2 like 0 dislike
1.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 1.9k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

**** *** * ********* ******* ** i;
************ * * * ** * * ** j;
*** **** * * * * * ***** newNum1;
*** *** * * *** * * * ** newNum2;
*** * **** * * ** * gcd;
*** ** * **** ** ** * ** rem;
** ** * ** * *** * ** num1, num2;

* *** * * * ** *** ** *** * * * * * * * ** **** **** *

* * * **** ** * ** * * ***
* * * * * * ***** ***

* * *** ** * **** * != 0)
* * * * ** * * *** ***
* ** * * ** * ** * ** * * * ** * **** ** * **** = j%i;
********* * * ** * * ** *** * *** * * * = i;
*** * **** * * ******* ****** ** *** ** = rem;
** * **** ** ** ** ****
** ** * * * ** * *** **

***** *** *** *** * *** ** = num1/gcd;
* ** ** ** * * ** ** * = num2/gcd;

* * * * ** **** * ** * == 1)
    {
*** * *** **** * *** * ******* ***** *** ***** *** * ** *** *
    }

* *** * ** ******* ** **
    {
* *** * ***** * ** *** *** **** * ** *** **** * ** ***** * * *** **
*** * * *** * ** *

****** *** * * * * ** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** **** * * **** * * ** **** * * ** * * *** * * ***** *

** * * * **** * *** ** * * *
***** ***** * * * * * * *** *** * * **** **** **** * * *

    else{
* **** * * ** * * * * * ** *** *
    {
* * * * **** **** * * **** ** *** **
** * *** *** * * *** *** ** **** * * ****** *** ** * *** * ***** *** && deno%i==0)
**** * * * ******* ***** *** ** *** *** ** * *** * ** **** ***
** * ** * * * ** * ** ******** ** * * ***** ** * * ** ** * * * * ** ** ** * * ***
***** * *** *** ** ** * ** * ** * * * * * * *** ** * * * **** * ** * *** ** * ** ** * *
* * * ** *** ******* * *** * ** * * * * * * * ***** *
    }

** * * ** *** * * * * * * **
    {
** ***** * ** * ***** * ** *
*** * ****** ** * * **** *** ****** * * ** *** * * * ** * * * * && deno%i==0)
*** * * **** * * * * * *** ** * ** * * * * * * ** ***** *
** **** ** * * ** ** *** * * * * * * **** ** * * ** * ** * ** ** * **
**** * **** ** * * *** * * * ***** *** * ** ***** * ** * * ** **** *
** * * ********* *** ** ****** ** * ***** ** **** *** ** **** *
    }
* * * *** *** ** *** *** *** ** *** * ** *

    }




*** * ******* *** * ** * * *** * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * *** *** *
#include ** *

int gcd(int n, int m)
{
** * * ** * *** ******* gcd, remainder;

*** **** * ** * (n != 0)
* *** **** * *** ** *
* ** ** * ** ** * ** * ** ***** ** **** **** ** * = m % n;
* ** ** * *** * * * * * *** *** ***** * ** * = n;
* * * * * ** * * **** * *** * ** * * * *** = remainder;
** *** * ****** **

** * ** * * * ******* = m;

** *** ** * * *** **** * gcd;
}

int main (int argc, const char * argv[]) {

* *** * *** ** **** * ** * number1, number2;
* ** * * ** **** * * *** newNumber1, newNumber2;

****** * * * * * ** * * **** * * *** * * * * * *

* *** ***** ** ** * ** = number1 / *** * number2);
* ** **** ** * * * **** *** = number2 / **** ** *** number2);

* * *** *** ** * * * * * ****** ** * *
*** * *** ** * * ***** * **** ** ** ** ** ** *** ** *
** * ** * ** * **
*** *** ** ** ****** **** * * * ** * ** * ** **
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * * * ** ** **
* * * ** *

int * n, int m)
{
** * ** ****** int gcd, * **

*** * *** * * (n != 0)
**** * * {
* * ***** **** * * ** * ** = m % n;
*** * ** * * * **** ** * * m = n;
*** * * * * * *** n = * *
* * * * * }

* ** * ** gcd = m;

** ** ** * * gcd;
}

int main (int ** ** char * {

* ** ** int * ** * **
** ** int * ** ** * *** ***

*** *** * * * * *** ** * *** * * * * ** * * *

*** ** * * * * * * = * / **** * *****
* * * **** * * * = * / * * * *

****** ***** if * *** * ***** *
*** * *** * ** * * *** * * ****** *** ** ** * * **
*** ** ** else
* * *** * * **** * * * *** * **** * *** * *** *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ** * ** * *** i;
* * * * ** ** * * * * * j;
** ** ** *** * * * *** newNum1;
*** * ****** ** ** newNum2;
** **** * *** ***** * *** * gcd;
** * ** **** ******* * ** rem;
********** **** *** ** * num1, num2;
    
* * * ***** ** * * *** * ***** *********** * * **
** * * * **** * *** *
* * ** * **** ***** **
* ** ** *** * ******* **
** * * * ** ** * *
* *** * ** ** ** * * != 0)
* ********* * ** ** * *
* * * * * *** **** * ** * * ** * * **** ** * * * = j%i;
* ** ** * **** * ***** * * ** * * *** ** * = i;
*** ***** * * * ** *** ** * ** * ** * * * *** = rem;
** * **** * ** * * **
* * *** * * * * ** ***
    
* **** ** *** ** * * * **** * = num1/gcd;
* * * * ** *** ** ** ** ** * = num2/gcd;
    
