2 like 0 dislike
14.4k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 14.4k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

** * * ** * * *** * i;
********** * * * * *** ** j;
* * * * * ** **** * newNum1;
* * * ** * * ** * *** newNum2;
* ***** *** * ** * *** gcd;
** ** *** ** * * * rem;
****** ** * ** ** *** * num1, num2;

** * * *** ** ** * * ** ** * ** ** * *** * * *** * * *** *

** ** * ** * * * * * * *
* * * ***** * *

* * * * * * ** * != 0)
** * ** ****** **** *
***** * ***** ** **** * * *** ** *** *** ** * = j%i;
** * * ** ** *** * ** ******** *** * ** **** ** *** ** = i;
*** * * ****** * *** * ** * **** * *** ** **** ** = rem;
**** ** * *** * * * *
** * * * ** *

***** *** ** * * = num1/gcd;
** ** ** * * **** * * ** = num2/gcd;

* *** * ****** * ** ** * * == 1)
    {
***** * *** ** * * ** **** ** * ** ** ** ** **** * *** ** ***** * *
    }

** * * * *** ** **** * *
    {
** * ** ** * **** ** **** * ** ** * * ****** * ** * **** * * ** * * *****
* ** * *** ** * **

* ** ** * * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
***** ** * * **** * **** * *** * * * * * ** *

*** * * * *** *** *** *
* * ** * * * * ** *** *** * ** * * ** * **** ** ***** *

    else{
** ** * * * ** * * * * * **
    {
* ****** * *** ***** ** ** **
* **** * ** * * ** * *** ** * ****** * *** * * *** *** ** * * * && deno%i==0)
** **** * * ** * ******* *** *** ***** * **** * * * * * **
** * ** ** * ** * *** ** * ***** **** **** ** * * * *** * * ** * ** * * *** * * * **
* *** *** * ** * ** * ** * ** ** ** * * * ** *** * * ** * ** *** *** * **** *** *
** * ******** * * * ***** * *** * * *** * * * **** * * * ** *** * * *
    }

* * **** * ** *** * **
    {
* * ** ******* ***** *** ** * ** * * * * *
* * * * ** * *** ***** ** * *** * **** ** * **** ** ** *** * * * ***** ** ** && deno%i==0)
* *** * * * **** ** *** * ** * * ** * ** ***** * * **** ** * *
*** ******* * * * * * *** ** * ** *** ** * **** * **** ** *** * * * * *** **
** * * ** * ** ** *** * ** ****** * * * *** * * * * *** * *** *** * ** * *** * * * *** *
* * * ************* *** * * * * ** *** * * * ** * * ** * * **
    }
** * * * * ** ** * * ****** **** * *** * *

    }




** * *** * * * * **** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** *** * * *
#include * * * * *

int gcd(int n, int m)
{
* ** * ** * * * ****** gcd, remainder;

** * * *** *** *** ****** (n != 0)
****** ** ** *** ** ***
* ** * ** * ** *** * ** ** *** * *** *** * = m % n;
* **** * * ** ** ** ** ** * ** * ** * * = n;
* *** * *** **** *** * *** * * * ** * = remainder;
******* * ** ** * *

*** ***** ** ** *** = m;

** * ** ** ** ** * **** ** **** *** gcd;
}

int main (int argc, const char * argv[]) {

*** ****** * *** * ** **** number1, number2;
** *** * * * ** ** newNumber1, newNumber2;

** ** ** * * ** * ** * * * * ** ** * * * * ** * **** *

* * * ***** * * * ****** = number1 / * *** * number2);
** ** * ** * * ** * = number2 / * * *** number2);

** * * * * * * ** * ***** ** ** *** ** * **
* ** * *** * * * * ** ** ** * *** * ** * *** * ** *
*** ** ** ** **** * * * **
** * *** ***** *** * * *** ** * * ** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
*** * * * *******
* * * * * * *

int * n, int m)
{
** **** int gcd, * *

*** ** *** (n != 0)
* * ** ** {
* * * * * * ** * * ** = m % n;
** *** ** * * m = n;
** * ** * ***** * **** * ** n = ** *
* ** ** }

** ** * ** gcd = m;

**** *** * * gcd;
}

int main (int * char * * * {

* * * * int ** *
* * * *** int *** *** * * **

* *** ** * * * *** *** ***** * **** *** ***********

* * * *** * ** = ** / * * * ***
* * ****** ****** = ** / *** ****

** * * if * ******* **** *
** **** ** * ** ** * **** * * * * ** * **
** * * * else
* * ** * ** * ******* * *** ** ** ** ** ** * ***
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * * *** * * **** * i;
*** * ** **** * * * * j;
***** *** *** * *** * ** newNum1;
* *** * *** ** * ** * newNum2;
* ******** **** * ** ** * gcd;
* * ** * * ****** * *** rem;
* ** ***** * * * * * num1, num2;
    
*** ** ****** * * *** **** * * * * * *** *** *
**** *** ** * ** * ** *
* ** * *** *** ***** * * ** *
**** * *** * * **** **** *
** ** * ** ** *
* * * * * *** != 0)
* *** ****** * **
** ** * *** * * ****** **** ** *** *** * * = j%i;
* *** * * ** **** *** ******* * ** * * ** * = i;
** * * **** ** * ** * *** *** ** * * * * = rem;
*** ** * * * * ** ** *
** * ** ***** * *** *** *
    
* **** ******* *** = num1/gcd;
* ** * ** *** * ** *** = num2/gcd;
    
