11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
10k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 10k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

***  * *** ** **   * **   *****  i;
 *  ***  *    * **** ** *** *   j;
** **** *   **** ** **** newNum1;
***  **    ****    * **  **  * * **   newNum2;
* ***  ****  * * ** ** *  gcd;
***    * *  ***   *      ** rem;
 **   **  * ****  **** * ** num1, num2;

*   * * *  * *  **    **    *** * ***    **     * ** *   ** *     **

 ***  ** * *  * *  *  * **
****  * *   ** ** **       *  *** *

 ***  **   * ***  * *  *  * ** != 0)
*  *  *     *   ** *  ****  **** 
 * * *  * *   *       ** * * ** *  *   **  *   **     *  = j%i;
**    * **  *  * ** *   ** ******  **  ***  ***   ***   = i;
*  **  * * ***   ** ****  *    **  * * ***  *  * ****   = rem;
***  *** * **  *        * *  
* * **   **  * * **    ***

    * *    ** **    **    *  = num1/gcd;
*** **  ** * ** *   ** *  * = num2/gcd;

      ***   **** * ** **  * *  *   *** == 1)
    {
*** ***  * ** *  *   *  * *  *****  ** *  * ** * *****  * **  * **  * *  * *
    }

    * *  **** * *** ** **   * 
    {
  *   * ***** ** *  ** **  **  *** *** *** * **** * **  ****    ** * ** **  * *   * *****  
**** *** * *******  *** *  *** *

  *  ****** * * *  * ** * *** *   * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
**  **  *    * * **    ****** ****    ****  * * ** * *  *

 * **  * * ***** **   ***   ** ***
   ******   ****         **   *     *  ** ** *    *  *        *  * * *   * ** ** ***  * * *

    else{
   *   ********  **  ****      *  ** *   *
    {
*  **     ****  * **** * *   *    * *     * *  
**  ****     ****  * *   ***  **  ** ******  ****       *  *** * *    **  *** **   ** ** && deno%i==0)
****   ****** * *  *** ** ***** **  *  **      * ******* * ** *  * * ** *   * 
 ** **  **** *  *****    *   *  * * * **  ***   **** * * **  *  * *  **  * * *  ***  **** *   *** * *   
     * *   **   **  ** *  **** *  *   * * * ****      ***** **    **  **  *  *** **  *  * *   * *  * 
* * *   * *  * * ****** * * * *  **** * ******  *     **  ***     *  ****  
    }

*** * * *   ***** *   *  * * *****  *
    {
 **** *    *   ** * *  *****  ****   ***  
* **   *   * *** **** ****  * *  ** **  ***** *   ***       **   **  * *  ** *** *   *  && deno%i==0)
 ****  ****  *    *     **  *  ** *** *  * **  *   ***        ** * * *  * * ***  * *** * * ** 
 * *  *** ** * *  *****  *   * *  ***** ********    ** *  *   ** * *    ***   *  * *   ** ** *   *   **
*** **     * *****  *   * *  * ** **** **         ** *  ***     ******  *   * ****  * ****   *  * **  *  *** ****
*** ** * * **   *  **  ******* *   ***  * *****   * ***    *** * **    *   * * * 
    }
 *   * *    *     * *** **  * **   ** **** **    **    * *

    }




*    ******  *** * ***  *    0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **    *       *   
#include ** * **  ** * * *

int gcd(int n, int m)
{
*  *****  **** *   * *  ** gcd, remainder;

**   *    ** ***  *     **   * (n != 0)
  *  *** * ***** *  ** **   
   *** ***      * ***   **** *  ** ***  * **   *  **********  = m % n;
**** * *  **** * *   * * ******** ** *  *  *   * ** **** = n;
 *    *   ***  ** * * *     **   *** **  ** **** * = remainder;
** **  *    * * * **** *   

 * * *  *   *  ***   ** *** **** ** * = m;

**  ****  ** **  *** * ** * ** gcd;
}

int main (int argc, const char * argv[]) {

***  * *  *   **  *  **  *  number1, number2;
* **** ** *  ** **** * * * newNumber1, newNumber2;

 *   * ** *  ** *     * ***  **  * *   * * ****  ** **    **** ****   **  * ** **  **

*** * *  **  **** * **  *  *  ***    = number1 /  *      * number2);
* *  ** * * ***        * ****   * *   = number2 /  * ***  number2);

