2 like 0 dislike
18.3k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 18.3k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* ** * ** *** *** *** i;
* * ** ** *** * * * * ** j;
* *** * ** ** newNum1;
* ***** * * * * ** newNum2;
** *** * **** ** * * * gcd;
* ** *** * ** *** * rem;
** * **** * **** num1, num2;

* * * * * ** * ** * **** * * * * * * ****** *

******* * * * * * * *
* * *** * ***** *

** *** * ** **** *** * != 0)
** * *** * * * *
* * * ** ** *** * ** * * * **** ** * = j%i;
* * ** ** ** *** ** ***** *** ** ** ** *** = i;
***** ** * * * * * * * * * ****** * ** ** * * *** = rem;
*** ** * * ** ** ** *
* * ** * *** * ** ** ****

***** * * **** *** * * * * = num1/gcd;
* * * ** **** ** *** * = num2/gcd;

**** * *** * *** * *** * *** == 1)
    {
* **** * ** * *** ** *** ** ** * ** * **** * *** ** *
    }

*** ** ******** * ***
    {
******* * * ** ** * * * **** **** * * **** * *** ** * **** *** * * ** * *
* * ** ** * * * * * ****

* ** * *** ** ***** ** * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* **** **** ****** ** ** *** * * * *** ** ** **

* ** * * ** ** **** *** ***
* ** * *** * ** ** * ** * * ** ** ** **** *** * * ***** * * *

    else{
* * ** * ** ** * * ******* ** *** *
    {
******* *** * **** * * * ** *
* ******* ** *** * * * **** ** *** ** ** *** * *** * * * * ** && deno%i==0)
*** * *** ** *** ** * **** * * * * ** ** *** * *** * ** * ******
* *** * ** * ** * * ** * ** ******* * * **** ** *** ** ** *** * ** * * * * **
* ** ** ** * ****** * * *** * ** * ******* ***** * *** * ** * *** * ** * * *
** * ******* ** * * * **** * * *** * ** * * * * **
    }

** **** * ****** ** * * *
    {
* * ** * * **** * ** * **** * *****
* **** ***** * ***** **** * ** *** ***** ** * * ** ** * * ** ** * *** * && deno%i==0)
**** * * ** * * ** * ** * ** * * * * ** **** ** * * ** *
* * ** * ** ***** * *** ** * * ** * **** **** * * * * * * * *
* * *** * ** ** ** *** ** ** *** ** * ** ** *** * * * * * * * * ** * **** *
******** ** * * * * ** * *** * * * ** * *** * ** ** ***** **
    }
* *** * *** * * ********* * ** * **** *

    }




***** **** * * *** ** * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** ****
#include * * ** **

int gcd(int n, int m)
{
** * * ** * * *** * * gcd, remainder;

* * *** ** * * ** **** *** * (n != 0)
* * * *** ** * ** *
**** * ***** * * *** * * *** * ***** *** * * ***** = m % n;
* *** * ** * * * *** ** * ** * ** * ******* ** = n;
* *** ** * * * * * * * *** ** * ** ** = remainder;
** * *** *** * * **

****** * ******* ***** = m;

* * *** * **** *** ** gcd;
}

int main (int argc, const char * argv[]) {

* ** ******** **** *** * number1, number2;
** **** ** * *** newNumber1, newNumber2;

* *** ** * * * ****** ** * * ** * * * * * * ** ***

*** * ** ** **** * ** * = number1 / * ** number2);
* *** ***** **** * *** * = number2 / **** * number2);

* * ** * * ** * * * ** * **
* * **** ***** * * * ** * *** ** ***** ***** * * **
* ** * * * * * ** * *** **
* * ** * * ** ****** * * * *** * ** *** ** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
** * * * * ** ***** **
* ** **** * * * * *

int ** n, int m)
{
** ** ** * ** * int gcd, * * **

*** * *** (n != 0)
* ** * ** {
* *** * ** ** * * *** ** *** * = m % n;
* ** ** ** * ** ** * **** m = n;
* * ** * **** * ** ** n = *** **
* * ** ** }

**** * gcd = m;

* * * * ** gcd;
}

int main (int ** char * ** * {

* ** *** int * * *
* ** ***** ** * * int **** * * *

* *** * ** *** * ******* * * ** * * ** *** ** *

* * * * * * * * = **** / * * *** *
** ** ** *** = * ** / * *** *

* ** ** * ** if * ******
* ** * * * * * * * * * * * ** * ** *
*** * * *** else
* ** * * * * * **** * * *** *** ** * * * * *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
**** * **** * ** ****** * i;
** * * * * ** * **** j;
* ** * ** ** * * ** * **** * newNum1;
* *** * * ** * newNum2;
* * ** ** ** ** *** *** gcd;
** * ******* * **** *** * ** * * rem;
*** * * * * * ***** * num1, num2;
    
***** ***** ** ** * * * * **** *** ***
* ** * *** * ** * *
** ** ** * **** * *
** * * * ******** *
**** * ***** ** ** **
* ** ****** ** * * * ** *** != 0)
* *** ***** * *** **
* * * *** * * *** * **** ** * * *** ***** *** * *** = j%i;
** * ***** **** * ** *** *** ** * * * ** = i;
** **** * * *** ****** * *** * * * * *** ** ** = rem;
** * *** * * ** **
*** ** ** ******* *** ** *
    
* ** * *** *** * ** * **** = num1/gcd;
* * ** **** ********* ** * = num2/gcd;
    
