11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
14.2k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 14.2k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

  **  *** ******  ***** *     ** i;
**** ******* *   *   *  * * * j;
 ** ** *  *   ***  * ** * * *    *  newNum1;
*   *  **    **** ***  ***** newNum2;
** *   *      ** *****  gcd;
*   ** ***  *  **  **     * ** rem;
**  ****  * **  * * * *    * ** num1, num2;

** *****  *  ***** ***  *   **     *     ********      ** **  *** *  *

******  *    * ***  **    **** * *
** ** **       ***  **** ***  **

 *  * * *******  * * **   ****** != 0)
   *****    * **  ** ****    
**   *  **           *     **** **   *      *** *  * ***    = j%i;
  * * **** ******   ****       * *    ****** **   *      ** * = i;
**     *  * * *****    *    ** ** * * *  *  ******  * *  = rem;
** * **  *  *   *  * ***  *   
 ** ** *  * ********** *** * *

*   **    * *  ** *** **  *  = num1/gcd;
**  ** ******   *  ***    *  * * = num2/gcd;

****  *  **  *  **  ******      * == 1)
    {
  ***** **  *  *   ****  **** **   *   * ****** *** ** *    *     *  * ***    ** * *
    }

***   *     * ****** * *  **
    {
* ** *    *  *** *** **** *  *   ** * ** ******** * * * * **  ****   ** *  **** *  **  *  *  
*    ****** ** * *** ****  ****** *

 * *  *** *  *** ** * ***   *  * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
       * *  ** ***** *  ** ** **  *  * *     * ** *  **  ********  *** 

 * **** ** ***** * * *  *   *** * **
  **  * *     * **    * **  ** **  * *   * **  *   **    ** * * **   *       * 

    else{
* *     * * *  ** ** ***   *****     **
    {
 * *   *  *   ** * *** * ** ***      * **  * * 
    **  ***** * *  *   ***  **  *  * *  *  ***  * ****       *** * **   ** ***  **  *****   && deno%i==0)
 **    **  *   *** ** *   ***  *   ** **** ** ** ***        ** * ***  ****   
 * * * ** *****  **************     * * *  *  * * ***** * **** *   *   * * * * ****   * ** * ***
 * *  *       ****  * * **  **  *   *  * **   *  *   * * **  * **  * *   *  *  * ** *  *   *    
* * **     * * **** * * *  **** **   *  **  * *     *   * *  ** * * ***  *  * ** 
    }

**    *    ** ** * *   *        ****   * * ** 
    {
  *  *  * ** *  **** * *      ****** ******* ****    
   **    **** *  **     *    * * ***     *  *   ** *  ** *  *** ** *  ***  *****  *  * && deno%i==0)
***  **  * * *   ******  *    **  *  **   *** ** *  * *  *  ************ ** * 
***  **   **  ******  ** *  ****   * **   ****  *    ****** ** ** ****  **   *     *  * *
  *   *   * *  *  * ** **** *    *** * *   **    *  ** ***  *  **   **  *****  ** ** ****   ***  **  **  *****
*    * *  ***** **   ** *  **** *  * ** **  *****   *  *  *  **     **  * **  **
    }
 ** ** *    * ******* ** **  *    **** * * *  *  * ***

    }




** *  *   *  ** **  * *  ** *  0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * * **  **
#include **      **** * *

int gcd(int n, int m)
{
*  **  * *  * ***   ** * gcd, remainder;

******  ** ** ****   ** *    (n != 0)
 * *   *****  **      *   **
****   * *  ***       *****     *** *** **  ***** * **   *    * = m % n;
 *****     ****    *** * * ** **   * *  *  * *  ** ** **    = n;
*  ***  ** ******** **      * * * *  ** ** ** **         = remainder;
***  ** * **     * *   * *   ***

 * * **  * ** ** * ***   *   = m;

* * *   *****    *  * *** *  gcd;
}

int main (int argc, const char * argv[]) {

 *** * **   ********* *** *  number1, number2;
 * *** * * * * *  **  *  ** newNumber1, newNumber2;

* *   *** * *  * ******   ** *****  * ** ** *     ** **** *  * * **   **  ***

 **  ** * *    ** **   **** *   ** = number1 / ***** number2);
 ** ****  ****  *  *   ***  * * = number2 / *********  number2);

