11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
12.7k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 12.7k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

    ** **** ** ***** * * * **  **     i;
   **  * *   ****** j;
 *    *  ****  * * *  * ****  newNum1;
** * **** ***** **  ** *  newNum2;
* **** **     *  * * ** * gcd;
*   * * *** **  ***   ******* rem;
*  ***** **** ***  **  **  num1, num2;

*  *   *  *  * **** *  *  **  *** *   * **  *       * * **

 *   ***   * ** *  ****  ** *  *
* ** *    *   *** * *** *   * * *

***   *  *  *   ** *  *  * * * *  ***  != 0)
** ** * **   *  ****  *  
*     * *****  *** *  **  * **  *** ** ** ***  ** ****  = j%i;
*    ** *** *      * * ** *** * *** * * * *   *   * = i;
 *****   **   *  * *    *** * * **   *  *  * * **  ** = rem;
     ** *    ****   **  
***** ******   *** *   *  *

**    ** * **   *  *****  *** = num1/gcd;
 ****  **  *   ***  *   **  *   * = num2/gcd;

     ** *  *       ***    * ***     == 1)
    {
 *  ** * *  * **  ****   **   *****   *  **     *****  ** ***    *  * * *  * * * * *
    }

 * **    *  * *** *****   **
    {
 * *****    *  ***     *** ** * * ********     **  * ***   **   ***    ** ** *   ** 
  * *** *      *   ** ****  

  **  * *    ** *    *** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
 **      **   **   *****    *    **** ** * ***  * ** ******  *****    

 *   * ** * *   *  *  *   *   **  *  ** *
  ** * * * *** ***   * *** * *** *  *   *** * *** **     ** *** *** * * ****   **** *  *     *

    else{
    * **    ** * *  ***  *** *  *  *    *
    {
**  * *  **** *     ** *  ****    * **** *   *  
*  *  *  * *** * *  ** ***  **   * *** * **    * **** * **  *    *    *  *  * **  * * *   *  && deno%i==0)
*  ** * *  *   ***  *         * *  *   * *    * *  *    ***** **** *  ** ***  
  * *  *         * *    * * * * **  *** ****** ** **  *    **** ********** * *    **  ***  * *    * ** ** * * 
* *** *  **   *  *   ***** *** **  * ** ****  ** * *** ***   *  * ** ** ** *  **        * **    
***  ***  * * *  *  *  ***   *    ** * ***** ** ** *** ** *****    * *   *** * **   *
    }

  ** *  ** *****  **  * *   * **  ***   * 
    {
 * **    ***** * ** ***  **    ****  *  *
 **   ****** **   *   ** *   *     **  * * *  **  *   * **  *       ** **  **  * && deno%i==0)
****     * **   ** **  *** ***  **   *   *****  **** **  *    **     **   ***  ******
* *** *  **  *  **  *** * *    * *  *****  **** ******** *    *** * *        ***   *  * ********  * ***   **       *
* * ****  *  **  * ***  *   *** * *   * * * *  * * *** * **  ***  *** * * **     ******* ***   * * **   ***  *
 **  **** * **  * *** **     ** *  * *** ****  *   *   *   *  ** **  *  * *     ***  
    }
** * *  *      *****   * *   ** *   ****** ** *  * *

    }




    **       **  * **** * ***** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** * *  *** *****  *
#include *    *  ** * **

int gcd(int n, int m)
{
   *   ** * ** *   *   *   gcd, remainder;

  ** ****** ****  *    ****  **   (n != 0)
     *   ** * * ****** * **    *
   ****** *    * **  ** * **** * *  **  * * *  *  *   *  * = m % n;
* **  **  *  **** * * *  *       * * *** ****   ***   *  ** = n;
    *******  * *** * ** * * * ***  ** **  ***   **** = remainder;
*  * *     *  * * *    *        

**  ** * * *** *   *   *******  = m;

* * * ***  * * * *  ******* * **   gcd;
}

int main (int argc, const char * argv[]) {

** ***  **     **     *   number1, number2;
*   *   * ** * *** *    * ***   newNumber1, newNumber2;

  * **  **  *  * * *****  * ***** ** * ** *     ** *  *  * *    *       

 *  * * ** ******** * ***     = number1 / ** * * number2);
 *** *  *  *  ****  ****** *   = number2 /   ** *   number2);

