2 like 0 dislike
13k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 13k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* * * * *** ** * ** * * i;
***** ** ** ** * j;
* *** ** ** ** *** *** * * newNum1;
* **** * * ****** * newNum2;
** * *** * * *** *** * * * gcd;
*** ** * * * * * rem;
** * * * **** * * num1, num2;

* *** *** ** *** * * ***** * * * * * *

** * * ***** ** **
* * * *** * ** * * * * *

********* * * ** ** * * * != 0)
**** * ** *** *
** * * * * * *** * ** * * ** ** ** * * ** ** * = j%i;
** * ** *** * ** ** **** **** ** ** ** = i;
*** **** ** * * ** * * * ****** ** * *** ** = rem;
* * * * * * * ** *
* * ** ** *** ** *** *

********* *** ** ****** ** = num1/gcd;
* ** ** * ** * ****** *** = num2/gcd;

* *** * * * ***** * ** * ** * == 1)
    {
*** ** * * ** ** ** ** *** * * *** *** ** * ** *** *** ***** * **** *
    }

* * **** ** * * *
    {
* **** * *** **** **** * * *** * * *** ******** * ****** ** *** *
*** ** * * * * * * ** **

***** ***** * ** * **** * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** * * * * * * * * ****** * * * ** *** **** **

***** ** * ** * *** ** ** * ***
* * ** * * * *** **** ***** * * **** ** * ** *** ***** *** * * **

    else{
**** * **** * ** ** *** **
    {
** * * ** * ** * *** **
* *** * ***** * * ** **** * * * * *** ** * **** * *** * * ** * * ** * * && deno%i==0)
* ********* **** * * *** * ** * **** * * * * * **** *
* * * ** * * * *** **** * ** * ** ** * * * ** * * * * * ** ** * * * * * ****** ** ***
**** * *** * * * **** * * * * *** * * * * *** ** * * * *** * ***** ** ***
****** * * * **** * ** * ** * * ** * *** ** ** * ** ******** ** * * *
    }

* * **** * ** *** ***
    {
* *** ** ** * *** * *** **** **
*** * ** ** ** * * * *** * ** * *** * * *** **** ** ** ** && deno%i==0)
* * * ** * ** *** * * ** * *** * **** **** * ***** ** ****
* ** * *** * ****** * * * ** ** *** *** *** * * ** * * **** * * * * * ** ***
* * * *** * ******* * * * * ** ** *** * ** * ****** ** **** * ** * * *** **** * ****
* ** * ** * * * * * ** * * * * *** * ** * **** * * * * **
    }
* **** * *** * *** **** ***** ** * ** *

    }




* ** ** * ** * * ***** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * * ***
#include * * ** * **** **

int gcd(int n, int m)
{
* * *** ** * * * *** ****** gcd, remainder;

*** *** * * * **** ** (n != 0)
* * ******* *** *****
*** ** *** * * ** * * * * * * *** * * * ** * = m % n;
** ** * * ** ***** ** * ** * * * * **** * ** = n;
** * * ** *** ******** * * ****** * ** = remainder;
** * * ** ** ** * * ***

* ** *** ****** * ** * ** * = m;

*** * * * ** ** **** ** gcd;
}

int main (int argc, const char * argv[]) {

***** * * ** * *** * number1, number2;
***** * * * * * * ** * newNumber1, newNumber2;

* ******* * * ****** * ** * ** * * ********** ** ***** ** *** **

* ***** **** * * ** *** ** = number1 / * * number2);
****** **** ** ** * ** * = number2 / * * number2);

* * **** *** * ** ** * * * ** * ***
* * * ** * * **** ******** ** * ** * * * * ** *
* * ** ** ** * * ** *
* **** * ** * ** ** * ** *** * * ** **** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * * * * ** * *
**** ** * ** ***** **

int *** * n, int m)
{
* * * * ** int gcd, * *

* ** * ** * (n != 0)
** * * * {
** * * * * ** * * *** **** * = m % n;
* ** * **** ** * * m = n;
* * * ** * ** * * ** n = **
* * ** * * * }

** *** * * *** gcd = m;

* * * * ** * gcd;
}

int main (int * ** ** * char * ** {

***** * ***** int * * ** *
**** *** int *** * * ****

*** *** *** ** * ** **** **** * ** ** ** *** * *

* ** * * * = * * / *** * *
* * * ** *** ** * = ** / ** * * *

* *** * ** ** if * * * ***** *
** *** * **** ******* * ** ***** *** *** ** *****
** * * * else
* * * * * * * ******* *** * ***** ** * * ** * ** **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * * ** * * ** i;
* * * * * * j;
** ** ** * **** *** newNum1;
**** * ** * newNum2;
*** * * * * ** * * * gcd;
*** * ** ** ** rem;
**** **** * * * * * num1, num2;
    
** * ** * ***** *** * * ** *** *** ******* *** * *
* * *** ** ** *
******* * * * * * *****
**** * * ** ****** * * *
** * *** **** * *** ** * *
* * **** **** ** * ** ** **** != 0)
* ** * ** ** * * *
** ***** ** * * ** ******** ** * *** * * * = j%i;
** **** ** * ** * *** * ****** * **** * * * = i;
** *** * ** * * * * ** *** ** ** ** ** **** = rem;
* ** ** * * ******
*** * *** *** * * *
    
