0 like 1 dislike
5.2k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 5.2k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* ** * *** * *** **
int main()
{
* * ** ****** *** **** * **** *** ** * * *
** ***** * ** *** ***** *** ** * %f ** ** **** ** * ** ** * ****
* ** * * * ******* * * = (b*b-4*a*c);
* * ****** *** * * * * * * = (-b + sqrt(D))/(2*a);
* * *** ** ** * * * *** = (-b - sqrt(D))/(2*a);
* * ** * **** * ** * * * = -b/(2*a);
* **** ** ** * * ** * * =sqrt(-D)/(2*a);
* * * * ** ** * ** ** * *
**** * * **
* * *** * ** * *** ** ** **** ** *** * **** * * ** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * * * ** *
** * * **** ** ** ** *** * * * ****** * * * = %.2f\nx2 = %.2f",x1,x2);
* * *** ** * * **

** * * * * ** * * if(D==0)
** ** ** * * **
** * ** * ** *** * ** * * ** **** * * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** ** ** * ** ** * * ** **** ** * ** * * * = x2 = %.2f",x1);
* ** * * ***** ** * ***
* * * ** * ***
** ****** ** * *
* ** * **** * * * ** *** * ** * ** **** * ** * * *** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * *** * *** **
**** * * ** * ** * **** ** *** * * ** * **** * * = ** ** ** * *** * ** * *
* **** ** ** * * * * * *** * ** * * * * * * = * ** * *** * ***** * *
* * ** ** * * **** * *
* * * * * ** *** * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** * ** **** *

int main()
{
* * * ** * * ****** n, i;

* * ********* * ***** ** **** ** &n);

* ** ** * * * ** = 1; i <= n; ++i)
* ** ** * ** * ****
** *** ** *** * ** ** * ***** % i == 0)
** * * * ** * * * ** *** * * * * *** **** * * *** * * * ** ** ", i);
* * *** *** **

* * ** ** ***** * **** ** * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * * * ** ***
* ** ** * *

