2 like 0 dislike
11.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 11.9k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

*** ** * * *** i;
* *** ***** * ***** ** j;
* *** ******** * * ** newNum1;
* **** * *** *** newNum2;
** * * ** ******* *** gcd;
* * * *** ** **** rem;
* *** *** **** * ** * num1, num2;

* * * * ** ** *** **** * ** * ****** **** * * * * * *

* * **** **** ***** * * * * *
** **** ** ** ** ** *

* * ** **** ** * * ***** != 0)
**** * * *** ** *
* *** ** * * * * * * * ****** **** * * * = j%i;
** ** *** *** * * * * * ** * ** ** = i;
* ** * * ** * ****** * ** ***** * * * * * ** * * = rem;
* ** * * * * * ** * *
* * ** * * * *** **** * * ***

* * *** * ** * * * * *** = num1/gcd;
* *** * * * ** * * * = num2/gcd;

* ***** **** ** *** *** ** * == 1)
    {
**** * * * ***** * ** * *** * * * **** * *** **** * ********* ****
    }

*** * *** * * * ***** **
    {
**** ** *** ** **** ** *** * ** ** ** ** * * * * ** ** ***** ** ** **
** ** ****** *** ** ***

** * ** * *** * ** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** * * * ** **** * ** *** * ** * * * *

* *** * *** *** **** ** *
* * * *** * * ** * * * * ***** * ** *** * **** * ** * * * * *** ** *

    else{
* **** * ** ****** **** ** ** *
    {
* ** * **** * * ** ** *** *
* ***** ***** *** ***** * ** *** **** * * * **** * * * *** * && deno%i==0)
** ** * * * ** *** * ** *** * * * *** ** *** ** * * ** ** ** **
*** * ** ** **** *** ** * * ** * ****** * * * ***** **** ***** * ** ** ** ** *** ** *
** * * * * * ***** * * * * ****** ** * * * ************** * ** * ** *** ** **** ** * * *
******** ** ******** ** *** * * ** ***** ** * * * * * * ** *** * **** **
    }

* ***** ** *** * ** **** **
    {
* ** **** **** * * * * * **** ** ***
** ** ** ** * * * ****** * * ******* ** * * **** *** ** * * ** * * && deno%i==0)
** ** *** *** **** * * * *** ** * ** *** * **** * * * *
** * **** ** ** * **** * * * ** * ** **** **** * ****** * ** * ***** *
** ** * * *** * ** *** *** *** * * ** * * **** ** *** * ** * * * *** *** * * ***** **
* ** *** **** *** ** * * ** *** ** **** ****** ** * * *** * *
    }
* * * * ** ** * * * *** * * * ** *** **

    }




*** ** * ** *** * *** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *** **
#include ***** * **

int gcd(int n, int m)
{
* *** * ** * * gcd, remainder;

* * * ** * *** * ******* * * (n != 0)
**** * ** ** *** *
* **** * * * * * * * *** ***** * * * *** **** = m % n;
** ****** *** * *** ** * * ***** * ******** * = n;
** *** * * * * *** *** * ** * **** * ** = remainder;
* * **** ** * * **

* * * * * ** * * = m;

* ** **** ***** * *** ** ** gcd;
}

int main (int argc, const char * argv[]) {

* * *** ** * * number1, number2;
** *** ** ** ****** * * ** newNumber1, newNumber2;

** * ****** *** ** *** * * ** ******* * * * * ** ** **

* * **** ** * *** *** * ** ** ** ** = number1 / *** ** number2);
* ** **** * **** ** *** * = number2 / * *** * number2);

** * * * *** * * *** * * *** **** * **** ** * ***
*** * * * ** ** ** *** * *** *** ** * ** **** * **
* ** ** ** ** * * ** * **
* **** ** * * ***** * ** * ** ** * * * **
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* *** * *** ** *
****** *** ****** ** *

int * ** n, int m)
{
** *** int gcd, * *

** ** ** * * (n != 0)
* * * * *** {
* ** *** ** * * * **** = m % n;
* * ** * ** * * m = n;
** ** ** * * *** * * n = ***** *
* * **** }

** ** * **** gcd = m;

* ** *** ** ** * gcd;
}

int main (int * ** *** char * ** {

* ** * * * int * * ** *
** * ** int ** ** * * * *

** * * * * ** ** *** ** ** * ** ** * ** * **

*** ****** ** ** * = * / ** *** ***** *
* * *** ** ** = * / * * *

* * * ** if ***** *** * **
** * * ** ** * * ** ****** * * * *** * * *
** * * * * else
* * **** * *** ** * ** ****** * * **** * ***
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
**** * * ** * **** i;
** *** * ****** * * * j;
*** * *** ** ** ** * newNum1;
**** * *** ** * * * * newNum2;
* * * **** ***** * gcd;
* * ***** * * * *** ** *** ** rem;
*** * *** ** * * ** * num1, num2;
    
* * * *** * * * * * * *** * ** * **** * * * * * * ***
* * ** * *
* * * ** * ****** * *
** * * ** * ** *
* ** * * *** *** * ** ** *
* ** * * * * *** ** * != 0)
** * * ** * ** ***** ***
*** * ** * **** *** * ** * *** * *** * * ** * = j%i;
* *** * * ********* * *** ***** * * ** * = i;
* * ** * *** ****** *** * ** *** * * ** ** = rem;
* ** * * ** * ** ** *
** * ** * ** * *** *** ****
    
* ** * * *** ** * *** = num1/gcd;
* * * * * * ** ** = num2/gcd;
    
