0 like 1 dislike
7.6k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 7.6k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* * * * * ****
int main()
{
** ** **** ** * *** * ** *** ** ** **** * * ** ** ***
* ** ** * ****** ** * ** * * %f *** ** * * ** ***
** * ** * **** = (b*b-4*a*c);
** * ** * * *** ** = (-b + sqrt(D))/(2*a);
*** * * * * * * *** * = (-b - sqrt(D))/(2*a);
*** * * *** * ** *** * ** *** = -b/(2*a);
* * * ** ** *** ** * ** ** ** =sqrt(-D)/(2*a);
** *** ** * ** * ** * **
** *** *** ** * ** ***
* ** **** * *** *** ** * * * ** ** *** * *** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * ***** ** * *
* ** * * ** ** * ** ** * ****** ** ** * ** = %.2f\nx2 = %.2f",x1,x2);
** ******* ** ***** *

* ******* * * ** * * * * if(D==0)
* * * * ** ** * * *
* * *** *** * * * * * * *** *** ** * * * **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * *** ** * **** ** * ** * **** * * *** = x2 = %.2f",x1);
* * ** ****** * *
* ***** **** *** * *** * * *
* * * * ** **** * *
**** **** ** * * *** * ** ***** * **** ** * * * * * ***** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * **** * ** * *
* * **** * * ****** *** ** * **** ** * **** ** = ** ** ** * * * ** ** ** *
***** * * **** * ** * * *** ***** ** * ***** * ** * = * * ** ** *** ** ***** *** ***
* *** * * *** **
* ** *** ** ******* * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include **** ******

int main()
{
*** ****** * **** * ** *** n, i;

* * ** **** * * ***** * *** * * * &n);

* ********* ** *** ** ** * = 1; i <= n; ++i)
** * **** * * * * *** **
** ** ** * * * ** * * *** * *** * ** ** *** ** % i == 0)
* * **** *** * * *** ** * * * * *** ** * *** * ** ** * * * * * ", i);
* ** *** * * * * *****