     * *   ** *  * *         **  **   *  *  **   ***
*  * * *    *  **  *** * * **   * *   *****     *      ***  
****  **  ********** *   * *
 **  ** ** * * *******  *** *  ** * ***  * **   **
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** * ** * *   ***  ** 
**  **      *     *  *

int * **   n, int m)
{
 *  *   * ****  * int gcd, *** 

* *  *     ** *     (n != 0)
* ** * * * *  ** {
  * ***  *** *  *   ** *     * *   * *    = m % n;
* ***   * * *   ** *  * *  ** ** m = n;
*** *  **  **  **  ** **   **  * * n = *    **
*  ** *   ****    }

     ** ** gcd = m;

***  **  **    *** gcd;
}

int main (int **  * char *     {

   ** *    **    int   *  **
    **   *** ****** int * * * *   *** ***

 * * * *  *    ***     *  ******* *** *   * ***  **  **  ** *   ** 

   *  *  **** *  * ** * =    * /  **  * ** * * 
* ** * **   ** * *  **  = * *  /   **** *  *   * 

* **  ** * if  ** * *  ** ******** **
 *    ** * * *  *   *  **  * * **        * *  *  **** * *
*    * *  * ** else
*** * * ** **   *     **     **  *******    *** *   * 
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 ** *   ***  * *   * * *****  i;
* *     * * ** *  *  **  **  * * j;
* * * *   * *****  * * **    * newNum1;
*** ***** *   ** **  * * **   newNum2;
** **  *  *  *** ****** **  gcd;
    *  *   *** ** * ** *  * rem;
 * ** ** *****  ** ** * *  num1, num2;
    
 **   **  *** *   * ***   * **    **** ***  ***     *  * *** *  *
*** *      ** *     *****  
* **    * ** *   *   * 
*   *** *** * *   ** **  **  *  *
   *     **   *   **
* ** * * ******* ** ****  *******  != 0)
 **  **   * **     * * **   *
* ***  * *    ** ** ***  **  *  *****    * ****   = j%i;
 *   *** ***   **   * *  ************ *  *        = i;
  * * *  *  *   * ******** ******   ** * *     ***  ** * * = rem;
* ***    ** ** * ** *  *
** *  ** **** * ***  * * ** *  *
    
   *  * ** * ****    *  * * * * = num1/gcd;
      ***   * *     *    * = num2/gcd;
    
 *  ***** ****   **  ** **** **        == 1)
 *   *** *****  **     ** * *
 ** * * * ***   *     ******* ** * *  ****** *****   *** ***    *     *     *
 ** **   * * * ****     *    *
    
 **** *  * * *    * **   **
* *  *   * *   ** *  * *  **** * 
***** **   * * **    ** ** ** * * *  **  ** * *   * * **  **  * **    *  ***** * **   *****
  *** * * *** **  *   ** **** 
    
 **** *  * **  ** *    **** **  0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 **** *****  **    ** ** *** i;
***  *  *********  ** *** *   * j;
**  *   *   *  * * * * *   * newNum1;
 *   *  *** *** ** *****     *** newNum2;
   ****** * * *  *** *   **** * gcd;
 *   * ** * *    ** * **** ** rem;
** *  ****   ***** *    *  num1, num2;
    
 *  ****     * **  *** ***    *  *     ***  **  * ** ***  * * **
* **   ** * * *** **    * 
* *      ** *******  ***  *     
** **  * ** * * *     * **
 **     * ***   *  * *     *  *
 **** *   * ** *** ****  *  *** != 0)
    ** *  *** **   **** ***
 *    *****   *** *   * *  *  ** * * *         *     ** = j%i;
 * * *  * *  *   * ** *   *  ** * * * ***     *   **  *   = i;
****** ** ******    * * ** *  *   * *** *  * * *** = rem;
 ****       * **  *******   ***
** * *** *  **       *  ****    
    
***    **   *  * * ****     ** = num1/gcd;
**  *       *  ** ** ***   ** *    = num2/gcd;
    
*******      *    *  **  * *    == 1)
 *** * **  **  * *   *  ** *** 
** * ***  * *****  ***  * *  *** ******** *** **   * *** ** * ****** ***    **  *
**** **** **** * ***  *** **
    
 *** *  **    *  **  **  
 * **  *  *    * *** **  *
***  *  *   ** ****        *   ***   *    **  *** **  **  ** *    * *   * *** * *
*  * * * * *** ** *** *  ***  
    
