11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
4.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 4.9k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

 *** ***  * ****     * ****      i;
**  *** * ***  ****   ****    * j;
 * *  *** **** ** *  *    *  * newNum1;
*  * *  * *** ** * *** *** *  newNum2;
** ** ***  **     ** *  **    *** * gcd;
  * * **  * *   ****** * rem;
** *  **  **   *    *** **  *  num1, num2;

 ** **  ****** *  ** **    * *  ****** *  ** **  * *     * *****

**** ** *     **  *  ** * ** 
*   *** *   *  * *  * *****  * **  

* ****** ** *****    * *   ***  != 0)
      * *  * * *** * *  *   * 
    **  * * * * * *  *  ***** **  ** **** ** **** **   ** = j%i;
** ****** * **   **  ********      * ****   ***  = i;
 *   *******  * ** *  *   **  ** * **   ****** **   ** = rem;
***** *** ***   * ** ** * *
*** * ** ** *    *   ******  

** **** *  *       * **  **   *   = num1/gcd;
  *       *     ***     ** ***     = num2/gcd;

   *  ********  ***** ** **** **** * == 1)
    {
    ** **** ***     ** *    *  ** *  *** * *** ** *   ** *** *** **  *       ***
    }

 ***** * ** *  ***        **** *
    {
* ***  ** **  **  *  **    *  ** ****** * **** * * * * * ***** *    ***   ****  ** *
***    * *  ***  * *   

 * ** * **  ****   *** ***  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
    * **     *  ** *  **** * *  *   *** **  **   ***** *** * **** *

****** ****        * *  *****  ** * * ** 
 *  ** *  **   *    **  *** * *   **  ***   *  **  * *****  *    * ***** ***   * 

    else{
*      * **     ** * * **** * *   * *  *** 
    {
    ***    *****  ******* ** * * ** **  * ** *
* **   ***  *****  * *   *** ***  *   **** * **    ****** *    **  * **  && deno%i==0)
 *     *  ** ** **  ** * ***     ** * * ****  **  *  **   *    **   ****** * *   *
  *** ** *  ******  * * * *   * ****  ** *  * **  * *      *** * *   ********* ** * * * ******  *    **     ** * 
   *  * * * *** *  ***  ***     * * *    ** ** * * * *    * * *  *     * **** ***    **** **** * * * *****   
***  *  * *  *** ***   * **    *    * * * * ** * * *  ****    **     ** ** *  ***   * ** *
    }

*******  ** **        ** ** ******  *  **  *
    {
*** **  **** ** * *         **   * *     * ***
  ***   * *** *** *** **  *  **  *  ***  *  ** **** *  **   *  ***       ***** * ****  *** **   && deno%i==0)
* ***** *   ***  * * ***  ** *** ***** * ** *** *  * *   *  **  * ** ** *** * * 
 *    *** ***  *        *   *   **** *      * * **   *   ***    *** **   **  *      ** * ***  * *   *
 ** ***** *** ********  ** **   ** * *****  **  **  *** *  **  * ** *****   **  ***  *    *  * * *  *   ** ** 
 *** * * ***  * *   ** *   *    * **** ***  *** *    ****** ** ********    *   *  *
    }
 *   **  ** *   *  *  *      *      *  ****    ** *** *** 

    }




  * * *  **** *** *   *    ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *  *  *******    *
#include ** *  *  * *   *

int gcd(int n, int m)
{
 *** ****   *     *   * **   * gcd, remainder;

* *    *  ***  * ********    (n != 0)
*   ** ****  *** *  **   *  ***
 *  *  ** *  **      ******  * *  * * ** ****     **   * = m % n;
 *      *  *** * ****  * *  *** **   ****     *   **    = n;
     *   ****  *   * * **  ** * ****     *   **  ** = remainder;
** *****  * *      *   * ** ** 

*** ***  *** **** ****  *   * = m;

  **  * **   * * *** *  *      gcd;
}

int main (int argc, const char * argv[]) {

 * ** * *   *   *    * * *   * number1, number2;
 *    *  ** **     * ** *  *  newNumber1, newNumber2;

 *** * ***  * **    ** *      ** *  ***    ** ****  ***** ** *  ******  *** 

  * * *****  ******* *     ** * * = number1 / ** ** *** number2);
* * *** * *  ***** * *  ****** = number2 / *   *   number2);

