11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
13.6k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 13.6k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

 **  ** *    ***     *   i;
 * *  *** **  * **   * ***  j;
* *******    *  ****** ** **  newNum1;
*   *** *** *   **  *  *** newNum2;
*  * * *    **   *  *  *** *** gcd;
*   *** **    * *  * *   * **  rem;
   **   ** *    ******  ** ***   num1, num2;

 ** *  * **    **  ****  ** * *  *   * *  *** *   *  ** *** **  *     *** * 

***    *  * *  * * *   * *   ***  
  * *  * ** **   ****     *  **

***  **  ****   * ** **  * **   != 0)
* * *   **  *  *  ***** **
 ***      *** * *   *  ** **  *   ** * ** * * ***  *   ** *  * = j%i;
 * **   ** *    * *  *  ******* * ***** *  ** ** *   ***** = i;
** *  *   ** * *  *  * *  ***    * *    **   ****      **   * * = rem;
 * * *  **    **     *****  ***
** * * ****  *    **   ***  * **

*  **   **  * *****  **** *  ***  = num1/gcd;
    ***           * * ****  *  *** = num2/gcd;

  *  *  *  **  * ****  ****  *  *** == 1)
    {
* * * **  *     * ** *  *     * *    ***   **   ** *** *******   **  * *** 
    }

 ****   * *   * ****   **  * 
    {
* * * **  *  *****  ***  *  ** ** **      * *    ** * ** * **  * **** *  *      ****   
 *      ** *  *** **   *  * *

** ** * *  **** *** * * *  *** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
*    *** * ****   * **   * *   *  *  *  *    ***    *** *   ** *  *  

 *** *     *  ** **  ** *****  *  ***
**   *   ****  **** ** ******* ** *** *     *  * *   * ********  * *  * * 

    else{
   ** *   *   *  *   ***  **  * **   *  * 
    {
**** ***    *   **   *** ** *** ** * * *
****   *     * ** * *   ** * ****  ** **  **   *** *   **   *  * *****   ****  * **  **** *   && deno%i==0)
*****   * **  * *****   *  *** ** *  *** **** ** * *** * * **  *   *****   *    
* ** *   *   ****** * *  *  ** * * ****** ****  *** * **  * * * *  *** *** * *  **   * **  *  *  * *****  * ** 
* *  *   * * **  ****    **    ****  * *   *** *     *    ** * * *   ***     * * *      **  ***   **** **** **  ** 
 * *   **  * ********    ***  *  *** ** ** * * * **   *  *    ** **    * * *** * **
    }

 ** **   *   ** * * *        ** * *    
    {
**  ****     **  ** ***        *    ** ***  * * * * 
   *    **  *  * *****    ***** ** *** ***         *   ** * ** ****    ** ***   ****  **    && deno%i==0)
 *** *** *  ***  *  ****     *  * *    *  * ** * * *** * *****  **  * ** ***      *   
* **  *     ** * * *** **   *****  * **   *  **     **   *** ***   ******* *  ****   * *  **  * * *      
 * *  *****  * ** ***   **** **** * * * * *      ***   * ****  ** **** ** *       * * *  **** ** * ***   ** *** 
 *  **     **  *** *  ** * **       ***  *  * *  * ***  ** *  **** ***** *  * 
    }
*  * *****     **  ** * ****  ***  **** ****  * * *  ***** *

    }




*  **    ** ** ****  * ***   * *  ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include      **  **   ***
#include   *  *  *  *** * 

int gcd(int n, int m)
{
 * *** **   ** ** **** * * gcd, remainder;

    **    ** ** * * * *  * * *** * (n != 0)
*** *   ** *  **** *    ***  
    **   **  *  ** *  * ***     * * ****   *  **   *  **  * * = m % n;
* ***  * *******  *** ****   *     **   *  * *  **  = n;
   **    ****** * * ** *** * ** **** ** ***  *   * * * = remainder;
 *  ***** ***    **  *   ****  **

 * *  *** *** * * * *    ****  *  = m;

*** **  *  **       *** * *   **  gcd;
}

int main (int argc, const char * argv[]) {

******* ****** * *  * *** *** *  number1, number2;
**   ***  ** * * *  *** *     * newNumber1, newNumber2;

  **  ** *    * **** ****   * ** ***  *  * **** *  ** *  **** * *   * **** * *

    *     **** * *** *      *    *   = number1 /   *  **** number2);
* ***   **  *    *   ** **     ***   **  = number2 /   * **  number2);

