2 like 0 dislike
1.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 1.9k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* **** ** * ** * * **** i;
* ***** ****** ** ** j;
** * * *** *** * newNum1;
* ** ** * ** * ** newNum2;
** ** ** * ** *** gcd;
* * **** ** * * ** ********** rem;
*** * ** ** * *** * * num1, num2;

* * ** * * * * ** * * ****** * * *** ** * **

* * * ** *** * * *
* * * ******* * * * ** ******

* * *** * * * * *** * != 0)
* * ***** *** * * * *
* *** ** * *** * * * * * *** ***** * * = j%i;
* * * * * ** * * ** *** ** * ** * ****** = i;
* ** * ** * ***** * * * * *** ** ** ** = rem;
** *** *** * ** * ** **
** ** ** * * * * ***

** * * * **** ** *** * * = num1/gcd;
* *** ** ** *** * = num2/gcd;

* **** * * * * * * * == 1)
    {
*** * * * *** * * **** ** **** * * *** * * * ********* *
    }

* * **** *** **** ** ** *
    {
** * * * * ** * ** ** * **** * * * ** * ** * * * ** ** * * * *
* ** * * ** *** *** *

* * *** * * * * *** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * * * * * ** * ** * *** * * *** *** * * *** * * *

* ** * * *** ** * **
***** * **** * ** * * * ***** * * * *** * * *** ***

    else{
* **** * * ** * ** * * * *
    {
* * *** ** * ** ***** * * * * *
** *** * * **** * ** * *** * * *** * * * *** * ** * *** * * ** * * ** && deno%i==0)
* * *** * * ** ***** *** * * * * * ** *** ** * ***** ** * * * ** * *
* **** **** ******* *** ** ** ** * ** ** *** ** * *** **** * * * * * ** **** * ** ***
* * *** * ** **** *** * ** * ** * * * ***** ** ** *** ** * **** *
* ** * ***** **** ** ***** ***** ** * ** ** * *** * *** ***** * *
    }

** ** *** * * ** * * * * *
    {
* * ********* ** * ** ** *** *
* * * ** * ******* * *** ** * * * ** ** * ***** ** **** && deno%i==0)
*** * * * * *** ** * ** * * * * * ******* * * * * * ******** *
* * * * *** *** * ** *** ***** * ****** ** ** * * * *** * * ** ** ** * * ** *
* ** ** ** ** ** *** ** ** *** ** ** *** **** **** ***** * ***** ** * **** ** ***
**** * ** **** ****** * * * *** ** * * *** * ** ** ** * * ** **
    }
*** ** *** *** * ** ** * * * * ** * **

    }




** **** ** * *********** * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * *** ***
#include ** ** *

int gcd(int n, int m)
{
** * * * ******* * gcd, remainder;

* **** * **** * * (n != 0)
* **** * **** *** * ** *
* ** ** *** ******** ***** ** * * ** * **** = m % n;
*** * ** * *** *** ** ** * ** **** = n;
** *** * * ** *********** * ** ** * = remainder;
*** ** ****** * ** ** ** *

* * * ** ** * * ** ** * = m;

* ** ** * * ** ** * ***** gcd;
}

int main (int argc, const char * argv[]) {

* * *** **** ***** ***** number1, number2;
** * * **** * **** * newNumber1, newNumber2;

***** * * *** * * ** ***** ********** * * ***** ** * ****** ** *

* ** **** * * *** * ** * = number1 / ** ** number2);
* *** * * **** * *** **** ** = number2 / *** *** number2);

* ** * * ** * * **** **** ** ***** ** * **
* ** *** * ****** ** * * * ** * *** ** ** * * ******* * *
* * * ** * ** *** ** *
** **** ** *** * * * * ** **** * ** ** ***
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * * ******** * * *
***** * ** ** ** *

int * * n, int m)
{
* * * * * int gcd, ** ** *

** ** **** ** (n != 0)
* ** {
** * * * * * ** * * = m % n;
** ** ** ** ** ** ****** ** m = n;
* * * * * * * * **** n = ******
** * * * }

* * ** * gcd = m;

*** * * * ** gcd;
}

int main (int *** ** char * ** {

*** * * *** int * * * ** *
* *** *** * int * * * * *

* * * * ********* ***** * *** ***** **** * * ** * *

* ** * *** * * * = * / * * *
* ** * *** **** = **** / * ** * * * *

*** ** ** *** if ** ****** * **
* *** *** * * ** * ** ** ***** * * * *
* ** * **** else
* *** * * **** * * * * *** ** ****
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ** *** ** * i;
* * * *** *** ** **** j;
****** *** *** ** * newNum1;
*** * ** * **** * newNum2;
*** ** * * ** * **** * * ** gcd;
* * ** * ** * * * ** **** rem;
*** *** * * ** * ** num1, num2;
    
* * *** ** **** * * * *** * ** ******* ***** * **
** * * ** ** *** * *
*** * *** *** * * ** * *
* ** * ** ** * *** ******* ** *
* * * *** * * * * *
* ******* **** * * ***** != 0)
** *** * * *** * * * * **
* * * * * * * *** * * * * * *** ** * ** = j%i;
* * * * ** ** * ** **** * *** **** * ** = i;
** * * ***** * * * * ***** * *** ** *** ** = rem;
** ****** * *** ******* **
* * ** * **** * * * *** ***
    
* * * * ** * * * * ** * * = num1/gcd;
* * ** * ** * *** ** *** = num2/gcd;
    
