2 like 0 dislike
7.8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 7.8k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

** * ** ** * *** * ******* * ** i;
********* * **** * * *** j;
* * ** *** * ****** * * * * newNum1;
*** *** *** * * **** newNum2;
* * *** * * gcd;
* * ** ** * * * * * rem;
*** * * *** ********* ** num1, num2;

* * * **** * * ** ** * * * **** **** * * ** * *

** ** * ** * ** * * * ** **
* * * * * ** ** ***

***** * * *** * * *** * != 0)
* ** **** ** ** ***** *
* ** * ** * * ** * * * *** ** ** ** * *** = j%i;
* ** *** ** * * * ** * ** *** ** * * = i;
**** * ***** * * * * ** * * * *** ** ** * * = rem;
* ********* * ****** * * *
******* *** * * ** ** *

********* ** ****** *** * ** = num1/gcd;
**** * **** ****** * *** * = num2/gcd;

** * **** ** **** ** ****** == 1)
    {
** ** * * ** **** *** * ** * ** ** ** * *************** * * * **
    }

* ********** *** ***
    {
* *** ******** * * ** * * * ** * * * ** ******* ** * ** * * **** *** *****
********* ** * * ** * *

* ** * ****** ** * ** **** *** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** * * * * ** * ** * *** ** * * *** *** *

* *** ** ** ** * * **** ** **
* ** ** ** ** ** ** * **** * * * ** * ** ** ** * * **

    else{
** * *** * * ** ** * * * ** * ** **
    {
** * * * ** * ** ** **** * * *
* *** ** * ** ** * * **** * ** ** ** ********* * * ** ** * *** && deno%i==0)
* *** * * * * ** * *** * * *** **** ** ** ****** ** **
* ***** *** * ** * * *** *** * * * *** * * ** ** * ** * ** * *** * * *
*** ** ** ** * * ** *** * * *** * * *** *** *** ** ** * **** ***** **** *
* ** * * ** * * ** * ** * ** *** *** ** *** **** * ** **
    }

* * * * **** * ** **** * * ** *
    {
* * * * ** ** * * * * * * *** *
* * * * * * ** * ** * * *** ****** **** * ** *** ** * * *** *** && deno%i==0)
*** * * *** * * * *** **** * * * * * *** * ** *********** * * *** *
** ** * ** * * **** **** * * ******* ** * * * ** * * * * **** ****** ***** *
* ** * ** * * * * ***** * *** * ** * ****** * ** * ** * * * * * * * * ** ***
* * * * * *** * * * * ** * ** ** ** **** ****** *** * * * * ****
    }
*** * * * **** * ** * * ***** ** *** ** *

    }




*** ** ** ** * ** *** ***** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** * ** ****
#include ** ** ***

int gcd(int n, int m)
{
* * * * * * *** ** gcd, remainder;

** *** * **** ** * * (n != 0)
*** ** * * ** * ** ***
** ** * *** ** * * * * ** ** * ** * **** * * ** = m % n;
** **** * * ** **** ** ** **** * ** * ** * * ** * **** * = n;
* *** *** * * * * ** * * * *** ** * * * ** ** = remainder;
* * * ** * ** *** ***

* * ** *** *** ** * * = m;

* * ** * ** * ****** **** **** * gcd;
}

int main (int argc, const char * argv[]) {

* * ** ** *** * * * number1, number2;
**** **** * * * *** ***** newNumber1, newNumber2;

** ***** ** * * **** ** * * ***** * ** ** ***** ** * ** * * *****

* ** ** * ****** * ** * = number1 / ** number2);
* * ** * * ** **** * * * ** = number2 / * **** * number2);

* * * * * ** * * * ** * * ***
* *** ** ** ** ***** ****** * * ** ***** * **
***** * * * *
*** * * * ***** * * * ** * *** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * * ** * ** * * ***
** *** * * * * **

int ** * n, int m)
{
** * * *** int gcd, * ***

* * * * * *** * (n != 0)
* ** * *** ** {
******** * * * * *** * * = m % n;
* * * ** * *** ** * * ** * m = n;
* ** *** * * ** * ** n = * * *
* *** * ** ** }

** * * * ** gcd = m;

* * * ** * gcd;
}

int main (int * * char * *** {

* * ** ** int ** ** ** *
** *** *** int * **** * *

*** ** * * * * * ** ** *** ** * * * * *

* ** * * * * ** = ** / *** * ***
* ***** * = * ** / * * * * * * * **

* * ** * *** if * * ** **
* * * * ** * * ****** * ** ** *
** * ** else
* *** * * * * ** ** * * * ******** ** * * *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ****** **** * ** i;
* * * ***** * ** * ** ** j;
* **** * *** * * newNum1;
**** ** * ** ** **** newNum2;
** ** * * * * ** * gcd;
* * ** * *** *** * ** * rem;
* ** * ** * * * ******** **** num1, num2;
    
** *** *** * * ** * * * * * ****** *** ** ** ** * * ***
*** * **** * * * *
** **** * * * ***** *
***** *** ** * * *
* ** * * * ** * * ** * *
*** *** ** * ** *** != 0)
*** ** ** ** * * * * * **
* *** * * ** ** * ** ** ***** ** *** ***** = j%i;
** * * *** ** ***** * * * ** * ** ** *** ** * ** = i;
* * *** * * ** ** * **** ******* ** = rem;
*** * ** ** * *** * ****** *
* * ** * ***** *
    
* **** * *** * ** ** ****** * = num1/gcd;
* ** ** * ** **** * ** *** * = num2/gcd;
    
