11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
16.5k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 16.5k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

 * * * ***** ***  *** **  **  i;
  * ** **    *  **  *   * * * j;
**  *  ****   * **   **  *** *  newNum1;
 * *  **    ** **  *** * ** * newNum2;
* * ** ***** ** **    **  * gcd;
** **   **  *  ***   **** *    rem;
* ***        *  **** *** *  *      num1, num2;

**   ***  ** *****   *** ** * * *** * ****   *   *** *  ****  *    

   ***  * **  * ***  *   ***  
 ** ****   *       ***   *    

*     * **  ***** * * * *** != 0)
** * **    ** *****  * *   *
 *** * **  * * *** *** *      ****  * * *  ** * ****   = j%i;
* * ** ** * ** * *  *  *  *  ***** **  ** ********  **  *  = i;
   ** ***  ** *   * ***** * ***    * **  ***   **   * * = rem;
* ****   ** **  *  
 **   *  *     **    * *  * **

 ** * ** *******       * * * ** = num1/gcd;
* *  ** *  *   ** **** *    ** ***    = num2/gcd;

 *** *** * *      *** *  *     ** == 1)
    {
  ***  *****  * *   * **** *  **** ***  *  ** ***      * * ***    * *    ****  * **
    }

   * *   ***** *  ***     *    **   
    {
*     ** **   * *     **  ** *    *   ** * ** *  ** * ***      ***  ****     *   ****
**    *  * * **   **  *   ** *  

 *** * * ***        *****  *   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
  **  *   *    *    *   * * *  *  **   * *    * * * ** *** * *  **  * 

 * **  * *      ** **   * **   ****
 *    * * *  ***** ** * **  *** *    ***** *  *   * * **     *    ***   * * * *** *  * 

    else{
**   ****** * * * *   * ******     ***
    {
       * * * * ** **   ****  ****  * *
* * ** *** *     *  *   ** *****  *  *        **  ** * * ***   ** **** ** *****   ** *** && deno%i==0)
* *** *  *  *** *     *    ***     * * * *         *    *  *  **   ***  *   **  *
**  ***  **** *     **   *** ** * ** *** ***** ***    ***   ** *  *  ***  ** *   **   *   *** ******** *   
* * *** * * *  ***  ** ****** *****  *******  ** * **  ***  *  **  *** *** **  * *    *** *  *  **  ***** 
 * * ***  *   * *   *   *** *   ******     *   ***   **     **  ** **  *** 
    }

  **  *  **   * **  **    **       * * *  
    {
 ** ** *** ** *    *  *  *  **   **   * * *  ****  
 *** ***    *  ***** ** ** ** *  *    ***  * * ** * ** * ** * *   ***** *   ** ****    * ** *  && deno%i==0)
 *   **  *  * *** *   * *  ** **    *  *** *  ***    ** *******  **  **   *   * *
 *    *   * **     *   *   ***** ** * ** *   ***   *  **  * ****  ****  *      * * * * **   ** *
 **  *   *** * ** *      *****   *** ** *   ***  ***  * ** ****     *  * ****** *** *  * *** ** ** *     *
     * * *    **   * **   **** ******* * **   ***** *** * *   ** * ** ****  
    }
   ***  * *****  *****    *   * * **  *    *  *    *  **** 

    }




**  * **         ****    0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** **    ****  *
#include *** ******  

int gcd(int n, int m)
{
 *** ****** *     * *** *** * gcd, remainder;

**     **        * ** ***** * (n != 0)
     * **     ***  * *  *   *
****  *** * ** *   ** * ****** *  ****  *  ** *  **  * ****   ** = m % n;
  *  * ***  ***  * ***    ***   *** *  *   *  *  = n;
*****  * **** * ***** *** *  *  *****  *      * * *  ** = remainder;
   ***  ***** ** ***     *

****   ** * *    * **    * ** = m;

*****    **   *  *     *   * ** ***** gcd;
}

int main (int argc, const char * argv[]) {

 **  * **  *  * *    ******  * number1, number2;
 ** *     ** ** *  * **   newNumber1, newNumber2;

 **  **  **   ** * ***  *  ****  ** **   *    **  **  * *  ***** * 

******** *    **** ***   * *    **  = number1 /   * *  number2);
**** ***** * *  ***  * ** **  * = number2 / ** ***     number2);

