2 like 0 dislike
15.1k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 15.1k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* ** * * ***** *** ** i;
**** ** *** ***** ** ** j;
* ** ** * * * * * * newNum1;
** ** ***** ** ** newNum2;
*** * * * ***** * gcd;
** *** *** * * ** rem;
** **** * * ** **** * * num1, num2;

*** * **** * **** ****** * ** **** * * * *** * ** * *****

* * * ** * **** * * ** * **
** * ** ** *** * ****

** *** ** * ** * != 0)
******* ** ** **
** * * * *** * ** * ****** * *** * *** * * ** * * = j%i;
***** * ** * *** **** * * **** **** ** ** ** ** * * = i;
** *** *** * **** * * * * * * **** ** * ***** ** = rem;
* ** * ** ** * *** *
* ** * **** * ** * ** **** ** *

* * * ** ***** ** * * * * = num1/gcd;
* ** ** ** * ** * * ** = num2/gcd;

** * ***** * * * * *** * ** == 1)
    {
** ** **** * * *** *** **** * *** * ** ***** * * * * **
    }

* * * * ***** * * ***** *
    {
* ** ** * * * ***** * * ** * ** * *** *** ** **** * **** * * **** *
* * * * * * ***** *

*** * ** ** * * * ** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** **** * ** * ** ** * ** *** * * * *** * ** * * *

* ******** * ** *** ** ** **
* ** ** ** ** **** * ** * ** ** * ** * **** **** * ***** * * * **

    else{
* * * ** *** * * * **** ** *** ** **
    {
*** * *** * *** ** * *** * * * ** **
* * * ******** *** ** * **** * ** * ** ** **** ****** ***** ***** **** * * ** && deno%i==0)
** ** * *** *** * ** ***** **** *** ******** * * * ** ****
* ** ******* * *** * * *** * * ** *** * * * * *** * ***** *** * * ** *** * ** * * ******
***** * * * ** *** * * * *** * ** * * ** * **** * * ** ** ** *** ** ** **** * *
**** **** * ** ** ** * ** * * ** * * * * ** * * * ** *
    }

* ** ** *** * * ** *** ** * ***
    {
**** ** * *** ** ** * *** * * *****
** * * * *** ** * ** * * * ** ** ** *** * ** * * *** ***** * ** && deno%i==0)
* *** *** ********** * **** **** * * * * ** ** ** * ** ** ** **
**** ***** * * ***** ***** **** * *** * **** ** * ** **** * * *** * **
** ***** * * ** ** ****** * ** *** * * ** * ***** ** * * * * * * * *** **** ********
* ****** *** *** ** ******* ** * * * * ***** **** ** ** *** * * ***
    }
* * ** * *** ** * * *** ********** ** * *

    }




** *** * * ** * * **** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * *
#include **** * * *** *

int gcd(int n, int m)
{
* * ** * ** ** * *** gcd, remainder;

* * * *** ** *** * (n != 0)
** * * * ****
* * * * * * * *** *** ** *** **** **** ** * = m % n;
** * ****** * ** *** * *** * ** = n;
** *** *** ** * ** * ** * ** * ** * ** * ** = remainder;
******* * *** ** *

* * ** **** * * * ****** = m;

* **** * * * *** * gcd;
}

int main (int argc, const char * argv[]) {

* * ** * * ********** * * *** number1, number2;
*** * * * * **** **** newNumber1, newNumber2;

*** ** ** ******* * * ****** *** * * * * * * *** * * *

* ** *** * * ** ** **** * = number1 / ** * number2);
* * ****** * * * * = number2 / ****** number2);

* * **** * *** * ***** *** ****
** * * * **** * ** * * * ** *** ** * * * ** *** **
** * *** * * *** *
* ** * * * * * * * *** **** **** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* *** ******* *** *
* * * * * **

int ** n, int m)
{
**** ***** * ** int gcd, * * *

* * * * * * (n != 0)
** **** ** {
***** ** * * * * * * ** **** = m % n;
*** *** * * ** *** m = n;
* * * * ***** ** n = *** *
**** ** }

** * ** ** gcd = m;

***** ** *** * gcd;
}

int main (int ** * char * **** {

** * *** * ***** int ** ***
* * **** int * ***** ***

*** *** * * * * * ** ** * ** *** ****** *

**** **** *** ** = * / *** ** ****
*** ** ****** ** * = *** / **** * * * *

** * * * ** if ** *** ** * * *
* *** * * *** *** ** * * * * * ** *
*** ** ** else
**** * ** **** * * * *** ** *** * * ** *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** *** ** *** *** * ** i;
***** ** ** ** * * *** j;
*** * * ** * ** ** newNum1;
* *** ** ** * * * * *** newNum2;
* * ** ** ** * * ** * gcd;
**** * * *** *** ******* rem;
* *** **** ***** ** * * num1, num2;
    
** * * * ** ** * **** * ** **** * *** **** * * * *** *
**** * * ***
*** ** * * ** ** ** * ***
* * * *** * ** ******** * **
** *** * ** ** * ** ***
* ***** * * ** * ** ** != 0)
*** *** ***** ***** ** * *
* *** ** * * * *** *** **** ** ***** * * = j%i;
* * * *** * ** * * * * ****** = i;
* * * ** ** * * *** * * * *** ** * = rem;
** * **** ** *** ** ** * ***
* ***** * ** * * *** ** *
    
* ** *** * ** **** **** = num1/gcd;
** ** * * * *** *** *** = num2/gcd;
    
