0 like 1 dislike
12.8k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 12.8k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
*** * ** * * *
int main()
{
** **** *** * * ** ** ** *** * *** ***** * *
** ** * * * * ******** ** ********* %f **** **** * * ** * *
* *** * * * * *** *** = (b*b-4*a*c);
* * * * **** * ***** = (-b + sqrt(D))/(2*a);
*** * * ***** ** **** * = (-b - sqrt(D))/(2*a);
**** ** * ** * * ***** ** = -b/(2*a);
*** *** * ** * ** ** *** * ** =sqrt(-D)/(2*a);
** * * * *** * ** ** *
* * *** * * * * ****
* **** ** *** * **** * * ** * * * * ** * ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * ***** * ** **
** * * ** * * * ** * *** *** * *** *** ** = %.2f\nx2 = %.2f",x1,x2);
* * * *** *** ** ***** *

* * ** * * ** ** * * if(D==0)
* ***** *** ** * *
** **** * ***** * ***** * **** * * ** ** * * * * **** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * *** * * * * *** **** **** ** * ** *** *** ** * *** = x2 = %.2f",x1);
* * **** ** *
** **** * * * * *** *
* * ** * **
**** * * * ** * *** *** ** * * *** * * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and **** * ** ** ****
** ** ***** * ** *** ** ** ** ****** *** * * * * * * * = *** * * * ** * **** * * * *
*** ** * * **** *** * * *** ***** ******* * * *** *** * ** = * * * * *** * * *** *****
* *** ** * ** * * ******
* * *** ** * ** ** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * *

int main()
{
* **** * **** **** * n, i;

* * * * * * * ** * *** * ***** ** &n);

* * * *** * **** * ** * = 1; i <= n; ++i)
** * ** ** ** * * ** *
***** ** *** ** *** * **** * ** ********* ** * % i == 0)
*** ** * * * * * * *** * * * *** * **** ** ** **** ** ** * * ** * ", i);
***** ** ****

