11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
14.7k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 14.7k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

*  **   **   * ***** ** * ** i;
   ** * * *     * *   **  *** j;
**  *   * **    **** *   **  ** newNum1;
 *** ** * *   *    *   ** * *** ** newNum2;
*   *        *** *  *   * *  gcd;
  *      *** *** ** *  rem;
*   *** *   * **** * *** *  num1, num2;

***  **   ** *  *** * *     ** *       *    * *        ** ** **  * * * *

*  ** * ***   ** * * ***** * ** * 
 *    * ** ** *     * *  ****   

*  *** *** * *     **  * **** != 0)
**  * **  **  *     ** *   *
 ** **  ****  **   **  *  * ***   ** ** **** **  *   ** *** ** = j%i;
 **  ** ****  ** *************      ***   * ***  *   ** **  * = i;
 **          *  * * *** *   *   * **    ***   * ***  = rem;
 **  **  *     **  * **    * 
* * *****  * *  ** *      ***   

 *** *     * *   *   * ****** = num1/gcd;
 * * * *** * * *   *  *      *  = num2/gcd;

  *  *   **   * *  **    ** *    * == 1)
    {
*  *  *** ***** *** *** *** *** ** *** *  ** * *   *    **** * * ****   
    }

 *   *    ***** **  ***** ** *
    {
  *   ****     *   *    *   **** * ****** ** *  *     ** *******  *     **   * *** ****   *
*  *    ** *** *****     **     

*  * **    *  ***  *   ** * *** **      0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
  **   **    *  *  * * * *   ***  *  ******  *** *   *     ***  * *  ***

  **** **  *   ** * ********  ****    * *** 
* *      * *  ****  **     ** *  **   *    *  *** ***** ***    * * *   * **  *  

    else{
****    ** * ***   * * ** *   * *   *  ** 
    {
     ****  **  ** ***  ****    *****  **  * * *
***  *    *  **** ***  * ****    * *   *  *  ** ** **    * ****  **     *** ** *    *   *  && deno%i==0)
* * *  * **  ***      ****  *  **  **  ***** ** ** **** *  * * *****     ****  **  *   **
*  **  **  **  * ** *  *    *  **  **** *   **  * * **    ***   *  **    * *  * ** **** *****  *****
 *****  **  **** ***   *  **   *** *  *  * *  ** ***      * *    ***      **** *  ***** * **  * * *****   
*  **    * * *   *  ***   ***  ** *   **  *  ***  **    ** **   * *** **  *
    }

****  *** *  ****   ** *  *** *  * *** *  * *  
    {
*    * *  ***   * * ****    *  * * * * ***
**    **   * *  *  * * *  *    ** ***      ***** *   * ** * *  ** * *****  *  *   **   **** && deno%i==0)
** *   **  *   **   *   ****    *  * *    * *  * * **  ** * * * ** * ***** *  * **** 
 **  **    * ** **   *   * ** *       **  *   **** * **  * ** * **** * *****    **   *** ***  *  * * 
**   *  *   ***  *  **** *   ***  ** *       **** *  ***  *   **** **** * **** * *  * * **  ****   * 
     ** **  *  ****** * ** * * ** *   ** * *  ***** * ** *  ***** *** ** ** 
    }
***  ***  * ****  ****  *  * ** *** * ** ***  * * 

    }




*     ** **   *** * ***  * *** ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** *  ***     ****
#include  ** * * ****

int gcd(int n, int m)
{
***** **  * * * * *** gcd, remainder;

  * **   *  * *** *   ***   * (n != 0)
*  * ***  **  ****     * * *  
  ***  * **** ** * ****   *     * **   *     ** *** = m % n;
**** *     *** * *****  *   **  ******  * *  ** *   * = n;
***       **    ***   *   * * ** ** ** ***   **    *   * = remainder;
 * *****     ****  *** * 

**  *** * *   *     * *** *  = m;

      ** ***** ** **    **      ** gcd;
}

int main (int argc, const char * argv[]) {

* **  ***   *** * *** * ** ** ** number1, number2;
 * ** *******   ***  * *  * newNumber1, newNumber2;

*** ******* * ******      ** *****   **    * *  **  *  *    *    *  **** 

 **       *  *  *** *     *****   = number1 / *** *  * number2);
**  * ** **  **   *    *  * = number2 /  * *  * *   number2);

