0 like 1 dislike
14.6k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 14.6k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* * ****** ** *
int main()
{
* * * *** ** * ** * ** * ** ** * * ** *** * ** * ** ** *
* * ***** *** * * ** * * *** * * * %f ** * * ****** * * *****
* * *** ** ** ** * * = (b*b-4*a*c);
** * ** * * ** * ** = (-b + sqrt(D))/(2*a);
* *** ** * ** * * ** *** = (-b - sqrt(D))/(2*a);
** * * *** * * ** ** * = -b/(2*a);
*** **** * * * ***** ** * * * =sqrt(-D)/(2*a);
******* * * * * **** * *
**** **** *** ** ** * ** * * * *
* * * * **** * ** ** * * ** *** ** ***** *** * ** * * *** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ** * * ** ** ***
** * * * ** **** ***** ** * ** ** ****** ** = %.2f\nx2 = %.2f",x1,x2);
** ** *** * ****

** *** * ***** if(D==0)
****** * ** * * *
**** ***** * ** * ***** *** *** * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * * **** * * * ** * ** ** *** * * *** * ** = x2 = %.2f",x1);
* * ** ** ** *** * **
* ** **** * ** * ** *
* * ** *** * ** * *** * * *
** * * * ** ** * * *** *** * *** * * ******* ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** * * *
* **** * * * ***** *** **** ** * * ** * * ** * = ** * * * * * ***** *** * *
** * *********** * * ** * ** * ** ** ** * * **** = * * ** * *** * **** *
** ** * ** * * ** *** *
* * ******* *********** * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** ** ** * **

int main()
{
** * *** * ** *** ** * ** n, i;

* * * **** ** * **** * * ** *** * * * &n);

* * * *** * * * ** * * * = 1; i <= n; ++i)
** * * * * ** * * ***
* * ** * ** *** *** * *** * * * *** ** % i == 0)
* * * * *** * * * ** ***** * * * *** ** * ** * ** * * * * * ", i);
* ** ** * ** ***

*** *** * *** * *** ***** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** ****** * ** ***** *
* * * ** * ** * ** *