* ** * ** *** * **** ** *** == 1)
** * *** * * *** *
* ** * ****** ***** **** ** ** * * ********* *** *** ** * * **
** * * ** ******
    
* *** * *** ** * * **
* *** ** *** *** * *
** * ** ***** ** *** ** * * ** ** * * **** ** ** ** * ***
**** * *** *** * ** * *
    
***** *** ***** * * * * *** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * * * * * ** ** **** * i;
**** ** * ** * ** * j;
* ** ** ** ** **** * newNum1;
** * * * ** ** * ** newNum2;
** * ** **** * ** * * * gcd;
* ** *** ** *** * *** *** rem;
* * ** * *** *** ** **** *** num1, num2;
    
**** * *** * ** * ** * ** ****** * ** ****** *
* * **** * ** * *******
*** ******* **** * *
* ** ** ** * *** ** *
***** * ** * ** ** ** **
***** *** ** * ** ** * ** * != 0)
***** * *** ** ***
* * * * ** * * * * ** ** = j%i;
* * * * ***** ** * * *** ** * ****** = i;
* **** * * ** **** *** ****** ** * *** = rem;
** * ** **** * ***
** **** ** ** ** ** * *
    
******* ** * *** * * = num1/gcd;
** ** *** ** * ** * * ** = num2/gcd;
    
** * ** * **** ** * * * **** * == 1)
*** *** * ** *** * **
** * *** ** * ** * * **** ** * *** * ** * * * *** ** * ** ***
* * * ** * ** * **
    
** * * * * *** * ** *
* ** * * ******* ** *
** * * *** ** *** * ** * ** * ** ** *** * ** * **** * * ** * ** * ** * * ** *
* * **** *** * * * **
    
*** * * ** * * * ** ***** *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* *** * * ** * **** ** * ** ******* *********
* * * * * *** * * * * * * **** ** * *** **
    {
** ** * * *** * * * ***** * ** * * ** ** * * * * *
*** * ** ** ** * * ** ****** ** * **** ** ** * ** * **** *
******** *** * * ****** * * **** * ***
**** * * * *** ** * * *** ** * **
* * * ** * * * * * ** * * ** * ***

* ** * ***** *** ** *
* * **** ***** **** *** ** **** *** * **** ***** *** * **** *** * ** * **** * *** * * *
* ** ** **** * * ***** *** * * * ***** ** *** * ** * **


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* *** * ** ** * *** ** * a,b,GCD;
** * * * ** * ***** * ** ** * * * * * ***** ** ******
** *** *** ** * * ** ** * *****
* * ***** * ** * * * * *
**** ** * *** **** ** **** * * * * * * *** * * ***
** * **** * **** ***
** ** *** ** * * * * ** * ** *** * **** ** **** *** *** * * *
** **** * ** *** ** * * 0;
}
* ** *** * * * * ** * gcd(int a, int b){
* * ** ** * * * **** * * * ** ** * ** ** * (!b) return (a);
** * * * ******* * * ** ** *** *** * *** ****** gcd(b, a % b);
**** * * ** * *** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** ** * * *
#include *** * * * *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
** * ** * ** * **** gcd, remainder;
* * * ** * * * *** * * *
* * * **** * * ** * * (n != 0)
** ** * *********** * *
* *** * * * * * * * * * * *** * * ** * = m % n;
* ** ** * ** **** *** ******** ** ** * ** * *** = n;
* * **** ** ** * *** * *** *** * * * = remainder;
** ** ** * * * *
**** * * * * * *** *
* * * *********** ** ** **** * = m;
*** ** * ** **** **
** * *** * ** *** **** ** *** gcd;
}
int main (int argc, const char * argv[]) {
********* * * * * **** * number1, number2;
* * ** * * * * **** newNumber1, newNumber2;
** * *** * ** ** *
*** ** * ** ** *
** * ** *** * * * * * * * * **** * ** * * * ** * *
** ** * *** * * *****
** * * ****** ** * ** ** * = number1 / gcd(number1, number2);
** *** * ** * * *** *** * *** = number2 / **** number2);
* * ** * * * ** * *
*** * ** * **** ** **** *
* * * * ** * ** * * ( * * * *
* * * * ** * **** * * * **** ** *** * * * *** ** ** ***** * ** newNumber1);
* * * * * * ********
* ** * * * * * **
******** * * * * ** ** * ** * ** ***** * * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* ***** * * ** *** * * a,b,c,d,e,f;
**** * * * ** *** * ** * * * * * ** ** ** * ***
** * **** * ** * ** *** **
* * * * * * * ** *
* ** ** **** **** ** *
    {
*** ** * * * ** *** * * * * ** *** ** ****** **
** *** * **** ** ** *** * * * **** * * * ** ****
* * * * * * ** *** * *** * *** *
    }
*** * **** *** * *** ** * ** * *
    {
* * * ** * ** * *** *** * **** *** ** ** ***** ** * *
*** * * *** ** * ** ** **** ** ** *** * **** ** **** * ** * * *
*** ** *** * * * ****** ** *** * * * * *** *
** ** ** *** * * ** * * * * * * ** ** ******** ** *** * * * *
    }
** * ** * *** ** *
    {
* * * ** ** ** * *** * * ** ***** *** ** *** *
* ** ** ** ** * *** * * ** * ** **** * * * *** * **** *
* *** *** * * *** * * * **** *** * * *
** *** * ** * *** * ***** * ** *** * *** * * **** * ** **** **
    }
* ** * ** **** ** * * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.7
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 15.3k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 15.1k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 19.4k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 14.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users