11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
16.7k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 16.7k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

* ****** *   ** * ****   **** i;
**  * *    *  ** *      *** ** j;
*******  *     **** **    * *  * newNum1;
   ****  **      **   *  * * newNum2;
   * **** *  * * * * *** *** gcd;
  *   **   * * ***  ** *  *  rem;
*    *    ***  * ****** *  ***    num1, num2;

  * * **** **   ***   *   *   * *** *  ** ******  ***    **  *  * * * * 

*  *** ** ** *   * **  ** ***
* **   **   **   *  *  ** * **

**   * *   *     * *****  *   ** * != 0)
 *    * **  ****  **   *   * *
**** *  *  ** ***  **   ********  *    *  * *    **     = j%i;
**  *****  ***  *       *  *  * ** * ** *     ****** = i;
*    **  ***** *   *****     * *** * *  **  * ***  = rem;
   *    *  *  * * ** *  *** * 
 ***     ** * * **  *   **** *  **

 * *  * *   ** * *** *** *** * ** = num1/gcd;
* *** *       **    *** ***  *   * *  = num2/gcd;

  *     ******   * ***   * * == 1)
    {
 ** *  * * ** **** * *** *    *  **** ******   **      *   ***    * *** **  *   *  ** ** 
    }

***   * ** *    ****** 
    {
 * *** ***  * * ****   *** *  *** *   ***  *   * ***     *  ** * ***    **  * *****
  ****** * *** **** ** *

* **   *  * *** ** * ** **   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
 *  ** * *  *      ** ******  ** * *    * ****  * ** *  ** *** * * 

  *  ******** ****    *********   *** ***
   **   * *   ****  *   ** *** ** *  * ** * ******** * ** *  *  ***    *  *  ****

    else{
 **   ** *  * *** *      ***  *  * **** * 
    {
 *** *** *** *** **  ****** **    **  * * 
 *** *   *     ***   **** **  * ** * * ** *      *  ***      *  **** * ***  *   ** **  && deno%i==0)
*  ** *** ** *  ***      ***   * *  *  *  * ****   **  **** *** **  **   * *** *** *
*   * *  **  ***   **   *  *  * * *  ******   **   *  *     ** *****    ** ** * * ****  **  *   *  * ****  **
*** ******    ** * * **  * ** *   *    *  *  *** *** *     * * *** ** *   * * **   **** ***   ** * ***** 
 ** *** * * * *  ***  * ** ** *** ** *   **   *     *** *  * * *** *    *****     
    }

**** *  ** ** *  ** ***  **    *** *  
    {
* **  *  *   * **    ** * ****** *  * 
 * *** ** ******   *   ** ** *    ** *   *   **  *   *** * *   *  *** *    **     && deno%i==0)
  * *  **** *        * ***** * * *  ***   ** * *** ** ***  ** **  *  *  ** *****   *
 *  *  *   ****  ****  ** ** ***  * *  **     * **  * **   **     * * *** ***    ***   *     ** * *** *
 * *   ***   * *  *****   ****   * ** * * ** * ***        *    ** *** *   * ** ** *  *** *****  *     *
** **  ** ** *  * *  **        * * ** *      *    *   * * ** **   ** **  **  *  *
    }
* ** * *  *  * *****  *   **  *** * * ***** * * **     *

    }




* *  * *** *   **  ** * ** *  ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ****  ******  ****
#include ** * *      *  

int gcd(int n, int m)
{
* *   ******  *** * * *    *   *** gcd, remainder;

     * *     *  *        ** * (n != 0)
***  *    *   ***** *   *** **  
*   *    **    ******* ***  * *  ** * ******** **  *  = m % n;
  * ***  ***  * *****  ** *    ** *   **** ***  * = n;
**       ***    * * * *** *    *  *  * *   * *  = remainder;
***  * ***   *  ***   ******

*** *** ***  ****  ***  *  *  = m;

* *    *     **** ** *** *** ** *  gcd;
}

int main (int argc, const char * argv[]) {

 *    ** ****  **  * *** * number1, number2;
*  ****   **  **   **  ** *  newNumber1, newNumber2;

** *   *** *  * *****  *  ** * ***  ***  **  *  * * ** **     ***** **

 *  *  **   * ** * *   *  * * **  = number1 / * ** * number2);
*  *  *      * **   ****  * **** = number2 / *   *  ****  number2);