int main()
{
* * ** ** ** * ***** ** * * * * **** *
* ** **** *** *** * ** ** ** *** * ****** ** **** ** * *
** * * * ******* *** = ** * ******
* * ** * * * ** * **
** ** * * * *
* * * ** * ** ** * **** * *
* ********* * * ***** * * * = -b /(2*a);
* * ***** ** ** * * * * * * * ****
* * ** * * **** * * * = (-b)/(2*a);
* * ** ** * *** * ****** **** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = **** ** * **
* **** ******** ** *** *
****** *** *** ** if(D==0)
**** ** * ** * * * **
* * *** * * ***** ***** ** = (-b + ***
******* ********* * * ** * ** = (-b - ** * *
* *** * * * * ***** ** * ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * * *
* * ** ** ** * * *** *
* * * * ***** * * * if(D>0)
* ** * ****** * *
*** * *** * * ** **** * * = -b/(2*a);
* * * ** * ** * = (-b + * *
*** *** * ******* ** = (-b - * * * **
** ** * * * * ** ** ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = *** *** * *****
* *** * ** *
***** * * **** *** ** ** * 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ***** * ***
#include * * *** ***
int main()
{
* ***** ***** * * ** a,b,c;
* ** ** * * * ** * * ** * * *** * ** **** * ** * ** * **** *
* * * ***** ****** ** *
** * ** *** * ** * * * * * ** **
* **** ***** ****** **
* **** * * **** * ** * * *** ** ** *** **** * * ** * * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * ** **** ** * + * * * ** ** ** - ** *** *
* * * * *** * * ** **
** ** * ****** ** *
* ** **** ***** *** * if (b*b-4*a*c==0)
*** * * * * ** * *
**** * *** ** * * ** ** * *** *** ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** * * ** + * ** **** *
** ** * *** ** **** * **
***** ** * ** **** *
*** * * ** * * * *** **
** * * * *** ***
* * ** *** ** * *** ** ** ***** ** * **** * * ***** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** ** ** * ** *** ** **** **** ** **** ** * ** * * *****
* **** * **** * *
***** ** * * ** * ** ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** * ** *
#include * * *** ***
int main()
{
* * *** * *** ** * **** * a,b,c;
** * * * * *** * ** *** ** * ***** ** ***
* ** * *** * ***** * ***
* * * ******* * * **** ******* * ****
*** *** * ** * *
** * ** ** ** ** * ** * *** ** * ** * * **** * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = *** * * * * + *** * * *** * - * **** ** * *
* **** ** * * **** ** * *
* ***** * ** *** ***
* * * ** ****** * * *** * if (b*b-4*a*c==0)
***** * *** * * ** * *
* * * * ** *** * * * ** ** * * ****** * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * ***** *** + **** ** * **
* ******* *** ** * * ** **
* **** *** * * ***
* * ******** ** * * *
* * * * *** *** ** *
* * ** * * *** *** ****** ** ** ** * * * ** * **** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= ** * * ** ** ** ** * ****** ** * * * * ** *
** **** * * *** *
*** * *** * * ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
** ** *** * * * a,b,c,d,x1,x2;
* * *** ** * *** *** * ****** * * * * * ** ** * * * ****
* ** ** * * ** *********** * * * *
*** * ** * * **** **** ** ***
** ***** * * * **** *** *** **** *
* *** * ** ** ** *** * * * * **
* * ****** ** *
*** * *** *** ** ***** ** * ** ** **** ** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** ** **
* ** ** * *** *** ** * * * * * * ** *** **** * * = %.2f\n",x1);
*** * * * **** ** ** * **** * * **** * *** *** ** * = %.2f",x2);
*** * *** * **** ** * *
* * * * ** *** * * * ** * * if(d==0)
*** ** * ** *** *** *
** * * ** ** * * ** ** ***** ****** * ** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * ****** * ** ** ** * ** * **** * * ** *** * * = x2 = %.2f",x1);
** ** * ** * ** * * ** **
***** * ** * * *** ***
** ** *** ***
** * ******* * **** ****** * * ** * ** * * * ***** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * * ** ***
* * ***** * *** **** ** * * * ** * ** *** ** = * **** * * * ***** * *
* ** ** * * * ** * * *** ***** *** * * ** *** ** = **** * * ** * * * ** *
* ****** * ***** **** *
* ** * **** * ** * ** * **** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
***** * *** * * * ***** **** * *** ***** **** ** * *** * * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
** * *** * * * * * * * ** ** * ** * **** - (4*a*c);
* ** *** ** *** *** ** ** * ** ** * * ***
** * *** * ***** * ** ** *** ****** * ** * **** ** * * ********** ** **
*** * * * ** * * * ** *** * ********** * ** ** ** * * * * *** ** (-b+spD)/(2*a);
*** * **** *** ****** ** ** **** ** * **** * ** * * ** * (-b-spD)/(2*a);
*** * ** * *** *** ** * * * ** * * ** ** * * (x1==x2){
* * * * * * ** * ** * ** * * *** * * ** ** * ** * * * * * *** * * * * ** ** * * *** ** **** * * * ** *** ***** X=%d\n", x1);
** * *** * * * ** ** * * * * * ***** *** *** *** ** * * * **
* * ** **** ** ** ** * *** ** ** ** *** ** **** * ***** ** {
*** *** * *** * * * * * **** * ** * * * * * ** * *** ** **** ** ** * ** * ** *** * * * * * ** *** * * * ****** ** **** ** X=%d或%d\n", x1, x2);
****** * * ** *** * *** ** * ***** * * * ** * *** *
        }
* * * * ** * ** * * * * *** * * * * ** * if(D==0){
* * * ***** * * * ** * ** * *** **** *** * ** ** * ** * * * (-b)/(2*a);
* * * * *** ** **** ** * *** ** * * *** * ** * **** ** * ** **
* * * * * *** * *** * *** ** *** ** * *** * * ***** * ** *** ** * * * * * *** ** ** *** ** * * * X=0");
** ** * * * * * * ** * * ** ** *** ** * *** *** * *** *
* *** * **** **** * ** **** ***** * * ** ** ** * * ** * **** * ****
* * * *** ** * * ** ** ** *** ** *** * * **** * * ****** * * *** * ** * ** * * * * * ** *** ** * * X=%d\n", x1);
* ** * *** *** ***** *** ** ** * * * ** * *** **** * ** *
        }
* *** * ** *** * * *** ** * ****** * ****** ****
* ** * * * * * * *** ** * *** * * *** ** * * * **** ** * *** ** * * * *** ** ** **** * *
** * *** ****** * ***** * ***** *** * *
    }
* * * * * *** * * * ** * ***** * ****** ** * ** ****
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* * * *** * * * * * a,b,c,D;
* * * *** *** **** x1,x2;
**** **** * ****** ** * * * *** * %d **** * ** * * ****