** * * * **** * * ** = num1/gcd;
*** * * * ** * ** **** = num2/gcd;
    
*** * * * *** ****** == 1)
**** * * * ** * ** *
* * *** *** ** * ** * ** * *** * * ******** ** *
* * * * **** * **
    
* * ***** ** * * **
* *** ** * ** *** * *
** * *** * *** ** * * * ** * * ****** ** *** ** * * ** * ** ** ** * *
** *** ** ***
    
** ** ** ** ***** ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ** ** * **** * **** i;
*** * ***** *** * * * j;
* * * ***** * *** ***** newNum1;
** * ** * * * ** ** * ** newNum2;
****** * *** *** ** ** ** * * gcd;
*** * *** * ***** * ** rem;
** ** ** **** *** * ** ** * * num1, num2;
    
*** **** * ********* * **** ** * *** * ** ***** ** * * *** ** **
*** ** *** * *****
* * ** * * * * * * *
**** **** *** * *** **
*** ** * *** ** * * ****
* ** * **** * ** * != 0)
***** ****** ** * * ****
* *** * ** ** * ** * * * * * * * * ***** *** = j%i;
**** ***** ** ***** * ** * * * * * * * * = i;
* ** * * * * * * *** * * *** ** *** * ** = rem;
* ** * * * * * * ** * *
* * * * **** * **** ***
    
* ** *** *** * * * = num1/gcd;
* * * * * * * **** * * = num2/gcd;
    
* * * ** * * ** * ** * == 1)
*** * * * * ** ** ** * *
* * **** * *** * *** * * * * ** * **** ** ** ** ** ** *
* **** ***** * *** **
    
*** ****** * * * *** **
* *** * ** ***** ** *
* * * * ** * ** * * * ** * ****** *** * **** ** ** ***** * ** ** **
*** * ** ** * ** * *
    
** ** ****** * * * ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** *** * ** * * * * * * * * ** **** * *** *
* *** * * * * ***** * * * * ** ** *** * *
    {
** * * ******* * * * *** **** * * * ** ******* *** **
** ** * * * ** *** * * ** * ** * * * ***** ** *
* * * * * * ** *** * *** ** * * **
* ***** *** * * ** **** ******
* * *** * * *********** * *** **

* * * *** * ***** ** ** ****
* ****** * * ** ** **** * * * **** ** * ** ****** *** ** ** * * * * * **
*** ******** * * ** ** * * ** * ******* *** *** ****** * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*** ** *** * * * ** a,b,GCD;
** ***** * ** * ** *** *** **** * **** *** * ******
** * **** * ** * **** **
** *** *** * * * *******
* *** * ** * ** * * * ** ** ** * * *** * ** ** **** * *
**** ** * * ** *******
* * * ** *** ** ***** * **** *** **** *** * * *** * * * ** ** * *** ** * **
* * ******* ** ** *** * 0;
}
* *** ** * **** * * * * gcd(int a, int b){
**** * *** * ******* * ** * * * *** * * (!b) return (a);
* ** *** * ** ** * * * ** **** * *** *** * gcd(b, a % b);
* * ** ** ******** ** *****
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** **** *** *
#include * * ** ** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* ** ** ** ** * * * ** ****** gcd, remainder;
** ** * * *** * * **** * *
** * ** ** * * * **** * (n != 0)
**** *** * *** ****** * ***
** *** * ** * *** *** * * ** * ** * *** * * * = m % n;
***** **** ** **** * * **** * *** ** *** * = n;
** **** * **** * *** *** ** * *** * * * **** ** ** = remainder;
**** * *** * ***** ******
* * * ** * **** * *
* * ** * * ***** *** ** * * = m;
*** * ***** ** ** *
* * *** **** ********** * * gcd;
}
int main (int argc, const char * argv[]) {
** * ** * ** * *** * * *** number1, number2;
** * * * * **** ** newNumber1, newNumber2;
* ** * ******** *****
******* * * * * ** * *
* ** * *** * **** ** **** * * * ** **** *** ** * ***
* ** *** * **** *
* * *** ***** ** ** * ** * = number1 / gcd(number1, number2);
** ** ** * * * * **** * = number2 / *** * number2);
* *** ** *** * * *
* ***** *** * * *
* * * ** **** * * ** ( *** *
* *** * ***** * ** *** * * ** * ** *** * *** * * * newNumber1);
* * * ** * * * * * ******
* *** * * **
** * * * * * * * * ** ** * *** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** * * * * * * *** ***** * ** a,b,c,d,e,f;
* ** * * * * **** ** * ** * *** **** * *** *
** * * *** ** *** * ** ***
** *** ***** * * **** * * *
* * *** ** ** * * ********
    {
* * ** * * *** * * *** * * * * * * *** *
* **** * *** ** **** *** * * * * *
** ** ******* *** ** * * **** * * * * * * ***
    }
* *** * * *** * ** ** ** * * **
    {
** ** * * ** ** *** ****** * *** * *** **** * ** **
* * ** **** * * ***** ** * * * ** *** ** ** *** ** * ** ** * * ** *
**** ** ** * *** **** *** * * * * **
**** * *** * * ** **** **** * ** **** * *** ** ** * * ****** **
    }
** ** ** ** ** * ** **
    {
** * ** * ** **** * * ***** *** ** * ** * **
** * ** * * * * *** * ** * * ** *** ** ** ** ** * * * * * * * *
*** ** ** * * * * * * *** * *** ** * *
* *** **** **** * * ** ******** **** ** ** ************ * ***** *
    }
* * *** ** *** * * ** **** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.174.40
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 13.3k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 13.2k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 16.8k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 12.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users