** * * ** ** ***** **** **** * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
**** * * ****** **
* * ** *

int main()
{
* * * ** *** * * *** *** ** * * ***
****** * ***** * * ** * * * * * ** *** ** *
********* ** *** **** = *** ** **
* * *** * ** * * * * ** * ***
* * * * * * ** * **
** * ***** * *** ** ** * ** * **
** * *** * * *** * ** = -b /(2*a);
* ** * * ** * * * * ** ** ** ***
*** * * *** * *** *** = (-b)/(2*a);
* ** * ***** ** *** ** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * * * ** **
* * * ** ** * * ** ********
* * *** * * ** ** ** if(D==0)
* * ** * *** *****
**** ** * ** * * * * = (-b + * * ** *
*** * ** * ***** *** * *** * = (-b - * ***** **
** **** **** ** * *** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** ** **
*** * * * * **** **** *
* * * **** **** * if(D>0)
* * ****** *** ** * ** *
* **** * * * * **** ** = -b/(2*a);
** ** * * * * * * = (-b + * ***
* ****** * * **** * *** * * = (-b - ** * *****
** **** * * * * * * * ** * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ** *** * **
** * ** ** * *** ** ***
* **** * * ******** * * * 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** * *
#include * *
int main()
{
* *** ** * ** ******** ***** a,b,c;
* **** * **** * * ******** * *** * ********** * ***** **** **
* **** ** * ** * *
** * ** * **** ** * *** * ** *
* * **** * **** ** *
*** * * ** ** * **** ** **** * *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ** * * * + * ********* - ** * * *
**** ** ** *** * **** * **
* * ** ** * * ***** **
* ** ** ** * **** *** **** if (b*b-4*a*c==0)
** *** *
** * * * * * **** * ** * * * ** * * * ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** * * * * + ** ***** *
* *** * * ** ** *
* * *** *** ******* *
** * ****** * ** * **
** * *** ** ** ** * * *****
* * ** * ** * *** ** *** * * *** * ** * **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** * *** ** * *** ** * ** **** * * ** *** * *** * *
**** ** ***** * ** *
* * * ***** ***** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** ** ******
#include * ** ***** **
int main()
{
* ** * ****** * * ***** * ** a,b,c;
** ***** *** ** *** * ** * *** ** * * ** ** ** *** *
*** * * * * * ** * **
* * **** *** ** ** * * ** * * **
* * * * *** ** **
* ** * * *** * ** * ** ** **** * * * **** * *** **** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * ** ** + * ** ******** * - * * * * * * *
** ** * *** * * * **
* ******** * * * * * *
**** ** * ** ** * if (b*b-4*a*c==0)
* * ****** ****** ** * *
* * * *** *** **** * * *** * * **** ** **** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ***** ** + * ** * * ***
* ** ***** * * * *
* * ** * ** * * * **
** * * ** * ** *******
*** *** **** * ***
** *** * *** * * * * * * ** * * ** * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * **** ***** * ** * *** * * ***** ** * ***** * * * ** *
*** * **** *** *****
* * * **** ** * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* ** * ** ** ** * a,b,c,d,x1,x2;
* ** * ** * * ** ** * ** *** **** * * *** * ***
** ** * * * * **** * * ** *
* * * ** **** * * **** ** * ** *
*** * * * * ***** *** * * * *** * ******* *
** ** ** ** * ** * * * **
* * ** * **** * ***** * **
* ** * ** * * * **** * *** * ** *** ** * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and **** * ** *
* * * ** * ** ** * **** * ** * * * ** * ** ***** * ** * ** * = %.2f\n",x1);
** ****** * ** * * * ** * * * *** * * *** ** = %.2f",x2);
** * *** * ** ***** * *
*** **** **** * ** * * * if(d==0)
* ** ** *** * ****
********** ** * * ** *** **** * * ***** * ****** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * *** * *** ** *** * * ** * **** *** ** *** ** = x2 = %.2f",x1);
* * *** ** ** ** *
** ** ** * *** * * **
* ** * *** * ** ** ***
***** * * *** ** * ** * * * ** ***** * * * *** ** * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** *****
* *** ** * *** *** * ** ** ** * ** **** * * * ** = * * ***** * * **** * * * ***
* ** * ***** * ** ** * * ** * *** * ** ***** *** * = ** * ******* * **** *****
* * * * *** * ** *
* * ** * * **** ** **** ** * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* ** ** *** * **** * ** * ** * ** * ** * **** *** ** * ** * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* ** * * ** ** *** * *** ** ** ******** * * *** *** ** - (4*a*c);
* * * ** ** * ** * * * * * ****** ** ***
* ** **** ** **** ** ** ** * * * * * * * *** ** *** * **** * * ****
* *** * * * * * ** **** * * * * * ** *** * **** ** *** (-b+spD)/(2*a);
*** * * * ** * ** ** * ** * ** ** * ******** * * ** ** ***** * * (-b-spD)/(2*a);
** * *** * *** * ** ** ****** * *** ** * * * *** *** ** ** ** (x1==x2){
* * * * * *** ** ** **** * * * ** ***** * * * * ** * * ** * **** ** *** *** * * * ** * * * ** ****** X=%d\n", x1);
* * * **** * **** * ** * * ** *** * * ** * ** * * **** *** *** *
* * * * ** ** * * * ***** *** ** * * **** ***** * ** {
** * * * *** *** ** * ** ** ** ** * * *** * ** * ** *** ** * * ** * *** * ** *** ** * * ******* * * * * ** *** X=%d或%d\n", x1, x2);
* * * *** * * * ** * * * * **** * * *** ** * * ***
        }
**** ** * * ***** * ** * * ** ** *** * if(D==0){
*** *** **** ***** * * * * * ** * * * ** * ***** ** *** *** * ***** ** (-b)/(2*a);
******** *** * **** ** ** ** * * ** *** * * **** * ** * ** **
* * * **** ** *** * ***** ** *** ** *** *** * * ** ** ** ** ** ***** ** **** *** ** ** X=0");
* ** ** * ****** ******* * **** * * * **** ** * *** ** ** ** * *
***** *** * *** * * * * ** * * * *** * ***** * * * ** **
** *** * ** * *** * ** * * ***** ** * * *** ** ** ** * * **** **** ** * ** * * * * * *** * X=%d\n", x1);
* * * **** * * * * * * * **** ** ** **** * * ** * * ***** * * *** *
        }
* *** ** * **** ** **** * * * * ***
* * * ** *** *** * * *** ** * ** ** * *** * * * ** **** * * **** *** * ** * * ***** **
** * *** *** ** * * * * * * **
    }
**** **** ** * ** * ** * * ** ** * ** * * *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
** * *** * *** * * ** a,b,c,D;
*** * * ** * ** *** * **** * x1,x2;
* * ** *** **** ** * * * * * %d * * *** *** *** * * * ** *

