2 like 0 dislike
6.3k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 6.3k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

** *** * * ** ** ***** i;
* ** ** * *** * *** ** j;
** * ** * * * *** * newNum1;
** * * * *** ** * newNum2;
** ** ** * **** * * * * gcd;
*** * ** * * ***** * rem;
* ***** * * ***** * * ** num1, num2;

** ******** * * * **** * ** **** *** ** ** ** **

** * *** ***** * ** * * **
* * ** *** ** * *** **

* * * ** * **** * * != 0)
* ** * * ** * * *** **** *
* * ** ******* *** * ** * ** ** ** * *** ** = j%i;
* ** * * * * * *** * *** * ** * *** * **** * = i;
* *** ** * *** ** * ** * ** * * * * ***** * = rem;
** * * *** * * ****
** ****** ** * * *** *

* * * * * * ** ** * = num1/gcd;
****** *** ** ** * = num2/gcd;

*** **** * ** **** == 1)
    {
* ** *** * ******* * **** *** **** * * ***** * * ** **** ** *
    }

* * * * *** *** **** *
    {
** * * ***** ** * * * ** ** * * * *** ** ** * * ** **** * *
* ** * ****** ** **

** *** * ** * ** * * ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * ****** * **** * * * * * **** * *** * ** * *** **

* * ** *** ** ** ** *
* * ** *** * ***** * * * * * ** ** ***** ** *** * *

    else{
** **** ****** *** * ***** *** *
    {
** * ** * * * ** **
* * * **** * ** *** ***** ** ** * *** * * * **** * ** **** && deno%i==0)
* * **** * * ******** ** * * * * * ** ****** * * * ******* *
* **** ***** * * ** *** * * ** ** ** * ** * **** ** *** ** * ** *** ** ****** *
* **** * * ** ** ** * * * ** * * ** **** * ******* * ** * * ** **** * ** *
**** * **** * ** * * ** * * ** ***** * **** * **** * * * **
    }

* * * * * **** * *** ** * ****** **
    {
* * ****** * * * ** * * **
* ** * ** *** * **** ***** * *** * ** *** * * **** * * * * *** *** && deno%i==0)
* ***** ** *** *** * **** ** **** ** * ****** * * ** *
* * *** ****** * * *** ** * * * **** * ****** * * * * *** **
** * ** * ** ** * *** * * * ** * ** ** * * **** ** * * *** ***** **
*** **** ** ******* ** * ** * ** * ** ** ** * ***** * * ** *
    }
* ** *** ** **** * *** * ** * *** **

    }




* ** * ***** * * * ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** * * *
#include ** * *** ***

int gcd(int n, int m)
{
** * * *** * ** * ** gcd, remainder;

** ** ** * * ** **** (n != 0)
* * ** * * *** ****
* * * * * * **** * * ** * **** ** ** ** * **** * = m % n;
* ** **** ** * * ** * * * *** * * **** ** * ** * **** = n;
*** ** ** ** * * ** ** ** ** * * = remainder;
*** * ** ***** * ** ******

* * ** ** * **** ** * * * = m;

** ** ** * * **** * ***** ** * gcd;
}

int main (int argc, const char * argv[]) {

** * ** *** * *** ******* ** *** number1, number2;
* * ** * * * ** *** newNumber1, newNumber2;

** * * *** ** * **** * ***** ** * *** * * **** *** **

** ** ** ***** ** * * *** = number1 / **** * * number2);
** * ** * * * ***** ** * = number2 / * ** number2);

***** ***** ***** * * * * ** * * ** *** * **
*** * *** *** * * *** * * * * **** * * * * *
* * * **** * * * *** *
* * * * * ***** *** * **** * ** * * * * *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * **** *****
** * * * * ** *** **

int ** n, int m)
{
*** ** * *** int gcd, ***

** * * * ** (n != 0)
* ** *** * ** {
**** * *** * * * ** ** ** ** = m % n;
* * ** * *** * m = n;
*** *** * ** ** *** ** n = * * * *
* ** * }

****** * ** gcd = m;

* *** *** * *** * * * gcd;
}

int main (int * ** * char * ** {

***** * * int ** * ****
*** *** * int * ** ** * *

* * * ** * * * * * * * * * * ** * * *

*** ** **** * * * = * * / ** * ** ****
* ** * ** * = ** / ** ** ** ***

* ** ** ** * if * * ** * * ****
** ** * ** ** ****** * *** *** * ** ** *****
***** **** else
*** ** ** ** * * *** * *** * **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
*** ** * * *** i;
* ** ** * * * ** * ***** j;
** * *** * * * *** * * newNum1;
** * * * * ***** * ****** newNum2;
* * ** **** **** * gcd;
*** * **** ** * ***** rem;
* * *** * ** * ** ** num1, num2;
    
* * * **** * *** * * ** **** ** *** * ** * * * ** * * ** ** * ****
* ***** ** ** *** ****
* **** **** ** * ***** ****
* * **** * * *
** * *** * * ****
** * ******* ** * *** * * != 0)
* **** ** ** ** ** * ***
* * *** ** ** ** ** *** * * * ** **** ****** = j%i;
* * *** * **** * ** *** * * * **** * ** = i;
* * ** * ** *** * ** ** ** * * ** * * ** = rem;
** *** *** * ** *
* * **** * * ***** * * ** *
    
* ** **** * *** *** * ** = num1/gcd;
* * ** * * *** ** *** = num2/gcd;
    
