11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
12.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 12.9k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

******         * *** *     i;
* * ****** ***  *  **   *   j;
 ** ***  ***  *  *** ***  * *** newNum1;
 *    ** * *** * *   * **** newNum2;
  *** **      ****  *  * * gcd;
   ****   *  ****  *  ** * *  rem;
* **      * **  * * * ***** ** num1, num2;

 **  **     ***  * * **** ****          *** **  *  *  ** *     *******

 **  * * ** * ***  *    ** *  
* ** * * *****     * * *****  * * 

    *  *     *  *    **  ***** *  != 0)
* ** *  * * *  **  ** ****  
* ** ** *  * *   *    *     **   * * *    *** ** **  * * *    = j%i;
*  ** *  * * *   * * *  **   *   ***** * **  * **** ** = i;
** ** *   *  * * *  * *    * ** ****  **** * * ** = rem;
**  ** *** *  ***** * **  * 
* *** **  **  ** *   ** *****

  *****    ** *   *  *  *** ***   = num1/gcd;
*  **    *    ** ****     ***** = num2/gcd;

** ** *  *     *  *    ****  *    == 1)
    {
 *  *** ** * ** *   ******   ****    ** **    *          *** * **   
    }

 *     *  *** * * *  *  ** ** *
    {
* *****     *** ******    ** * * ** * *      * * *** **     *  ** *      **  *  
* *  * *   * * *  * **** 

*  *   **  * *   * *    * *** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
 ***** * *  *  ** * * *** * **  *     ***  ********* * ******* * *   *  

  *** *   *** ***** *   * ** **    *  **   * **
   * *  **** *  **  **    *  * **    **** * ** * ** * *  * * * * **    *********  *

    else{
****  **   **  * *  ***    **  *** *** * 
    {
* **  **  ** *     *   ******* *     *  **  **
  *  *    * *  *  * * ** *      *   ** * **   *** ** ** * *  * *** **  *****  *    ***** ** *  * && deno%i==0)
  *** * **** **  * *  * *  *  ** *   *    ** ***** ** ****   * ******* *  * *  * *   *   *
*  * ****  ***** *****  *   **   *    *   ** ***    * * **** **** *  *   ** **  * **  **    **   *  *  *
 * *    *  *   *   * * *  **   ***          *** ** *    *   ***** *  ** **** **      ******* **  *  * *****  
 *** ** * * ***   * *** *  *** **  *   * *** ******* *    ******    * *  *** 
    }

  * **  *  * * **  ** **  * ** *** *
    {
****    *     **   * ** **  **  *  * ** *  **
* *  * * *  *     ** * **   *  * *   * ******** *  * *** **  ***** **  ***  *     * * * * && deno%i==0)
 **   *   *        ** *** **** ****  * * *  * *  **  *  * ** * ***    *    * * *   
 * **  *  **  **   * * **  * *      *     * *** ** * *  * ***  *** ****  * **   * ** * ******  * ** **
   ** ***   ** * ** **    *  ** * *  ** * * **   ** *  *  * **  * * *  *  ** **** ****   ** **  *  *    
 *    ** * ** *  *    * ****   ***    **** * * *   *  * *** ** *    *****   *   **
    }
*  * ***   * * *** * *  *   *    ****   *   **** **  ***

    }




 *  * *** * * *   *** * *  ***   * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***     ** * *   
#include   **    * *** ** 

int gcd(int n, int m)
{
 *** * * * ** *  * * ****  gcd, remainder;

*   *  * ***** *  **     *** *  * * (n != 0)
***     **  ***  * *   * * **
  **** ***     **** ***   *    ** ***  ** *** * *    * **  ** * = m % n;
 *        *    **    *  * ***     *       ** * *  *** *** = n;
 *** *  * *     *       *   ** *  * *   *     **  = remainder;
** * *  * ** **   * *   * 

  ** *  **  ** *   ***    * * **** = m;

 * * *  **   * * *  *      *    * **  gcd;
}

int main (int argc, const char * argv[]) {

  * ***  ** *  ** * ***** *****   number1, number2;
  ***     *    ** **  **  **  ** newNumber1, newNumber2;