** *   **  ** ***   *** **  * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* ** ****  ****   *   **  *  *** *  *  ***      * *    * * *  *      *
  * **   ** * *  *   * ** ** * * * * **** *  ***  *   * ** **   
    {
 * * *  ** * *  ***  * *** **  **   *     *** *   ** ** * *  * 
* * *****   *   ********   *** *  *  *  * ******  *** * ***
**********   **  * **  *   **  *****  
* * * ***   *    *  * * * *** *   * *** 
 ** *  * ** * * *** * * ****  *  **   *  **

 * *****  *    **    * ****** ***
  ** *  *   **   * ***  **   ****      * * * *  *     *   ****   **   ***  *** * * * *     ***  ****  *  ** *** *  * 
* *  * ***    * ** ** *  * * *  ** * *   **      **   *   *    * *** **  ** *  


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
 *  *  ***   **   ** * ** a,b,GCD;
    *        * ***    **  ***    ** **     ****  **  * * **  *** *
* * *   * * * * * *** *  *  *  *
*****  ***  * ****  ******   * *
   * * ***  **   ***   **   * * *  *****  * *  *  *** *   *  *********    ***  *** *
***** *  *   *  ***   *   ** *
   *  *  *** ***  * ** *  * ** ** ***  **** **  * *    * * * ****       * *
*   *  * **** ***  * *  *    ***  0;
}
   **    ****    **  ***  gcd(int a, int b){
   **   *   * ** ****  * **  *  ** * * *  **  * **** * * * (!b) return (a);
   * *  **** *** *** *  * *** *  *** ** **    *  **  *  gcd(b, a % b);
  ******** ***** ** *****  *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** * * ***    **
#include *    *  *    ****

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
*    **  *  ***  **      **  gcd, remainder;
**  *  **     **** *** **
****   *     **  * **   ** ***  (n != 0)
*   *** *           ** *   **
*  ****  *   **   * *  ****   **  * *    **  *    **  *    *** * *** = m % n;
 ** *    *** *     * *    ** * **** * ** *  ***   * = n;
  *** **** *    *** ***   **   **  ** *** **  ***  *     * *   = remainder;
 *  * **   ***    * *   * * 
  * *** * * * ** * *   * *** 
* *** * **   **  **  = m;
 ****    **** * *  *  **** *  
* ***   *      ** ** * **   ** *  * gcd;
}
int main (int argc, const char * argv[]) {
* *    * * ** **  **  *       ** number1, number2;
      ****  *  **  ****  * *   * newNumber1, newNumber2;
  ** * *  *  **   ****  *  
  *        *** ** *   ***  *
  **      *** **** **   ** ***  **** ********  **  * ** * ***  * *  *  *
    *     * * * * *    **  * **
**     * **    *  **      ** * *  *  *  = number1 / gcd(number1, number2);
    *    * *    * ****      *******  = number2 / * *     number2);
**** ***   ***  ***  * 
    **  **  * ** * * * *   
  *       * ***** *  *   ***   ( *     ***
* ** ** **    ** * *   ** ** *********    *       * **  *  * **  *  **  *  newNumber1);
* * * ** ** * ** *    ***     
 **  ***  ** ** *  ***** 
 ** **  * **     * ****          **     * * **  ** *   newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
     * *****  ** * **  * * *  ** a,b,c,d,e,f;
 *** *** *   ** ** * *  * * **    * ***  * ** ** * * ** * *   *
 *      ******** * ******   
 *  **********     *  ** *     
   **    **** *        ***** * * * 
    {
* *  ** *   **** *   *    **   ****  ***** **** ***   ***
* ***     ********  * *  ***   * * **  ******** *** * ******* ***
   ** * ** ** ***  *   *     ****  **** *   * *  *** *   
    }
 ***     **  * ****   *   *** *   **
    {
  ****  * *   *   ** *  **** ***   *** *  *** ** ** *** * **
*  *    *        **** **  ** ** *  *    * ** * *  * ***  ** ***    * ** ***
  **    * * **   *** *  ***  **   **  ******* **  ****  *  * ** 
  *** *   ****   * **    *** * *   **** **     **   *  *  **** *    * *** * *  **
    }
 *  *     *  * *** * ** * *  *****
    {
*** * ****  **  **** * ****    **  **  **  * *** * *  * * * 
* ***  ** * *    ****    *  * ***     *    * ** ***      **     * * *  *** * ****
** * *** **  *  * *** *      * *  *  **   *** * * *** *  *
  ***** *   **  **** *   *   *  * * ***     * * ** * ** **** *  *********  ***  ***   **
    }
**     ** **   ** *   * ***  0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.151
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 9.9k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 9.7k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 12.3k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 9.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users