2 like 0 dislike
7.8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 7.8k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

***** * * *** ** ** i;
*** ** * ** ** * * **** * * j;
* *** * ** * * ** ** * *** * newNum1;
* *** ** ** ***** newNum2;
* * * * ** * * * * * * gcd;
** * ** * **** * ** rem;
** * ** * * * * * * **** num1, num2;

* *** * * ******* * ******** ** * * * * ***** ****

** ***** ** ** * * ** * **
* ********** * * ****** * *** **

* *** * * * ** ** * != 0)
** ** ***** * * * *
** * * * ** * *** **** * * ** *** **** * ** = j%i;
* ********** **** *** *** * ** * * ** *** ** ** = i;
** * * ** ** *** * * * ** * ** * * * * ***** = rem;
* * * * * *** ****
* * *** *** **

* ** ****** * * ** = num1/gcd;
* * ** * ** * * *** = num2/gcd;

* * ** **** ** * ** * ***** == 1)
    {
** * ** **** * * **** **** **** * * * ** ***** *** * **
    }

* * * * *** * *
    {
* ** ** *** * ** ** * * * * *** * ** * * * * *** ** * * * * *
** * *** * * * * ** * *

*** ******* *** * * ** *** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * ** * ** * * **** ** ** * ** ** * ** ** **** * * ** * **

* *** **** * ** * **
* * *** * *** * *** * * *** * ** * * * * * * * ***

    else{
* *** ** * ** ****** ** ** ** *
    {
* * * * * **** * * * ** * ** * *
** ** * ** ***** *** ** **** * *** **** * * * * * * ** *** *** && deno%i==0)
** ** * * **** * ** ** * *** ** * **** *** *** ** * * *** ****
******* **** * * *** *** * *** * ** * ** ** ***** ******* * * * * ** ** * *** * *
* * **** *** * * ** *** * * ** * ** * * * * * * * ** * ** *** * *** ** ** *
* * * * * * ** * * **** * ** ** * * * ** * ** ** * ** * * *
    }

** ** * * * ** ******* ** * * * * *
    {
** * **** * ** *** * * *** * * ** * *
* * *** * *** * * * * * ** * * * * ** ** * ******** *** *** ** ** ** * && deno%i==0)
* * * * * * * ***** ** ** * * * * * ** ** *
* ** * * ** ** **** * ** **** ***** ** **** * ** ** * ****** ** * * *
* *** *** * *** *** * * **** ** *** * *** * * ***** ** * *** *****
* ** ***** *** ** *** * * * ********* * *** * ** * ** * ** *** *** * *
    }
* ** * *** * * ****** * **** * * * * * * *

    }




*** * ** * * * *** * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** ** * **
#include * * *******

int gcd(int n, int m)
{
** * * ** **** * *** gcd, remainder;

** * * ** * * * * (n != 0)
* ** * **** * * ** * **** *
* * * *** *** **** *** * * *** ** ** *** * ***** = m % n;
*** ***** * *** ****** ** * *** * * ** * *** = n;
* ** ** * *** * ** ******* ** *** * * ** * = remainder;
* ** * ** *** *****

**** * * ** * * * = m;

* * ***** **** * * * gcd;
}

int main (int argc, const char * argv[]) {

* * * ** *** * *** * * number1, number2;
* * ** **** * **** ** ** ** * * newNumber1, newNumber2;

* *** ** * * * ****** * * *** * *** ** ** * ** * * *** **

*** * * ** * ** * *** * = number1 / ***** number2);
** ********** ** * *** *** * * = number2 / ** * * number2);

** **** * * *** ** * ** **** ** ** *
* * ******* ***** **** * * * **** ** * *** ** ***** * ** *
* ***** ** * * * **
** * * * * * ** * ** ** ****** ****** * ** ***
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* ** ** *** * *
* * * ** ** ** *******

int * n, int m)
{
*** * ** * int gcd, * *

* ** *** * (n != 0)
**** * {
*** * ** * * * ** * ** * = m % n;
****** * *** ** *** * ** * m = n;
* * * **** * ** ** * ** n = * *
* ** ** * }

* *** ** ** * gcd = m;

*** ** * * **** * gcd;
}

int main (int * char * ** {

*** **** int * *
* *** * * * int ** * * *

** * * * ** ** *** *** * * **** *** *

* * * * ** ** = * * / ** ***
* ** ** * *** * = ** / * * * **

* * * * ** *** ** if ** ** * ** * * **
* * * * * ** * ** ** *** ** **** ** **
**** * ***** else
*** * * ***** ** **** * * * * ** ** **** * ***
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * * * * * ** ******* * *** i;
**** * **** * * ** ** * * j;
* ** *** *** * * newNum1;
* **** * ***** ***** * ** newNum2;
* ** * * ** *** * * gcd;
** * * * * ** * ** * * * * rem;
* * * * *** num1, num2;
    
* *** ***** * * **** * **** *** * * * *** *
* * ** ********* *** ** *
** ***** * ** * ** **
* *** * ** * * * * * * ** *
** ** ** * * *
** * * * **** **** * * ** * != 0)
* *** *** ****** * ******
*** *** *** * * * ** * ***** * * ** = j%i;
* * **** * ** * ****** ** * ** * * * * * * ** * = i;
*** ** ** * * * * * ***** ******* * * * * = rem;
* * ** ** * * **
* * **** ** *
    
* ** * *** *** ** * = num1/gcd;
********* * * * ** *** * * = num2/gcd;
    
