2 like 0 dislike
15.1k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 15.1k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* ** * * * *** *** i;
** * **** ** ** * * j;
* * ** *** ** * * ** newNum1;
** *** * * ** *** * *** newNum2;
** ******* * * * * *** gcd;
***** * ****** **** *** * * rem;
* ** ** ** ** * * ** * num1, num2;

** ** * * * * * * ** * ***** * *** *** * ***** *****

* * ** ** ** * ****** **
* **** * ** **** ** * ***

** * ** * *** * * * ** != 0)
** * ** ***** *
* * * * * ** * * ***** *** ** ** * *** ** ** = j%i;
** * * * *** ** * * * * * ** ** * * = i;
* * ** * ** ** * ** *** ** * ** ** = rem;
** * ** *** *** *
* ***** * * * ** * * *****

* * ***** * *** ** ** **** * = num1/gcd;
*** *** * ** ** ** * * * * = num2/gcd;

*** ****** * * * *** *** **** == 1)
    {
*** ** * * * ** * * ** *** ** * * * * * ** * ***** **
    }

*********** ****** * * *
    {
** ** * ** * * * * ** * ** ********** ****** **** ** * * * * * * * *
*** * *** ** * * * ** ***

* * *** ** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** * ** ***** * * **** ** * ** ** * * **** ** ** * ** * * *

*** ** *** ** *** * **** *** *
* ** * *** **** ** ** * * ** * ** *** ** ** ** **** * * *

    else{
****** *** * *** * ***** * ***
    {
* ** ** ** ** ** ** * ***
**** * ** * ** ** *** * ** * * *** * * * * ** * ** * * * ** && deno%i==0)
* **** ** * * * * *** * * * ** ****** ** * ******* ** ** * ****
* ** *** * * * ** * ** * * * ** ** * ** * *** ** ** * * * **** *** *** ***
*** * * *** ** * **** ** ****** * ** * ****** * ** * * * * * ** ** * * ** ** **
* ** ** ***** **** * * **** ** * * * * ** ** **** ****** **
    }

* * **** ** * **** * * * * *
    {
* ****** * ** ** **** *******
***** ** * ***** *** * ** *** * *** *** * * **** ** *** * *** ** * && deno%i==0)
* **** ** * * *** ** *** ** * ** * *** *** * * ** * * ** ** ** * * * *
* ** * * ** * * * * * * ** ** * * * ** ****** * * * * * * *
* ***** * * * ** ** * * * ** * ***** * * ** * ******* *** * ** * * ** *** * * **
** * ** * * ** *** * *** * * ** * ** **** **** ***** * * *** * ** * *
    }
** ** *** * * ** ** * ** ** * * *** ***** * * ** *

    }




* * * * * *** * ** **** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** *
#include ** * * **

int gcd(int n, int m)
{
* * ** ** ** gcd, remainder;

* ** * ** ** * * * * * ** (n != 0)
** *** ****** * ** *
* *** ** * ** *** * ** * * ** *** * * * * = m % n;
*** * * * * * * *** * ** **** * ** * * = n;
* * * ** **** ** **** * * *** ** *** * ** * = remainder;
** * * ** ** *** ** **

* * * * ** ** * ** = m;

* * ***** **** **** ** gcd;
}

int main (int argc, const char * argv[]) {

**** **** **** * ** * * number1, number2;
* ****** **** * * *** newNumber1, newNumber2;

* *** ** * * *** ** * ** * *** *** * *** ** ** * * * **

*** ***** ** * * ** * = number1 / **** number2);
*** * *** * **** ** * = number2 / * * * number2);

*** * *** ** * * * *** * * *** ** * *** **
* ** * ** * * *** ****** **** *** ** * * * * **
* ** ** * * *** *****
*** * * * * *** *** *** ** * ******* ** *** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
*** * * ***** * * **
* ** *** ** ** * **

int *** n, int m)
{
** * * * int gcd, ******

* * *** * * (n != 0)
**** * ** * * {
****** * * * * * ** ** ** * * = m % n;
** ** ** * * m = n;
** *** ** * * ** n = * * *
** * **** }

** * * gcd = m;

*** * ** ** * ** gcd;
}

int main (int ** char * ** * {

*** ** * * * int * * *
* * * **** int * ** * * *

* * ** * *** * *** * ** * *** * * ** * **

* *** * * *** * = * / * * * *
* *** ** ** * = *** / ** * *

** *** if * * * * ** * **
** ** **** * * * * ** *** * **
* * *** ** ** else
** * *** * **** ** ** *** *** ** * **** * * * *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
********* * ** * * * * * i;
* * ** * * * * * j;
** * **** **** **** * * newNum1;
** ** * * *** * * * newNum2;
* * ** *** * * * *** gcd;
** * ** ** ** * * * rem;
* ** *** ** * * ** * num1, num2;
    
* * ** * * ***** ***** ** * * * *** **** * * *
* ** ** **** * *****
* ** * * ** * *** * * ***
* *** ** * * ** * ** *
** ** * ** **
*** * ** * * * * * *** != 0)
**** ***** **
** ** * **** * * **** ** * ** = j%i;
** * * * * **** * ****** ** ****** = i;
*** ** ** * **** * **** * * * *** *** * ** = rem;
* * ** * * *** * ** ** ***
* ** **** * * * *** ***
    
** * ** ***** ** ** ** * * = num1/gcd;
** * * * * * * * * **** ** ** = num2/gcd;
    
* * * * * * ** * ***** *** == 1)
* * * * *** * ** * * **
***** * ** *** **** * * ** ** * * * * ******* ** ** ** * **** ****
* * * *** ** * ** * *
    
