2 like 0 dislike
11.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 11.9k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* ** *** *** * * * i;
******* **** * *** * * * **** j;
** ** ** * ***** * ** ** newNum1;
* * ** * ** * *** newNum2;
* * ** **** * ** ** gcd;
* ****** ** *** *** * * * rem;
** * * * * ** * * * num1, num2;

* *** * ****** ** ** ** * * *** * * ****** *****

** * * * * ******** **
** ** * * *** * ** **

*** **** * **** * ** * != 0)
** * ***** *** **
*** * ****** * **** * * ****** ** ** = j%i;
*** ** * * * *** * * **** *** *** ** ** ** * = i;
* * ** * *** ** ***** * * * * * * *** *** * * = rem;
* * * **** * * *
****** * *** * * *

*** * *** * *** **** **** = num1/gcd;
** *** *** ** * *** *** * * ** = num2/gcd;

** * ** * * ** * == 1)
    {
** ** ** *** ** ***** ****** ** * * * * **** ** *** ****
    }

* ***** * * * ** ** *
    {
* * *** * *** * ** ** * *** * ** * ** *** * *** *** **** * * *
** **** * **** * **

* **** ******** * **** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* *** * *** *** * * *** ** * * * * ** * ** * * * * **

** * * ** *** **** ******
***** * **** * *** *** * * ** * *** ** * * * * *** *** ** * * ** * **** * * *

    else{
** ** * * *** *** ** ***
    {
*** * **** ** * ***** *** ***** * ** *
*** ** ***** * * * *** * *** ** ** * ** ** * * * * * ** * * ** * && deno%i==0)
* * ** ** ** ** * * *** * **** *** * * ** * *** *** * * ** **** *** *
* * ** * * * * ** ******* ** * * * *** ** * *** ** ** * ** *** ******* **** * **** **
** * ****** * ** * *** * * * * ** *** **** ****** * **** * * ** ** * *
***** * ****** * * ***** ****** * * ** * * ** * * * * **** * **** **
    }

*** * * * ******* ** * ***** *
    {
* * * ** ** * ** * ** **** * *
* **** ** *** ** ** * **** * ** ** ** ** * * **** ** * * ** * ** * **** * && deno%i==0)
* ** ** **** **** ** * ** * *** ** * * ***** ** * *** **
** *** * ** * **** * ** * ****** ** * * * ** ** **** * * ** *** *** *** ** **
* * ** **** ** ** * ****** *** *** * * ** * * * * *** *** *** *** *** **
* ** ** * *** *** * * ** ** * * * *** ** * * ** * ** ** *
    }
*** ******* * ** * ** *** * ** **** * ** *

    }




** * * * * * * * * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** **** ** *
#include ** **

int gcd(int n, int m)
{
* *** ** * ** ** ** gcd, remainder;

* **** *** * ** * * * (n != 0)
** *** * * ** ***
**** *** *** *** * ** * * * * * * ** ****** ** = m % n;
******* * * ** * ***** *** *** **** * * = n;
* ** ** *** *** ********* *** * *** * = remainder;
** ** * * ** ***

*** * * ***** ***** = m;

* * * **** ** ** *** ** ** * gcd;
}

int main (int argc, const char * argv[]) {

* ** ****** **** * * ** number1, number2;
* * * ** * *** * **** newNumber1, newNumber2;

** ** * *** * ***** ******* *** * * ** * * **** *

* * * * ** ** * ** * = number1 / * * ** number2);
* *** * ** * ** * * ** * = number2 / * * number2);

**** ** ** * ** **** ** * * ** ** * *
** * * * * **** *** ** **** ***** ** * ** * *** * *
** * ** * * **
** ******** * ** * * * * * ** ** ****** * ******
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* ** * *** * ** **
** ** *** * ***

int n, int m)
{
** * * int gcd, *** *

* * * * ** * ** (n != 0)
* ***** * {
* * * * * * * * * ** **** * = m % n;
* * ** **** * ** * m = n;
* ** **** **** * n = ******
*** ** ** * }

** *** gcd = m;

** * * ** * * gcd;
}

int main (int * ** char * ** ** {

* * ** * int *
** *** * * * int ** ** *****

***** *** ** * * * ***** * * * * *** * ***

* * * * * * * * = * ** ** / ***** **
*** *** ** * ** * ** * * = ** * / * *** ** ***

* * * * * if **** * * * ** *
* ** ** *** ** ****** * *** ** ** ****
* *** ** * else
** ** *** * ** * ** * * * ** * ** * * * **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * ** *** * ** **** * i;
****** ***** * * * j;
*** **** * * *** * ** ** newNum1;
* * * *** ** ** ** *** * newNum2;
* ** ***** * * *** * ** gcd;
*** * *** * * * * * * rem;
** *** * ** * **** num1, num2;
    
* **** ** ****** * *** * * * *** * ******* *** * *** **
* * * ** * ***
*** ** * * ** ** ** *
***** * * *** *** ****
* * * * **** * * *** *
** *** * ******* *** * ** != 0)
** ** * *
*** * * * **** * * *** ** ** ** **** ** * = j%i;
*** * * * ** * ** **** ** * * * * * = i;
* * ** * *** * * * ** ** ****** = rem;
*** ** ** * * * ***
***** ** * **** * ** * ***
    
** * * ** *** * * ** = num1/gcd;
* * * * ***** * * * = num2/gcd;
    
***** ** ** *** *** * ** * == 1)
* ****** * ** ** **
* * ** **** ******** * ** ** * * * * * ***** *** * * ** ** * * ** *
* * * ** ** ***** ** *
    