**  ** * ** ***   *  ******* * **  *    ******** *  * ****    *   ***  *** **

 ** *** **  *  *******  * *** *   = number1 /   **   * number2);
 ***  *  ** *** ***   * * = number2 /  * * ** number2);

 *** * *  **   *  **  * *     **    * *  *      *  *
    ** *** * *   * ***** **  *    * * *  ***  ******   *  *  **  *    
    *   * ** * * ** **  ** * **
*****     ** * *   *  *** *  **  **  ** *  *  ** 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  ** *    * * * *  ** *
  * *  *  **  **  * **

int **** * n, int m)
{
  **  *   *  * **  int gcd,  ** * * 

* *  *   *   *  ** (n != 0)
   *  *    **  * {
**** * *         *    * ** *      *  = m % n;
* ** *  * *** * **   *  **** *  * * m = n;
 ** ****  *  **     *    **       n =  **  *  *
  * * * * * *****   }

**   * * *** ** gcd = m;

*****  * ****** ** ***  gcd;
}

int main (int  *   *   char *      {

 *  ***    **   * int * *****   * *
**   *  **   * int  ** *   * *   **

***     **   *  * * ** *     **  ** * *******         *     **

 * *****   *    * * *   * =  *** /  **    *     * ***
 * *   *  *        * *** =   * /  *****    *   ***

***** *     * * if * * ****** *  **   **
*  ** ** * **       ***   * ******* **   ** * * **** **  
*      * * ** * else
*****   ****** * *     **        *  ***   ** * 
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
***     ** *  *** * ** **  **  * i;
 ** *  *   * * *** * ** * *   j;
*** **  *   * **    ** *  ** newNum1;
  ***********  ***  * *      newNum2;
   * **  * ****  * ***  ** * gcd;
    * * * *** ***    *   ** * * rem;
 *** ****    **  **   **    ** * num1, num2;
    
     ***  *   ***** *** ** *** ** *    ** *   ******** ** *
*** ****   * *  *       * 
** ***  *** *  *** * ** **    *** 
** *    **   *  *** *  *  * ** *
* **  * * *      * * ** *** 
* * ***   ** **** * * * *** * != 0)
* * ** *  * **  *  * *     *  
*** **  * **  * *****     ***   * *** * **  * ** * * * * = j%i;
    *  *  *  *    *  * **     * *** *** ****  **  = i;
*** * *   **   ** *  *   *  *  *** **  * * * *     = rem;
 * *  * **   * * *  **
 **  * **     *   ***     * *
    
   ** **** * *  *   *** *****   ** *  = num1/gcd;
  * ***** * ** * * ***** ***   **   = num2/gcd;
    
**   *   * * **  ** *     ***    * == 1)
*** **  ** ***  *   * ** * *** * 
*  * * ** * ****  ***** **    * *  * **    **   *  *******  * *  * *    **  *******  
  * *** *  ** * ***  ** *  * ** 
    
*  *** *   * **  ** * * *** *  **
***    ** *  *  *  *** * ** 
   *    **  *  * **   **   *   * *  *** *** ********** ** ** * *   *  **  **    
 ** ***  *  *** **** **  * *  
    
  * *   ***  **  ** * ***   0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
* **  * *  *    ** **** *** * i;
    **  * ******** * * *****   j;
*** *  *  *  *  **** ** ****  *   * newNum1;
 *** *  *****   *   **  * ** **  newNum2;
 * ***   **  *  * * *    ***  * *   gcd;
        ****  * *  ** * *    * rem;
*** *    ** *   * * **  *     num1, num2;
    
* ** *   **  *   ** * *  ** ** **** ** * * ***     ***** * *  * *   * *   *   *   
 **  * ***  * *  *       * 
*  ****   * ***  *   *      **
 ** ****  **   **   *     * *
  **  **   *** * ***   * ****
*  *  *  * ** ******** * *  *   * * != 0)
 *  ******    ** **    * *   
   *  **     * **   *  **  *        * ***     ** ** *  * *   = j%i;
  ***** *   ** ***   ****  *  *   ** * * **** **  * *   *  **   = i;
*  **** * *     * ** *  **  ***  ** ***** *  ** = rem;
 *       **   **** * *  **   *
**** *  * ***** * **     ** *  
    
 ****      * ***  * *  * *   *  = num1/gcd;
 ***  *   *    * * *     *  **** = num2/gcd;
    
 **** * * **  ** * * * *  **** == 1)
     *      ***      **   
** ***  * **** **  ***    *      * *  *   *   *    * **** * * *     **   *  **
**** * **** * *    *   *  **
    
* * **     ***** **  ****  *** 
   * * ** ***    **   *  
  **  * *   **    *  *  ** **   * ***     * * *** ** *   ** ** * *** ** **   * * ** *
 * *  **  **  ** *  ** **** *
    