* *       *  ******    **  **** ** * ****   *** 
 ***  *  * * * *  *** * ****    **** **   *   **** **  * *   * *  * 
** ** * **    *** **  * **
*  * *  ***   * **  *** *   ** * * *   *** **    * *   
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*    *  *  ***  * * *
**   *        *  *  

int   *  n, int m)
{
** ***  * *  * ** int gcd,    * ** 

*    **   **   *    * * (n != 0)
* **  ***  * {
*  *  *   *** * ** ** **  ** * *  * * * = m % n;
 **  *  **      ** * *  m = n;
 *****       *   *****  *     * n =     **** 
    *   * **    }

 * **  ** * ****  * gcd = m;

**   * * *** *    *  * gcd;
}

int main (int  * *    char *  *   {

* ** **  **     int ***  * ** **
 * **     *  * int *** * * *  *  

 *  **     * ** * * **  ** ******* ** * ****  * ** * * *  *   ** *   

  * ***  * **** *****  = *** *  / * ***  ** *   *  
 *      ****    *    **  = **** * / * *   *  

   *      * *  if * ** ******    *
 *  ***     *   ** **   *     *    *****      *    * 
* *  * ** * * * else
  **      **** **    *** **  **  **  **** * *** ****  ** * * 
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 ****** * * * **  *  ***      i;
 **        ** ***** ***      ** ** j;
  *  ** **    * *** ****   ***   newNum1;
 *** *** **  **  *** *** newNum2;
**  **   *** **** **  ** * **  *  gcd;
** *** * * *      *   ** *  ** * rem;
**   *    * * *    ***    * *    num1, num2;
    
 * ** ** * * ** * * * **** ******* ** *  ***  ** ** * * * ***** *   **  ** 
   *   ***   ****   * ****  *  
***     *       *****    **  ** 
******* **** ***  **  *  *  **** 
* **  ***   * * * * **  
***    * **** * *   *  **  * *** *   != 0)
   * ****    ******    ** * 
***  * * ****** *  ** * *****     *** ** ** *** ****  * *   * = j%i;
    ** * * *    *        *  ******    *** *   *  *****  = i;
  * *  *       **** * *     **  ****** *     * * = rem;
*  *****  *  ** *       * * **
  ** * *   * *  *   * **** * * * **
    
  * ***     *   **   * * * *   = num1/gcd;
   * * *   **    **   ** *****  *  *  = num2/gcd;
    
*  *     ** *  **  *  *** *   *** * == 1)
 **       **  ** *  *
 *  **  *    * * **  ** * ******  * * **  * ***  **   ** ** * * * *  ** *
*   **   * * *    ** *****
    
    *** ***   **   **  ***  
* * ****** ****  *     **  
  **** *   **    **     *  * *** ****  * **   *   **  *         ***  * **  * * *  *
* *  * *    **     **** 
    
 ***   * ***** *   **  *  ** *  * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
  * *  * **** *    ** * **** i;
* * *  ** ** ** *** ** ****  j;
  **  *** *  **  **    newNum1;
 **  * **  *   ** *   *   ** newNum2;
*  *  ** ** *   ***  **** gcd;
** ***   * **  ***   *   **    ** rem;
  *  *  * * * **  * * *     num1, num2;
    
 * * *  * ** ** ** *  **    ***  **    ** ** *   * ** ****  *    * *
* *     *  ***** *    
* ****** *       *** ** ***
  **  ***  **    *   ** * * * * ***
****  **  * * * * **    
* * *   ** *   *  *  ****  != 0)
    **** *  ******** *** 
     *   * **  ***   ***  * **   * ****  *  * * *****   *  *  = j%i;
**    * *   ***** *   *** **   * ******  * ***** * = i;
  ** *  * ****  *    **** *  * *    * * *** *  **  *      = rem;
* **    * * *  *  * *   **
***  *   ***  ** ** *    * * 
    
*** * ****** *****  * *  *    = num1/gcd;
*** *  *  *** *   *       ********* = num2/gcd;
    
***** * *  **  **  * **  ***    *** == 1)
    ***** **    **** **
* *    ** * **     *     ****  * *    *** ****   * * * * *  *   **  * **  * ** ***
***** *** ***   ***** * * **
    
**** ***** ***  ** ** *     *** 
**** *** **  ***  ** 
 **      ** *   *** * **** ** ** ** *****   *  * **    **    **** *  *** **      ** * *  
 ******* * ***   ****    *    *
    
