11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
16.7k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 16.7k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

     **** *   * **  ** *  i;
    *** ***    ** *  *  *      j;
** *** ** *  * *** * *  *   newNum1;
*** ***  *****  *    * ***  newNum2;
   ****  *  ***   * ** ** gcd;
 ** *****     ***   * * *   rem;
    **     *   *  * *      *  num1, num2;

 *** *  *** * *****     *    *       **   *   **    * **    *  * **  ** 

**     * ** * *  *    *  * *** *
***  ** ***   * *  *    * * *****

* * ***  *** *   ******* * *   *  ** != 0)
 *  * ** **  ****   *** ***    
 *   ** **  *  *  **   *** * *   * *  ***  *   **** * *  = j%i;
   * *      *** * ***  * * * ****    ** ***  ** * ***  = i;
*   *  ** ****     *      * **  ***** ** ** ***  **** *   = rem;
    *** ** *     * * *****     * 
  ***** ***      ***     *   *   ** 

* ** * **    ***  * **  *    *   = num1/gcd;
 ** * *  ** **   * * ** *   = num2/gcd;

*****   * ** * **   * **  * *  * *  == 1)
    {
 * * * *** **  * ** * **  **  *  * **  *   *  * * * * *  ** ** *      *       *  * *   ***  
    }

* * ***  ***      *  * * ** 
    {
* *   * *** *  ** **    ***   **   ** ***** ** *  * * * **** *   ** **  *     * * ** *
 **         *****  ** ** **

  * *   ** * ** **          *** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** * * ***    *  ** ** * *   **   *  * *** ** *** *   ***  **** ** ******* 

* *****    *  *** * *   * * *    * * *
  * *  ****  *  * ** ***   * **   * *   ** ****    ** ** *     *  * ** * **  *

    else{
 ** ***  ** **  *  *  *** **** ** ** 
    {
* *  * *****  ** **   ** * ** ***  **   * * 
 *   **   *** *   *   **  * **   **    **   * **    *        * *   *  **   ** ***** *  && deno%i==0)
 * * ** ***    **** ** ***  *  ***  **   *   *   * *** *  * **  **** **
  *  *    *** * **   ***  * **  ** ***  *** *   *  **    ***  *  **  **  * ** **   ** **   *** *  *** *  ** **
  **** *** **  ******     ** ** *  *  *** *  * * ** **  **  * * **  * * **    *   ***    * *   *** * * ****  *    **
**** ***    * ***  **   ***  *  ****         *      ***********  *  *   ** *** *** *    
    }

*  * **    *     *** ***  *  * *** *  
    {
* **  * *** **** * **** * ** * *** *         
*  ****** **  *** *** *   *   *  *** **  ** **  **       ******** *    *  *  * ** * ** && deno%i==0)
** *    *** *   *   ** * ******* *    *  * **   * *   **  *    ***** **  **** ****** * 
   *   ** * ** ** ** ** ****** ****    * *** **    * ***  ***  ** * *  *   ** * *  *****  * * * * * * **
*   *       **** *     *** ** * *  ** * * **       * *    ** *      ***** ***   * ****     *    * ***
* *  **  ***     *  * * ** * *   *  * **   *    *     ****  ** ******        *  * ***   
    }
**  *** * * *   ** * * * *** *   ** *  * *     *   **** * *   

    }




 ** ****  *  ***  **  *       0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * ** *  **   
#include   ***  ***** **

int gcd(int n, int m)
{
***      * ** *  ** ** *** **  * * gcd, remainder;

** * ** * *   ** ** * ** *** (n != 0)
** ** * ****   *************** 
***   * * ***      ****** ** *  * * **     **  *    *  = m % n;
*** ** * ** *******   **    * **  ** *   *   *  = n;
  ********* * **  *******     *  ******* *  *   **  *** = remainder;
   *  ***  * *         *****

*    *  ** **   **  *** ***  ** = m;

  ************  *****  **** gcd;
}

int main (int argc, const char * argv[]) {

 *             ** ** * *   ******* number1, number2;
* * * * * * **** *  **   * ** newNumber1, newNumber2;

   ** ** * *  *   ****** *****   *   *    *  *     *    *****  * *** * *** * 

***     ****    * *** *  ***   * *    = number1 / **   * number2);
**  *********    * * *        *  ** = number2 / *     number2);

