11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
8.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 8.9k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

 *       * ** *  ***   i;
      **   **  *     ***   ** j;
*     *** *   *    *  * *     *  *  newNum1;
   **   *     * *   ** ******* newNum2;
 *  *     *        *  *** gcd;
 **  ** *  *       * *** ***    rem;
*    * ** *  * ***  ***  ***   ** num1, num2;

  **  ***   * *   **   *****  *   *** ***  *** **** **** *** * ***   * * 

* *  * **  ****  *******  ** **
* * ***  **   *  * ***  *    **   

**     * *  **  *  ****     * * != 0)
*  ** *****  **  * * *    ** 
*  * * ****  *** * * **   * *     ***  * * *   **** *  **     * = j%i;
 *** ***     ** * *   * **** ** ** * ****  *  * * *    *    = i;
*  *  * ** **  **** ********* *  * ****  ***  *** ** ***  = rem;
** * * * *** *  ***** *
   *    *   * * *    * *** *  * 

 * **** ** *       * * *   * **** = num1/gcd;
* *  **   ***    ***** **  ***  = num2/gcd;

*  ** *  * *  ** **** * *  **   ** == 1)
    {
   * ** *  *  **   ***  ** ** * *  ***    *** * **  * * *  ** ******* 
    }

** * *  *    **   ***    ** **
    {
 *  *   ** *  **** *  *** * ***  *** *  *       *    * ***** *** *     ****  *  
** *        *** ** ****** * ****

** ** * **** * ******        ***   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
*** ***  * ** *** *   *  ****   *  **  * **  ** *       **  *        

**  *** * * **** * *   ****   ***  ** 
    **  * * *  ***      ***  * *  * * ** *  *  **  **  *  **  ** * *    *  * **  * ***

    else{
***  * ** * * * **** *  **  *  **  *  **
    {
*     **** *  * **  * *** ****  *  * *  *     *  * 
*  **  **  ****   ****** *   * ** * * *****  ***  ***       ** *   *   ***    *  *  * **  && deno%i==0)
    *  * **** ** *** **  *   * * ***  *  ****** *  ******* ** * * *   **    ** 
*** **** * *** **** ****  *** *** *   ** * * * ** *** *   ** * *   * * *******  **  * ** **   *  ** ***  ****
**   *** *   * ** * * *** *      *  * * ***  **    *  ** **** **  ********** *** *  ** *  ***   ** * ** *   *** **
**** * **   ** *   ** * ** * *** **  ****   * *  * ** *  * **    * * *  * ** * *
    }

*** *** * ** * ********    * **     * ** ** *
    {
 ****  *  *** ***** * ** **** * ***  
 ***  * *  ** *   * **    ** **  ****    ***** ** *  * ** **    **  ****** *     *    **** && deno%i==0)
*      **   * *****    ** *    * ** * *   *   *    *  **  *   **** ****  ** ***  * *** 
*** *   * * *     * ***** ** * * * *** ***   ******  ******       ****     **  ** *  *** *   ***** * ** *
* * **** *  ** *   *** *    * **   *  * ** ***** ***** ** **  ** * *   ** * *  * *  *** ** ** **  * **** *  
** * ** ** *** ** *  * *****   *   *** ****** **  *** *    **   **** ***      * ******** ***
    }
  *** **  **    ** * * * *    *   ***  *  * * * * **   **  

    }




  **** *** * * * * *** **  * ***  *    0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     *     ** **  **
#include ** *  ** **  *   ** 

int gcd(int n, int m)
{
  *  ******   * **   **   gcd, remainder;

* **  * * *  ***  *   *  *    *  *  (n != 0)
* *  * ** **** * ** * ***   
** **  *    ****     *  *  *  *   * **    **  ***  *****   = m % n;
  *  ****     *   **    *   **   **** ** *  * ** ******    ** = n;
**   * **   * ** *    ** *     *   *  ****  *  * ** = remainder;
  **  *   *   *  *  *  ** 

*   *   *     ***       **** * * = m;

    ** *  ******    **   *  * *  gcd;
}

int main (int argc, const char * argv[]) {

* *   ***   *****   * *** *  * number1, number2;
*  ****    *** *** **   *    newNumber1, newNumber2;

 **  ***     ***   ****  *   *  * *    ****  ** **        **** **   ** *** * **

** * * * ***      * * ***  **  **** = number1 / **   *   number2);
 *    ***     * *** ** *   *  = number2 /  ** ** *  number2);

