0 like 1 dislike
7.6k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 7.6k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
****** * * *
int main()
{
*** * * * *** * * * *** * ** *
*** ** ** ** ** * * * * * *** **** * * %f * ** * ** ** * * * * **
* ** * ** ***** * * ***** = (b*b-4*a*c);
** ** ** *** *** = (-b + sqrt(D))/(2*a);
* *** ** * * * * * = (-b - sqrt(D))/(2*a);
* ** * * * ** * **** = -b/(2*a);
* ***** **** * **** ** =sqrt(-D)/(2*a);
***** * ** * * ***** * *
* * * * ** * * *
** *** ** * **** ** ** * * ** * ** * ** * ** **** * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and *** *** ** * *
* * * * ****** *** * ** * * * * * *** ** = %.2f\nx2 = %.2f",x1,x2);
*** * *** ** ** * * ** ****

** ****** ***** * * * * if(D==0)
***** *** ** * * *
*** * * * **** * ** *** * * * * ** ***** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
**** * ** * ** * ** ** *** ** * ****** *** *** * ** = x2 = %.2f",x1);
**** * * * **** *
* * * * * * ** **** **
****** * * ** * ** * * *
** * * * ** ** ** ** * * ** * * * * * * ** ** ***** * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** * * * *
** ****** *** ** **** ** * * * * * * ** * * * * * ** = * *** * ** **** * ** * **
* *** *** * ***** *** *** * * * *** ****** ******* = * ****** **** * *
* * ** ** ** *
* * * * * ** *** ******* * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** * ** *

int main()
{
*** **** * * * ** * * *** n, i;

* * * * ** * * * *** ** *** &n);

** * ** ** * ***** * * **** * = 1; i <= n; ++i)
* ** * * *** *
** ** **** * * * * * * * *** * * **** * * % i == 0)
****** * **** *** * * * * * * * *** * * * * * ** *** * ** ** ***** ** * * * ", i);
** * * ** ** * * ****