  **  ** ** *  *** * *  ****   * **** *  ****  * * 
  *  ** ** *   *  ** ****   *  **  *   ** **    ** *   * *  *****   
*   **   ***       ** **   * **
* **    * ****  **  ** *    *   **   **   **   *   ****** 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**   *  **** *     *  
* * **  ***    **** **

int  ** n, int m)
{
** **  *    * int gcd,   * * *

*    *   **    *  (n != 0)
   *  ** * * {
 *  *    * *  *** *    ***     *  * = m % n;
***   * * *  *  * * **** * **  *   *  m = n;
*****  ****** * ***    ** * n = *   ***
   * *  *   * *** }

* **  *   * *   gcd = m;

          ***   * *** gcd;
}

int main (int    *   * char * * * * {

  ** ** ***   int  * * ** **** 
  **  * ** *    int   ** * *    *    * * 

  **    **   ** *      ****   * *  ** *   ***  ** ****** * ** *    *

**   *  *    *   * *    = *    *  / ****   ***
 *** **  *****  ****** = *    /    ** * *  *   * 

*** *     * *** if *   *   * **    * *     
  ** ***    * * ** ***** * *  **** * *   *     *  *  *
     **  ** * else
 ****       * *****  * * *  * * * *    *  * *       * **  
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
* * **   *      ****** **  ** i;
  * ** ** * * ***** * *** ** j;
     *** * *  * ** *     * newNum1;
******   ** *       * ** * newNum2;
**  ** *    *** **   *   gcd;
*      *  * *  * ******** ** * rem;
*  *  ***     ** **      *  num1, num2;
    
* *   **    ***  **       *        ******      ***** ** *** ****      **
 ** **   **   **** * **   
  ***   **** * **   **** ***     *
 *   ** ***   *  *** * * ****** 
****  ****    ******   ** * 
**** *** ** * **  * *** *****  != 0)
   *  * ** * **  * **** * 
**  ** **      ******  **  *** ** **   ** ******* **   * = j%i;
**     * ***  * ** * **  ** * * **** ******     = i;
**    ** ** **  *    ** **  * ********** *   *   * * *  ** = rem;
***  * * * ***      **   ****
 **** *   *  **** ***** * * * *******  
    
** * * *  ****** *   *         ** = num1/gcd;
 ******* ***  ** *****  *   ** * = num2/gcd;
    
 *** * ** * * ***  ***    * ** ** * == 1)
** ** *  **  **  ***  *  *
*** * *   * *  *  *  * ***     * ** * *    ***    * ***   * *    * *  * **  *    
    * *  * * *    **** 
    
**** *  ** ***** * * * *******
* *  *   **   ** **  *** * *
*  * ** ****** * ** ** *    **** **** * *** * *** * ** **   **  *  ****   ** * * * **   
*   *  * *** ** *  **   *   ***   *
    
* *   *  **  **   *** * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 **    *     ** *   **** * * ** i;
* *  * * * ***  *** *****  j;
 ** ***** ** *  ** ****  ***** newNum1;
* ** ** **** ***  * *  **  ** * newNum2;
    * ** *****   *** * *  *** ** gcd;
  * **** *** *****   ***   *  * rem;
 *** ** *    *  *****  *  **** *  * num1, num2;
    
 *  *  ********   ****** * ** *   ** * ******** ***** *****  *  *    
* * ***   * ***  *  *  * 
  * *   ** *  **      *   *  ** *
*******    * * ******  * ** * *
*   * **     * *  ********  
 * ** *    **  *   *** **  * * **   != 0)
 *** **  * * ***     *   **  ** 
 *   ** *** ** *** **** ******* *   * ** * *** **** *     = j%i;
  *    * *    **** *      * *** * *  *  *   * * *** **  * = i;
*********** * *  ** * * *** ***** **    ** *    = rem;
*  **  ** * * *  ** ****  * 
* *** **** * * **** *   ***    
    
*******  *  * ** *  *  ** * ** *   = num1/gcd;
* ** *  ****  ** ** **   *  ****  = num2/gcd;
    
         ** *    ***** ****** ** *** == 1)
*  * ***  ***** *  ****   ***
  * **   * ****   ***     *** * * * *      *    * ** ***** * ** * ** ****     ******
* *  * ** **   * *      
    
*  * *** *******   *  *  * ** * 
*   ** *  *   ** ***** 
 *     ***  *** * ** *** ***  ******  ***   ** * *  ** *  * * *    *** **   ***  ** *
*  *  ** * * *  **   *   *** * 
    
