11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
2k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 2k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

*** *  ** ***** ***** **  *    i;
*  *  * *   * * *   * *  *   j;
*         **     *** *     *** * newNum1;
* ** *  * *      *   ***** ** newNum2;
**   ***  * ** ** **  * **  *  gcd;
   * *     * * *****   * rem;
* *  * ***** *    **   **     num1, num2;

* *** ***    *     **  **  *  *** * *  ***** ** * ** ** ** * **  * *

*   *** *** *   * **  ** * **** 
* ** * ***** **   * * *** *     *

**  **   **  *  ****** * **  * != 0)
   **** **  *  *  *****  
  **  ** ****  * *    * * **  * ****** * ****  **    *   * = j%i;
*    *  * ***  *  *** *  ****       **    *  *  ****** = i;
*  *  ***  ** **** **  ** * ** *** ******  ****   *  = rem;
  * ***      * * *   * ** 
*   ***  **** *  * * * **  * * 

****   **** * ** **   **** * ** = num1/gcd;
*** *  **  ***    **  * **   *   = num2/gcd;

**** * *  ** * * *  * * * *  * * == 1)
    {
  **    * ** *    * ***   *  **    **********   **** *      ***** *** ** *  *    * *
    }

   ***  **  **** *   ****** **   
    {
**    ****** ***  * **** *  ************      * * ** **   **  **  ** *   **  **   **** *
* ** ** ****** ****   *    

  ****  **      * ***   * ******* ***  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
 *  * ***** * *  ** * *********  **   * * *  ****  *   ** *  

      ***  *  * * *** **  *       * 
   *  * * ** *  ** **   *  *    ***  ******* ** *  *  **   ***   **    *  *  

    else{
*    * **** **  ******* * * * *     ***
    {
** *** ** *** ***  **   **** **   ***   ** ***  * 
**   ****   *  * ****  ****      **  * * **  ****  *  **  ***  * * ***** *** * ** ****   && deno%i==0)
 *  *  **  ***  * **** *   ** **      *  **  ****  *     *  ** *   ******* ** ** 
 * * ** *  *    *** **  * *******  **     **  ** ****  ** ***** ** * *  *   *  *  **       * *** *  ** * 
****  * * *  *  **      ************ * *  **  * * *  ***  ** **** **   ** ** *    **  ***   *** ****  * * ** * 
* **  **   **    *     * * **  *****   ***  * ** * * ***  *  * * *****  *  *  *   **   *
    }

* *** **  ** * **   **** **   **  **   * *   **    *
    {
 * *   **** ** **  *   *   **   *   ** *** 
  *   ********** **   *  ******   * * * *    *  *  **   *         *   ** ** ****  && deno%i==0)
 * *  *  *   ****  *    * *     * ** *  ** ******   *   * *   ***** *** *  ** ***
 **   * *    * * * *    * ***   *****  * *  ***** * ***   * ****** **** *   *      ** ** * * *  **
 * *   *  **   *** *** *   *    ** *  **  *** * *  * *  * ***** *  ** * *** *   * *   *******      *  **
* **  ** ***     *  *   *** *  *  * *          *  * *** ** ***  *    
    }
****** *** ** *       * **  *** * **  *    *** ** ** *****

    }




*****  **** ****  ***      *** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** ** * **    *
#include    * *    *** * *  

int gcd(int n, int m)
{
 *** *** ******    * *  * * gcd, remainder;

* **    * **** ***   ** **  **    (n != 0)
     ***  ** * ***** *   ** * * 
  **    *** *  *  **  * ** ** *    *  *   * ***** * **** *** = m % n;
  **  ** ** * ** **    * * ***** *     *  *****  *  = n;
*   * * ** ***              *** **  *** ***     *  * **  = remainder;
* *  *  ***  * *   *   ***     *

* *   ****** ***  ** **** * ****  = m;

 ***    * ***** * * **    ** ** gcd;
}

int main (int argc, const char * argv[]) {

***         *  *   ****   **** **  number1, number2;
  * *  * *  ****  *  ** ** *** * newNumber1, newNumber2;

* ** *** **  ***   **    * * ** *   *   ***    * *     **   * **  * 

   *    * *** * *  * ***    = number1 /   *    number2);
* * *   *      * ***** ***      **  * = number2 / *  ** ***  number2);