      **  * ****  *  *    *    *    *   ***  
*     **  ** *    **  *  *  *  *  * *** *******       * ** * * 
* *   ******* *       * *
    **  *   *  *  ** * * *  *    ** * * *  * * *** 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***    **  *  *    ***
 ***     *** *** *   

int ***   n, int m)
{
***      * *  int gcd,     **

 * **  * *** *   * * (n != 0)
    *       {
  ** *  *     *    *   *  *  **     ** *   = m % n;
**  *  * ***    * *   *  * *  m = n;
 ***  **  *   * ** * *    ** n =  * * *   
* *** **   * }

***  *  **   ** * gcd = m;

*      *     *  * *   gcd;
}

int main (int *** **   char *  **  * {

  * *  *** *  int  **      ***
  * ****    *   ** int *  *** * *   * 

  ******   ** *****  ** **    * *  ** **   *  * ****  ** * 

* ******  *  *     * *** =    *  /   ***  ***  *  *  
    *  *   * * * ***  =  ** /   * ** * * 

*    *   **  if *  ****  *** **   **   
** *  ** * ***    *     * * * *** * ** *      *  * *  *****
*  * *** * * * *  else
 **** * *      * *  *  *   * * *** *  *** * **   **     
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 ***       * *  ** ***  ****  i;
   ** ** * ** **  *** *   **  ** j;
  ** * **  *** ** * ** ***     newNum1;
***  *    **  ** *  ***     * newNum2;
  *  ***      *** *  *    ** **   gcd;
**    *   ****         **   rem;
 **   * ***   *       * * **     num1, num2;
    
 ****     * *  *  *  * ***  ** *  *****  *  ** *  *     **   *     ****  * 
***   **** ***  **  *  ** **
* *  *  **  *  *    *    *  ****
 ** ***** * ** * * *** *   ***  *  
 **  ********     * ******
*    *  ** * ***  *****    * != 0)
 * *   *****    * **  ** * ***  *
** *   * ** * * **   * *     *****       * *   *  * *** * *    = j%i;
 *** ***  ****** *  **  *  ** *  **  * ******* *** * **  = i;
     **   * *  * *   *******    *** *** * * *  *  * * * * = rem;
*** *  * ***    * **** * * *
  **     ***    **     * *** **** *
    
* ****   ** *  * * *** * * ***** = num1/gcd;
 ***   *  ** * ** *** *  * **** = num2/gcd;
    
**  *   *   **  *  **  ******* *  == 1)
*   * ***  *  * *   *   * *** **
   *** **  * *** *** **   **  *  **    * * **** ** * **** * *  ** * ** *
  **** ************* *** 
    
 ** *  *  **  *  * ***  *** **
 ****      * * **  * *     ** * **
  * * ****   ** ***** ** *  *   *** ***********  **** *  * **** *** *   ***   * ** **
 *  * * *        *    *** *  *
    
  **** * *   ** * * * *  * *** **  0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 *  * *  *****     * *  **  i;
 **   ****  ******* * * **  j;
*** **  **   *  *** ** * * *   *  newNum1;
  * *   **** ** * * **    * *  **  * newNum2;
******* ** * * **   **** gcd;
** ** *  ****   *  *  * *    rem;
 ** ***** *    **    *** *  *** num1, num2;
    
   * * *  **** ** ***** **** ***  ** * **   **  **** *  *  * ** **
  **   ** * * * * **   *** * *
* **   **    ** **** ** *    ***
****  **** ** *     **
* * *     *      *    **
   *  *       **  ***** *     ***  != 0)
    *** * * ** *    * ** * * * **  
 **** * * *  ** *  *  **  ** **   * * * * **  ********   = j%i;
*  ** **** * *****  **  *         ** ***    *    *     = i;
 *** **  ******* * *     ** *   * * ***  ***  ****** ***  * ** = rem;
** * **   ******   *   ****  
** *** * *   *  **  ** *  *  **  ** 
    
**    * * **  **  **   ***** * = num1/gcd;
       ** *     *  *    * * *    = num2/gcd;
    
 **** * ** * *   ****** *  **** ***  ** == 1)
  *  *  * *  **   *    ****
* * *  ****   *   **  ***  **  ** *** **  **    * **** **  ** ***    **  *  *
  ****** **     ***  **** * * 
    
* * *  ***  *** * **   * * ****  
* ** * **    **** **  * * ** *** 
  ** * *       *****    **     **  *   *    *    *** * *   *  *  ** *   ***  ** *  *   
 **    ***  ***   **** ** **
    
