2 like 0 dislike
11.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 11.9k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* * * * * ******** i;
*** * ****** **** ***** ** j;
***** *** ** ** ***** * newNum1;
************** *** *** * newNum2;
** ** * * ** * *** **** ** * gcd;
** * ** ** ** * * * ** * rem;
**** *** * * * *** num1, num2;

** * **** * **** *** * **** * * * ** **** * * **** *

** ***** ** ***** * *
*** * ********** ***** **** *****

** ** ******** **** ** ** * != 0)
****** *** ** *** *
**** ** **** **** * * ** * **** * * * ** = j%i;
*** ** * * * ** *** * ** * **** * *** ** * = i;
** * * ** *** ***** * * ** * * *** = rem;
*** *** * ** ** ** ** ***
* * * ** *** *** **** * ***

** * * ** *** * * ** ** = num1/gcd;
** ******* * *** *** ** = num2/gcd;

* ** ** **** ***** ** ** * == 1)
    {
* * ** * * * * * * * ** *** * ** * * ** ***** *** * *** * * **
    }

* * ** ** * ** ** * *** **
    {
*** * * ** ** ** ** **** * ** * * ** ** ** * * * * * * * *** *
** *** * *** ** * **

* * * *** ** * * ** ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * *** *** *** * ** * * * *** ***** ** ** ****

** * * ** * * * *** * **
* * *** * * *** ** ** ***** ** * **** **** ** ***** * **** * *

    else{
* ** * ***** *** * * * * *** **
    {
* ***** * *** ** **** ** ***** **
** * *** * ** ** *** ** ****** ** * * *** *** * * * **** ** * * *** && deno%i==0)
** * * ******* ** ** * ** *** * * * * ***** *** ** *** *****
* * ** * ** * * * * ** * * * *** * * * ** ** * * * **** ** ** * **** * *
*** ******* ** * * * ** ** ** * * * *** ******** ** * ** * * * * * * * ** * ** ** ** ** **
**** * * ** * *** * * * *** ******* * * * * **** **** ** * ***
    }

****** ** **** * * * *** *** * *
    {
* **** * ****** *** * *** * ***** * * ** *
* * **** ** * ** * * * * *** ** *** * * * ** *** * ** ** && deno%i==0)
* **** * ** * ** ** **** * * ****** * ******** **** *** ** ** **
** * * * * * * ** *** * **** * * * *** ** *** *** * * * * ** ** * ** * ****
** * * ** ** ** * * * * ******* * * * * ** * ** ** * ** ** *** ** * * ***** *
** *** ****** * ** ** * * **** ** * ***** * ** * * *** * * ******** ** *
    }
** * ** * ****** * * * * **** * ** ** * ** *

    }




* * *** ** * * * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** *** **
#include ** * ** * **

int gcd(int n, int m)
{
* * * * *** * * gcd, remainder;

*** ** * * *** * * * * (n != 0)
* * * * ** * * *
*** ****** * * ****** ** ** * *** * = m % n;
* * *** * ** * * *** * * **** **** ** * * *** * ** = n;
* ** ****** * ** * * *** * * ** = remainder;
* * *** * *****

* * **** ***** * = m;

* ** *** * *** **** * ** gcd;
}

int main (int argc, const char * argv[]) {

* **** * * * ** * * number1, number2;
* * ** ** * ***** newNumber1, newNumber2;

** * *** ** ** ***** * * * * * * ** ** * * *** *****

** * * * * * * ** * * * * = number1 / * ** number2);
****** ** ***** * ***** = number2 / * *** number2);

* * * * **** *** * **** * ** *
* ** ** ** * *** ****** * ****** *** ** * * * * ** *
* * *** ** ** **** * *
** * *** **** * * **** ** * **** ****** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
**** * * ****
*** * * * *** *****

int *** * n, int m)
{
* ** ****** int gcd, ***

**** * * * ***** (n != 0)
* **** * * ** {
** * * * ***** * ***** ** * = m % n;
* * * * * * * * *** m = n;
* * * * ** * * * *** n = * * *
*** * ***** }

* ** * * * * gcd = m;

* * * *** * * gcd;
}

int main (int * ** * char * ** {

* * * * ***** int * * * *
* * ** * * int * ** *** **

* * * ***** * * ** ** * * * * * * **** *** ** *** *

* ** * ** * ** * ** = ** / * ** * *
* ** * ** *** = / ** * *****

* * * * * * * if *** ** ***** *
* *** ** * ** ** * ***** ****** * *
** ** ** else
**** * ******* **** ** *** ** * *** * * * **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * ** ** ** ** ** *** ** i;
** **** ** * ** * * * j;
* * ** * * ** * * * ** newNum1;
* **** ****** * ** *** * * newNum2;
** * * * * * * gcd;
* ** ** *** * * *** ** rem;
* * ** * ** * ** * ** num1, num2;
    
* * * **** ** * * * **** ** * ** ** * *** * *
* * *** ** * * *
* ** * **** * ** **** **
***** **** * ** * * *
* ** * * * * *
** * ***** ****** * * != 0)
**** **** **** *** * * *
* *** **** * **** ** * * ** ** * *** * * ** = j%i;
** ** * * * **** *** * *** * * ** ** * * = i;
** *** * **** ***** * *** * ** ** ** = rem;
** ** * ***
* * *** * * ** *** **
    
* * * ****** **** ** *** * * = num1/gcd;
** **** ** **** * ** = num2/gcd;
    
