2 like 0 dislike
11.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 11.9k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* *** ** ** * ***** ** * * i;
* ** ** ****** j;
*** * * * * **** * newNum1;
* ** * **** * *** ** * * newNum2;
** ** * *** ** ** ** gcd;
** ** **** ** ** ** * rem;
* ** ** ** * * * * ** num1, num2;

*** ** ***** ***** **** * * * * **** * *** ** ** * * **

* * * * **** *** * ** ***
* ** ***** *** * ** *** *

**** * ******* * * * ** != 0)
* * * * ** * **** ******
* ** * **** *** **** * * * * ** ********* = j%i;
* **** ** * * * ** * *** ** ** *** * * = i;
** * * ** *** * * ** ** * ************* * ***** * = rem;
* * *** * ** * ***** *
** ** * * *** ** * **

*** *** *** *** * ** * = num1/gcd;
* ****** * ***** * ** * ** = num2/gcd;

** *** * * * * ** * == 1)
    {
*** * ** ** ** * ** ********** * * **** ** *** *** ** *** *** *
    }

** ** ** **** ** * *
    {
** * * *** ** *** ** * * ** * ** ** * ** ** **** **** * * * ***** * ** ** ***
*** *** ***** *** * *

* ** ** *** ** ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** **** *** * ** *** ** * ** ** * * ** ** * *** *

* ******** *** * *** ** * * * **
**** ** * * ** * ***** **** ** * ** ** * * * * * * * * **** *********

    else{
* * * * ** ** ** * *
    {
*** *** * * **** * * * * *****
* * * * ** * * *** **** * *** *** ** * * **** * ****** * *** * ** && deno%i==0)
* **** ***** ** * * **** * * ** * * *** * * ******* ** ** *
** * ** * ** * **** * *** * ** * * ** ** ** ** ** ** * * * *** * **** **
* ****** *** **** * * ** * * *** ** *** * ** ** * **** ****** ** ** * ** *****
** * ** ** * ** * * * * *** * * * ** * ** * * *******
    }

*** ****** ** ** * *** * * * ******
    {
*** ****** ** * ** * * ** ** **
* *** *** **** ** **** * **** * ** * **** **** * ** ** * * ** ** **** ** && deno%i==0)
** * ** * ** * * *** *** * * * * ** *** * ***** * * *
** ** * * ** ** **** * * * * * * * * *** ** *** **** * **** ** **** * **
* * ** * * * * ** ***** ** *** * * ***** ** ** * * * * * * * *** * **
* * ** **** ** * * ** ** * **** ** * *** * ** * * * * * *** * **
    }
** * ** * * ******** * ******** ** ************

    }




*** ******** ** *** *** ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** *
#include * ** *** *

int gcd(int n, int m)
{
* ** ** * * ** * * gcd, remainder;

* *** *** * *** (n != 0)
***** * ** * * ** **
** * ***** * ** ** ** * **** * *** ** * * *** = m % n;
* * * * * ** * **** * * * ***** * *** *** = n;
** * * * **** * * * ** **** *** * * = remainder;
** * ** ** * *** *

** * *** * **** = m;

* ** * ** ** *** * gcd;
}

int main (int argc, const char * argv[]) {

* * * **** ** **** * ** *** number1, number2;
** * * * **** ***** ***** newNumber1, newNumber2;

* * *** **** *** *** * ***** ** *** **** *** * * **** * ***

** ** * * *** *** * * = number1 / ** * ** number2);
* * * ** *** * **** = number2 / * number2);

** * ** * * ** ** * * * * *** * **
** *** *** ** *** * * ***** ** * * ** * * ** * ***
* ** * ** * **** * **** *
**** * ** ** *** * ** ** * * * * ** * ****
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
***** *** * **** * * *
**** ** ***** *

int ***** n, int m)
{
*** * *** * int gcd, *

* * * *** * (n != 0)
* * ** * * {
* ** *** * * * * * = m % n;
*** ***** *** ** * * m = n;
* ** * ** **** * n = *** **
*** *** * * }

* * * * * gcd = m;

*** * ** * gcd;
}

int main (int *** ** char * * **** {

* * * ** int ** * ****
****** * *** int ***** * *

** **** ** * ***** **** * * * * *** * * * * * * *

* *** ** ** * * = * ** / **** * ** *
* *** * ** * ** * = * * / * * * ** * ** *

* * * * * *** if *** * ** *******
** ** * * *** * * ** * *** *
* ** * * else
* *** **** * * ***** **** * ** **** * * * * * * **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ***** ** ** ******** ** i;
* * * ** * * * * * * ** j;
* * * ** * ***** newNum1;
** *** ** ** ** * * newNum2;
* * ** ** ***** **** * * gcd;
*** ** ** * ** **** rem;
* * * * ***** *** ** num1, num2;
    
* ** * ** **** **** *** ** * ** **** * ** * * ** ***
* ** * *** * **** *
* *** * **** * *** * *
** * * * ***** * * * * **
** **** *
* ** ** * ** **** ** * ***** != 0)
** ** ** * ****
* * ** **** * * * **** * * * * *** ** * = j%i;
* * * *** ** **** * * * ** * *** * **** * = i;
** * * **** * * ******** **** ** *** * * **** * = rem;
* * * ** ******
*** * *** * ******* ** * **
    
** *** * * ** * ** = num1/gcd;
** * * *** * * ** * * *** = num2/gcd;
    
* ** * * * ***** ***** * == 1)
** *** *** **** *** *** **
* * ** ** * * *** *** * *** *** ** ***** ** ******
* ** ***** ***** **** *
    