 *  *  ***    *  *** *         ** * ***      **** 
*   ****    * *** ** ** ****  * *****   **  *** ***   ** ** ** * 
**   **  **** ***** ******
*  * **  **     * * * ***  **  * * *   * ** *  **** 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**   * *** **** * * 
*      *     *  ***** 

int  * ** n, int m)
{
  *    ** *** int gcd, *  *    

 ****     ***  (n != 0)
 *   * **      * {
** *** ** *** **  ****    * ***  *   * *  = m % n;
******  ** ** ****  *  *  m = n;
*  * *  *      ** ** * *  * n =   *** 
* **    * ** }

  ****   **      gcd = m;

**  **  ** * * gcd;
}

int main (int * * ** char *  ** * {

***** * **  *  * int      *     *
*  * * * * int *          ** **

 * * **   ** **   ** ****** *   *     **  * * **  **  *    **  *

*   **** * * * *   * **  = **** /   * * ***  **   
* ** *    **      **  * =  ** /    **** *   **  *

* * *****  *  * * if  *  * * ** *** * * 
***  *   ***   ** *  * ***     *     * **** **    *** *
** *    *       else
 ****  ** **  * ** ** *   *   ** *  * *  *  ** *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
   *    * * **    *    * *  i;
    *    * *    ****  ** ** j;
    **  **** * **    *  * **  newNum1;
  **  ** *  **   *  **  * newNum2;
 ** **  *** ******  * ***   * *** gcd;
  *  ***   *  **  * *      *** * rem;
***    *   ** *  *    *  **   num1, num2;
    
 * ****** *  *  **   ** *  *** * *****  *  *  ** **** *** **  *
*** **  ***  **  **  **  *
 *  * * *  *    ***    ** *   *****
    ***     *  *  * ****  **   *
 ** *   * * * ** ****    
 * *   *  **   ***  ** *  ***     != 0)
** * * * ***  **  *   ***   
*** * ** **  * **** ** * *   * *  **     * * ***** ****   = j%i;
 **   ** *  *** ** *  ***   *  * *  *     *** ***  ** = i;
 ****  * **   * **  ***  **  ******* ***  ***  *    = rem;
* * *** *  ** *   *  ** 
* ****  ** **   *  ***   *  
    
 * ** * * ****  **  **  ** * *  = num1/gcd;
*** **   **  ***  ** * *  ***   * = num2/gcd;
    
 ** *    * ** **  *   * * ** * *   == 1)
**    ** *  * ** *  ** ****
   * ***     *    ** ***     *   *  ***  *** ** *    ***** *  *****     
**** ******** ****    * *  * *  **
    
** ***** **      *****  *  * 
     * *  * * *    ** * **   *  *
 ****   * *    **  **   ***     *   **** ** * * *    ***  *  *  *** *  * * *  * *    *     ***   *    ***
*  *  **** *  *  * **  ** ****    
    
**   *    *  *******  * **   * * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
*** ***   * *   ***** * * *    *  * ** i;
 **  ***** *  *  ***    *** *  *  j;
*    ** * *  * ** * *  ***  * **   * newNum1;
*    * ***    * * *  ***   *  * newNum2;
 ******  * ***** * **** * * gcd;
*  * ****  *  * **    * * *** rem;
 *  * *  **           *  num1, num2;
    
*   * ** *   * ** *****   *       ** **** * *** **  * ****   *******
      * ** *** ***   * * 
*  * **  *     *  * **  ** 
 * ** ** *  *** ** ***  * *     *  
    *** * *   * **    * **
*** * ** * ***   *  * ** * * *      != 0)
 **  *    ******  ** ** * **  
           ***  ****** *           ******** * ** *    = j%i;
**   **      * **    ****   *  * * ***   *  ***   * = i;
  **   ** *    * * *   *  ***  ** ** **** * *    *   ** = rem;
** ***    *  **  *** *** *** *  *
     * *    * *  ****    * ** *** *
    
 ** *  * ** *     ** **  * * ** *  * = num1/gcd;
 ** * *  ****   * *****  **   = num2/gcd;
    
 *  ** *    * * *  *****     ** == 1)
***  * *  ** *     * * * *  **
*  ** ***  ** * *  * * * *   ****   ** **  **    ***   **  **      * *  ***   *
    ****   ***    ** ** 
    
* **  * *  ***    * *********    
** *** *** *** ** ****** *
*       ***  ***     *       **    *     **     *  * *    ** ***  *** * ** * * *   *  *
 **  **  *** **  *   ** **
    
