11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
11.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 11.9k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

*  ** *   **** ** ** *    * *  ***  * i;
     * * **  **  **** ** **  j;
 * ** *******    *** * * *** newNum1;
*  ***    *   * *   *** * * newNum2;
 *  ** * * *** *  ***  *** gcd;
** * * ** **  * *    ** *** rem;
 **  *     * ** *  **   * *****    *  num1, num2;

**      * *   *  **    *** *** *** ** *  * ****    ** *** * ****

* ***** * *  ***  ***    *** ** *
 ** * *     * * **     *** ***

  * * **** ** *  * *  **    *  != 0)
 *     *    *****    *** **
 *  ***** *    *****  *   *  ** *  **   *** ***   * *  *      * *   = j%i;
*    *  * *   *  ** *    * * **   ****   *  *** * ** = i;
*  *     * *    **  **  * ***    *     ** ** *** **    * = rem;
*   **   ****    ****   *
*** * *** *  ***** * **  ****

* ***  *  * * * * *     * **   **** * = num1/gcd;
 *   ** *     * ***  *    **    *** = num2/gcd;

 * ***  * ** **   * **** * * **    == 1)
    {
*** **  ** *** * * ** ***  *      ** **     ***   *    * *   *****  **  ** **  
    }

 ****  **  ***   *  *  * * **  ** 
    {
*  *  * **    ***    *  ******* *  *  * **      ****    *      * *    *** **** * * *  * 
* * *** *   ***** *******

** ****  * ****   *    *  *** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* ***** *** *     **     ***    ********** ** * * *        **** 

***     *   ***    ***  * *  ******* 
     **** **   ***   *   ** ****  * *** * * **      ** * ****** *** ******** *   ** *  *

    else{
 * ** **   **  *   **  **   *** * **** * 
    {
 ** ********* *    ** *   *   **** * * *    **
  **  *   **  * ** *****  ******    **** ** *** *   **  * *  *  * **      ****    *  ***   * && deno%i==0)
     *** ***   ** *** * * *  *  * ***  *  *****   *****  ** * * ** ********
*****     * * * * *** * * * *** * *  **   *  * ***     ******** **   *** ***   * *    * *** *   * * *** **  *       
 *    **  ** * *     ** * *   * *** *** *   * * * *     ****  *   *  *      *  **** * ** * *    **  * ***
  * * * *  ** ** ** *     **  *       ***   ** * * ** ** * *   * * ********** *   *   *
    }

 ******** ***    ***   *   ** 
    {
**  * ****   * *    *  * * *   *** **  * 
*   **  *  *   * * ** * **    * *    *     ***** * ** ** ****    * ******  * *  **  *** * *  * && deno%i==0)
 *     * *  *  ***     *   *  *   ** *  *  * *    ** *        **  ** * ***** 
 **   *  * *** *     *  **** * * ** **** **    **  *  *  *    * **  **  * * ******  ****** *  ** **   **  *   
  **** *  * *** ** *  ****   ***      ********   ******  **       * *  *  ****  *  ***  * ***** 
  ***  *** * * * *  ***  *  ** ******* ***** *  **  ****** * * ********  ****  * ** ** * * * 
    }
*  *   **       ***** ** *****   * *  *  *** ******   ** 

    }




**  *  ***  *   ** * **  *** *   ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *** * * * **** * 
#include   *** ** *  * * 

int gcd(int n, int m)
{
  * *   *** ** *     *  ** gcd, remainder;

* * *  * *** *  *  * * * *  (n != 0)
  * **   ***     *** * * ***
*  *   * **   ***   ** ** * ****   * **    ** *  * *** * = m % n;
**  * * *  *    **     **    * * ***** *   **    *   * = n;
   *  * ** *  * * *  * * ** * ** ** ***  * **   ****** **  * = remainder;
* *   **  *******  ****  ** 

  *      ** *****   * * * = m;

**   * **    ** ** ** **  *    *  gcd;
}

int main (int argc, const char * argv[]) {

 **    *      *  * *  ****   number1, number2;
** ** *    **  ** * **   *  newNumber1, newNumber2;

*    *  ** **  *   ***** *********  * *** ** *   ** * **   ** **    **  *

* *** *  **  ** ****  * ** ** = number1 / * * ***  number2);
*****  ** **      * ** ***  ***  = number2 / ***    *  number2);

