11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
7.8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 7.8k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

** **    * * *  ****       * *   i;
** *  ** *  * * *   *    *  j;
  *  ***  *  ***    ** *    *  newNum1;
   * ****  **    * **   ** ***   newNum2;
**** ***   *   ******* **  gcd;
   **      ** **   **      ** *   * * rem;
*******    **  *  * **  ** *  num1, num2;

**    *   *  ** **  ** **   *   ** ****     *  *    * *  * *** **

 * ***** *  **   * *** *  * *   ***
   * **** *** * *    * *    **** **

   * ** * * ***  *   ****** ** * * != 0)
*  * *** ** ******
   *  **  * * *  *    ** *    *  * ** **  ** **    = j%i;
* *   *   ***     * * ***** *  * ***   ** **  *   *  *  * = i;
 *   * *    ** *   * * * **      *   ****** * **** *** = rem;
* * **   * ***** * ***   **** *
* ***  * *** **** *  *  * * 

  *  * * ***    ** **** ***  = num1/gcd;
   *** *        * *   ***   = num2/gcd;

     *  ***     **  **    * **** == 1)
    {
 ***** **  * *     ***** * *  **    *   * ** * *  **  ***  **  *****  *
    }

  ** *      * * ** **  **   ** 
    {
****** ** **  ** ****    **  * ****        * ** *****  *    **   *   *** **** *   * * ***  
 **  * * * *    * ****    ****

  *  **  * **    ** * **      ***    0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
**   **    *     * * *  * * **  * *  * ** *   * *** ** *  *   * *  *** *

*** * *  ** *       * ****   ******
  *** * *  ***********    *   ** ****     * ****    *** ***  *  *** * ** * **   **

    else{
        ** **         ******   * **
    {
* *     ***  * ** * ** *  *   **  * *  **** * 
**     *  *   ** * *    *     **  ** * * * ***  **   *** **    ***   * * **  ****  * && deno%i==0)
*   *** *  *****     **   *  *   * *** ** *       ******    * * *** * *  *  * ***    
  **** * *   * ***     *  * * *   ***   * * * ** *   ***     *    *  ****  * * * ** *****  *****     
*    * ** **    ***  *** * *  *  ****  ******* **** *** * *  *   **  **    *     **  ** *  *  *  *     ***    **     * ** 
    * *  *** **  ** * **    ** *      * **   *   *  * * *  *   * *** *   ******
    }

 ** * ****     *  ***  ** *  *  ***  * * ** *** *
    {
***  *****  *****    * *  ***     *** *****
  *   **   ** *  **      *  *****   *  * * **  **  * *  * *** ***  *  ****   * *    **** ***  ** && deno%i==0)
   *   *   * ** *   *   *  *** *** *** ** * *** * *  *****   * *  **   * 
   *    *  *         *   * *  **  * ** **   *  *    * * *  **  **     **    *  *  *  * ** * * **** ** **
*  *     ****** * *   ******   ****  * ** **** **  **** ****      *  **** *********   * *** **     *** ***** *   * *    *
*  ** ** ** ***  * * *****  * ***   *      ** *   **** **   *** *   ** *  **  * * 
    }
    *  **** **   ***  * **  **   * ****** * *   ***  *  **

    }




**     * *  * * **      * **     * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *** * ****** 
#include ***      ****   

int gcd(int n, int m)
{
* ***  ***  *       ***  *** * gcd, remainder;

*   **  ****      *  * *******   **  **  (n != 0)
*** *  * *   ***  *  ****  
* *  **  * *  *  ***  *   *  * ** *****  *   *  *  **  * * * * **  = m % n;
** * *****      ** ****  *  **  ***** **** *  *   * = n;
*** ***  **  *******  * **  ******** ***  * *** **   ** = remainder;
* * **  ** * ***           

    ** * ******* *   *  * * *** = m;

****   * ***** ***  *** ** ** gcd;
}

int main (int argc, const char * argv[]) {

* * **  **  **  ** ** ** * number1, number2;
**   ***   ****  ** ***   * **  * newNumber1, newNumber2;

 ******* * * *  *   **     *** **   * **  * ** *  ***   * **** * *   ***   **

*   **   * ***  *   ****       * = number1 /   ** **     number2);
**************   **  * * *  **  = number2 / *** ** number2);