   **** * * * **   **  **       ** ***** *  ** * 
***     * * ***  * * ***       *  *    ****  *  * * * * ** *
     * **    * ** *** *** 
 **      ***** *  *   **  * *    ** * **  **    *** ***   * 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
      ** ** * ** ** 
 * ** * **  * ****** *

int ***  n, int m)
{
  ** *  ***  * int gcd,   * *  *

** * **     * **     * (n != 0)
***  * ***    {
* **  * *   **  *    **   **  * * ***  = m % n;
 ***  * ***    *  ***  **  *  m = n;
 *  *    **  *  *  **       n = *  * *
 ** **  *  *  }

 ** * *        gcd = m;

 * **  *  * *  **   gcd;
}

int main (int   * *** char *  *  {

   ** *     ** * int *     * **
    *  *   * int  ** * ** **  ** *

 *   * *  * * ** *** *    *    *** **** *  *   *       ***   **** *

***        ** **  ****   =  *   / *********  * *  
  ** * *    ** **         =       / *   * ***  * *   

* *  ** *     *** if **    * *******     
   *                  *    ********         * *  *   *  **  
****  ****   else
  *  *  *    * *   *** **       * *  *   **  ***  * ***  **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
*  **** ****    ****** *** **  i;
 ** *  ****  **** ** *** *   *** j;
 *  * *  **       * * * * *    newNum1;
 * *     ***   ****  *  ** * newNum2;
* *   ** * **  * * * * ** * *  gcd;
   * *   **   *  *   *****  *     rem;
 **** *    *    * * * ***  * *   * num1, num2;
    
* ** ***** *   * ** **** **   *  *   *  * *   *** *      *  ****    *
   ** * **   * ***  * *    * 
 **  *   ****     * **** *  
     * * * *  **  *   ** * * *
** ** **   * *   * **   *** **  
     ** ***      **    **   * *** != 0)
  * ***   *  * **   ** **
   **  *  **  * **    **  **** * ** *   * *** *    * = j%i;
* ******* *     ****** * *  *** *  **  **  **  **** * = i;
    **   *  *   **  * *  **    * ***   *  *     *** ** = rem;
* *  *  * ** ***   * ** 
** ***  * **  *     *  *** *    *
    
*    *   ****   * ** ***   * *   * = num1/gcd;
   *  ********* * *       ** ** * * = num2/gcd;
    
 **    ** ** *       * ** **     * * *  *  == 1)
* *    * *  **** *  * *  **    * 
 *  * * * ***  ** * **  * * *  *****  *** *  ** ** **  ** * * *  *** * * 
 * ***  * ****   *  *  *
    
 * * *   *** *    ******** ***
 * **    *** ** **** * * 
**   * * *  * *   ****     ** *** * **  *  ****   *  **   * *** **  * *   ** ********    *
***     ******** * ****   
    
   **   * * *   *    **     ****  0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
*        * ***** *  **  i;
** **  * ***  ** *** *   *   ***** j;
* **  ******  *******  *  *    newNum1;
*****    * * *  ****    *  newNum2;
   * *****         * * * ***  gcd;
**   *      * *   * *    ** rem;
    ** ** * **** **** * *  * num1, num2;
    
*  * **   ** **** ** *  **   *  *   ***  * *** **      *  *       ** 
***** **  **  * ** * * *   **   
  * * * *       * **    ** * 
 *** **         ******  ** *****   *
  ***  *  ** * **   ****   
* *  ***  **** **  ****  *  * **** != 0)
* ** * ***** * **   * *   *  *
*    *  * *  ****  * * ***    ***  *  *****     ** ****   = j%i;
 ***   ** * ***  * *******   * *         * * ***   **    ** = i;
  ** * * *** **  ***  **    **     *  *    ***   *   *    *  *   = rem;
***   *  * * *  *      ** 
*  **** **    * **** *  *****   
    
*   *   ***  ***   *  * *  **  *  = num1/gcd;
** *   * **** * *  *  * *   ***   *  = num2/gcd;
    
* *   * ** * **** * *** *** * **  == 1)
 *     *   ** *  *  *** *** *  
 ** *** * *      *** ****     *****   ***  ** * * * * ** ** ** ***  ****** * ** ** 
* *  * ****  ****  ****  *** 
    
 * *  *       * **   **** *
  *  ***  *  *  *  *****  
** ***  ** * * *  ** **   * *     * *  ** ** *** **  ** * * * * *** ** *   * * ** ** **  * **** **** **
  *     * **  * *** **  * 
    