** ** **** * ** ** * ** ** * *
******* ** ** * * * * ** * ** * * *
****** * * * ******* ** **** * *

**** *** **** ** * A,B,C;
*** ** * * ** * ** *

** *** *** **** * * *** **
** ** ** * * * ** *** ** * ** ***** ** * ** * ** of %.2fx^2 + %.2fx + %.2f = 0  are real and ** * **** * * *
* ***** ** *** ** ** **** **** * ** * * ** * * = %.2f\n",x1);
* * *** * ** * * * * * * ** *** * * * * * ***** = %.2f",x2);}

*** * * * * *** *** * ******* * if(D==0)
*** ***** ** * *** ** ***** *** * * ***** * * ** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
** ** * * *** * * *** * ** ** * ** ***** ** = x2 = %.2f",x1);}

*** * * * *** * * ** ** if(D<0)
* * *** ** *** * ** ** ** ** *** * ****** of %.2fx^2 + %.2fx + %.2f = 0  are complex and ** ** ** *
** ** *** * ****** *** ******* * * * * ** * ****** bb,d,dd;
* * ****** ** *** *** ** ** *** * ****** ****** *** ** **
****** **** * * ******* ******* ***** * ** ** **** *
** ** **** ** ** ** ** * * *** * ** * * ****** * * * * * *** = **** * * * * * **
* ** * ** * * **** * ***** * ** * ** *** *** ** * *** * *** ** * = * **** ** * ***

* * ***** * * * ***** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
** * ** ******
int main()
{
*** * * ***** * **** *** ******** *
* ******** **** ** * **** * ***** %f ***** **** ** * ********* * *
*** ** *** * *** * ** *** = (b*b-4*a*c);
* * * ***** * * *** = (-b + sqrt(D))/(2*a);
** * ****** * * * * ** ** = (-b - sqrt(D))/(2*a);
* * * * * ** * = -b/(2*a);
** * * ** *** * * * **** *** =sqrt(-D)/(2*a);
***** ** **** *** **** ** * * ****
* *** ** * * * * *
* * **** * *** * * * * ** **** * ** * ******* * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * *
** * ** ** * * ** *** *** ** * * * ****** * * ** * ** * *** * = %.2f\nx2 = %.2f",x1,x2);
** *** * ** *** * ***

* *** *** *** * * * if(D==0)
* * *** ***** **** **** **
* *** ** ** * *** ** ******* * * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** ** * * * *** *** * * * ** **** *** * ***** * * * = x2 = %.2f",x1);
* * **** *** *
* ** * * ** * ***** *
* ** * ** **** * * *
****** ** *** * * *** ** *** ******* * *** **** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * **** *** * *
** ****** * * * * ** *** * ** ** * * ******* * = ** * * * *****
* * *** * * * **** ** **** * ** **** ** * ** ** * ** ** ********** = *** ** ** ***** ** **** * *
* * *** ***** **
*** *** * ***** ** * *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * * * * * **
int main()
{
** ***** * **** ** **** * ** ***** ****
** ** ** ** ** * * * * *** %f ** *** * * * ** ***
*** * ** * ** * ** * = (b*b-4*a*c);
* ***** * * * * = (-b + sqrt(D))/(2*a);
* * * ** ***** *** = (-b - sqrt(D))/(2*a);
* * ** * **** * * ** * * * = -b/(2*a);
******** * * *** * *** * ***** =sqrt(-D)/(2*a);
**** *** **** **** * **** * *
* * * ** * ***** **
***** * * * * * ** * ** ** ***** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** **** * * * **
* * *** ** *** **** * **** *** *** ** ** * ** * *** = %.2f\nx2 = %.2f",x1,x2);
* * ** ****

* ***** ** * * ** * * * if(D==0)
** ** * ** * * * *
*** * * * * ** **** * * ***** * * * ** **** * ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * ** * ******** ********* ** *** ***** *** * ** * *** * * * = x2 = %.2f",x1);
** * *** ** * *** *
* *** * * **** *
*** * **** * * * * **
* ***** * *** * ** ** * ** ** * ** * * * *** **** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ** * ****
** ** ** ** * ** ***** ** **** * *** * ** * * * *** ** = * ** * ** *** **** * *** *
* * * *** * * * *** *** ** * * * * * ** ******* * ** = ** ** * * * ** ** **
* **** *** * * ***
*** *** **** ** * * ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.136
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users