**** * * ** * **
** ** * * *** **** **
* * * * *** * * ** *** * * ** *** * ** * * * * *** * * * **** * ** ** ** *
***** * * * *** * ****
    
* * * * * *** ** *** ** * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * * * * **** i;
* *** * *** ** ** j;
** ****** * * * * ** newNum1;
**** * ** ** * * * **** newNum2;
** * * * **** ****** * ** gcd;
* ** * ****** **** ** rem;
*** ** * * * ** * * num1, num2;
    
** * * ***** ** * * ** ** * ** * *** ***** ******* *
* ** *** ***** * *** * *
* ***** ** ** *
* ***** * * * ** **** * *
** * **** ***** * * * **
*** ** **** *** ** **** *** * != 0)
**** * ** * * * ** *** *
***** * * * * * ** ** *** * * ** * * * ** * = j%i;
* ** * * * *** **** *** ** * *** = i;
* * *** * * * * * ** * * * * *** ** * * *** * = rem;
* * ** * * * ** **
* ****** * * ** * * * **
    
* * * ** * * * *** **** * * = num1/gcd;
**** * ** * * *** = num2/gcd;
    
** ** ** * * * ***** ** ***** == 1)
*** *** ** * ** **
* * ****** * * ** * * ** ***** * * ** * * ** *** *** *** ****
** * * * *** ****** * **
    
**** **** ** * *** ****
*** ** * *** **** **
* * ** ** * *** * * * ** ** * * ** ** ** * ** **** * ** ** * * * * *
* * * * * ** * *
    
* *** * ** * ***** * * *** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* *** ** * ** **** * * * ** * *** * * * ***
** * * * * * * * * * * * *** * * * *** * **** *
    {
*** *** * * * * * ** * * *** ** *** ****** * **
* * * ** ** * ** * *** ** * * ** ** ** **** ** * * * **** ***
* ** ** * **** * *** ** ** *
* * * *** * * * * ** ** * * ** * ***
** ** * * ** * * ** * * * * ** **

** * **** ** * * ** ** **
* **** * **** *** * ** *** * * **** ** * ** *** * *** **** * * **** *** * *
* ** ** * * ** ** ** *** *** ***** ***** * ** ** * * * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
**** * * * * *** ** a,b,GCD;
* * ** *** * * *** * ********** * * ** ** ** ** *
* ** *** * *** * ***
* * ** * *** * * ** ** * **
*** ** ** ** *** * * * ** ** ** ** * * ** **** * **
* * ** ** * * * * * **
****** * *** ** *** * * **** * * * **** * * ** * * * * ** ***
***** * * ** * *** * 0;
}
* * * * * * * ***** gcd(int a, int b){
* ** **** ** * * * ** * * *** * ** * (!b) return (a);
* * **** *** * ** *** *** ** ** **** ******** gcd(b, a % b);
******** ** * * * *** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * ** ** **
#include **** ** * *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* * * * ** ** **** ** * gcd, remainder;
**** *** * **
** ** ** ****** ** *** (n != 0)
*** ** **** *** * ****
** * ** ** ***** * * *** * *** * * = m % n;
** * * * * ** * ** * * * ** = n;
** ** *** * * * * **** * * * **** * = remainder;
* ***** * ** * * * *
* * * * * * * * ****
* ***** ** * ** * * = m;
* * ******* * * * **
** **** * * ** ** gcd;
}
int main (int argc, const char * argv[]) {
** * * ** * * ***** number1, number2;
** ********* ** * **** newNumber1, newNumber2;
* * * * ** **** *
** ** ** ** **
*********** * **** * **** **** ** ** * * **** * **** * ***
* * ** * * * *** ***
** * ** ** *** * ***** * **** = number1 / gcd(number1, number2);
* * * * ** *** ** ** * = number2 / * * number2);
** * * * * * ** * * *
*** *** * * * * **
* ** ** * ** *** * * ** ( ***** * *
*** * * ** * ** ** *** ******* * **** * * **** *** ***** * *** newNumber1);
* *** * ** * ** * * ** * ***
** * ***** *** * **
* ** * ** * * * * *** * * * *** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* ** *** ** **** * * ** a,b,c,d,e,f;
* *** * ** *** ** ****** ****** * *** ** ** *
* * * * * ** *
* ** * ** * * *** **
* ***** ** ** * ** **** * *
    {
*** * *** ** ****** * *** ** * ** * **
**** ***** ** *** * ** * * * ** ** ** ** *
**** * * ** * * ** * *** *** *** *** ** * * * *
    }
** ** ** * **** * ** *** *****
    {
* **** * * * *** ** ** * * * * * * * **** *** ** * ****
** ** ** * **** ** ** ** * * ** * * * * * * ** *** * ******** *
* * * * **** * ** * *** * **** ** ** *
** * *********** * * * *** * * ** * * ** ** * * * **** ** * * **
    }
* ** ** * *** ** *
    {
* **** * * ** ** * ** ** ** * * * * *
*** * *** ** * * *** *** * *** *** ** * * ** ** * ** *
* *** ** * ** * * *** ** * * * *** * ** * **
*** * ** ***** *** **** * *** * * * * ** ** * ** * * * *** * *
    }
** * ** *** ***** ** * * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.184
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 12.2k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 11.8k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 15k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 11.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users