 ** **     ** * *   * *  ****** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
 * * *  *  *    *****       ***      * *            *     ***
  ****** **   **   ** *  **    * **  * * **  ***    ****** 
    {
  *   **  ** ****  **    ***** *  *  *****  * *  *  **   ******   **** 
  *   * *  ******   ****** **  *  **  ** *  ***  ** *** * ***  ***     
*    ***  **  ***   *    * **      ***  *     
 ** *** *    *****  *  *  **  *  * * **   ***
 ** **** ****        **  * **            * * * ** ** 

* * * * **     *  * ***  ** *     *
*   *   **  ***     ** *  *   *   * * * *** *  *  ** * * * * **** **    * *  * * ** ***    **  
    **    * * **** ** ** *** ** **  *     *   *  **** **   ****  **      


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*     ** *      ** * *** *   a,b,GCD;
 *  * * *   **  * * ** **    **  * **     * ** * *  ** ***  * **
* *  * * * **** **   * *    ** ** ** **
**   *   *      * *****   *          
*    **   ***  * **    ** *    ***  *  **** *****     ** * *  **   * **
* *  **** * **  ****  *      *** **
  **   *  * * *   * ** **** *  ******  ** **    *   * *   ****** *   *   *  ****
* *  * *  ****  ** * **  ** ****** * 0;
}
* *** *** **** ** *  **** * gcd(int a, int b){
*  ** **   ***** ** ** ***  *   * *** * *****   ** ** * (!b) return (a);
   **** ****** * **      **  *******   ** * * * ** *    ***  ** gcd(b, a % b);
 ** *  ** ******** ***
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * ***** * *******   
#include *** * *  *  ****

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
  * ** * *** *  *** *** **** **** gcd, remainder;
  **     * ****** ******   
*  **** ** **   *  **  *  *   **   (n != 0)
      *  ***  * **   ** ******
  * **  ***   **  * **  **  *** *** *    *****  *** **** * = m % n;
* *  * * * ** * **    * * ** *      **  *  *  * **** = n;
**** ***   **     ** *  *    *    ** *    * ***   = remainder;
       **  * *** ***    *   
* *      * ****** * **  **   *  *
 **   *   *   ** **** **  * *** = m;
 ***    ** ****  * *  *   * * *
**** *******  * *    ****    gcd;
}
int main (int argc, const char * argv[]) {
 ****  *  **** *    ***  *** number1, number2;
 ** ** * ***      *** * ***  newNumber1, newNumber2;
  ** *** **** ******  *** 
    ***   ** **  **   ****  *
*   *      * *   *  **** * *     *     * *   *   ** *     * *** * 
      **   *      *  ******  
*     * ***  *   ***   ** * *   * *   = number1 / gcd(number1, number2);
 * **** ** ** ***** * ***  * ***  * = number2 / *   ***   number2);
*** *** *** **    *  *  ** 
          *   *   *** *** 
  **    * **  * ***  ** (    **  
* * **    *  *  *** *****  **   **  * *       ***  *   ** *   * ** *** newNumber1);
 ** ** * * **  *   **  * **
 ** *   **  * ******  ***  
   **** *  * * **** ****** **   **  **   ** *      * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*    *     *****    **     *** * a,b,c,d,e,f;
 * * * *   ****   *   *** ***   **   * ** ***  ** *  * * *** ** * 
* ***  ** **  * ****  **** * *
*  ******  * *          *** 
 *        *** * **  ****** * 
    {
** * ***  ** *          *  ** ***   *  ** * ******
 ********   *  ** *    ** ***     **  * * ** **  **  
  ** **  * *   ** *** ** *  ******  * ******* *    ** ***
    }
  *   ****   **   *  *** *  **   *
    {
**      ******   **** * *   *** **** ****      *   * *  * *  *
***** ***  *    ** **** *  **** ****** * **    * *    *   **** ** *****   *     * *
 ***** * **    * * ** **** ****** *** ** ****  *****
** ** ** *   *** * ** *  ** *    * **     **   * * *** ** *   ** * ***  **  **
    }
**   *   * *         * ***      
    {
   **    ****   ** ** **   *   *  **  **  *       *        ****
*  ** ** * **      ******   ***  *  * ** ***   *   *   *        * **  * * * * *
** ****  *  *     **   ** ***** **** **    * * **   
 ** **** *** * * * ** *      * ***  *****  ***    ** *  ** ***  * *    **
    }
  *****  ** * *  *    ****  * **** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.12
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 13.3k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 13.2k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 16.7k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 12.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users