11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
15.7k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 15.7k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

 * ****** ***  *        ** *** i;
*   **  *** ***  * ** *    ** j;
* ***  **  ***  *   ***** ***  *  newNum1;
* **  * ** ** * *  *  *    *  ** newNum2;
*    ** **  *****  * *  ***  * gcd;
* * ****  ** *   *** *****  * * * rem;
 ******  * ***** * *     *   * * num1, num2;

**** ** **   **     * * ** *** * *   *  ****   **  * * ******* * 

 *   *   ****** *** *** **  ** 
**     *  ***** ** **** * *   

*     **** * ***    **    *  != 0)
***** * *  **  *   * 
*  **   ***  **  **  ** *  *   *****   *  * *   *   ** = j%i;
*  *    *  ****   * ** * ******* * *  **    *  *  ***  = i;
*   *   ** *  *   *  ** * *** * * *  *  **   * * * = rem;
 *   ***    * ** * ** * *   ** **
* **  * *   **     * *  *   ** 

 *  ** *  ** *****  *** ***** * ** = num1/gcd;
**   *   **  *  *** **** *******     = num2/gcd;

****     **  *  ***** **    *  * *    * == 1)
    {
 *** *** **  * **  *  * * *  **** **********  ** *  * * ** ** * * *  *   ***   
    }

  *** * * * * ***   * ** **
    {
 * *** * * *  * *    **** **      ** *****   ***  **  * ***** ***   * * ***     * 
 * *   * * **  * ******** **   

***   **   ** *   *  *** * *   * ***  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** * * **  * **   ** * ******* * ** * ***  *   *  ** *   *** ****

 ** **   *  ** ** *  * ***   **  ******* 
**** *   *  * *  * * *   * * *  *****     *   * ** * *  * * **  **** **

    else{
 *  * ** ** * *     * * **   ****** * 
    {
   **** * **  * * * *  *   * *  * ** * *
* **    **    *  **  **  **    ** * * *    *    *  * **** * *  ***********   **      *        && deno%i==0)
 * **     ** *  *  ******  *** **** *  ***  *  ** **** ** **    *  *  ** *   *
 ***  * **** * ** *   *   * **      *** **  *  * **** * *  *     * ****** **  ***   *  *** **  ***  **** **** *  
  ***  **  * **   ** *   ****** *     *    * * *  ** ********   * **       *     ***   * **** *** **** 
* *      *  *    **** **** ***    *** ** * ** * * * * **** *** * *     * ***  * **** ***
    }

** *** *  **  ********   * ****  ** ***    * 
    {
*  **  *****   **  *** * **   * * 
* *     *    *  ***** **  *     * *    *   **    *     *    **     **  * * ***  **  * * *  *  && deno%i==0)
* *  ***** *     *** *  **  **   ** ** * *    **   **         *  *  **     *     
* * * * ** *  ** ** * *  * * *  * **     *    * *   *  **   *  * ** ****       **      *  **  * ** * **** 
*    ** *   * ** *  *** *  **  *****   *  ** **  ** *    * *     *   ** **  *** ***  *   * ****** * *
 **  *** *   * ** * ****   *  *       *  **  **  * *        *****  *****  *  **  ***
    }
**    * *****  **  * **   ***  * * ** ** * ** * ***  

    }




 *    * ***  **  ************ *  *  0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  * ****  *     
#include  *     * *   **

int gcd(int n, int m)
{
* **   * * * * **  ** *    gcd, remainder;

**     **   **** *  *  ** **** ** (n != 0)
 ** *  *   ***  * ***    *
** *  ** **  ***   ****** * *  ***  *  ** *  *** ** **   = m % n;
*    *    * * ** * *   **** *  ***  **** * ******** = n;
* *     *****  ***   *  ***  **   ***  **     *  = remainder;
 **   **** ** ** ** *  * *  

 ****   *     **    **  *    = m;

* * *   ** *     * * *    * *****  gcd;
}

int main (int argc, const char * argv[]) {

*   *   *  ***** *      *  **  number1, number2;
***** ** ** **     * ** ***    *  ** newNumber1, newNumber2;

 *** *** *  ** **   **     * *  *  * *  * *   **    *   *  *  *   * *  * 

      *    * ***  *   ** ** *  *** = number1 / * **    ** number2);
*****   **   * * **** ***   ** ***  = number2 / *****  * number2);

