11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
12.3k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 12.3k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

  *  * *  *    ****   * * *  * **   i;
 **** * *   *   * ** * ** j;
* *     ** *   *  ** * ***** newNum1;
* *     ** *   *** ** * ***** * * newNum2;
*  ******* * * ** *******  * *  * gcd;
***  ******* ** **  **  *** ** ** rem;
** * * **** ** *       * * num1, num2;

      **   *** *** **     *  *   * **     **       * * *      *

 *   **  * * * * * *  *   ***
*** *    *  *   * * * **    * * * 

  * *  ** **** **** *  * *  != 0)
  *  *  ****  **   ***     **
** **   *  *  ***  **   *      **    *** *******   = j%i;
** ***** *  ** ***  *   **  *  * **   **** ***  * *   = i;
* ** *****  * *   ** *   ******  * *   * * *** **  *  *   = rem;
*  * *  *********  *** * *  *
  * *  *  *  **  * ** ** * ** *

**   ******   * *     * * *      = num1/gcd;
 **   *  *  ********* *   *    = num2/gcd;

 *    **   * *   * *    *** * *  == 1)
    {
   ** *    *** ** * **  *   ** *     ***   * **    * *****   **** *** *   *  * * *
    }

  *   **     * *      ***** ** 
    {
**  * *     * *** **** ***       * *  * * *    *  ** * * * *** **   * ****    **** * * *
* *    * ** * *   **    ** *

**     ** *    **   **  *** * **    0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* ** * ** ** ***** ***    * ***** * ***   * *  ** *** ** * * * ***  *    

*  **     ** ***      **  * **    ** 
 * **   **      ***  * *  * ***   **  ***     ** **  *  ****  **** * *** ***   * * * *

    else{
* *       *** * ***     * ****** *    * *  * 
    {
**** ** *** *  *  **   ***  *  ***  **    * *
**  ***   *  *** **   ****    * *  *** * * **  ***   * *** * *  *  *   * *  ***** * ** *   && deno%i==0)
  *    * **  *********  *    **      *  * **   * * ***  * *  *  *** *** *    
*    * * ** ***** * ***   * ****  **   * **  ***** **    *   ** ** *     * ****    ** * *          * *  
****   *  * *         * **    ** ****  *  * ** ** ******** **   **  ****** ** * *****  *  ***** *****
  *  **  * * ** *  * ** ** ***** * *  * * **  *  *  * **    *** ** ***  **     ** 
    }

    *    ***    ***** ** **  **  *   *
    {
 * ***  * ** ** ** * * * **** * **   **    *  * *
 **     * *** **  *  *   *******   **  **    * *** *   * ***   ** ** *   * * *  ** && deno%i==0)
 * *   ***  *  ** ** * *  * * *  ***** ** *  *   ***  * * * *  * ***    ** *   * ** *  *
   **      ****** ** *   *   *    ****** *  *** * **  **       *   ** ** **      *** * ** *  **    * *  
*  *   *  **** **   *  **** *       *   * *  **  ** *   *     *       *    *      **         ** **    *** ******
*   ***   ****  *   **      *     *    *******     ****** ***      *      *  
    }
**    * *  * ****   ***  * ** ****** * *  ** *** *  *  *  *

    }




 * ******        ** ***  *  0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  ***  *** * **
#include         * **    

int gcd(int n, int m)
{
*** * ** * ** ***  * *  **  *      gcd, remainder;

 ** ***** * ** ***   *    *     (n != 0)
 **  *   * *     **      ***   
*** *  **     * *  **   ** *  *** ** ***    *    = m % n;
  *   *   *  * * **  **   * **       *  * ** **  * ** ** **  = n;
** **  * ***  *  **  ***  * *   ** *  **** *  * *  *  * *  * = remainder;
*   **** *****   *  ***  *  *  *

    ***  *****  *    *   *   *     *  = m;

* *  **  *  * **   ** *  *     gcd;
}

int main (int argc, const char * argv[]) {

*                   * ***  * **** number1, number2;
***** **  *    *******      ** newNumber1, newNumber2;

 ***  *** * ** **  ** * **** **  *        ***      *  *   *  *** *

 ****  * **** * **   *  ***** ** ***  = number1 / *** *  number2);
* * *  *  * ** *** **** *** *** * = number2 /     *  number2);