* * ***  * *     ** *  ******* *** * * * *****  ***  
    * ****** * *    **    * * ** *     *** ** **   *    **  * * ******* * 
  *   *         * * ** *  *
  **    * ** ****  ****** ****** * **  **  *   *   ***
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* * **  * **      ****  
 ** *  *** * **   *   * *

int * * ** n, int m)
{
*   *  *  * *** int gcd,      

  * * ** *** *   *  (n != 0)
*   **        {
     *     *     * **** ** *  *****  *      = m % n;
 *      *  **** * **  **  * ** *  m = n;
*     *      *  * ** ***    *   n = ***  * * 
******   *    *    }

 * *    *   gcd = m;

 ****** ***  * *   gcd;
}

int main (int **     char * *** * {

 * ** **   ** *  int  * *  *** 
* **    * *  int  * **   **   * ****

 *  ****    * * ***  * * * * *** **  **  ******** * ***   *

  * ***** *** * *      =  ** ** /  * ** * *** *
***   * *** *  ** **      = **   / ** * * *    *  

*****  *  **  if **     *   ******  *  * *
** **     *****      ***     *  * ** * *  *   * * ** *** 
** *   * ** * else
 *   * *  * * * **** ** *   *      **  *****  *****  *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 * **    **** ** *** **   * **    i;
  **    * * *  **    ** * *  j;
* **** * *****    ****** *  * newNum1;
   ** ** ****  *  *   ****  *  * newNum2;
  **   *   ** *  ******* *   gcd;
 *  *  * * *** * ** **** * * ** **   rem;
* *     ** *  ** **  ***   num1, num2;
    
* ** *  ***** **** ***    *  ** * ** * *     * ** *   *         ***  *
*     * *** **  *   **  **
 **  **** * **    **  * * ** 
  *   * ** **** ** ********* 
 ** *  * * ** *   * *  *  *** 
*    **  **    ********* != 0)
****  **      *******      *
    * *  *  * ** *   * *** **  ******* *   **  * ** *  *   * = j%i;
* *  ** ****  *  **  * * *  ***      **** * * *  *   = i;
 *****       **  **** * *    * ***    *  * *  *      ***  = rem;
* *  *** **   * **  * * *** **** 
 ** **  ****  *  * ** 
    
   ***** *   * * **** * *****         = num1/gcd;
** ***** *  **** *  *           * *  = num2/gcd;
    
***  ***** ** **  ***** * * == 1)
  * * **** * ** * *  *   * * 
 * * ** **** * *  *   ******** ** *** **   ** **  * * ****** **     * **** ** * * *    
***  * * ***     *     * ** * **
    
**    * * ******* ** *     *** 
* * *  *** *   * *  ** * 
* **  ***   * * * *          * **   *  ** **** ******  * * *****  *** ** * *** **     *** *  
   ** **  *   *** * *  * ***** 
    
** **  * * *    **** *** *  *** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
** ***** *      ** **  *   i;
 ** **** * **  **       * **  j;
 *  **  * ** **    ** * * ** ** * * newNum1;
       **** *   * **     **** newNum2;
*  ****      *** ***      ***  gcd;
* ****  * **  **  ***  *  rem;
*   **    ** * * ***  *** * *  num1, num2;
    
** * ***    *  *  **  ** **   *   ****  ** *  ** **   ** *   *   * ** 
   *    *  **   ** * *  ***  
**  *     *  **  *     ** *    **
*    * *    **   * ** *  *   
* ** * **  *    * *  ***  * 
  *** * *    *** **  * ******  != 0)
*  *  **   * *** * *   * *
* * ****  *** * * *  ****** * * *  *     * ****  *    * ***  = j%i;
  **** *   *    ****** *    *  *** ** ** ** * **** = i;
 **   *** * * ** * *****        * *    **** *  ******   *  *  *  = rem;
 **    ****** *  ***    *
* ** **    **** **** *    
    
 *  *****  * *  * *** **     ***** = num1/gcd;
 ** *  ***   *  ***** ** *  * ***  *  = num2/gcd;
    
  * * * *   ** **    *** ****   * * * == 1)
** * *        *** *  *    * * 
***  *** ** * *    * **   *       *   ***  *  * *** *    *  ** *******   *  ***  **** *
*   * *  *  * * * *******  **   *
    
* * **    * * ****   **  * **
    ***** ***  **** *
***  *   *   * *  * * * *   *      * *  * **   **  **  *   ****     * * *   * *     *   
  ****  * *  *     *   *
    
