11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
18.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 18.9k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

 **  **  **    ***  **   ** i;
 *  ** ****** * *      **     j;
*   ** **** *  * * *** ** *** newNum1;
  *   *  **  **** ** *****   * * newNum2;
 *          * *** *** *  *   * gcd;
*  *** **  ***   *  *  *  *   rem;
  *  * *****    * *  * *  ** *   num1, num2;

 *  * * ** ** *  ***      * ***  ***  *   ******* *   ** *  *****  *** *  ***

 * *  * *******    **      * *** * 
* *   *** ***      *  **  * *

**  *     ******  *** **   ***** * != 0)
** *** ***   **  * ** * * * 
 **  ******* * *  *   ***    *** * **** * *** **  * * * = j%i;
 * * *** **  **** *** **  * * * *   ***   **   ***  ** ** ** = i;
    *** *  **  * *    * * ***** *  *  ** ** **   *  = rem;
*   *** **  *  ***       ** 
 *    ** *   *    ** * * *      ***

* * *  ************  *    **   ***     = num1/gcd;
   * * ** * * ****** * **   **  = num2/gcd;

*    * * * *    * *****     *  ****     == 1)
    {
   * **  * * **   ** * **  ** ***      * * *  ***   *  * ****** * *   * * ****
    }

**  ** ****   *   *** **
    {
          **** **   ***        ** *** ** ***   *  ** * ***  *  ** ***** *  **  
 *  * *  ***  *******  * *  *  *

*  ***   * *   * *         *  * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
  *  * ***** *      * *      *    * *   ***  * *  *  *** ** * *    *

*   ***  ** ***** * **        *  ******
* **    *  *** *  ****  ***  **   ****        ** **  *  *  *****   * ***  *   * *  

    else{
**   * *   ** *   *  *     *  ********  *
    {
      *  *** ** *    *  * *  *****   
  *        *    *  ** * *  * *    * ** *  **  *  *******   ** *   **** **   *  **  * *   *   && deno%i==0)
*  ****        ** **  * **  *** * *  * **  * *  * *****  *   ***     *  * 
***        * ** * *     ** ** *   ***  ****   * * *  *** *   *  *    **   **** * * ** * *  **  * ***   ** * * * *
** * *  *** ***     ***    * ** * ****    **    ***   ** * *   *** * * ****  **  ******* *  ***     *** **     
* *      *   ****   **    *   *    *   *** **** **  ***   ** *     * ** *   * *   ***  *
    }

  ***    *  *******   **   *   * *      
    {
****  * *  **   *   **  ****   * * *  ** 
 ** **** ** *** *       *    ** * ***   **  *   *** *** *  **     **** **** * * **     *    && deno%i==0)
  *      *  * *** ** * ****   *      *   * *   * *   * *  ***  ** *    ****** **
 *****    ** * *** ************* ****** *      *******      ****** * **  ** **  ****  *** *   **   **
   *  *   ** ***** *   ** * * * ***      *  ***** * ** * *    ******  *  *   *   **  ****  *   * ****  * ** *
* * **   * *  *** ******* ***   **** *    * ***      ** * * ****    * ** * *  *** 
    }
* *  ** *** *  *** *** * *  *  * *   *** *   *  * * 

    }




** **  *       *      * ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  *    **** * *
#include ***** *  * ***

int gcd(int n, int m)
{
 **     * *   *  * *** **    ***  ***  gcd, remainder;

*   ** * ***  *** **      * ***  *    (n != 0)
*   * * *** *  * ***** ** 
 * * ** ****      * * *    *     ******* *  **   * *   * = m % n;
**   **     **  *******  ** *   *  ** * *****   * * ***  * *  = n;
****** *  ** * * *       *********** ***   *   ** * * ** = remainder;
 * ** ********  *  *     

*  **  ** *** **  **     = m;

  * * * * **  *  *  * *     * gcd;
}

int main (int argc, const char * argv[]) {

  * ** * **    * ** *****    number1, number2;
* * ** * *** *   *** ****  ****  * newNumber1, newNumber2;

 ** ***  *   ***    *   * *   **   *     **  *      **        ***    *  * *****

** *  ** * *        *         * *** * = number1 / *** ***  * number2);
 *   * **  **  ** ** ***** ** * = number2 / * *    number2);