* * * * * * *** ** * * **** * == 1)
* ** * * * * * **** *
* * * * *** ** * * ** * ** **** * * * *** * * *
* ** * * ** * ** * *
    
* ** * * * *** ***
****** * ** ****** * ****
** **** * ****** * ** ** * ***** ******** ** * ******** * **** * **
*** * * ** * * * *
    
***** * * * ** **** ** * * * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
*** *** * * * i;
* ** * *** ** * * * *** j;
* ** * * ***** * newNum1;
* * * * ** * *** ** newNum2;
*** * *** * * ** **** gcd;
** * *** * * * * * rem;
* * ** * ** *** * * *** ** * num1, num2;
    
* * * ** ** ** * ** * * * ** * * * *** * * *
* *** * * ** **** * *
* * * * * * *** **
* * * * ** ** * *** * *
** ** * * * *** *
* ** * **** **** * * * * != 0)
* **** *** * ** **
* ***** * ** ** * * ***** *** ** *** * = j%i;
* * ** ** ** * ****** * * **** = i;
* **** * * **** * * ** **** * ***** *** ***** = rem;
* * ** *** *** ** ***
***** * ** ** * * * ** * **
    
*** * ** ** * *** * * ** * * = num1/gcd;
* *** * ** * * *** *** ** = num2/gcd;
    
* * * ** ** * * ** * **** * **** == 1)
* ** ** ** *
* ** * * * **** *** * ** * * ** * * ** * * * *** ** *** * ** **
** *** ** * * *
    
* ** * * *** ** *
** * * * * *** * *
* ****** ** **** **** ** * * ** ** *** *** ** * * * ** * **
* * **** * * ** *** ** *
    
** * ** *** *** ** *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** ** * *** * ***** * ** ** ** ** ** * ** *** * *
* ** * * * ** * ***** ** * * * ** * ** * ****
    {
** *** * * ** * * *** ** * * ***** *** ** ** * ** ** * *
*** *** ** * ** * ** *** * * *** * * * * * **
***** *** **** ** * ** *** * * * * * **
* * ** ** * * * * ***** ** ** **
*** ** * * * ****** *** * ** ***** * *

* * **** *** ** * *
***** * ** ***** * * * * ** * * ** ****** * ***** * * ** *** * ** * ******* * * *
** ** ** * * * *** ** * ** * * * ***** * * *** * *******


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* * * ***** *** * ** a,b,GCD;
***** ******* * * * ** * * * ******* **** * ** ***
***** * * *** ** * * * ** **
* ** ** * * ** *** * * * * *** *
*** * ****** * * *** * *** * * * ** ** * *** **** * * ****
* * *** * * * * *
* ** * * * * ** * ** * **** * * * ** * * *
* ** ** * *** ** ** * * * 0;
}
** ** ** *** * * * * * *** * gcd(int a, int b){
* ** * ****** ** *** * ** * ** ** (!b) return (a);
***** * ** * ** * *** ***** * ** **** ** * ***** ***** gcd(b, a % b);
* * ***** ** * ** **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * **** ***
#include * **** **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* * * * ** ** * * gcd, remainder;
* * * ** ***** * * *
** * * * * ** ***** ** ** *** (n != 0)
* * ** * ** * * **** *
* * ** **** **** * *** * * *** **** * ***** * * * = m % n;
* ********* * * ** *** * ** *** ** = n;
** * * * ** * * * **** **** * ** * * ** = remainder;
** * * ** **** * **** ** *** **
** * ** ** **** * * *
**** ** ** ** **** * ** * = m;
* * *** ** **
* ***** * ** * *** ** * gcd;
}
int main (int argc, const char * argv[]) {
* * ** * * **** * ***** number1, number2;
** ***** * * * * newNumber1, newNumber2;
* * * ** * ** * *
******* ** * * *** ** *
** * ** ** ** **** ******* ** ** * ** ***** * *** ** * *
* **** * ***** *
* * * * ** * **** * = number1 / gcd(number1, number2);
** ** * * * * * *** * = number2 / ** * number2);
*** ** *** ** ***
* * ** ** ****** * *
** * ** **** * ( *** ** *
*** * * * * **** *** ** ** * *** ****** ***** newNumber1);
****** * * * * * * ***
**** * * ** ****
**** * * ******** * * * *** *** ** * * ** * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** * **** ** * *** * a,b,c,d,e,f;
*** ** ** ** ** ****** * * ** * ***** ***** ** ***
** * * *** * *** *
*** *** ** *** ** * ** *
*** * * * ** * * *** *
    {
***** * * ** * * *** ******* * * ** * **** *
** * * * ** *** **** ** **** * ** ** * * ** *
* ** *** ********** * * ** * * * * * * * **
    }
* ***** ** ** ** *** ** ***
    {
* ** * *** *** *** * * * ** ** *** *
* * ** * * * ** * * * ** * **** *** ****** ** * * * *** ***
****** *** * * ** * * *** **** * * *
** **** * * ** * * ** ** ** * **** ** * * * ** *** *** * **** **** **
    }
* **** ****** * *** * * * *
    {
** * **** ** ******* ** * * * * *** *** * **
**** * * *** * * **** * * * * *** * *** ** * * *** * **** ** **
***** * * ** ** * * *** * ** * ** ** * **
* *** ** * ** * * *** ** *** ***** *** *** * * ** ********
    }
* *** * * * ** ** ** * *** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.200
©2016-2024

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 2.4k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 1.9k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 2.5k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 1.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users