 *   *  *** ***** **  *  ** * **  * ** **   
**** * * *   * *     * *  *      *  *  ***  *    ***     *    ***   * 
*  * ** ****   ** * * *   * *
***** * *   ***   *  ***   ******   *  **   **  *    *  *** * 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ****  * ** *   *  *
*  ** *     * ******* 

int  *** n, int m)
{
    *    **    int gcd, *     

***** *  ******   *  (n != 0)
***   ***     **    {
***  ** *     *  *     *  ****   *   * = m % n;
    ***     *** * *      *** m = n;
*** **       *  * *   **  ** ** n = *  *
**  * * * **    }

***       *  ** gcd = m;

 *  ***** **  *** *** * gcd;
}

int main (int  *** *   char * *   {

 * ***   ***** int  * *   * *   
 * *    ** * int *   ***  *** 

 * **  ***   **    **   *   **  *    **  ***  *** * * 

*** **    *  * **  * = *  / * * *     ***
* * ***   *  *** * **   * =    * /   * ** ** *  *** 

 **  ***   * **  if *** * ***** **  *    **
******* **   *   **** ***** ****      **      *** * 
*  *       ** **  else
 * **  ***   ** *  * ***    * *** *          ****** *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 * *** *  **  * *   *  *   * * * **  * i;
 ***** ***     **      * *     j;
      * * *  *      ** *     newNum1;
*  ****** **  * *  *  ** ****     *   newNum2;
 * *  * **** ***     *** ***  ** gcd;
  *    *     * * *    *  *   rem;
 *    *****  *  ** ***  ** * num1, num2;
    
 *  ** * * *** **   *  *  ***** ****** * **   **    *  * * * ** *
 ****    **  *   *  *** *** 
    * **   *** * *     ** **** 
*** **  *  **  *  *  ****   *** *   ***
 *  ****    **  *  * **  *
**  ** *** * *  **  ********      != 0)
  *   ****   *  *  **     
** *  * *****      *    **  **** ** * *  *** * ****  ** = j%i;
  ***** *** ***  *  **** ***** **  **** * **  *  *** **  = i;
  **   *  **** **   ***  * ***** *   ** ***** **   * *  = rem;
*     *** ***  *      *
 * ***      *    *** *** *  ** * **    
    
 *  **   ** * *   *   **** **   = num1/gcd;
*** *  *  ** ** * **        *   *   = num2/gcd;
    
 *** *      *****  ****** * *  *  ** ** == 1)
 ** * * *** ** * **   * ** 
** ****  ***  *   *    * ** **        * * ** * *   ** *   *** *   *** *      
    * ***       * *****     
    
*   *  ** ***  ***  * *** * 
*   ** ** * **   ** *  * * ** *
 *** ***   **  **    **  *  ** ** *  * ****    * **  *  * * ***   * * **** * **  * **  * **  
*   *** ** **   * ** *  *  ** ****
    
 **** * ***  **** **** *    * *      * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
***     ******   **  *   ** ** i;
 ** *  *       ** * *     ****  j;
** **    **  ***  *  **   * *****  newNum1;
*****  **   **  ****   * * *   * newNum2;
 * *   *   *   **  **  *   **  gcd;
* * *   *  ** *  * * rem;
*  ***    ***       * *   *  num1, num2;
    
 **   * **  * * *    **   *  ** * ***  ** * * ***     * *** *  *  **
   **  ** * *  * *     * * * 
 ** * ***        ** * *  * * *
 ** * **  *    * *   ***   *  
 ***  * * * *  * **   ***  *
* *  ** **  ****          **  *   != 0)
  * *   * *   **    *** *** **   
*  ** * **  *   *     **   * ** * *  *  *  ***  *  **    * = j%i;
  **  *   *  *** *   *  **     ***  * *  ***  * ** = i;
*      ***  * ****    **   **    ***  *  *  **     ****   ** = rem;
****  *    *  *  ****   *
  *** * **   ** ** *  *** *  * *
    
  ** ***    * ** * ** **   *  * = num1/gcd;
 *  *  **** ****   * ****  * = num2/gcd;
    
 * ***  * **    *** **   * **** == 1)
     *    * ******** ****   * * 
* *   *  *  *   ***  **    ****  * *****  ***  *       **   *    ******    * * 
 **  **  * *  **    * *  ***
    
 *    *   * *  **    ** *  ***
 * *      *   *** *   * *** **
 **   * *     **   ***    * * ** *  * *  *   ** *** ***   *   ** ***  * *  ***** ** **
 *   *  *** *  ** **    * * 
    