* ** **** ** * *** * == 1)
* ** * *** ** * *
** * * ********* * * ** **** * *** ** * ** *** * * * ** * ***** ** **
* * * * * ** ** **
    
**** * ********* ** * ***
* **** * ** * ** * ** **
* ** * * * * *** **** ** ** * * * * ** ** * *** * * ** **** ** **
*** * *** ** * * ** **
    
** * ** * * *** * ** ** * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ***** * * ** * * * ** i;
** * * ** * * j;
* ***** ** ** ***** * * ** * newNum1;
* * * ** * * ******* newNum2;
* * **** *** * *** * gcd;
***** ****** ******* rem;
** * * * *** * ** num1, num2;
    
** ** * * * * * * ** ** ***** * ***** ***** ** **
* ***** * * ** ** ***
*** ****** * * ** * **** ***
* * ** *** * *** * * *
**** ******* * ** * * **
* * ** ** **** * ***** *** != 0)
* * * * * * * ** *
* * * * * ** **** * * * *** ** * * ** *** = j%i;
* ** * *** **** ***** **** * * * * ** * * * ** ** * ** = i;
** * * ** ** ** * *** ** **** * * = rem;
* ** * ** ** * * **
*** ***** * * * * ***** *
    
* * * * **** * * ** = num1/gcd;
* * * **** * * **** * ** = num2/gcd;
    
* ** * ** ** *** * *** ******** == 1)
* * * ***** ** ** * * *
** * * * ** * ** * * * * * * * **** * ** * *** *
*** ****** ** *
    
* * * * ** *** *** *
* *** *** ** ******* * *
** ***** ** * ** * *** *** * ** ** * * ** ******* * * ******* *
** * *** ** * * * *
    
*** * ** * * * ** ****** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* ** ** ** * * * *** ** * * * * *** *** * ** * **
* * *** * * * * ***** * **** ** ** ** ** * * * * * ***
    {
* * * * * * ** ***** *** **** ** *** *** ********
* * * *** * ** ***** ** **** * * *** ** * ** * * *
** * *** * * *** * * *****
*** *** * ** ** * * *** * ***
* * ** ** * ** * *** **

** * *** * * * * * *
** *** ***** *** * ** **** * * **** **** * ** * *** **** ** * *** ** ****
* * ** ** **** ** **** ** * * * * **** ** ** * * ** ****** ** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*** * * * * * *** ** ** *** a,b,GCD;
* * ** * * * *** ** * * * * *** ***** **** * * **
* ** * * *** ** * ***** ** **
* * * **** * * *
* * ** * * ** * * ****** * * ** *** * *** **
*** ** * * * * * * ** *
*** ***** ******* * *** * * ** * ** * * *** ** * ** **** * * * **
* * ****** * ** * * ** ** * 0;
}
********* * *** * ** **** gcd(int a, int b){
* ** * ********* * * * ** **** ** * ******** ** (!b) return (a);
* * * * * *** * * ****** * ** * * gcd(b, a % b);
** * * * ** *** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * *
#include * * ** ** **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* * * * * ** **** gcd, remainder;
** * * ** * * *** * **
*** ** *** * * *** * (n != 0)
* ***** * ** * *** *****
*** * * * ** * **** * * * * * * ** * * * * * = m % n;
* * *** * ** ***** *** **** ****** **** ** = n;
* * *** ** ** * * ** * * * ** ** *** * ** = remainder;
* ** ** ** **** * * * *
* * * * ** *** * **
* * * ** * **** ** = m;
***** ** ** ** *** *
* * * ** * **** gcd;
}
int main (int argc, const char * argv[]) {
* *** * * ****** **** number1, number2;
* ** * *** **** * * newNumber1, newNumber2;
* **** *** ** *
******** * ** *
** *** *** * ** * * * * ** *** ** ** *** * *********** ** **** *
** *** * ** * * *
** ****** * *** * * ** * * * = number1 / gcd(number1, number2);
* * * * ** ***** * ** ** * = number2 / ***** * number2);
* * * **** *** * *
**** *** * * ** *
* * **** * ** * ***** ** ( ** * ** **
* * ** * * * * ** * * ** * * * * * * * * ***** *** * * ** * * * newNumber1);
**** ****** ***** * * *******
* ** * ** ** * * *
** * * ** *** ** *** * * ** * * * ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*** *** * * * ** * * ** a,b,c,d,e,f;
** * **** * ** ** **** ****** ** ** * *** * ** * * * **
* ** * ** *** * * ******* *
**** **** ** *** ** * * *
** *** ** ** * **** * ***
    {
* * * ** **** ***** ** * *** ****** ** ** * **
* * ** * * * * ** ** *** ** *****
* *** ** ********* * * * ** * * **** * * * **
    }
* *** * ***** * * * ** *
    {
** * * ** **** * * **** * * * * * *** ** ***
**** * * ** * ** * *** * ***** *** *** ***** * * *** **
* ** ** * * * * ** * * * * ***** * ** *** *** * *
** * * * * *** * ** *** * *** **** * ** *** ****** * * * ** ****
    }
** * ** * * ***** *
    {
*** * ** * *** **** *** * ** ** * * * ****** * ** * *
* ** * * ***** ** ** * * *** ** **** ** ** *** * * * *** ** *
* * * * * * * ** * ** * ** *** ** * ** * ** *
** ******* ** * *** * * *** *** ** * * * * * * * ** * *
    }
* * * * ** ** ** ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.173
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 12.2k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 11.8k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 15k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 11.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users