* ** * ** ** **** *** ** ** == 1)
** ** ** ** * ****
* ** * * *** * * **** * *** * ** ** **** * ** * * * * * ***
* * **** ** * *
    
*** * * * * *** *****
**** * * ** * * ** * *
****** ** ** * *** * ***** ** *** *********** * * ***** ** ** * ** **** * ** *
** * ***** * **** ****
    
** ** ******* ** * ***** ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * **** * * * * ** * i;
**** *** ** * * * * j;
* ** *** * * ***** ** * newNum1;
** * * ** *** * ** newNum2;
** * ** *** ** *** gcd;
** **** * * * ***** * ** *** rem;
* *** * ** * * ** *** ** num1, num2;
    
* * ** * ******** * * *** * * ** * * ***** * ** **
** * * ***** ***** *
**** * *** * *** * **
***** * * *** ** *** *
* * ** ** * * ** * **
* ** * * * * ** != 0)
* * ** * * *** *** *
* * **** * * * ** * ** ***** *** * * * * * = j%i;
** **** ** * ** ** ** * ******** ** *** * * ** = i;
** **** * * ** *** * * * ** ** * *** ** * ** = rem;
*** * ***** ** ** *
***** ** * * *** *
    
* * ******** *** * *** ** = num1/gcd;
** * * * ***** ** *** = num2/gcd;
    
* ** ** ** * * * * == 1)
* **** ** **** * *
* * *** * ******** ** *** * ***** * * ** * ** ** ******* * ****
** ** * **** ** ****
    
**** * *** * ***** ** *** **
* * * * * * ***** **** **
*** ********* * * * * ********* * ** * ** * *** ******* ** ****
* *** **** * *
    
**** * ** *** *** * * ***** * ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** * *** * * * ****** *** *** * ** * * ******* ** * ***
**** * ** ** * * *** ** ** ******** ** * *
    {
*** ** ** * * *** ** * ** ** * * * * * * * * ** * ******
* ****** * * *** * ** * *** ** * * * * ** ** * **
* ** * ****** ** * ** * * * **
* *** * * * ** ** * **** * ** **
*** * * * * ** ** ***** ** *** ****** *

* * ** ** * *** **** **
****** **** * * * * * * * * * *** * * ** * * **** * ** * ****** ** ** * * * **** * *
* ** * ** *** * ** *** *** ** ** ** * * * ** ** * **


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*** *** * * **** * a,b,GCD;
*** ** *** * * ** *** * ** *** **** *** * * * **** *
** ** ** * ** * ** *
** *** * ** ** *** ***
*** * * * * ** ** *** * ******* ** ** **** * * ** * ****
*** * *** ******* **
* ** * * ** * ** * ** * * * * ** *** * ** *** ** *
* ***** **** * * ** ** 0;
}
* ** ** *** * * ** gcd(int a, int b){
* * **** * * * ** * ** * * ** **** ***** * * (!b) return (a);
*** * * *** * ** * ** ** *** * * * * * * * * ** gcd(b, a % b);
* ** ** *** *** ****
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** ** *
#include * * ** * **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* ** * ** **** * ** ** gcd, remainder;
* * ** ***
** * ****** ***** ** ***** * **** (n != 0)
* ** * ** ***
* * * ** *** * * *** * * * * * **** * * *** = m % n;
** * ** * *** * * * * *** * *** * ***** *** = n;
** *** *********** *** ******* * * ***** * = remainder;
* *** **** ** *
* ** ** * ** * *
** * ** * * * *** = m;
* * * * * * *****
* **** * **** ***** ** * *** gcd;
}
int main (int argc, const char * argv[]) {
**** * * * * ** * * number1, number2;
**** * * ** newNumber1, newNumber2;
* * * *** ** ** * *
*** **** ** *** ** *
* * * ** ** **** ***** ** * * ** * ** * * *** * *
*** * * ****** ** *
** *** *** * * ** ** * * = number1 / gcd(number1, number2);
* * * ***** * ***** *** * = number2 / * *** * number2);
* * **** **** * *
*** ** ** *** ******** *
** * *** * ** * * **** ( * ** * * *
*** * *** *** ** * * ***** * * ** *** * **** ****** * * * newNumber1);
* ** **** *** * * * *** *** **
**** * ** ** *** * **
**** * * ** ** *** * ** * * * *** * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * * * * ***** ** a,b,c,d,e,f;
******* * *** ** ** ** ** ** * * *** * * * *
* ** ** * ** * *****
*** ** *** ** ***** *
* * * ** ** *** *** * *
    {
** * ** * * ******* * ** ** *** * ** * * * *
** ** * ********* *** **** * ** * *** ** ** *
*** ** * ** * ***** * * * **** * ****
    }
** ** ** ** ****** * * * *
    {
** * ** * *** ** * ** * * *** *** * **** ** * **
* ** ** ** ** *** ** * ***** * * * * ** * * * ** * ***
* **** ** **** *** ***** * * * * * ** **
* ****** * ** ** * ** *** * ** * * *** ** * ** * ** * **
    }
** * * * * ** * ** ***
    {
* * * ****** ** * ** * * * * * ** ** * *
* **** * ** * *** * * **** ****** * ** *** *** * ** **
*** * * ** * * * ** ** * *** **** ** **** *
* *** * ****** ** ** *** *** * * ** ** *** ** ** ****** * ** * *
    }
******** ** * * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.25
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 6.8k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 6.6k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 8.1k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 6.4k views
12,783 questions
183,443 answers
172,219 comments
4,824 users