2 like 0 dislike
8.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 8.9k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

*** ****** * * ** ** * * * * i;
*** * * ** * * *** * j;
* ****** * * * * * * newNum1;
*** * * * * * *** * * * newNum2;
** * * * * * * *** gcd;
* **** *** * *** ** ***** * rem;
* *** * ** * ***** ** num1, num2;

** **** * * * * * * * ** **** * * * * *** ** * * ** * **

******* ****** * * * * *** *
** ** ****** * ** *** *

* ** * ** * * * ** * * * * * ** != 0)
* ** ** * * ***
* **** * * * * * ** * ***** ** **** ******* = j%i;
** * * ** *** * * *** **** *** * * ** * = i;
**** ** * * * * ****** **** * *** ** ***** = rem;
* ***** * *** *** * *
** * * * ********* * ** **

* * * ** * **** **** * * * = num1/gcd;
** * * * ** * ** ** * ** = num2/gcd;

* ** * *** *** ** ** * * == 1)
    {
* * * ** **** * **** * *** ** **** ** ** * ** ** ** *** * * * *
    }

** * ** ** *** ***** ** ****
    {
*** * * *** ** * ** ** ** * *** * * * * * ** **
* * * * * * **** *** * *

* ** *** * * **** * *** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** * ** *** * * ***** *** ** ** * * * ** ** *** ***

* ** * ** *** ** *** * ** **
* * ** * * * * * * * * *** ** ** * ** **** * ** * * * * * * ***

    else{
* * * * * *** ** * *
    {
* ***** ** * ** ** * * * ** *
* * ** ** * * ** * * ** * * **** ** * * * * ***** * ***** && deno%i==0)
* ** * ** *** * ** **** ** * ***** * * * *** * ** * * * * **
****** **** * ** * * *** ***** * * ** **** ** ** *** * * * * *** * * * ** * * ** ** * * *
* * * ** * *** ** ** * *** *** ** *** ** ** * * * * ** * * *
** * * * *** ** * ***** ** *** **** *** ** ** * * * * ** **
    }

* * *** ** * ** * ** ** **
    {
** * **** * ** * *** * * *
*** * * * *** *** ** * ** * * ** *** ** * * * *** * * * * * **** && deno%i==0)
*** ** ** **** *** *** **** * * * * *** ** * *** * * * * **** ** ****** *
*** * ** *** * * * * ** ** * ** **** ** ** * ** *** * * *** * ** *** ** *** *
* * **** *** ** * * * *** * ****** * * ** * ****** * ***** *** *** * * *** ** *
****** ** * * * * ** ** * * * * * * *** * *** ** * * ** **
    }
*** ** * * * ** *** *** * * *** * ***

    }




* ** *** *** * * * * * * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ****** *
#include * ****** ** **

int gcd(int n, int m)
{
* * * *** * * ** * *** *** gcd, remainder;

* * * * ** ** * (n != 0)
**** ** * * ******
* ***** * *** * ** * * * * * *** = m % n;
********* *** ** * ** *** * ** * * * = n;
* ***** * * * * * * * * * ** * * * *** = remainder;
* * * * ** ** * **

***** * *** ** ** ** = m;

* * * * * *** * * * * * * ** * gcd;
}

int main (int argc, const char * argv[]) {

*** * ** * * ** ** ** * * number1, number2;
* * * * *** ****** ** * * newNumber1, newNumber2;

* * ** *** *** * ** * ** ***** * ** * *** * * ** ** * *

** ** ** ** ** * * **** * * * = number1 / * **** number2);
** ** * * * **** * * * = number2 / *** * number2);

** * * ** * * * *** ** * ** * *** ** *** *
* ** * * ** *** * * *** * * * *** * ** *** * *** ** * * * ** *
* *** * * **** * **
*** * * * * * * ******* * * * ***** *** * * ** ***
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
** ** ******* **
****** ** *

int *** n, int m)
{
* ** *** ** int gcd, * *****

**** ** * * ** (n != 0)
** * ** * * * * * {
* ** *** * ** * * ** * * = m % n;
* * * ** * * ** **** * m = n;
** * * ** * ** n = * *
*** ** * ** }

* * * * * gcd = m;

** ** ** * ** gcd;
}

int main (int ** * char * * {

**** * ** int * * ** ** **
* * * * int *** * ***

* ** ** ** * * * ** * * *** **** * ** * * * ** **

* * * ** * ** = * / ** * * *** *
*** * **** * ** ** = * / *** * * ***

* * * * if **** ** ** *
* ** * * * * * * ** * * * ** * * **
* * *** ** else
* ** * * ** ** * * * * * * ** * * ** ***
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ** * ** ****** * * ** * * i;
***** **** * * * ** *** ** * j;
*** ** * **** * * ** newNum1;
*** * ** * *** * ** * newNum2;
* ** **** ** *** * gcd;
* * ** * ** * * ** ** rem;
****** * * * * * * * * num1, num2;
    
** ** ** ** *** *** * * * * * **** * **** * * **** * ****** ** *
** ** * * *** * *
* * ** * * ** *** * *
* **** * ** ** *********
* * * ** * ** ** *** * *** **
* ** *** * * * ** ** != 0)
* ** ** *** ** **
** **** * **** *** ** * ** ****** * * = j%i;
*** * ** ** * ** * ***** ** ** ***** * = i;
** ** * * * ** * * *** * * * ** ** *** = rem;
**** ** ***** * ** ** *
* *** * * ** * *
    