  **    * ****    *    ** * *** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
 *   * * ****   ***  * *** *******  **** **  **    * ***** * * *** ** 
*    * * ***   *** *** *    * *    ** *  **   ****  ** ** **  
    {
***     ****  **  *   ******   **   ** *  ***** *  * ****   **   *   *
 *  ******  ***  **  *** ****     ** **  * ** ** *   *  **** ******
** ***  ** **  *** *** * *       * ** ** 
  *  ** * ** ** *  *   * *  **  ** **    * ** 
  * * * *     *  *  *  * **  *   *   ***    *

*   * ** ***   *   *  ***  *  **  
 **  ****  *  ** *  **  **  *  *  **  **** ** *  ** **      *** * ******    *     **   * * * * 
 **  *** **    ** **  ***  * * ****** ****    *     **    *** ** * *  *** **


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
** *****  **  **  * *  *  a,b,GCD;
 * * ***    * *** *  *  ** ***  *   *** * * ****       * ****  **
   **  * *****  * *  *  ***  *  **    *
**** ** *** *** ** *** * ***   * * *** 
    *    ***** ***  * *  **  * *  * * ** ** ** *        * ** ***  *
   *** **        ******   *****
    *  *  **  **   *   ** * ****   * ** * ****  **   ** * *   *  *  **
   ****  * * *   **** **   * 0;
}
 *  **** * *** *  **  gcd(int a, int b){
  *   ** *  **  **** * * *** *  * * *   *      *** *  (!b) return (a);
* ** **  *  *** ** **** **   * *  * *   * * ***   ** **  *  gcd(b, a % b);
**    *  *  *    *******    *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ****   *   * ** 
#include  *  *     **  ****

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
    * * *** **** * ** **    gcd, remainder;
* *  **  *** ***    *    * 
****    *  *** * ******* * * (n != 0)
  *  *  *  * *   *  ******
* * *  **     *  **    *  * *   **** ** * *   *****  ***  ** = m % n;
***   **        * ****   *   *****  **  * *   ** ***  **  ** = n;
*** **  *   *  **  *    ***   *** *   * * **   *   *  = remainder;
* *      ****  **  *** * *  * *
   * *** * *  ***  **   *  
*** ** *  ** ** *  **** ***     = m;
*****  **   **** ** ****  
**  *  * *        **  * *  *    gcd;
}
int main (int argc, const char * argv[]) {
* **  *****     *    ****  *  *   number1, number2;
**  ****** *  **     * *** newNumber1, newNumber2;
*     * *** *  * ** *** **  * *   
** **** ** *  **  * 
  ** * * * * * **  ****   * ** ****  **  *     ** **   ******  *  *   *   *
  *  *** **  ** *  * *** *  *
   * *  ** *   **   ** * * * * ** *  = number1 / gcd(number1, number2);
*  *     * * *** * ** **  * * = number2 /  *   *  number2);
  ** *    **  ** * ***  *****  
 **** *  *    *****       ** *
   *** *** *** ** ** * ** **  *  (   * ***  ***
**** * **  ***  *** **  * *  ** *   * ****  * ***** *  * ***   *       newNumber1);
 *      **  ******** *  **   *  
 * **  *****   *     *  **   *
** *  **  ** *    ** *** *    *   * * *   ****      ***  newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
 *   *** *  *     ***  * * *   a,b,c,d,e,f;
 **  *     *** * *** ** ***   * ** *     * ***  * * **   **  * * *  *
* *** **   **** *  ***   * **  
*   *  ******* * **** ****    
    *  *        **      ***   * ** ***
    {
    *       **  **  *  *   *    **** * ******* **** ***
**  *** *    *** * * ** * *  *   *  *  ** * *      ****  
* **   *  ***  *  * **  * **  * *    * **  ****    *
    }
    *** * **** *   * ** ** *** *  ***
    {
* **     *    **  ******* **  * *   ** **** *   *  * *  ** **** *
** **  ** *** * * * * **     * ****** *****    ** **  * * **  ** *  * *    
 **  * ** *      **  *** ***  ***  ** **    ** **   *   **** 
        * *  * ** *** *  *    *  *  *   * *  *  **  *   * **  *  * *  ** * *** *  
    }
**  **  *   * **    **   * * ** *
    {
*** *   ** * **   ***  * * * *  * *  **** **  ** ****   ** * *
  **  * *  * * * **  *   ** *  ** *   ** * *  **** * *       **   *** ***** * **
*** *** *   ****     *  *** *    ****  *  ***  ** *
   **  *  ** *  *  **  *   ****  * *     **  * **   ** **       *       *  *  * 
    }
**          * *   * * *** * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 16.6k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 16.3k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 21.4k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 16.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users