* * * *     *   *    * **  *  * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
*  * *** ***  * **** ** **  *   * ** ** *  ** *** *  ** *  ***  
 ***    ** * *    *  * ** * *   ** *  *  * * ***  *   * ** *** *
    {
** * * *  ***    ***** **  **** *  *** ** ***   * ** ***     ** *  **  
 *  *   **  * ** ****  *** *  *   *** **   ** * **** *   ***  ***
** ****** *** * *    * **      * *   *** * ***** 
**** * **  ** *** *** ** ***   * * * **  *** *   ***  
**   * * *  *  **  *** * **    ** ** * ***

 ***       *  *** * **  *  *
** ***   ** * ****  *   **  ***    * *   ***  * ***  *    * ***  * ** * ** ***** *  ****  ***   * 
* *  ***  **    ******  **   *      *  **  * *** ** ** ****    ** * *** 


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
***  **  *** ** ** ******  *   a,b,GCD;
*  *   **  * ***      *  *       ** *  *  *  *    ** *  ** * * 
  **** **  * ***  *  *   *    *** *
 *  *   * *    ****  * ** ******** 
*  *** *   **   * ****** * *  *** **   ** **** **   *** ******* ***
   ** *     **  *  *  * *    *
** *   *  **** ****   * *** ** *  *** ** * *****       *     * *** * *** **
  * ** * ***    * * **  ***   *  * 0;
}
 **   *      **  *  **  ** *   * gcd(int a, int b){
 ***  * ***  ** ***    *** **** *****  **   **  *  * * (!b) return (a);
**   *  *  * **  * **********  * *     **  ** **** **** * gcd(b, a % b);
**  * *******   *** **  *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ****  *     * ***
#include   ** *   * ***  *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
 * ** *****     *    * ** * gcd, remainder;
   *  * ** ** * * *****  * * *
***  * *  **    **    **     * (n != 0)
*  *     *   *  **  **   **   
** ** *  * *** *   * ** * *  * ** * * **     *** * *    * = m % n;
***** * ********* * *   *       * ** * **    *    *  = n;
*** * **** *  *     ***  *  ** *** *  ***    * = remainder;
** * *  *   * *  *  * * ****    
 ***  **** **** * *** *   *   
** **** ***    ** ******  = m;
*  ***   * ** * *** * * * *  
*  * *  * ** **  ***  * * *****  gcd;
}
int main (int argc, const char * argv[]) {
****    **  * ***   **  * ***   number1, number2;
*** *  * *  *    **  * **   ***   newNumber1, newNumber2;
* ** *  *  **   * * *****    *
*  * **  * ***    **    * * 
* **** ***    **** * * * *     * **   *   ***    * *   *  **  * *****  *    
**   ***** * * * *  *  **** 
**** * **   *** *   ******* **  = number1 / gcd(number1, number2);
  *  * * ****  *  ***   * *  *   = number2 / *   **** number2);
 * **** ***** ***  ** *  ****  *
***   * ****      * * **  
  ** **** *  ***  ** ***   * ( *      **
 * *  *  *    *   ****  *        * *** ** ****  *   ****        * ** * *  newNumber1);
*         *  *    *** **      * 
**  **  *   **** * *  ****  
** * * * ***     **  *     *    *** * * ** * * * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*** *    ***    *  ***  ** ** a,b,c,d,e,f;
**  *   ** **** *    * ** *   *     *****  ** **  ****    * ** *
**** * * **    **   **     **
***  *      *  *   ******    **  * 
   ** *     ** *****   *  ***** ** *  
    {
 * ***** *   *  * *     *  * * * ****  * * ** ****   *  
* **   ***  ******  ** *   ** * ***** ***    * * ** ***  
*** * ***     *** ** *    * * * ***    ****** **      *** ** * 
    }
*   ** ****** * ** *  *   *  *   *  
    {
       *   * *** * *   **   ** *    *** * *** * * ** * *   ** * 
*  * * *  ***  *     **** ** * *    ** ***  ** *  *       *   ** **  **
 *** *** ** ** **   * *   ** *  **  *** ****  **  **  *** **  
**** *    *  **** *** *  *** * *   *   ** ** *** *  ***  * ** ******** *   * *** ** ****
    }
  **  *   ** *  *  *   * ** 
    {
**  *  ***  *** ** **  * ******* *  **    **   *** * *  *** *  ****
**   **   * * *** **   * * ****  ***** **   ** *     *    * ****     
** ******  ***  *** **** **    *  *** **   **  ** ***  *** *  
* **  * **  ***  *     ****  ** * * ********* **  *  *    ********  *    *  **      * * *  **
    }
*  *     * * ***        *  ** **  0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 17k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 16.8k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 22.1k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 16.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users