  ***  *  * ** **  ********* ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
 *** * ******* * ****  *** * **  * * * ** **    ** * * ****   **** ***
**     * ** **   *  ** *  *  **  *** * *   **  ****  ** *  *   **   ***  *
    {
     * **   *    ****  *  ***   *    * *  * *   *** ** * ******     * **
  ***  * * **   *** *** *** * *  *** *** *    **   *    * * *
 ***** * ** * *  *      *  **  * ** *  *
  *    *      ** **   ** * ***  *  *****  **  
     * *   * *  * *  * ** *****  *  ***    

 ******   **   *****   * * *   *
  * * * * *  ****   **** *** **  *** ****  * **  ****** ***  * *** *  *** ****   * **   **         *   *
*****  * *   *    * ****** *  **   ** * *   * ********* * *** *   **  * ** ** * * * **


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*  *  ** ** **  *  ****   ** * a,b,GCD;
 **********   * **** *** *  ****  *   * * **  ****   *  
   * *** * ** ** *   *   ****  **   ***
***   *        *   * ***   * * **  
**  * ***********   ** * * * * *  * ** *   ******  **** *** ***     * *  *  * *
*     * ** ****** *   ***  ***
****   * *********  **  * ******** * ** ****** ****** *    ** * *  * 
 ***   *   *  ** **    * *** *    0;
}
 ** *    ***   * *  *  **   * gcd(int a, int b){
***** **  * * *   *** * *    * ** **    ***     * * ** (!b) return (a);
 **  **  **      *  *  *  ****** ****  * * * ************ **   * gcd(b, a % b);
  **    *  ***  ** *     ** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  * * * ***   
#include   *   *  * * *  

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
*    **  **  *** * ******  ** gcd, remainder;
   *  * *********   ** * ******
   * ** * *      **** *  *  *  (n != 0)
*  * *     *** *    *    * 
   ** *  **       * ***   * *      * ****  **** **   **   *   *  = m % n;
        * ***       **    ***   *  ***   **      ***  = n;
** **  ***  * *  ****** * ** * **  **** ***  *  ***    * = remainder;
 *    *** ** ** * **  ** ***     
    ** * **    * * *    *** 
 * *   *   *  **** **  ** * = m;
 *****  ******  * **    **  *  
*   * ** **      ***    * *** gcd;
}
int main (int argc, const char * argv[]) {
 *  **  *  *     *  ****  * **  * number1, number2;
   * *** **  * *    * **    newNumber1, newNumber2;
****  ****   * ** *  *** **
      * *******   ** *** *
 ****     *   * * ****  ** ***** **  * ***  ***    * **  *  *  *
*   *   *   ***    *  ** *  *
  * ***         *** * ** ** **      ** = number1 / gcd(number1, number2);
*** **** *  **  ****  ****   *** = number2 / * * ***** number2);
 **  ** ***   *  **      * *
   *   ****** * *  ***  *     
** * *  **   *    * ** ** * ( * * **   *
** *  **  ** *  ** *  *   *****  *** ***    ** * ***** *  * ***    *     * * **  newNumber1);
 * *   * **  ***   **   *   
 ** ** ** ** **     
**** ****  ****** **  ** *** ** ***    * *    * ** * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** ** **  *  ***  ** * **   a,b,c,d,e,f;
 ** ***** * * ** *  ** ** *    ****  * **          ****  **  ***  *   **
*  ****  * **  *      * * 
 ** **   **  *  * * *   * 
***** * *       *   * **  ******** *
    {
   * *   *   * **** **     *    * * ***   * *  **   ***    
*** **   **  ** *********  ***  ** *    ** *   **   **  *** *
 * ***  *   * * *     * ****  *  ** * ** *******   *     * 
    }
**  *  *  *  ** *  * *   * ****     *
    {
   ** ** * *    * *  * * * ** * * *****  *    * *  * * *
 **   *  * ***** * *    *** **   * *  ****  * ** ***  ** *  *** *       **** 
** ** *  **   *** *** **** *   *** * *  *  ** * * ** ** *
   *   *  *** ** * * *   *  *     *      * *  ** * **   * *******  ** *** *
    }
  *   *  **** ** * ** *  **  *** ***
    {
*    *   ***** **  *  **  * *    * *  ** **    **** * 
   ***   *  *  *** ****** ***** * *       *  * ** ***   *   *    * *   *  ** ******   ***
*  * *  ** ***  *    *    *   * *   *** ****  *   * ** ** * 
 * *      **** * * ** * ******* *** * * * *  ***  ***  *  **  * ********* *****  * 
    }
 * ** ** ***    ***     0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.168
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 14.6k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 14.3k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 18.3k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 14k views
12,783 questions
183,442 answers
172,219 comments
4,824 users