** * ** * *** * * ** * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
**** *** * * **
* ** ** ** ** * *

int main()
{
* **** ** ***** * *** * ** * ** *
*** ** ***** * *** ** *** ** * * ***** ***** * * *
** **** * ** * * ** = *** * * *
** ******* * ***** **** * *** *
** ** * ** *** ** ****
* ** *** * * ***** * * ** * **
** * * * ** * * * *** = -b /(2*a);
* * * ** * * ** * *** ** * ****** ***
* *** ** * * * *** = (-b)/(2*a);
* * **** *** ** * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * * * *** * * *
* *** ** **** * * **
* * ** * * * * * if(D==0)
*** ** * *** * *
**** ** * * * * ** *** * = (-b + * **
* ** * * * * * ***** * ** * = (-b - * * * **
** *** ** * ** * ** ** ***** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * *****
* ** * * * ** *
*** * * * * ** * * if(D>0)
***** ** * *** * ** ** *
*** ** * *** ******* **** = -b/(2*a);
* * * ****** * ******** = (-b + ***** ***
*** ****** * * * * * = (-b - *** **
* ** * ** * ** * * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * *** ** * * *
* * ** *** * **********
**** ** * ** ** * ** **** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** *** * **
#include ** * * ****
int main()
{
*** *** * * * *** * * ** a,b,c;
* *** *** * *** * * * * * ** ** * * ** * ** * * * * ** *
** * * * * ** ** * * ** *
*** * * * * ** *** *** * ** **
* * * ** ***** ** ***
** * * ** * * ** * *** * * ** * * * ** ** * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * *** ** * + ****** ****** **** * - * ******** ***
*** *** ** ** * ** *** *
* * * *** **** *****
* * *** ** * *** **** * if (b*b-4*a*c==0)
**** *** ** *** *** * *
* *** * * * ******* ** ***** *** **** ***** ** **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * ** * ** + * *** * * *
* * * * **** * ***
* * * ** * ** ** ** *
**** *** * * * ****
*** ***** ***** ** ***
*** *** **** * * **** *** *** ** * * ** * ** * * * *** * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * **** * * ** ** ** ** ** * * * ** * ** *
** ** * * ******* * ***
**** ** *** * * * ** * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * *** ****
#include ** ** **
int main()
{
* * * *** * *** * * * a,b,c;
** * * ** ***** * * *** ** *** **** ** * **** * **** **** * *
* * ** **** * ** *
*** * * *** ** ** * *** * ** * ****
* ** * * ** **** ** *
* *** ** * * * * **** ** ** * * * *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ***** ** * + *** * * * ** - ** * **
***** * * *** * ** **
* **** * ****** ** ****
* * ****** ** ** * *** * ** if (b*b-4*a*c==0)
*** * ***** * * * *
** ** *** * *** ** ** * * **** *** **** ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** *** * *** + **** ** **** ***
* * ** * * ** ***
** ** * ** * * *** ** ****
* ***** ** * **
* * **** **** **
* * ** ** * ** * * * * ** **** ** *** * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * *** * *** * * * * ** *** * * **** * ** **
*** *** * * ***
* *** ** ** * * * * ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* ** * ** * ** ** *** * a,b,c,d,x1,x2;
* * * * ** * **** *** * * ***** * * *** ** *
* * * ** ** * * ** * * ***
* * *** * * * * ** * ** ** ** * * *
* *** ** * **** * * ** * ** ** *
** *** * * ** * * * * *
*** * * * *** ** ***
******** * ** * ** * **** * * ** ** * * * * * ** ***** *** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and **** ** *** ** *
*** * * ***** ** * ** * ***** ** ***** *** ** * * = %.2f\n",x1);
* * * *** **** ** ** * * *** *** ** * * *** ** = %.2f",x2);
*** ** * ** **** ****
* *** * * ** ** *** if(d==0)
* * * ******** *
* * * * **** * ** * ** ** *** ***** **** * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * * ***** * *** * * ** *** * * **** ** * *** = x2 = %.2f",x1);
* ** * * * **** **
* ** * ** * * ** * **** **
* **** * * * * ** *
* ** * * * * * **** ** ** ** * * ** ** * ****** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * ** *** **
** * * * ***** * *** * *** * * *** **** ** ** ***** = *** ** * **** *** *
* * **** ** ******** *** **** * * * ** *** ** * * ** * ** = * ** ** * * ***** ***** * **
* ****** ** **** **** **
**** ** *** * *** * **** ** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* ** * * * * *** * * * * **** * *** *** ********* * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
*** * * * *** ** ** * **** * *** * * * * - (4*a*c);
*** * * ** **** *** * * ** * * * * ** * ** ** ** * **
* ** * * * *** ** ** * * **** ** ** ** ****** ** * *** * * * ** * ***
* **** ** * *** **** * *** * ** * ** * * * * * * ** * * *** (-b+spD)/(2*a);
* * * ***** ******* * ***** * ** * ** **** ** ****** ** ** ** * *** (-b-spD)/(2*a);
* *** **** * *** *** ** * * **** *** *** *** ****** ** * (x1==x2){
** * * * * ***** * * ** ** *** * **** ** ** * **** * * ***** * * *** ** ** * ** ** *** * *** * ** *** * ** ** * * X=%d\n", x1);
* * * * * * ** * ** * * * * ** * *** ** *** * * **** *
* * ** ** ** ** * ** *** ** ** * *** * * *** *** * *** *** * ** * {
**** *********** * * * **** **** * **** * * *** * * **** **** ** ** * ** **** * * ** * * ** * * * * ** *** * X=%d或%d\n", x1, x2);
**** * * ** * ** ** * * * ** * * * * **** * * * ***** *
        }
* * *** * * ** ** ** ** **** ** *** * * ** * * ** if(D==0){
** ***** *** * * ** *** *** * *** * * ** **** * ** *** ** * * ** * * ** ** * ** * (-b)/(2*a);
** ** * ***** * ** *** ** ** *** ********* * ** * ** **** ** *
* ** **** *** *** * * ***** * *** *** **** * ** *** * *** ** * ***** * * ** ***** ** * * ** * * * X=0");
*** ** ** ** *** * **** * ** ***** * ******* *** *** * * * * *** * * *** * * * *
* * *** *** **** *** * ****** * * ** ** ** * * *** **** ***
* * ** * * *** ** * ** * ****** *** * ** **** * ** * ** *** **** * *** * ** ** *** * * * X=%d\n", x1);
** * * * ** * * ** ** * ** ** * ** ** *** *** **** * ** ** * ***
        }
**** * * * ** * ** ** ** ** ** ** **** *
*** * ** *** * ** ** * * * * ** ** *** * * * ** *** ** ***** **** * * *** * *** ** * *** ******
***** ** * ** *** ** * * ** *** * ** **
    }
** * * ******* *** * * * * ** * ** *** ** ***
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* * ** ** ** *** ** a,b,c,D;
** * * ** **** *** x1,x2;
* ** * * ** * ** * *** * %d ** *** * ** * * * * ** ***

