2 like 0 dislike
16.4k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 16.4k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* *** * ** * *** * * i;
* ** ** * ** * * j;
* ** **** * * * **** * newNum1;
*** ** ***** ** ******** ** * newNum2;
* ***** *** * * * * * gcd;
** * * * * * ** ****** * rem;
** * *** * * * * * * ** num1, num2;

** * * ** **** ** * * * ** ******** ** *** ** * * *

*** *** * ** * **
** ***** * ***** * *

* * * * ** *** != 0)
* * *** * * *
* *** * * * * * ** **** ** * **** * * ****** = j%i;
**** ** * ** * ** * * ** * * **** * = i;
* * ** * ** ** * * *** * ** * ***** = rem;
*** ** ** * * **
* * * ** * ** * ** ** **

* * **** *** *** * * * * **** = num1/gcd;
* ****** * * ** * ** * = num2/gcd;

* ** ** * ** *** ** ** * * * == 1)
    {
***** ** **** ** * ** ** * *** * * * * * * ** * * **** *
    }

** * * * * ** *********
    {
* ****** *** * ** * * * ** * * *** * * * * ** * * ** * **** ***
**** **** ********* *

* ** * * * * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
**** ** ** * ** *** * ** ** * * * **** * ** * *

** * ** * ** * *** * ***
** * * ** *** *** * ** ***** *** *** * * * * * **** * * *

    else{
* ** ********* *** * * ** * ****** * * *
    {
***** *** * * * * * * *** * ** * *
* * * *** * * *** ** * * **** * * * *** * *** *** * * * *** * **** * * && deno%i==0)
** *** ** *** ***** * * * **** * * * ******** ** * *** *
* * * **** * ** ** * ** * * * ** * * *** * ** * * * ** * * ** ** * *** * *
**** * *** * ** *** ** * * * * * * ** ** * ** * ****** ** *** *** ** *** * *
** * ** *** *** * **** * ** *** * ** ** * ** *** *** ** ***** ******
    }

* ** * * ** * * * ** ** *
    {
*** ** ** * * * ** * * ** ** * * *
* **** *** * ** ** * *** *** * * * * ** ******** ** * * * * * * ** ** && deno%i==0)
* * *** * ** * * * ** ** ** * **** ** ****** ******* ***
* * * * * * ***** * ** * ** * * * ***** * ** ** ** ** ****** **** ** *** *
*** * * *** * *** * ***** * **** ******* **** * *************** *** *** * * ** ** *** * ** * *
** * ** *** ** **** * * ** * ** ** * * ** **** * ** * *** *** **
    }
** ** * * ** * * * **** *** * **** * * ** *

    }




* ***** * * *** ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** *** *
#include *** * * ****

int gcd(int n, int m)
{
* ****** * *** * * **** * gcd, remainder;

* * * * ** * ** ** (n != 0)
*** ** * **** * ** **
* * * * ***** * * * **** ** ** **** = m % n;
* * * * * * *** * * **** ******* ** * ** * * * * ** = n;
*** * *** * * ** * * * ******* * ** = remainder;
* ** * * * * ** * ***

**** ** **** *** ** = m;

** * ** **** ** * ** gcd;
}

int main (int argc, const char * argv[]) {

*** * ** * **** * ** **** number1, number2;
***** * ** ** * * * newNumber1, newNumber2;

** *** * **** ** *** * ** *** * * ** ****** * * ** ** **

** * ** ***** *** * ** = number1 / ** * * number2);
* * * * * * **** * * ** = number2 / ** * number2);

* *** * * ** * ** * * * ** * **** * *
* **** ** ****** ** * * ** * *** * * *
*** ****** ** * ** ** * *
* * *** *** * ** *** * * * **** ****** * **** * * * ***
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * * ** ** **
*** * ** **** * *

int * ** * n, int m)
{
*** * ** * * int gcd, * ** **

*** ** * **** * (n != 0)
* * {
****** * ** ** ** *** * ** *** *** = m % n;
** * *** * * * m = n;
*** * * * **** ** n = ****
** }

* ** **** * * ** gcd = m;

** **** ** gcd;
}

int main (int * *** * char * * {

* ** * * * int ** *** ****
** * *** *** int ** **** * ***

* *** * ** * ** * *** ** * * * * *** ** * * ** * **

* * * **** * * = / ** * ** *
** * * * *** = ** * * / * * * *** *

* * * ***** if ** ** * *** *** *
** * *** ***** *** *** ** * **** * *
** * ** * else
** * *** ****** ** ** * * ** * * **** * *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** ** ** * * ** * *** * i;
* * ** ***** * * ** ** j;
* * * *** ** ** newNum1;
* * ** *** * * * * *** * newNum2;
**** ***** * ** * * gcd;
* * ** * * *** * * rem;
** * ** ** *** ** * num1, num2;
    
*** **** ** ** ******* ** *** ** ** * * * ******** **
***** *** *** ****** * *
** * * ** * ** ** * * **
** * * * * **** ** *
* * *** * *** *** *** * **
**** * * ** * ** * * * != 0)
****** * ** ** ** *
* **** * * * *** ** * ***** * ** *** * ** * *** = j%i;
** ** ***** * ** * ** * **** ** * * * ** = i;
** ** * * * * ** ** *** * *** * ** = rem;
* * ** **** *** * **** *
* ** ** *** ** *** *
    
* * * * *** ** *** **** = num1/gcd;
*** * * ** * *** * *** * * = num2/gcd;
    
