11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
2k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 2k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

   * **    * **      **** i;
*** *  * **    *  *   * **   * j;
*    ****** *  * * *****    ** newNum1;
   *   *  ** *   *    * ** **  ** newNum2;
 *     * ** ****  *   **   * * * gcd;
**    *****  * **  * * **  ****** rem;
 **  *  ******  *   *    num1, num2;

*  ***  *  * *** ** *** ** ** ** *** ***    *    *    **  *  *    

*    * *    **** ***   ** *
**  ****      *   ****    ***  *** 

  ** ***** **  *  *       **  != 0)
*** * **  ** * *  *** ***
 * ** ****    * ***     ***  ***  **  ******* *   * * = j%i;
  * ******* **   ***** *** **  **** ** * *  *  **   *  = i;
 *** ** *** *** ** ** *******  *  *        ****      *  = rem;
**   * *    *  **      * 
  *       *   *****  *     **

* *  * ***  * **** * *   **    ** = num1/gcd;
 **   *  **** * *** * *** * * = num2/gcd;

 * ** * **   ** ** **    *   *** == 1)
    {
 * ******  *  ***** * *  * *   ***  *****  **   *  * * *** *  **       **** * * 
    }

   *     **** *  ** *  *     *  *
    {
    ****** ***** ** *** **   * **             * * * ** * ** *     *  ** ***  * * * ** *
 *  *  *  *** *** *** *** * *

*  * *   ** *  *  *   *** ** **   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
 ***    **   * ****  * * *   *   * *   *    ** *  ** * * * *   *  ** *

 *   * * * **   **** *   **   **** ** 
*  *    ** * * **      * ****  *   * *   ***** ** **  * * **  ***  ** ** **** *

    else{
  *    **  * *** ** *  **** **   *
    {
    **    * *  **    *   **     **    **    
**   ** * * ** * **  *   **   ** **  *   * * ** ** * *   *    * *  ******   *      && deno%i==0)
*** *****  ******** *** ****   *    *   ** * **     ** ** * ****     * **  **
 ***   * **   **  ***    *  * *** *  ***     *  **  * *     *****   * *** **** ** ** * **  ** **   ****
* * **  *   *    * ****** **  *  ****  * ***  *    * *  *   ** * * **  **  *   **** *** **  **   * *   ***
*  *  **  **   *** * **  *  * ** *******    ** *  *  **  ** * **** * ****
    }

  *   *     *    *    * *   *    **   * **
    {
 * * *  **** *  *** *  *  *   * ****       *  
 *    *** *      ***** ****  *** ****   *   *  * *** **  ** ***      **  * ** * *** * ***  && deno%i==0)
  **   * **               ***  *  *   *  **   ** ** *     **** *** * * * * * *** * *
     **** *** * *       * *        * ****   **   ***  ***     * **  ***  *  * *    * **** ** ** ** *   ******    
 * *   *** **   ***   ****     * ** ***   ***    * ****** * *     **** **     *  * * * * *   * 
 *** * *  * *  **   * **** *******      *    *** ** ** * *    *    * * *   * *  * ** * *  *** 
    }
  ***** *** * *  *   *   *** **  *  ***  *  ** ** 

    }




*   * ***** ** ** ***   * **  ** * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** ***   * ** * 
#include **        * **

int gcd(int n, int m)
{
 *     ** ** **     gcd, remainder;

 *  *   ***    * *** * *** ** ** * (n != 0)
 **  *  ******  * ******
**  ** *  **  *   ** * *  *  *  * *** * *  ** ** *  *    = m % n;
 **** ** **  * ******    * *** * * * *  *    * ** ** ** = n;
* *  ** ***** **  ******* * * * **  ** *** * *   *     * * *  *  = remainder;
**   *  * * *  *  *  * *** 

**   * *    *   ****** *    *    = m;

**  **  *   * **  *   * * gcd;
}

int main (int argc, const char * argv[]) {

***** *     **** * *  * *  *  number1, number2;
  ***      * * *  ***        newNumber1, newNumber2;

** ** ********* *** *      *** * ** *    * **  **  ** *  *   * *    

   **    * * ** * **   * * **** = number1 /  *  *** number2);
*   **** *  *** * **     **  * = number2 / **      ** number2);