** ****  ** *   *  **       * *    *  *** *  ***  * *
 *   *   * *   **** * *  ** * **  * **  *    ***  *  *  *   * ** 
     *   * ** ** *  *   ** 
   * ****** *  ***  **  ** ****    ** ****  * ***  *** 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* ** *      **  *  ** ** 
**  **  * ** **  **      *

int * **   n, int m)
{
** *** ***  *   int gcd,  ***** * 

 **  * * *  **   **     * (n != 0)
 *  *     ***  {
*** *   **  *  *         ** ***   ** = m % n;
 * *    **     ** ***** **** m = n;
*       * * *  *   **     * *  * n = * ***  
 *  * *    **  *  }

***  *  * *     gcd = m;

  ** * *   *   *   gcd;
}

int main (int **  * * char * *  *  {

    *  * * *  * int   *  *  ** * **
***      ** **  int  ***  * **    

 * * *  *  * * * **  **   *** ** **   ** ******* ***  * * 

 **    *****     ** = ****  /  * *  *  * ** 
 * **   * * *** ** * ** = ***    /    **       *    

   **     *     * if   * *  *** *****
* * *   ** ** **** ***    *     **   * ***    *** **
 ***   * * ** * else
**  *   * ***** * ***  * * ** *   * * *  **** * * *  **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
   **  * * *  *** **   ****    i;
* * *  ** * * ** *    *  * j;
** ***     * * *  *** ****** newNum1;
  ** *   * *   *** **    *   newNum2;
*  ** * *** **  * * **  * * *     gcd;
**  * * *   * * **** *     * * * rem;
******  * ****    *    *** num1, num2;
    
**** *****   * * *    * *   * ****    **  ** *   * *  * *  *  
   **  **   * ********  *****
*  *    * ***    * *  ** * **** *  
  * ***  * ** **** **** * **  ** 
 ** *  ** * *   * ***   ** * **
* **** *    *****  **** * ** *  ** != 0)
 ** ** *    ** *   ***   * *
  ***** *  *  **  ***   ******  *  ** **  ****  ** * *** * = j%i;
 ***** ***   *** *   * * *  * * * * ** ** * **      *** ** = i;
*  *     **      **** ** ****  ** *   * **   ** *  = rem;
    *   *  *   * **** * * * *  
 * **  * **  *      **  * *** ***
    
* **  ** *  *   *  ** *  *   ****  = num1/gcd;
 **   **   ***  * ** *  * ** *  *  = num2/gcd;
    
**  ***  ****  *  **** *    ** *  *  == 1)
 * ** ****   **      **
     *  * ** * * *  **   **  * *** * * * *** * ** * * **** *   **  **    **  *  ** * ***
  *   **** * ***   **   *  ***
    
*  *  *     **  *  * ** *
* *  * *    * * ****  *  * * **
*****  **  *  *** * ***  ** *  **  *  *** ***   * *  *    * * * *** *    **  *   * * 
 ** **    * *** *    ********
    
  *    *   * *    *     **   ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
***** *  *   ** *******      *      i;
* ** **   *    * ***   ****   *   j;
*** **  * ** *  ***** *** *** *  newNum1;
** *   **   * * * * ** *  * * ** newNum2;
*  *  *    *   **  *** * ** **  gcd;
 * ** **  *  **  *** **** * rem;
   * * **  ** **  ***  **  num1, num2;
    
   * *   *  ***  * **    *   * ******** **   *  ** *  ** ** ***  *      
    * **     * *    * * * *  *
 ***  **  * *  *  **  * *** ***** **
      * *  * **  **   ***  *
*    * *   *  * *  *  *  
* * **       * * *   *   != 0)
 ****      * *   *** ***  
  **    **  ** * *      **  *   * *     * **    * **  * = j%i;
     * ******       ****  *** *       *  *   ****  *** = i;
*   *   *** ****    *  *  *  ***   ***   ***    ****  = rem;
****  *** * * *   * * ** * *****
       ****** * * *   *   *  *  
    
* *   * *****     ***  * *  = num1/gcd;
  ** **     * * **  *** **** * = num2/gcd;
    
* *** * ****  *   ** ** **   **   == 1)
*  ****   *  ***    ****  * 
  * *  * **** **  *    ** **   *** * *  **** * *   *     *        *   ***   ** *** 
*  ** *    * * *  **  *   *  
    
 **  **** **     ** ** * *  
 ***   ** * **  ***  **** 
** **  **   *   ** ***        * *** * ** **** *  *** ** *  * *   *** *   * *
*  **   ******** ** **  **    * * 
    