*  *   *  **** *   * * *  *  * * **** **   ***  * *
  **** ***** *  * * * *** **     *****    **  ****  **     ** 
    ** **   * ** * *  *   * *
 *** **     *      *  * *** * * *   * *       ***  *  *  ** 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   ** * **  ** *  * * *   
** * **  **   * * **  * *

int ****  n, int m)
{
* ** *   **     int gcd, *****  * 

  *  *   *** ** **  (n != 0)
    *   *    *  {
*  *  ***     *     * *  *  ****    **  ** = m % n;
 * ***** * *    * ***    * *      m = n;
   ** *** *  **  *  *  *   * *  n =    *  
   **  *** * * *  }

 * ***     * **** gcd = m;

**   * * *  **  *  gcd;
}

int main (int   *      char * **  {

***   *  ***    int ** **  *    
* ***   *** *  * int  *    **    * * *

*    *   ** **    *   * * ** ** **   *** *  *   * *        *  ****

*    *** * *** * **** =    ** /   * * * *    * 
** * **  **  **    **** * = * * *  / * ** ***  *

*        if  * * *     *** *  
*  ***  ** *   *  ** *   * *  ****   *         *   ** **
***   * *  ** else
*  * *       *  *  *** ****  * ***   ** * **     * * 
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 ***    ** **   **** *    *   * i;
**  **  * * *    *  **   j;
  **** ** **  *  * * **      *** newNum1;
*   ****   *   * ****     **    newNum2;
***  *  **  * *    ** *  * * * gcd;
 * ** *  *  ******  * *   rem;
*  ** ****    ***   * * *** *     num1, num2;
    
 *** *     ***  *  **  *   * ** ****      **    ****  **   **** **
**   **  *   * * * * * * * *
  ****  * ***  *   ** * * *** *  
    *******    **   * * *
* *  ** *  *   * *        **
*   * *    *** **  * * **  ** != 0)
 *** *  ***      *******   
****  *   *  **  **  **         *   * * *** * ****  * * ** = j%i;
**      *    ** * **** *    *   ****      * *     * = i;
 ****** * *  ** ** ** ***  ** ********      * * ****  = rem;
 * **  * **** * **  *    ** 
 *  ***  *  * **  *    **  ***  **    
    
*  * **  *****  *   * *  *******   = num1/gcd;
* *    *  **  * *   ***** ** * = num2/gcd;
    
  **    * **  * ******* **   *  *    == 1)
 * **   *       ** * * 
* *      ** * * ***** *   **   *      * ** *** **   *** **  *  *    *    * ** * ** 
 **  *   ****   * ** ***** 
    
 * **   *** *       **   **  
 * *** * ** **** ** ** 
  * *  *  * ****  **** *    ** *  * ****** *    *  *   * * *   **  * ***  * *   ***     *
 *  **      *  **  ****
    
    * *   * *  ******* * * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 ** * ****    ** **     i;
 **    *** *** * * *  *   **  j;
*   **   *  ** * ****  * *** newNum1;
* *  *** **       ***** * newNum2;
*  ****  * *      *  *     * gcd;
 ***  * ***   **   *  ****  rem;
** **** ** ****** ** * *  **  num1, num2;
    
*  *  *    *  * *  **  * * ***   *  *    *   ******* *      **  ***** *  
***  * * ****   *******  
**** * ** *  ******* **** * **  
** *    *  * *****    ***    *       
 * ***** *  *** *  ** *  ***
 **  * * * **      ** *   **  *  != 0)
 ***  *****   * * *  ****  
 * ** *      ***** **  *  ** * ** * *** **  * ** *  *** = j%i;
* ***  *    ** * **  ***     *** **** * * * *  **   * *    = i;
   * *  ** ***  **  *   *  ****** * *  ** *** * ** ** ***  = rem;
*   * *  * ***   **  ******
  *** *** *     * *  *   ** *** * 
    
*  *** * ***  * * ** * *   *  = num1/gcd;
  *   *  *** **  * *    *  ** * * = num2/gcd;
    
**  * * * * * *   * ******  **    == 1)
  ** ***   *  *   *  *  * *  ***
* **  *  **    **    * **          *     * *  *** ****   *    **  ** * **  *  * 
* * **  ***  * * * *     * *
    
*  ***   ***** **    * ** **** 
**     **    * * *    ** 
*  *  *** ** * ** ****** ****  **   ** *  *  ***** * *   *  **    **  **  *  **** *   
***** * *   ****  ***  * ***
    
