2 like 0 dislike
1.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 1.9k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* * ** ** * *** * * i;
* * * * ** ** * * * * * j;
* * * *** ***** * * * * * newNum1;
** ** * ** ***** * * ** * newNum2;
** ***** **** *** * gcd;
* * * ******** * ** * * * * rem;
** ***** ** * ** ** ***** * * num1, num2;

* * ********* ** ** ** ** ** * *** ** * * *** *

**** *** ** *** * **** *****
* * * ** ***** *

** ******* * * * * * ** != 0)
** *** ** * * **
** **** ** * * ** ** * * *** **** * **** * = j%i;
* * ** **** * * * * * * ** ** ***** = i;
* *** * * * * ** ** * * *** * ** * = rem;
* * * * * * *
* *** ** ** * ** *** * **

** * ** **** * ** = num1/gcd;
* ** *** *** *** * *** * * * = num2/gcd;

*** * * * * *********** ** ** == 1)
    {
*** * ** * *** **** ** ** **** ** * *** ** * * * * * * ** * *
    }

** * * * ** * * **
    {
** * * ******* * * ** * ** ** * *** * * *** ** * *** * * **
** * * ** * * ***

* * * * ** * * ** ** *** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * ** *** ** ** *** ** * **** * * * ** * * *** * **

** * *** * *** * ** * **
* * **** ** * ** ** *** ** * * * ** ******* ** **** **** * **** ** *

    else{
* * * ** ** * * * ** * * ** *
    {
* ***** * ** * *** ** ** ** ** *** * * *
*** * * * * * * **** * *** ****** * *** * * ** ** ** * * * * *** ** **** * && deno%i==0)
* *** * * ** * *** ** * ** * * *** *** **** *** * *****
* *** * * **** *** ** ** * ***** **** *** * * **** * * * ******* * ** ** ** *
* ** ** * **** * *** **** ** ** * * * ** * *** *** * *** * *** **** *
***** * * * ** ** ** ** * * *** **** * * * ** ***** * **** **
    }

** * **** **** * *** * * *** *
    {
* *** **** * * ******* ** * * **
* ** * ** *** ** **** * ***** ** * **** * ** *** *** * * ** && deno%i==0)
* * *** * * *** * *** *** ** * * ********* * * **** **** ** * ** * ***
* * * * * * *** **** *** ** ** ** ** ** **** * * ***** ** ***
** * *** * * * ** * * * * * **** * *** ** *** * *** * * * ** **** ** ** * *** **** * *
** ** *** ** * * * * ** * **** * **** * * ****** ** * ** *
    }
* * ****** * ** * *** ** ** *** *** * * **

    }




*** *** ** * * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * **** **
#include *** * * *** *

int gcd(int n, int m)
{
*** * * * * ** gcd, remainder;

* ** *** * * ** *** * * (n != 0)
* ** * * * * ***
** ** * *** * *** ** * * ** * * *** * *** * = m % n;
* ** ** * * * * ** *** * * *** ** * * * = n;
* **** *** *** * ** * * * * * *** = remainder;
* * * ** ** * ** **

* * * * * * * * *** = m;

*** * ** ** *** *** * gcd;
}

int main (int argc, const char * argv[]) {

** **** * **** * ***** * number1, number2;
* **** ** * * * * ** newNumber1, newNumber2;

** * *** * **** * * *** ****** * *** * * *** *

* * * * ****** * ** ***** = number1 / * ******* number2);
** * **** * * ** **** ** ** *** = number2 / * * * number2);

* * * * ** * * * ** * ** * ** * * * ***
* * **** **** * ** * ** ** ** ** *** * *** ** **
* *** ** * * * * *
*** * *** ** * * * * **** ***** **** * ** **** *** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
** * *** * *** * *
*** *** * * * ***** **

int *** * n, int m)
{
**** *** * int gcd, ** *

* **** * *** * (n != 0)
** ** * {
* **** * * ** **** ** * **** ** * = m % n;
* * ** ** ** * ** * m = n;
***** * ** * * * ** * n = **
** *** * * *** }

*** * * * * * gcd = m;

* * * * ** gcd;
}

int main (int *** * char * * {

** * * * * int ***
* * ** int * * * ** **

* * * ** * * * ** * * * * * ** * **** *

* * ** ** = * * * / ** ** * * *** *
** ** ***** * * = ** / ** * **

*** *** * * * if * ** ***** * *
* ** * ** **** * ** *** * * * * *** * * * * *
* * * ** * * else
** * *** * *** * * *** * *** * ** ** ** * **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ** * * ** *** * * * * i;
** * ** * ***** * **** j;
****** * * * * * * newNum1;
** * * * * *** ** newNum2;
** ********** **** *** gcd;
** ***** **** * ** * rem;
* **** ** **** *** ** num1, num2;
    
** * * ** ** ** * * * ** *** ** *** * ***
* *** ** *** **** ** ** **
** * * * * * * * ** **
* * ** * *** ****** *** * *
* * * *** * * *
** **** ** **** * **** * * != 0)
** * *** *** *** *** *** **
****** *** ** * ******* * ** **** ***** * ** = j%i;
** *** **** *** * * ** *** ***** ** **** = i;
*** ** * ** * ** * ******** *** ** **** ** ** * = rem;
** *** * * * * *
** ** * ** * ** * **
    
* * ** **** ****** *** = num1/gcd;
*** *** ** * ** * **** *** = num2/gcd;
    