* **      * *     *  ** **   * *** **     **   ***
 * * * ** ** * * **  **   *** ** *** *     **** *   ** *    ***
* * ****   **  **    ** *  ******
*   * *  * *  ***  * *** *    ** **  **   *** *   *  *** ****
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ***  *  **    ** * *
 *  **  * *  * * * **

int *  ** n, int m)
{
   *   * **     int gcd,  **** *

 ** **     * *   * (n != 0)
*  ******     *** {
**      *** * ***    *  * *   * *  * = m % n;
**  *  **   *  *  ***   m = n;
*  *  * ***  *** * * *  ***  n =  *  *
* *  * *    * *   }

 ***  *** *** gcd = m;

 ***     * * *   * * gcd;
}

int main (int * **  *     char * *   {

 **    ** ******   int  ** ** **  ***
*  *****  * ** ** int **  *  *  *** *

  * *   **** **  *  ** ** ***  *        * ** *  *****   *  **

 * ****    * *  * *     = *  *  / * * *   **  *
    ** ** *   *  * ** = **   / ****** * *  ***

  *    **  ****  if  *  *  *  ** * **
  * *      *     **      *  * * **  ***  * * * * ****
***     **  *   else
*  ** **  **   ****          *  *  *****  **  *  * ** *  
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
** ** * **  * *   ***   * **    * i;
*   **  ***   * *   *   *    * **  j;
     **** *  ***** *** ****    newNum1;
 **     *     * *** *  *   ** newNum2;
*  * *   ****   ****   ** *  gcd;
 *  * ****    ***** ***  **  rem;
* * * **    *** * * * ** *    num1, num2;
    
    ******    * ** * ** *  *** * * * * *  ***    *  *   * **  * * *
 *  *   * * **  **   * *  *  
*  ** *  *  * **   ** **  **** 
*  ** ****   ** **    * ***    
  **     * ** *    **
      * ** **   **       *  ** * * *  != 0)
 ****** * **** **** **  * *
*** ** * **     **** * * *  ****   **** * **  **    = j%i;
***         **** *** *   ** ** * ** *   *   *  * * * ** = i;
**  *     * *  **** *  *  *** **     *    **  *     **  *   = rem;
** ***** ***  ****   **  
*          *  ****  *    * *   **
    
* * * *  * *  **   ** ***  ******** = num1/gcd;
**   **** **    * ***  ***** *  **  * = num2/gcd;
    
*      *   * ** *  ****   *   * * * *** == 1)
  *     *   *  ****    
* ***     *  *  **  * ** *  *     * * * * *   **** **  ** ***  *     * 
  *  ******  *  *** *  *  *
    
 ** **   **   **** *     ** * *  
 **  *  **     *    *   * *
 ** * * ****     * *    *  *** *  ** *** ***  **    ***        ** * * *** **  **  *
* *    *  * ***  ** **     **
    
** *  ** **   * ** **    0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
**** * * *** ***      ** *   * i;
 *** * * ****  ** **  **    *   j;
*  * *** ** ** **    ******    **** newNum1;
 ** ** **     *****  *****  newNum2;
    *    **  *        * * * gcd;
*  **        *   ** ***     *   rem;
 * **      **    ** *** *** *** *  num1, num2;
    
  ** ** *** *     ***** **  *** *** * ***    *    *  * * ** 
 * *   *** * *     **** * *** *   
*** * *** * ** *  **  **** * * *  *
 *  *   *  *********** **   * 
********* ****     *  **  ***  
*   ******* * *  * *  **  * *  != 0)
  ** ***  *  * **  *  *   
 ****  *  *    ***   ** * *  **  **  *******   *      = j%i;
   * *    *****   *  * **  * ** **    *   *** *    = i;
 *** **  *** ** * * * * *    ** **  **     ***  *  *  * = rem;
** * ***  *  *   * ** ** *** 
  *  **   ** *** *    ** * 
    
  *  ***** *  * * *  **   **** * = num1/gcd;
 ** *  *** ** *  *   ***  **   = num2/gcd;
    
** *** ***   ****  * ******  == 1)
   *   * **  *    **  *     * * 
***** *  * *    **  *  ** *    * *** ****  *      **  *  ** ***** *   **** *    *   *
 *   ***********  *
    
*    *****   ***   **    *     * *    
 * *** *     *  *   * *
** *** **** ***    ** ********   ** **** * **   * * *   *     * * ** ** ***  *  * ***** * 
  *** *      **  ****  **** **
    