 *** ***    ** * * * ** *  *  *****  *** ** ** * **
  * *** **  ****   ****  *** **  *  *      * *** *** **    ** *  ** 
 *  ***   **  ***    * * *   *  **
   *  **  * **  * *  **** * * *** * ** * * * **   * **   
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  **  * **  **  ******
****    **   *   *  ***

int *** *  n, int m)
{
*    **     *    int gcd,  *****

** ** * *   * * *  (n != 0)
** * *  *  *** * * {
* ***    **** **  * **     *** **** * *  * = m % n;
* *     *****   ** *   * ** m = n;
 * **  *    *    ***  **  *** n = ** ****
**  * *    ** ** }

* * * *   ** *  * gcd = m;

**** **  ****  * gcd;
}

int main (int  *   *  char * *   {

 *   *     * *  int  * **** **  *  *
 * ***  * ***  int *  **  *     

***  *** * **    *  **** ***       * *   *            *****   

 *    ** * ** **   ***  =  *** /  ****   *   * 
    ** *******    **   = *   * / ** *   * *  *

*  ** * *  ****** if  *       ** ** ** * 
**  **   ****  * ** **  ** *     *   ***  *    *   * 
    * ***  *** * else
***       **   ******     *** *  *     * *     ** **  *  ** * 
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
     * *****   **  ** *  ***** ** * i;
**      *  ***  * ***    * j;
* **  * * *** **    * ** ** newNum1;
 *****  *** * ** *  **     * *   newNum2;
     *  *** **** *  ** ***  gcd;
 * * *  *   * * *    * * **** *  rem;
  *  ****** *** *  *** **  *  num1, num2;
    
** ** * *  *      ** **     *   *** * * * ***   *  ** *  * ** ***
*  *   **  **    *   * ***  ** 
 ******* *  ****  *  ** * ****
*  *    **** *   * * *  * *** **
*** * * *  **    *       **  
     *****  * *** * *      ** *  != 0)
  ** ** ****     ***** ** **  **
  *** *  *****  * * ****** ** ** ** *  *      * *  **   = j%i;
*  **  ******   **** *  ** * ****  *  * *******    *  *  * *  = i;
****      **     ** *  ** *  *     *   *  **    = rem;
***  ***    *  * *  *** **
 **    ** * ** *  *** *     
    
**   * *      *  ***** *    * **** = num1/gcd;
***** ** **** **** ****   ***   ** = num2/gcd;
    
     *   ** ** **** * **  ****   *****  == 1)
 ******   *  *   ****  ***
 *  * *******      * *  ** *    **      *** ***  **  *    * **** *    ***  * *  
** ***** ****   * *   *
    
    * **   **  ** * ***** 
  *        * *    **      ** 
***  ** * * * **** *** *** *  *    * ****  * *  **** ** *  *    ****     *   * ** ****
****  ****   * * * * * 
    
**  * * *  *    * * *  * ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
      ** * *  *** * **  i;
**  *  * * * * * *** ****   *  j;
 *** *  * * * * ** * **** ***** * newNum1;
 *    *      **   *   **  ****  newNum2;
* * * **   * *  ***** ** *   * gcd;
***   ** *****  *  *   *   *    rem;
   ** *  *   *** **  * *  ** num1, num2;
    
****  *  *****  *   **  * **   * *   ***** * * **  *      * **    *
***  *  * ** ******  ***   * **
 **  * *        * * * ****
** *   ******  *      **   ***** **
     * *     ******* * 
*** *    *    ***  **** *** * * * != 0)
 *    * * ** *  ** * *     *
 *****  *    *  ***  ****   *** * * **     ** * *** ** * ** * = j%i;
* *** **** * * *** **   ** *  *   * * *  *    ***  *    ** = i;
* *  * *  ** *  ** **  ***  **    *  **** *** ****  = rem;
 ******  ** *  *    * **  ****
  ***   * ******   * ** ** *** 
    
 * *    ***  ** *      ** * ** **   = num1/gcd;
**   *  *****  *     *  * *****    = num2/gcd;
    
* **  ** * *  ***   * *** *** * ** * == 1)
  *    ** *****   ** *   
****  **  *** * *  *  *  **  *   *  * * **   * *    ** ***    * *  ** ***** 
*** *** ** *   *  **  * 
    
    *    * ***  *   * *   
**    *** * ** *  *  *** * *  
*   * *    *      ***  *  * ****** * ** ***     **  * * *        * ** ****  * *        
**   *   * **** *  *** * *  ** **
    
