2 like 0 dislike
12.4k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 12.4k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

** * ********* * * ** i;
*** * * * ** * * * * ** j;
**** * * * * * *** newNum1;
* * *** ** ** ** ** newNum2;
** * ***** * * ***** * * gcd;
* ** ***** ** * * * * rem;
** ** * *** *** num1, num2;

** * ** ** * * * * ** ** ** ** * * ** * ****** *

** ** * *** * * * **
*** ** ** * ** ** * * *

* ** * * * *** ***** *** ** * != 0)
** ** * * *** * * * *** **
* ** *** *** * * * ** *** * ** * ** * ** ** * *** * = j%i;
* * *** * **** ** ** * ** * ** *** *** * ** * * = i;
* * * ** * ** * *** ** * ** * * ** = rem;
* * * ** * * ** * *
* ** * * * * *** **** *

* * **** * ** * * ***** * ** ** = num1/gcd;
** * ** * * *** * * * ** = num2/gcd;

*** *** * * ** ** * * * * * == 1)
    {
* ** ** ** ** *** * *** * * *** * * ********* **** * * *** **
    }

* ** * ******* **
    {
* ** * * **** *** ****** ** * ** * ** ** * ** * **** * ** * ** **
****** ** **** *** ** ***

* * * * ** ** * * * ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
**** * * ** ***** ** * * * *** ** ** *** ** ** * ***** ** ** *

** * * * * *** * ** * * **
** * * ***** * ** * ** * ** * * * * ** ***

    else{
* ** ** ** ** *** *** **
    {
** * * * **** ***** * ** * * *** *
** ** *** ** ** *** * ** * *** *** ** ** * **** ****** ** ** * **** && deno%i==0)
** *** ** * * * * * * * ** ** * ***** ***** * ** * * * ** * **
** * * ** *** *** ***** * * * * * *** ***** ** * ** * * * * * * * *
* * * **** * *** *** * * *** ** * * * *** * * * * * * * ******* *
* * * ** * ** ** * *** ***** ** * * * * *** * * ** ***** *
    }

** ** * ** ** ** * ***
    {
* * ** *** *** ***** * ** * * * *
***** * * **** ** ** * * * * * **** * * * ** *** ***** * ****** && deno%i==0)
* * * * * * ** * ***** * * * * *** *** ***** ** * * ******* * ** **
*** *** * * ***** * * * *** * * ********* ** **** * **** *** * * * * ** *
** ** ** ** * **** * * * ** **** ** * *** * * ** ** ** *** * * ** * * ** ** *
*** ** * * ** *** * * ** *** **** ** * ***** ** * * ** *
    }
* **** ** ** * * *** ** **** * * *** * ** *

    }




** ** * * * ** * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** * * * **
#include * * * * *

int gcd(int n, int m)
{
****** ******** * ** gcd, remainder;

* * **** * * * * * (n != 0)
* ****** * ***** * *
**** ** * **** ** * * ***** * ** * * ** ** * * = m % n;
* * *** * * * ******** **** * * ** ** ** * * = n;
** **** * * * *** * * ***** *** * * **** * = remainder;
* ** ** * ** *** **

** *** * ** * **** *** = m;

* ** * * * *** ** * ** *** * * gcd;
}

int main (int argc, const char * argv[]) {

** ** * ** **** number1, number2;
** *** * **** **** * **** newNumber1, newNumber2;

** * ** *** * * * * * ** ***** **** * * * * * *** ** * *

** * * ** * * ** ** ***** * * = number1 / ** * number2);
***** * * * * ** * * * = number2 / * ****** number2);

* *** ** **** * ** ** ** * * * * *
* * * ** * * *** * ** * ****** * **** * *
***** * * * * * **
** ***** * *** * ** * * **** ** * ***
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * * *** ** *
* * ** * **

int *** ** n, int m)
{
* *** * int gcd, *** **

* ** * * (n != 0)
* * *** * {
**** ** * * ** ** = m % n;
*** ** * * * ** * m = n;
** ** **** * *** ** ** * * n = * ****
** * * * *** }

* ** * gcd = m;

** * * **** * *** gcd;
}

int main (int *** * char * ** * {

* ** * *** int * * * * **
** * * ** * * int ** * ** **

* ** ** * * * ** ** ***** ** * * ** ** * *** *

* *** ** ** * = * * / * * * * * * *
* * * * * **** * = ** * ** / * ** **

* *** * ** ** ** if * ** *** * * *
* *** * ** * ***** * * * * * **
** ** ** * else
** **** **** ** *** * * **** * * ** * ***
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * * ** * * * ** *** i;
* * * * * *** * * * ** j;
** ** * * * ** * * ** newNum1;
*** ** * ** * * * ** * ** newNum2;
** *** * * ****** *** gcd;
** *** * ** * ** *** rem;
* **** * ** * *** num1, num2;
    
**** * ** *** * * ** * * ********* *** ** * *** *** **
* * ***** ** *** * ** **
**** ** * * ******* * * * * ** *
** ** * * * * * *** * *
** ** **** * * * * ** * *
* *** *** ** * ** * * != 0)
* ** ** * **** *** * * *
****** *** * ******** *** ** * * * ** ** * *** = j%i;
* * **** * * ****** ** * * ** * ********* = i;
** *** * * *** * ** * * * *** *** * ** *** = rem;
* ** ** * ** * * *****
***** **** * ***** * ** **
    
* * * * * * * ** * = num1/gcd;
** * * **** * *** * *** = num2/gcd;
    