** *** *   * ** ** * *  * **  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
  *** *    ** ***      * *    **   *      * * ** ***** ******  *** *
    * ******  * *  **  * * **    ** ** ***   ****   ***** 
    {
****    *   *  *  *    *  *  ***** *  * ***  ** *** *        *   * 
  * * **  ***  ***   * **  * **  *****  *      *   * **  *   **
 * * * *** ***  * *   * *  *******  
 *** * * *  ******   * * ** ****       * * * *** 
*  *        * **  *  ***** *  ** * *** * ** **      

   ***  *  * * * ***     * 
*  *  * ***    *  **  * *   *  *    * *   ** ** *****    *  *   *   **  ** ****  *     ** * *    
 * * ***** *    ** *  *** * ****     * ***   * ****  *  *    ** *********    ***  * 


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
 *   * * * **  *** * *****    a,b,GCD;
*  ** ** ***    *****    * *  * *  * *     * * * * ***  * *
*  ** ****    *   **   * **** ****
   *    ***   ****  *  *  *
***    ** * ***  * **      ** * * ** * * *  ** * ******   ** *  *        * * *   
 * *  *  **   * ** * * *****   **
    ***   **  **   ****    * **  * * * *** *  * **  **  *  *   ****    * ** ****
       ****  ****** * ***  ** 0;
}
*   *  *   *  *  *   **** gcd(int a, int b){
* * **  *  ***   *   ***   *** ****   ***  **** *     (!b) return (a);
**** * * * *     *   *  *  * ***    *** * ** ** ***  ** **   gcd(b, a % b);
*     ***  * ******   * ******
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *     ** * * 
#include *  **  * * **  **  

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
  *   *  ** * *  * *  gcd, remainder;
***** * * * **  *** ***   * *
  *   ***  *  * * * **** ** * (n != 0)
***** ** *   *       ** ***
***  *   * * **  * *** * * **** *  * *    *  **  *  * ***** **     = m % n;
* *****  * * ** * *  **** * ***   *** *****   * * ** * *  * * **  = n;
      *   *** *** * *  ***** *** * *** *   ***** *** = remainder;
 *    ** **  * * ** *  *  * 
*** ***  * *  *  ** * ** 
 ****  *  **   ** *   ** = m;
* ****  **** * * * *** * *
** ** ***  **** *   ***  ****   **** gcd;
}
int main (int argc, const char * argv[]) {
 ***** * ****  **  **  ***    number1, number2;
* * * *  *  *   *** **    **   *  newNumber1, newNumber2;
* ****     ** ** ****    * * *
   ** * **** **   * **** *
*     *   *  ***  ****** ***  * **  *  *   *   ** *** * **   * **   * ** *  *
***  * *** *  * ** ***  ****
  *   * **  ***   *** *  **  * = number1 / gcd(number1, number2);
*  * ** ** ****  ** **   ***  ** = number2 /    **   number2);
  * * **** **   * ****** ****
**     *   *    * **** *** * 
 * *   ********  **** *  * ( * ***   *
 *  ***   * *  * ***    ** * ** * **  ** * **   ** ** ****  ***** *  ** ** * **  newNumber1);
 ****  *  *  ** ** * **     ** **
 *  *  ** *** *** *  *  
**    **  **  * *      * ** ** ** *      * * **   *  newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
   *    **** **  *    *   ** a,b,c,d,e,f;
*   **  *     * * * ****    * ** *   **   *** *  ** *  **   
 **    ******   * ** **   *
  *     *  ** **** *  *  
* ** *  * ** *  * * ***    * ** * 
    {
* * **** *  **   *   ****     * **** * ******  *   *
    ** *  *****    * *  ***    * * * * *  * *    *** 
** *** * *  **     * *****   * * *   **** * **  * 
    }
     *  * * *    *    *  ** *** ***
    {
   * *** *    **   ** * **  **   ** **** **** *    *
*  * * * * ******    * ***   ** *  *******  **  **  *      * * *  ****
 ***     * *  * ***  *   ** * ** * *  * *  **   **   *  
*  *  ** *  * ** *   * ***     *** ** **   *** * ****  *    ** ** ** *    ** * * 
    }
 *  *** *  *  * *  *   *  *
    {
* **  ***** ** ***  *   ****   *   *   * * * ***** * ** *      
** *   **     *  **  * * *  * * *********   **  **** **  * * ****   * ***         * *****  **
* *    *  **  *****  * ** **  **  *** * **    ***   *   * ** 
*** *** ***   ***  **   ** ** ****  *  * * *  *    * *  **     *** ******* ** *** *     
    }
* * ** ** *** * *** *     *** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.65
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 13.9k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 13.7k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 17.4k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 13.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users