** **  ** **  *** **** **** *  *   0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
*  *   * *   *  *    ***   *******  *    *** ***   *  ** **    
         ***   *   ***   * ** * *   *     * *  *   *       ** 
    {
*  * * **  *   ** *** *     *   *  ***     * ****   **   * *     ***** *
 * **  * **** ***      ** *** *** ** ***** *** *  *   * *  *
**** **  ****  ******  *   ***      ** ** **
   *      ***        *  *  **  *  **  ***  *
 ** **   *   *   **  * *  *  * ** ***    * ***    *

 **  *  *     ** * * **  **     
 * ***  ** * ***  *  * * *** * *****  ******  *  * *    *  ***   ***** **    **   *    *  * *  * * * * *   * **
 *     ** ***   **  **        *** *** ***  ****   ** *** *  * *  **  *  


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
**   *  * **   * *   * ** a,b,GCD;
* *   * *  * *  **   *  **** ** * *  *  ****     *  * *     * **
 * ***  ***    ********** * * **  *
  *  * *** *  * ** * *  * *  ****  *  
***** **   **  **  ** **  ****  ****** * ** *  *  ** * *****   ** * ** **   
 * *****  *  *  * * * ** ***  ** 
** ***   **** ** **  *  *** **  *  *    ******   * * **   **      *** **
 * * ***    ******   *   **  0;
}
   *****    **  * ** * ** gcd(int a, int b){
*  * *** ***  *  *  ***   ** *  *  *  * **       ** *  (!b) return (a);
     ** * ***    ** ****  *  * **  ****   ****   *    **     gcd(b, a % b);
** *  * ******    *  ** *  *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  *******  * * *
#include ***** ** ** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* ** **  **  ** *** ****  * * ***   gcd, remainder;
     *   **  * ****** **  *
 * *           **      *      * (n != 0)
 **  *  * *  ** *******  * 
 **   *  *      *    **     * * * * ****  * *  * **   ** *   = m % n;
  *  *  ** **     ****  ***  *  ******  ***   **** **  * * = n;
   * ***  *** **   *  ******    * **** *    ****      = remainder;
** *   * * ** **  **    * **
  * ***   *****    ***  *** 
**  ** ***  ***   * ***   * = m;
*   *  * *** *  **   *     
  *** *    *** * **** ** *   *** * gcd;
}
int main (int argc, const char * argv[]) {
* * *** *  ***  * * *  * **** *  number1, number2;
* ***** *** *  * *** *  *  * newNumber1, newNumber2;
 *   **   * * * **  **      
  *   *  * ** **   ** **** * 
  *      ** ***** * ** * * *  **  ** *   * *   *** * ******  *   *  * *  * 
* ** *      ** ****    ***    
* ***      * **  * ****  **  ** = number1 / gcd(number1, number2);
** ** *     **   * ***  *  **  * ***  = number2 /  *   *** number2);
  * ********   ** ** * *   
 * * ** *  * ******** ** * * ** * 
   *  **  ***  *  * *  ** *   (  *  *** * *
*   * *  *   *  ** *  *   **    *  *  *  *   **  *** *    ****   * *****  ** newNumber1);
* *  **   **  **** * ***   **  
***  **** ** *  * **  
  ** **** ***  * **   ***   * ****   *  **    **   **** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*  *** ******  ** * *  *** * a,b,c,d,e,f;
***** * * *** *  ***   ***    *  *   *  ** ******  ***         
  ** **   ****** *  *   ******
    * *** * ** *  ** *    
 * *  **     ** ** * *** ***   **  *
    {
** ****  **  **       *  *  ***  * *   **  ** ** **   * * * 
  * ****  * *    * *  *      **  *  * *     ** ****  * **
 * ****  **** *  ** ***     *** *  * *  ** * * *** * * 
    }
  ****  ** ****  *    ***  *****
    {
  * * * *        ***    *  * *   ***  * *** *  **  *  * *   ** *
     *     ****  **   *      *** *** ***   ***  * * *     * ** *   *** **  **   
* *  **   **     ** *    *  *   **   ****   *** * ** * 
*     * *** * *   ***  *    * *  *    ** *** * ***** **** ** ***   *** ** ******
    }
** *** **   ****  **  * **
    {
   **  ****   **  *  *** ***  ***    **  * * *   **** ****** ***
  ** ** ** ** * *  * **  * ******   *   *  *** *   * ** *  **    * ** * **  
*  *  * *  ** ****  **** * **  *  **   * * *** ***   *  **
 **** ** *** * *  * *** ***    ** **   ** **    ** **   ***       **     *  *       ***
    }
***   *   **   *  **        ** ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.164
©2016-2026

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 15.8k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 15.7k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 20.5k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 15.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users