** * ** * * * * ****** == 1)
* * * ** ** ** * *
**** * * * ** * ** * * ** ******* * *** * * * *** *** ** *
******* * *** ** ** * *
    
* * * *** ** * **
* ** *** * ** ** ** *
* * * * * * * ** *** ** ** * * ** ******* ******** *** ** * ****** **** ***** * * * *
** * ** ** * **** ****
    
* *** * ***** ** * *** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** * ** * *** ***** i;
****** **** * ****** * * j;
* ******** ** ** **** ** newNum1;
****** * * *** * ** newNum2;
* *** * * * * * ** gcd;
** *** ** *** * * * * ****** rem;
* * ** * * ** *** **** num1, num2;
    
* ***** ** *** * * * ** **** * ** ** * * ** **
*** * * ********** *
* * ** **** **** *
* ** *** ** * * * ** * *
******* * * ** ** ** *
* * * * * ***** ***** != 0)
* ** *** ** * ** ** ** *
* * * ** * **** *** * * * **** ** *** * * * * * = j%i;
**** ** ** *** * ** *** ** ** * ** ** * ***** *** = i;
** * ** ** * * * * * * * * * * * = rem;
** * * * * ***** *
* ** *** ****** *
    
* * ** ***** * ** ****** * ** = num1/gcd;
* * * ** * ** * * = num2/gcd;
    
* * *** *** * *** *** * * == 1)
** ** **** *** * **
* *** * **** ** ** * * * **** ** ** ** **** **** * **** * * * **
** * ** * * ***** **
    
** *** *** ** * * **
** ** ******* *******
* ** ** *** * ** ** *** * * * * * * ** ** *** * ** * ******
**** * * * ** * * **
    
* * * **** * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* ** * * *** *** * *** ** ** * * * ** * *** * ** *
* * ** * ** * ** * **** * ** ** ** ** ** * ****
    {
* ** ******** * ** ** * *** * ** * ** * * ** ********** *
* * * ** *** **** * * *** ** ** ** * *** ** * ** * *
* **** * * * ** * * * ** * * * *
* * ** * * * * ** ** * ***** *** *
********** * * ** * * **** * ****** ******

* * ** * * ***** * *
* * ****** * * *** * * * *** **** * * * ** * * ******* ** ** **** * * * * * ****
* * *** * * * * ** * ** ** **** * ** ** ** ** * **** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* ** ** ***** * * * * a,b,GCD;
** ***** * * * * * * ** ***** * * *** ********** *
*** ** * * **** * ** ****
** ** * * ** * * ** ** ** **
* * ** *** * **** *** * * * ** * * * ** ** * *** * * ** **
* *** *** * **** ** ***
****** * * ** **** **** ** ** ** * * * ** * * ** *** **** * * *
** * ** ******* ** 0;
}
** * * * *** * * * * gcd(int a, int b){
* * ** * * * * ** * *** ** ***** * * (!b) return (a);
** ** ***** ** * *** ** ** ** * ** * *** ** gcd(b, a % b);
** ***** * * * **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** ** * * *
#include ** ** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
*** * ** * **** *** * gcd, remainder;
* * *** ** * * **
** * * * * *** ** ** (n != 0)
** ** * *** * * * *****
* * * * * **** * * ***** * ****** *** * * ** *** = m % n;
* *** ** ** *** *** *** * ** * * * **** = n;
* * ** * *** *** **** * ** * *** * * * * = remainder;
* *** ** ** * * ****
* * **** ** ** ** *
* **** * * ** * **** * = m;
*** * * * *
** *** ** ** * * * gcd;
}
int main (int argc, const char * argv[]) {
* ** * * ** ******* ***** * number1, number2;
*** *** * * * ** ******* newNumber1, newNumber2;
** ** * ** * * *
*** *** *** * *
* ***** ***** * ** ** *** * ** * ****** * **** * * ** ** * ***
* ** ** * * * * * **
*** * ***** ***** ****** = number1 / gcd(number1, number2);
*** ***** ** * *** ** * * = number2 / *** * number2);
* * ** * * **** **** * ** *
** *** * * * * *****
* *** * * * * * ( *
* * *** ** *** ** ** * * ** **** * * * * * *** * **** newNumber1);
** ** ** ** **** *****
* * * * *** * * ***
* * * *** ** * **** ***** ** * ***** ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** ** **** * *** * * a,b,c,d,e,f;
* * ** ** **** *** ****** ** * ** ** *** * * * ** ** **
* **** *** * *****
* ** * * * *** ** **** ****
***** ** * * * * ** * * *** * *
    {
********* * ** *** * * * ** * **** **** * ** ***
* ** ** *** * * * * * *** * * ** * ******
*** ** * ****** * * *** *** ** *** **
    }
* * * * * ** * ** *** * * ***
    {
* * * ***** ** * **** *** *** * * ** **** **
* ** ** ** * *** * ** ** ** ** * * * ** * ** ** **** * *
* * * *** *** ** * * ** ** * ** **** **** *
** * * ** * ** ** *** * *** * * * * * *** *** ***** * ***** * ** *
    }
** ** ** ** ** * **
    {
*** ** * * * * * ***** **** ** * * ** ** **
* ******* ***** * ** ** ** * ** **** ** ** * * * ** * * * * *****
* * * * * *** * ***** ** * ** **
*** * * * * ****** * ** * **** * * ** ** ** **** * *** * ** *
    }
* * *** ** * * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 18.2k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 18k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 23.9k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 18.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users