2 like 0 dislike
14.4k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 14.4k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

*** * * ** * ** ******* i;
** * * * * *** * ** * j;
* ******* * *** ***** * newNum1;
* ** * * ** ** ** * newNum2;
* **** * * ** *** * * gcd;
** * *** ** * * * * rem;
* ** ** ** * ***** * ** num1, num2;

*** * * ***** *** ** * *** * * ** *** * * **

**** *** ***** * * * * ***
* ** * * ***** ******** *

* * ** ** * ***** ** * *** * != 0)
* ****** ** ** * * ****
***** ** ******** * *** ** ** * * ***** * ** ** * = j%i;
** * ** **** *** ** * * * ** *** * ** * * ** * = i;
** * * *** *** ** * *** ** ** *** ** = rem;
** **** * * **** * * *
* * ** * ** *

** ** *** ** * * * ***** * = num1/gcd;
* ** **** ** *** *** = num2/gcd;

** **** ** ******* ** * * == 1)
    {
* * * ** * ** *** * * * * * * * * *** ** **** * * * * *** ** *
    }

* ** ** ** * *** *** * * *
    {
* * * ***** * * * * * *** ***** ** * * * ** * ** * ** * ** * * * * ** *
***** ** * * **

***** * * * ** ** * *** ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * *** ** * ** ** * *** * ** *** **** * **

*********** ** **** *** * ** * ** **
* * * * * * * ** * * * * ** ******* * * ** * * * *** ** *

    else{
** * * **** ** ** * ** * * ** *
    {
****** * * * * * ** * *** * ** * *
*** *** * ** *** * ** ** ** * * *** **** ** * * **** * ** ** * * * && deno%i==0)
*** *** * * * * ***** * * **** ** ** ** * ***** *
** * ** * ** * * ** * * * * ** * * ** * * * ** * ** * * *** **** **** ** * *
** * * ** * * ** *** ****** ** * ** ** *** *** *** * * **** ********* ** * * **
**** *** * * * * ** * ** * ** * * ** * * * ** *** *** ** **** * *
    }

*** ** * **** *** *** *** ** * **
    {
***** * ****** * * ** ****** * * * * * * *
** * * *** ** * ** * * **** **** * ** **** * *** ******* * * * ***** ** * && deno%i==0)
* ****** * * ** ******** ** ***** * * * * * *** * ** ******* **** *
* * ** ** * * * * *** * * * * ** * *** **** ** ** * *** ** ****** ** * ** * *** ***** * **
* *** ** * *** * * * * * * * ** * *** * ** * * * * * * * * * ***** **
* ***** * *** ** ** ** ** ** * * * ** ** ***** * **** * ** ** *
    }
* **** ** *** *** * ** * * *** ** * * ** ** ** ****

    }




* **** ** * *** ******* 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** ** *
#include *** * *** ** *

int gcd(int n, int m)
{
***** ** * **** * *** * **** gcd, remainder;

* * * * * ** * * * ** ** (n != 0)
* ****** * * **** **
* * * *** * * *********** ** ***** * ** * * = m % n;
******** ** *** * * **** ** ** **** * ** = n;
**** ** ** ** ** ****** *** * * * ** ***** = remainder;
* * * * * * ** * * **

*** **** * * *** = m;

** * ** ** * * * ** * *** gcd;
}

int main (int argc, const char * argv[]) {

** * * ** ***** ** *** number1, number2;
** ** * ** *** * * * * newNumber1, newNumber2;

* * *** *** * * **** * * **** ** ** ** *** *** * *** * **

** * ****** * **** * *** = number1 / * * * number2);
* *** *** * * *** * * * * = number2 / * ****** number2);

*** ** * * * * * * * *** ** **** *** **
** ***** ********* * *** * * ** * * ** * * * * **
********* * ** **** * *
* ** * * ** * * ******* * * * * * * * ****
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
*** ** ** *** **** *
* * * *** ***** ****

int ** * n, int m)
{
******* ** ** int gcd, ** **

** * * * ** ** (n != 0)
* ** * * * {
* * * * * ** * ***** *** * * * = m % n;
** * ** ** * **** ** ** m = n;
* * ** * ** *** * * ** ** n = ********
*** ** * * ** }

* * * ** gcd = m;

**** ** **** **** gcd;
}

int main (int * *** * char * *** * {

** ***** * *** int * * ***** *
* * * * int *** * * *** **

** *** * * * ** ** *** ******* ** **** * * ** ** * *

* *** ** * * *** ** = / ** ** ***** ****
* * * * **** *** * = *** * / *** * * * **

* *** *** if * *** * ** * * *
** ** ** *** ** ** * * ** * *
* ***** * else
** * * ** ****** ** ** * ** ** * ** * * **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ***** * ** * ** * ** * i;
** * ** **** ** ** *** * * j;
* * * ** ** *** newNum1;
** * ** * ****** * * newNum2;
*** * * ** * * ** * * ** gcd;
*** ** *** * *** ****** rem;
* ** ** * ** ** *** ** *** num1, num2;
    
* ** ** * ** *** * ** ** ** ** ** * * * ** **
* * ** ** * * ** *
* ************ ** ***
*** ***** ********** *** *
*** * ** ** **** * * * * *
* * * ** ** ** * * * ** * != 0)
* ** * ** ** ** ** ***** *
*** *** * * ** * * *** * * *** * ** *** * ** = j%i;
** *** **** * ** * * *** * * **** *** = i;
********* *** ** ** ** * * *** ** ** * ** = rem;
* ** ** * ** * **
* * * * * * * * * *** *
    
