2 like 0 dislike
7.8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 7.8k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* * * ** * ** * * * * i;
****** * * * ***** * ** j;
* ****** * *** * **** ** newNum1;
**** ** * *** ** ** *** newNum2;
*** * ** ** *** ** gcd;
*** * ** * * * * ** * rem;
** * * * * * * *** ** * * * num1, num2;

* *** * * ** * ** **** * * * ** ****** * * * *

* * * * ** * *****
** ** ** ** * ** *

* *** * * ** ** ** ** != 0)
* * * ** * * ** * **
* ** * * * ** *** ***** ***** ** *** ** * ** * * = j%i;
*** ******* **** *** *** ***** * * * *** ** * = i;
******* * * * ** *** ** **** ** = rem;
****** *** **** ***** * *
** *** ** * ****** ** * *

* * * * *** * * ** * * ** * * = num1/gcd;
* * * * ** * * * = num2/gcd;

* * * *** ** * * ** ** == 1)
    {
****** ** **** ***** ** * * ****** *** * *** * ** ** * ** * ****
    }

*** * **** * ** ** **
    {
* * * ******** * *** *** ** ** *** * **** ***** ** ** * * * *
* * **** ***

* * * ** *** ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** *** ** ** * * ** ** * * * * ** * ** **** *** ***

* * * * ***** * ** **
** * * * * * * ** * *** ** *** * * *** *** ***** *** * ***

    else{
* ** * ** *** * ****** * *** ****
    {
*** * * ** * ** * * * ** * * *
* * ** * ** *** * ** ** ** * ***** * ***** ** * *** && deno%i==0)
* ******* * * ****** ****** ** *** * * **** **** ****** * * ***
****** * * **** ******** ** * ** *** *** **** * ** * * * **** * ** * ** * *
*** * * * * *** * ** ** *** * ** ** ** **** * * ** *** **** * * * ** ** ** * * ** ***
** ** *** *** *** * * ** ** * ** * * ** * ** * * **** *
    }

** * ** *** ** ***** * *
    {
* * ** ******** * * ** * **** *
* * * *** * * * ** * * * **** ** * * ** * ** *** **** * ** ** && deno%i==0)
** *** * **** *** ** * *** * ** *** ***** ** * * ** * ** * * * * * ***
*** ** **** * ** ** ********* * * * ** *** *** * ** ** ** *** ******** ** * ** *** * ** **
***** *** * * * ** ** **** *** * ** ** * * * * * * * *** * * ** * * **** * * ** ** *
****** * * * * **** ** * * *** ** * * * ** ****** * ** * *
    }
** * **** ******** * ** * * ** ** *** **

    }




* ** * * *** * ** * ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** ***
#include ** * **** **

int gcd(int n, int m)
{
*** *** * * * ** * ** ** gcd, remainder;

** ****** * * * (n != 0)
* **** ** * * * *
** * * * ****** ** ** ** *** ** * **** ** * * *** = m % n;
** *** ****** * **** *** * **** *** ** * * = n;
****** * ** ** ** * * ** ** *** *** * * = remainder;
** * ***** * * * ** *

*** **** * ** **** * = m;

** *** * ******* ** * ** gcd;
}

int main (int argc, const char * argv[]) {

** **** * ** * *** * number1, number2;
*** * * * * ** * *** * * newNumber1, newNumber2;

** ** * *** ** ** * *** * ***** * ** * ** * * * * * *

*** * *** *** * * ** * * = number1 / ** ** number2);
* * ** * **** ** * * = number2 / * *** number2);

** * * ** * * ** * ****** * *
**** * ** * * * ***** ******* *** ** * ** * * *** * * *
* * * ***** ** * *
** * ** * * *** * ** * **** ** * **
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
** * **** * ** *
** ** *

int *** n, int m)
{
* * * * * * int gcd, ** *

** * ****** * (n != 0)
****** * * ** {
* *** *** * * ** * * ** * = m % n;
* * ******* *** **** m = n;
******** * ** * * * * n = ** *
* * * ***** }

* * ** * gcd = m;

* * ** * * **** gcd;
}

int main (int *** char * * * * {

** * * * * ** ** int ** * ***
* ** **** int * * ** *

* ** ** * *** *** * ** ***** * * *** * ** ***

**** * *** ** * = ** / **** ****
* * ** * * ** ** = * ** / * * ** ***

**** * ** if ** * * ***
*** * * * ** ** *** ** * * * *** ** ****
* * * * *** else
****** ** * * * * *** * * *** * * * ******
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * * * **** * * *** * i;
* ** ***** ***** * *** * j;
** * *** * * ** ** newNum1;
**** ** * *** *** * * newNum2;
* ** * * *** ** ** gcd;
***** * *** **** * * rem;
*** * * ** * ******* num1, num2;
    
** ** ***** * * ** * *** * **** ** * * ** * ***
** * * * ***** *
** *** * * * ** *
* **** *** ** ** ******
** **** ** * *
* *** *** * ** * * * ** * != 0)
** * *** * **** **** * *
* * ******* ** * * **** * ** * * ** * ** = j%i;
* * * * ******** * ** ***** ** ** * * * ** = i;
* * * * * *** *** **** * **** * * = rem;
* * ** ** * ***** * *
* ** * * * * **** * **
    
* ** * * * * ** * * ** = num1/gcd;
*** * * * * * * * ********* = num2/gcd;
    