**  **  *    ******  * *  * * *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
  ** *  **  * **** ***  *  * **    **  * *****   *****  **  *   
* * * *   * ****     *   *    ***  * ***    * * **  ** * * ***
    {
* * *  ***      *  *  * ** * * * * *    *  ***    * **** ***** **  ** ***
 *        **** ***    **        ** *  * ** **       ** **  * * 
*  * * * *** ***   * **           *   *  **  **
*  ***     **** ** **  *  *  *  ***  *  
 *  * *    *  **   *** **  * ****    *** * *    **** 

  ** ** * ** * ****      *    
 *    * * *   *  * *    *** * **  ****** * *  **** ** ******  ** **  * * ** * *** *  * *    *
 ***      **  ***  * **   *  *   **  * * *        **  *  * * * *     * ***** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*** *  *** ** ** **  *     a,b,GCD;
   ***  ** * *   **  * *  ****** * *   **** * ***  *   *****   * ***
****** ** *****   *        ***      ** **
 *  **  *        * *   * * **** ** *
 *****  *    ****** ** *****  **   *  ***  * ** * * ** ** **
   * * **    ***  * ** *  ****  
  ** ** **   *   *    * ** *  **     * *   * *****      * ** ** *** ** **
*  * **   * **  *** *  ***  **   0;
}
** *  ** ***  **** *    *** gcd(int a, int b){
 *  *  ***   ** **  ****   * * ***   *   **   **** (!b) return (a);
***   *    ** ** ***  * **   *   *** **  **  *   **** *  gcd(b, a % b);
 **  *** * *  **    *** **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *****   * *** *  *  *
#include       ***  ** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
*   * * *    ** *  **    *      gcd, remainder;
*     *      *  *** *   
***** *   ** **  *   *  *  *  (n != 0)
  *     ****    ****** ***
 ** **   *  *  *      *  *   * ** * * *  *****  ****       = m % n;
  * **** ****  **  *   * ** * *   * * *   ***   ***** = n;
*  *    *** **    **  * *    * ******  **  **  *     * * * = remainder;
**    * **      *   **  * *
* *  *   * *****   ** * *** 
       * *  **** * * *****  * * = m;
 ** ** *** * * **** ** *  
 *    ** * * *   *****     ***** gcd;
}
int main (int argc, const char * argv[]) {
* **    * * ** **       * * number1, number2;
***** *****    *  * **  ***   * newNumber1, newNumber2;
** *  ***** **** *  *****
 *   **  **** *   *** ***  
 ********* ** **   ******* ** *******        *   **    * * **    
* * **  **  *     ****** **** ***
*  *  ****** *  *  *  **  **      **** = number1 / gcd(number1, number2);
* **  ** **  **** * *** *******  **  = number2 /  **   *** number2);
    **    *  ******* ** 
 ***       *** **    * *  * ** *
*   * *  ** *  *    ** **   * ( **     *  
*****  *** ******* ** * *** ** *****  *** *  ***  *****    * **        newNumber1);
 * ** ** ** *  *** *  ** *   *   
*****  * **   *   **  *  *
  ***  *****  *   * * *  * ****  ***  *  * ***** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
******  * ***   ***  *    * * a,b,c,d,e,f;
  ******* ***** **   * * *** * * *   ** *  ***  *    * *  * ** 
   **    *** ****  ***  * ** *
* *    * *  * *   * *   
  **    * *     *   ***  * **  * ** *
    {
*        ** ** * ****  **  **  ****    * *  ****  *  *  *  * 
  *   *       ** * * ***   *  ***   **    *  *** * **  
    * *  ** ** *    *** *** ****** *  *   **    *** *
    }
*  *** *  * *  ** *    ****  **  
    {
**** ** **** *    *  *    ***  *  * * *   *******   * ***   *   
* **  * * *****  ***  *  **  *  *  ** *  ** *  * * ******* * *   ***  **
  *  * **  *  *     **  * **    **   *  *  **  * ** ****  *
   ** *   ***  * *** * **  * ** *** **   * ***  * *  *** ********    ** * ** *  ****
    }
     * *** *  ******   ***   
    {
* **    * *    ** ***  *  *   ** *  **        *    **  **  ***
 *  * *  *   *     ****   ** * * *   * * * ** *  * ***  *** **  **  *    ****     * 
* ***   *     **  *** *  *  * ** *  ***   **   ***** 
*** ** *** **** * *  *   ****   * ***** ****  * *******   *      ** **** *  **  * *     * *  
    }
 *      *  *  *   *     *** ** * * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.36
©2016-2024

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 5.5k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 5.2k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 6.4k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 4.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users