****** ** * * * * ** **** == 1)
** * * **** ** * * **
****** ** * * * ** ** *** * * ** ** *** ** * **
*** ** * *** * ** ** * *
    
* * * * * ** **** **** *
* *** ** *** *** ** * *
* * ** *** ******* *** ** ** * **** ******* ** * ******* ** * *** * *
**** ** * ******** **
    
********* ** ***** * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* *** **** * * * * * i;
* ** ** ** **** *** * *** ** j;
** **** ****** * * ** *** ** newNum1;
*** * * ** *** * * * * newNum2;
** * * * ** *** *** * gcd;
** **** *** * ** ** ** **** rem;
* *** **** * ** *** * ** * num1, num2;
    
* ***** *** ** * * * * ****** ** * ** * ** * ** * ****** * ** *
** ** * **** * ** *** **
* * * * *** * * ** **
* **** * * ***** * * **
* * * * *** * * * * *
* * * *** * *** ** *** * * ** * != 0)
******* * * * * * *** *
* * * * * ** * ** * *** * * * * * ** = j%i;
** *** * ** * * ** ** *** * *** **** * * = i;
* * * *** * **** * ** ** * *** ** * *** = rem;
*** ** * * * ****** ** *
* ** * ** * * ** * ***
    
* * *** ***** **** * ***** *** = num1/gcd;
*** ** * *** * * * = num2/gcd;
    
* ********** * * ** * **** == 1)
* * * * ** * * ** *
* **** *** ** *** **** * *** ** * **** * * * * * * * ****
*** ** * ** * ******
    
** **** **** * * *** * * * *
** * ** ** ***** * ** *
* * * ****** ** * * * ****** * ** *** ** * ** * * ** * *
* * * * ** * * *** * *****
    
****** *** * *** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** *** *** *** **** * ** * * *** ** ** * *** *
** * ** * ***** ** ** * * * * * * ** ** *** ***
    {
* ******** * * ** ** ** *** * * *** * ** *** *
** * * ** ** ** * *** * * * * ** * ** * * ** * * ** ***
* * ** *** *** * *** * **
* *** * * * *** ** *** * ** * * *
* * * ***** ***** * * * * ** *** **

* ** * *** *** * * * * *
** ** * * * *** ** * * ** * * * * * * **** *** * *** * **** * *
* ** * * * * **** * ** * ***** ** * * ** ** * ** ** * **** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* ** * *** ** ** * * ** a,b,GCD;
** * * * * *** ******* ** * ** ** * * *** * **
* * ****** ** *** ** * **
* ***** * ***** * ** *** * *
** * * * * * ******** * * * * * *** ** * ** *** * ** * **
* * * ** *** * ** * *
** ** ** * * * *** * *** *** ** * ** * * *** ** * * * **
* * ******* ****** *** 0;
}
* *** * * *** * ** * * gcd(int a, int b){
* * **** * * * ** ****** ** ****** ** * (!b) return (a);
* * *** **** * * * **** * *** * ******** * * * ** gcd(b, a % b);
*** ** * ** ********* **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * **** ** **
#include * * * * *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* ** * * * gcd, remainder;
*** * * * * ***** * ** *
** *** *** * **** * *** (n != 0)
*** * * ***********
** ***** * * ** * *** ** *** * * * *** * * ** = m % n;
**** * * * ** ** * ** ** * * *** * * ** = n;
* * * * * ***** * * * ** ** *** ***** * = remainder;
* * * * * * * ****** ***
* * *** *** * * * * *
* ** ** * * *** ** ** = m;
* ** *** *** ** * * *
****** ** **** * * ** gcd;
}
int main (int argc, const char * argv[]) {
* * ***** * *** * * number1, number2;
* *** ** * ** ** ***** newNumber1, newNumber2;
* * *** **
*** ** * *** ** ***** *
** * * * * **** * ** **** ****** * * * ***** ** * **
* ** * * * * * *
* *** * * ** ****** = number1 / gcd(number1, number2);
* ** * * ** * ** * = number2 / * *** number2);
* * * * * ********* * * **
** * * ** ** *** ** *
** ** ** * * * ** * *** ( ** *
** * **** ** ** * * * * * ** * ** ** ** **** *** newNumber1);
* ** *** * *** *
* * * **** ** *
** * ********* ** * * **** ** *** **** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** * * *** ** ** *** * * a,b,c,d,e,f;
** *** * * * ******** * * * *** *** * * *** * * **
*** * **** *** * ****** *
** * ** * * ** * **** ***
** ** **** ** * * * ** *** * **
    {
* **** * * ***** ** ** * **** * * * *** ****
* * ** * * ** * * **** ****** * ** ****** *** **
** ** * *** * ** ** ** * * * * ** * * * *
    }
* *** ** * * *
    {
* * *** * ** ** * * * *** ** * * ******
* ** ** ** * * **** ** ** * *** ** ******** ** ** * *** *
* * ** * ** * * * * *** *** * *
**** * * * * ** ** *** ** * *** ** * ** * * ** ** ** * **
    }
* * ** * * ** **** ** * *
    {
*** ****** * * **** ** ******* * ** * *** * * **
* * * ********** ** *** *** **** * **** ** * * * * ** *
*** * * *** **** * ** * * *** *** ** ** * * * * **
** ** * ** ** * ***** *** * ** * ** * * * * * * *
    }
* * * * * ** *** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.38
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 12.2k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 11.8k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 15k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 11.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users