** * * * * ***** * * *** **** ** * * == 1)
*** * * * ** *
* * * **** *** * * * * * **** * * * **** *** ** * * * *****
******* * ******** * * *
    
**** * * * * * *** * **
****** * **** * * *
**** **** * * ** * * **** *** * * * * * * * *** ** * *
** * * * *** ** ***
    
*** * * ***** ***** * * * * * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** * * * ** ** * * ** ***** i;
*** ** * *** * * * * *** j;
* * * * * ** *** * ** newNum1;
* * * ** ** * * **** newNum2;
* ****** *** * *** * gcd;
** * *** *** ******* rem;
* *** **** * * num1, num2;
    
*** ** ****** * * ***** ** ** *** ******* * ** *
** ** ****** * ***** *
** * ** *** ** * *** **
** *** * ** *** * * * * **
**** * * * * * * * *
**** ** * * ** * ** * * != 0)
***** * * ** ** *** ***
** * ***** * * ** * ** ** *** * *** * * ** = j%i;
** * ***** **** ** ** ** * * ** * * ** = i;
** ******* * ** ** ** ** * ** **** *** ** * * = rem;
** ** ** ** **** **** * * *
* * * *** * ****** * * * *
    
* * **** ******* ***** * *** = num1/gcd;
******** *** * *** * *** ** = num2/gcd;
    
* **** * ** **** * * * == 1)
* * *** * **** ** **
** *** ********* ** * * * * **** *** ** ** ** * * * ** * * ** * ***
** *** * * *
    
**** * ** * * *** ***** * **
** * * ** * **** ** *
* *** * ** * * ** *** ** ****** * * *** *** *** **** ***** ***** * ** * * *
* ** * * ** ** *** **
    
*** ***** ** * **** * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
***** *** * ******** ** * **** * *** *** * * * **
** * ** * * *** * * ** * * ** *** * * *** * *****
    {
* *** *** * **** * * * * ** *** * ** * * ** ** * ** *
** * ** * * **** ** **** * **** ** ** * * **** ** * ** *
* *** *** *** **** * ** * * **** *
*** ** *** ** * ***** * * * ******** *
****** * *** * ** *** * ** ** *** *

***** *** * * * ******* *
* *** * * ** * ** ******* *** * * * *** * ** ** * * * ** * * **
* *** ** ** *** ** * ** **** * * ** * * **


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*** **** **** * **** ** a,b,GCD;
**** ** * ** **** * * *** ***** ** **** * * *** *** **
*** * * ***** *** * * ** * * *
*** ** * * * ** *** **********
* * ** ********* *** * * ** ** ****** * ** *** * ***
** * * * ** * * * *
* * ** ** ** * *** * **** *** * ** *** *** *** * **** * *** * *
* * * ***** * * 0;
}
** ** * * ***** **** gcd(int a, int b){
* *** ***** ** ** **** **** * * * (!b) return (a);
* * *** * ** **** ******* * * ** * * * * * ** *** gcd(b, a % b);
**** * * * * * ** ** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * * ** * *****
#include * ** * ***

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
**** ** ****** ** gcd, remainder;
** ** * * ** *** * ***
*** *** ** ** * * * * *** (n != 0)
**** ***** *** ** * *****
* ** * ** **** * *** **** ** **** *** *** * * **** *** = m % n;
** * *** * * * * * * * * * ** * * * = n;
* *** *** * ** **** **** ** * ** ** *** * * ** * ** = remainder;
* ** * *** ** **** * * *
* * * * *** *
** ** * * *** * ** * * ** * = m;
* ** *** * * ** **
*** * * *** ***** * ** ***** gcd;
}
int main (int argc, const char * argv[]) {
* * * **** * * * * ** number1, number2;
* * ** *** ***** *** newNumber1, newNumber2;
* * ** * * * **
** ** ***** * * **** *** * * *
* * * *** * * ****** * ** * ** * * * * * * * **
**** ** ** * ** ** * ***
* * * * ** * * ** *** *** ** = number1 / gcd(number1, number2);
* * *** ** * * * * * * ** = number2 / * *** ** number2);
* *** * * * * ** * * *** *
* *** ** * *** * * *
* *** * ** **** * * * ( ** ***
* ** ** ********* * ** ********* ***** ****** * * * * newNumber1);
**** ** ***** ** *** ***** *
* * ** * ** ** ** *
******** * * * ** **** ** * ** * *** ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * * * * * ** ** *** * a,b,c,d,e,f;
****** *** **** *** * *** *** * ** **** * *** * * ** *
** *** ** * ****** * *** ***
* * * * * * * ** ***
*** ** ** * *** ***** * ** *
    {
* * *** * * * * * ***** ** ** *** * ******* ***
** * * * * * * *** * * ** ** ****** * ***
** * ** * ***** ** **** *** ** ** * ** * **** *
    }
***** * * ** * * **** **** ***
    {
*** * ** * *** ** * * * * ***** * *** **
* ****** **** * ****** **** * ** * * * * * *** ** * * ** ** *******
* * ** * * *** ** *** ** * * * * * *
*** ** * *** * * * ** **** *** * **** * * *** * * *
    }
**** ** ***** ** *
    {
* ** * **** * * *** * * * *** * *** * ******
**** * * ** *** * * * ** * *** ******* ** * * * ** ** **** ** * ***
* ***** **** ** * *** * ** **** * ****
** * * * * * *** * * *** *** ** * *** * * *** * *** * * *
    }
** ** * * * * * * ** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.121
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 8k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 7.7k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 9.7k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 7.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users