* * * ** ** ** ****** **
* * ** * ** ** ** *** *
* * * *** ****** *** * * *** ** * * ** **** * *** * ** ** ** * *** **
** *** ** **** ****
    
* ***** ** * ** **** **** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** * * * ** *** ** **** * i;
*** * *** ** * ** *** * * *** j;
** ***** ** * * ** ** newNum1;
**** * * * * * ** ** * * newNum2;
**** * ** * *** *** * gcd;
*** *** * * ******* rem;
* * *** ** **** * num1, num2;
    
* * * ** * * ***** * ** * ** * * * *** * **** *
******** * * * * *
* * *** ** * * * * * ** **
* ** * * *** *** ****
* ** ******* * * *** * *
* * ** * * * * *** ** * * != 0)
** ** ****** ** **
*** ** * * * *** * *** *** ***** ** * * * = j%i;
* ** * ***** * * **** * * *** * **** * * = i;
**** * * **** ** *** ** * *** * * * * = rem;
** * * *** **** * **
**** *** * ** * ** ** * **
    
** **** * ** ** * ** = num1/gcd;
* ******* * ****** * *** = num2/gcd;
    
* * ** *** *** ** ** * ** * * * == 1)
** * * *** * * **** * ** *
**** * * * * * * * * ***** * *** * * * ** * * * * ** ** ** **** * *
* **** ** *** * * * *
    
*** * * * * * * * **
* * * ** * ** ** * * *
******* * ***** ** *** * *** * ** *** * * * * * ** ** * * * **
** *** * * * **** * *
    
* * **** * * *** ** * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
**** *** ** * ** * ** * *** * * * * ** ****** ** **
*** * **** ** * ** ** * **** * * ** **** ** ** *
    {
* *** ** * *** **** ** **** ** * * ** * *** **** * * * **
** *** * ***** * * * * * *** ** * * * * ***** ***
** * * * * ** * *** *** ** ****
* * * * * * ** * ** * * * ****** **** ***
* * * ** * * *** * *** ** * **** * ***

**** ***** * ** ** * **** ** **
*** * *** **** * ******* **** ** *** *** *** * * * ****** *** *****
*** ** ** *** * ** **** ** **** * **** * *** * ** ** ** * * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
** * ** ** * *** * a,b,GCD;
* ** *** * *** * * **** ** ** * * * * ** *** ** ** *
* ** *** ** * * * * * *** *
** * * * * *** * *
* ****** ** * *** * ****** ** * * ** * ** * ** * * * *** *** **
* ** * ** *** ** **** **
* *** * * * **** ***** ** *** ** ** *** ** * *** ************ *
* ** * * ** ****** 0;
}
*** * * ** ** ** *** * gcd(int a, int b){
*** * * **** ******* ** ** * * ** ** (!b) return (a);
*** **** * * * * * * * * **** * gcd(b, a % b);
* **** ************ * * * **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * **** *
#include * * ** * * **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
** ** ** ** * ** * *** gcd, remainder;
* * * **** ** ** * *
***** **** ** ** ******** (n != 0)
*** * ** ***** * * *
* * * ** * * ** ** ** * ** ** ** * * *** = m % n;
** **** * * * ** ***** * *** **** * *** * = n;
** * *** *** * * * **** ** * ** ** * * ** ***** = remainder;
* ***** **** * * ** * *
* ******* **** ** ** **
***** * ** * * * ** * * ** = m;
** ***** * ** ** ***
** * * * ****** ** ** *** gcd;
}
int main (int argc, const char * argv[]) {
**** * *** * ** * ***** number1, number2;
* ** ** ****** * * newNumber1, newNumber2;
* ** * * ****
* * * ** * ** * *
** ** ** * ** ** ****** * * * * * * ** * *
** ** * ** **** *
* * ***** * ** * * ** * = number1 / gcd(number1, number2);
* * * * ** ** ** ** * *** = number2 / ** ** number2);
* * ********* *** * ***
** * ** ****** * * **
* ** * ** * * ** * * ( ** *
* ** ** * * * ** * ***** ** ***** ** * ***** ** ** * newNumber1);
*** **** * ** ** *
* * * ** * * ** * *
** *** * * * ** * * *** ** ** * * ** ** ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * **** * *** a,b,c,d,e,f;
** ******* * ** * * * ** *** * *** * ** * * * *
* ** * * ** ****
* ** ** * * ******* **
* * * ** * * * * **
    {
*** * * ******* * * * * **** ** ** *** * *
* ******* ** ** ** * ***** * * ** ** *** * ****
* ** ** ** *** * ** * ** * **** *
    }
* ** * * * ***** * * * *** **
    {
* * ** * * * ** *** * * * ** * ** * * *
* * ** * ** * ****** * * ** ** * * *** ***** * *
* * * ** *** *** ** **** ** * * ** **
* ** * * * ********* * * * ***** ***** * ** * *** * * *** * **
    }
****** * ***** * ** *
    {
** * * ** * *** ** * * *** * ** ** ** ** **** * *
*** * ** ** *** * * * * * * ** ** * * ** * * **
** ** * * ** * ** ** ** ** * **** ** * * * *
* * * * * ***** ***** * *** ** * **** * * * **** ** *** ** * * * *
    }
** * ***** * *** ** ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.184
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 12.2k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 11.8k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 15k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 11.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users