 ********  * *  ** * ***  * * ** * *  **  ***
  *     **** **    ** ****  * **  * **  * ** * **     * ** *         **  
**   * ** **   * *   ****   
 ** *  **  ** * ** **   * * * * ***  *  * * ****  *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * * **  * *      *** **  
**   **  *   * **** 

int    * ** n, int m)
{
* *    * * * * * int gcd,  ** **

  ***** **        ** (n != 0)
 ****  ** * {
*      ***** *  *** *** ** **   **    = m % n;
 *  * * *  **  ***  *** *** m = n;
**    * *  * *  *   * *   n = *** * **
 **  * *  ****** }

*   **   ** *** gcd = m;

       *   *  **  gcd;
}

int main (int  *   * char *  *  {

  ** * *   *    int *    **
  * * * ** * *  int ********    * ** 

*  ****  ** * * **     *** * * *     ***    * *   ** *****  

 * **  *    *   * **   = *    / *    *** **** * 
* **  ** * ** ** = **  * /  *    **   *** *   

**        **  if ***  **  ** *   *** *
 ****  *  ** *   * * ***     * ** * **** ** **  *   *   **   
 ** ** *  **** else
**  *    ** **  *    * ** * *  ** *  ***** * *    **** 
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
** * *  *   ** **     *     * i;
 *  ** ****  ** ***   *** ***** j;
*   *******    ** *  ***  newNum1;
* * ** *   **    *  *    newNum2;
* * * **** **   *    * *       gcd;
   * *   **** * ****     * *** rem;
  *******    *  * *   *     num1, num2;
    
 **** *    *  * **  *  * *   ** * *****  *   **    *  * **   * * ***  *  
*** ** **    **** * * ***   ***
   ****   *  ** *  * **  *  *** * *
   *** ** **  *   *  * *
 * ** * **   *** **  ****
 **    ***  *     ** ** *  * * != 0)
 * * **   * *  ******  **** *
*  ** *     * ** ***  *  *   ***** *  * * * * *   **  * * * = j%i;
 **  ** * **    ***     ****** *  ***     *** *    * = i;
 *   ** * ** * * ******  *** * * * *     ***  *       ** * * = rem;
 ** ****** **  *  **  ** 
** **** *  * *  ** *** *****  *
    
 ****   *  *  *   **     * *   = num1/gcd;
 *** * * ** *    * **  **** * * ****** = num2/gcd;
    
* ** * **** * ** * ***   ** *    == 1)
  *  *  * **  * **  * ***** *  
*****  ** ** ****    *  *  *  *  *   * *  * ***  *  ***   *     * *  **  * *    ***** 
** *    ***   ***** * *  *
    
* *   * *    **    ***  * *     ** 
  ** * * * *   **     * ***  * *
**  *    ** **  **     * **** *****   * *  ****  *    *** *** ** ** * ***  * * ** 
 * * * *****    *    ***   * 
    
 **  *   ****** * *   ***   *  *** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 **  *   **** * *    *  ***    i;
   *    ***  *** *  * ****   ***    ** j;
*******  ***  **    **** * * *  newNum1;
** *        ***   ***  *     * newNum2;
 *** * *  *  *  *    *  ** gcd;
 **  **   * *** *  * *  *  * *** rem;
*  ***    **** * ** ** ***  num1, num2;
    
  ***** *     *   *     ****  *   *  **     *  ** * ***** * **  *
** *** *** *  * *  *  *
****    *   ***   **** **** * * 
    ** *   * *    ***** **  *
 ** ********  *** * ******
 ** * ** **** ***      *  *  *  != 0)
* * * * **** **     * *
    * * **** ****   *** * * *   **  *   * *  ** *** *   * = j%i;
   * ******        ****    *   * *     **  **    * *** *  = i;
  * *   ** *    *   *  * ***   ***  *** * *   ****  ***   ** = rem;
* *  **   ***** *     ***  *
* ** *  ** *  **  *     **   
    
   *  *** * * *     **     * * = num1/gcd;
*** ****       **  * **   * * *  = num2/gcd;
    
***  * **** *****  ******* ***    * *  == 1)
*    **  *  * ***  * ***** **
 ****  * *  **   **  *  * *  *   **** *  **  *    ** ***   ** * * *** * ** **  **
*** ** **  ****   *** * *
    
  *    * **** ** **** ********
 *  ******    * *     **** **    
**    *   * ****  * **   *** *  **    ** ******   *    * **** ***  ** * *****  ** * ***  * * 
**  *** * ** ***       ** * * *
    