* *** ***  * * ****   ** * * *     * * **  * * **
* ***  * * *   ** *  ** * *   ** ****    ******  ****   *****
  * **  *  ** * * *   ***** * *
* *  ****  *   *****  **      *****  *  *     * 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
     **  ** **   ** ** *
** ** *  *** * *** *** *

int ** * n, int m)
{
 **  *   ** * int gcd,      * 

 ****    ***   *  *** (n != 0)
*  * *  * * **  {
  ****   ** *  ** * **  *  * *     *   * = m % n;
*     ** * **  ****    *   m = n;
**   *    * *** *  * ** *   * n =     
* * **  ** *   }

 *  **    *   * *  gcd = m;

   * ** *  * ** gcd;
}

int main (int   *  * * char *  *** {

*** ** *  **** ** int *      ***
 * **   *  * * int * **  ***  *   **  

 ** * *    * **  * ***  *** *   * *    *** *       *** ****

 *** * * **   *    *   ** = *   * / ***    ****** *
* *   *    ** ***  * * * *  =    **  / *** * * ******** 

* * **   *** * if ** ** *  *  *  *   **
   ** * **  * ***   * ***** *****   ** * *  **  *  * *  **  * ***
  *  * * *** ** else
 ***  *   *** ** *  *** * ** ** *****  **  *  ** ** *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
* *     ** *   *** *** **  * ***  * i;
    ** *  *  **  *   *  *  **    j;
**  **  * * **  * ***  ***   * newNum1;
*  * * ** *   *    *** ****** newNum2;
    ** ***   * * * ****  *   *** gcd;
*   * ***  *  * *** *  *** rem;
**** * *  *     * **   *  num1, num2;
    
*  ***   *  ** **    *  ***   ** * * *   ****   * ** * ***  *  * **
*   * ***  **   *  *  *    ** 
      * ****   *    *  ***   **  
**** ***  *****   ****       ** 
* *  **** *  ***  * *****
 * *  *      ******  **** **        * != 0)
*    *  ****   *   *  * *
*  **  ****  ***  *   *  *          * *   * *   ****   = j%i;
  **   ***** ** ******* *    **** ** ** **** *    * = i;
**  ****** *** *   *   * * * *  **   **** **      * *** ** = rem;
  *  *   **** **  ** **** **
   * *** **  *** *   **    ****   
    
  *    ** * *** **** ** ***  * **** = num1/gcd;
* ****  * *      ****  *   ****  *  * *  = num2/gcd;
    
    * ** ** *  * *** *  ** ****** == 1)
 **  **  *** ****** **  *
** ***       *   * *    *    * *  **** * *    * * *    ***  *     *      *  
 *  *  *   * **   * **** *
    
 ** **  ***  * **** * * 
*** **** ***  *    ******* 
***    * *    *** * **       **  * * *   ** ** ** * * *   * ** **** *** ***  *** * ***** 
**  *  ******  * **  *** * ** **
    
 ** ** **** **** *      ** **    0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
**** * *      *  *  * *  ** * i;
 **           * * **  ***   j;
 *        ***         * * *   newNum1;
     *  ***** **  *  **   *   * newNum2;
* **  *  *   ** *** ***      * *  gcd;
*  *    *   **  * ***    ** rem;
* * * * *  * * ** *  * * * * num1, num2;
    
   **  *   *  * *  *  *  * **  *** ****  *  *   **  * * ***      *
* *    ** ** * **** *   * 
*    ** **  *   *    * *  *  * *  
 * *    *      *  ** ***   ** * *
**    *     *****  ***  * * * ** 
* *    * **   ** * *  *  **  != 0)
*      ***  *   * **  * *
     * *  *     *  **** *  **  * **   * * ***   *** *   * ** *  = j%i;
   *  *  ** *  *    **       *** * *** * ****  ***   * = i;
  *  *  *  * **   **  *  * **  *  **    *      **  *  = rem;
*   * **  *   ** **    *
* * * ****** *  ***** **      *   
    
  ****   *  * **** ** ***** *** * = num1/gcd;
 * ** *  ******  ****  *****   * ** = num2/gcd;
    
     * *   ***   *     ** **  *   == 1)
 *  * * * * * **       
 **  ** * ** * ***     *  ******    ***   *******     * *  **     **  *** *****  
 *  *** *** * **  * *   
    
**** ** * * **  *  **  ** *  
*   *   ** ** **  **  * ** 
**  *        *    *   ** *    *****  **  ******* ***   *  * **  *  * ***  * ** **  ** * * *
 * * *** * * * *     ** 
    