****** * *** ** ** ** ** * *** ** == 1)
* **** ***** *** * * ** *
* ** * *** * * * * ** * ** * * **** ** * * ***** * ** * **
** * *** *** ** *** ** *
    
** * * ** ** **** *
* * ** ** * **
* ** * ***** * *** * * * * ** * * * ** **** ****** ****** * **** * ** ** * *
* * *** * * * ** **
    
* ****** **** ** ** *** * * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * *** * ** ** * * i;
*** * * *** * * * * **** j;
* **** * ** **** * newNum1;
* * * * * * **** * ** newNum2;
** * * *** *** * ******** gcd;
** * ** * * ***** * * **** rem;
* **** *** ** ** ** num1, num2;
    
* * *** ** ***** * *** *** ** * ***** ** * ** ****
** ********* ** **
* * * ***** * * * * *****
* * * * * ** * ** *
** ** * * *** ** ****
* * * ** *** ** != 0)
****** * ** **** * ***
** * *** *** * ** *** * * * ** * * *** * *** * = j%i;
* * * * * * ********* ** *** ** *** * ** * ** * * = i;
** * * ** * *** ** ** ** *** * ***** * * * = rem;
**** * *** ** * **
* * *** **** ** * **
    
** * ** * ** ** * * = num1/gcd;
* **** * * *** * * * * = num2/gcd;
    
** * * ** *** ** *** * *** == 1)
* * * * * ** ** * ***
* * *** * * **** ** **** ** * * * * * **** * **** ** * * *
**** **** ****** ** * * *
    
** **** * ** * * * * *** ****
* * ** **** ******
* **** * * * ** * * ** * * **** ** * ** **** ** * * **** * * ** **
** * * ** *** ** * * *
    
** ** ******* * * * ***** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
*** * * * ** *** *** **** * * * *** * *** * **
* * *** * * * ** * * * * * ** * *** * ** ****
    {
* * *** ** * * **** *** ** * ** * * * ***** * **
**** ***** ** ** *** * *** * * ** ** ** * * * * * *
* *** * * ** * ** * ** ***
** ** ** ** *** * ** * * * * * *** *
* ** * * ***** * * **** * ** * *

**** *** ** *** * * *
******* * * * **** * * * ** ** *** * ** *** *** * * *** *** ****
* * * ** **** ***** * * ** * ** * * *** ** * * *** **** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* *** * * *** ** a,b,GCD;
* * * ** * * *** ** ** ** *** * * **** ** ** * * ** ** *
* * *** ** * ** ***
* **** ** ** ** * ** ** **
****** **** ** * * * * * * * * * * ** ***** ***** * * *
* * * * *** * *** * * * *
* *** * ** * ** * * * ** ** * * * ** * * ** * * *********
* * ******* ** ** ** * *** * 0;
}
** * **** *** * *** gcd(int a, int b){
**** **** * * * * * * * ****** * * * * * (!b) return (a);
** ** ** * *** ** * *** ** * * * ***** gcd(b, a % b);
* ** **** * * *** * * *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * ** ***
#include ** * ** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* * * ** * ** * * ** gcd, remainder;
* * ***** * * **
**** *** * ***** * (n != 0)
** ****** * ** ****
* * * ** * * * * * * ** ** * * * ***** ** * = m % n;
*** * * * * * * *** **** * *** * ** * = n;
* * * ** ***** * * **** *** **** * * *** * = remainder;
**** ** * *** * **
* *** * * * * **** * * *
* * ** *** * ** = m;
* **** *** ** * ***
** ** * * * ** * ** gcd;
}
int main (int argc, const char * argv[]) {
* * * **** *** * * ** number1, number2;
*** * ** ** *** *** * ** newNumber1, newNumber2;
* * * ** **** **
* *** ** ******* * * **
* ** * * ***** * ******* ** * * ** ** ** *** * * ** ** *
* ** * ** *** *** ****
* ** ** ** ****** * * * = number1 / gcd(number1, number2);
***** ** ** * ****** * ** * * = number2 / * *** number2);
* * * * ** * * * * *
*** *** * ** ** * *
**** * * ** * * **** ** ( ******
* *** ********* ** ** ** * * * ** * * * * **** *** * * * * newNumber1);
* ** ** * ** ***** *****
* ****** ** *** * **
* *** * ** * * * * * * **** * ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* ******* ** * * * * * a,b,c,d,e,f;
* ** * * ****** ** ** * * * * *** ** *** ** ******
* ** * * * * ***
* ********** * *** ***
** * * * ** * * * *** ** *
    {
** ** * * ** **** ** ** ** **** * * ** *
* * * * * **** *** **** * * * ****** *** ****
* * ** * * **** ** * * * **** **** * * *** *
    }
** ** *** ** * * * ***** * * * *
    {
* ** *** ******** ** *** *** * * **
* * ** * * ** **** **** * * ** **** * ***** **** ** ** * *** **
* *** * ****** ** * ** *** *** ** **** ***
** * * ** * ** ** ** **** * ** **** ***** ** * ** *
    }
*** **** *** ** ** **
    {
*** ** * ** ** * * **** **** * ** * *** * **
* **** * *** ***** * ** * * * * * * * * *** * ** ** * *** * **
* * ** * ** * * ** * * * * * * * * *
* * ** * ** ***** ** * ** ***** * ** * ** ** * * ****
    }
* * * *** ******* *** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.62
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 8k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 7.7k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 9.7k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 7.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users