     * ***  ** * *****   **** **  *** **  ***  ** ***
** ** * * **** * **** *   ***  ** ** * *   *****      * *  **    ** 
   *  * * *   ***  * *    
 * * ********   ********  *  ** *** *  **** ** **    ********  
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***    * *******  
*** *  * *  ***  *****  

int  * * n, int m)
{
**** **  *    ** int gcd,  ****

 *     ** ** * *     *  (n != 0)
     **    * * *  {
* * **    *** ** * *  *  * * * **   * = m % n;
*   * * **  ***** * ***  * *   m = n;
  *  *      ****    *  * ** * ** n = *     
****  * ** *  }

* **  *** ******   gcd = m;

  **     *** * *   *  gcd;
}

int main (int   *   char * *   {

  * * ***  ** int  * *  * *** 
** **  *  *     *  int    *  *    *** * 

 ** * **   *** * * *  **     * *  * ****** *  *   * *  

**     *           *  *   =   *  /   ****  *  ** **  
* *  *  *    *  *      =  * * /   *****  * ** ***

 * * ** * *** * if *  *  *  *  * ***** **
**    *   **  *   *  *  *        *  *  * * *** *****   *  *  *
* * *  *  ** * else
*** **       ** ***  *    **  *  ***      ** *  **** *** 
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
***  *  ** * **   *       *  i;
 **** *  ** * *  * * ** * * *   * j;
* * * *** ** ***  *   **  ***   * newNum1;
* **  **      **         * *  *   newNum2;
* * * **** * *****  *** ****  gcd;
* *   *  **    *** *** *** rem;
***  ** * *  ** *  *  * *****  num1, num2;
    
 *** *  *  ***    * * *  ** *   *   **  *  * ** ** *   *****    ** ** 
*      **       *  ****
  *  * *   * * * *   **** *  * *
*   ** **** * ** *** **  **  * * * 
 **  ** *****  **   **  *   **
 * *  ** **     * *** **  **    != 0)
* ** ***  *  ***   * ** 
 ***  **  * ***   * *  ***    **  *     ** *  *  ******  *   = j%i;
 *****      *   ***** * *   *   *  *  * * **** = i;
*****  ******  *  **     * **    * **** **  *   *        * = rem;
  *  **    ** *** ***   *
 **      **  ** ** **    *    *
    
*  * **  ***  *** * *    *** *****   ** = num1/gcd;
  * **** *  ******** * ** * **   * ** = num2/gcd;
    
 **  *** ** *  * *     **  *****   ** == 1)
*** * *  * * * ** *****
*  * * ***  *****  *   *   *  ** **** *  *     ***** *  *  ** **  **  * *  **** **  ** 
*  **   *  *  *  * * *      *  *
    
  * **        ** ***  ** *  *
* **     * *     **       
* *** *   * *  ****    *     *   *  * **   * **   *  * *  **   *  * ** * *  * *  
      ***   * ******  *  *****
    
*     * ** *  *****  *  *  * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
** ***  ** ** *** **   ****  i;
  **     ** **    **   * **** j;
    *     * **   *  **  newNum1;
*** *  ** *** ** *  * ****  * newNum2;
 ***  * **  ** *   ******   gcd;
*** ** ** * * *** **  ***  *  rem;
  *** ** *  *    * *   *** * * num1, num2;
    
 ** ****  * * ****      ** *  * * **  *  ***  **  * *    *   
**   * *  * * * *    *
*    *   **   ** * **  *** **** 
* **  *  * *   **  *** *  
  * **  **  ****   **   * *
****    *    **  * ** * * *  ** != 0)
  *****      *  **       *  *
 *  *  *  ****  * * * **    **  **   **     *** *    ** ** = j%i;
 * * *  ** * * *** *   *      * *  ** *  * **  ** = i;
 ** * *  *   ** ****  ** **  * * * ** ** * ** ** * *** * = rem;
 *  * *   * **   ***** **  
* * * * *  *   * ** ***  **** 
    
 *  ** **  **     * *******    = num1/gcd;
****   * * *** *     *** * ****  = num2/gcd;
    
* * *** ********          * *   * **  == 1)
*** *  * *   * * * ** * ***  *** *
   *  ******   ***   * **      * *   ** * ** * ***  *** **  *  * **** *  *      ** **    *
 * *  *** * **  *  **  * **
    
**  **** ***** *** ******* **** *
*  * ** *  ** *  ****** *****   * *
**    *  *** ** *       * *  * *** * ***   *  *  *  *  *     ** **  ***  **  ** **
    *  * **  *********   ** **
    