int main()
{
**** ** *** *** * ** ** ** ** * * * *
** * * ** * ** * ****** *** *** ** ** ** * **** ****
** ** * * ** * *** = *** ** **
** * * ** ** * * * * ** *
* ** ** ** ***** **
* * * * ****** ** * **** *
** * * * * *** **** * ** = -b /(2*a);
** *** * *** ******* * * ** * ** **
** * ** *** * * * **** = (-b)/(2*a);
**** *** **** * ** *** * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = *** * ** ****** * * ***
** * *** * * ** ***** **
* ** *** ** * * * *** if(D==0)
* * * * * * * ** * * ***
* ** **** * * * * = (-b + * *
* * ** ** *** * = (-b - * * * * *
* * *** * ** * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * *** ** *
** * * ****** * **** * * ***
* ****** * * * ** * ** if(D>0)
** ** *** * * * * * **
********** * ***** * * * ** = -b/(2*a);
*** * * * * ** * * = (-b + ** * ****
* *** * * * **** * = (-b - * *** *
* ** *** ** ** *** **** ** * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ** * *** **
*** * * * *** ** * * **
* * * * * * ***** ** ** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** ****
#include * * * * *
int main()
{
* * * * ********** * ** * * a,b,c;
*** * * * * ** * * * ** **** ** * * ** *** * * * * * *
* *** ** **** * **
***** * * * * * *** * * *** **
** * * * * * ****
* * * * * * * ** * * ** ** * ** ** ** * ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * ** + * ** ****** * - * * * **
* * * ** * ** *** ** *
** * * * * * * * ** *
*** **** ** * ** * * * *** if (b*b-4*a*c==0)
* ** * *** ** *****
* **** ** * * ** * ** *** ** * **** **** ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** ** * * ** + *** ** * ** *
** ** **** ** *** ** *
** ***** *** ** ** * **
* *** * *** * ** *
* * * * * *** **
* ** ** ** * ** ** * * * ** * **** * **** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * **** * * * * *** * * * *** *********** * * ** ** *
******* * * ** * * *
*** *** ** * * * ***** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ****
#include * * * **
int main()
{
** * * * * * * **** * *** a,b,c;
**** * * **** * ** * ** *** ** * ** * **** ** * * ***** *
* *** * ******** *****
*** ** * ** *** ** * * * **** *
* * *** ** ** * * *
* * * * * * ** * ** * **** ** * * ** *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ***** ** ** * + * ** *** *** - * ** ** ***
** *** **** * ** * * * *** *
* *** ***** ** * * *
*** ** ** * ****** if (b*b-4*a*c==0)
** **** *** ** **
*** **** * ** **** * ** ** *** ** ** * * ** * *** *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * *** *** ** * + ** * ** * **
*** **** *** * **
* *** **** **** * * ***
* * * ****** * * * *
* ** **** *** ** **
** ** * *** **** * **** * * * ** *** * * * **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= ** ****** * * * * * * * *** ** *** ** * *
***** * *** * ** * * **** * *
* * * *** * * ** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* ** *** ** * ** ** * *** * a,b,c,d,x1,x2;
* ** *** ** ** * * ***** * * * ** * * * *** ** * * ** *
* *** ** * * * * * * * **
* * * **** * ***** *** *** **
**** * ** ** **** * * *
* * * * * ** * **** * ** ** *
* * ***** ** ** ** ***
* * * * ***** *** * *** * ** * * * * * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * **** **
* * * * * *** * * *** * * *** ** *** ** * *** * ** = %.2f\n",x1);
* *** * * ****** ** * * * * ** *** * ** ** * = %.2f",x2);
** *** **** ** * * * **
**** ** * * **** ** ***** if(d==0)
**** * ** * * * ** * * *
** ** * * *** ** * * ** * * *** * * **** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** **** ** ** ** * **** * *** **** * ** * * * *** * * ** * = x2 = %.2f",x1);
* * * * * ** ** ** *
* * **** ** * *** ********* *** *
* ** **** * *** * *
* *** * ** ** * * ** * * * ***** * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** ** ** *** ** *
*** **** ** * *** **** *** * *** * *** ** * * ** * *** * * = * * ** *** * * * * * **
* **** * * * * ****** * ***** * **** ** = * *** * * ** * * * ** * **
* * ** * * ** ** **
* * *** * * * *** * * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
** *** * **** ** * * ** *** * * * ******** **** * * **** * * * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* * * * * ***** * * * * *** ***** **** * ** * * - (4*a*c);
*** * *** * * * * * *** * ***** * *** ** *** * *
*** * * *** * ** **** *** *** **** ** * * ***** * * * ** * * **
****** * *** * ** ** *** *** * ** * ******* * ***** ** * ******** (-b+spD)/(2*a);
* *** *** *** ** **** * * ****** * ** * ** * *** * ** ** * * ****** (-b-spD)/(2*a);
*** **** * * ** **** * * * * * **** * *** *** * * * * * * (x1==x2){
**** * ** *** ** **** *** * * ** * * * * *** * ** **** *** * ** *** ** * * * * * * ******* * * * ** **** ********* ** X=%d\n", x1);
* * * ** * * ** ** * ****** * * * * * * * ****** ** ****** **
* **** **** *** * *** * * * * * * * ** **** **** * ** ** {
* * * **** *** ***** ** * * *** * * ** * *** * ****** * ****** *** * *** * ** * * * ** *** * ** * **** ***** * **** * X=%d或%d\n", x1, x2);
* * ** * ** * ** * * * * * *** ** *** * * *** ****** **
        }
*** *** ** *** ** * * ** * * ** ** * ** * if(D==0){
* * **** * ****** * * *** ** *** **** ** * ** * ****** * * * *** * ** (-b)/(2*a);
* * * * * * * * * * * ***** * ** * ** * ** * * * ** * ** * * * * * * **
**** * * ** * * * ** * * * *** * *** ** * **** * * * *** *** ** * ** ** * **** *** * * **** ** * * * * X=0");
* ** *** * * * * ** ** ** * ** *** * * **** *** * * **
* * * ** *** *** * * * * * ******* * * *** * * * ** * * * * ** * *
** * ** ** ***** ***** * * ***** * ** * ** ** *** ** * ***** * * * ** * * * **** **** ** ** * * *** * X=%d\n", x1);
*** ** ** ***** * * * ***** * ** ** ********* ** * * **
        }
* ** * ** ** * * *** ** ** ** * *** * *
** **** * * ******* * * ********* ** * * ** **** *** ** * * ** * *** **** ** ** * *
** **** ** ** * * **** ** *** ** *** * ** * *****
    }
* ** ***** ** * * * **** **** ** * *** * **
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* ** ******* * ** * * ** * ** a,b,c,D;
* ** * * **** * * * ****** x1,x2;
* * * *** ** * * * * *** ** %d **** * ** ***** **** * ** ****