* *** * ****** ** ** * * *** == 1)
* * ** *** * **
* *** *** * * * * * ** * * *** ** * **** *** *** * * **
* * * ******** * * * *
    
* * *** * * * * * **
* * * *** * * ****
* ** ****** *** *** ** * * * *** *** ** *** ******* ** *** ** *
** ********* *** ** *
    
** ** ** *** * * * * * ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ** * ***** ** **** * * * i;
* *** * **** * * j;
*** *** * ** ** *** * newNum1;
* ** ** * *** * * * newNum2;
* **** *** * ******* * gcd;
* ** *** * * *** * rem;
*** ** * ** ** ** * num1, num2;
    
* ** * ***** *** * * ** * * ** *** *** * * * * *
* ** * * * *
* * ** * *** ** *** *
*** * * ** * * **** * ** *****
** ***** * ***** * *** ***
**** ** * * * * ** * != 0)
* * ** ** *** ** **
***** * * * ** * * *** **** * * ** * * * = j%i;
** * * ** *** * * * ** ** * *** ** = i;
** ** ****** * * ** * **** * * * ** ** *** ** * = rem;
* ** * * ** * *** * **
* ** ****** * **** ****
    
* ** *** * ** * = num1/gcd;
* ***** * **** * ** ***** = num2/gcd;
    
* *** ** * ** *** *** *** * == 1)
***** ** ** ** *
*** **** * * * *** *** * * *** * *** * * * *** * * *** ** * * ****
* * * * * * * * *
    
** * * * **** * *** *** * * *
* * ** ** ** *** *
* *** * * ** * * * * * * * *** ****** ** ***** * ** *** **
* ** * ** * * * * *
    
** *** * * * *** *** * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* * * ***** * ** ** * ** * * ** *** **** * *
* * * * * * * ** *** ** *** ** *
    {
********* ** * ** *** * * * * ********** * * *** ***
*** *** * ** * ** * ** ***** * ** * * *** **** **
**** * ** * * * * ** *
** ** * * *** * * * ** *** **** *
* * **** ** *** * ******* * ***** * * *

* *** *** **** ****
** ** ** ** ** *** ** ** *** ** * ** ***** * ***** ** *** ** ****** * ** ** * * *
* ** *** * * * * ** * **** * * *** **** * ** ** * **


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* * ** * *** **** * * * a,b,GCD;
** * ** * * ** ***** ** * * ** * * * *
* * * * ** * ****** * ***
* ** *** ** ** * * * ** **
** ** *** ** * * * * ** ******* ***** *** *
** * ** * * * * *** ** ** ***
** * * * * *** ** ** * * **** ** ** * * * ** * * ** * ** **
* ** *** ***** * **** * * * 0;
}
** ** *** ** * ** * ** * * gcd(int a, int b){
* * ***** *** *** * * ** * * * ****** **** (!b) return (a);
*** ** ** * ** ** **** *** **** * ** * ** * ** gcd(b, a % b);
* * * ****** * ** **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** *** * ** *
#include * * ** ** * ***

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* * *** ****** * * gcd, remainder;
* ** * *** ** * ***
* * *** *** * ** (n != 0)
* * * ** * * ** * *
** ** * ** ** * * * ** *** * *** * * ** ** = m % n;
* * * * *** *** * * * ** ** * **** * = n;
** ** * *** ***** ** *** ****** ******** ** * * = remainder;
* ** * * ***** ******* *
**** * * * * **
* * * * * ** ** ** ** **** = m;
* ***** *** * * * * **
* ** **** ** * * ** gcd;
}
int main (int argc, const char * argv[]) {
*** ** * *** * * * * number1, number2;
* *** * * ***** ** **** newNumber1, newNumber2;
*** *** ** **** ** ** ****
* * *** ********* * * *
**** *** *** * **** * ** ** * * *** ** *** * *** **
********* * * ** *** * *
*** * *** * ***** ****** * = number1 / gcd(number1, number2);
* * * * * * ** * * *** = number2 / * ** number2);
**** ** *** **** ** *
*** * ******* * *** *
* * * * ** * * ** ** ** ( * ** *
** * * ** ** * * * ** * **** * ** ** **** **** * * newNumber1);
*** *** * ** ** **
** * ******* *** * **
* * *** ** * * * * ** * * * * *** **** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* ***** ** ** ** * a,b,c,d,e,f;
*** * ******** * *** ** ** ****** *** **** * ** ** * *
* * * * ** ***
* * * ** * * * *** *
* *** *** ***** ***** * ** ** *
    {
** *** * * * * * ** * ** ** *** *** * *****
* *** ** ** * * * ** ** ****** * ** * ***** ** ***
* ** * * * * *** * * ** * **** * * * ***** *
    }
* ** ** * * *** ** * * ****** *
    {
** * * **** * * * ** ***** *** * * ** ** * ****
** * * ** * **** * ** * *** ** ** ***** ** **** *** ** ***
*** * * ** ** *** * ** * **** *** * **** ** **
** **** * ** ***** ** * * *** ** **** ********* * ** ** *** *
    }
* * * *** ** * ** ** **
    {
***** * * * * **** ** ** *** ** ** ** * * * *
* ** ** ***** * * * ** ** *** *** *** * ** **** * *
* * * ** * * ** * * * ** **** ** ****
* * ****** * * * * ** *** * * ** * * *** * * ** * *** **** ** *** *
    }
* * * * * ** * ** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.39
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 12.4k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 12.4k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 15.7k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 12k views
12,783 questions
183,442 answers
172,219 comments
4,824 users