     ***** * *     ***
 *   ***       * * *  (n != 0)
* * *** **   ***   *  ** * *** 
* ***    *   **  ****  ** *  ***  *  **** *  ** * = m % n;
   * * **  *** ***        * *    *   *  *   *   ***** *   ** = n;
*   ***   *** *  *      *  *  * *** **   *    *  = remainder;
   * ******  ** *  ***  **
***    ***     ** ** **  *
*   *  ****   *       **** = m;
* **   * * *        *   *
  * *****  *     * *     *  * * gcd;
}
int main (int argc, const char * argv[]) {
* **  * **** *   *  * *  *** number1, number2;
** *** *    *** *      *    * newNumber1, newNumber2;
** ** **** *   ****   *      ** 
**   * *  *****  *  * *****
 *** * *     **  *  **  *  ** ** *  * *  *     *   * * * **   **  **   ** *
     * * *******    *   
**      ** * ****    * *  * ***  = number1 / gcd(number1, number2);
** *  *  *** ** * *  * ** * *  ***** = number2 / *  **** number2);
 ****** * *   ***  ****
**    * *   *  **    * ** 
****     ** **  * ** *   ** **  * ( * * *  *
  **  *     ***** *** * ** * *   * * *  ** * ***** *     * *   ** newNumber1);
******    **    *  *        *
**********   ** * ** *  ***  * 
**** *  * * *    **** *   *** **  ** *   *****   * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* *****   **  ***  * **  * ****** *  a,b,c,d,e,f;
 ** *      **** *  ** *****  ***   *  **  **  *    * ** *** * 
 *    ***      **   *      *
 * * *** *   *     **** *  * *
*  ** **    * * *  * * * ** ** ***  
    {
**    * * * ****   *    *** *   **   *  **** *     *  
*  * *** *  * * **** *  *****  **** * *   * *     *    
  ***** ****  *   * **   ******** **   * * *  *       ** 
    }
  *   ** ***** **   **   ** *   * *
    {
** ** * * * * * * *     **   * ******** ***  **  * ** *   **** *
***** **    ** * *  *  *  ***** ** *** *******     **  ** *     ********* * * *
*  *   *  *    ***   *   *    ***  ******   *  *****      
*  *** * * * ****  *** * *  *    **   *     ** *  * *  *   ********* * *** *  *  **** 
    }
  *  * *  *   *** *  ** **  *
    {
       *  ** **            * *   **   **  *     * **  * *    ******
*  ****   ** *  **** *   * *   **  ***  *** * *  * ** *** ** ****** * * 
  * ***   * ***  *   *  *  *     ****** *    *       *
   * * *     *   ** *   * *  *****  * * * ** ** ****    ** ** ****  * *** *  
    }
      * * ** * **         ****** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.165
©2016-2026

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 16.4k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 16.1k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 21.1k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 16k views
12,783 questions
183,442 answers
172,219 comments
4,824 users