2 like 0 dislike
17.5k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 17.5k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

*** * * * **** ** * i;
* *** ** * ** * * *** j;
**** ** **** ** ** * newNum1;
* ** * * ** * **** * newNum2;
** * * * * * * ** gcd;
*** **** ** * ** ** * rem;
***** * *** ** * ** * num1, num2;

**** * ** ***** * * * *** *** ****** **** * ** ** ** * *****

** * ** ***** ***** * ** * **
* * ** * ** * ** * *

** ** * **** *** **** * ** != 0)
*** * * ***** **
** ** * * * * * * *** * * ***** * * *** ** **** = j%i;
** ** * *** * * ** ***** * * * ******** ** *** = i;
** * ** * **** ** ** * * * * **** * * * * = rem;
* **** ** * * * ***
*** * ** * * * **

* * ** * ** * * * * = num1/gcd;
** **** ********* * ** ** = num2/gcd;

* * ***** *** **** *** **** == 1)
    {
*** * * * * ***** ** * * ** * * ** *** * * * * ***
    }

* * * * *** *** **
    {
** ** * ** * * * *** ** * **** ** * * * ** ***** * * *** * * ** *
** ** ******** * *** *

* * *** * * ** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
*** ** * * * * * ** * ** ** * ** *** *** *

* * ***** ** * * *** **
* ** * *** *** * * *** ** *** * * * * * ** * **** * ***** ** ****

    else{
* * ** * * * ** ** ***
    {
* * ** ** * ** * * ***** *** * *
* * **** * **** ** ** ** ** * * ** ** * * * * && deno%i==0)
* * * * * * ****** ** * * ** * * * *** ****** * * * ********* **
** **** ** ***** ** * ** *** **** ** * * * ** * * *** * * * **** ** *** * * * * * * * * ***
* ***** ***** * ** * * * * *** ***** * ***** ** * *** ** * ***** *** *** ** **
*** * ** ** ** * * * ** *** * * * **** **** * * ** ** * ********
    }

***** ** ** *** *** ** *** *****
    {
** ** * * * * *** *** * ***** * *** ****
* **** ** **** ** *** ** * * * ** * ** * * ** ** *** ** **** * * && deno%i==0)
*** * * * * ** * ** ** * * * * * * * *** * **** ** * ** ** * ***
** * * ***** * ***** ** * * *** ** ** * * ** ***** * * ** * * * ***** ** ** ***
**** ** * **** * **** ** **** ******* **** * * ** * * *** *** ****** * *** ** ** **
** * ** ******* ** * * * ** * ****** ** ** * * * * * *** *** ***
    }
** ******** * ** ** * * * * *** ** * *** **** * **

    }




** * ** * * *** * * ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** **** **
#include * * * * * * *

int gcd(int n, int m)
{
* *** * ** ******* ** * gcd, remainder;

** **** * *** *** ****** * (n != 0)
* ** *** ***** * * ** * ****
******* * * ** **** ** * * * * * ** * ** * * * * = m % n;
* *** * * * **** ** ** * ** * *** * **** = n;
** ******** * * * ** * * *** ** ** * ** * * = remainder;
* **** *** * * *** ** *

******* *** * * * ** ** = m;

** *** ** ** * ** gcd;
}

int main (int argc, const char * argv[]) {

* * * ** * *** ** * * * number1, number2;
** * * ** ** * * newNumber1, newNumber2;

* * * * ** * **** * * * ** ** *** ***** **** **** ** * ****** **

**** *** * *** ***** * * = number1 / ** ** ** number2);
****** *** * ** * ** = number2 / ** ***** number2);

** *** ** * ******** * * * ** ** * * *
** * *** *** * * ** *** ** * * * ** *
* * * ** ** ** ** * *** * *
*** **** * ** *** *** ***** ** * ****** * **
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* ** ** * ** *****
** *** * ** * ** * **

int * n, int m)
{
* * * *** *** int gcd, *** *****

** * * ** (n != 0)
*** * *** {
* * * **** * ** *** *** = m % n;
* ** * ** * * * * * m = n;
* * * ** * ** * *** ******* n = ** **
* * ** }

* ** * gcd = m;

* * * * gcd;
}

int main (int ** char * * * {

** *** int * **
* * * int ** ** * **

** * * ** * *** **** *** ** ** * * * *

* ** *** ** ***** = ** * / ****** *
* * **** * *** = * / ****** *** **

* * *** if *** * * * * * *
* ** * * * ** * *** ** * *** * * *** **
* *** ** ** * else
****** * ** ** **** ** * *** *** ** * * *** ** **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
**** ** * * *** ** * *** * i;
* * * * ** **** *** j;
** * ** * ***** * newNum1;
** ** ** ****** * ****** newNum2;
* *** ** ** * ** ** **** gcd;
*** ** ** * * * * * ** rem;
** * *** ** * * * num1, num2;
    
* * * * **** * ** * ** *** *** **** * * *
*** *** * * ** * **
** * * ** ** * * ***** *
*** * ** *** *** **
** ** ***** **** ***
* * * * ** * * *** **** * != 0)
* ** *** *** ***** **
** * ** *** * * ** ** ** * ***** ***** * * * * * = j%i;
* ** * ** ** **** ** ***** **** ** = i;
* * ***** * * * * * **** * **** * *** = rem;
* * *** * * *
*** ***** **** * * ** * ***
    
* **** * * * *** * * = num1/gcd;
*** **** * ** * ****** = num2/gcd;
    