**** **** * * * * * ** * ** * == 1)
* ****** ** ** * ** *
* **** *** * * * ** ** ***** *** * **** * * ***** ** * *****
** * ** * ****** * ** *
    
********* *** * * * ** *
* * ** * * * * * ** ***
* * * ** ** **** ** * *** ** * * ** * ** * * ** **
** * * * **** ** *
    
* *** * ** * ** ******* 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ** * * *** ** * ** i;
*** ** * * ***** *** * ** j;
** * ** ** ** *** * newNum1;
*** * * * *** * * * **** newNum2;
*** * * * * * * *** * gcd;
*** * * * ********** * *** rem;
* * * * * ** num1, num2;
    
* ** ***** *** * * ** * ** * * ** ***** ** * ** *
* * ** ******** *
* * ** * * ** ** **** ***
* *** * ******* * ***
* * ****** * ** * * *
* ** *** *** * ** ** != 0)
* * ***** * ******
* *** ***** *** *** ***** * * ** * *** * ****** = j%i;
* **** * * * * * ** * * * * *** **** = i;
* * *** **** *** * * * ** ** * ** * * = rem;
* * **** ** * ** ** **
* *** **** ***** * ****
    
*** * ** ** ** * *** = num1/gcd;
** * ** * ** * ** * * ** = num2/gcd;
    
** ***** * * ***** * ** * ** *** == 1)
* * * ** * * ** ***** *
** * * * * * * * * * * ** ** *** * * * *** *** * ****** **
* * * * ******** * ** **
    
* ** ** * ** ** **** ** ***
* * * ** *** ***** * *** *
*** ** **** *** * * ** * * * * * * * * * *** * * *
****** ** ** **
    
** *** *** * * * *** * **** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
****** ***** * * * ********* ** * * * * * ** * **** *** *
* ** * * * *** * * ***** ** * * * * *** * ***
    {
** * * * **** *** * ** ** ******* * ** *** * *** * *** *** * *
*** ** *** *** * ** * * * * * * ** * * * * *
* * * *** * *** * * * * * * *
*** * * * * ** ***** * *** ** **
** * * * * * * *** * ******* * **

**** ** ***** * * * * * * *
*** * ** *** * * * **** *** ** * * * ***** * * ** * * * *** ** *** * ** * ** *
** * ***** * * ** * * ** ***** ** ***** * *** * *** ** * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* ** * ** * **** a,b,GCD;
* * * * ** * ** * *** *** * * * * * *** ** * **
** * **** ** * * ** * ** ** *
** ********* ** * * ** *** *
* ** **** *** ** ** * ** * ** *** ** ** * * * ***
** ******* ** ** *
** ** *** **** *** ** * * * * * * * * *** *** * * * * * * *
* * * * * ** * *** 0;
}
* * ** *** *** ***** ***** * gcd(int a, int b){
* * * * * *** ***** * * ** * * ** * **** (!b) return (a);
** * ** * * * * * * ** * * * ** **** ** ** ** * gcd(b, a % b);
* ** * * * ******
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * *
#include *** *** **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
*** *** *** * * * ** * *** *** gcd, remainder;
** * * * * ** *
**** * ** * * **** * ** *** (n != 0)
* * ** * * ** * ** * *
*** ** * * ** ** * ** * * ** * = m % n;
** ****** * *** ** * ** * * * ** * ** * = n;
* * * * * * ******* ** ** ** **** = remainder;
* * *** * ** *** * *
** ** *** *** * * * * * ** *
* **** * ** * ** * = m;
* * * * ** * ** * ****
* * ****** * **** ** *** * gcd;
}
int main (int argc, const char * argv[]) {
*** * * *** * ** * ** ** number1, number2;
** * ***** ** * * ** * * newNumber1, newNumber2;
***** * ***** * * * *
* *** *** * * * *
* * ***** ** ** * * * * ** * ** * ** *** * *** *** * * **
* * ** ** *** *** * ****
*** ** * *** * *** * ** = number1 / gcd(number1, number2);
* ** * *** * ** * * * * = number2 / ** ** number2);
*** ** ** *** *** *
**** * * ** **** * *** *
* * **** * * *** ** * * ( * * *
* * * * * * * *** *** ** *** ** ** * * ** ** * ** newNumber1);
** ** ** * *** **
** ***** ** ** ** *** *****
** ** * * * * * ** * ** * * *** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** * * ** * * *** a,b,c,d,e,f;
**** **** * * * * **** ** * ** ***** **** ** ** **** **
* * ** * **** * * * **
*** ***** **** * * ** * * **
* *** * * *** *** * **** ** *
    {
** *** ** *** *** ** * * * *** * * ***
* ** * ***** * ** ************* * ** * * *
** * ** * ** * * * *** * ** ** **
    }
* * * ** ***** * ** * * ** ** * *
    {
** * ** *** * ** * **** *** * * * ********* **
* * * ** **** * **** ** ** **** * *** * ** * * * * ***
* * * * ** * * * **** * ** * * * *
* * * * * * *** ***** * * ** ****** * ** ****** ***** * *
    }
* * * *** * ******** * * * *
    {
***** * * * * * * * **** * ***** * * ** *
**** ** *** **** **** * ** * * *** * ** * * ** * * *** ** * ***
******* * ***** ** ** *** * **** * * * *
*** * ** ** ** * * * * **** * * ***** * ***** ** * *** ** **
    }
* * * * *** ** *** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.2
©2016-2024

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 2.4k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 1.9k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 2.4k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 1.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users