***   *  *****  *  **    ** ***   ** * *** *   *
***** ****  * ***  *  *   *   *  *   ***  *  ** **  * *** *
 * ****  *  **** *   *    **  * *
* * *  **   **** ***   ** *  **  * * * *    ***    * ***  
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  ** * * *  * **  *****
** ** *   *****  ** **  

int      n, int m)
{
*    * *    *   *   int gcd, *  *

  * * * **  * * *  * (n != 0)
**  **    ****  {
 ***  * **  *  ** *   ** *  **   = m % n;
  *  *  ****  **   ** *    ** ** * m = n;
 ***  *         *****  *  * * ** n =   *  **
   *    ** * ** }

 **    *** *** * * gcd = m;

* **  *    * *   ** gcd;
}

int main (int  *** *  *  char * * *** {

****  ***  **   int   ***       
**** *   ** **  int  *** **  **  *  

  ***  * *   *   * *    * *****  *         * ***** * **** *   *

 * *  ***   *      *** *  =  *   /  *** *** *   ** ***
** **   **  **  ***   = **** / * * ** * *  *  * 

     * * *     if    ** ***    ** ****  **
**  **  *****     * *** ****  **    * *  *    *** * * *  *
** ****   * **  else
 *  *  *** *       ** *** *  * *  ***  *  **   **     ***
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
  **  * ***     **  * **  ** i;
*  *  ***   * *** **  *  ** **   j;
       ** *   *  * * *   **  **  newNum1;
 **  * ** *   ** *****   * *   newNum2;
* ***     **  ** ***   **   *   gcd;
*   *   ***  ***      *    *   rem;
 ***** * *** **  * ** *       * num1, num2;
    
  * **** **** *  *****   *   *  *** *    * **  **  * *  *   * **
*     * **** * **   ** *  *
**  **       ****    ** * * *  ** 
**     **  * **  * * **    *     * 
  *     *     * * ***   ** 
 ****    *  ** * ** * ***        * != 0)
*   *** *  *  **  *       ***
 **      *  *    **    * * ** *******  * **   ** ** **   = j%i;
*  **     ****** *  ***** *****  *   *   *  * *  **  **  * = i;
 *  *******    **      ***   *   **  ** *    *** ***   * * *  = rem;
**** ** ***  * *   **  * ** **  
**      ***  *    ***   *   * *
    
**** ****  ****      ** **    = num1/gcd;
       *   *     *   *****  = num2/gcd;
    
************ ** *  * *  **    == 1)
**  * *** **  ** * ** ** *
  *      **  * ***   ****  *   * **  * *     * **  **  ******* ***  * **     * ** **   ** **
    ** * ***   *** * * *    * 
    
** **    ** **** *    ** * 
**     *     **** ** *  ****  
* *  ** **  *** * ***  **     **  ****  ***** *   * *  * ** ***** ** *      *** ***    
* * *  *   **  * *  ***  *
    
 **  * *  ** ***** *   * *  0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
**** *  *** *  * ***  * * i;
*  * *  * ****** *   **  * j;
 **** **     *   ***   **  newNum1;
****    *   ****       ****** newNum2;
 ** * ** *      *  **** **  ***  gcd;
* ***  *    *  * * *   ***   *  *** rem;
*      *   *   * ***   num1, num2;
    
*** ***   ** **  *** *    * ** *  **      * ** * *** *  ******* *    
* *** ** * **** **    *     ** 
 * ** * * * **  * * * * * *
** *  *  **   ** *****   * * ** *   
 *   *   ******  *****  * * 
  *      **  *          *   * * * != 0)
*  ****    *      *  *** **
** *** *** ***   ** **  **   * *  *** *   **  * * ****  ** = j%i;
   * *      ********** *   ** **   *   *   **     **  = i;
  **** *** *   * *       * ** * * * *** * * * **  ***   * * = rem;
 * **  **  *********  *   * * *
 **   ** * ******  ***  **      **
    
    ** * ** ****  *   *** *   = num1/gcd;
  **   **   * ***  ** ****   * = num2/gcd;
    
*          * **  ***  **  *  * *  *  *** == 1)
* *      **   *  * **  *** 
 *** ** *   *  *   * *** *      ***        ** * **        ****   **  **       *
        *****    *     *** 
    
* ** * * * * *  ********  **     
** **  *  **** **   * 
  * ** * *  *    * **** ** * *   ***      *   ****   ** *       *** * **  **  *** * * **
* ** * * ** *        **  
    
