2 like 0 dislike
8.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 8.9k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

*** *** * * * * * ***** i;
* ***** * * ** ** *** * * * j;
** ** * *** * * **** ** newNum1;
*** *** ** ** * * ** * * *** newNum2;
* * ***** * **** * ****** * gcd;
* * * * * *** *** rem;
** * ** *** num1, num2;

* * ** * ******** * * * * ** *** ** * ** * ***** *** * *

* * ** * ****** *** ** *
* * * * ** *** ** * * * ** *

** *** * * ** != 0)
** * ** ** **
******* ***** *** * ** *** * ***** * * = j%i;
** * **** * ** * **** * *** * ** ** ***** ** * = i;
* * * * * * * * ** * *** * * ** * * **** * = rem;
**** * ** *
* ** ******* * * * *

* * ** * *** * * * * ** = num1/gcd;
** * * * * *** ** ** * = num2/gcd;

*** ** ** * * * * *** == 1)
    {
* * * * ** * *** * * ** ** ** *** * ** * * ** * ******* ** * **
    }

** * * *** **** ******* *
    {
* * ** * ** * * ** * ******* * *** ******* * ** *** ** *
* ** * *** ** * **

***** * *** *** ** * * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * **** ***** ** * * * ***** * * * *** *** * ***** * **

** ** * * * * * *** *** *
** * ** ** * * ** * ** * ****** ** ******** ** * * ** **

    else{
* * * **** ** **** **** * * *
    {
*** * ** * * * ** ** *
* ** * * ** * * * * * * ** **** ** * ** * * * **** * ** * * * ** ** ** *** && deno%i==0)
*** ** ** ***** ** * ** ** ***** ** ** * * ** * *** * * * * *
*** * * * *** * * *** * **** ** **** *** * *** *** ** *** * *** ** ****** * ** * *
** *** * *** ** *** ***** * ***** * * * ** **** * * * *** * ** * ** ** ** *
** * * ** * * *** * * * * ** * *** * * *** *** * *****
    }

* * * ** * ***** ****** *** *** *
    {
* * * ** *** * * * * * * * ** * *
** * * **** **** ** ** * *** * ** ** * ** * * * ** **** * ** * * ***** && deno%i==0)
* * * * * *** * **** * **** * * ** * * ** * ** ** *
** * * ** *** *** * * **** ** *** * * * * * * *** *** * ** ***** * * *** * ** *
* *** * * * ** ** * **** * * * * * * ** ** * **** *** * * * **** ** * ** *** ***
***** *** * ** **** ** * * *** * ** ******* ** ** ** * * ** *
    }
*** * ** ***** ******* * * * * *** *** ** **

    }




* * ** *** * ** * * ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** **** * *** **
#include * ** * * * * *

int gcd(int n, int m)
{
**** **** * ** **** ** gcd, remainder;

***** * *** * **** * (n != 0)
** ** * * * *** *** * *** *
** * ****** * *** ** * ****** ******* *** *** = m % n;
* *** ** * ***** * ** ** ***** ** * **** ** * = n;
* * ** ** * ** * ***** ** ** * * = remainder;
*** **** *** * * ** *** **

* * * * * ** ** * * = m;

* ** ** ***** ** *** gcd;
}

int main (int argc, const char * argv[]) {

*** ***** ** * * * * ** number1, number2;
* ** * * *** ****** * * newNumber1, newNumber2;

** *** ** *** * ****** * * ** * * * *** *** * ** * ***

** ** * * ** *** ** * ** = number1 / * number2);
* * * * * * * ** * ** * = number2 / **** * number2);

**** * * ** * *** ** * * * * *** * *
*** * * * ** * ***** * * * ** ** * * * * * * * * * **
** ** * * * * ** ***
** ** * *** * * **** * *** * * *** **
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* *** * ** * ****
* * ***** *

int * * n, int m)
{
* * * * int gcd, * **

** ** * ** ** * (n != 0)
**** * * {
***** * * * * ** * ** * ** = m % n;
** * * * ** * * * m = n;
** * ** * ***** ** * n = * * *
* * ** * * }

** * * * gcd = m;

***** * * gcd;
}

int main (int ** ** char * * {

* *** * * * int * ** *
** * ** ******* int * * *

** ** * ** *** ** ** ** * * * ** ***** * *

* *** *** ** * **** * * = / ** * *
* * * * *** * * = *** / * * ** * **

* * * * * ** if * * ** * * **
** * * *** * * ** * **** * *
** *** * * else
* *** * ** * * * * * *** * * * * * **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * ** * *** i;
* ** * ** ** * ***** ** * j;
**** * ** ** ** newNum1;
* ** * **** ** ** newNum2;
* **** *** ** * * * ** gcd;
* * * ** * * *** *** * * rem;
** **** * ** ** ** ** * * num1, num2;
    
** * * ****** * **** ** * * ** * * * *** ** ** *
* *** ***** **** *
*** *** *** * * * * *** * *
* *** ******* * * ** * ** *
*** * ** * *** * ** *
* ******* * ***** * ** * != 0)
** * **** * ** ** * ** *
*** * * * *** * **** * * * * *** * * ** = j%i;
*** *** * * * ** **** ** **** ** * * * = i;
****** * * **** * * * *** **** ****** * * * = rem;
**** * **** * * * *** * *
** ** ** * * * * * ** *
    
* * * ****** * * * = num1/gcd;
*** *** ***** * * * = num2/gcd;
    