  * *  **** ******* * * ***** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* * *** *  ** *  *  *** ******    ** ** *     * ***   **  * ** 
    ** *       * ** ***      *   * ** **  * *** ** * * ****** *
    {
      **   ** ***  * ** **   *  *  *   * *     *   ***     **    **** * 
 ***  ***  **  ****** ***  *  * *     * *   ** * * *********
*  **  *  *   * ***   **  * *   ** *  *
******  ***    ****    **** ** * **   ***   *
*****  ******  * ** *  *  *    ** *** * * ***   *  *

      *  * *    ** *   **  * 
***  **** * *      * * ** ** *  ******    *     ***  *    * * *       **** * ***  * *** *** ****  ****
  *  * ***  **** *  *** * ** *    ** * *** *    *     **  * **** **** 


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
   ** ***  *  *    * ** ***** a,b,GCD;
 * ***  * ****  ** ** *** * * *** * *   *  **  *  *     * 
   *   * *  * * * * ** **   *      * 
*****  * * * **   *   * **** *   * *  
 * *   * *  **** **   ** *  * **   *  *** *  * **    ** ** **** * * 
** * * *****        * * ****   * 
**     *** **       * *    *  *** * * **  ***** **   * ** **  **    *  * *  **** **
   **  ** * ***** *  *  * *** *  0;
}
 *       ***    * * *  ** gcd(int a, int b){
****   **  * ** ********** *** * *    **** *   ****  (!b) return (a);
  ****** * * ** *** ***** *    *  * * *****   ****      gcd(b, a % b);
 *   ***   *  *   * * *  *  **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** ****   ** *
#include  **   *** *  * *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* ** * *  * * *     * *  ** *** * * gcd, remainder;
   ** ***   * ***  *  ****
** **  ** **   * * * **   **     (n != 0)
******** *****      ***  * **  
 ***** * *  *  *  * *** *    *    * * ** * * ******* * ***    = m % n;
   **   * **        *  ** *     ** ** *   ** * **  ***  *** **** = n;
  *** **  ** **     *  *  **** **** ** *  * * * *  *** = remainder;
 * * * ****  *    * ***  **
 * **     **   ***    *  ** *  
* * *  *****  ******  **** *   *  = m;
* ** ** * * *  * *** **  **** *
 * ** *  *** * ****** *   **   gcd;
}
int main (int argc, const char * argv[]) {
* * * ***** *  ** ****   ***  number1, number2;
*  **    *   * * * * **     newNumber1, newNumber2;
* *   ***   * * ***  ***  ** *  
  **   **** * *******  *   ****
*** * **  *  *     *   ** ** * * * *  * * *** ***  * ** * * * **   **    *
************** **    *  * *  *
**** ***** *   * **  * ** ****  = number1 / gcd(number1, number2);
* *    **     *   *   * * *    **** **   = number2 / *        number2);
**** ****** * *    **  ***** ** ** 
  ** **  ** * ***  * *  *   
         **  *  *   ** ***   *** ( ** * * * *
 ****  *   *******   *   ****** **  * * ***   *    * **** *** *  *  **  newNumber1);
*   ** * **  * *  ** ****     * * 
 *   **   *    *** ** *****
****  * **      *********** * * **  * *   ** *  ** * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
 *** * *  *  *** *  *  ** * ** ** a,b,c,d,e,f;
***   **  *  * * *  ** ***** *** ****  * * *  * *  * *  ** *  ***
  ** * **    ** * *   *  * * ** 
* **    * *** *   * ** ** ** **** ****
 *** * * * *** * *** *  **   ** **   **
    {
**** ** *****   ********  ** *** *  *       * * *** *   *
    * ***  **   * * ***  * ******** ***  *   ****** * 
**  *  *    ***       *  * *  *  *    **** *     *  ** * 
    }
**  *  *** *** * * * *   *** *  ***   
    {
**    *   *****      *  * *   * ** *  *     ***   *   ** **   
 ** **  *** **       * * *  ** * ***    * **    *   *      * ** *** **  * *
 * ***** *    ********  *** * *** *  * **    ******         
**  *   **  ** * *     ****    * * * ***   *   **   *   * **  *   ** * * * *
    }
*    *  *    *     ** **  * * *
    {
 **  * * ***** *****       *   *   ***  **** * * *  *       
**    *     *  * **     * *  * *   *   ********** * **** ******    *  ** ***    
 *   ** * *  **   ** * *  *  *   ***  **   * * * * *  * *   * *
****  * *****  * *    *** * *   *** * *  * ***  * *******  ****  ** *     *   **
    }
** *    * *** ****   ** * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.1.189
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 9.1k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 8.7k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 10.9k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 8.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users