  *  ***  ** ***** * ***   * * **      *    * ***  
   ******   *** ***      ** ** *      *  ** ** *   *       **   
* ** **   **  * *   ****  ** * ***    
 *** * *   * ** * **    ** ***   *    **     ** *  * 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  **  *** ***    **
 * * *    * **** *  ** 

int   *  n, int m)
{
 *  ** *  ** * int gcd,  *  **

**  *   *** *     (n != 0)
    **   * ***  {
 **** *  **  *  ** *  * *   * *   ** * = m % n;
***    *       ***   * * m = n;
 *  * ** **    *   ***   ** *** n =    *
** * ****   **     }

* **  * * * *  gcd = m;

******  * * *  * *  * ** gcd;
}

int main (int **     * char * *** * {

** *  **   *  **  int *** *    * *
   **** *** *  int     **** *  *  * 

***  *** *   *** ** * **  * * **  *   **     *      **     *** 

  * * * * ** *  ***   =  ***  /  * **   *  **** 
 ***  ***  *   *** * ** ** =  *** * /      *** *  * 

  **  *    *     if * *    ********  ** *
** **   ** **  * * **    ***   *  *  *    ***  *** *
*****      *** else
*****   ******   *     ** * * ** * * ****** ***  * 
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
     ** * **    ** *   * * ** i;
* *   * *   *  *****    ****  j;
 *** **  ** *** **** ***      **   newNum1;
 * *  ** ** ***  * *    ****** newNum2;
  *** *** **** *    * *   ***  * gcd;
****  ***      **  **   ** *  rem;
  *  ** *   *    * *  * ***    *  num1, num2;
    
** **  *** * * ***  ** **  *  *  ** * *  ** *   *  ****** * ****   *  
    ***  * *  *  *     
 *     * ** * * *  * *      
 ****   *  *** * * ** *    * * *  * **
 * * * *  * * **  ** *** 
* ** ** *   **      * **  **  **** != 0)
*    * ** *  * **  **      ** 
  ** *     * **  * ***  ***  **   *   ** ** ***** * *  = j%i;
*  *  *** ****   **    ***   *  * ***   **   ** **** *  ** = i;
*** ** * * *   ** *  *  ***  *  *  ** **  ***    ********   * = rem;
* *  *  *  ***     * * ** 
*       **** *  * * *** ** ** * 
    
* *  * *    *   * * * *  *    * = num1/gcd;
*** * **** * *   ** *   * **    * = num2/gcd;
    
 *     * **    **     **  *  * * **   == 1)
*   ** ******* *** ** * 
** * *     *****  *  **   *      ** * ***      * ** ***  **  * *     *   *  
*     * ** *** **  *   *   ** *
    
   ****   ** ****  * **    
**** **    **** *  ** *   ** 
* ********* * * *  **  *  ** ** *    ******* ** *  *****  **   * ***   *****  **
**  *** * *  *    * ** *** *
    
**  **** ** ** ****   * *   0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 * *******   **  * ***    *** i;
  **  * * ***** **   *** *    * *   j;
  ***  *** ** **** **  *     newNum1;
**** *****    ***  *   ***** newNum2;
  **  *** * * *  *   *******   gcd;
**          ** **** **** rem;
 * * *  ** * ****  *    * *** * num1, num2;
    
 ** *    **** **** **    *  ** ***   * * *** *** **  ** *   * *  *
*   *****  ** *   **** **    * *
*** **  *      *     **   ***
* * ****   **** *  *** *  **     *
  *** * *   *   *     *****
  *  ****  **   **  *  *******   != 0)
 ** **    *    * * * *  ** * *
* ***   * *  *  ** ** ***** *  * * **** * *** *  **  * = j%i;
*   ***  * * ***** *  ** * *    **   ** *  ** * * = i;
      ***    **     *   *   * **   **      * ****      * *  = rem;
    * ***  * **  **** *   *   
* ** *  ****   * *    * ** *  *
    
***    * **  **  **** *  *    ** * = num1/gcd;
* * * **  *** *    *   ** * *   * = num2/gcd;
    
*    **      ** **  * ***  *      *  == 1)
**   *    **  *   * ** **  
  **  * *  ** ***   *      *  *   *   *   ***  * *  *****     *  *****
*   *******    *   *  ** **** 
    
** ** *   ** *  ****       
****  *   *  ** *     * **
  ****  * *  **   *  *   ** * *  *   * *  ** *  ** ***   *** ** * *  ** *  **** * * *  * 
  ** * ****   ** **    ** 
    