* ** * ** * * ** ****** == 1)
* * *** * ** **** ****
** **** * * * ** **** * * ** * * * * * *** * ** ** * ** ******
* * * ** ** * * **
    
** * *** ** * * ** * *
** * * * ** ****
* * ***** * * ** ** *** * *** * * ** ******* * * ** * * ** * ***
**** * * * * * * ** ** *
    
** * ** * * * *** * * * * * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
*** * ** ****** ** ** ** * i;
*** ** ** * *** * * ** j;
** *** **** ** ** * newNum1;
* * ** * * **** * ** *** newNum2;
*** ***** * * ** ** ** ** ** gcd;
*** *** *** *** * * * * rem;
** * *** *** * ** * num1, num2;
    
** * * ** *** ** * * * ** *** ** ** * * ** * * ***** *
* * **** * * * * * *
**** * *** **** * *** **** ***
** ** * ** ** ** * * * * *
** * * * * * * *** *
** ******** ** * * * *** ** * != 0)
* * ** *** * * ****
* * ** * ** *** * *** * *** * * = j%i;
** * **** * * **** ** * * ** *** * = i;
** * *** ** * * ** *** ** ** * ** ******* * * *** = rem;
* ** * ** ** *******
* ** ** ** * ** * * * **
    
***** ***** * ** * *** = num1/gcd;
* *** * ***** * ***** * * = num2/gcd;
    
*** ******** * ** *** ******** * == 1)
** ** * * * *** ***
** * ** ** * *** *** ******* * * * * * * ***** * **** ** * ** *
** * * ** *** **
    
** **** * * * *** *
** * ** ** *
* ** * * *** * * **** **** ** ****** * * ** * * *** *** ********* *** * **
*** *** * * * ****** *
    
* * * * * *** *** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* * *** * * ** * * * *** ** ** * ** * *** *** ** * *
* ** * **** * * *** **** *** ** * ** * **
    {
** ** * * *** * * *** ** * ** * * ** *** * * * * *
********* * * * ** * ** * **** ** * * * **
** * * ** * * *** * *** * *
** **** ***** * * *** ***** *** ** * *** ** ***
***** * * * ****** ** * * * * * * *

* * ***** ** ** ** * ****
** * * ** ** *** *** ***** ** * ** *** * ** **** * * ** * **** ***** *** *** *
* * ** * * * * * * * * **** ** ** ** *****


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* **** ***** *** *** a,b,GCD;
** ** * * * * ** ** * * * ** * * ** * ** * *
** * ** * * * * * *** * ***
* * ***** ** ** * * *** *** ** **
*** * ***** ** * **** ** * * *** **** ** *** * ** * *
** * * * ** ** ** *
*** * * ** * * **** * *** * ** * *** * * * * * * ** ** * *
* *** ** * * ****** * ** 0;
}
**** *** ** * *** gcd(int a, int b){
* ***** ****** * * * ** *** ** ********** (!b) return (a);
* **** **** ** ** * **** ** * * * ** * * ***** gcd(b, a % b);
* ** * ** *** ****
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * *
#include ** *** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
******* * **** * **** gcd, remainder;
* * * ** **** * * *
* * ***** ** * * * * * * (n != 0)
* ****** * * *** * *
** ** *** *** * ** * * ** * * ** ** * ***** = m % n;
* * *** ** ** * **** * * * *** * *** = n;
**** ** * * * * * * * ** * **** * * * * * = remainder;
** * **** * *** *
*** * **** * **** * *****
* * * ** ** *** ** = m;
* ** * * * ** * ** ** **
** * ** ** * ** * * gcd;
}
int main (int argc, const char * argv[]) {
* ******* * * ****** number1, number2;
** * * ******** *** * **** newNumber1, newNumber2;
** * * *** ****** *
* ** * ** ***** * * *
******* * * * ** *** * * * ** ** ** * *****
** *** **** * ** *
** *** * * *** *** * = number1 / gcd(number1, number2);
** * * * *** ** * * * ***** * = number2 / ***** **** number2);
**** * * ** ** * * *
* *** **** ** * * * ***
** * * ** * ***** ******** ** ( * **
* ** * ***** * **** ** * * ** * *** ***** *** ***** * *** ** * newNumber1);
*** * * * * * * ** * *
* ****** * * ** ***
*** * ** * ****** * *** *** * * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * ** *** * * *** a,b,c,d,e,f;
*** * *** **** ** * ** *** * * ** * *** * * ** * * ****
* * ** ** * ** *** * *
* * ** *** ** ***
* * ** * ** *** ** *** **
    {
* * *** ******* * ** ** * *** * *** * ** ********
* ** ** * * * * ** ** *** ******* * * * *** * * *
* * ** ** ****** ** * ** ** ** * ** *
    }
* * ***** **** * * *** ***
    {
* ** * * ** * ***** *** *** * ***** ***** *
* ***** * * *** * * ** * ** *** * ****** * * * ** * * *** *
* * ** * ** * **** *** * * **** * * **
** ****** ** *** * *** * *** ** **** * * * * * *** * ** * * *
    }
** * ** ** * * * *
    {
* ** * **** * *** * * * ** ** * * * * *** ** * ***
* * *** *** ** * ****** * * * *** * * ** ******* * *** *
** * ** ** * *** * *** * * * **** * * * * ** **
* ********* ** * * ** ***** * **** * * * * ** *** **
    }
** * ** *** ***** **** ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.1.189
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 9.1k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 8.7k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 10.9k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 8.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users