 ** *  * *   *** ***** *  *  *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
  * ** *   ** *   **  *  * *    **** ***   *    *  ** *   *  * *  
* ****** **   *   * *  ****  * * *   ** *    *    *** **  *     
    {
* **** **** *** *      *** * *      ***    * *   * ********* **  *** *
  ** *  *  ***  * *** *  * *  * ***** *  * ******* * * ***   ** 
*    *     *** **  *****  ** **  *  ***   
**  *     * **  * ****** *  **  *  *  ** *  * 
 *   *   ** * *     ** * * * ****  ****    **  **   *

*** *  *   ****** * * *** *    *   * **
**    *   ****  **  ** **   **  **  * * *  **** *    ***** * * **   *  * *   * ***** * ***   **  *** *
* *   *  *    ***** *** * * *  ** **     * *  **  * * *   **   * ****  *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
***** ****   * **  **  ** ** * a,b,GCD;
  * **  *  ***   *  *  **** * *** *   * *   *** * * *  ** * 
 ****** ** * * *    *   **  * 
*   ******  ****  *      *  * *  
 * *     ** *       **  * ** ** **    **  ** **** ** *      *    *  *  
*    **** *    *  * ** ** * ** *
**  ** **       * * ****   **** *****  ***  **  *  **** *** *****    * ***
* *  *  * *   ** ***    ***   0;
}
* *   ***    ****  ** * *  gcd(int a, int b){
 *  ** *     ****     ** ** *   *  * * *   **** * ** (!b) return (a);
 ***  *** * *** *      *  *    * *  **   ***    *  *    *  gcd(b, a % b);
 ****    *   *****    * **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  * *  ***** ** 
#include * ****** **  *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
 ***   *      *** *     ***  *  gcd, remainder;
    * *   **     * ******* *
 ** **      * * * *    * ****    * ** (n != 0)
******  *    **** *  * *  * *
 * *  ** * *   * **   **  *** * *   **  * * **** ***   *** * = m % n;
* * ***   ***  * * *   *** *   *  ***    **     ****  ** *  **** = n;
 **  * * ** *  *   *        * *  * * * ******* *  ** *** = remainder;
 *   *   *   ***  *     *
 *  ****  **   * * * *   
 ****  **** *** *   **  *    = m;
 *  *    * *  ***    *  **
*  *** **** * *** *    ***  *  gcd;
}
int main (int argc, const char * argv[]) {
    *    *  * *  **  *** *** * * number1, number2;
  *   **   * ******** *  * ** *  newNumber1, newNumber2;
  *   *    *   ***  *  *
  *  *** **  *  *    *    * 
    *   * * **  * ****  *  *  *   *  * ** *        * ** *** ** ***    *  
 *  *   **** *  *******   
** *  ***** ** * *** *     ** *  ***** = number1 / gcd(number1, number2);
****  ***** * *  ********     ***** = number2 /     ** *  number2);
*** ** * * *   *  **** ****  *
*  * **  *   *** **       * 
*   *   **  ** * *    *  **    (  **** ** 
  ** * * *  **    * *  ** * *** *  **  *       *  *   * ***** *  ****  *  newNumber1);
**      **     *  *  *** *** 
** ** *** ** **  ***      * **
**   * ***  ****     *** ** * *********   * * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
  ****** * ****   * *   *     a,b,c,d,e,f;
 ***** ** *      *  ** ***  **  *** *** * * ****     * * * * **  
  ** * **  **  **** * * ***
 *   ***   * *  *** *  **  *
 ** **   * * * **** **    ** **   * **
    {
 * ****   ****  ** ***  * **   **   * * ***          
  *  *  ** *    ***  ***        * *  * *   ** *** * **  *  
*  *******     ** *        *****  **  *   ****** *** ****     
    }
 **  * * * * ****** *****   * *   **   **
    {
* * *     * *    * *  ** **** *   ** *  *  ** ******* **    *   
* **  **** ** *  *  ***    ***  ******  ** *** ** *  *   *   **  *  * **
  *****  *** *    * *  *        *  **** **  ***  *  * 
* *  * *  *****   **  ** ***   ****   **   **** ****  *** * *  * *  ** ** ***  *
    }
******      * ***  *  *  * ****
    {
*** ** * * ** ***      *   *  * *   **  * **** ****    **  * *
    **  *****   ** **  * ***    *  ***  *** **  * * **  * **  * **  *** 
    ** ***  **  **** * ** ** * *** *   *  *** **
  ***** ******** *  ******  *  *  * * ** *  *     * ***** *    **  *    * ** *** 
    }
* **  **     ** ***  *  ***  0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.51
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 15k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 14.9k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 19.3k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 14.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users