* ** * * ** * * * **
* * * * * * * * * * **
* *** ** ***** * **** * **** **

* ** ** * * **** **** * ** A,B,C;
** * ** ** ** * * ** * * *

*** * ** ***** *** * ***
* * * ** * ** * * * * * ** **** * * ***** ** ** * * ** ** of %.2fx^2 + %.2fx + %.2f = 0  are real and * ** *** ****
*** ** ***** * **** ****** * ** ** *** * * ** ** * *** = %.2f\n",x1);
* * * * ** * * ************ * * ** ******* ** ** ***** = %.2f",x2);}

** * * * * ** *** ** * * if(D==0)
* * ** * ** ** * * * *** *** * * *** * ** ** ***** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* * * ***** ** ** *** ** *** * *** * * * ** * **** * = x2 = %.2f",x1);}

* * ***** * **** * * * if(D<0)
*** ** * ** * * *** ** *** *** * * * **** ** *** of %.2fx^2 + %.2fx + %.2f = 0  are complex and * ** ** * * *
*** ** * **** * * * ****** ** * *** ****** ***** * * * bb,d,dd;
** * * * ** * * * ** * ** * * * *** ** * * * * * *** * * * *
* * ** * * ** * **** * *** * * ** *** *** ** *** *
* * * ****** ** ** * * *** * * * * * ** * *** * * ** * ** = * * ******* ** *
**** ** * ****** * ** ** ** * * ** **** ** * *** ***** ** * * = * ** * * * **

** * ** * *** * * ** *** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * * ** * *******
int main()
{
* * **** * ** ** *** * * **** * ** **** ***
* **** *** * ** ** * *** *** * * %f ** ** * *** *** * ***********
* *** * * ** * * *** = (b*b-4*a*c);
* * * * * ** * = (-b + sqrt(D))/(2*a);
* **** * ** **** * = (-b - sqrt(D))/(2*a);
* ***** * ** *** ** * ** = -b/(2*a);
* *** * *** * * *** *** *** *** =sqrt(-D)/(2*a);
**** ** * *** * * *** * * *
*** * ** *** **
*** * * **** ***** ***** * * * **** * * * * ***** * * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * ** * *** *
**** ** * * ** ** * ******* * ** * *** * * * * = %.2f\nx2 = %.2f",x1,x2);
*** ** * *** * ** * * ** ***

* ** **** * ******** **** if(D==0)
** * * *** *** **
* ******** ** *** * ** * * * *** * **** *** * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * *** ** ** ** *** *** ** * * * * * * ** *** ** * = x2 = %.2f",x1);
** * ***** * * * *
* * ** ** *** * * ***
** * * * * *
* **** * * * * *** * ** ** *** * * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** ** * * * * *
* * * ** *** * * * *** ** *** ** * ** ** * ** ******** = *** *** ** * * **
* * ** *** * *** * ** * **** * * * * ** * ** ** ** ******* * = * ** * ******** **** * ** *
*** ** ** *** * ** **** *
** * * ** ** *** ***** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * * * *
int main()
{
* * **** ** ** * ** ** *** * * ** ** * * * ****
* * * * * * ****** * ** %f * * * ** * ** * ** ****
*** * * * ** * = (b*b-4*a*c);
** * * * * ***** * = (-b + sqrt(D))/(2*a);
** * * * * *** *** * = (-b - sqrt(D))/(2*a);
** ** ** * * * **** ** = -b/(2*a);
********* ***** * * * ** * * =sqrt(-D)/(2*a);
* *** *** ***** *** * *
* * *** ** * ** *
** * * ** *** * * * * *** ** ** ** *** * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and * *** * * *
* * * * * * * ** * *** * * ** * **** *** = %.2f\nx2 = %.2f",x1,x2);
** *** * *** * * *

******* ** **** * ** ** if(D==0)
* * ** * * * * **
* ** **** ** * **** ****** ***** * * * *** ** ****** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * ** ** *** * * ** * **** ** * * * * * * ** ** * ***** = x2 = %.2f",x1);
** * ** **** * *
** ** * * * * * *
** ***** ** **** * *
** ** * * **** * * * ** * *** * ** * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * ** * * **
** * * ** *** ** *** ** * *** ** * *** * * * = ** ** ** * ** * * ****
*** * * ****** *** * * ** ** ** * * **** ** * * * * ** ** = *** ***** ** *** **
* * *** * ** * ***
** *** * * * ** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.12
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users