** ** *** ** ** ** * ** * * == 1)
*** * ** * ***
*** *** **** * * ** * ** * * ** **** ** * * * ** * *
* * ** ** * ** ** *
    
* *** * * * * ** * ** ** **
* * * * * *
*** * * * ** ** * ** ** * * ** * * * *** ** * ***** *** * **** * * * *
* * ** * * *** **** *
    
* * *** ** ** ** * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** * * **** ** * * i;
******* * ** **** * j;
** *** * * * newNum1;
* ** * * * ***** * newNum2;
* * * ** * * * ** gcd;
** * * * * **** * * rem;
* ** ***** * ** **** ** num1, num2;
    
** *** ** * * * * ** ** *** * ** ** ** *** *
** * ** ***** * * *** ** *
** * ** * * * ** ** ** *****
* ** ** *** * *** *** **
* ** * * * * * *** * *** *
* ** * * * ** *** * * * != 0)
* * **** * ** ****** *
* **** ** ** * * * * **** * * = j%i;
****** * **** ** *** ** * *** *** **** * ** **** * ** = i;
* ** * *********** * ** ******* ****** * * * *** * = rem;
**** ** ** ** * * ****
* * *** * *** *
    
* **** * *** * * = num1/gcd;
***** **** ** ** *** = num2/gcd;
    
** * * ** * * * ** * ***** * == 1)
******* **** * * **
** * * **** * **** * **** ** * * **** *** * ** * ** ** * *
* * * * ***** * *
    
* ** * **** ** ** * * *
** * ** * * * ** ** ***
**** * * * * * ****** ** * * ** * *** ** *** * ** ****** * *** ** *
* * ** ** * * * * * ***
    
*** *** ** ****** ** * * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* * ** * ** **** ** * * **** **** * *** ** ******
* *** *** * * * * * * ** * **** ** ***** * * * * *
    {
* ** ** * * * ******* *** * ******* **** **
** *** ** * * * ** * *** * ** *** * *** *** **
**** ** * * * * * * * * * *** * * * *****
* * ** * * ** * ******** ** ** **
* ** ** * * ** * ** ****** * ** * **

** * * ** * * * * *
* * * *** * ** ** ** ** * * *** * * * *** **** * * ** ** **** * * ** * ** ** *
* * ***** * ** * * * * * **** **** *** ** **** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* ** *** * * * * **** * a,b,GCD;
** * * * * * * * * * * * ** *** ** **** * **
**** **** *** * * * * * * * ****** *
* * ***** ** * ****** *** * ****
** * * ** * ** *** ** * ** ** **** ***** *** ** * * ** **** ****
** * ** * * ** ** ** *** *
** * * * **** * * ** * * * * * * * * ***** *** ***** ** * *** *** ** *
** ** * ** * * * ****** 0;
}
* * * ** *** * * * gcd(int a, int b){
*** * * **** * * * *** ** * * ** (!b) return (a);
***** * *** ** * * * ** **** * **** gcd(b, a % b);
** ** * ****
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** ** * ** *
#include * ** * *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
****** **** ***** ** * gcd, remainder;
** * * * ** **** * *
* ** ******* ** **** * (n != 0)
* * * ** * ** *** * **
* * * * * ****** * * * * * *** * *** * *** ** ** = m % n;
* * ** * * * ******* *** * * *** *** ***** ** = n;
*** * *** ** ***** * * **** * ** ****** = remainder;
* * ** * * ** * **
* * * ** * * *
* * ** * **** * * ** = m;
** * * * * * **
** * * ** **** *** * ** gcd;
}
int main (int argc, const char * argv[]) {
* * * * * * * *** number1, number2;
* * *** *** ** ** newNumber1, newNumber2;
* * ** * *** *** *
* ** * * ** * * *
**** * * * ** * **** * **** * * * *** **** **** **
*** ** **** * ****
* *** * ** * * **** ** * ** * * = number1 / gcd(number1, number2);
** * * ** * ** ** *** * ** ** = number2 / * ***** * number2);
* * * * * *** * * ***
***** * ** ***** ** *
**** * * * ( **** *
**** ** * * ** * * ** * * ** * * *** * *** ** ** * * newNumber1);
* ** ** * * ** *
* * * ** * * *** *
* *** ***** ** **** ** * * * * ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*** ** * ** *** ** ** * a,b,c,d,e,f;
* ** * ** * * *** *** * * ** ** * ** ** * * **
*** ** ** ** *** **
****** * * * * * ** *
** ** * * *** ** ****** **
    {
** **** * * ** ** * *** *** ** ** * * * ** *
** * **** *** * ** ** * * ** ** *** ** **** *
* * ***** * * * ****** * * ** * *
    }
* * ***** *** * * ** ** *
    {
** * * * * * * * * ***** * * *** *** * ** * **
*** * ** **** * ** ** ** *** ** * *** ** **** ** * ** * **
* * ** ******* ** * ** ** * * * **** ***
*** ** * *** **** * ** ** * ** * **** ** ******** * * *** ***
    }
** ** ** * ** * ****** *** *
    {
*** *** ***** *** *** * * *** *
**** **** * ** ** **** * *** *** * ********* *** * **** * ** * * *
** **** *** * * **** *** * * * * * * **
*** *** * * * ***** * * **** **** ** * *** *** * * * ** *
    }
** * ******* * * ** *** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.52
©2016-2024

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 2.4k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 2k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 2.5k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 1.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users