** * * * ******* **** ****
* * * * * * * * ** *** * * *
* *** ** * * * * * ** ** ********

*** * * * * * ** ** * A,B,C;
**** ** *** ** * ** * ** * *

** * ** ** ** * *** ** * *
** ** **** **** * * ** ** ** ** *** * * ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0  are real and * * * * * * *
* ** * ** **** *** * * *** * ** ** **** * ** * * *** = %.2f\n",x1);
** **** **** * ** * * *** *** * ********* * ** * * = %.2f",x2);}

* **** * * ** *** ** * **** if(D==0)
** * ** * * ** * ** ** * * ** * * *** * ******* **** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
***** *** * * **** * * *** **** * *** * * * *** * ** * = x2 = %.2f",x1);}

** * ** *** * * * * if(D<0)
*** * * * * * ** ** *** * ** * * **** * * **** of %.2fx^2 + %.2fx + %.2f = 0  are complex and ** * *** *
**** ***** * ******* *** * ******* * ** ** * bb,d,dd;
* * * ** * * * * *** * ** * * * * * * * * * *
* * *** ** * ** ****** * * *** *** * * * ** * ***** * * *
*** **** * * * ** ** ** * * * * *** ** ********** * ****** = * * ** ** ** **
*** ** ** ** * **** * * * ** ** * ******** * * * ** ** * * = ***** **

* ** ** * * * * * * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
** * ****** *** * *
int main()
{
* * *** * **** * ** ** **** ** ** **
** * * ** ** * ** * ******* * * %f * ** * * * * *** **** * *
** * * ***** * = (b*b-4*a*c);
** * * **** ***** * * * = (-b + sqrt(D))/(2*a);
* * * * *** * * ** = (-b - sqrt(D))/(2*a);
* * * * ***** * *** ** **** * = -b/(2*a);
*** * * * * ** * ** ** * * =sqrt(-D)/(2*a);
** * ** *** ** ** * *** * **
* **** ** ** * *
* **** * * ** * *** * ** * * * ***** * ** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ** * * *
* * * * ** ** * * * * * * ** ** ***** *** *** * = %.2f\nx2 = %.2f",x1,x2);
** * * * ** *

** * * * * ** * * * if(D==0)
* * * * * * ** *** *
**** * ** *** *** * ***** * **** * **** * *** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * ** *** ** * * ** ** ** * * *** * * * *** ** ** * * = x2 = %.2f",x1);
**** * ** * * *
* *** **
* ** * * * ** ** * ****
*** * * ** ** *** * * * *** *** * * * ** ****** * *** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and **** * ** **
* * ** ** * ** * ** *** **** ***** *** * ** *** * ** * * * = ** ***** * *** ** * ****
** * ** * * *** * *** ** * * *** ** **** * * ** * = *** **** *** ** **
******* * * * *** ** *
* **** * **** ** ** **** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
** * ** **
int main()
{
*** ** ** ***** ** * ** * ** ** ****** ***
* *** * * * * ** ** *** * %f * **** * *** * * *
* * ** * *** * = (b*b-4*a*c);
*** * *** ***** *** * = (-b + sqrt(D))/(2*a);
* ** ** ** ****** ** * = (-b - sqrt(D))/(2*a);
* ** ** * * * * ** * ** * = -b/(2*a);
*** *** * * * * * * *** * =sqrt(-D)/(2*a);
*** * * *** * * * * *** * * * * **
* * **** *** * **** * *
** * ****** * * ** * *** ** * ****** * ****** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * ** * * ***
* ** * *** * ** ** ***** * * ** **** * ** * * = %.2f\nx2 = %.2f",x1,x2);
**** * ********* ***

** ***** *** * * *** if(D==0)
* ** * * * * * *** *
*** ** ** * * *** ** * ** * **** * ** ***** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** * * * * **** ** ** * * * ***** ***** *** * * * * * = x2 = %.2f",x1);
* *** ** **** * * * ** * **
***** * * ** *** *** ** *
* * ** *** ** * ** *** * *
*** **** *** * *** * ** * ***** ** ** * * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ** **** * **
** * * * ** * * ** ****** *** **** ** * * * *** * = **** * * * * * *** * *
***** * * * * ****** * * * ** ** ** **** * ** **** * *** = ***** * * ** * *
** * ** ** ** * * *
*** * * ** ** * * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.19
©2016-2024

No related questions found

12,783 questions
183,443 answers
172,219 comments
4,824 users