**  *******   *      **    ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
 * * ***** *  ****** * ** ***    *      **  ****** **      ****
* ***    ***   ***    ****   **  *  *    **     * * ** *****  * *  **
    {
*  ** ***   *  ** * * * ** *  *** ** **  *     *    *  ** *** *  * 
* *****  ** * **** *   **      *   *** ** *  * **  *   ***** **** 
*  * * * * **  * **  *   *** **  **** 
**       **  ****   ****     **   *     **  * * * 
* **  **  *  *   *   ** ***        * * *  *  

*   ***       ** * *     * * *
  * **** * * * *  * * * *******   *******      *  **   *   * ***   *   ** * **********  *** *  **
 **    * *    *   *  * *** *  *   ***   **     * ** * *   **   **  *    


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
   *    ** **  *  ***** *   a,b,GCD;
      ** * **   **  ** *** * *  ** **  * ** ** *  *   *       **
   * ***  ****  * * * *  *  * *    
** **  **  *     *  * *  * *   *
  ***  * *** **** **    * *   **** *   * * *  *** ***  *  ** **   * * * **  ****
 * *     * * *  *  * ** *   ** *
*****    * *  * *  *  *  ***     ***  * *  **  ****   *** *   ***    ***  *
 * *       * * **** ***** 0;
}
    ***    *  *****   gcd(int a, int b){
    *****  ****** *****  **  ** ****  ***** *  * ***  * (!b) return (a);
   ***  *        *   ***      ***  **  ** *  **** *    **  *   gcd(b, a % b);
  * *    *  **** * **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *   *  * *  
#include * * ******  

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
  **** ** **   * * **      *   gcd, remainder;
* ** *   * **** * **  *  * * *
 ** ****    * *   *    * *   (n != 0)
  *  *   * **  ****  
** * ** **     ***** * *  *  * ** ***    *  **     * *  *  **   = m % n;
*   ********* ** *     *  * ***     *** ***  * * **     * ***   = n;
* ** **** ***     **  * * *  **** *** *    *  = remainder;
   ** ** * *  *  *    * *  
** ***  * * *      ***  *** 
* **** *  *      **   * * * ** = m;
* * ***   **** **   *  * **  
  **   **    *    ** **  **  *  gcd;
}
int main (int argc, const char * argv[]) {
  * *          ***   *** *** number1, number2;
*****  * **    *** *  *       newNumber1, newNumber2;
 ***   *  * * * ***** **  
*  *     *  **  * ** *     ***
* **    *       ****   *   ****    **     * *  ***  **       **  *    *  *  
*  ** *** ****  *  *  ** *    * **
** *  * **** *  * **     * **  ** ***  = number1 / gcd(number1, number2);
*  *** *  **     *    ** * ********  = number2 / * *  *     number2);
** * **     ** **** *  * * *
 ***   ** **  ** * ******
  ***** *    ** ***** *  ** * ( ***   
** * **    ** * * *    * ** * ** **   * *   **    * **  *  *****  ***  * newNumber1);
****  *    *     *  *   ***  *
 * **  **** * ****   *
 ********  * * ** **** *** ******* **** *  ***  * ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* *  * *   * *    *    *  *     a,b,c,d,e,f;
*** * * ******   * **  *   ** ***  ***** *   * *      ** 
* ***  *****   * **  ** **
*** ***      *       ***  *   **   * 
    * *   **  *    ***  ** * *** **  **  *
    {
**  **   ****  ***    *   *    * * **  **  *  ***    *  * * 
 ***  ** *       *******  *  **** *   *  ** *  * * * *   *  ** 
   *    ***   *     **  ** **   **** *** * *  * ******** 
    }
*  **    ** * *** ******  *  *** ** *  * 
    {
* *  * * ** ****** *   *       ***  * **  **  ***    * ***  **
    **  *     ***** ** *** * ** * *        ** **  ** *** ***** ** *   
   ****   *** *   * *  *** **** ****   **  **  **   **** 
*  *  ***   *  *   ** * *     * ** ** *  * ******   *****  * * *** *** * 
    }
 * *** ***  ***** ***  ***
    {
 *** * ** *******  * * ** *  *   *** * * ** ****    *
*** *   * * *  * ***** *    *   ** * * *  ****** *** **   ****        *   *    **
 * ** ****  *  *  ** * *  ********** *  *  *   ** *  ***  *
***** ** ***   **  ***    *  *    *   * ****  **   *  * *  **  *  *      * **  * *    * * *
    }
 *****    ** * * **     **     **  0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.62
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 8k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 7.7k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 9.7k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 7.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users