******** * * *** * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** **
** * **

int main()
{
* * * * * * ** ** ***** * * ** *
** *** ** ** * * ** * * ** * *** * * *** * * ** * * **
* * * * *** *** * * ** = *** ******
** ** * * ** * *** * ***
* * ** * * ** **
** ** **** * *** * * * **** *
****** ** * *** *** ** * = -b /(2*a);
* * * * * *** ** * *** *
* *** **** *** ** ******* = (-b)/(2*a);
*** * **** *** * **** ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * ** * *** * * **** *
** ** * *** ** * *
** ** ** * ** * * ** if(D==0)
** *** * * * * *
*** * *** * * * * ** = (-b + ** *** *
**** * * * * * * = (-b - * *****
* * * *** * * *** ** ** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** **** * *
* * ** ** * ** ****
*** * * ** * * ** * * if(D>0)
* **** ** * ***** ******* *
*** * ** * ***** *** *** * = -b/(2*a);
**** *** * * ** * * **** *** = (-b + * **
* * * **** *** **** = (-b - * * **
* **** * ** **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ** ** * **
** *** ** * * ****
* * ** ** ** * * ** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** * * ** *
#include ** ** * **
int main()
{
** * ** *** * * ** a,b,c;
* * * * * *** * * ** ****** * * ** * * ** ** ** * *** ***** **
** * * * * ******** *
****** * ** ** ***** * * * ** * *
* ******** *** ** *
* *** *** * ** **** ** * * * ** *** **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ** **** * * + * ** ** * * ** - ** * *** ***
* * ** ** * * *** **
* * * * * * * ****
*** * * **** *** ** ** * ** if (b*b-4*a*c==0)
*** *** *** **** * * * *
** * * *** **** * * ** *** ** ** * * * ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * **** * + * * *** * * *
** ** * *** *** *** *
*** ***** * *** * *
* * ** * * ** * ***
***** *** ******* * ***
* * * ****** * * ** ** * * ** * *** ** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** * ** **** * * ****** *** **** * ***** * ** *** * ***
** *** ** **** * *
* ******* ** *** *** ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * * * **
#include ** ****
int main()
{
****** ** * * * * ** a,b,c;
* *** *** * ** ** * ** * ** ** ** * * * ******* * ** ** *
** ** **** * ** *** * *
** * * ***** *** ** **** * ****
** * * *** * ** * *****
** * * * * *** **** *** *** * ** * **** * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = *** * * ** + * * *** * *** - * * * *** ***
* ** * ** ** **** ** **
** *** * * *** ******
* * * * * * * * *** * if (b*b-4*a*c==0)
**** * * * *****
** **** * ****** * ** * ** * ** ** *** *** ***** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** * * + ** ** * *
** * **** ** * **
* *** **** * * *** * * **
**** * * * * * * * ***
* * ** * *** ** *
* * * ** * ****** * **** *** * * * ***** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * **** ** * * * *** ****** * * **** ****** ** **
* * ** ** * ***
* *** * * * *** * ** ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
** * ******* *** * a,b,c,d,x1,x2;
**** * ** ******** * * *** ******** * ** * ** **
** * ** *** * * * ** * *
**** * *** **** * * * ** * * ***
* * * ** *** ** ** * * ** ***
* ****** ** * * * *** * *****
***** ** ** ** ** * ** ****
*** ** * * ** * * * ** * **** ***** ** *** ** **** ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and **** *** ** **
*** ** * **** * * ** * * ** * * * * ** *** * ** = %.2f\n",x1);
* *** ** *** ** * ***** ** * ** ****** * ** * = %.2f",x2);
* * * ** * ** *
* ** * * * * * ** * if(d==0)
*** * * *** *** *
* ** *** ** * ** ** * *** ** ** * * * *** ** **** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * ** ** * * **** *** *** * ** * * ** **** ** *** *** ** ** = x2 = %.2f",x1);
* ****** **** * * ***
** * ** *** ** * * ** **
***** * * * ** *****
* **** **** ****** * ** * * **** * ** ** ** * * *** ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * *** * * * *
*** ** ** * * * * ***** *** ** * * * * * **** *** ** = * ***** *** ** * * ** * * ***
* ****** * ******* * * * * ** * *** * ****** ** = * ** * ** * * * *** * ** *
* * ** *** * * ******
*** * ** * *** ** **** **** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
** * **** **** ** * *** * ** *** ** * * * * ** * *** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
*** * * *** * *** ** **** ** ** ****** - (4*a*c);
** * * * ** * ** * * * * ** *** * *******
* ** * * **** *** *** * ** *** * ******* * ** ** ** *** ** * * * ** ** *
* *** ** *** * **** ** * * * * *** * * *** * *** * * ***** (-b+spD)/(2*a);
* ** * ** * * ** ***** * * * * ** ** * ** * * * * * (-b-spD)/(2*a);
*** **** *** * * ** * ** * ** **** *** *** ** ** *** * * **** * *** * * * *** (x1==x2){
* * **** *** *** ** ** * **** * *** ** **** * ** * * *** ******** ** *** * * ** * * ** * * ** * * **** * **** * **** * X=%d\n", x1);
* * **** * ** * ** **** * *** * *** * ** * *** ******* ***
***** * ** ** ** **** ** * * * * * * * * **** *** **** * ** ** ** {
* ***** ** **** * * ** **** * * * * *** ** * **** *** ** *** ** * **** ** **** * ***** ** *** ******* ** * * * * X=%d或%d\n", x1, x2);
* * ** *** * ** * * * * * ** * * *** ** * * ** * * ** * *
        }
* * * * * ** * ** * *** ** * ** ** if(D==0){
** *** **** * ** * * ***** **** **** *** ******* ****** ** ** *** *** ** (-b)/(2*a);
* ** * * * * ** **** * **** * ** * ** * ** ******** ** * *
*** ***** * ** ***** *** * * * * * ** ** **** * *** * *** * ** ** *** *** ** * ** * ** ***** X=0");
* ** * * * * ** * * *** * * * *** * * * * * * * *
*** * * ** ***** * ** * ** * * * * ** * * * * * *** ** ** ***** * * ** *
* * ** * * * * **** * * ** *** ** ** ** * ** * ** * * * ** * ** *** * * ** * **** *** * X=%d\n", x1);
* * * ** * * * ** ** ** * **** * * * ** *** **** * * * ****
        }
* *** * ***** * * ** ** **** * * *** *** ** ** **
* *** * * *** **** ** * * * * ********** * **** ****** * ** * ** ** * * *** * *** * * * ** * ****** * * * **
* * *** ** ** ** * ** ********** * ** * ***
    }
***** ** * * **** * * * ** * * **** * **
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
** ** ******* * * a,b,c,D;
**** ** * * ** *** x1,x2;
* * * * *** * * ** * * *** * *** ** ** %d *** **** * * ****** * * ***