*** ** * * * * * * ** * ** * == 1)
* ** ** ** ** * * * *** *
***** * * * *** * ****** ****** **** * * ***** * ** ** **** *** *
*** ** * ** * * ** **
    
* * ** *** * ** * *** ***
* ** *** ** *** **** * ** *
** * **** * ** * *** ** * **** ** *** **** ** ** * ** ****** *** ** * * *
* * * * ** * ** ** **
    
******** * ** * *** *** * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** ** * **** i;
***** * * ** * * * j;
** ** * ******* *** * * newNum1;
*** ** * *** * ** * newNum2;
** ** ** ** ** * * * gcd;
** **** * ** ** *** ** rem;
*** * ****** * * * * ** ** num1, num2;
    
** ** ** * ** ** ** ** *** ** ** * ** *** ** * *** ** * **
** *** ** * *
*** ** * * * * * **
*** * ** ** *** ** * **
***** **** *** * ** **
**** * * * * * * ****** != 0)
** **** * ***** * ** * *
* *** * * ** ** * * **** ** * ** * *** *** = j%i;
* ** * *** * * *** ** * ** * * *** * * * * * * = i;
* **** * * **** ***** *** * *** ** ** * *** * = rem;
* * *** * * * *******
***** *** * ** *** * * *** *
    
* * * * ** ** ** * = num1/gcd;
*** * * ** ** **** * ** = num2/gcd;
    
** ** ** ** * * ** * ** * == 1)
*** * ** * *** ** *
* * * * * ** * ** * * *** * **** * * * * * ** ** *** * ** *
* ** ** ** *** * * ****
    
* * * * * **** * * *** * *
** * ** * * ** **
**** *** ** ** *** * ** * ** ** * * ** *** **** * ** *** * ***
* ** * * *** ** ** **
    
** * * * ** ** * ** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* * ** * * * ** ** * * *** * * *** * ** ** **
* *** * * * ** * * *** ** * ** ** ** ****
    {
* * ** ****** * * ** * ** ******* * ** ** * ** * * **** *
* * * * * **** ** * ** ** * ** ***** * *
*** * ** * * * * * * ** * ** ******
* ** ** * **** **** * *** ** ** *
****** * * *** ** * * **** *** * * *

** ** ********** * ** *** * *
*** ** ** * ** ** ** *** * ** * ** * ** * * * *** * ***** * **** * * * ** ** *** * ** * *
*** ****** * * * * * ****** ******** *** * ***** *** *** **


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* * ****** * *** * a,b,GCD;
* * * * ** * * * * ** * * * ** * * * **** * * * ****
** * ** ********** ** *** *
*** * *** ** * * * ***
* ** * * *** * * ** * *** *** *** ** **** ***
* * ** ** * * * * ** *
* ***** * * * ** ** * * * **** * * ** * * **** **** **** * ****
* *** ** ** * * * ** * 0;
}
* * * **** ***** * * * * gcd(int a, int b){
* * * ** * ******* * * * * * * ** * * ** * * (!b) return (a);
*** ****** *** *** ** * *** ** * ***** ** * * * gcd(b, a % b);
* ****** * **** **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * *** *
#include ** * * ** **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* * * ** * **** ** * gcd, remainder;
* ***** ** ***** **
***** *** ****** * *** * * (n != 0)
* * ** * *** * * *
* **** * * * * *** ** * * ** * * * ** * = m % n;
** * ** * * * ***** * * ** ** * ** * * * ** ** = n;
*** ** ** ***** * * * ** *** * ** ** *** * **** = remainder;
* * ***** ** ** *
* * *** ** ** **** *
*** ***** **** * *** *** * = m;
*** * *** *** * * *
* * ** ** **** * *** ** gcd;
}
int main (int argc, const char * argv[]) {
** * * * ***** ** *** number1, number2;
* * ** **** ***** * * newNumber1, newNumber2;
* * ******
* ** ** ** *** ** * *
*** **** * ** ** * *** ** * *** * * * * ***** ** * ****
**** * ** *
** * * * ** ** **** *** **** = number1 / gcd(number1, number2);
* ***** **** * * *** *** * = number2 / ** * number2);
* ********* ** * ** ***
* * * * **** * ** *** ***
* * ** **** ** ** *** ( ** * ****
* * ******** * * *** ** ** * * * ** ** * * newNumber1);
* *** ** ***** *** *** * *
* ** ** * **** ** *
* * * * ** * ** ***** * * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * *** ***** ** * * * a,b,c,d,e,f;
* * ** *** ******* ** *** * ****** ** * * * * * * * *** **
*** * ****** *** **** ** **
* *** * ** **** * * ** *** *
* *** * ** * * * **** * *
    {
* ** * ** ****** ***** * * * ***** * ** * *
* * * ***** **** ****** * ** * ** *** * *
** * * ***** * * **** ** * *** * * *
    }
* * * * ** *** * ****
    {
* ** ** * * * *** ** * *** *** *** ** ***
**** ** **** ** * ** ***** * ** * * * * * * ********** * * *
*** * * **** ** ** ** * * ** * ** * * *** * *** **
** * * ** **** * ** ****** ** * * * ** * * ** * * * * *** *** ** *
    }
****** ** * * * ******
    {
**** * * * ** * ******** *** * * ** ** ** * *** ***
** * * ** * ****** * ** * ***** * * ** ** ** * * ***** *
** * * * * ***** *** * ** * ** * ***** ** * **
** * *** * ** * ** ******* * * **** * * *** **** * * *** ***
    }
** * * * *** ** ** **** * *** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 16.4k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 16.1k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 21.1k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 16k views
12,783 questions
183,442 answers
172,219 comments
4,824 users