 *  *** *** *  * * ** * ***     *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** * ** *** *   ***  ***  * ** ***  *  *** * * *  **  *******  
   * **  ** ** ***** ***  ***  * * *   *  *     ** * ***   *** *
    {
** ****** ** **  ** *  * *    ** *  *      *** *    **  *** *   *  ***    
 *   *** *  *** **   *  ***** ** ***** * **** *  *   *  *  * *      * 
 * *   *    *    *** * *  **   * *  *  *    * ** * 
*  ***** *      ** **** ** * ** * * *  * * * ****
  * ** *  ***     * *** **   *  * *    **    ***

 * * *  **********      * *       
 **** *   * **  * **** ** * ******* ****** ***    *  * *** **    * *    * **** *** *  ***    
   **** * *  *  * * * ** *   ***  * *   * **   ** ** *** **  *  ** **    *** * ** ** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* *   *  **   * * *     *   a,b,GCD;
 * * ** *** *** * ** ***   * *   ** ** **** ** * *    * * * 
 *   ** ** **   *      ****    ******* *
*  **   *  **    *  ** ***  *  *
 ****  **** ***** ** *  ***    *    * *** *    * ** ** *****   *  * 
***  * *** **  *******  
   *  ** *** *** ** **  ** ** *****  *     *      *   *** **    *  *** * *****
***  ****  * **** ** ****     0;
}
*      *****   * *  *** * *  *** gcd(int a, int b){
 ****  ******     ****  * *  *  ***  *  * ** ***   *   (!b) return (a);
*  **  *  * *  **    * ***     **   * *  *** * *  * * * gcd(b, a % b);
 ***  *   **  *****    *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** ** *   ***
#include   **** ***  *  *  * 

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
*  *  * *******  * ** ****** ** ** gcd, remainder;
 * *  **     *  **   ***
***  *    **** * * ** * *   **** (n != 0)
 * *   *   *  * ** * ***    * 
**  * *  ***   * **    ** *** ****   ** **  **   * *  = m % n;
*** ****     *     * **** ***   *  * **  *** **    * *  = n;
  * *  * * **  *** ** **   ** ** ***   ** *** *    ** **** = remainder;
** **** *       ******  * **
  **  ** *   * * **    **
**** ** * ***  *  ** * *      * = m;
 * ***  ** ***** *    **  *
  *** ** *  ***      *** * ** * *   gcd;
}
int main (int argc, const char * argv[]) {
  ** * *** ** ***  ***** ** *  * number1, number2;
   *    ***   *****  *  * *   newNumber1, newNumber2;
* *    ** * **   *** 
 **  * ***     *  * ** **   *
*  **   *** * * * **     *    **  ********  **   *   **  * **  * * *  * 
 *    **  ** *      ** * *
  ** *  *  *** * ****   ****  **   = number1 / gcd(number1, number2);
 ******** *****    ***** * ****  * = number2 /   * *** number2);
  * * * *    * * ** * * 
  ***** *   *****  **  *    
   ****    *** * **  * *** ( **** **
  *  * * *  *** **** **    *   ** *   * *  * **** * **** **  *  ** *  **  *** newNumber1);
*   ** **  **      ** **  ** *
*    *** * *  *  * **  ** 
*   ******  *** ***           ***   *  ****    * *  *** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
 *  * ***** *   *  * * **  a,b,c,d,e,f;
   *** * * ***  ***  *   * * **   *  * * *  *  *   * * * **    ** *  
  * ***   ****  * **  ** *** 
 *  *  ***  *  * **   * ** *   **
* ********** ** *     * ** *  ** **  
    {
 ** * * *   *** ***  ** *    * * ***    ****  **   *
*** **  ***    ***** **     **   *  *     *** *  **** ** 
 ****      ***   *  * ***  *** **     ** **   *    ***** *******
    }
**** *  **    * *  ** **   *   *   * **  
    {
  **           *  *  **  ****** ****   *  *  ** **   * *    **      *
**  * ****  * *  **  * *    ** * * * **** *     * *  * **      **   *  *  * ** **
 **** * *  * * ** **  **** * *   ** *****   ** * ****  **
    *  * *****  **  * * ******  ** *   * ** * * *****   * *  *  **  * **   * 
    }
** ***   * ***  *****   ** * 
    {
  * *  * *    ** **  *** *  ****  *   * ***  *   * *  *    *      
  *   ** *  *  *    * **      **     *    ** **** *** ** *  *   *  **  * *** 
***  **  **       ** * ****    ***  ** **   *** ****   *  
* ***   *      *  *** **  ** *  *    *  ** * ** **** **** ** ****** * * **  **  ***  * 
    }
*  *   ***  *****  ****  *  *** ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.70
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 13.2k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 12.9k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 16.3k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 12.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users