 **  *   *  *  **   ***      0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** * *  ** **  *   *  * ****   **   * *     *** ** ** *   **  *   *
  ***      ** *** *****  * *  ****  ***     ***** *   
    {
  *** * *  ** **    ****** * *   *** *  * *** *  *  *  ***** **  ** 
 ***     ** **  ***** * *** **  ** * *  ****  *  **     ******** **
*   * * * **** *  **   ** ** **     * * *    
 * *  ** **  ** * *   ** **   *** * ** ** **  * 
 *    *   * ** ** *  *  **    ** * *  **** *

    * ***  *   *** **** *    * ****  **
 * **  *** ** *    ** **** ** * **  ****    **   ****     * *   * * **  ***   * **   * *   **** **  *  ***    *
**   **  * **     **           **  *  ** *   *   *  * * **  *  *** ***  *  *  ****


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* *  **  ** ******* *  a,b,GCD;
   ***   *     *   * ** *      * *** ** ** *  ***   * **      *
   **    *  **** **  * ****  ** * ***
**** *  ** **    ** * ** *    
** * ** ****  *   * * **   ***** ***  **** *   *** * *** *  ***   * *  * 
  ***  **  ** ** *  ******      *
 * * ** * *** *  *** ** **** * * **  *   ****  ** **  * * *    **  ****    *
   *   *  *     * ** *  * ***  **  0;
}
**  *    *  *      * *   * ** ** gcd(int a, int b){
*****     *  ** **  **  ***   **      ******* *  **  *  (!b) return (a);
 *** * ******  ** * ** * * * *     ***        *   ***    * * gcd(b, a % b);
*   * *  *  * * *    * *    *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * *** **  * ****
#include   *      *   

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
  * * * *  *   * *  ** * ** gcd, remainder;
* * ** *** ***  ** * * * *  *  
**  ** *  * **** **  *    ***  * (n != 0)
****    *    *  ** **  ** ** 
*  **   * *   *     ** **  ** * **  *** * * *    *   **  *** = m % n;
     * *******    * **   * ***  * *****   *    *  = n;
** **** *   ******     *  ***  *    ** *     ***   ** * = remainder;
  ****  **  ** ** **    ** ** 
* *** * * ***** **  * * 
  * ***  *   **     * **** = m;
 *********  ***  **     * *
*  ****  *    **** *    ***     gcd;
}
int main (int argc, const char * argv[]) {
**  ** * **** ***   * *  number1, number2;
* *** * * *  **** **   *   newNumber1, newNumber2;
**   **     **** *  *     
*** *   *  *  ***  *    *  
 * **   *** * **  ***       **     *   * **  *  ***       * ** * **  * *
 **  ** * *     * *    
**     *   *****    * * ******    = number1 / gcd(number1, number2);
* *****  * ***    * * **  ** ****   = number2 / ******* number2);
  *** * *     **   * * *   ** **
 ***  * ****** ** * *    * **
* **** ***     *  ** * **** * ( ** ** *   
*** * *  ***   **   *** * **  * * **  *   ****  *** * *      *   ***  *  newNumber1);
*  *     *   ** **  ***    *
    ***    ** ****** ** * 
  *      *      *    ** *  *   *  **  ***  * *    newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*  *     * * *** ** * * * * ** a,b,c,d,e,f;
 **    *  *   * *****     *  ****** *** * *  * **     
 ** ** **  *  *  *   ****  * ** ** 
*   **   * ** **  *   **** * 
   * **        ***  * ** * *  *  ***
    {
**       **  ***     ***** *   * **  * ** * * ** * *  *
*** ** ** *   ****** **    ** *****     * ******   **   ***   * 
*** *     ** ***  *  * * * ***  * * * *  * * *     ******  ** *
    }
 ** *  ** * *   **  * ***    *  *** *   * **  
    {
 **  ** * ****** ** * * ** * * *    ** ***** ** **** ** * 
   *    ** * **   * ****** * ****  ** *   ** ** ***  * *  * **** *     **
   ** * ** ***   * * *    * *   * *    *   *  *******
   ** *  ****  ** **   ** * * * *  *     *****  * **    **   *   **  * *****  ***  * * *
    }
 ***  *** ** *   * *   ***
    {
 **  *      *  *        ** **            **** **  * * **   
********** **    *** * * **  * *  *** **   **** * ** ** * ** ** *** *** * * 
 ** * ** *         ** *  * * *  * ****  *** * * **** ***
  **  **  * *******    *   * ** *   *******  * *      **** *  ***  * * ** ***  ** ** *  *
    }
**   ** * * *** **  *  *** ***  ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 16.9k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 16.6k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 22k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 16.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users