 ***  **  *** *** ** **  *  **  **  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
  **  **** * *** *  ***** **** ** ** * **  *  *** * * * *
******   **  * * ** **   *** * *  * * * ** **    ** **  ** 
    {
  ** *    **  *     *  **   *  ** *      * ****     *   * ****  **  
  *   ** *****   *    *   *      **** ** *      **  ** * ****
**** ***  ***          *   *** ***    ***** *
 **  * **   *  * * * ** * * * ****  ***     *** * * 
* **  * ** *  * ****  *  * *** **** ***   * **

**    *   ***     **  *  * *      *
*  ****    *  *  *   ****  *  ****** ****** ***  ** **** ** **** * *   **  * * * *   *  * *    ** *
 **  * *****  **     **  * **** ** * **   *     * ** *   *  ** ** * *  ******   ** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
**  ***** ****    * **  a,b,GCD;
    * ***** *** * * ***  *** *   *  * * * ****   **  ** * * *  *** * *** 
  * ***** **********  *      
 ** *    * * *    * * *     ** 
 *  **  **  ***  *****     * * *  ** *  * *     *  ** ******  * ***  **   
   ** ***** ** ***** *  * *   *
*** * ***  *      ***** * *  ***     ** * *       *** ** *    ***  **
*  *     * **  *  **   **      **     0;
}
** *  *   ****   *  **  ********  gcd(int a, int b){
*******  ****       **   * *  * **   **  * *** *   *      (!b) return (a);
 ** * *  ** *     ** * ***** *     *** ***    ****  gcd(b, a % b);
 *     ** ** **  ** * * *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  ***  * ** *** 
#include     *** ** * *** 

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
*  *** ****    * * *  *** gcd, remainder;
   * *   *** ***  ** *  * * *
 * ** ******** * *  ** * *     (n != 0)
 * *****  * * * *  ** **   
       * ***** *** ** **   ***  *** *  * * *  *****   * * = m % n;
   *   **  ** *    ***** ** ** * * ** * ***  *     ** **      = n;
* ******   * ***  * ******  *** *  *  **         * * *   ** = remainder;
  ******* **** **** *** *** *
    **  **    *   * ** *** ***  
 *     *    ** ** *    *** * *  *    = m;
 *    ** * *   **   *  
  * *   *  *  ****  ****** * ** ***   gcd;
}
int main (int argc, const char * argv[]) {
  **** ** **  *  * * **** *** number1, number2;
 **      * ****  *  * *   *  *   *  newNumber1, newNumber2;
*  ** ****** ***      * **** **
 ****   **  *  *     * ** **   *
**  ***   * *  *   ** * *   ***     *  **  *** **  ** ****  ** *****  
  *   * *   ****  *  *  **
 ** *    **  *** ****   *   * ***   = number1 / gcd(number1, number2);
***     *******  *    *      ** *   * *  = number2 / *  *   ***  number2);
*** *****  *    ***   * 
**   * * * * *  *****    *
 *  ***  **  **   *  * * **   ( * ***   ***
** * ** *  ****  *** ** * **** * *****        *  ** ******* **** ** * *** newNumber1);
 **  ** ********* *  **     * 
*  ***    * * ***** *   * *
 **    *  **** **   * * *** * **  **  ***    * ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
   * * * *  * ** ***      **** *   a,b,c,d,e,f;
* ** ** *  ***** * * ** * **** * ****  **  ******   **** *** *  **** 
*     **    *  *   *** * *** *** 
** ****      *  *  *** * 
** *  *   **       **  **   *    
    {
 *   * * **  *** *  ***  **  ****    *   *   **  ** *  *
*   *** *   *    * *  **** *  **   * * ********* *** **  
*   * *     ** **   **** **  ** * *  ** * *** ****** ** ** 
    }
    *   ** *   ****   ** ***  * * *  * 
    {
  ** * *     ******* ** * * * * *    * * **    ** ****   ****
 *****  *  ** **  *   ***  * ****  * *   * **  *   ** ** **  ** *  **  ** *
*   ** * *** **********    *  *      * **  * * *   
   * * **   * *    **   *  ** ** *  ** * * **** * ***** **  * *** *** *  **   ******
    }
 **   *   * *  * * * *** *****
    {
        *  *       ** *    ** ** ** ****  *  ****   ***   *
  ** *   * ** *   **  ** * ** ***  * *   ****     ***        * ** **  **  * ***
* * *   *    *  ** **  *  **  *     * *  * **  **** * **** * 
**  *  *     ****  **** **   ***  * **    *    * *  * * **  ** *** * ** *     ** 
    }
 ** **** **  * ****  *   *   * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.101
©2016-2024

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 2.4k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 2k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 2.6k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 1.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users