  *  *    *  *  ***** ***** *  **   0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
*   ***    **     **  **   ***  *      ***  *   ***   * *****   * 
***   **  *   ** *** *   * * **    ****   *  *** *  **  **  
    {
** * *****   *   * *  * *     **  * * ** **  *    ** *  ****  *   ** 
**   *****          **    **   * *** ** * * ** ** *  * * * *  ** *   
  *   *   *  *  ***  *   ***** * **    **
* **   *  *  *  **   **** ** ****     ** **
  *** ** * **              *   ** **    *  *  ** *

** ** *** ** ** ***   **    *  
    *** * *   * * ** * *** * *  * **   * * ** **** *** * **    ** ****  **  * *    **   * *
* ***** * *   *  *    *** *   * * *     * **      *  **  *   ** ** *   * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
  *  **  *   ***   * **  ***  a,b,GCD;
  *  ***  *  **    *  ***** **   *    ** ********** *  * *   **   *
*         *   *  *  * **  *  *  
      *  * *   *    **** *  **  
**** *  ** *** *** **        * * * **  *** * ***  *** **  *  **   * *  
  ****** * * * ** * *    **  **  *
 * **  * *    *   *  * * **  *   * ***** **    **   ***  * *****   ***  *  * **
******    * ***  *  *   **   *  0;
}
** **      * ****  ****  *  *  *** gcd(int a, int b){
 * ** ***** *   *  *    *     ********** *    * *** *  **  (!b) return (a);
* **** ** *   ****  **  * *    *  **  * *****  ***    * *   gcd(b, a % b);
 *  **** **   **   ***** * * *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    ** ***  * *
#include *  ****** * **** 

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
***  *    * *** *** ******   **   gcd, remainder;
*** ** **** *   *  *** 
****  *** ** * *  *  *** ** **   (n != 0)
*  *  **  *** **  **   * ***
**     *     *****  *      *** * * **  * **      *** *****  *  = m % n;
   **   **** * * *   *****   * * **  * *  * **  * = n;
******** * *  * ***    **  ** *** ******** * ****  = remainder;
 *****  **   *  ** **      
   ** ****  **  ** * * ** *
 *  * *   *       **   ***  ** * * = m;
****  **   ** * * *   *   **
 * ******** ***    ***  ********* gcd;
}
int main (int argc, const char * argv[]) {
*       ***   * * ***  * ***   number1, number2;
***   *** * **  **** **** ** ** newNumber1, newNumber2;
******  *** ** *    * *   **  
 * * ********  * *****  **** 
 **** **** **   * * **   * **     * * * * * **   * ** *  *   ** ** *  *  **    * ** 
*   *   ****  *  ***  ****
  *     **     ** * *  **  * = number1 / gcd(number1, number2);
**** ** *   *  ***  *      * *  ***   **  = number2 /  ****** *  number2);
    ** **  ** ***      ****  
 *  **   ****** *    **  *****   
 **  **   *  * *    ** *   ( *  *  ** 
 *     *** * *******  *  *  *  *  *  ** *  ****     ****     *   * * ** ** ***** newNumber1);
***** **   *   ** * ***   *****   
*  *** **    * * ****  * * *
   * *     * ***** * *   ****   * *   * *** * * *   newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
  *  **   *** * *  *  *  ** **** *** a,b,c,d,e,f;
 **   * ** ***  *   ** ** *   **** *       ** *  ** **    * 
* **** ****** * ***   ***** * 
    * * **   *  ***  *  
 *  * * *     *   **** * *** **   * *
    {
   * ** **  * *   **  * *   *     *    ******  *
***    ***** ****** **  *   **  ***   * ***       ** ** **
****  * *   **   * * * *   ****  **  ** * ** * *  
    }
  * *** *****    ** * * **     * ** *
    {
   ***  ** ****  **    * *  **             *   ** ** **
**  **** **  **  ***   *  * *  ***  * *** ***   ***** **  * * *   * *****    ****   
*    **  **** ****   ** *  *   * ****   *   ** 
* * ******** **** ** * **** *  * ** *  *    ** *      **** ** * *           * ***
    }
  *     *****  *** ****  *   *
    {
  *** *  * ***** * ** ***   *  *  **   *  ** ********      
  ** *     **  *   ***   * **** *   *   *  **  **  *** **  **   *    * *  
*  * * * **   *  *****    *** *   * ****  *   *** * *  *  * *
  * ** ** * * ** **   *    **  * **** *      * **  * *  * *    * ****   ** * ** 
    }
 ** *   *   ***   **   ** **** *   *** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.184
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 12.2k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 11.8k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 15k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 11.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users