* * **** * ** ** * * **** == 1)
* * ** * * * * * ****
* *** * * * * ** *** **** * * * ** ** ** * * ** * * * * ** ** * * **
** * **** **** * ** *
    
**** * * ****** * *
*** * * ** * ******* * * *
*** * * ** **** *** * * ***** **** **** * * * * * * *
*** * *** * ** ** * * **
    
** * **** * *** * * * * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
**** * * * ***** i;
* ** * **** * j;
* *** * ** * * * ** * ** newNum1;
** * **** * * * * * * newNum2;
* ** ********* * * * ** gcd;
** * * ** * **** ** rem;
** ** * * * *** **** **** ** num1, num2;
    
**** * * * ** *** **** ** ******* *** * * * ****** *
* * ***** ** ****** * ***
** *** ** ** ** *** *
* * * **** ******* * * *
* * * * * * * ** ** * *
* ** * * ***** ** * ** * != 0)
* ** *** * ** ***** * * * *
* * * ** * ** * * **** *** *** * **** *** = j%i;
*** ** **** * * *** * * * * * * * * *** = i;
*** *** ** ** * * * * * *** ***** *** * * = rem;
** *** ** ** * * * ** *
* * * * **** ** ** * **** *
    
* **** ***** * *** * = num1/gcd;
* * * * *** * ** **** = num2/gcd;
    
* * * ** * * *** * * * * == 1)
** ** * * ** *** ** * *
*** *** ** **** ** * * * ** * *** * * * *** * * **** ** ****** ** ***
* * ** * * * **
    
* **** ** *** ** * ** *******
* * ** * ** ** **** ** * ***
* * ** *** * * *** * *** * * * * *** * ** ** ** * *
** ** * * *** ** ** * *
    
* ** **** * * * * ** *** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* *** *** ** ** ** * * * * *** ** * ** * *** * * ** *** *
** * * * * *** ** * **** ** ** * * * * **** ** * *** **
    {
* * * ***** ** *** * * **** *** * *** ** ** * **
* **** *** * **** * ** ** * ****** * ** * * * ****
** ***** * * * *****
* ** ** * ********* *** ** * ** ****
* *** *** **** ***** ** * * **

* * ** **** ** * ** ** **
*** * ** * ** ****** * * * * ** * ***** * * ** * ** ****** ******* * * ******* **
*** * ** *** * **** *** *** * ***** ***** **** *** * *** ** * * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*** * **** ** * * *** a,b,GCD;
**** * * * * *** * ** ** *** ** ** * *** **
* **** **** * * * * ***** ** *
* *** * ** * * ** * * ** *
*** * * ** * * * *** *** *** ** * * **** * *
* * ** *** * ** **** * * *
*** * *** ** ***** ** * ***** ** ** ** ** * *** * ******** * *
*** ** * * *** *** * * ** 0;
}
****** * ** ** ** * * gcd(int a, int b){
* *** ** * ** * *** * ****** *** * * * * * (!b) return (a);
* * ***** * ** ** ** ** ** ***** * ** ** gcd(b, a % b);
** **** *** * * *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * ***
#include * *** ****

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
**** * ** ** *** *** gcd, remainder;
* ** ** * * *
* * ** *** * * ** * * (n != 0)
* ** ***** * ** *
* *** ** *** ** * * * ****** * **** ** * ** ** ** = m % n;
* * * ** *** *** ** * *** *** * ** **** * = n;
* ** * ** * ** * * ** ** * ** = remainder;
***** * ** ** * * ****
* * *** ** * * ** **
* * ***** **** ** * * * = m;
* * * * *** *** * * *
** * * ** ***** ** ** gcd;
}
int main (int argc, const char * argv[]) {
**** * ***** ** ***** ** number1, number2;
*** * * * *** * *** **** newNumber1, newNumber2;
** * **** ** *
*** * ** * * ** *
*** ** * ** * * * * ** ** ** * ** * * * ** ** **
*** *** * *** * * ** *****
* **** ** * *** **** * = number1 / gcd(number1, number2);
** ** * ** * * * * * * = number2 / * * *** number2);
* * * ** * * * *
* ** * * * * * ****
* * **** * * **** ( ** ****
* ********** ** * * **** *** * ** ** ** * * * ** * * * newNumber1);
** ** ** *** ** * *
**** *** ** ** * *** * *****
* * * * * * * ** * ** ** * ** ** **** * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** * * * ***** * a,b,c,d,e,f;
** **** * *** ** ** ***** * **** * * **** * ** **** * **
* **** ** * **
**** * ** ** *** * **
**** ****** * *** * **
    {
** * * * ** ** *** ****** **** *********** ** ** **
**** *** ***** ** **** *** * * ** *** *
* *** *** *** ** * * **** * ******** * ** * ** ** ***
    }
*** *** ** * * * ** * ** *
    {
** * * ** **** ** * *** * ** **** ** * **
**** *** * * ********* * *** ** * * ** * ** * *** * **
* ** * ** * * ** ***** * * * * ****** * **
** * ** ** * *** * * * * **** ** * * * * ** **** * *
    }
*** ** * ** * * * *
    {
* ** *** * **** ** *** *** * * ** * ** *
* * * **** * * *** ** * * ***** ** *** * *** * * *** * *
** * * * * * ** * * ** * **** *** * ** *
******* ** * * *** * * * * ***** *** *** * * **** ** *
    }
** * * *** ** * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.93
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 14.6k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 14.4k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 18.5k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 14.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users