* ** **   *******  ****   * *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
 * * * ** * ** * *   * * **   *  ***  ***        *     ** *
* * *** *    ********  *  *  **** ** *  * ****   * *     **    *
    {
*   *****       *  * **       ***     * * ***    *  ****** *  * * ***   
**     *   *  **  **   ** *** ** **** **    **   **  *** ****  *    * **
   * *  ** **  * ***  ** * * ** *   * ** * * 
    *  *     **  ********    *****  **     ** * 
 * ***  **    **    **  *****  **  ** *** **  *

 *    **  **  ***** **    * *    *
      ** * * **     **    *  * **   ** **  *   * *** *       ******* ** ** *    **   ** **  * ** ** *** *
 ***** ** ***  * ** ****  *    *****    * ***  *    ***  *****   ** *  **      *  *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
  **  * **** ***  *  *  a,b,GCD;
 * ***  * ** **  *** *   ** *  ** *** *  *  * **   ***** **  *** * * ***
    *    *  **     **    **  * 
** **  * * ****** * ***    * ** **
**** **  ** *   * *  **  *  *  *** *   *  *  *** ***  **** *  *** **** 
*  **** *  *** *    *** 
 *   * *** * * *   ** ** ********  **   * **   **  * *** * *    **    **    *  *
     *** * **  ****** *  ** *  * 0;
}
 ** ** *** * * ******  ***  gcd(int a, int b){
*    *******   *****  ***** *  ** ** *** ** *** *   ***  (!b) return (a);
  * **   ** **  * *  * *  * *  **  ***   **  ** * **** * ** gcd(b, a % b);
   *     * *  **   *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   **  * * *** * 
#include *  ****  ** ** 

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
 *  *** ** ***** ** *  ** * gcd, remainder;
 **** * ***  *  *** * ** *
   *  ******* * *  * **** (n != 0)
  *  *    * ****   * ***  
 ********    * ** **  *    * * *  ** ***  *  ***  ***  = m % n;
  ***** ***   ****   ** ** * *   **** ** * **  *  * ****     = n;
 *     * **    ** ** * * *     *  * *** *** **    * * *   = remainder;
  ** *    **  * *    ***
 * *        *** * **  ** * **** 
  *  *** *     **** *  ** *   = m;
**** ***** **    * *  *  * *
** ***     ***** * *    **  ** * gcd;
}
int main (int argc, const char * argv[]) {
*  ***  *  * * *** ***    *** number1, number2;
 *  **   * * *    *******  *   * newNumber1, newNumber2;
*  **   *** *  ***  * * **** 
*** **  *   * *   *** 
 ***   * *  **    **    * *****   *  * **  ***  *** ****  *** *  **   * ** 
  *    **   **    * ****  ** *
  **  ***    *      * *       ***  ** = number1 / gcd(number1, number2);
**    **    ***  * *    ** **   = number2 / *  *** number2);
 **  ****  * * ****   * ** 
 * *** ** *  ****  * * *  * ** 
** *  * * ** *   *   *  *  ( * *****
   *  * ** ** ** **** ***** * *       *** ** *** ******** ** ***** ****** ***** newNumber1);
*  * * ** **  ****    *   * * *  ** 
* ***** ** *  ** *****  
 *** *   ** **** *** * *  **  *    **  * * * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
***  ******       ***** * * *   ** a,b,c,d,e,f;
 ** * *****  ***** **  *  * * *        *****   **** ****  *     
 *********   ***  *** ***       
 * ** ** *   *     **   * 
  *    *   * *    *    *  * * *** *  * *
    {
*** *   ** * *** **** **** *    * *     ***  ** ** *  ***
***** ******  ** **  *** ***  ** * ** ***   ***  *** *** * 
  * * *   *****  ***   * * *     * * * * *    * * * 
    }
*    **** ******* *   **          *  *** * 
    {
  * ***  *  * *   * ****** * ***** **** * * **    ** **   **** **  
 **  *    * * *  * ***  **  ****    * ** *   ***** ****** *  *      *  ****
  ** **  ****    ** *** **   **  *  * **   ****    *** *  * * **  
*** *  * *  *** *  **** * * *** * *** *  *   ***     *  ** ** * *        **  *  *** 
    }
  *       * *  *** *      *  ***
    {
*** **  * *** * **** *   ***  **** *   *       *** **      *  *
 *  *** ***** * ** * * * * ******** ****    *  *  ***  ** ***  * ****  *****  * *
*** *     * **** *****  ***   *      * ** ** *** *   * 
* *  ** *      * **  **  * **  **   **** **  ***  ****** **   *** ***** * 
    }
 *  *  **  * ****     *** ** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.188
©2016-2024

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 2.5k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 2k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 2.8k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users