* *** ** * * = num1/gcd;
* *** ** ** * = num2/gcd;
    
*** * * * **** * *** * == 1)
* ** * * ** ****
* *** *** * ** ** ** * *** *** * * *** *** * * * ** * *
* * ** * ** * **
    
****** * * * * ****
****** * ** * * ** ***
** * * * ** * * * ** * * * **** * * *** ** * * * ***** ** ** ** *
* ** * * ** **
    
* ****** * * ** ** **** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
******** *** ** ** ** * ** * i;
* * * * *** ** * ** ** * j;
* **** *** * *** * *** * ** newNum1;
*** * *** ** * * *** * ** newNum2;
* * * ** * ** ** * * * * gcd;
* **** * * *** * rem;
*** * * * *** *** *** *** num1, num2;
    
* * * ** **** ** ** * *** * * ** * ** ***** **
** * * * ** *** * *
*** * *** * * ****** *
* ******* *** * ** * ***
* * * ** *** ** * * ** *
** * ********* ** * ** != 0)
*** * * * ** *** * *
* * *** ** * * * ****** *** * ** ** ** ** = j%i;
*** ** * ** *** **** ** * * * ****** ** = i;
* * ** * *** *** ** *** * ***** **** * * ** * = rem;
* * * ** ** ** *
* ***** ** * * * ** *
    
* ******* * * *** ** ** = num1/gcd;
** * ********* ** *** * * = num2/gcd;
    
** ****** * * *** * * ****** ** == 1)
* * * ** * *
* * * * ** * ** * * ***** * * **** * ** ***** ** *** * ***
* *** * *** ** * ***
    
* ** * *** ***** **** *
* * ** * ** ** * * **
** **** * ** ** * ** ** * * * * ** **** **** ** ** * * * *
**** * * ** **** * **
    
*** ** * **** * *** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* ****** * ** *** *** * ** * * * * *
* **** *** ** * ***** * * ** ** **** *** * ***** *** * *****
    {
**** ** * ** * ** * * *** * * **** ***** * *
* *** * * * * * ** * ** **** * *** * *** **
** ** * * *** * * * *** * ** ** **
* ** * *** ** ** * ***** ** ** * *
* * * * * **** ** *** ** * ** ***

**** * * * ** *** ** *
* ** * * ** * ** * *** * *** *** * * ** * ** * ** **** * * * *** ***** * *** *
* * * **** * *** *** * **** * * ***** * * * * * * ** **


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
** * ** ** * ******* * ** * * a,b,GCD;
** * *** * ******* ***** * * ** * *** * * * * **
* * ** *** * *** *** *** ** ** *
** * ***** ** *** *** * * * * *
******** * ** * * * * ** ****** **** * * * *** * **
* ** * * * *** **
**** * ** * *** ** ** ** *** * * * *** * ** ** * ** * * * *
**** * * * ** * ***** 0;
}
* ** * ** ** * *** * gcd(int a, int b){
** *** * * ** ** *** * *** *** *** (!b) return (a);
* ** ** * * ******* * *** ** ***** * * ** * *** * * gcd(b, a % b);
** * **** * * ** ** * *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * **** *
#include * ** *** ***

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* ***** * * * *** * * gcd, remainder;
** ** ** ** * * * ** ***
* ** ** * *** ** * *** (n != 0)
* ***** ***** * * *
* ***** ** * * * ***** * *** * * * ** ****** *** * * = m % n;
* ** *** *** * * * * * * *** * ** ** * ** * = n;
*** ** * * * ** ***** * * ** ********* ****** *** = remainder;
*** * * * **********
**** ****** ** *** *
*** *** * ** * * ** ** *** = m;
*** ** * * * * * *
** * * *** gcd;
}
int main (int argc, const char * argv[]) {
*** * ***** * ***** ** * * number1, number2;
* * **** * ** * newNumber1, newNumber2;
** ** ** * * ** * ****
*** *** * ** * * *
** * * * ***** * * * *** ***** ** ** * * * * ** *
***** * ** * * *** * *
* *** ** * ******* * ** ** = number1 / gcd(number1, number2);
* * * * ** ***** ** ** ** * = number2 / *** ** number2);
****** * * *** * * *
* * * ****** * ** *****
** * ** * ** ** *** * ( *
* * * * * **** ****** ** *** ** * *** * * ** * * * * newNumber1);
* ** ** * * * **** *
** ** ***** ** **
* *** * * *** ** ***** *** * *** * * * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
**** * ***** * *** a,b,c,d,e,f;
* * * * *** * **** * *** * * ** ** ** * **** ****
** ** * ** * * *** **
* ** * ******* * *****
** * *** ** * * * * * ** **
    {
* ** *** * * * * * * * * * ** *****
* * * * ** ** ** ** *** ** **** * ****** ** *
*** * * **** * * *** * ** * ** * ** ** *
    }
****** *** * * ** ***** ** *
    {
* ** *** *** * *** * **** * ** ** * ***** ** * **
* * ****** * * ****** ** ****** ** * ** * **** ***** * * *
*** *** * ** * * ** * * ** * ***** * * * * *
* ** ***** **** *** ** * *** * * ***** * * * * **** * * *** ** **
    }
* ** ***** * * ****** *
    {
* **** * *** *** ** * * *** *** * * *** * **
** * ** ***** * ** * ** ** * * *** **** * * * * * ** ****
** * * *** * ** *** ** * * * **** ***
** ** * ** *** * * * *** * * **** * ** * * ******
    }
* * * * * *** * * ****** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.78
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 14.7k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 14.6k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 18.7k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 14.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users