* ** * *** ** ***** * * * **
***** * ****** * * *** *** ** *
* * ** * * * * * ** *** * * *

* ** ** ** ** ** ** A,B,C;
*** ** * * * ****** * **

** ** * **** ** **** * * *
** ******* * * * * * * *** *********** ** ** ** *** of %.2fx^2 + %.2fx + %.2f = 0  are real and * * * * ****
* * *** *** * * * * ****** * ** ** *** *** * ** ** * ** = %.2f\n",x1);
** **** *** **** ** * **** ** **** ** ** **** ** *** ** = %.2f",x2);}

*** * *** * * ** ** * ** ** if(D==0)
* * *** * *** * * ** * ** *** ** * * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
**** * * ****** **** * * * *** * * * * * * *** * ** * = x2 = %.2f",x1);}

* ** *** * ** * * * **** * if(D<0)
* ** * * * * ** ** *** ** *** * ** ** * ** * **** * * of %.2fx^2 + %.2fx + %.2f = 0  are complex and ** ** * ** ** * *
** * ** * * * * * * *** ** * *** * ** bb,d,dd;
* * ** *** ** **** * ** * ** *** * ** * * * ** ** ** *
* ***** * * *** **** *** ** ** ** ****** * ** *
**** * ** **** * * **** * * * * * *** ** ** * ** * ** ** * = ***** * * *****
* **** * ** ** * **** ** ****** *** * * ** * * ****** ** * * * = * **** * *****

* * * * * ****** ** ** *** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* ** ** * * ** *
int main()
{
***** **** * * * *** ** ** **** *** **** * **** ***
** * *** *** *** * * * %f * * * ** ** * * ****
** *** * * ** * ** = (b*b-4*a*c);
* ** * * * **** * *** = (-b + sqrt(D))/(2*a);
***** ** **** * ** * * = (-b - sqrt(D))/(2*a);
*** * *** * ** * * *** = -b/(2*a);
* *** ***** ** ****************** =sqrt(-D)/(2*a);
* ** * **** *** ** * *
** * *** * ** * ***
** ** * * **** * * ** ***** *** * ** ** *** * * * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** * ** ******
*** * *** * ** * * * *** **** ** * * * * ** *** * * * = %.2f\nx2 = %.2f",x1,x2);
*** * ** *** ** ***** * **

* * **** * ** * * * ** ** if(D==0)
** **** *** * * * **
* * * * * * *** ** * ** *** * * ******** * *** **** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
***** ** * * *** * ** * ** *** * ** * * ***** ** * * * = x2 = %.2f",x1);
***** ** * *** *** * ******
* ****** ** ***** ****
* ** * * ** ***
** * * * ***** * * **** * ** ** ** * *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ** * *
* ** ** * *** ** **** ** ** * ** ** * ** ** ** * * * = * * * ** * ** * * ** *** * * ****
** * * * ** ** * * * * ** * *** ***** * * *** * *** = * * * ***** ***** * ***
* **** ** ****** ***
* * * ** ** **** ***** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
***** ** **
int main()
{
* * * **** **** * * * ** *** *** **** * * *
* ** *** * * * ****** ** * * ** * %f ****** ** * * *
***** * * * * * ** * ** = (b*b-4*a*c);
** * * * ***** ** * = (-b + sqrt(D))/(2*a);
** * *** ** ** = (-b - sqrt(D))/(2*a);
* * ** * * ***** ** = -b/(2*a);
***** * ** * * * * ** * * * =sqrt(-D)/(2*a);
** * *** *** ** *** * * **** * *
*** * ** * **** ** * **
* ** ** * **** ** * *** * * ******* ** * * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** ** ** * *
** **** ** *** * **** * * * * * ** *** * * * ** = %.2f\nx2 = %.2f",x1,x2);
* * * *** ** * * * **

* * ***** **** ** *** ** * if(D==0)
* ** * * * ** ***
** * * *** *** ** ****** ** * ***** ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* **** *** ** *** * * * ** ** * * * ** ***** * = x2 = %.2f",x1);
* *** * * * *** **
** ** ** ***** ***** * *
** * ********* *** **
** ** **** **** * *** *** ** ***** * ** ***** *** ** ******* of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** *** *** **
* ** * ** ** * * ******* ** ** * ** ** ** * ******** *** * = * ** ** * * * * ** *
** ** * * * **** **** ** * *** ** * ** **** * = **** * * * **** ** *
* * * * *** ** ** * * * ***
*** ***** * ** * * ** * * * ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.93
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users