*** * *** * * * = num1/gcd;
** * *** * * * * * ** *** * = num2/gcd;
    
** * * *** * * * * ** **** == 1)
*** ** **** *** *** * *
** * *** * * * * ****** * * * ** *** * * ***** * * *** * *** ***
** * * * * * * *
    
* ****** ** * **
*** ** **** * *** ***** *
* *** * * ** * * *** ***** *** ** * ** * ** *** * *** * ** * * * ** *****
***** *** ** ** * *** * * **
    
***** * * * * ** ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
******* * * * * *** * ** * i;
* * * * * *** * * ** j;
** * **** * ** * **** ** * newNum1;
** *** *** ** *** * **** newNum2;
**** * * * * * ** * ** gcd;
* * ***** *** *** * * ** rem;
* *** ** **** **** ** * ** * num1, num2;
    
* *** ***** * ** * *** ********** * ** * * * *
* * * ** **** ***
** ***** * **** * * *
** * * * *** ** * * *
*** * * * * ***** * * *** **
* *** * * * * ** ****** * != 0)
***** * * ** ****** *
*** * * ** **** * *** ** * * **** * * ***** = j%i;
* ** ** ** ** * * **** * * * ** ** * * = i;
* ** * ** ** ******* ** * ** ** * *** ** * = rem;
** * * * ** ***** * * *
** * * * ** * ** * * ***
    
* ** ***** ** ** **** * *** = num1/gcd;
** ** ** * * * ** * = num2/gcd;
    
* *** *** ****** *** * == 1)
* *** * ** * ****** * *
* * *** * * ** ***** **** * * *** * * ** ** ** ** * * *
**** ** ** * ** * * * * *
    
* * * ******** * **
**** * ** ** * * ** ** *
**** * ** ** * ** ** * ** * * ** ** ** * * **** ** ***** * ** * * * * ***
* * ** * * ** * **
    
**** *** ***** ** * ***** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* **** * * *** *** * *** ** * * *** ** * ***** ** ** *
** ** * ***** * * *** ** *** * * * ** **
    {
* * *** **** * * * ** * ** ** * * *** ***** ** *
* * *** *** * * * ********** * * * * * ** ** **
** ** * ** * **** *** *****
* *** **** ** * * * ** * * * *
*** **** * * * * *** ***

* * * * ***** * * ** ** ***
* * * * ** * * **** * ** * ** ** * ** ** * * ** * *** *** * ****** * **
* * ******* * * ** *** ** *** * ****** *** ** * ** * * ***** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
***** **** ** **** ** ** * a,b,GCD;
* * * ** * * * *** * *** * ** ******** *** ** * *****
* *** * *** ** * ** *** *
* ****** ** * * ** * ** *** *
* ** * * * ** * * * ** * ***** * * *** * ** * ** * *
* **** * **** **** * * **
* ** ** ** * * * * ** *** ** ** *** * **** * **** * ** **
* *** *** **** * * * * * * * 0;
}
* * ** *** * * *** * gcd(int a, int b){
* *** *** *** * * ** ****** * * * ** ** (!b) return (a);
******* ** **** * *** **** * ** * * * gcd(b, a % b);
** ***** * * * ** **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ******* ** * *
#include ** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
*********** *** ***** gcd, remainder;
** *** * * *** * *** * *
* ** * * *** * ** * ** ** (n != 0)
****** * *** * * * * * *
** * * * *** * * * ** * * ******** * * = m % n;
**** *** * ***** * ** * ** * * * * * * * = n;
**** ***** **** ** *** ** **** ** * * * * ** ** * = remainder;
* * *** * * * * * *
* * * * **** ** * ** ** *
* ** * ** * **** * = m;
** ** *** ** * * * **
*** **** *** ** * **** * gcd;
}
int main (int argc, const char * argv[]) {
*** ****** *** ** ** ** number1, number2;
** ** * ** * * * *** * newNumber1, newNumber2;
* ** ** ** ** *** * * **
* ** * ****** * * * * * ***
** * ****** ** *** ** **** * * ***** * ** * * ******
* ** *** *** * * **
* ***** * ** ** * **** ** = number1 / gcd(number1, number2);
* **** * **** *** ** **** * * * = number2 / ** * number2);
* * * * * *** ** * ***
** * * ** **** ** **
* *** ** * * * ** ******** * ( *** ** ** **
** ** * * * * **** * ****** * * * * ** * ** * newNumber1);
* * * * * ***** ****
*** ** * ** * ***
* * *** ***** * * *** *** * ** *** ** ** * * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
**** * ** * *** ** a,b,c,d,e,f;
* * * *** ** ** * **** *** * **** * * * ** ***** * **
* * ** ** * **** * ****
* * ** ** *** * *** * *** **
* * * *** * ** * *** *
    {
* * *** ** * *** * * * * **** * * *
* ** ** *** * ** * ****** * * ** **** * **
* *** ****** * *** ** ****** * * * * ** * *
    }
** *** * ** *** * * ** * * * * *
    {
* ** ** * * **** * ******* ****** * *** *** *
***** ** * * *** * ** * * * **** *** **** ***** ** ******* * ** **
** * ******* * * * ****** *** ***
* *** *** * **** ** ** ** **** * * *** ** ** * * *** * *
    }
** ****** * **** *** * * **
    {
********* ** ** * * *** * ***** * *** ** * * ****
* * * *** * * ** ** ** * ** ** ** * * **** * * ** *
*** *** *** ** * ** * * * * * *** * * ******
*** ** * **** * ***** * * ****** * * *** **** ** *** **
    }
*** **** * ** * ** * * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.1.188
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 9.1k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 8.7k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 10.9k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 8.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users