* * *** * * *** * * * ** *** * == 1)
* *** ** * * * * * *
* * ** * * *** *** **** *** *** * ** ** *** **** ** * *****
** ***** * * ** ****
    
** ****** * * *** *
* *** ** * * * ***
* * *** * ****** *** ** * *** *** *** ****** * * *** ** ****** ****** * * *
**** *** ** **
    
* ** * * ***** * * * * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ** **** *** * **** i;
* ** * ***** ** * j;
* * *** * * * ** ** * * ** newNum1;
** * * ** * ** ** * newNum2;
* * *** *** **** ** * * gcd;
* *** **** * *** rem;
* * * ** ** * ** num1, num2;
    
*** * * ****** ** *** * * * * * ** ** *** ** * *
* **** **** * * * *** * **
***** * * ** *** * *** * * ** *
* * * ** * ***** ** * *
* ** ** * *** ** *
** * * * ***** *** * ** * != 0)
* * ** *** * * * **
* *** ** ** * ** ** ******** * * *** * * = j%i;
** * *** * * * * * * * * ***** ** * **** = i;
** ** *** * * ** **** ** * * ***** ** * *** = rem;
*** * ** * * * * ****
* ** * * * **** * * ****
    
***** * ** *** * * **** ** * = num1/gcd;
* * * ** ** * * *** * ** = num2/gcd;
    
** ***** *** * **** == 1)
** * * * *** ******* *
* **** ** *** ***** * **** ** * *** **** * * ******* * * * ** * * *
****** ** * *** *
    
* * * *** *** ** * * *
*** * *** * *** *** ** *
* * **** * * ** * * * *** * * **** *** * ***** * * ** * ****
* * **** * *** ******* *
    
* * **** ** ** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
*** * * *** ****** * ** *** ** ** ** *** * * ** *
* ** ** ** * * * * * * ** * * * * * * *
    {
** *** *** ** * * * *** *** ** ** ***** * * * *** ****
** * * * ** * * * *** * **** * ** * ****** * *
* *** ** * **** * * ** *** ****
* ** ** ** * * * * * * * * ** ** * * * ****
*** *** * * ***** *** * ** * * *** *

* **** *** * *** **
** ** ** * *** * ** * * ***** * * * * ** *** * * ** *** ** ** ** ** * ******
** *** * ** * ** * ***** ** *** ** ** * * ***** * ** ****


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*** * ** ** ** * * ** ** a,b,GCD;
** * * ** * * * * * * ** *** * ** * *** **
** * ** * ** * ** * **** *** * *
* ** ** *********** ****** * *
** *** * * * * ******* *** *** * * * ** * * **** * * *
* ** ** * * * ** *****
**** ** * * ** * *** ** ** * ** * ******* * ** ** * *** ** *** * *
* * * * **** * * * * 0;
}
** **** * * * ****** gcd(int a, int b){
* * ******* * * * * *** * * ****** (!b) return (a);
****** * *** *** * * ** * * ** ****** *** * gcd(b, a % b);
* *** * * * ** * ** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ****
#include * *** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* **** **** ** * ** ** gcd, remainder;
** * * * ** * * *** *
* ** *** **** **** * * ** (n != 0)
** ** ** * *
**** * ** * * * ** ** **** * ** ** * ** *** * = m % n;
** * * **** ** **** *** * * ** **** ** = n;
** *** ** *** ** *** **** **** * *** * = remainder;
** * *** * ** * * *
** * *** * **** *
** * * * ** ***** * ** * = m;
* * * * ** *** * * *** *
** * *** ** ** * ***** gcd;
}
int main (int argc, const char * argv[]) {
** ** *** ** * ** * number1, number2;
** *** ** *** * * ** * *** newNumber1, newNumber2;
* ******* ** * ****** *** *
** * * * ** * ***** *
** ** * * * ** * ***** **** * ** ** * *** * * * * * * * *
** * ** ** **** * * *
* ** ** * * ** **** = number1 / gcd(number1, number2);
*** * * * *** *** ** * * * = number2 / * ** number2);
** ** *** ** *** ** *
* *** **
* ***** ** * **** *** ** ( **
** * * * * * ** * ** * * * * * ** *** * * **** * ** * * newNumber1);
* ** * * **** * *******
* ** ** * *** * * **
**** * * ******* * * * * *** **** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * * ** ** * *** **** a,b,c,d,e,f;
* * ** *** **** *** * * *** *** ** * * *** ** * * **
*** ** * * ***** * * ***
** ** * ** * **** *
*** * * ** * ** * *** **
    {
* ** *** * * **** * * * * *** ** * *** *
*** * **** * *** *** ******* * * ** * * * ** ** ** *
* ** * ** * * ** * ** * **** * * * **
    }
* ** ** * * * * * *** * ** *
    {
* * * *** * * * ** * * ** **** * ** * **** *
*** *** * * * ** * ** * ** * * ** *** * * ** * * **
* * ** * ** ** *** * * **** ***
*** *** *** * * ** * **** * * * * * * **** ** *** * * ****
    }
* ** * ********** * *
    {
** ** * ** ** * * * ** *** ** * * ** * * ***
** * * ***** *** *** ** *** * *** * * * *** * **** * *** *
* * ** * * * ** * * ** ** * * *** * *
*** ** * * * * * * ** * * * ** * * * *** ** ** * * *** *** ** * *
    }
** * ** * *** * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.50
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 8k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 7.7k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 9.7k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 7.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users