* *** * ** ** *** ** *
* * * * * * *** ** * * * ** ***** *
* * * ***** * ** ***** * * ** **

** * * ** * ***** * ***** A,B,C;
* * * ** ** * * ** * *

* ** * *** * ** * * *** *** ***
* **** * * * ** * * *** ** * * * ** ** * * * of %.2fx^2 + %.2fx + %.2f = 0  are real and ** * * * * **
** ** * * *** * * * *** *** *** * * **** *** ** * * ** = %.2f\n",x1);
** ** * * * * * ** * ** ********* * **** * *** ***** ** *** ** = %.2f",x2);}

** * **** * * * * * ** * if(D==0)
* * * * ** * * * **** ** ** ** * ** * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* **** * ** ****** * * * * ** * ** * ** * * * * ** = x2 = %.2f",x1);}

* ** ** * * * * * * * if(D<0)
* * *********** * ******* * ** ** * ****** ** ** of %.2fx^2 + %.2fx + %.2f = 0  are complex and ** * ****
*** * * ** * * * ** * ** **** ** * * * * *** * bb,d,dd;
*** * * * *** * *** * *** * ** * * * * * * * **
*** * ***** * ***** ** **** * * ** * * *** * ** * * * ****
* ** *** ** * * *** **** * ** ** *** * * * *** * * * * * = **** ** * ***
******* ** * * * ** * * ** * * *** *** **** * * = * * ** ** ***

*** ** ** * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* ** ** * *
int main()
{
****** * * * * * * *** * **** ***** * * *
** ** * ** * * * * ** *** %f ** * ** *** * **** * ** *
*** ****** ****** = (b*b-4*a*c);
* * ** ** * ** ** = (-b + sqrt(D))/(2*a);
* * * * * * * *** * ** = (-b - sqrt(D))/(2*a);
** * * *** * **** * *** = -b/(2*a);
** **** * * ** * ** * *** ** =sqrt(-D)/(2*a);
* *** * * *** * ** ** **** *
* * ** * ** *** *** **
*** ** *** *** * *** *** * ** **** ******** ** ** * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * ** *** *
****** **** ** * * ** *** * * * *** * * = %.2f\nx2 = %.2f",x1,x2);
* * * * * * ** * * ****

** * ** ** *** **** * * if(D==0)
* * * *** * * * * * * *
* ** * * * *** * * * ** **** *** * * * ** ** ***** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** *** * ** ** ** * ******* * * * * * * ** ** **** * * ** = x2 = %.2f",x1);
* * * * ** ******** **
* *** * * ** *** ** *
********** *** * * **** **
****** ** * ** **** ** ** ** ******* *** * **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * * ** *
* *** ***** ** * * * **** **** *** * ** = * * **** **** * ****** *
* * **** * ** * * * **** ** * * ** * * * * * *** = **** ***** *** * * *
* **** *** ** * * * * *
** * ** * * ** * ** * ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
*** * ****
int main()
{
* * * ** * * * * ** * * * *** ** **
* * * * * * ** * ** * *** * %f *** * * *** ** * * * **
** * * * ** * ** * * = (b*b-4*a*c);
* ** ** ** * *** ** = (-b + sqrt(D))/(2*a);
* ** * *** ** *** * * = (-b - sqrt(D))/(2*a);
** * * * ** * ****** *** = -b/(2*a);
*** * * * * ** * * * * * ** *** =sqrt(-D)/(2*a);
* * ** * *** * ****
* * * ** * * * * ** *
* *** ** * * * ** * * * ***** ** * *** *** ** *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** * ** ** * ***
* ** *** * ***** * * ** * * * ** *** * * *** * * * = %.2f\nx2 = %.2f",x1,x2);
** *** * * * *

** ** ** * * *** ** if(D==0)
* ** * *** ** *** **
*** ** * ** * * ***** ** * * * * * ****** * * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * *** **** **** * * * * ************ *** * = x2 = %.2f",x1);
** ** ** ** * * *
* ** ** * **** * * ****
** * * *** * * * ***
* *** *** *** * *** *** * ** ** **** *** * **** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** ** *** **
******** * * ** * * * ** ** ** * * ** ****** * ** ** = * *** *** *** * *
* * ** * ** * *** ** **** ***** ** ** * * * = ** * * **** ** * *
* ** * *** *** * ** ****
** ** * *** *** ** * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.16
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users