* * ** * ** *** *
* * * * ** * ****** *
* ** *** * **** * **** ** * ** * ** * * * * * * ** * ****** * *
* ** * * * ** **** ***
    
*** * ** * * ***** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * ** * *** *** * ** ** i;
** ** *** * * * ** *** j;
******** ***** * *** ** newNum1;
* * * ** * *** newNum2;
** * * * ** ** ** * ** * * gcd;
** *** ** * *** * rem;
* *** ** * **** * **** *** ** num1, num2;
    
**** * *** ** * ***** ** * * * ** * * **** ** *
* ** * ***** * * * * * ****
******* ** ** ** * ** *** *
* ** ** * ** *** * * ** **
** ** ** * * ** * *
** ** * * *** * ** * * * != 0)
** ** * * * *** * *** ** * ***
* * **** * * * * * ** *** ** * ** ** = j%i;
***** * **** ** *** * * * * ** **** * ** = i;
****** ** ** * *** * * ***** * * * ** *** = rem;
*** ** * * ***** ** * *
* ******* ** * * *** * *
    
*** ** ***** * * * * ** = num1/gcd;
** ** **** **** *** **** = num2/gcd;
    
*** * ** *** ** * **** == 1)
* ** ** ***** **
* ** ***** *** * ** * * *** * ** * ** * ** * * ** * ** * *
** *** * * * **
    
** ** **** ** *
** *** ** * * ** ********
** *** * ***** * *** * * *** * * **** * ******* * ** * * **** * **
**** ***** * *** ** ** *
    
** * * * * *** * ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** ** * ** ******* * **** * **** ** * ** **** **
*** *** *** ** **** * * ****** ** * ** *** * ** ****
    {
** * * *** ***** * * ** * * *** * ** * * ****** * *** **
* **** * * * * * **** * * * * * *** *** * *** ** ** *
** *** *** * *** **** *
** * *** ** * *** * * * * **** * *
** * ** * *** ** * **** *** ** ** **

* * **** * * * * * * *
* ** * * * ** * * *** *** ***** * ** * * ** ** **** ** ** ** * * * * * * *** *
* **** * ** * * *** * ***** * **** *** ***** *** *****


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
** * * ** ****** *** * * a,b,GCD;
**** * * * *** * * * * * * ** * *****
**** *** *** * *** *** * * * *
* * * **** ** **** * * ** **
**** * ** *** * * * ** ** * * *** * ** ** * * * ****** **
* * ** * ** **
* *** ** * * *** ** * * ***** * * ***** * * *** * * ****** * * * ** *
* * * *** * ** ** 0;
}
* * * ** * ** * * *** gcd(int a, int b){
***** ** ***** ** ** **** * ** ***** *** ******* * (!b) return (a);
* *** *** * * ** ** * * **** ******* ***** * gcd(b, a % b);
* * * *** ** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ****** **
#include *** * ** * *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
** ** ****** * *** gcd, remainder;
* * ***** **** *** * *
** * *** **** ** ** ** ** (n != 0)
* **** * * *** * * *
* *** * *** *** *** * ** ** *** ** ** ** * * ******* = m % n;
** * *** **** *** * * ** ** *** *** * ** ** * ** *** *** = n;
** * **** ******* * **** * ** * *** ** = remainder;
**** * ** * ** *
* * *** ** *** ** *******
********* * * * *** * *** = m;
** * * * ** ** * * *
*** * * *** ***** ** * * ** * gcd;
}
int main (int argc, const char * argv[]) {
* * ** * ** * * * *** number1, number2;
* *** *** * * * **** newNumber1, newNumber2;
*** *** * ** * ** ** * *
* * * * * ** ** * *
** ** *** * * ** * * * ***** ** * *** *** *** ** **
** * ** * * ** * *
* * * * * ***** * **** = number1 / gcd(number1, number2);
* **** ** ******* * *** ** * = number2 / ******* number2);
* *** ******* ** ** *
** * **** * * ** * ***
* * ** * *** * *** * * ( * ****
* * * * * * * * ** * ** *** * * ** * *** * * ** ****** ** newNumber1);
** * ** *** ** * ** * **
** ******* * * *
****** ** * ***** * ** *** * * ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** ****** **** ** * * a,b,c,d,e,f;
** * * *** *** ** ** * ** * *** * * ** * * **
* ** *** ** *** ** * * * *
* ** * ** *** **** ***
*** * * * * *** * **** ***
    {
*** * ****** * * ** ** * * * * * ** * * ** * *
* ** *** * * *** ** * * * * *** * * *
**** ** * * *** ***** *** ****** ** ******* *
    }
** ** **** ** * * *** *
    {
** ** ** **** ***** **** * * *** * * **** *
** *** *** ** * * * ******** * ********* ** * * ***** **
** * **** ****** * ** * * ***** ******
*** ** * * ** ** * ** * ****** *** * * * * ** * ** * * ** ****
    }
* ***** * * * ** *** *
    {
* * * *** ** * * * ** * *** * * *** * *******
** ***** * *** ** *** * *** ****** ** * ** * * ***** * *** * ** *
* * * * **** ** * * * * * ** * * ** * ** ***
*** * * * ** ** * * ** ******* *** * * ** ** * * * *
    }
* * ** * * *** * * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.59
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 15.3k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 15.1k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 19.4k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 14.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users