* * *** * *** * ** **** * == 1)
* * *** *** ** ** * *
* * *** * * *** * ** * ** * ** **** **** ** **** *** * * * * *
* ****** ** * * ** ****
    
** *** ** **** * * *
* * ** * **** **
** *** ** * ** * ** * *** **** * * * ** * ** * ** ***** ** ** * **
* * ** ** * * * *
    
** * ** * * ****** ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* **** * ** ** * * * ****** i;
* * * ** ** ** * * * * j;
* * * *** * ** ** ** newNum1;
*** ** ************ ** * newNum2;
* ** ** * * * * ** * *** gcd;
* **** * * * * * ** ** rem;
**** **** ** * ** ** * num1, num2;
    
* * * * * * * *** ** * ** ** ** *** * **** * *
** ** ** *** * * ** ***
* * * * * * * * * * **
* ** * * ** ** * *******
***** *** * * * * **
*** * * * **** ******* ** != 0)
* ** * * ** *** * **
**** *** ** * * * * * * *** * **** * ** ** = j%i;
*** * * ** *** *** ** * ***** ** *** * ** = i;
** * *** * **** *** * ** * * * ** = rem;
* ** *** * * * *
***** * **** * *******
    
* **** * *** * * ** * ** = num1/gcd;
* * * *** *** * * * = num2/gcd;
    
* ***** *** * **** * ** == 1)
* * * * * *** * *
* *** * *** *** * * ** ******* * **** ****** * * ** ** *
** * ** * **** *
    
** * ** ****** ** *** **
* ** * * ** * *
* * * * ** * * ***** * **** **** *** * ****** * ** ** **** **
*** ** **** **
    
**** * * * ** ** *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
***** **** ** * * *** * * ** ** **** *** ** ***** **
* ** ** * **** **** * ** **** * * **** *** *** ** *
    {
** * *** **** * * ** * ***** ******* *** *** *** *
* * * * * * * *** * * ** ** * ** * ** ** **
** * **** * ** ** * * * ****** *
** **** * * * * * *** ** ** **
** **** * * ** * * * **

* *** ****** * ** * * * ** *
* * * ** * ******* ** * ** *** ** **** ** ** ** * ***** * **** ****** * * * *** * **
* * ** **** * * ** **** * * ** * * ***** ** * * ** * ** ****


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
** ***** ** ** * *** * * * a,b,GCD;
* *** ** ** * * ** ** ** * * * ** *** **** **
*** * ** * *** * ** ** * * * ****
* * * * * *** ** * * ** **
** * *** * ** ** * ** ** ** *** *** ** ** *** ***
** *** * * ** *****
* ** ** *** * * ** * ** ** *** ** * *** ******** ** * **
* * * **** *** 0;
}
**** * *** * ***** * gcd(int a, int b){
* * ** ** * * * * **** ** * * * * (!b) return (a);
***** ** *** **** ** * * * * * ** ** ** gcd(b, a % b);
** * ** * * * * ****
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * *
#include ** * * ****

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* * ******* * ** **** * gcd, remainder;
* * *** ** ** * * * * ***
* * ** * * * ** * * * (n != 0)
* ** *** ****** * *
* **** ** ** * ** * * * ** ** ** * ***** * ** * = m % n;
***** ** ** * * * * * ** ** * * *** **** * = n;
** ****** * ** * ***** * ** * * * ** * * * * = remainder;
** * * * * * ** *
** ** * * *
** * * **** * ** ****** * = m;
** * *** *** * *
* * * * ** * ** * * gcd;
}
int main (int argc, const char * argv[]) {
* ** *** * * * ** ** number1, number2;
* * * * * *** *** newNumber1, newNumber2;
* **** * ** *****
* *** * * * ** ********
***** * *** * *** * * * * ** * * ** ** ** ** *** * ******
**** ** ** * * * ** * *
** ** * * * ********* ** * *** = number1 / gcd(number1, number2);
*** ** * *** * * ** ** = number2 / ** * number2);
* *** * **** ** * * *
***** **** ** * ** * ***
*** * ** * * * * * ( ** *
** * * ** **** * ** * *** * ** * * ** ** * * * * newNumber1);
* ** *** * * * * ** *
**** ****** ** * *
* * * * ** **** * * ** *** *** ***** *** ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* *** ** * *** * a,b,c,d,e,f;
* *** * ********* * *** * * ** *** ** * **
* ***** * ** **
** ** *** ***** ** ** *
* ** * ** * * *** ** * *
    {
* * * ***** * **** * * ** * * *
** * * * * * * ** * * ** ** *** ** * * **** *
**** ***** * * * * * * ** * * ** *** * ** *
    }
* ** ****** * ** ** ****
    {
* ** ** ** ** * * * * ** * *** * *** **
** * **** ***** * ********* **** ** * * * *** ** * ** ** ** * * ** * **
* * * **** * ** * ** *** ***** ** *** * **** **
***** * *** * * ** ** * * * ** ** ** * *** ** ****** * ** *** * * *
    }
**** * * ** *** *** *
    {
***** *** **** * * * **** * **** ***** * ** * ******** ***
** *** *** ***** ** * **** *** * * * ** ****** *** ****** * *** *
***** * * * ** * * ** * * ** * **
***** ** * ** * ***** ** *** * *** *** ** * ** **** ***
    }
***** *** *** * * * ** * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 17.4k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 17.2k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 22.6k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 17.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users