  *   * * ***  ***  ***  ***  *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
   ** *** *** ** ** *    **** **** * ********  * **** ** **   *** 
** * * ****  ** * *     *  ***** * ***     **    ***    *  * * * 
    {
*  **  * * * ** **   *     ***  ****** **** * * * ** ** * *  * * ** 
 *** *   ***  *  ****   **    * **  **** * ***    *** *  ** * *    ** *
* *   *  *   * ***  *    *      * ** * *  * 
  *** *** *   ** ** *  * *   * *** * * **
 ** ***** *  **   ** *   *** *    *******  **** *

** * ** ** * *  * ****** ** *
***** *    *   *  ********* *****  *  *  **  *******  * *** **  * ** * ***  *** * * *** **** *   *** **   **
*   *   *   ** ** **** *  *  *    * * ***   **     ** ** ** *   * *   * **   *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
     *  *** ** *   ***  *  *   a,b,GCD;
* *  *   ** *   **   * **  * ** ****     *** ****  * *  **   * ** *
 **   *** ** ** *  *     ***  *****
*  **  **  *****    * *     * *       
** * *  ****** *    ***   * *   ** ***      *  ** ***  *   *  **
 ****** **** *** *    ****    * 
** ** *** * *   **   *  * * ***     *  *  * ****    * *** ***   * *    *   **
 * *** **** * *      *** *   * 0;
}
***    *****     ** *  ******* gcd(int a, int b){
  * ** *** *** *  * ***   ** * ******  *   ** ** * *** (!b) return (a);
      *   **** ******         ****  ** ** ** ** **** *** gcd(b, a % b);
**    **     ** * *** *  *   **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ****** * *** **** 
#include   * ** ** ** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
 * ** ***** * **   *    * gcd, remainder;
  * ** ** *  *     * *   ***
*  **   **** * * *** ** **    ** (n != 0)
 * *   *          * ****
**  **    * ****   * *    ****    * * ** *  ***** * *    ** = m % n;
   ***  * * * **** **  ***     **  *  ****   ****    = n;
   ** ****    * ****  * * **  *****  *     *  ** **  *** = remainder;
*   * **** ***  **   **  **
   * **    ***   **     *
*  *** *    ** * * *** ***   = m;
          *   * ****  *  * ***   
**  * **      ** ***  **  * gcd;
}
int main (int argc, const char * argv[]) {
* *   ***  ****   *  * *     number1, number2;
*  ******* *     ** * * ** **   newNumber1, newNumber2;
**  ** *** * *   * *  *   **
 **         ** * ****** *
*    * * *  ***** *  ** *  **      **** * **** *   * ** * * *   *  ***** 
 **   ***   * *    * ******
   **    ***  *   ***  *** *    ****** = number1 / gcd(number1, number2);
** ** * *** *     * *  **  *    ** = number2 /  *** * ** number2);
* *   **** ** *    *  *
  ** *****   *   * ****** **
*  * ** **** *     * **   ( * **   **** 
**** * ** ** **** **     *  **    * * *  ** **** *  ****    ***  *   * newNumber1);
*  *  **   ** *   ****  *** **
*       ***    ** * * ** *** 
* *   *  ***  **  ** * * *  *   * *  *** *  *  newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
   **  ***   **           ** a,b,c,d,e,f;
 **   *   *  ** *   ***  *****   ** **    ******** ******* **
* * * **  *   *    *   * ***
***** * *  **  * *   *****   
 * ***   *  * ****    ***  *    **    
    {
    *  *   ** * *  *  * *   * ** *  *  *  *** * **   ***  
    * ** *  ** *** ** **   ** *   **   **     ** * *    *
  * ****   ****** **  * *  *** *   **  **  *  * ** ** **
    }
*  * *    * ***  *  *** ** ***   *** *  *
    {
*   *****  **  **    *   **** *         ***   * *   ****   
      ** ******* ** *** ** ** * ***** ** **   *** ***** *  *  ** *  **  **
* **** ***  *   **   **   * * * ** * *  ** * *** *
* *   **   ** *  *** * ** ** *  ***   *  *  * ****** **    ****  **  ***    **   **
    }
 **  * *   *** * ** **    ** 
    {
** ******* *   **       **  * * *   *** ***** * **
 * *  *** **   *  ***  *   ** *** * * ***  ***   * ***** **   * ** * ** *   *     * 
***  *** **   *  * *** * **   **  * * *       ****   *     
 * *  *  *    ** **   *   **** *** *** * *** ** *  * * * ** **** ** **      *  *   *
    }
 **     * ***    * ****** *   * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.81
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 12.4k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 12.3k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 15.6k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 11.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users