*   ****** *      * * *   *** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
**  ** *  *   **  *** *   *  * * * ******* *       * *    **** 
 *** * **   * * ** **** *** **    ****   **** ** *** **** *   * ** * **
    {
    *   *  **   * **** ** * ******* *   **** *  * * *  ***       *****   
* * *  *   *  ***** **** * * ** * **  * * *   *      *   ***** * *  *
  **     **   ** **    ****       * **** *****
 ***    *  ** * ** ***          *  * *  ***
 * *  ** *   *  ****  * ** *** ****** * ***    

***   * **   *** **  *  ** *** * 
**** ** *  *****    ***    * *    *     *   * * *** *  * **** * *  * **  *   * *  *** ** *****    *** 
 *    * ***  *  *  *  * ***   *   **  **   *****   *  * *  ** ** ** ** *     * 


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
** * *  *  *** ***  * * * ** * *   a,b,GCD;
 *  *** *   ** * * ***   *  * ***  ****   *  **** *** *** ** * * ****
** ** *   *** * ***  * ****  ******
  *      *  ** *** ** * **  **
* * ***  *   **  ***********  * * ** * *** ** **  **  * * *    * *
   ********* ********  * *  ***
  * * ***** *      **    ***   ** * * ** **** *** * ******   * ****   ***    *   * * *  
*         * *  *      **  **  *  0;
}
 *  *  *  * ****     **  *** gcd(int a, int b){
 **  **  *  *  * *   *     * **  ***** *   ** *****   **  (!b) return (a);
  * **  *  ***   ** *   ** ** **     *   *** * **** *** gcd(b, a % b);
***   * * **  *** *      *     **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ****  *    ****   
#include   *   **  *  * * 

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
*  * ***  * *   ** ***   ***** gcd, remainder;
***** *     * * * *  *    ** *
***    *   ***** ***    **    (n != 0)
 *  * ****  ***     *** **   ***
**    ****  *** * ****  ***  *    ****   *****         *  * * * * = m % n;
* **** *****   **    **** *** *    * *** * * *** = n;
* *    ** ** *  *** *  *    ***  *  ** *  * ***   * **  = remainder;
* *** ** ****  ***  ***
**   * *****  *    **     * **
*    *    **  *** ****   * ** = m;
 **   * *  *  *   ** **
  *    ** *  ***  ** *** ******* * gcd;
}
int main (int argc, const char * argv[]) {
 **  ** * *   ***  *** **    * number1, number2;
* * **   **** *   ***   ***  * * newNumber1, newNumber2;
  *   *    ** **  * *
** ***    ** * * *** *** **  
*    *   *** ** * *         **  * *    * ***     **   **  ** * ***   ** *   **
 **  *   * ***  ******* * 
**  **  * * *    *******  *** ***  = number1 / gcd(number1, number2);
 ** * ** ********* ** ****  *** * = number2 /  ******   number2);
  * *  **  **  *  * ** 
 *** ***    *****  ** **   * 
*   *   ********* *     * * *  * (  *   
 *   ** * *      * *** **   *  *   * **  *** **  ** * *   *  ****** * *   *  newNumber1);
* ** **  *  ***     **   *  
** *   ***   *****   *    * 
 * **  **    *  * ****   * *    *  ***    **    * **  newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* *   *   * *** **  **     *  *      a,b,c,d,e,f;
 ***  ** **   ***  ** * **  * *      ****   * ** * * **** **    **** 
* ****   **** ** **    * ** ****  *
*  * ****** *** *  ** **    ***
**   *** ****   ** **  *  * *    
    {
**  **   *   **  ***** **   *   * * *  ** ** * *****
** * ** * * *    *  ***** * *    ***   ****** **  
 **  * *    *    * ** ***   *     * *  ** * *   **   *     **
    }
  **  * ****    * **  * ** ***  *     * 
    {
*   * *  ** * ** ******   ***** ** ***** *  *  ** * * *     **** * 
 *   * * * **** *  *   *     **  **** * **   *   * ****  ** **  ** ***   * ** 
* ***** * * *  * *     **         ****** *** **  ***   **  ** **
   ***   ******    *   * ****   *** ******  **    * * *    * **  * ***  **  *   **
    }
 **   ****    ** * *  *    **  *
    {
 **** ***** *  ***  *** *   * ****  *** *** **  *  ** **    
***  *  ********   ****  *     *** ***   *  *****  * * **    ** **   * *   * * *  * ** *
  * ***        *  *  ******  *     **    *   * ** 
*** *   **  ** * *  ***  * *  * ** ** *   ****** *  * *** * * *****  * *** ****** *
    }
  *  ** *   ** *     * * * ** * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 18.8k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 18.8k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 25k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 18.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users